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  • Add inputs to more than one row in a structure array in matlab

    - by ZaZu
    Hi there, I would like to know how can I get certain inputs and put them in more than one row in the structure ... I basically want a structure that updates one input per row in ever loop. The loop is looped 30 times, so I want to have 30 rows and 2 columns ( x and y columns) I have this code : For N=1:30 . . . Binary = bwlabel(blacknwhite); s = regionprops(Binary,'centroid'); centroids = cat(1, s.Centroid); hold(imgca,'on') plot(imgca,centroids(1,1), centroids(1,2),'r*') . . . end I dont think this does what I want ... only the first row is updated in my loop .. So how can I create this structure ? If you want more info please tell me and I will update it right away. Thanks !

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  • PHP while(variable=mysql_fetch_assoc) - explanation

    - by Petr
    Hi, I have been working with C# so this is quite strange for me: while($variable=mysql_fetch_assoc) I have not been able to look up in PHP manual how it works. I guess that in each loop it advances to next element of assoc.array. But what is this generally called in PHP? I am just not used to see '=' in loop condition.

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  • Loop each x elements

    - by Cimm
    What's the beste way to show a list with 20 images in rows of 5? Or, in other words, how do I clean up this ugly snippet? <div class="row"> <% @images.each_with_index do |image, index| %> <%= image_tag image.url %> <% if index != 0 && index % 5 == 0 %> </div><div class="row"> <% end %> <% end %> </div>

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  • Loop crashing program having to do with 2D arrays

    - by user450062
    I am creating an encoding program and when I instruct the program to create a 5X5 grid based on the alphabet while skipping over letters that match up to certain pre-defined variables(which are given values by user input during runtime). I have a loop that instructs the loop to keep running until the values that access the array are out of bounds, the loop seems to cause the problem. This code is standardized so there shouldn't be much trouble compiling it in another compiler. Also would it be better to seperate my program into functions? here is the code: #include<iostream> #include<fstream> #include<cstdlib> #include<string> #include<limits> using namespace std; int main(){ while (!cin.fail()) { char type[81]; char filename[20]; char key [5]; char f[2] = "q"; char g[2] = "q"; char h[2] = "q"; char i[2] = "q"; char j[2] = "q"; char k[2] = "q"; char l[2] = "q"; int a = 1; int b = 1; int c = 1; int d = 1; int e = 1; string cipherarraytemplate[5][5]= { {"a","b","c","d","e"}, {"f","g","h","i","j"}, {"k","l","m","n","o"}, {"p","r","s","t","u"}, {"v","w","x","y","z"} }; string cipherarray[5][5]= { {"a","b","c","d","e"}, {"f","g","h","i","j"}, {"k","l","m","n","o"}, {"p","r","s","t","u"}, {"v","w","x","y","z"} }; cout<<"Enter the name of a file you want to create.\n"; cin>>filename; ofstream outFile; outFile.open(filename); outFile<<fixed; outFile.precision(2); outFile.setf(ios_base::showpoint); cin.ignore(std::numeric_limits<int>::max(),'\n'); cout<<"enter your codeword(codeword can have no repeating letters)\n"; cin>>key; while (key[a] != '\0' ){ while(b < 6){ cipherarray[b][c] = key[a]; if ( f == "q" ) { cipherarray[b][c] = f; } if ( f != "q" && g == "q" ) { cipherarray[b][c] = g; } if ( g != "q" && h == "q" ) { cipherarray[b][c] = h; } if ( h != "q" && i == "q" ) { cipherarray[b][c] = i; } if ( i != "q" && j == "q" ) { cipherarray[b][c] = j; } if ( j != "q" && k == "q" ) { cipherarray[b][c] = k; } if ( k != "q" && l == "q" ) { cipherarray[b][c] = l; } a++; b++; } c++; b = 1; } while (c < 6 || b < 6){ if (cipherarraytemplate[d][e] == f || cipherarraytemplate[d][e] == g || cipherarraytemplate[d][e] == h || cipherarraytemplate[d][e] == i || cipherarraytemplate[d][e] == j || cipherarraytemplate[d][e] == k || cipherarraytemplate[d][e] == l){ d++; } else { cipherarray[b][c] = cipherarraytemplate[d][e]; d++; b++; } if (d == 6){ d = 1; e++; } if (b == 6){ c++; b = 1; } } cout<<"now enter some text."<<endl<<"To end this program press Crtl-Z\n"; while(!cin.fail()){ cin.getline(type,81); outFile<<type<<endl; } outFile.close(); } } I know there is going to be some mid-forties guy out there who is going to stumble on to this post, he's have been programming for 20-some years and he's going to look at my code and say: "what is this guy doing".

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  • VB.NET 2008 Application crashing during Do Loop

    - by RedHaze
    I am writing an application to compare each item on listbox1 to all items on listbox2. If the item is found, then remove it from both lists. The goal is to only have the items that were not found remain on both lists. The problem is, the application just hangs and I never get any results. I looked at my code several times and I cannot figure out what's going on (programming noob I know...). Can anybody help me with this? Code Snippet: Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click Dim a As String Dim b As String Dim y As String For i As Integer = 0 To ListBox1.Items.Count - 1 a = ListBox1.Items(i) y = 1 Do While y = 1 For x As Integer = 0 To ListBox2.Items.Count - 1 b = ListBox2.Items(x) Dim res As Int16 = String.Compare(a, b) If res = 0 Then y = 0 ListBox2.Items.Remove(i) ListBox2.Items.Remove(x) ElseIf x = ListBox1.Items.Count Then Exit Do End If Next Loop Next End Sub

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  • Nested <a> and <span> challenge

    - by PaddyO
    Hi all, Trying in vain to get a nested link working within a nested span. This is a working test page for the code below to explain what I'm trying to do. Any ideas on how to get this working in valid html? I guess it's either a nesting order or style syntax thing but I am at a loss. Any thoughts much appreciated. <div id="greyback"> <ul id="scrollbox"> <li class="listcat">List header</li> <li><a class="menu" href="#freeze">List item 1<span><b>This text has popped up because you have clicked the list item, which has an "a" tag and now has :focus. That "a" tag is the first of two.</b><br><br>What I am trying to do is to set the second "a" tag as a DIFFERENT "embedded" link in this box<span style="color: blue; background-color: yellow;">eg, here<a href="http://www.conservationenterprises.com" target="blank">This is the second (nested) "a" tag in this html nest. It is a link to an external site. Instead of this being an always-visible link, I want it to sit within the yellow box in the first span (click the List item 1 to display).</a></span> </a></span> </li> </a></span> </li> </ul> </div> and the CSS: #scrollbox {margin: 0 auto; margin-top: 1em; margin-bottom: 1em; width:19em; height:auto; max-height: 21em; overflow:auto; border-bottom: 0.1em solid #FFA500; border-top: 0.1em solid #FFA500;} #scrollbox a {float: left; color:#000000; text-decoration:none; width:18em; height: auto; margin-bottom: 0.5em; font-family: Arial, sans-serif; font-size: 0.9em; text-align:left;} #scrollbox a.menu {} #scrollbox a span {display:none; position:absolute; left:0em; top:0;} #scrollbox a span img {float: right; border:0; max-width:7.5em;} #scrollbox a:hover {border: 0; color: #7ebb11; font-size:0.9em;} #scrollbox a:hover span {border: 0; color: #535353;} #scrollbox a span:focus {color: blue;} #scrollbox a:active {border:none; color: #535353; text-decoration: none;} #scrollbox a:focus {border:0em solid #000; outline:0;} #scrollbox a:active span, #scrollbox li a:active span, #scrollbox a:focus span, #scrollbox li a:focus span {display: block; width: 52.5em; min-height: 20em; height: auto; left: 1.5em; top:18em; z-index:10; font-size:0.9em; text-align: left; padding: 1em; padding-bottom: 0em; background-color: #c3FFe3; color: #535353; border: solid #FFA500 0.25em;} #scrollbox li a:active span span, #scrollbox li a:focus span span{display: block; width: auto; height: auto; min-height: 2em; left: 25em; top:10em; z-index:10; font-size:0.9em; text-align: left; padding: 1em; padding-bottom: 0em; background-color: transparent; color: #535353; border: dashed red 1px;} .ul#scrollbox {padding-left: 0.1em;} #scrollbox li {float:left; list-style: none; background: url(blank.png) no-repeat left center; margin-left: 0em; font-family:Arial, sans-serif; font-size: 0.9em;} #scrollbox li.listcat {float: left; text-align:left; width: 18em; margin-left: 0em; margin-top: 0.1em; margin-bottom: 0.3em; padding-top:0.5em; color: green; font-size: 0.9em; font-weight:bold;} Cheers Patrick.

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  • Scala Unit type

    - by portoalet
    I use opencsv to parse csv files, and my code is while( (line = reader.readNext()) != null ) { .... } I got a compiler warning saying: comparing values of types Unit and Null using `!=' will always yield true [warn] while( (aLine = reader.readNext()) != null ) { How should I do the while loop?

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  • [java] How to get ALL the information from a socket

    - by raven
    Hello, I'll begin this question with the claim that I have read the java networking guide before asking you. I do not understand how to READ the socket and get all the info summed up into a string. the socket might contains more than 1 line [trying to make a chat]. Please do no refer me to any other site unless it clearly states "this exact line does this.." because I failed to understand what this code part does BufferedReader stdIn = new BufferedReader( new InputStreamReader(System.in)); String userInput; while ((userInput = stdIn.readLine()) != null) { out.println(userInput); System.out.println("echo: " + in.readLine()); } Please, I just want to make a loop that will receive information from a socket, get all the content together into one string [I also want it to know where to add another line]. Thanks allot for anyone who helps, I have been trying to get an answer from tuts for hours and just failed to understand!

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  • Using Jquery 1.8.0 return false is not breaking an each() loop

    - by user1879729
    Here is the script I am using. $('.row').each(function(){ $(this).each(function(){ if($(this).find('.name').val()==""){ $(this).find('.name').val(data.name); $(this).find('.autonomy').val(data.autonomy); $(this).find('.purpose').val(data.purpose); $(this).find('.flow').val(data.flow); $(this).find('.relatedness').val(data.relatedness); $(this).find('.challenge').val(data.challenge); $(this).find('.mastery').val(data.mastery); $(this).find('.colour').val(data.colour); done=true; } if(done==true){ alert("here"); return false; } }); }); It just seems to totally ignore the return false and I can't seem to work out why!

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  • Historical Rolling Daily sum

    - by user2980057
    I have a table of consisting of Dates and the amount of revenue recorded for that day going back for about 12 years. What I would like to do with this data is create a new table with Dates and prior 7-day revenue numbers. Any guidance would be greatly appreciated. Below is an example of what my source table and what my results would need to look like.... Source Table.. DATE | Revenue 12/31/2013 | 200 12/30/2013 | 300 12/29/2013 | 400 12/28/2013 | 100 12/27/2013 | 200 12/26/2013 | 150 12/25/2013 | 350 12/24/2013 | 450 12/23/2013 | 200 12/22/2013 | 300 12/21/2013 | 100 12/20/2013 | 300 Resulting Table... DATE | 7Dayrev 12/31/2013 | 1700 12/30/2013 | 1950 12/29/2013 | 1850 12/28/2013 | 1750 12/27/2013 | 1750 12/26/2013 | 1850 ETC......

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  • PHP while loop, table row

    - by Elliott
    Hi, I'm trying to loop through a database and output data into a div, if there are 3 divs horizontally accross it will the start a new tr until it reaches another 3 etc. It is currently outputted like : [] [] [] [] [] [] Currently I have it working when it reaches 3 it starts a new row, but I don't know how I can only echo a new tr once? As it creates a new table row each time. echo '<table><tr>'; while ($result) { $i ++; if ($i&3) { echo '<td> <div>Row Data</div> </td>'; } else { echo '<tr> <td> <div>Row Data</div> </td></tr>'; } } echo '</tr></table>'; The $result variable is the recordset from my sql query, everything works fine I just don't know how to only create a new table row once? Thanks

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  • How to iterate over numerically named object properties

    - by Scott Schluer
    So I have a horribly designed class that I can't change that has properties like this: object.Color1 object.Color2 object.Color3 etc... How can I iterate through those with a for loop. In other words, something like this: for (int i = 0; i <= 40; i++) { string PropertyName = "Color" + i; if (object.PropertyName != "") { // do something } } Obviously this code wouldn't work but it gives you an idea of what I'm after. I have to do some processing on each property and I don't want to repeat my code 40 times. :) A loop would be perfect, I'm just not sure how to create the name of the property on the fly.

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  • How to get the next row from the Database table?

    - by Parth
    How to get the next row from the Database table? Such that the row might be incremented row that is if structure has a field called "id" then the row can be id++ or very next incremented row, but it may also b any other id containing row (NOT VERY NEXT) , (because the ids could be deleted from the table). the point of id I am talking about is It could be 1,2,3,4.... or it could be 1,6,7,8,23.. so on.... Please help for fetching the next row in the for loop to get it checked.

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  • Why won't this piece of my code write to file

    - by user2934783
    I am developing a c++ banking system. I am able to get the float, newbal, values correctly and when I try to write to file, there is no data in the file. else { file>>firstname>>lastname; cout<<endl<<firstname<<" "<<lastname<<endl; cout<<"-----------------------------------\n"; string line; while (getline(file, line)) { //stringstream the getline for line string in file istringstream iss(line); if (iss >> date >> amount) { cout<<date<<"\t\t$"<<showpoint<<fixed<<setprecision(2)<<amount<<endl; famount+=amount; } } cout<<"Your balance is $"<<famount<<endl; cout<<"How much would you like to deposit today: $"; cin>>amountinput; float newbal=0; newbal=(famount+=amountinput); cout<<"\nYour new balance is: $"<<newbal<<".\n"; file<<date<<"\t\t"<<newbal; //***This should be writing to file but it doesn't. file.close(); The text file looks like this: Tony Gaddis 05/24/12 100 05/30/12 300 07/01/12 -300 //Console Output looks like this Tony Gaddis 05/24/12 100 05/30/12 300 07/01/12 -300 Your balance is: #1 How much wuld you like to deposit: #2 Your new balance is: #1 + #2 write to file close file. //exits to main loop:::: How can I make it write to file and save it, and why is this happening. I tried doing it with ostringstream as well considering how I used istringstream for the input. But it didn't work either :\ float newbal=0; newbal=(famount+=amountinput); ostringstream oss(newbal); oss<<date<<"\t\t"<<newbal; I am trying to self teach c++ so any relevant information would be kindly appreciated.

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  • Python2.7: How can I speed up this bit of code (loop/lists/tuple optimization)?

    - by user89
    I repeat the following idiom again and again. I read from a large file (sometimes, up to 1.2 million records!) and store the output into an SQLite databse. Putting stuff into the SQLite DB seems to be fairly fast. def readerFunction(recordSize, recordFormat, connection, outputDirectory, outputFile, numObjects): insertString = "insert into NODE_DISP_INFO(node, analysis, timeStep, H1_translation, H2_translation, V_translation, H1_rotation, H2_rotation, V_rotation) values (?, ?, ?, ?, ?, ?, ?, ?, ?)" analysisNumber = int(outputPath[-3:]) outputFileObject = open(os.path.join(outputDirectory, outputFile), "rb") outputFileObject, numberOfRecordsInFileObject = determineNumberOfRecordsInFileObjectGivenRecordSize(recordSize, outputFileObject) numberOfRecordsPerObject = (numberOfRecordsInFileObject//numberOfObjects) loop1StartTime = time.time() for i in range(numberOfRecordsPerObject ): processedRecords = [] loop2StartTime = time.time() for j in range(numberOfObjects): fout = outputFileObject .read(recordSize) processedRecords.append(tuple([j+1, analysisNumber, i] + [x for x in list(struct.unpack(recordFormat, fout))])) loop2EndTime = time.time() print "Time taken to finish loop2: {}".format(loop2EndTime-loop2StartTime) dbInsertStartTime = time.time() connection.executemany(insertString, processedRecords) dbInsertEndTime = time.time() loop1EndTime = time.time() print "Time taken to finish loop1: {}".format(loop1EndTime-loop1StartTime) outputFileObject.close() print "Finished reading output file for analysis {}...".format(analysisNumber) When I run the code, it seems that "loop 2" and "inserting into the database" is where most execution time is spent. Average "loop 2" time is 0.003s, but it is run up to 50,000 times, in some analyses. The time spent putting stuff into the database is about the same: 0.004s. Currently, I am inserting into the database every time after loop2 finishes so that I don't have to deal with running out RAM. What could I do to speed up "loop 2"?

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  • More compact way to do this?

    - by Macha
    I have a couple of functions that loop around the surrounding cells of a cell. The grid is contained inside an array. In my code, I have checks to make sure it's not one of the edge cells, as checking an undefined cell causes an error. As such, I have code like this: if(x > 0) { var firstX = x - 1; } else { var firstX = x; } if(x < 199) { var lastX = x + 1; } else { var lastX = x; } if(y > 0) { var firstY = y - 1; } else { var firstY = y; } if(y < 199) { var lastY = y + 1; } else { var lastY = y; } A lot of lines of code to do very little. Is there a more elegant way to do this?

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  • JQuery: loop through elements with more than one css class name that share only the first class name

    - by omaether
    Hello, I'm trying to use JQuery to loop through several div's with more than one class name, that all have the same first css class name and each one has a different second class name, e.g. <div class="maintext blue"> </div> <div class="maintext purple"> </div> <div class="maintext chartreuse"> </div> <div class="maintext puce"> </div> <div class="maintext lime"> </div> In JQuery I have tried $(".mainText").each(function (i) $(".mainText.*").each(function (i) $(".mainText" *).each(function (i) $(".mainText .*").each(function (i) But it will not select any of the divs with class="mainText ..." thanks for considering the question.

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  • Python for loop question

    - by Joe Dunk
    I was wondering how to achieve the following in python: for( int i = 0; cond...; i++) if cond... i++; //to skip an run-through I tried this with no luck. for i in range(whatever): if cond... : i += 1

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  • [Java]Queue in while loop, cannot modify the value?

    - by javaLearner.java
    This is my code: Iterator it = queue.iterator(); while(it.hasNext()){ random = randNumber(1,2); if(random == 1){ queue.poll(); } else { queue.add("new"); queue.poll(); } } It gives me: Exception in thread "test" java.util.ConcurrentModificationException at java.util.LinkedList$ListItr.checkForComodification(LinkedList.java:761) at java.util.LinkedList$ListItr.next(LinkedList.java:696) Edit @Jon Skeet: What I want to do is: I have a queue list in, let say the size is 10, lets say: a,b,c,d ... j Generate a number between 1 and 2. if 1, pull (remove the top element) else if 2 add new element I will stop the loop until I added 3 new elements

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  • Java - Can i have a faster performance for this loop ?

    - by Brad
    I am reading a book and deleting a number of words from it. My problem is that the process takes long time, and i want to make its performance better(Less time), example : Vector<String> pages = new Vector<String>(); // Contains about 1500 page, each page has about 1000 words. Vector<String> wordsToDelete = new Vector<String>(); // Contains about 50000 words. for( String page: pages ) { String pageInLowCase = page.toLowerCase(); for( String wordToDelete: wordsToDelete ) { if( pageInLowCase.contains( wordToDelete ) ) page = page.replaceAll( "(?i)\\b" + wordToDelete + "\\b" , "" ); } // Do some staff with the final page that does not take much time. } This code takes around 3 minutes to execute. If i skipped the loop of replaceAll(...) i can save more than 2 minutes. So is there a way to do the same loop with a faster performance ?

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  • ruby looping question

    - by jonepatr
    Hello! I want to make a loop on a variable that can be altered inside of the loop. first_var.sort.each do |first_id, first_value| second_var.sort.each do |second_id, second_value_value| difference = first_value - second_value if difference >= 0 second_var.delete(second_id) else second_var[second_id] += first_value if second_var[second_id] == 0 second_var.delete(second_id) end first_var.delete(first_id) end end end How do I do this, because this doesn't work?

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  • Retrieving the value of a concatenated variable within a Java FOR loop

    - by Rajat
    I have been using this "logic" in C++ and VB with success, but am tied up in Java... Simply put, public void DataProviderExample(String user, String pwd, String no_of_links, String link1, String link2, String link3) { for (int i=1;i<=no_of_links;i++) { String link = "link"+i; System.out.println(link); } Now, if the variables link1, link2 and link3 have a value of "X", "Y" and "Z" respectively, upon running this program, I get the following output - link1 link2 link3 What I want is - X Y Z Any ideas?

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  • Python: Determine whether list of lists contains a defined sequence

    - by duhaime
    I have a list of sublists, and I want to see if any of the integer values from the first sublist plus one are contained in the second sublist. For all such values, I want to see if that value plus one is contained in the third sublist, and so on, proceeding in this fashion across all sublists. If there is a way of proceeding in this fashion from the first sublist to the last sublist, I wish to return True; otherwise I wish to return False. In other words, for each value in sublist one, for each "step" in a "walk" across all sublists read left to right, if that value + n (where n = number of steps taken) is contained in the current sublist, the function should return True; otherwise it should return False. (Sorry for the clumsy phrasing--I'm not sure how to clean up my language without using many more words.) Here's what I wrote. a = [ [1,3],[2,4],[3,5],[6],[7] ] def find_list_traversing_walk(l): for i in l[0]: index_position = 0 first_pass = 1 walking_current_path = 1 while walking_current_path == 1: if first_pass == 1: first_pass = 0 walking_value = i if walking_value+1 in l[index_position + 1]: index_position += 1 walking_value += 1 if index_position+1 == len(l): print "There is a walk across the sublists for initial value ", walking_value - index_position return True else: walking_current_path = 0 return False print find_list_traversing_walk(a) My question is: Have I overlooked something simple here, or will this function return True for all true positives and False for all true negatives? Are there easier ways to accomplish the intended task? I would be grateful for any feedback others can offer!

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  • Java: "cannot find symbol" error of a String[] defined within a while-loop

    - by David
    Here's the relevant code: public static String[] runTeams (String CPUcolor) { boolean z = false ; //String[] a = new String[6] ; boolean CPU = false ; while (z == false) { while (CPU==false) { String[] a = assignTeams () ; printOrder (a) ; for (int i = 1; i<a.length; i++) { if (a[i].equals(CPUcolor)) CPU = true ; } if (CPU==false) { System.out.println ("ERROR YOU NEED TO INCLUDE THE COLOR OF THE CPU IN THE TURN ORDER") ; } } System.out.println ("is this turn order correct? (Y/N)") ; String s = getIns () ; while (!((s.equals ("y")) || (s.equals ("Y")) || (s.equals ("n")) || (s.equals ("N")))) { System.out.println ("try again") ; s = getIns () ; } if (s.equals ("y") || s.equals ("Y") ) z = true ; } return a ; } the error i get is: Risk.java:416: cannot find symbol symbol : variable a location: class Risk return a ; ^ Why did i get this error? It seems that a is clearly defined in the line String[] a = assignTeams () ; and if anything is used by the lineprintOrder (a) ;` it seems to me that if the symbol a really couldn't be found then the compiler should blow up there and not at the return statment. (also the method assignTeams returns an array of Strings.)

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