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  • PHP4: Send XML over HTTPS/POST via cURL?

    - by starmonkey
    I wrote a class/function to send xml over https via PHP4/cURL, just wondering if this is the correct approach, or if there's a better one. Note that PHP5 is not an option at present. /** * Send XML via http(s) post * * curl --header "Content-Type: text/xml" --data "<?xml version="1.0"?>...." http://www.foo.com/ * */ function sendXmlOverPost($url, $xml) { $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); // For xml, change the content-type. curl_setopt ($ch, CURLOPT_HTTPHEADER, Array("Content-Type: text/xml")); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $xml); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); // ask for results to be returned if(CurlHelper::checkHttpsURL($url)) { curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0); } // Send to remote and return data to caller. $result = curl_exec($ch); curl_close($ch); return $result; } cheers!

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  • Save a form in an XML file using Ajax and JSP

    - by novellino
    Hello, I want to create a simple form with a name and an email and save these data in an XML file. So far I found that using Ajax with jQuery is quite easy. So I used the usual code: //dataString have the values taken from the form var dataString = 'name='+ name + '&email=' + email; $.ajax({ type: "POST", url: "users.xml", data: dataString, dataType: "xml", success: function() { .... } }); If I understood well, in the url I should add the name of the XML file that will be created. When the user clicks a button I call the function with the Ajax request, and then I should call somewhere a function for generating the xml. I am using also two beans. One is for setting the elements of the user and the other is for saving the data in the XML. I am using the XStream library for the xml although I don't know if is the best solution. The problem now it that I can not connect all these together in order to save the data in the XML. Does anyone know what should I do? Thanks a lot!

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  • LINQ to XML contents of child records.

    - by Fossaw
    I have this LINQ to XML enquiry... var Records = from Item in XDoc.Root.Elements("Item") where (string)Item.Element("ItemNumber") == item.ID.ToString select Item; ... where ItemNumber is a reference number used in the XML, (originally written by this program but manually edited by "others"), and item.ID is the database version of the same thing. The query executes, and I can test for the number of entries in the result fine... if (Records.Count() < 1) ... you get the idea. I have established that there is only one record. Each Item has several child fields. I want to test the values of the child fields are reasonable before passing them on to the database update sub-system. The XML is produced by the program, but edited by users, so I need to really check what is coming back. So I tried... if (DB_English.ToString() != Records.Elements("English").ToString()) ... DB_English is from the database, but the XML in Records, does not contain the contents of that field, it contains... System.Xml.Linq.Extensions+<GetElements>d__29`1[System.Xml.Linq.XElement] ... so, how do I get the value of this element in the XML file? I need to check the field in the XML has not been altered, (the manual editors of this data file are not potentially 100% reliable).

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  • How to find/extract data from xml with jQuery

    - by darryl
    I'm trying to extract the StateLongName and StateShortName values from the xml below. I know there has to be a simple elegant way to do this with jQuery. <NewDataSet> <Table> <StateLongName>Alabama</StateLongName> <StateShortName>AL</StateShortName> </Table> <Table> <StateLongName>Alaska</StateLongName> <StateShortName>AK</StateShortName> </Table> ...elments removed for brevity </NewDataSet> Here's what I've tried. Load the xml from above into a Javascript variable name xml. Try #1 $(xml).find("TABLE").each(function() { var stateName = $(this).find("StateLongName").innerText; var stateCode = $(this).find("StateShortName").innerText; }); Try #1 doesn't find anything and never goes inside to load the stateName and stateCode variables. Try #2 $(xml).find("StateLongName").each(function() { var stateName = $(this).find("StateLongName").innerText; var stateCode = $(this).find("StateShortName").innerText; }); Try #2 does find matches, however the stateName and stateCode are left undefined. Try #3 $(xml).find("StateLongName").each(function() { var stateName = $($(xml).find('StateLongName').parent()[0].innerHTML)[1].data; var stateCode = $($(xml).find('StateLongName').parent()[0].innerHTML)[5].data; }); Try #3 works but there has to be a better way. Please enlighten me. Thanks for you time!

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  • Idiomatic way to build a custom structure from XML zipper in Clojure

    - by Checkers
    Say, I'm parsing an RSS feed and want to extract a subset of information from it. (def feed (-> "http://..." clojure.zip/xml-zip clojure.xml/parse)) I can get links and titles separately: (xml-> feed :channel :item :link text) (xml-> feed :channel :item :title text) However I can't figure out the way to extract them at the same time without traversing the zipper more than once, e.g. (let [feed (-> "http://..." clojure.zip/xml-zip clojure.xml/parse)] (zipmap (xml-> feed :channel :item :link text) (xml-> feed :channel :item :title text))) ...or a variation of thereof, involving mapping multiple sequences to a function that incrementally builds a map with, say, assoc. Not only I have to traverse the sequence multiple times, the sequences also have separate states, so elements must be "aligned", so to speak. That is, in a more complex case than RSS, a sub-element may be missing in particular element, making one of sequences shorter by one (there are no gaps). So the result may actually be incorrect. Is there a better way or is it, in fact, the way you do it in Clojure?

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  • ajax html vs xml/json responses - perfomance or other reasons

    - by pedalpete
    I've got a fairly ajax heavy site and some 3k html formatted pages are inserted into the DOM from ajax requests. What I have been doing is taking the html responses and just inserting the whole thing using jQuery. My other option is to output in xml (or possibly json) and then parse the document and insert it into the page. I've noticed it seems that most larger site do things the json/xml way. Google Mail returns xml rather than formatted html. Is this due to performance? or is there another reason to use xml/json vs just retrieving html? From a javascript standpoint, it would seem injecting direct html is simplest. In jQuery I just do this jQuery.ajax({ type: "POST", url: "getpage.php", data: requestData, success: function(response){ jQuery('div#putItHear').html(response); } with an xml/json response I would have to do jQuery.ajax({ type: "POST", url: "getpage.php", data: requestData, success: function(xml){ $("message",xml).each(function(id) { message = $("message",xml).get(id); $("#messagewindow").prepend(""+$("author",message).text()+ ": "+$("text",message).text()+ ""); }); } }); clearly not as efficient from a code standpoint, and I can't expect that it is better browser performance, so why do things the second way?

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  • Transform RSS-Feed into another "standard" XML-Format with PHP

    - by ChrisBenyamin
    Hey friends, quick question: I need to transform a default RSS Structure into another XML-format. The RSS File is like.... Name des RSS Feed Feed Beschreibung de http://xml-rss.de Sat, 1 Jan 2000 00:00:00 GMT Titel der Nachricht Die Nachricht an sich http://xml-rss.de/link-zur-nachricht.htm Sat, 1. Jan 2000 00:00:00 GMT 01012000-000000 Titel der Nachricht Die Nachricht an sich http://xml-rss.de/link-zur-nachricht.htm Sat, 1. Jan 2000 00:00:00 GMT 01012000-000000 Titel der Nachricht Die Nachricht an sich http://xml-rss.de/link-zur-nachricht.htm Sat, 1. Jan 2000 00:00:00 GMT 01012000-000000 ...and I want to extract only the item-elements (with childs and attributes) XML like: <?xml version="1.0" encoding="ISO-8859-1"?> <item> <title>Titel der Nachricht</title> <description>Die Nachricht an sich</description> <link>http://xml-rss.de/link-zur-nachricht.htm</link> <pubDate>Sat, 1. Jan 2000 00:00:00 GMT</pubDate> <guid>01012000-000000</guid> </item> ... It hasn't to be stored into a file. I need just the output. I tried different approaches with DOMNode, SimpleXML, XPath, ... but without success. Thanks chris

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  • C# XML export for Excel table using XmlDocument

    - by Mark
    I am trying to write the following into an XML document: <head> <xml> <x:ExcelWorkbook> <x:ExcelWorksheets> <x:ExcelWorksheet> other code here </x:ExcelWorksheet> </x:ExcelWorksheets> </x:ExcelWorkbook> </xml> </head> However, if I use the following code, it strips out the 'x:'. System.Xml.XmlDocument document = new System.Xml.XmlDocument(); System.Xml.XmlElement htmlNode = document.CreateElement("html"); htmlNode.SetAttribute("xmlns:o", "urn:schemas-microsoft-com:office:office"); htmlNode.SetAttribute("xmlns:x", "urn:schemas-microsoft-com:office:excel"); htmlNode.SetAttribute("xmlns", "http://www.w3.org/TR/REC-html40"); document.AppendChild(htmlNode); System.Xml.XmlElement headNode = document.CreateElement("head"); htmlNode.AppendChild(headNode); headNode.AppendChild( document.CreateElement("xml")).AppendChild( document.CreateElement("x:ExcelWorkbook"))).AppendChild( document.CreateElement("x:ExcelWorksheets")).AppendChild( document.CreateElement("x:ExcelWorksheet")).InnerText="other code here"; How can I stop this from happening? Thanks!

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  • How to check if a node's value in one XML is present in another XML with a specific attribute?

    - by Manish
    The question seems to be little confusing. So let me describe my situation through an example: Suppose I have an XML: A.xml <Cakes> <Cake>Egg</Cake> <Cake>Banana</Cake> </Cakes> Another XML: B.xml <Cakes> <Cake show="true">Egg</Cake> <Cake show="true">Strawberry</Cake> <Cake show="false">Banana</Cake> </Cakes> Now I want to show some text say "TRUE" if all the Cake in A.xml have show="true" in B.xml else "FALSE". In the above case, it will print FALSE. I need to develop an XSL for that. I can loop through all the Cake in A.xml and check if that cake has show="true" in B.xml but I don't know how to break in between (and set a variable) if a show="false" is found. Is it possible? Any help/comments appreciated.

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  • Having trouble parsing XML with jQuery

    - by Jack
    Hi Guys, I'm trying to parse some XML data using jQuery, and as it stands I have extracted the 'ID' attribute of the required nodes and stored them in an array, and now I want to run a loop for each array member and eventually grab more attributes from the notes specific to each ID. The problem currently is that once I get to the 'for' loop, it isn't looping, and I think I may have written the xml path data incorrectly. It runs once and I recieve the 'alert(arrayIds.length);' only once, and it only loops the correct amount of times if I remove the subsequent xml path code. Here is my function: var arrayIds = new Array(); $(document).ready(function(){ $.ajax({ type: "GET", url: "question.xml", dataType: "xml", success: function(xml) { $(xml).find("C").each(function(){ $("#attr2").append($(this).attr('ID') + "<br />"); arrayIds.push($(this).attr('ID')); }); for (i=0; i<arrayIds.length; i++) { alert(arrayIds.length); $(xml).find("C[ID='arrayIds[i]']").(function(){ // pass values alert('test'); }); } } }); }); Any ideas?

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  • Multiple XML/XSLT files in PHP, transform one with XSLT and add others but process it first with PHP

    - by ipalaus
    I am processing XML files transformations with XSLT in PHP correctly. Actually I use this code: $xml = new DOMDocument; $xml->LoadXML($xml_contents); $xsl = new DOMDocument; $xsl->load($xsl_file); $proc = new XSLTProcesoor; $proc->importStyleSheet($xsl); echo $proc->transformToXml($xml); $xml_contents is the XML processed with PHP, this is done by including the XML file first and then assigning $xml_contents = ob_get_contents(); ob_end_clean();. This forces to process the PHP code on the XML, and it works perfectly. My problem is that I use more than one XML file and this XML files has PHP code on it that need to be processed AND have a XSLT file associated to process the data. Actually I'm including this files in XSLT with the next code: <!-- First I add the XML file --> <xsl:param name="menu" select="document('menu.xml')" /> <!-- Next I add the transformations for menu.xml file --> <xsl:include href="menu.xsl" /> <!-- Finally, I process it on the actual ("parent") XML --> <xsl:apply-templates select="$menu/menu" /> My questiion is how I can handle this. I need to add mutiple XML(+XSLT) files to my first XML file that will containt PHP so it needs to be processed. Thank you in advance!

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  • How to make restrictions on XML Schema Complex type?

    - by chobo2
    Hi I am reading the tutorials on w3cschools ( http://www.w3schools.com/schema/schema_complex.asp ) but they don't seem to mention how you could add restrictions on complex types. Like for instance I have this schema. <xs:element name="employee"> <xs:complexType> <xs:sequence> <xs:element name="firstname" type="xs:string"/> <xs:element name="lastname" type="xs:string"/> </xs:sequence> </xs:complexType> </xs:element> now I want to make sure the firstname is no more then 10 characters long. How do I do this? I tried to put in the simple type for the firstname but it says I can't do that since I am using a complex type. So how do I put restrictions like that on the file so the people who I give the schema to don't try to make the firstname 100 characters.

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  • Webserver directory index: index.xml?

    - by Marius
    Hello there, I am making my first RSS-Feed, and I want to host it like this: www.example.com/rss/ I tried to name the xml-file "index.xml" and place it inside the directory, however, when I type http://www.example.com/rss/ i arrive at "Index of /rss" where the file is listed as being part of the directory, but it is not loaded automatically. What can be done about this? Thank you for your time. Kind regards, Marius

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  • Displaying XML in Chrome Browser

    - by Josh
    I love the Chrome browser but I use XML quite a lot in my development work and when I view it in Chrome I just get the rendered text. I know that the source view is slightly better but I'd really like to see the layout and functionality that IE adds to XML namely: Highlighting Open/close nodes Any ideas how I can get this on Chrome? Thanks, Josh UPDATE: The XMLTree Extension is available on Google Chrome Extension Beta Site. Thanks again for your help.

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  • Retrieve MS SQL database or table struture in XML

    - by clutch
    Is there a way to export the database schema in well formed XML of a MS 2000 SQL Server. I'm looking for just the structure not the data and the more detailed the better. The XML may be used in a migration processes. I'm more familiar with MySQL then with SQL Server so please be detailed if you hav time. Thanks

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  • Search in multiple xml files

    - by Ram
    I have a windows Xp Sp2 system where the windows explorer search is not able to find the text in xml files. Is there some setting that enable the search in xml files? It finds in text in text / doc files in the same folder.

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  • Notepad++ Reindent XML breaks lines.

    - by C. Ross
    I'm attempting to use Notepad++ TextFX HTMLTidy - Tidy: Reindent XML. This works well with the following exception. Lines longer than 70 character are wrapped, breaking the validity of my xml. This: <RevieweeDepartmentName>BB AAAAAAAAAA AAAAAAAAAA AAAA</RevieweeDepartmentName> Becomes this: <RevieweeDepartmentName>BB AAAAAAAAAA AAAAAAAAAA AAAA</RevieweeDepartmentName> How can I get it to stop this behavior?

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  • Retrieve MS SQL database or table structure in XML

    - by clutch
    Is there a way to export the database schema in well formed XML of a MS 2000 SQL Server. I'm looking for just the structure not the data and the more detailed the better. The XML may be used in a migration processes. I'm more familiar with MySQL then with SQL Server so please be detailed if you have time. Thanks

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  • GWT simple form validation example

    - by nablik
    Hi, I'm looking for nice and fast way for validating forms in GWT, that can display errors one by one, focusing on the offending field. I've found gwt-validator and gwt-validation, but their documentation lack of examples. Thanks for help

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  • MVC2 Client validation with Annotations in View with RenderAction

    - by Olle
    I'm having problem with client side validation on a View that renders a dropdownlist with help of a Html.RenderAction. I have two controllers. SpecieController and CatchController and I've created ViewModels for my views. I want to keep it as DRY as possible and I will most probably need a DropDownList for all Specie elsewhere in the near future. When I create a Catch i need to set a relationship to one specie, I do this with an id that I get from the DropDownList of Species. ViewModels.Catch.Create [Required] public int Length { get; set; } [Required] public int Weight { get; set; } [Required] [Range(1, int.MaxValue)] public int SpecieId { get; set; } ViewModels.Specie.List public DropDownList(IEnumerable<SelectListItem> species) { this.Species = species; } public IEnumerable<SelectListItem> Species { get; private set; } My View for the Catch.Create action uses the ViewModels.Catch.Create as a model. But it feels that I'm missing something in the implemetation. What I want in my head is to connect the selected value in the DropDownList that comes from the RenderAction to my SpecieId. View.Catch.Create <div class="editor-label"> <%: Html.LabelFor(model => model.SpecieId) %> </div> <div class="editor-field"> <%-- Before DRY refactoring, works like I want but not DRY <%: Html.DropDownListFor(model => model.SpecieId, Model.Species) %> --%> <% Html.RenderAction("DropDownList", "Specie"); %> <%: Html.ValidationMessageFor(model => model.SpecieId) %> </div> CatchController.Create [HttpPost] public ActionResult Create(ViewModels.CatchModels.Create myCatch) { if (ModelState.IsValid) { // Can we make this StronglyTyped? int specieId = int.Parse(Request["Species"]); // Save to db Catch newCatch = new Catch(); newCatch.Length = myCatch.Length; newCatch.Weight = myCatch.Weight; newCatch.Specie = SpecieService.GetById(specieId); newCatch.User = UserService.GetUserByUsername(User.Identity.Name); CatchService.Save(newCatch); } This scenario works but not as smooth as i want. ClientSide validation does not work for SpecieId (after i refactored), I see why but don't know how I can ix it. Can I "glue" the DropDownList SelectedValue into myCatch so I don't need to get the value from Request["Species"] Thanks in advance for taking your time on this.

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