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  • Rails controller processing as HTML instead of XML

    - by Andy
    I've recently upgraded from Ruby 1.8.6 and Rails 2.3.4 to Ruby 1.9 and Rails 3.0.3. I have the following controller: class ChartController < ApplicationController before_filter :login_required respond_to :html, :xml def load_progress chart.add( :series, "Memorized", y_memorized ) chart.add( :series, "Learning", y_learning ) chart.add( :series, "Mins / Day", y_time ) chart.add( :user_data, :secondary_y_interval, time_axis_interval ) respond_to do |fmt| fmt.xml { render :xml => chart.to_xml } end # Also tried # respond_with chart end end However, when I call the 'load_progress method' I get the following: Started GET "/load_progress.xml" for 127.0.0. Processing by ChartController#load_progress as HTML Completed 406 Not Acceptable in 251ms I have also tried changing the respond_to block to respond_with chart But I get the same response. I've read all the new Rails documentation on the new respond_with format but I can't seem to elicit an XML response. Am desperately hoping someone has some ideas.

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  • jQuery won't parse xml with nodes called option

    - by user170902
    hi all, I'm using jQuery to parse some XML, like so: function enumOptions(xml) { $(xml).find("animal").each(function(){ alert($(this).text()); }); } enumOptions("<root><animal>cow</animal><animal>squirrel</animal></root>"); This works great. However if I try and look for nodes called "option" then it doesn't work: function enumOptions(xml) { $(xml).find("option").each(function(){ alert($(this).text()); }); } enumOptions("<root><option>cow</option><option>squirrel</option></root>"); There's no error, just nothing gets alerted, as if the find isn't finding anything. It only does it for nodes called option everything else I tested works ok! I'm using the current version of jQuery - 1.4.2. Anyone any idea? TIA. bg

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  • hide XML element from appearing in browser

    - by ffsb
    HI, I have a website which I am setting up. However, I want the first page (Home) not to have any sub menu. When I change the value of true to false all the other pages where I want the drop down to appear also disappear. I want other pages to have sub menu but not the home page. I have tried to change the xml path etc, but nothing seems to work. Can somebody please advise on this. I am new to xml and finding this very challenging. I have uploaded the config.xml and the layout xml's. I have also placed the index.htm and js script there. http://www.mediafire.com/?sharekey=043102ffea137c3c67cd7f7bd65f7eef3662a86c6a842d54ea4ac78345cbe4ce Also could someone please help me understand from where it is reading the config.xml.

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  • Javascript - use to load xml data from URL

    - by spenf
    I have this url with some xml data in it: http://64.182.231.116/~spencerf/union_college/Upperclass_Sample_Menu.xml And I would like to load this xml data into my javascript script so I can parse it. I am using parse.com Javascript SDK, in there cloud code. Here is the code I have tried: Parse.Cloud.define("next", function(request, response) { response.success("Hello world!"); $.ajax({ url: 'http://64.182.231.116/~spencerf/union_college/Upperclass_Sample_Menu.xml', // name of file you want to parse dataType: "xml", // type of file you are trying to read success: parse, // name of the function to call upon success error: function(){alert("Error: Something went wrong");} }); }); But when I run this I get an error: $ is not defined at main.js:

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  • git pull not working

    - by dorelal
    I am not using github. We have git setup on our machine. I created a branch from master called experiment. However when I am trying to do git pull I am getting following message. > git pull You asked me to pull without telling me which branch you want to merge with, and 'branch.experiment.merge' in your configuration file does not tell me either. Please specify which branch you want to merge on the command line and try again (e.g. 'git pull <repository> <refspec>'). See git-pull(1) for details. Here is result of git remote show origin > git remote show origin * remote origin Fetch URL: ssh://git.domain.com/var/git/app.git Push URL: ssh://git.domain.com/var/git/app.git HEAD branch: master Remote branches: experiment tracked master tracked Local branches configured for 'git pull': master merges with remote master Local refs configured for 'git push': experiment pushes to experiment (local out of date) master pushes to master (up to date) As I read the message above experiment is mapped to origin/experiment. And my local repository knows that it is out of date. Then why I am not able to do git pull?

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  • git submodule pull and commit automatically on webserver

    - by Lukas Oppermann
    I have the following setup, I am working on a project project with the submodule submodule. Whenever I push changes to github it sends a post request to update.php on the server. This php file executes a git command. Without submodules I can just do a git pull and everything is fine but with submodules it is much more difficult. I have this at the moment, but it does not do what I want. I should git pull the repo and update and pull the latest version of each submodule. <?php echo `git submodule foreach 'git checkout master; git pull; git submodule update --init --recursive; git commit -m "updating"' && git pull && git submodule foreach 'git add -A .' && git commit -m "updating to latest version including submodules" 2>&1s`; EDIT// Okay, I got it half way done. <?php echo `git submodule foreach 'git checkout master; git pull; git submodule update --init --recursive; git commit -am "updating"; echo "updated"' && git pull && git commit -am "updating to latest version including submodules" && echo 'updated'`; The echo prevents the script to stop because of non-zero returned. It works 100% fine when I run it from the console using php update.php. When github initialized the file, or I run it from the browser it still does not work. Any ideas?

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  • gem5 parser error

    - by huxain
    I am trying to run parser from here, but it gives this error: This program requires jinja2 version 2.7 or later I have already installed the jinja2 package by running sudo apt-get install python-jinja2. Can anyone tell me what I'm doing wrong (with a little guide to run the tool as well)? The m5out folder is here, with the stats for a ARM core simulation, so you don't have to install gem5 to get those two files required by the script.

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  • Java Plist XML Parsing

    - by Jannis
    Hello everyone, I'm parsing a (not well formed) Apple Plist File with java. My Code looks like this: InputStream in = new FileInputStream( "foo" ); XMLInputFactory factory = XMLInputFactory.newInstance(); XMLEventReader parser = factory.createXMLEventReader( in ); while (parser.hasNext()){ XMLEvent event = parser.nextEvent(); //code to navigate the nodes } The parts I"m parsing are looking like this: <dict> <key>foo</key><integer>123</integer> <key>bar</key><string>Boom &amp; Shroom</string> </dict> My problem is now, that nodes containing a ampersand are not parsed like they should because the ampersand is representing a entity. What can i do to get the value of the node as a complete String, instead of broken parts? Thank you in advance.

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  • Android, sending XML via HTTP POST (SOAP)

    - by Intosia
    Hi, I would like to invoke a webservice via Android. I need to POST some XML to a URL via HTTP. I found this snipped for sending a POST, but i dont know how to include/add the XML data itself. public void postData() { // Create a new HttpClient and Post Header HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost("http://10.10.4.35:53011/"); try { // Add your data List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2); nameValuePairs.add(new BasicNameValuePair("Content-Type", "application/soap+xml")); httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); // Where/how to add the XML data? // Execute HTTP Post Request HttpResponse response = httpclient.execute(httppost); } catch (ClientProtocolException e) { // TODO Auto-generated catch block } catch (IOException e) { // TODO Auto-generated catch block } } This is the complete POST message that i need to imitate: POST /a8103e90-f1e3-11dd-bfdb-8b1fcff1a110 HTTP/1.1 Host: 10.10.4.35:53011 Content-Type: application/soap+xml Content-Length: 602 <?xml version='1.0' encoding='UTF-8' ?> <s12:Envelope xmlns:s12="http://www.w3.org/2003/05/soap-envelope" xmlns:wsa="http://schemas.xmlsoap.org/ws/2004/08/addressing"> <s12:Header> <wsa:MessageID>urn:uuid:fc061d40-3d63-11df-bfba-62764ccc0e48</wsa:MessageID> <wsa:Action>http://schemas.xmlsoap.org/ws/2004/09/transfer/Get</wsa:Action> <wsa:To>urn:uuid:a8103e90-f1e3-11dd-bfdb-8b1fcff1a110</wsa:To> <wsa:ReplyTo> <wsa:Address>http://schemas.xmlsoap.org/ws/2004/08/addressing/role/anonymous</wsa:Address> </wsa:ReplyTo> </s12:Header> <s12:Body /> </s12:Envelope>

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  • How to validate xml using a .dtd via a proxy and NOT using system.net.defaultproxy

    - by Lanceomagnifico
    Hi, Someone else has already asked a somewhat similar question: http://stackoverflow.com/questions/1888887/validate-an-xml-file-against-a-dtd-with-a-proxy-c-2-0/2766197#2766197 Here's my problem: We have a website application that needs to use both internal and external resources. We have a bunch of internal webservices. Requests to the CANNOT go through the proxy. If we try to, we get 404 errors since the proxy DNS doesn't know about our internal webservice domains. We generate a few xml files that have to be valid. I'd like to use the provided dtd documents to validate the xml. The dtd urls are outside our network and MUST go through the proxy. Is there any way to validate via dtd through a proxy without using system.net.defaultproxy? If we use defaultproxy, the internal webservices are busted, but the dtd validation works.# Here is what I'm doing to validate the xml right now: public static XDocument ValidateXmlUsingDtd(string xml) { var xrSettings = new XmlReaderSettings { ValidationType = ValidationType.DTD, ProhibitDtd = false }; var sr = new StringReader(xml.Trim()); XmlReader xRead = XmlReader.Create(sr, xrSettings); return XDocument.Load(xRead); } Ideally, there would be some way to assign a proxy to the XmlReader much like you can assign a proxy to the HttpWebRequest object. Or perhaps there is a way to programatically turn defaultproxy on or off? So that I can just turn it on for the call to Load the Xdocument, then turn it off again? FYI - I'm open to ideas on how to tackle this - note that the proxy is located in another domain, and they don't want to have to set up a dns lookup to our dns server for our internal webservice addresses. Cheers, Lance

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  • How to Deserialize XMLDocument to object in C#?

    - by Deepfreezed
    I have a .Net webserivce that accepts XML in string format. XML String sent into the webserivce can represent any Object in the system. I need to check the first node to figure out what object to deserialize the XML string. For this I will have to load the XML into an XMLDocument (Don't want to use RegEx or string compare). I am wondering if there is a way to Deserialize the XMLDocument/XMLNode rather that deserializing the string to save some performance? Is there going to be any performance benefit serializing the XMLNode rather that the string? Method to Load XMLDocument public void LoadFromString(String s) { m_XmlDoc = new XmlDocument(); m_XmlDoc.LoadXml(s); } Thanks

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  • Strange xml/html accent issue

    - by Ayrad
    I have an XML file that contains a message with html tags in it. The XML file is read by a java class that mails it to people. When the mail is received, the accents do not show. For example é doesn't show. I have tried &eacute; in the xml but it gives an error in eclipse saying that the entity has not been declared. I also tried simply inserting &#233; but that shows nothing in the final output. The 3rd thing I tried was using <![CDATA[é]]> but that broke the parser since it didn't output anything after it. However I noticed something weird. When i put something like this in the xml and added UTF-16 encoding <message>text bla bla blaa é&lt; it did ouput the é at the end like this bla bla blaa blaa é. EDIT <message>text bla bla blaa éé&lt; outputs ?é or just one é The file looks something like this: <?xml version="1.0"? encoding="UTF-16"> <message> &lt;b&gt;hello é &lt;/b&gt; </message> </xml> What gives?

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  • XElement Add function adds xmlns="" to the XElement

    - by JJoos
    I have a function which generates xml for a list object: public XDocument ToXML() { foreach (var row in this) { var xml = row.ToXml(); template.Root.Add(xml); } return template; } The template.ToString() reads: <RootElement xmlns="urn:testTools"> The xml reads: <Example><SubElement>testData</SubElement></Example> After the add function has executed the template.ToString() reads: <RootElement xmlns="urn:testTools"><Example xmlns=""><SubElement>testData</SubElement></Example> So for some reason there was an empty namespace added, how can i prevent it from doing so?

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  • Linq2XML not getting content of a node that contains html tags

    - by Dante
    Hi, I have an XML file that I'm trying to parse with Linq2XML. One of the nodes contains a bit of html, that I cannot retrieve. The XML resembles to: <?xml version="1.0" encoding="ISO-8859-1"?> <root> <image><img src="/Images/m1cznk4a6fh7.jpg" /></image> <contentType>Banner</contentType> </root> The code is: XDocument document = XDocument.Parse(content.XML); XElement imageElement = document.Descendants("image").SingleOrDefault(); image = imageElement.Value; // Doesn't get the content, while if I specify .Descendants("contentType") it works Any ideas? Thank you in advance

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  • XML to WordML basics

    - by Level1Coder
    I'm new to the world of XML. I'm not sure which way to build the XML so I provided 2 examples below. My question is: Given the XML, how do I transform either Example#1 / #2 to the WordML Result? What technologies do I need to accomplish this? Example#1: <NumberedList1> <Paragraph>Paragraph one.</Paragraph> </NumberedList1> Example#2: <NumberedList>1</NumberedList> <Paragraph>Paragraph one.</Paragraph> After transformation... WordML Result: <w:p> <w:pPr> <w:pStyle w:val="ListParagraph"/> <w:numPr> <w:ilvl w:val="0"/> <w:numId w:val="1"/> </w:numPr> </w:pPr> <w:r> <w:t>Paragraph one.</w:t> </w:r> </w:p> If there is a way to transform the XML to WordML, maybe I can opt to save the data in XML format in the db instead of building both XML and WordML on the fly for 2 different formats.

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  • How can I transform XML to invalid XML using XSLT?

    - by Damovisa
    I need to transform a valid XML document to the OFX v1.0.2 format. This format is more or less XML, but it's technically invalid and therefore cannot be parsed as XML. I'm having trouble getting my Xml transformation working because the .Net XslCompiledTransform object insists on interpreting the XSL as an XML document (which is fair enough). If I escape the xml-ish tags using &lt; and &gt, they get removed when I download the file. Here's the start of my XSLT: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="text"></xsl:output> <xsl:param name="currentdate"></xsl:param> <xsl:template match="Transactions"> OFXHEADER:100 DATA:OFXSGML VERSION:102 SECURITY:NONE ENCODING:USASCII CHARSET:1252 COMPRESSION:NONE OLDFILEUID:NONE NEWFILEUID:NONE <OFX> <SIGNONMSGSRSV1> <SONRS> <STATUS> <CODE>0 <SEVERITY>INFO </STATUS> <DTSERVER><xsl:value-of select="$currentdate" /> <LANGUAGE>ENG Any suggestions?

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  • How do I get a list of child elements from XDocument object?

    - by Nick
    Hello.. I am trying to get all of the "video" elements and their attributes from an XML file that looks like this: <?xml version="1.0" encoding="utf-8" ?> <videos> <video title="video1" path="videos\video1.wma"/> <video title="video2" path="videos\video2.wma"/> <video title="video3" path="videos\video3.wma"/> </videos> The following will only select the root node and all of the children. I would like to get all of the 'video' elements into the IEnumerable. Can someone tell me what I'm doing wrong? IEnumerable<XElement> elements = from xml in _xdoc.Descendants("videos") select xml; The above returns a collection with a length == 1. It contains the root element and all the children.

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  • search dataset from xml file

    - by Anelim
    Hi, I need to filter the results I obtain when I load my xml file. For example I need to search the xml data for items with keyword "Chemistry" for example. The below xml example is a summary of my xml file. The data is loaded in a gridview. Could you help? Thanks! Xml File (summary): <CONTRACTS> <CONTRACT> <CONTRACTID>779</CONTRACTID> <NAME>ContractName</NAME> <KEYWORDS>Chemistry, Engineering, Chemical</KEYWORDS> <CONTRACTSTARTDATE>1/8/2005</CONTRACTSTARTDATE> <CONTRACTENDDATE>31/7/2008</CONTRACTENDDATE> <COMMODITIES><COMMODITY><COMMODITYCODE>CHEM</COMMODITYCODE> <COMMODITYNAME>Chemicals</COMMODITYNAME></COMMODITY></COMMODITIES> </CONTRACT></CONTRACTS> My code behind code is: Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load Dim ds As DataSet = New DataSet() ds.ReadXml(AppDomain.CurrentDomain.BaseDirectory + "/testxml.xml") Dim dtContract As DataTable = ds.Tables(0) Dim dtJoinCommodities As DataTable = ds.Tables(1) Dim dtCommodity As DataTable = ds.Tables(2) dtContract.Columns.Add("COMMODITYCODE") dtContract.Columns.Add("COMMODITYNAME") Dim count As Integer = 0 Dim commodityCode As String = Nothing Dim commodityName As String = Nothing Dim dRowJoinCommodity As DataRow Dim trimChar As Char() = {","c, " "c} Dim textboxstring As String = "KEYWORDS like 'pencil'" For Each dRow As DataRow In dtContract.Select(textboxstring) commodityCode = "" commodityName = "" count = dtContract.Rows.IndexOf(dRow) dRowJoinCommodity = dtJoinCommodities.Rows(count) For Each dRowCommodities As DataRow In dtCommodity.Rows If dRowCommodities("COMMODITIES_Id").ToString() = dRowJoinCommodity("COMMODITIES_ID").ToString() Then commodityCode = commodityCode + dRowCommodities("COMMODITYCODE").ToString() + ", " commodityName = commodityName + dRowCommodities("COMMODITYNAME").ToString() + ", " End If Next commodityCode = commodityCode.TrimEnd(trimChar) commodityName = commodityName.TrimEnd(trimChar) dRow("COMMODITYCODE") = commodityCode dRow("COMMODITYNAME") = commodityName Next GridView1.DataSource = dtContract GridView1.DataBind() End Sub

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  • How to make xml in C#?

    - by kacalapy
    i have not worked with XML in a while can someone post the syntax needed to build and save an xml node structure that resembles that of a tree structure that is created by a recursive function. basically i have a recursive function that saves data found an a page(url) and then follows each URL found on that page recursivley and does the same to it. to audit this i want an output as a xml file to disk so i can see how it is doing its recursion and parsing. the code i have is below. please add to it the needed xml calls needed to create a xml structure like the one i show below. (please include the full name space so i can see where the objects i need in .net are for this.) page1.htm has 2 links on it: <a href=page1_1.htm> <a href=page1_2.htm> page1_1.htm has 2 links on it <a href=page1_1_a.htm> (this then will have some links also) <a href=page1_1_b.htm> (this then will have no more links on it - dead end) the xml should do something like this: <node url=page1.htm> ...<node url=page1_1_a.htm> ...... <node url="xxx.htm"/> ...... <node url="yyy.htm".> ... </node> ...<node url=page1_1_b.htm /> </node>

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  • XML Serialization Not Working For All Elements (C#)

    - by splatto
    I have an XML file that I'm trying to serialize into an object. Some elements are being ignored. My XML File: <?xml version="1.0" encoding="utf-8" ?> <License xmlns="http://schemas.datacontract.org/2004/07/MyApp.Domain"> <Guid>7FF07F74-CD5F-4369-8FC7-9BF50274A8E8</Guid> <Url>http://www.gmail.com</Url> <ValidKey>true</ValidKey> <CurrentDate>3/1/2010 9:39:28 PM</CurrentDate> <RegistrationDate>3/8/2010 9:39:28 PM</RegistrationDate> <ExpirationDate>3/8/2099 9:39:28 PM</ExpirationDate> </License> My class definition: [DataContract] public class License { [DataMember] public virtual int Id { get; set; } [DataMember] public virtual string Guid { get; set; } [DataMember] public virtual string ValidKey { get; set; } [DataMember] public virtual string Url { get; set; } [DataMember] public virtual string CurrentDate { get; set; } [DataMember] public virtual string RegistrationDate { get; set; } [DataMember] public virtual string ExpirationDate { get; set; } } And my Serialization attempt: XmlDocument Xmldoc = new XmlDocument(); Xmldoc.Load(string.Format(url)); string xml = Xmldoc.InnerXml; var serializer = new DataContractSerializer(typeof(License)); var memoryStream = new MemoryStream(Encoding.UTF8.GetBytes(xml)); License license = (License)serializer.ReadObject(memoryStream); memoryStream.Close(); The following elements are serialized: Guid ValidKey The following elements are not serialized: Url CurrentDate RegistrationDate ExpirationDate Replacing the string dates in the xml file with "blah" doesn't work either. What gives?

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  • AS3: Array of objects parsed from XML remains with zero length

    - by Joel Alejandro
    I'm trying to parse an XML file and create an object array from its data. The data is converted to MediaAlbum classes (class of my own). The XML is parsed correctly and the object is loaded, but when I instantiate it, the Albums array is of zero length, even when the data is loaded correctly. I don't really know what the problem could be... any hints? import Nem.Media.*; var mg:MediaGallery = new MediaGallery("test.xml"); trace(mg.Albums.length); MediaGallery class: package Nem.Media { import flash.net.URLRequest; import flash.net.URLLoader; import flash.events.*; public class MediaGallery { private var jsonGalleryData:Object; public var Albums:Array = new Array(); public function MediaGallery(xmlSource:String) { var loader:URLLoader = new URLLoader(); loader.load(new URLRequest(xmlSource)); loader.addEventListener(Event.COMPLETE, loadGalleries); } public function loadGalleries(e:Event):void { var xmlData:XML = new XML(e.target.data); var album; for each (album in xmlData.albums) { Albums.push(new MediaAlbum(album.attribute("name"), album.photos)); } } } } XML test source: <gallery <albums <album name="Fútbol 9" <photos <photo width="600" height="400" filename="foto1.jpg" / <photo width="600" height="400" filename="foto2.jpg" / <photo width="600" height="400" filename="foto3.jpg" / </photos </album <album name="Fútbol 8" <photos <photo width="600" height="400" filename="foto4.jpg" / <photo width="600" height="400" filename="foto5.jpg" / <photo width="600" height="400" filename="foto6.jpg" / </photos </album </albums </gallery

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  • Java split xml file

    - by CC
    Hi all, I'm working on a piece of code to split files. I want to split flat file (that's ok, it is working fine) and xml file. The idea is to split based of a number of files to split: I have a file, and I want to split it in x files (x is a parameters). I'm doing the split by taking the size of the file and spliting the size by the number of files to split. Then, mysolution was to use a BufferedReader and to use it like while ((n = reader.read(buffer, 0, buffer.length)) != -1) { { The main problem is that for the xml file I cannot just split it, but I have to split it based on a block delimited by a start xml tag and end xml tag: <start tag> bla bla xml stuff </end tag> So I cannot cut a block at the middle. So if when I'm at the half of a block, is the size of my new file is greater than my max, I will have to read until the end of the tag, and then, to start a next file. The problem is that I have all sort of cases, and is a bit difficult to search the end tag. - the block reads a text until the middle of the end tag - the block reads a text until the end of the end tag, and no more other caracter after - etc and in the same time to have a loop and read the next block. Some times the end of a block concatenated with the start of the next one, I have the end xml tag. I hope you get the idea. My question is, does anyone have some algorithm that does that more accurate and who i treating all special cases ? The idea is to split the file as quickly as possible. Thanks alot.

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  • Why am I getting the extra xmlns="" using LinqToXML?

    - by Hcabnettek
    Hello all, I'm using LinqToXML to generate a piece of XML. Everything works great except I'm throwing in some empty namespace declarations somehow. Does anyone out there know what I'm doing incorrectly? Here is my code private string SerializeInventory(IEnumerable<InventoryInformation> inventory) { var zones = inventory.Select(c => new { c.ZoneId , c.ZoneName , c.Direction }).Distinct(); XNamespace ns = "http://www.dummy-tmdd-address"; XNamespace xsi = "http://www.w3.org/2001/XMLSchema-instance"; var xml = new XElement(ns + "InventoryList" , new XAttribute(XNamespace.Xmlns + "xsi", xsi) , zones.Select(station => new XElement("StationInventory" , new XElement("station-id", station.ZoneId) , new XElement("station-name", station.ZoneName) , new XElement("station-travel-direction", station.Direction) , new XElement("detector-list" , inventory.Where(p => p.ZoneId == station.ZoneId).Select(plaza => new XElement("detector" , new XElement("detector-id", plaza.PlazaId))))))); xml.Save(@"c:\tmpXml\myXmlDoc.xml"); return xml.ToString(); } And here is the resulting xml. I hope it renders correctly? The browser may hide the tags. - <InventoryList xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.dummy-tmdd-address"> <StationInventory xmlns=""> <station-id>999</station-id> <station-name>Zone 999-SEB</station-name> <station-travel-direction>SEB</station-travel-direction> <detector-list> <detector> <detector-id>7503</detector-id> </detector> <detector> <detector-id>2705</detector-id> </detector> </detector-list> </StationInventory> </InventoryList> Notice the empty namespace declaration in the first child element. Any ideas how I can remedy this? Any tips are of course appreciated. Thanks All, ~ck

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  • Serialize XML child and keep namespaces in Java

    - by Guido García
    I have an Document object that is modeling a XML like this one: <RootNode xmlns="http://a.com/a" xmlns:b="http://b.com/b"> <Child /> </RootNode> Using Java DOM, I need to get the <Child> node and serialize it to XML, but keeping the root node namespaces. This is what I currently have, but it does not serialize the namespaces: public static void main(String[] args) throws Exception { String xml = "<RootNode xmlns='http://a.com/a' xmlns:b='http://b.com/b'><Child /></RootNode>"; DocumentBuilder builder = DocumentBuilderFactory.newInstance().newDocumentBuilder(); Document doc = builder.parse(new ByteArrayInputStream(xml.getBytes())); Node childNode = doc.getFirstChild().getFirstChild(); // serialize to string StringWriter sw = new StringWriter(); DOMSource domSource = new DOMSource(childNode); StreamResult streamResult = new StreamResult(sw); TransformerFactory tf = TransformerFactory.newInstance(); Transformer serializer = tf.newTransformer(); serializer.transform(domSource, streamResult); String serializedXML = sw.toString(); System.out.println(serializedXML); } Current output: <?xml version="1.0" encoding="UTF-8"?> <Child/> Expected output: <?xml version="1.0" encoding="UTF-8"?> <Child xmlns='http://a.com/a' xmlns:b='http://b.com/b' />

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