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  • Determine if FieldInfo is compiler generated backingfield

    - by Steffen
    The title pretty much says it all, how do I know if I'm getting a compiler generated backingfield for a {get; set;} property ? I'm running this code to get my FieldInfos: Class MyType { private int foo; public int bar {get; private set; } } Type type = TypeOf(MyType); foreach (FieldInfo fi in type.GetFields(BindingFlags.Instance | BindingFlags.Public | BindingFlags.DeclaredOnly | BindingFlags.NonPublic)) { // Gets both foo and bar, however bar is called <bar>k__backingfield. } so the question is, can I somehow detect that the FieldInfo is a backingfield, without relying on checking its name ? (Which is pretty undocumented, and could be broken in next version of the framework)

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  • Why do you sometimes need to write <typename T> instead of just <T> ?

    - by StackedCrooked
    I was reading the Wikipedia article on SFINAE and encountered following code sample: struct Test { typedef int Type; }; template < typename T > void f( typename T::Type ) {} // definition #1 template < typename T > void f( T ) {} // definition #2 void foo() { f< Test > ( 10 ); //call #1 f< int > ( 10 ); //call #2 without error thanks to SFINAE } Now I've actually written code like this before, and somehow intuitively I knew that I needed to type "typename T" instead of just "T". However, it would be nice to know the actual logic behind it. Anyone care to explain?

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  • How to pass a function as an argument?

    - by TFerrell
    I'm looking to pass an anonymous function to another function, but it doesn't seem to be working as I'd like. I've attached the code, I think it'd give you a better idea what I'd to do. <script language="javascript" type="text/javascript"> function do_work(success) { success; } do_work(function () { alert("hello") }); </script> Thanks in advance for any help.

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  • Pass parameter to controller from @Html.ActionLink MVC 4

    - by NetraSW
    Hello All, @Html.ActionLink("Reply", "BlogReplyCommentAdd", "Blog", new { blogPostId = blogPostId, replyblogPostmodel = Model, captchaValid = Model.AddNewComment.DisplayCaptcha }) In above line: I get error on blogPostId. The parameters dictionary contains a null entry for parameter 'blogPostId' of non-nullable type 'System.Int32' for method 'System.Web.Mvc.ActionResult BlogReplyCommentAdd(Int32, Nop.Web.Models.Blogs.BlogPostModel, Boolean)' in 'Nop.Web.Controllers.BlogController'. An optional parameter must be a reference type, a nullable type, or be declared as an optional parameter. Parameter name: parameters I have already assign a value for this on top such as @{ var blogPostId = Model.Id; } My Controller : public ActionResult BlogReplyCommentAdd(int blogPostId, BlogPostModel model, bool captchaValid) {} M i doing something wrong? Please give me an example on this. Thanks

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  • What's wrong with my If-statement to check uploaded file? (PHP)

    - by ggfan
    I am trying to test if the uploaded file is the image type I want. If it isn't a gif,jpeg, png, it should echo "Problem". But when I execute this code, it always says there's a problem. What's wrong with my if statement? $uploadfile_type=$_FILES['userfile']['type']; if ( ($uploadfile_type !='image/gif') || ($uploadfile_type !='image/jpeg') || ($uploadfile_type !='image/png')) { echo 'Problem: file is not a gif or jpeg or png!'; exit; } This code works when I am only checking one type of image. Ex: if($uploadfile_type !='image/gif') -- this statement would work but when I add a OR it doesn't.

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  • how can i send jquery ajax http request with php

    - by testkhan
    i have following form... <form action="http://mydomain.com/get.php" method="post"> <input type="hidden" value="thisisvalue" name="hdnvalue"> <input type="text" name="cost" id="cost"><br><br> <textarea id="msg" name="message"></textarea><br><br> <input type="submit" value="Send" id="send"> </form> the get.php file will response in 1 or 0 i.e 1 means recieved and 0 means not recieved now i want to send it to http://mydomain.com/get.php via http request with jquery ajax how can i do that get the returned value..

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  • How to find the submit button in a specific form in jQuery

    - by leifg
    I try to get jQuery object of a submit button in a specific form (there are several forms on the same page). I managed to get the form element itself. It looks something like this: var curForm = curElement.parents("form"); The current Element has the context HTMLInputElement. The several techniques I tried to get the according submit element of the form: var curSubmit = curForm.find("input[type='submit']"); var curSubmit = $(curForm).find("input[type='submit']"); var curSubmit = curForm.find(":submit"); var curSubmit = $(curForm).find(":submit"); var curSubmit = $(curSubmit, "input[type='submit']"); the result is always the same (and very strange). The result that I get is the same element as "curElement". So how can I get the right submit button?

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  • crash happens when NSMutableArray is returned?

    - by senthilmuthu
    Hi, I have coded like that(that function will be called again and again), but the returned object gives "BAD ACCESS", the NSLog prints correct string, but toReturn sometimes(i called again and again) gives crashes..any help to alter this code - (NSMutableArray *)getAll:(NSString *)type { NSLog(@"Type: %@", type); NSMutableArray *toReturn = [[NSMutableArray alloc] initWithCapacity:0] ; rs = [db executeQuery:Query1]; while ([rs next]) { [toReturn addObject:[rs stringForColumn:@"Name"]]; NSLog(@"name: %@", [rs stringForColumn:@"Name"]); } [rs close]; return toReturn; }

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  • Jquery - how i can get the video src value?

    - by 3gwebtrain
    i need to get the value of a video and need to change in to new value... for that i used this function: var video = $('#task2ResultVideo').get(0); console.log($(video).attr('poster')); // i am getting this $(video).attr('src',function(num,val){ console.log(num,val) // i am not getting this.. }) ? HTML: <video id="task2ResultVideo" autobuffer poster="img/task2-results-host-poster.jpg"> <source src="Video/webm/Task_2.4a_Host_treated.webm" type="video/webm" /> <source src="Video/ogv/Task_2.4a_Host_treated.theora.ogv" type="video/ogg" /> <source src="Video/MP4/Task_2.4a_Host_treated.mp4" type="video/mp4" /> </video>? But i am not able to get the values. what is wrong with my code? in case if i get the value how can i change the src? any suggestion please?

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  • spring-security and jsf

    - by Mike
    Hi! i am developing in JSF a Spring Security application. the login form is fine. however, when i try to retrieve the authentication object, in future code, i always get the authentication pricipal as anonymous. i try to fetch is like this: Authentication auth = SecurityContextHolder.getContext().getAuthentication();

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  • How to get the class of an input inside a jQuery each loop?

    - by Paul Atkins
    Hi, I have function which appends inputs inside a list item when a link is clicked. I then loop through these inputs using an each loop using the code below. It is working correctly as shown, however instead of using field.name I want to use the class of the input as the array key but when i try to do this the class is shown as undefined. Here is the code I am currently using: var values = {}; $.each($('li :input').serializeArray(), function(i, field) { values[field.name] = field.value; }); Here is the code I have inside the list item once I have appended the hidden inputs using jQuery append: <li><input type="hidden" name="group" class="group" value="2"/><input type="hidden" name="condition" class="condition" value="isany"/><input type="hidden" name="value" class="value" value="1,2"/></li> I can get the name attribute fine but class is always undefined. Could anybody help with this?

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  • alternative to lag SQL command

    - by mahen
    I have a table which has a table like this. Month-----Book_Type-----sold_in_Dollars Jan----------A------------ 100 Jan----------B------------ 120 Feb----------A------------ 50 Mar----------A------------ 60 Mar----------B------------ 30 and so on I have to calculate the expected sales for each month and book type based on the last 2 months sales. So for March and type A it would be (100+50)/2 = 75 For March and type B it is 120/1 since no data for Feb is there. I was trying to use the lag function but it wouldn't work since there is data missing in a few rows. Any ideas on this?

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  • $_FILES empty on image upload

    - by zvir
    i need help, i'm programing some kind of catalogue and i have a page where clients can upload their logo or images. every page i make is included in index.php and my url looks like something like this www.url.com/index.php?s=upload where "upload" is name of upload.php file. when i create form on that upload.php file and submit it, $_FILES array is empty. echo "<form method=\"post\" enctype=\"multipart/form-data\" action=\"index.php\" />\n"; echo "<input type=\"file\" name=\"image\">\n"; echo "<input type=\"hidden\" name=\"s\" value=\"upload\">\n"; echo "<input type=\"submit\" name=\"submit\" value=\"Spremi\">\n"; echo "</form>\n"; i tried everything and nothing works. $_POST items are returned but $_FILES are empty...

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  • How do i get my search bar to actually work?

    - by Sam
    Hey guys, I've got a search bar and it looks fine, but i don't really know how to make it search the whole of my site... Here's my html code so far: <form class="search2" method="get" action="default.html" /> <input class="search2" type="text" name="serach_bar" size="31" maxlength="255" value="" style="left: 396px; top: 153px; width: 293px; height: 26px;" /> <input class="search1" type="submit" name="submition" value="Search" style=" padding- bottom:20px; left: 691px; top: 153px; height: 23px" /> <input class="search2" type="hidden" name="sitesearch" value="default.html" /> Thanks in advance guys!

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  • Which code snipplets in PHP can create a input form, which creates a new set of data in my mysql dat

    - by smiyazaki
    I am using the Google Maps API with parts in javascript and others in PHP. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> Google Maps AJAX + mySQL/PHP Example // var iconBlue = new GIcon(); iconBlue.image = 'icon.png'; iconBlue.shadow = ''; iconBlue.iconSize = new GSize(19, 19); iconBlue.shadowSize = new GSize(22, 20); iconBlue.iconAnchor = new GPoint(6, 20); iconBlue.infoWindowAnchor = new GPoint(5, 1); var iconRed = new GIcon(); iconRed.image = 'icon.png'; iconRed.shadow = ''; iconRed.iconSize = new GSize(19, 19); iconRed.shadowSize = new GSize(22, 20); iconRed.iconAnchor = new GPoint(6, 20); iconRed.infoWindowAnchor = new GPoint(5, 1); var customIcons = []; customIcons["restaurant"] = iconBlue; customIcons["bar"] = iconRed; function load() { if (GBrowserIsCompatible()) { var map = new GMap2(document.getElementById("map")); map.setMapType(G_SATELLITE_MAP); map.addControl(new GSmallMapControl()); map.addControl(new GMapTypeControl()); map.setCenter(new GLatLng(47.614495, -122.341861), 13); // Change this depending on the name of your PHP file GDownloadUrl("phpsqlajax_genxml.php", function(data) { var xml = GXml.parse(data); var markers = xml.documentElement.getElementsByTagName("marker"); for (var i = 0; i < markers.length; i++) { var name = markers[i].getAttribute("name"); var address = markers[i].getAttribute("address"); var type = markers[i].getAttribute("type"); var point = new GLatLng(parseFloat(markers[i].getAttribute("lat")), parseFloat(markers[i].getAttribute("lng"))); var marker = createMarker(point, name, address, type); map.addOverlay(marker); } }); } } function createMarker(point, name, address, type) { var marker = new GMarker(point, customIcons[type]); var html = "<b>" + name + "</b> <br/>" + address; GEvent.addListener(marker, 'click', function() { marker.openInfoWindowHtml(html); }); return marker; } //]]> (I suppose the php will be called by "GDownloadUrl("phpsqlajax_genxml.php", function(data) { ..." in the javascript part of the sourcecode of phpsqlajax_map.htm) Now I need another php file and the code snipplets for it, which creates an input form where I can add some new locations to the google map. Following code is used to create the xml file here: http://detektors.de/maptest/phpsqlajax_genxml.php The next step would be, trying to make an plugin for wordpress that I could easily post a blog entry with a new location on the same map, which displays already some other locations stored in the mysql database. thanks! <?php require("phpsqlajax_dbinfo.php"); function parseToXML($htmlStr) { $xmlStr=str_replace('<','<',$htmlStr); $xmlStr=str_replace('','>',$xmlStr); $xmlStr=str_replace('"','"',$xmlStr); $xmlStr=str_replace("'",''',$xmlStr); $xmlStr=str_replace("&",'&',$xmlStr); return $xmlStr; } // Opens a connection to a MySQL server $connection=mysql_connect ($host, $username, $password); if (!$connection) { die('Not connected : ' . mysql_error()); } // Set the active MySQL database $db_selected = mysql_select_db($database, $connection); if (!$db_selected) { die ('Can\'t use db : ' . mysql_error()); } // Select all the rows in the markers table $query = "SELECT * FROM markers WHERE 1"; $result = mysql_query($query); if (!$result) { die('Invalid query: ' . mysql_error()); } header("Content-type: text/xml"); // Start XML file, echo parent node echo ''; // Iterate through the rows, printing XML nodes for each while ($row = @mysql_fetch_assoc($result)){ // ADD TO XML DOCUMENT NODE echo ''; } // End XML file echo ''; ?

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  • In Spring MVC, is it possible to have different return types in one request handler method?

    - by Bobo
    For example, if a request succeeds, I will return a View ,if not, return a String indicating error message and set the content-type to either xml or json. Based on what I read, seems like I should use "void" as the return type for handler methods. Check this out: "void if the method handles the response itself (by writing the response content directly, declaring an argument of type ServletResponse / HttpServletResponse for that purpose) or if the view name is supposed to be implicitly determined through a RequestToViewNameTranslator (not declaring a response argument in the handler method signature)."(Spring Framework reference). What I dont understand is what " the view name is supposed to be implicitly determined through a RequestToViewNameTranslator (not declaring a response argument in the handler method signature)" means? Any anyone give me an example?

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  • How to convet DataTable to List on runtype with out existin class property [closed]

    - by shamim
    Work on VS2010 C#,Have one DataTable ,want to convert this DataTable to List Suppose: Table dt; On run time want to create similar field from a datatable and fill fields in List.There is no existing class for list properties. ListName=TableName List property name=Table column name List Property type=Table column type List items=Table rows Note: Recently work on EF.To fullfill my project requirement, need to give flexibility to use to input and execute ESQL at runtime .I don’t want to put this execute result on datatable or List ,want to put this result on list. List has no existing class and property,don’t want to convert DataTable on list Type:DataRow If have any query please ask,Thanks in advanced.

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  • php random image file name

    - by bush man
    Okay im using a snippet I found on google to take a users uploaded image and put it in my directory under Content But Im worried about duplicates so I was going have it upload the image as a Random number well here is my code you can probably understand what im going for through it anyways <label for="file">Profile Pic:</label> <input type="file" name="ProfilePic" id="ProfilePic" /><br /> <input type="submit" name="submit" value="Submit" /> $ProfilePicName = $_FILES["ProfilePic"]["name"]; $ProfilePicType = $_FILES["ProfilePic"]["type"]; $ProfilePicSize = $_FILES["ProfilePic"]["size"]; $ProfilePicTemp = $_FILES["ProfilePic"]["tmp_name"]; $ProfilePicError = $_FILES["ProfilePic"]["error"]; $RandomAccountNumber = mt_rand(1, 99999); echo $RandomAccountNumber; move_uploaded_file($ProfilePicTemp, "Content/".$RandomAccountNumber.$ProfilePicType); And then basicly after all this Im going try to get it to put that random number in my database

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  • How to add visible menu item from php code (drupal)

    - by uta
    I have a content type with important "created" date field. And I have a menu link (in primary links) which is link to page that shows list of all nodes of my content type. (http://example.com/mycontenttype) I want to have menu links (visible in primary links) to each year when nodes of my content type are displayed (http://example.com/mycontenttype/2010). And I want to add these menu links from mymodule_nodeapi function, when the node is creating and only if it has a "created" date of new year. I know that I can create a pathes in mymodule_menu function, but it doesn't create a visible menu item. (Maybe I can somehow set parent_link_id or something else to do it?)

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  • Upload files, form within form

    - by Alexd2
    Hello everyone and thanks in advance. I have a problem and I have 2 form into one another, the domestic form is to perform a file upload. As I can do to make when sending in internal form not run the main form. <form name="x" method="post" action="xxx.php"> .... <form action="" method="post" enctype="multipart/form-data" target="xxx"> <input type="file" /> <input type="submit" /> </form> <iframe id="xxx" src="process.php"> </iframe> .... <input type="submit" name="pro" value="Register user"/ > </form> Doing this does not work, as this within another form. Any help or possible solution.

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  • spring component scan for classes

    - by awk
    I want to scan all the classes in a package that that are subclasses of the particular class. Then I want to take these classes and for each of them instantiate a bean of same type, using the class as a property. Then I want to gather all these anonymous beans and put them into collection. Is it possible to configure spring context in XML like this? Thx

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  • JQuery validation based on class?

    - by Mark Kadlec
    I have a form that will have dynamically created elements, one of those will be of date type. There can also be many fields of this type on my form, all which must be validated. I am using a strongly typed view in Asp MVC, so the name will change based on various factors. What I would like to do is validate based on a class name instead, since that will be constant for that type of field. Ie: <%= Html.TextBox("questionAnswers[" + index + "].AnswerValue", qa.AnswerValue, new { @class = "DateTypeClass" })%> So then I would need JQuery validation based on the classname DateTypeClass versus the Name. Any ideas?

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  • PHP-OOP extending two classes?

    - by user1292810
    I am very beginner to OOP and now I am trying to write some PHP class to connect with FTP server. class ftpConnect { private $server; private $user; private $password; private $connection_id; private $connection_correct = false; public function __construct($server, $user = "anonymous", $password = "[email protected]") { $this->server = $server; $this->user = $user; $this->password = $password; $this->connection_id = ftp_connect($this->server); $this->connection_correct = ftp_login($this->connection_id, $this->user, $this->password); if ( (!$this->connection_id) || (!$this->connection_correct) ){ echo "Error! Couldn't connect to $this->server"; var_dump($this->connection_id); var_dump($this->connection_correct); return false; } else { echo "Successfully connected to $this->server, user: $this->user"; $this->connection_correct = true; return true; } } } I reckon that body of the class is insignificant at the moment. Main issue is that I have some problems with understanding OOP idea. I wanted to add sending emails every time, when the code is run. I have downloaded PHPMailer Class and extended my class with it: class ftpConnect extends PHPMailer {...} I have added some variables and methods and everything works as expected to that point. I thought: why not to add storing everything in database. Everytime user runs above code, proper information should be stored in database. I could edit my ftpConnect class and add database connecting to the constructor, and some other methods to updating tables. But database connecting and all that stuff could be used by other classes in the future, so it definitely should be implemented in seperate class. But my "main" ftpConnect class already extends one class and could not extend not a single one more. I have no idea how can I resolve this problem. Maybe my ftpConnect class is to complex and I should somehow divide it into couple smaller classes? Any help is much appreciated.

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