Search Results

Search found 31253 results on 1251 pages for 'custom url'.

Page 351/1251 | < Previous Page | 347 348 349 350 351 352 353 354 355 356 357 358  | Next Page >

  • Problem in JsonResult

    - by Saravanan I M
    I am using the jsonresult for listing all the cities under a country. I retrieve the data from database and load it to a dropdown list using jquery. The problem is if the cities goes beyond 3000 then the jsonresult is not working. <script type="text/javascript"> $(document).ready(function () { //Hook onto the MakeID list's onchange event $("#Country").change(function () { //build the request url $("#HomeTown").empty(); var url = '<%= Url.Content("~/") %>' + "Location/GetCitiesByCountry/" + $("#Country").val(); $.getJSON(url, function (data) { $.each(data, function (index, optionData) { $("#HomeTown").append("<option value='" + optionData.geonameid + "'>" + optionData.asciiname + "</option>"); }); $("#HomeTown").option[0].selected = true; }); }).change(); }); </script>

    Read the article

  • Troubleshooting FORM POST problems

    - by brettr
    I'm using the following code to submit to a WCF service. I keep getting an error that the key is invalid. I have a webpage on the same server that I submit the same data (but different key) using a FORM POST. It works fine that way. I put the URL below all in a URL (including valid key from server webpage) and get the key is invalid error. I'm thinking the data I'm submitting through the iPhone isn't really going across as a FORM POST but rather as a URL. Is there anything I may be doing wrong in the following code or any other suggestions? NSString *stringForURL = @"https://abc.com/someservice.aspx"; NSURL *URL=[[NSURL alloc] initWithString:stringForURL]; NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:URL]; NSString *request_body = [NSString stringWithFormat:@"prop1=value1&key=%@", [@"r2xHEuzgDTQEWA5Xe6+k9BSVrgsMX2mWQBW/39nqT4s=" stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]]; NSData *postData = [request_body dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES]; NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setHTTPMethod:@"POST"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; [request setHTTPBody:postData]; NSURLConnection *connection = [[NSURLConnection alloc] initWithRequest:request delegate:self]; [NSThread sleepForTimeInterval:1]; self.receivedData = [[NSMutableData data] retain];

    Read the article

  • How to do google webpage translate in a Java class

    - by Robert
    Hi,this is a follow-up question of mine. Suppose now I have a URL : http://www.baidu.com/s?bs=%B0%C2%B0%CD%C2%ED&f=8&wd=%B0%C2%B0%CD%C2%ED and it work perfectly by inputting it in the text field of google translate and select from "Chinese" to English. My question is ,suppose now I want to achieve this in Java, I would like to adopt "Process q=Runtime.getRuntime().exec( "cmd /c start +URL" approach to do this. Could I achieve that by simply concatenating the Google translate URL and the webpage URL? If yes,could you please elaborte,thanks.

    Read the article

  • NullPointerException, Collections not storing data?

    - by Elliott
    Hi there, I posted this question earlier but not with the code in its entirety. The coe below also calls to other classes Background and Hydro which I have included at the bottom. I have a Nullpointerexception at the line indicate by asterisks. Which would suggest to me that the Collections are not storing data properly. Although when I check their size they seem correct. Thanks in advance. PS: If anyone would like to give me advice on how best to format my code to make it readable, it would be appreciated. Elliott package exam0607; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStream; import java.io.InputStreamReader; import java.net.URL; import java.util.Collection; import java.util.Scanner; import java.util.Vector; import exam0607.Hydro; import exam0607.Background;// this may not be necessary???? FIND OUT public class HydroAnalysis { public static void main(String[] args) { Collection hydroList = null; Collection backList = null; try{hydroList = readHydro("http://www.hep.ucl.ac.uk/undergrad/3459/exam_data/2006-07/final/hd_data.dat");} catch (IOException e){ e.getMessage();} try{backList = readBackground("http://www.hep.ucl.ac.uk/undergrad/3459/exam_data/2006-07/final/hd_bgd.dat"); //System.out.println(backList.size()); } catch (IOException e){ e.getMessage();} for(int i =0; i <=14; i++ ){ String nameroot = "HJK"; String middle = Integer.toString(i); String hydroName = nameroot + middle + "X"; System.out.println(hydroName); ALGO_1(hydroName, backList, hydroList); } } public static Collection readHydro(String url) throws IOException { URL u = new URL(url); InputStream is = u.openStream(); InputStreamReader isr = new InputStreamReader(is); BufferedReader b = new BufferedReader(isr); String line =""; Collection data = new Vector(); while((line = b.readLine())!= null){ Scanner s = new Scanner(line); String name = s.next(); System.out.println(name); double starttime = Double.parseDouble(s.next()); System.out.println(+starttime); double increment = Double.parseDouble(s.next()); System.out.println(+increment); double p = 0; double nterms = 0; while(s.hasNextDouble()){ p = Double.parseDouble(s.next()); System.out.println(+p); nterms++; System.out.println(+nterms); } Hydro SAMP = new Hydro(name, starttime, increment, p); data.add(SAMP); } return data; } public static Collection readBackground(String url) throws IOException { URL u = new URL(url); InputStream is = u.openStream(); InputStreamReader isr = new InputStreamReader(is); BufferedReader b = new BufferedReader(isr); String line =""; Vector data = new Vector(); while((line = b.readLine())!= null){ Scanner s = new Scanner(line); String name = s.next(); //System.out.println(name); double starttime = Double.parseDouble(s.next()); //System.out.println(starttime); double increment = Double.parseDouble(s.next()); //System.out.println(increment); double sum = 0; double p = 0; double nterms = 0; while((s.hasNextDouble())){ p = Double.parseDouble(s.next()); //System.out.println(p); nterms++; sum += p; } double pbmean = sum/nterms; Background SAMP = new Background(name, starttime, increment, pbmean); //System.out.println(SAMP); data.add(SAMP); } return data; } public static void ALGO_1(String hydroName, Collection backgs, Collection hydros){ //double aMin = Double.POSITIVE_INFINITY; //double sum = 0; double intensity = 0; double numberPN_SIG = 0; double POSITIVE_PN_SIG =0; //int numberOfRays = 0; for(Hydro hd: hydros){ System.out.println(hd.H_NAME); for(Background back : backgs){ System.out.println(back.H_NAME); if(back.H_NAME.equals(hydroName)){//ERROR HERE double PN_SIG = Math.max(0.0, hd.PN - back.PBMEAN); numberPN_SIG ++; if(PN_SIG 0){ intensity += PN_SIG; POSITIVE_PN_SIG ++; } } } double positive_fraction = POSITIVE_PN_SIG/numberPN_SIG; if(positive_fraction < 0.5){ System.out.println( hydroName + "is faulty" ); } else{System.out.println(hydroName + "is not faulty");} System.out.println(hydroName + "has instensity" + intensity); } } } THE BACKGROUND CLASS package exam0607; public class Background { String H_NAME; double T_START; double DT; double PBMEAN; public Background(String name, double starttime, double increment, double pbmean) { name = H_NAME; starttime = T_START; increment = DT; pbmean = PBMEAN; }} AND THE HYDRO CLASS public class Hydro { String H_NAME; double T_START; double DT; double PN; public double n; public Hydro(String name, double starttime, double increment, double p) { name = H_NAME; starttime = T_START; increment = DT; p = PN; } }

    Read the article

  • Solr Multicore Admin Problem

    - by Daniel M
    Im trying to add a url based security constraint to solr deployed in websphere 6.1. If I specify the core name in the url of the constraint then the admin url for that core gives a 404. Has anyone had any success with this or any suggestions? Cheers

    Read the article

  • iPhone Google Maps KML Search

    - by satyam
    I'm using Google maps with KML Query. But my query string is "Japanese" string "??????" I'm using http://maps.google.co.jp. When requesting data, I'm getting "0" bytes. But the same query when I put in browser, its download a KML file. My code is as follows: query = [NSString stringWithFormat:@"http://maps.google.co.jp/maps?&near=%f,%f&q=??????&output=kml&num=%d", lat,lon, num]; NSURL* url = [NSURL URLWithString:query]; NSURLRequest* request = [NSURLRequest requestWithURL:url]; NSLog(@"Quering URL = %@", url); NSHTTPURLResponse *response = [[NSHTTPURLResponse alloc] autorelease]; NSData *myData = [NSURLConnection sendSynchronousRequest:request returningResponse: &response error: nil ]; NSInteger errorcode = [response statusCode]; I'm receiving "myData" with 0 bytes. why?

    Read the article

  • RegEx, matching if not containing...

    - by Tommy Jakobsen
    I've been trying to figure out how to write this regular expression. It is to be used for ISAPI_Rewrite, a module for IIS 6, for doing URL rewriting. I want the url /hg/<parameter> to be mathed, so it can be rewrited to /hg/hgwebdir.cgi/<parameter>. I've matched it using ^/hg/(.*). My problem is, if the URL /hg/hgwebdir.cgi/<parameter> is used, the regex should NOT match. Using the above regex with this URL, will rewrite to /hg/hgwebdig.cgi/hgwebdig.cgi/<parameter> which is not correct. Can you help me create the matching pattern?

    Read the article

  • How to receive userinfo with google adwords api libraries

    - by PatrickvKleef
    I'm using the Google Adwords API libraries and I would like to receive the userinfo of the logged in user. I added the userinfo scope as followed: googleAdwordsUser = new AdWordsUser(); string oauth_callback_url = HttpContext.Current.Request.Url.GetLeftPart(UriPartial.Path); googleAdwordsUser.OAuthProvider = new AdsOAuthNetProvider("https://adwords-sandbox.google.com/api/adwords/ https://www.googleapis.com/auth/userinfo.email", oauth_callback_url, Session.SessionID); When the callback url is called, I'm trying to get the users emailaddress, but it isn't working, the error 'The remote server returned an error: (401) Unauthorized.' is thrown. string url = @"https://www.googleapis.com/oauth2/v2/userinfo?access_token=" + token; HttpWebRequest objRequest = (HttpWebRequest)WebRequest.Create(url); objRequest.Method = "GET"; HttpWebResponse objResponse = (HttpWebResponse)objRequest.GetResponse(); string result = string.Empty; using (StreamReader sr = new StreamReader(objResponse.GetResponseStream())) { result = sr.ReadToEnd(); } Does somebody knows how to fix this? Thanks.

    Read the article

  • How to call Twiter's Streaming/Filter Feed with urllib2/httplib?

    - by Simon
    Update: I switched this back from answered as I tried the solution posed in cogent Nick's answer and switched to Google's urlfetch: logging.debug("starting urlfetch for http://%s%s" % (self.host, self.url)) result = urlfetch.fetch("http://%s%s" % (self.host, self.url), payload=self.body, method="POST", headers=self.headers, allow_truncated=True, deadline=5) logging.debug("finished urlfetch") but unfortunately finished urlfetch is never printed - I see the timeout happen in the logs (it returns 200 after 5 seconds), but execution doesn't seem tor return. Hi All- I'm attempting to play around with Twitter's Streaming (aka firehose) API with Google App Engine (I'm aware this probably isn't a great long term play as you can't keep the connection perpetually open with GAE), but so far I haven't had any luck getting my program to actually parse the results returned by Twitter. Some code: logging.debug("firing up urllib2") req = urllib2.Request(url="http://%s%s" % (self.host, self.url), data=self.body, headers=self.headers) logging.debug("called urlopen for %s %s, about to call urlopen" % (self.host, self.url)) fobj = urllib2.urlopen(req) logging.debug("called urlopen") When this executes, unfortunately, my debug output never shows the called urlopen line printed. I suspect what's happening is that Twitter keeps the connection open and urllib2 doesn't return because the server doesn't terminate the connection. Wireshark shows the request being sent properly and a response returned with results. I tried adding Connection: close to my request header, but that didn't yield a successful result. Any ideas on how to get this to work? thanks -Simon

    Read the article

  • Zend Framework cleaning default routes when adding other

    - by Renato Aquino
    I have the following problem with Zend Framework. My project has several controllers like Video,Category and Post. The VideoController has an Action called categorylist, so the default URL/Route becomes /video/categorylist Since the action requires 3 parameters I whant to add one simple route: $router->addRoute( 'categorylist', new Zend_Controller_Router_Route('categorylist/:category/:page/:per_page', array('controller' => 'video', 'action' => 'categorylist','page'=>1,'per_page'=>6,'category'=>1)) ); With this I got my URL like www.siteurl.com/categorylist/42/1/6 but, the View Helper URL got crazy, and every url for the other controllers I try to echo it´s redirected to the categorylist route. So when I try this: <?= $this->url(array("controller"=> "video", "action" =>"view",'category'=>1),null,true)?> The expected result its /video/view/category/1, but I got /categorylit only. I tryied to debug the default routes but I got an empty array. print_r($ctrl->getRouter()->getRoutes()); Does anyone have some clue about this wierd behavior? I´m using Zend Framework Version 1.9.7

    Read the article

  • Accessing Virtual Host from outside LAN

    - by Ray
    I'm setting up a web development platform that makes things as easy as possible to write and test all code on my local machine, and sync this with my web server. I setup several virtual hosts so that I can access my projects by typing in "project" instead of "localhost/project" as the URL. I also want to set this up so that I can access my projects from any network. I signed up for a DYNDNS URL that points to my computer's IP address. This worked great from anywhere before I setup the virtual hosts. Now when I try to access my projects by typing in my DYNDNS URL, I get the 403 Forbidden Error message, "You don't have permission to access / on this server." To setup my virtual hosts, I edited two files - hosts in the system32/drivers/etc folder, and httpd-vhosts.conf in the Apache folder of my WAMP installation. In the hosts file, I simply added the server name to associate with 127.0.0.1. I added the following to the http-vhosts.conf file: <VirtualHost *:80> ServerAdmin webmaster@localhost DocumentRoot "c:/wamp/www/ladybug" ServerName ladybug ErrorLog "logs/your_own-error.log" CustomLog "logs/your_own-access.log" common </VirtualHost> <VirtualHost *:80> ServerAdmin webmaster@localhost DocumentRoot "c:/wamp/www" ServerName localhost ErrorLog "logs/localhost-error.log" CustomLog "logs/localhost-access.log" common </VirtualHost> Any idea why I can't access my projects from typing in my DYNDNS URL? Also, is it possible to setup virtual hosts so that when I type in http://projects from a random computer outside of my network, I access url.dyndns.info/projects (a.k.a. my WAMP projects on my home computer)? Help is much appreciated, thanks!

    Read the article

  • java connectivity with mysql error

    - by abson
    I just started with the connectivity and tried this example. I have installed the necessary softwares. Also copied the jar file into the /ext folder.Yet the code below has the following error import java.sql.*; public class Jdbc00 { public static void main(String args[]){ try { Statement stmt; Class.forName("com.mysql.jdbc.Driver"); String url = "jdbc:mysql://localhost:3306/mysql" DriverManager.getConnection(url,"root", "root"); //Display URL and connection information System.out.println("URL: " + url); System.out.println("Connection: " + con); //Get a Statement object stmt = con.createStatement(); //Create the new database stmt.executeUpdate( "CREATE DATABASE JunkDB"); stmt.executeUpdate( "GRANT SELECT,INSERT,UPDATE,DELETE," + "CREATE,DROP " + "ON JunkDB.* TO 'auser'@'localhost' " + "IDENTIFIED BY 'drowssap';"); con.close(); }catch( Exception e ) { e.printStackTrace(); }//end catch }//end main }//end class Jdbc00 But it gave the following error D:\Java12\Explore>java Jdbc00 java.lang.ClassNotFoundException: com.mysql.jdbc.Driver at java.net.URLClassLoader$1.run(Unknown Source) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at sun.misc.Launcher$AppClassLoader.loadClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Unknown Source) at Jdbc11.main(Jdbc00.java:11) Could anyone please guide me in correcting this?

    Read the article

  • dialing on iphone/ipod touch not working with documented procedures

    - by dave
    I'm trying to set up an iphone app to the phone number of a various sports store using the tel:// url passing method- I am developing on an ipod touch- usually on the touch you see the error message "Unsupported URL - This URL wasn't loaded tel://99887766" when you try and dial a number. I cant get this message to appear on the simulator or the ipod touch. do I need to do some sort of fancy signing before the app will dial properly? I am using this code: [[UIApplication sharedApplication] openURL:[NSURL URLWithString:[NSString stringWithFormat:@"tel:%@", [selectedBar phoneNumber]]]]; and I've tried adding the slashes: [[UIApplication sharedApplication] openURL:[NSURL URLWithString:[NSString stringWithFormat:@"tel://%@", [selectedBar phoneNumber]]]]; but neither work. I have also tried this way: [[UIApplication application] openURL:[NSURL URLWithString:@"tel://99887766"]]; and this way: NSMutableString *phone = [[@"+ 12 34 567 89 01" mutableCopy] autorelease]; [phone replaceOccurrencesOfString:@" " withString:@"" options:NSLiteralSearch range:NSMakeRange(0, [phone length])]; [phone replaceOccurrencesOfString:@"(" withString:@"" options:NSLiteralSearch range:NSMakeRange(0, [phone length])]; [phone replaceOccurrencesOfString:@")" withString:@"" options:NSLiteralSearch range:NSMakeRange(0, [phone length])]; NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"tel:%@", phone]]; [[UIApplication sharedApplication] openURL:url]; No matter what i do i can't get any response from the simulator / ipod touch that it is dealing with a phone number- When I press the button associated with this code, it doesnt crash, it's like its processed it and decided not to do anything. i even put an NSLog(@"button called"); in just before the code to confirm the button was working, which it is.

    Read the article

  • Will rel=canonical break site: queries ?

    - by Justin Grant
    Our company publishes our software product's documentation using a custom-built content management system using a dynamic URL namespace like this: http://ourproduct.com/documentation/version/pageid Where "version" is the version number to which the documentation applies, and "pageid" is a unique string which identifies that page in our back-end content management system. For example, if content (e.g. a page about configuration best practices) is unchanged from version 3.0 and 4.0 of our product, it'd be reachable by two different URLs: http://ourproduct.com/documentation/3.0/configuration-best-practices http://ourproduct.com/documentation/4.0/configuration-best-practices This URL scheme allows us to scope Google search results to see only documentaiton for a particular product version, like this: configuration site:ourproduct.com/documentation/4.0 But when the user is searching across all versions, we don't want Google to arbitrarily choose one of the URLs to show in results. Instead, we always want the latest version to show up. Hence our planned use of rel=canonical so we can proscriptively tell Google which URL we want to show up if multiple versions are being searched. (Users who do oddball things like searching 2 versions but not all of them are a corner case, so we don't care which version(s) show up in that case-- the primary use-cases we care about is searching one version or searching all versions) But what will happen to scoped searches if we do this? If my rel=canonical URL points to version 4.0, but my search is scoped to 3.0, will Google return a result? Even if you don't know the answer offhand, do you know a site which uses rel=canonical to redirect across folders in a URL namespace. If so, I could run a few Google searches and figure out the answer.

    Read the article

  • Ie7 float problems and hiperlinks problems

    - by Uffo
    Markup <ul class="navigation clearfix"> <li class="navigation-top"></li> <div class="first-holder" style="height:153px;"> <dl class="hold-items clearfix"> <dd class="clearfix with"><a href="http://site.com" title="Protokoll">Protokoll</a></dd> <dd class="with-hover"><a href="http://site.com" title="Mein/e Unternehmen">Mein/e Unternehmen</a></dd> <dd class="with"><a class="face-me" href="http://site.com" title="Erweiterte Suche">Erweiterte Suche</a></dd> <dd class="with"><a href="http://site.com" title="Abmelden">Abmelden</a></dd> </dl> </div><!--[end] /.first-holder--> <li class="navigation-bottom"></li> </ul><!--[end] /.navigation--> Css: .first-holder{height:304px;position:relative;width:178px;overflow:hidden;margin-bottom:0px;padding-bottom: 0px;} .hold-items{top:0px;position:absolute;} .navigation dd.with{line-height:38px;background:url('/images/sprite.png') no-repeat -334px -46px;width:162px;height:38px;padding-bottom:0px;overflow: hidden;} .navigation dd.with a{position:relative;outline:0;display:block;font-weight:bold;color:#3f78c0;padding-left:10px;line-height:38px;} .with-hover{background:url('/images/sprite.png') no-repeat -505px -47px;width:178px;height:38px;line-height:38px;overflow:none;} .with-hover a{position:relative;display:block;font-weight:bold;color:#fff;padding-left:10px} .navigation-top{background:url('/images/sprite.png') no-repeat -694px -46px;width:160px;height:36px;} .navigation-top a{display:block;outline:0;height:20px;padding-top:18px;padding-left:138px;} .navigation-top a span{display:block;background:url('/images/sprite.png') no-repeat -212px -65px;width:8px;height:6px;} .navigation-bottom{background:url('/images/sprite.png') no-repeat -784px -402px;width:160px;height:37px;} .navigation-bottom a{display:block;outline:0;height:20px;padding-top:18px;padding-left:138px;} .navigation-bottom a span{display:block;background:url('/images/sprite.png') no-repeat -212px -74px;width:8px;height:6px;} Also the links, are not clickable, if I click on a link in IE7 it doesn't do the action..it doesn't redirect me to the location. This is how it looks in IE7: http://screencast.com/t/MGY4NjljZjc This is how it look in IE8,Firefox,Chrome and so on http://screencast.com/t/MzhhMDQ1M What I'm doing wrong PS: .navigation-top a span and .navigation-bottom a span I'm using some where else, but that it's ok it works fine.

    Read the article

  • Validate uniqueness within a recent set

    - by Matchu
    Is there a standard Rails 3 way of detecting uniqueness within a particular scope, or is this custom validation all I can do? class Post < ActiveRecord::Base # [named scope for recent posts] validates do |post| if Post.recent.where('url = ?', post.url).count > 0 errors[:url] = 'has already been posted recently - thanks anyway!' end end end (Haven't yet tried that exact code, so there may be errors, but you get the idea.)

    Read the article

  • Play wave file using AudioFormat in java

    - by angelina
    Dear all, I m getting following exception while running my code on linux operating system.This code works fine on windows operating system.below is the exception and code used. java.lang.IllegalArgumentException: No line matching interface Clip supporting format PCM_SIGNED unknown sample rate, 16 bit, stereo, 4 bytes/frame, big-endian is supported. AudioFormat format = sourceaudio.getFormat(); format = new AudioFormat( AudioFormat.Encoding.PCM_SIGNED, format.getSampleRate(), format.getSampleSizeInBits() * 2, format.getChannels(), format.getFrameSize() * 2, format.getFrameRate(), true); AudioFileFormat.Type targettype = AudioFileFormat.Type.WAVE; AudioInputStream targetaudiostream = AudioSystem.getAudioInputStream(format, sourceaudio); sourceaudio.close(); targetaudiostream.close(); System.out.println("55555555"); URL url = new URL("http://localhost:8084/newvideo/PCMfile.wav"); Clip clip = AudioSystem.getClip(); AudioInputStream ais = AudioSystem.getAudioInputStream(url); clip.open(ais); System.out.println("seconds: " + (clip.getMicrosecondLength() / 1000000));

    Read the article

  • ASP MVC.Net 3 RC2 bug ?

    - by Jarek Waliszko
    Hello, so far I've been using ASP.Net 3 BETA. Everything was working fine till the update to RC2 version. Of course I've read ScottGu's article about RC2. My problem is following. Basically I have 2 controllers: public class DynamicPageController : Controller { public ActionResult Redirect(string resource, int? pageNumber, int? id) { } } public class SystemController : Controller { public ActionResult Index() { } } In the Globals.asax I have routes like this: public static void RegisterRoutes(RouteCollection routes) { routes.MapRoute( "SystemRoute", "System/{action}", new { controller = "System", action = "Index" } ); routes.MapRoute( "PageRoute", "{resource}/{id}/{pageNumber}", new { controller = "DynamicPage", action = "Redirect", resource = UrlParameter.Optional, pageNumber = UrlParameter.Optional, id = UrlParameter.Optional } ); } In the code, I have simple link creation: System.Web.Mvc.UrlHelper u = new System.Web.Mvc.UrlHelper(context); string url = u.Action("Index", "System"); and the url is "/my_app/System" in both versions (BETA and RC2) But the code below (the syntax is the same as above, only controller and action names are different): string url = u.Action("Redirect", "DynamicPage", new RouteValueDictionary(new { resource = "Home" })); gives url which is null in RC2. It should be (and in fact in BETA was) "/my_app/Home" Why ? Is it a bug ? How can I create url for my "DynamicPage" controller ? Regards BTW: From where can I now download ASP.Mvc BETA version along with ASP.Net Web Pages 1.0 installers ? Since RC2 announcement I have problems finding mentioned 2 installers. Normally I would upgrade my code but this issue described above makes me stay with BETA for a while, since I have no time for migration and testing everything now.

    Read the article

  • Bluimp file upload send data to the server on .fileupload

    - by MyName
    OK I've Googled...Googled and Googled again with no avail on how I can send data to the server like an ajax call's data option for the file upload: $('#file_upload').fileupload({ dataType: 'json', url: "@(Url.Action("UploadFiles", "ExcelUpload"))", // formData: function(form) { return [{ name: "dataTable", value : "@(Model)"}];}, progressall: function (e, data) { $(this).find('.progressbar').progressbar({ value: parseInt(data.loaded / data.total * 100, 10) }); }, done: function (e, data) { BadFile(e, data); } }); controller would look something like this: [HttpPost] public ContentResult UploadFiles(Mytype param1, MyType Param2) { .. } I want to do something similar to this: $.ajax({ url: "@(Url.Action("Action", "Controller"))", type: "post", data: { param1: value, param2: @(Model) } }); On the fileupload callback. Is this possible? How can I pass values to the ServerSide? Should I switch to a different uploader..? Please help me out! I need to resolve this as soon as possible.

    Read the article

  • With regards to urllib AttributeError: 'module' object has no attribute 'urlopen'

    - by Matt
    import re import string import shutil import os import os.path import time import datetime import math import urllib from array import array import random filehandle = urllib.urlopen('http://www.google.com/') #open webpage s = filehandle.read() #read print s #display #what i plan to do with it once i get the first part working #results = re.findall('[<td style="font-weight:bold;" nowrap>$][0-9][0-9][0-9][.][0-9][0-9][</td></tr></tfoot></table>]',s) #earnings = '$ ' #for money in results: #earnings = earnings + money[1]+money[2]+money[3]+'.'+money[5]+money[6] #print earnings #raw_input() this is the code that i have so far. now i have looked at all the other forums that give solutions such as the name of the script, which is parse_Money.py, and i have tried doing it with urllib.request.urlopen AND i have tried running it on python 2.5, 2.6, and 2.7. If anybody has any suggestions it would be really welcome, thanks everyone!! --Matt ---EDIT--- I also tried this code and it worked, so im thinking its some kind of syntax error, so if anybody with a sharp eye can point it out, i would be very appreciative. import shutil import os import os.path import time import datetime import math import urllib from array import array import random b = 3 #find URL URL = raw_input('Type the URL you would like to read from[Example: http://www.google.com/] :') while b == 3: #get file name file1 = raw_input('Enter a file name for the downloaded code:') filepath = file1 + '.txt' if os.path.isfile(filepath): print 'File already exists' b = 3 else: print 'Filename accepted' b = 4 file_path = filepath #open file FileWrite = open(file_path, 'a') #acces URL filehandle = urllib.urlopen(URL) #display souce code for lines in filehandle.readlines(): FileWrite.write(lines) print lines print 'The above has been saved in both a text and html file' #close files filehandle.close() FileWrite.close()

    Read the article

  • How to send a JSONObject to a REST service?

    - by Sebi
    Retrieving data from the REST Server works well, but if I want to post an object it doesn't work: public static void postJSONObject(int store_type, FavoriteItem favorite, String token, String objectName) { String url = ""; switch(store_type) { case STORE_PROJECT: url = URL_STORE_PROJECT_PART1 + token + URL_STORE_PROJECT_PART2; //data = favorite.getAsJSONObject(); break; } HttpClient httpClient = new DefaultHttpClient(); HttpPost postMethod = new HttpPost(url); try { HttpEntity entity = new StringEntity("{\"ID\":0,\"Name\":\"Mein Projekt10\"}"); postMethod.setEntity(entity); HttpResponse response = httpClient.execute(postMethod); Log.i("JSONStore", "Post request, to URL: " + url); System.out.println("Status code: " + response.getStatusLine().getStatusCode()); } catch (ClientProtocolException e) { I always get a 400 Error Code. Does anybody know whats wrong? I have working C# code, but I can't convert: System.Net.WebRequest wr = System.Net.HttpWebRequest.Create("http://localhost:51273/WSUser.svc/pak3omxtEuLrzHSUSbQP/project"); wr.Method = "POST"; string data = "{\"ID\":1,\"Name\":\"Mein Projekt\"}"; byte [] d = UTF8Encoding.UTF8.GetBytes(data); wr.ContentLength = d.Length; wr.ContentType = "application/json"; wr.GetRequestStream().Write(d, 0, d.Length); System.Net.WebResponse wresp = wr.GetResponse(); System.IO.StreamReader sr = new System.IO.StreamReader(wresp.GetResponseStream()); string line = sr.ReadToEnd();

    Read the article

  • can't jQuery 3d party dialog to do what i want :)

    - by ropstah
    i'm using NyroModal, a 3rd party jQuery based dialog script. According to these settings, I should be able to do this: $.nyroModalManual({ type : 'ajax', url : '/url', 'ajax' : { url : '/url', data : 'somedata=1' } }); However I receive an error "$.ajax() is not defined". How could this be? p.s. If I run console.debug($.ajax()) right before the nyroModalManual part, it shows the XMLHTTPObject nicely, so I'm probably doing something wrong in the settings... I just need to be able to pass data.

    Read the article

  • Can't download pdf with java

    - by gedemagt
    I'm trying to download a file from http://aula.au.dk/main/document/document.php?action=download&id=%2F%D8velsesvejledning+2012.pdf but it dosen't appear to be a pdf, when i try downloading it with this code import java.io.*; import java.net.*; public class DownloadFile { public static void download(String address, String localFileName) throws IOException { URL url1 = new URL(address); byte[] ba1 = new byte[1024]; int baLength; FileOutputStream fos1 = new FileOutputStream(localFileName); try { // Contacting the URL System.out.print("Connecting to " + url1.toString() + " ... "); URLConnection urlConn = url1.openConnection(); // Checking whether the URL contains a PDF if (!urlConn.getContentType().equalsIgnoreCase("application/pdf")) { System.out.println("FAILED.\n[Sorry. This is not a PDF.]"); } else { try { // Read the PDF from the URL and save to a local file InputStream is1 = url1.openStream(); while ((baLength = is1.read(ba1)) != -1) { fos1.write(ba1, 0, baLength); } fos1.flush(); fos1.close(); is1.close(); } catch (ConnectException ce) { System.out.println("FAILED.\n[" + ce.getMessage() + "]\n"); } } } catch (NullPointerException npe) { System.out.println("FAILED.\n[" + npe.getMessage() + "]\n"); } } } Can you help me out here?

    Read the article

  • RAR Decompress on iPhone Device

    - by DenVog
    Has anyone found a solution to decompressing RAR files on iPhone (not Jailbroken)? It would be great if there was a library similar to libz. I did not find anything official from [URL="http://www.rarlab.com/"]RARlab[/URL]. Anyone successful with integrating [URL="http://wdtz.org/iphone/unrar/"]unRAR[/URL] into their app? The source code appears to be C++? I know that this has been asked before, but I've not seen a solution other than porting unRAR which is beyond me. Would greatly appreciate any information or suggestions. Thank you.

    Read the article

  • VisualSVN Server RewriteRule/Redirect Apache

    - by dvkwong
    Hi, Relating to another question I asked regarding setting up Mercurial under VisualSvn server. Currently when you go to the /svn/ url you can see all repos including hg repos. I now want some way to redirects you to the correct url for hg repos Eg myserver/svn/MecurialRepo = myserver/hg/MercurialRepo Or the correct hg script is run, or somehow disable the Mecurial repos from not displaying under the svn url. I have tried using the RewriteRule in the conf file, seems like something is ignoring the it. Thanks

    Read the article

< Previous Page | 347 348 349 350 351 352 353 354 355 356 357 358  | Next Page >