Search Results

Search found 6394 results on 256 pages for 'regular expressions'.

Page 36/256 | < Previous Page | 32 33 34 35 36 37 38 39 40 41 42 43  | Next Page >

  • AWK: compare apache dates without using regular expression

    - by smallmeans
    I'm writing a loganalysis application and wanted to grab apache log records between two certain dates. Assume that a date is formated as such: 22/Dec/2009:00:19 (day/month/year:hour:minute) Currently, I'm using a regular expression to replace the month name with its numeric value, remove the separators, so the above date is converted to: 221220090019 making a date comparison trivial.. but.. Running a regex on each record for large files, say, one containing a quarter million records, is extremely costly.. is there any other method not involving regex substitution? Thanks in advance Edit: here's the function doing the convertion/comparison function dateInRange(t, from, to) { sub(/[[]/, "", t); split(t, a, "[/:]"); match("JanFebMarAprMayJunJulAugSepOctNovDec", a[2]); a[2] = sprintf("%02d", (RSTART + 2) / 3); s = a[3] a[2] a[1] a[4] a[5]; return s >= from && s <= to; } "from" and "to" are the intervals in the aforementioned format, and "t" is the raw apache log date/time field (e.g [22/Dec/2009:00:19:36)

    Read the article

  • Regular Expression doesn't match

    - by dododedodonl
    Hi All, I've got a regular expression in my cocoa-touch app (using RegexKitLite). NSString *week = [[NSString alloc] initWithFormat:@"%@", [pageContent stringByReplacingOccurrencesOfRegex:@"<select name=\"week\" class=\"selectbox\" style='width:134' onChange=\"doDisplayTimetable(NavBar, topDir);\">(.+?)<option value=\"(.+?)\">(.+?)</option>" withString:@"$2"]]; I expect it to match with the section of this (what is in NSString pageContent): <span class="selection"> <nobr> Periode<br> <span class="absatz"> &nbsp;<br> </span> <select name="week" class="selectbox" style='width:134' onChange="doDisplayTimetable(NavBar, topDir);"> <option value="14">17-5 - 16-7</option> </select> </nobr> </span> But it doesn't... I need the value of the option, it is possible that there is more than one (in that case I need them both separated by a ,. Can someone help me out? Regards, Dodo

    Read the article

  • need to clean malformed tags using regular expression

    - by Brian
    Looking to find the appropriate regular expression for the following conditions: I need to clean certain tags within free flowing text. For example, within the text I have two important tags: <2004:04:12 and . Unfortunately some of tags have missing "<" or "" delimiter. For example, some are as follows: 1) <2004:04:12 , I need this to be <2004:04:12> 2) 2004:04:12>, I need this to be <2004:04:12> 3) <John Doe , I need this to be <John Doe> I attempted to use the following for situation 1: String regex = "<\\d{4}-\\d{2}-\\d{2}\\w*{2}[^>]"; String output = content.replaceAll(regex,"$0>"); This did find all instances of "<2004:04:12" and the result was "<2004:04:12 ". However, I need to eliminate the space prior to the ending tag. Not sure this is the best way. Any suggestions. Thanks

    Read the article

  • JavaScript (jQuery) Regular Expression for searching through an array

    - by CoryDorning
    First and foremost, I do not know RegEx but am trying to piece something together to make this work. Just wanted you to be forewarned. ;) Anyways, I'm trying to create a regular expression to take a word from an array and see if it matches a word in another array. I only want the search to return true if the keyword array string contains the searchTerm word. (i.e. oneone would be false, so would ones). Any help is GREATLY appreciated. var searchTerm = ['one','two','three']; var keywords = ['String which contains one', 'This string is 2', 'Three is here']; var keywordIndex; // loop through each keyword array $.each(keywords, function(i) { $.each(searchTerm, function(j) { var rSearchTerm = new RegExp('\b' + searchTerm[j] + '\b',i); // if search term is found, swap accordion div content if (keywords[i].search(rSearchTerm) > -1) { keywordIndex = i; // grouping keyword is in } }); // end searchTerm loop }); // end keyword loop

    Read the article

  • regular expression repeating subexpression

    - by Michael Z
    I have the following text <pattern name="pattern1"/> <success>success case 1</success> <failed> failure 1</failed> <failed> failure 2</failed> <unknown> unknown </unknown> <pattern name="pattern2"/> <success>success case 2</success> <otherTag>There are many other tags.</otherTag> <failed> failure 3</failed> And the regular expression <failed>[\w|\W]*?</failed> matches all the lines contains failed tag. What do I need to to if I want to include the lines contains pattern tag as well? Basically, I want the following output: <pattern name="pattern1"/> <failed> failure 1</failed> <failed> failure 2</failed> <pattern name="pattern2"/> <failed> failure 3</failed> I am doing this in javascript, I do not mind of doing some intermediate steps.

    Read the article

  • Regular expression to convert ul to textindent and back, with a different attribute value for first

    - by chapmanio
    Hi, This is a related to a previous question I have asked here, see the link below for a brief description as to why I am trying to do this. Regular expression from font to span (size and colour) and back (VB.NET) Basically I need a regex replace function (or if this can be done in pure VB then that's fine) to convert all ul tags in a string to textindent tags, with a different attribute value for the first textindent tag. For example: <ul> <li>This is some text</li> <li>This is some more text</li> <li> <ul> <li>This is some indented text</li> <li>This is some more text</li> </ul> </li> <li>More text!</li> <li> <ul> <li>This is some indented text</li> <li>This is some more text</li> </ul> </li> <li>More text!</li> </ul> Will become: <textformat indent="0"> <li>This is some text</li> <li>This is some more text</li> <li> <textformat indent="20"> <li>This is some indented text</li> <li>This is some more text</li> </textformat> </li> <li>More text!</li> <li> <textformat indent="20"> <li>This is some indented text</li> <li>This is some more text</li> </textformat> </li> <li>More text!</li> </textformat> Basically I want the first ul tag to have no indenting, but all nested ul tags to have an indent of 20. I appreciate this is a strange request but hopefully that makes sense, please let me know if you have any questions. Thanks in advance.

    Read the article

  • Match over multiple lines perl regular expression

    - by John
    Hi, I have a file like this: 01 00 01 14 c0 00 01 10 01 00 00 16 00 00 00 64 00 00 00 65 00 00 01 07 40 00 00 22 68 61 6c 2e 6f 70 65 6e 65 74 2e 63 6f 6d 3b 30 30 30 30 30 30 30 30 32 3b 30 00 00 00 00 01 08 40 00 00 1e 68 61 6c 2e 6f 70 65 6e 65 74 2d 74 65 6c 65 63 6f 6d 2e 6c 61 6e 00 00 00 00 01 28 40 00 00 21 72 65 61 6c 6d 31 2e 6f 70 65 6e 65 74 2d 74 65 6c 65 63 6f 6d 2e 6c 61 6e 00 00 00 00 00 01 25 40 00 00 1e 68 61 6c 2e 6f 70 65 6e 65 74 2d 74 65 6c 65 63 6f 6d 2e 6c 61 6e 00 00 00 00 01 1b 40 00 00 20 72 65 61 6c 6d 2e 6f 70 65 6e 65 74 2d 74 65 6c 65 63 6f 6d 2e 6c 61 6e 00 00 01 02 40 00 00 0c 01 00 00 16 00 00 01 a0 40 00 00 0c 00 00 00 01 00 00 01 9f 40 00 00 0c 00 00 00 00 00 00 01 16 40 00 00 0c 00 00 00 00 00 00 01 bb 40 00 00 28 00 00 01 c2 40 00 00 0c 00 00 00 00 00 00 01 bc 40 00 00 13 31 39 37 37 31 31 31 32 32 33 31 00 I am reading the file and then finding certain octets and replacing them with tags: while(<FH>){ $line =~ s/(00 00 00 64)/<incr4> /g; $line =~ s/(00 00 00 65)/<incr4> /g; $line =~ s/(30 30 30 30 30 32)/<incr6ascii:999999:0>/g; $line =~ s/(31 31 32 32 33 31)/<incr6ascii:999999:0>/g; print OUTPUT $line; # } So for example, 00 00 00 64 would be replaced by the tag. This was working fine, but it doesn't seem to able to match over multiple lines any more. For example the pattern 31 31 32 32 33 31 runs over multiple lines, and the regular expression doesn't seem to catch it. I tried using /m /s pattern modifiers to ignore new lines but they didn't match it either. The only way around it I can come up with, is to read the whole file into a string using: undef $/; my $whole_file = <FH>; my $line = $whole_file; $line =~ s/(00 00 00 64)/<incr4> /g; $line =~ s/(00 00 00 65)/<incr4> /g; $line =~ s/(30 30 30 30 30 32)/<incr6ascii:999999:0>/g; $line =~ s/(31 31 32 32 33 31)/<incr6ascii:999999:0>/g; print OUTPUT $line; This works, the tags get inserted correctly, but the structure of the file is radically altered. It is all dumped out on a single line. I would like to retain the structure of the file as it appears here. Any ideas as to how I might do this? /john

    Read the article

  • Google Rolls Out Secured Search. It’s Slightly Different From Regular Search

    - by Gopinath
    Google rolled out secured version of it’s search engine at https://google.com (did you notice https instead of http?). This search engine lets everyone to use Google search in a secured way. How is it secured? When you use https://google.com, the data exchanged between your browser and Google servers is encrypted to make sure that no one can sniff it. Is my search history secured from Google? No. The search queries you submit to Google are stored in Google servers. There is no change Google’s search history recording. Any differences between Regular Search and Secured Search Results? Yes. Secured search is slightly different from regular search. When you are accessing Google Secured Search Image search options will not be available on the left side bar. Site may respond slow compared to regular search site as there is a overhead to establish between your browser and the server. Join us on Facebook to read all our stories right inside your Facebook news feed.

    Read the article

  • From escaped html -> to regular html? - Python

    - by RadiantHex
    Hi folks, I used BeautifulSoup to handle XML files that I have collected through a REST API. The responses contain HTML code, but BeautifulSoup escapes all the HTML tags so it can be displayed nicely. Unfortunately I need the HTML code. How would I go on about transforming the escaped HTML into proper markup? Help would be very much appreciated!

    Read the article

  • Limit user input to allowable comma delimited words with regular expression using javascript

    - by Marc
    I want to force the user to enter any combination of the following words. the words need to be comma delimited and no comma at the beginning or end of the string the user should only be able to enter one of each word. Examples admin basic,ectech admin,ectech,advanced basic,advanced,admin,ectech my attempt ^((basic|advanced)|admin|ectech)((,basic|,advanced)|,admin|,ectech){0,2}$ Thanks Marc

    Read the article

  • XSLT: Regular Expression function does not work?

    - by Fedor Steeman
    Ok, this one has been driving me up the wall... I have a xslt function that is supposed to split out the Zip-code part from a Zip+City string depending on the country. I cannot get it to work! This is what I got so far: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:exslt="http://exslt.org/functions" xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xsl:function name="exslt:GetZip" as="xs:string"> <xsl:param name="zipandcity" as="xs:string"/> <xsl:param name="countrycode" as="xs:string"/> <xsl:choose> <xsl:when test="$countrycode='DK'"> <xsl:analyze-string select="$zipandcity" regex="(\d{4}) ([A-Za-zÆØÅæøå]{3,24})"> <xsl:matching-substring> <xsl:value-of select="regex-group(1)"/> </xsl:matching-substring> <xsl:non-matching-substring> <xsl:text>fail</xsl:text> </xsl:non-matching-substring> </xsl:analyze-string> </xsl:when> <xsl:otherwise> <xsl:text>error</xsl:text> </xsl:otherwise> </xsl:choose> </xsl:function> I am running it on a source XML where the following values are passed to the function: zipandcity: "DK-2640 København SV" countrycode: "DK" ...will output 'fail'! I think there is something I am misunderstanding here...

    Read the article

  • Unable to convert from Julian INT date to regular TSQL Datetime

    - by Bluehiro
    Help me Stackoverflow, I'm close to going all "HULK SMASH" on my keyboard over this issue. I have researched carefully but I'm obviously not getting something right. I am working with a Julian dates referenced from a proprietary tool (Platinum SQL?), though I'm working in SQL 2005. I can convert their "special" version of Julian into datetime when I run a select statement. Unfortunately it will not insert into a datetime column, I get the following error when I try: The conversion of a char data type to a datetime data type resulted in an out-of-range datetime value. So I can't setup datetime criteria for running a report off of the Stored Procedure. Original Value: 733416 Equivalent Calendar Value: 01-09-2009 Below is my code... I'm so close but I can't quite see what's wrong, I need my convert statement to actually convert the Julian value (733416) into a compatible TSQL DATETIME value. SELECT org_id, CASE WHEN date_applied = 0 THEN '00-00-00' ELSE convert(char(50),dateadd(day,date_applied-729960,convert(datetime, '07-25-99')),101) END AS date_applied, CASE WHEN date_posted = 0 THEN '00-00-00' ELSE convert(char(50),dateadd(day,date_posted-729960,convert(datetime, '07-25-99')),101) END AS date_posted from general_vw

    Read the article

  • Ninject : ninject.web - How to apply on a regular ASP.Net Web (!MVC)

    - by No Body
    What I am looking is something similar to the below (http://github.com/ninject/ninject.web.mvc): README.markdown This extension allows integration between the Ninject core and ASP.NET MVC projects. To use it, just make your HttpApplication (typically in Global.asax.cs) extend NinjectHttpApplication: public class YourWebApplication : NinjectHttpApplication { public override void OnApplicationStarted() { // This is only needed in MVC1 RegisterAllControllersIn("Some.Assembly.Name"); } public override IKernel CreateKernel() { return new StandardKernel(new SomeModule(), new SomeOtherModule(), ...); // OR, to automatically load modules: var kernel = new StandardKernel(); kernel.AutoLoadModules("~/bin"); return kernel; } } Once you do this, your controllers will be activated via Ninject, meaning you can expose dependencies on their constructors (or properties, or methods) to request injections.

    Read the article

  • java Regular expression matching html

    - by user121196
    I want to match and capture the enclosing content of the <pre></pre> tag tried the following, not working, what's wrong? String p="<pre>.*</pre>"; Matcher m=Pattern.compile(p,Pattern.MULTILINE|Pattern.CASE_INSENSITIVE).matcher(input); if(m.find()){ String g=m.group(0); System.out.println("g is "+g); }

    Read the article

  • Verifying regular expression for malware removal

    - by Legend
    Unfortunately, one of my web servers was compromised recently. I have two questions. Is there a way I can scan the downloaded directory for backdoors? Is there anything I can do to ensure that at least known vulnerabilities do not exist anymore? Secondly, the malware put up the following in all index.* files on my webserver: <script>/*GNU GPL*/ try{window.onload = function(){var Hva23p3hnyirlpv7 = document.createElement('script');Hva23p3hnyirlpv7.setAttribute('type', 'text/javascript');Hva23p3hnyirlpv7.setAttribute('id', 'myscript1');Hva23p3hnyirlpv7.setAttribute('src',.... CODE DELETED FOR SAFETY.... );}} catch(e) {}</script> Obviously, this snippet seems to download some rogue file onto the user's machine. I downloaded an entire backup of the web server and am currently trying to remove this snippet from all file. For this I am doing: find ./ -name "index.*" -exec sed -i 's/<script>\/\*GNU GPL\*.*Hva23p3hnyirlpv7.*<\/script>//g' {} \; Just wanted to verify if this does the trick. I verified it with a few files but I want to be sure that this doesn't delete some valid code. Anyone suggests any other modifications?

    Read the article

  • Rewriting An URL With Regular Expression Substitution in Routes

    - by Sean M
    In my Pylons app, some content is located at URLs that look like http://mysite/data/31415. Users can go to that URL directly, or search for "31415" via the search page. My constraints, however, mean that http://mysite/data/000031415 should go to the same page as the above, as should searches for "0000000000031415." Can I strip leading zeroes from that string in Routes itself, or do I need to do that substitution in the controller file? If it's possible to do it in routing.py, I'd rather do it there - but I can't quite figure it out from the documentation that I'm reading.

    Read the article

  • SED - Regular Expression over multiple lines

    - by herrherr
    Hi there, I'm stuck with this for several hours now and cycled through a wealth of different tools to get the job done. Without success. It would be fantastic, if someone could help me out with this. Here is the problem: I have a very large CSV file (400mb+) that is not formatted correctly. Right now it looks something like this: Alan Smithee ist ein Anagramm von „The [...] „Alan Smythee“, und „Adam Smithee“." ,Alan Smithee Die Aussagenlogik ist der Bereich der Logik, der sich mit [...] ihrer Teilaussagen bestimmen. ,Aussagenlogik As you can probably see the words ",Alan Smithee" and ",Aussagenlogik" should actually be on the same line as the foregoing sentence. Then it would look something like this: Alan Smithee ist ein Anagramm von „The Smitheeeee [...] „Alan Smythee“, und „Adam Smithee“.,Alan Smithee Die Aussagenlogik ist der Bereich der Logik, der sich mit [...] ihrer Teilaussagen bestimmen.,Aussagenlogik Please note that the end of the sentence can contain quotes or not. In the end they should be replaced too. Here is what I came up with so far: sed -n '1h;1!H;${;g;s/\."?.*,//g;p;}' out.csv > out1.csv This should actually get the job done of matching the expression over multiple lines. Unfortunately it doesn't :) The expression is looking for the dot at the end of the sentence and the optional quotes plus a newline character that I'm trying to match with .*. Help much appreciated. And it doesn't really matter what tool gets the job done (awk, perl, sed, tr, etc.). Thanks, Chris

    Read the article

  • Regular expression that contains in it...

    - by Fabiano PS
    I need my regexp to match, all the highlighted words, in order, following: Fri/Feb/10 - *Nesta* manh\303\203\302\243,* @*anestesya *entrou* \303\240s 08:18AM Fri/Feb/10 - *Nesta* tarde,* @*pernas *saiu* \303\240s 08:18AM I was trying something like: /[?=Nesta.?=@.?=(entrou|saiu)]/ So I don't care what is in between as long as it has: ' Nesta ' AND ' @' AND ' entrou ' OR ' saiu '

    Read the article

  • Regular Expression Fill-Down

    - by richardtallent
    I have a plain text file something like this: Ford\tTaurus F-150 F-250 Toyota\tCamry Corsica In other words, a two-level hierarchy where the first child is on the same line as the parent, but subsequent children on lines following, distinguished from being a parent by a two-space prefix (\t above represents a literal tab in the text). I need to convert to this using RegEx: Ford\tTaurus Ford\tF-150 Ford\tF-250 Toyota\tCamry Toyota\tCorsica So, I need to capture the parent (text between \r\n and \t not starting with \s\s), and apply that in the middle of any \r\n\s\s found until the next parent. I have a feeling this can be done with some sort of nested groups, but I think I need more caffeine or something, can't seem to work out the pattern. (Using .NET with IgnoreWhitespace off and Multiline off)

    Read the article

  • Convert regular date and time to Julian date and vice versa

    - by zbz.lvlv
    I am currently working on a program that will calculate sunrise and sunset times. How do I convert yyyymmddhhmmss to Julian date? I need the date to be very precise. It'll great if there can be an example for such conversions. Calendar cNow = Calendar.getInstance(); Calendar cJan1 = Calendar.getInstance(); double julianJan1_2014_12_00_00 = 2456659; cJan1.set(2014, 0, 0, 12, 0); Date dJan1 = cJan1.getTime(); Date dNow = cNow.getTime(); long lJan1 = dJan1.getTime(); long lNow = dNow.getTime(); double diffDay = (lNow - lJan1) / 1000 / 60 / 60 / 24; double julianDate = diffDay + julianJan1_2014_12_00_00; The code I currently have.

    Read the article

  • php regular express

    - by kelly
    I have one string format like {blah\blah{\blah\blah...{\bl....}}}{blah...}blah... How can I get the content to the array in the first level, like array( "{blah\blah{\blah\blah...{\bl....}}}", "{blah...}"). Thanks in advance.

    Read the article

  • How to match filetype with regular expression?

    - by Sanarothe
    Hi. I'm stuck trying to get a regex to match a filetype in a sorting script. Dir.foreach(savedirs[0]) do |x| puts "Matching " + x + " against filetypes." case x when x.match(/^.*\.exe$/i) then puts x when x.match(/\.jpe?g$/) then FileUtils.move(x, sortpath[".exe"], :verbose => true) when x =~ /\.jpg$/ then FileUtils.move(x, sortpath[".jpg"]) end end I can't get any of these to match on in windows. All I need is to confirm that a given filename matches against compatible filetypes.

    Read the article

  • Regular Expression (preg_match_all)

    - by Helena
    This is my code: <?php $matchWith = "http://videosite.com/ID123"; preg_match_all('\S/videosite\.com\/(\w+)\S/i', $matchWith, $matches); foreach($matches[1] as $value) { print '<a href="http://videosite.com/'.$value.'"> Hyperlink </a>'; } ?> It's not working. I want to exclude every match that has a whitespace before or after the Link (with the ID). I used \S for this. For example if: $matchWith = " http://videosite.com/ID123 "; it should not display anything. Thank you.

    Read the article

  • using sfDoctrineGuardPlugin for regular member login?

    - by fayer
    i want to create users for my webapplication. im using symfony. i wonder if i should do that with sfDoctrineGuardPlugin or symfony's provided methods for this? // Add one or more credentials $user->addCredential('foo'); $user->addCredentials('foo', 'bar'); // Check if the user has a credential echo $user->hasCredential('foo'); => true // Check if the user has both credentials echo $user->hasCredential(array('foo', 'bar')); => true // Check if the user has one of the credentials echo $user->hasCredential(array('foo', 'bar'), false); => true // Remove a credential $user->removeCredential('foo'); echo $user->hasCredential('foo'); => false // Remove all credentials (useful in the logout process) $user->clearCredentials(); echo $user->hasCredential('bar'); => false or is the purpose of sfDoctrineGuardPlugin just securing the admin page and not the frontend logging system? thanks.

    Read the article

< Previous Page | 32 33 34 35 36 37 38 39 40 41 42 43  | Next Page >