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  • Django: Determining if a user has voted or not

    - by TheLizardKing
    I have a long list of links that I spit out using the below code, total votes, submitted by, the usual stuff but I am not 100% on how to determine if the currently logged in user has voted on a link or not. I know how to do this from within my view but do I need to alter my below view code or can I make use of the way templates work to determine it? I have read http://stackoverflow.com/questions/1528583/django-vote-up-down-method but I don't quite understand what's going on ( and don't need any ofjavascriptery). Models (snippet): class Link(models.Model): category = models.ForeignKey(Category, blank=False, default=1) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) modified = models.DateTimeField(auto_now=True) url = models.URLField(max_length=1024, unique=True, verify_exists=True) name = models.CharField(max_length=512) def __unicode__(self): return u'%s (%s)' % (self.name, self.url) class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) def __unicode__(self): return u'%s vote for %s' % (self.user, self.link) Views (snippet): def hot(request): links = Link.objects.select_related().annotate(votes=Count('vote')).order_by('-created') for link in links: delta_in_hours = (int(datetime.now().strftime("%s")) - int(link.created.strftime("%s"))) / 3600 link.popularity = ((link.votes - 1) / (delta_in_hours + 2)**1.5) if request.user.is_authenticated(): try: link.voted = Vote.objects.get(link=link, user=request.user) except Vote.DoesNotExist: link.voted = None links = sorted(links, key=lambda x: x.popularity, reverse=True) links = paginate(request, links, 15) return direct_to_template( request, template = 'links/link_list.html', extra_context = { 'links': links, }) The above view actually accomplishes what I need but in what I believe to be a horribly inefficient way. This causes the dreaded n+1 queries, as it stands that's 33 queries for a page containing just 29 links while originally I got away with just 4 queries. I would really prefer to do this using Django's ORM or at least .extra(). Any advice?

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  • django views question

    - by Hulk
    In my django views i have the following def create(request): query=header.objects.filter(id=a)[0] a=query.criteria_set.all() logging.debug(a.details) I get an error saying 'QuerySet' object has no attribute 'details' in the debug statement .What is this error and what should be the correct statemnt to query this.And the model corresponding to this is as follows where as the models has the following: class header(models.Model): title = models.CharField(max_length = 255) created_by = models.CharField(max_length = 255) def __unicode__(self): return self.id() class criteria(models.Model): details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() Thanks..

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  • Creating form object for variable kind of form.

    - by Bunny Rabbit
    i want to create a form for users to submit questions in django ..so far the models i have created are class Question(models.Model): statement=models.CharField(max_length=100) class Choice(models.Model): statement=models.CharField(max_length=100) value=models.IntegerField() question=models.ForeignKey(Question) Now i want to write a Form class for creating a above form but the problem is the number of choices are variable,a user can decide how many choices a question must have .How do i do that in django?

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  • How to retrieve items from a django queryset?

    - by sharataka
    I'm trying to get the video element in a queryset but am having trouble retrieving it. user_channel = Everything.objects.filter(profile = request.user, playlist = 'Channel') print user_channel[0] #returns the first result without error print user_channel[0]['video'] #returns error Models.py: class Everything(models.Model): profile = models.ForeignKey(User) playlist = models.CharField('Playlist', max_length = 2000, null=True, blank=True) platform = models.CharField('Platform', max_length = 2000, null=True, blank=True) video = models.CharField('VideoID', max_length = 2000, null=True, blank=True) video_title = models.CharField('Title of Video', max_length = 2000, null=True, blank=True) def __unicode__(self): return u'%s %s %s %s %s' % (self.profile, self.playlist, self.platform, self.video, self.video_title)

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  • Finding object count where a field is unique in Django

    - by Johnd
    I have a model that is something like this: class Input(models.Model): details = models.CharField(max_length=1000) user = models.ForeignKey(User) class Case(Input): title = models.CharField(max_length=200) views = models.IntegerField() class Argument(Input): case = models.ForeignKey(Case) side = models.BooleanField() A user can submit many arguments, per case. I want to be able to say how many users have submitted side=true arguments. I mean if 1 user had 10 arguments and another user had 2 arguments (both side=true) I'd want the count to be 2, not 12.

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  • TCO Models: Oracle invites you to the next webcast dedicated to Partners on Oracle Hardware and Solutions

    - by mseika
    The Oracle Hardware and Solutions Webcast Series is a sequence of one-hour Sales-Oriented Web Seminars, dedicated to Oracle Partners. This is your opportunity to learn about Oracle's Servers, Storage and Solutions strategy and portfolio, and their business value for you and your customers. The next appointment is for Wednesday, June 22, at 9am UKT / 10am CET:Total Cost of Ownership Models Examples: How we can sell Oracle HW and SW together, with better TCO, and benefits for both Oracle and the Partner!with Ilkka Vanhanen, Business Development Manager, Oracle EMEA Hardware Strategy Organization, who will talk about:   Concrete examples of the HW/SW TCO Model   Understand the competitive advantage provided by Oracle-on-Oracle Solutions   How Partners get new business from Oracle-on-Oracle Solutions   How Oracle is changing the game in Enterprise IT   Key benefits for both SW Resellers and HW Resellers   To register click here , then click on the “Servers and Solutions Webcasts” tab.          

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  • When using MVVM, should you create new viewmodels, or swap out the models?

    - by ConditionRacer
    Say I have a viewmodel like this: public class EmployeeViewModel { private EmployeeModel _model; public Color BackgroundColor { get; set; } public Name { get { return _model.Name; } set { _model.Name = value; NotifyPropertyChanged(Name); } } } So this viewmodel binds to a view that displays an employee. The thing to think about is, does this viewmodel represent an employee, or a "displayable" employee. The viewmodel contains some things that are view specific, for instance the background color. There can be many employees, but only one employee view. With this in mind, when changing the displayed employee, does it make sense to create a new EmployeeViewModel and rebind to the view, or simply swap out the EmployeeModel. Is the distinction even important, or is it a matter of style? I've always leaned toward creating new viewmodels, but I am working on a project where the viewmodels are created once and the models are swapped out. I'm not sure how I feel about this, though it seems to work fine.

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  • Why the cucumber features keeps running even though it fails?

    - by Millisami
    Its a rails 2.3.5 app. I'm using the rspec and cucumber for testing. When I run autospec, it runs correctly with the warning (Not running features. To run features in autotest, set AUTOFEATURE=true.) as below: [~/rails_apps/automation (campaign)?] ? autospec (Not running features. To run features in autotest, set AUTOFEATURE=true.) (Not running features. To run features in autotest, set AUTOFEATURE=true.) loading autotest/rails_rspec /home/millisami/.rvm/rubies/ree-1.8.7-2010.01/lib/ruby/1.8/pathname.rb:263: warning: `*' interpreted as argument prefix /home/millisami/.rvm/rubies/ree-1.8.7-2010.01/bin/ruby /home/millisami/.rvm/gems/ree-1.8.7-2010.01/gems/rspec-1.3.0/bin/spec --autospec /home/millisami/rails_apps/automation/spec/controllers/campaigns_controller_spec.rb /home/millisami/rails_apps/automation/spec/models/board_spec.rb /home/millisami/rails_apps/automation/spec/models/user_spec.rb /home/millisami/rails_apps/automation/spec/models/campaign_spec.rb /home/millisami/rails_apps/automation/spec/controllers/outlets_controller_spec.rb /home/millisami/rails_apps/automation/spec/controllers/boards_controller_spec.rb /home/millisami/rails_apps/automation/spec/models/outlet_type_spec.rb /home/millisami/rails_apps/automation/spec/models/vendor_spec.rb /home/millisami/rails_apps/automation/spec/controllers/brands_controller_spec.rb /home/millisami/rails_apps/automation/spec/controllers/vendors_controller_spec.rb /home/millisami/rails_apps/automation/spec/controllers/dashboard_controller_spec.rb /home/millisami/rails_apps/automation/spec/models/brand_spec.rb /home/millisami/rails_apps/automation/spec/helpers/dashboard_helper_spec.rb /home/millisami/rails_apps/automation/spec/models/outlet_spec.rb /home/millisami/rails_apps/automation/spec/models/client_spec.rb /home/millisami/rails_apps/automation/spec/controllers/clients_controller_spec.rb -O spec/spec.opts Now, as it suggests, when I run AUTOFEATURE=true autospec, the specs runs and the cuke features as well. But the problem is that it won't stop. It runs the features and runs them again and again in a loop. It doesn't stop after it fails. Is this due to the warning Warning: $KCODE is NONE as shown below?? [~/rails_apps/automation (campaign)?] ? AUTOFEATURE=true autospec loading autotest/cucumber_rails_rspec Warning: $KCODE is NONE. /home/millisami/.rvm/gems/ree-1.8.7-2010.01/gems/treetop-1.4.5/lib/treetop/ruby_extensions/string.rb:31: warning: method redefined; discarding old indent /home/millisami/.rvm/rubies/ree-1.8.7-2010.01/lib/ruby/1.8/pathname.rb:263: warning: `*' interpreted as argument prefix /home/millisami/.rvm/gems/ree-1.8.7-2010.01/gems/activesupport-2.3.5/lib/active_support/core_ext/object/blank.rb:49: warning: method redefined; discarding old blank? /home/millisami/.rvm/rubies/ree-1.8.7-2010.01/bin/ruby /home/millisami/.rvm/gems/ree-1.8.7-2010.01/gems/rspec-1.3.0/bin/spec --autospec /home/millisami/rails_apps/automation/spec/controllers/campaigns_controller_spec.rb /home/millisami/rails_apps/automation/spec/models/board_spec.rb /home/millisami/rails_apps/automation/spec/models/user_spec.rb /home/millisami/rails_apps/automation/spec/models/campaign_spec.rb /home/millisami/rails_apps/automation/spec/controllers/outlets_controller_spec.rb /home/millisami/rails_apps/automation/spec/controllers/boards_controller_spec.rb /home/millisami/rails_apps/automation/spec/models/outlet_type_spec.rb /home/millisami/rails_apps/automation/spec/models/vendor_spec.rb /home/millisami/rails_apps/automation/spec/controllers/brands_controller_spec.rb /home/millisami/rails_apps/automation/spec/controllers/vendors_controller_spec.rb /home/millisami/rails_apps/automation/spec/controllers/dashboard_controller_spec.rb /home/millisami/rails_apps/automation/spec/models/brand_spec.rb /home/millisami/rails_apps/automation/spec/helpers/dashboard_helper_spec.rb /home/millisami/rails_apps/automation/spec/models/outlet_spec.rb /home/millisami/rails_apps/automation/spec/models/client_spec.rb /home/millisami/rails_apps/automation/spec/controllers/clients_controller_spec.rb -O spec/spec.opts

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  • Dynamic model choice field in django formset using multiple select elements

    - by Aryeh Leib Taurog
    I posted this question on the django-users list, but haven't had a reply there yet. I have models that look something like this: class ProductGroup(models.Model): name = models.CharField(max_length=10, primary_key=True) def __unicode__(self): return self.name class ProductRun(models.Model): date = models.DateField(primary_key=True) def __unicode__(self): return self.date.isoformat() class CatalogItem(models.Model): cid = models.CharField(max_length=25, primary_key=True) group = models.ForeignKey(ProductGroup) run = models.ForeignKey(ProductRun) pnumber = models.IntegerField() def __unicode__(self): return self.cid class Meta: unique_together = ('group', 'run', 'pnumber') class Transaction(models.Model): timestamp = models.DateTimeField() user = models.ForeignKey(User) item = models.ForeignKey(CatalogItem) quantity = models.IntegerField() price = models.FloatField() Let's say there are about 10 ProductGroups and 10-20 relevant ProductRuns at any given time. Each group has 20-200 distinct product numbers (pnumber), so there are at least a few thousand CatalogItems. I am working on formsets for the Transaction model. Instead of a single select menu with the several thousand CatalogItems for the ForeignKey field, I want to substitute three drop-down menus, for group, run, and pnumber, which uniquely identify the CatalogItem. I'd also like to limit the choices in the second two drop-downs to those runs and pnumbers which are available for the currently selected product group (I can update them via AJAX if the user changes the product group, but it's important that the initial page load as described without relying on AJAX). What's the best way to do this? As a point of departure, here's what I've tried/considered so far: My first approach was to exclude the item foreign key field from the form, add the substitute dropdowns by overriding the add_fields method of the formset, and then extract the data and populate the fields manually on the model instances before saving them. It's straightforward and pretty simple, but it's not very reusable and I don't think it is the right way to do this. My second approach was to create a new field which inherits both MultiValueField and ModelChoiceField, and a corresponding MultiWidget subclass. This seems like the right approach. As Malcolm Tredinnick put it in a django-users discussion, "the 'smarts' of a field lie in the Field class." The problem I'm having is when/where to fetch the lists of choices from the db. The code I have now does it in the Field's __init__, but that means I have to know which ProductGroup I'm dealing with before I can even define the Form class, since I have to instantiate the Field when I define the form. So I have a factory function which I call at the last minute from my view--after I know what CatalogItems I have and which product group they're in--to create form/formset classes and instantiate them. It works, but I wonder if there's a better way. After all, the field should be able to determine the correct choices much later on, once it knows its current value. Another problem is that my implementation limits the entire formset to transactions relating to (CatalogItems from) a single ProductGroup. A third possibility I'm entertaining is to put it all in the Widget class. Once I have the related model instance, or the cid, or whatever the widget is given, I can get the ProductGroup and construct the drop-downs. This would solve the issues with my second approach, but doesn't seem like the right approach.

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  • How to import classes into other classes within the same file in Python

    - by Chris
    I have the file below and it is part of a django project called projectmanager, this file is projectmanager/projects/models.py . Whenever I use the python interpreter to import a Project just to test the functionality i get a name error for line 8 that FileRepo() cannot be found. How Can I import these classes correctly? Ideally what I am looking for is each Project to contain multiple FileRepos which each contain and unknown number of files. Thanks for any assistance in advance. #imports from django.db import models from django.contrib import admin #Project is responsible for ensuring that each project contains all of the folders and file storage #mechanisms a project needs, as well as a unique CCL# class Project(models.Model): ccl = models.CharField(max_length=30) Techpacks = FileRepo() COAS = FileRepo() Shippingdocs = FileRepo() POchemspecs = FileRepo() Internalpos = FileRepo() Finalreports = FileRepo() Batchrecords = FileRepo() RFPS = FileRepo() Businessdev = FileRepo() QA = FileRepo() Updates = FileRepo() def __unicode__(self): return self.ccl #ProjectFile is the file object used by each FileRepo component class ProjectFile(models.Model): file = models.FileField(uploadto='ProjectFiles') def __unicode__(self): return self.file #FileRepo is the model for the "folders" to be used in a Project class FileRepo(models.Model): typeOf = models.CharField(max_length=30) files = models.ManyToManyField(ProjectFile) def __unicode__(self): return self.typeOf

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  • extending django usermodel

    - by imran-glt
    Hi i am trying to create a signup form for my django app. for this i have extended the user model. This is my Forms.py from contact.models import register from django import forms from django.contrib import auth class registerForm(forms.ModelForm): class Meta: model=register fields = ('latitude', 'longitude', 'status') class Meta: model = auth.models.User # this gives me the User fields fields = ('username', 'first_name', 'last_name', 'email') and this is my model.py from django.db import models from django.contrib.auth.models import User STATUS_CHOICES = ( ('Online', 'Online.'), ('Busy', 'Busy.'), ('AppearOffline', 'AppearOffline.'),) class register(models.Model): user = models.ForeignKey('auth.User', unique = True) latitude = models.DecimalField(max_digits=8, decimal_places=6) longitude = models.DecimalField(max_digits=8, decimal_places=6) status = models.CharField(max_length=8,choices=STATUS_CHOICES, blank= True, null=True) i dont know where i am making a mistake. the users passwords are not accepted at the login and the latitude and logitude are not saved against the created user user. i am fiarly new to django and dont know what to do any body have any solution .?

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  • django 1.1 beta issue

    - by ha22109
    Hello all, I m using django 1.1 beta.I m facing porblem in case of list_editable.First it was throughing exception saying need ordering in case of list_editable" then i added ordering in model but know it is giving me error.The code is working fine with django1.1 final. here is my code model.py class User(models.Model): advertiser = models.ForeignKey(WapUser,primary_key=True) status = models.CharField(max_length=20,choices=ADVERTISER_INVITE_STATUS,default='invited') tos_version = models.CharField(max_length=5) contact_email = models.EmailField(max_length=80) contact_phone = models.CharField(max_length=15) contact_mobile = models.CharField(max_length=15) contact_person = models.CharField(max_length=80) feedback=models.BooleanField(choices=boolean_choices,default=0) def __unicode__(self): return self.user.login class Meta: db_table = u'roi_advertiser_info' managed=False ordering=['feedback',] admin.py class UserAdmin(ReadOnlyAdminFields, admin.ModelAdmin): list_per_page = 15 fields = ['advertiser','contact_email','contact_phone','contact_mobile','contact_person'] list_display = ['advertiser','contact_email','contact_phone','contact_mobile','contact_person','status','feedback'] list_editable=['feedback'] readonly = ('advertiser',) search_fields = ['advertiser__login_id'] radio_fields={'approve_auto': admin.HORIZONTAL} list_filter=['status','feedback'] admin.site.register(User,UserADmin)

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  • Why is Django reverse() failing with unicode?

    - by JeffS
    Here is a django models file that is not working as I would expect. I would expect the to_url method to do the reverse lookup in the urls.py file, and get a url that would correspond to calling that view with arguments supplied by the Arguments model. from django.db import models class Element(models.Model): viewname = models.CharField(max_length = 200) arguments = models.ManyToManyField('Argument', null = True, blank = True ) @models.permalink def to_url(self): d = dict( self.arguments.values_list('key', 'value') ) return (self.viewname, (), d) class Argument(models.Model): key = models.CharField(max_length=200) value = models.CharField(max_length=200) The value d ends up as a dictionary from a unicode string to another unicode string, which I believe, should work fine with the reverse() method that would be called by the permalink decorator, however, it results in: TypeError: reverse() keywords must be strings

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  • django admin gives warning "Field 'X' doesn't have a default value"

    - by noam
    I have created two models out of an existing legacy DB , one for articles and one for tags that one can associate with articles: class Article(models.Model): article_id = models.AutoField(primary_key=True) text = models.CharField(max_length=400) class Meta: db_table = u'articles' class Tag(models.Model): tag_id = models.AutoField(primary_key=True) tag = models.CharField(max_length=20) article=models.ForeignKey(Article) class Meta: db_table = u'article_tags' I want to enable adding tags for an article from the admin interface, so my admin.py file looks like this: from models import Article,Tag from django.contrib import admin class TagInline(admin.StackedInline): model = Tag class ArticleAdmin(admin.ModelAdmin): inlines = [TagInline] admin.site.register(Article,ArticleAdmin) The interface looks fine, but when I try to save, I get: Warning at /admin/webserver/article/382/ Field 'tag_id' doesn't have a default value

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  • list editabale error

    - by ha22109
    Hello all, I m using django 1.1 beta.I m facing porblem in case of list_editable.First it was throughing exception saying need ordering in case of list_editable" then i added ordering in model but know it is giving me error.The code is working fine with django1.1 final. here is my code model.py class User(models.Model): advertiser = models.ForeignKey(WapUser,primary_key=True) status = models.CharField(max_length=20,choices=ADVERTISER_INVITE_STATUS,default='invited') tos_version = models.CharField(max_length=5) contact_email = models.EmailField(max_length=80) contact_phone = models.CharField(max_length=15) contact_mobile = models.CharField(max_length=15) contact_person = models.CharField(max_length=80) feedback=models.BooleanField(choices=boolean_choices,default=0) def __unicode__(self): return self.user.login class Meta: db_table = u'roi_advertiser_info' managed=False ordering=['feedback',] admin.py class UserAdmin(ReadOnlyAdminFields, admin.ModelAdmin): list_per_page = 15 fields = ['advertiser','contact_email','contact_phone','contact_mobile','contact_person'] list_display = ['advertiser','contact_email','contact_phone','contact_mobile','contact_person','status','feedback'] list_editable=['feedback'] readonly = ('advertiser',) search_fields = ['advertiser__login_id'] radio_fields={'approve_auto': admin.HORIZONTAL} list_filter=['status','feedback'] admin.site.register(User,UserADmin)

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  • Django save, column specified twice

    - by realshadow
    Hey, I would like to save a modified model, but I get Programming error - that a field is specified twice. class ProductInfo(models.Model): product_info_id = models.AutoField(primary_key=True) language_id = models.IntegerField() product_id = models.IntegerField() description = models.TextField(blank=True) status = models.IntegerField() model = models.CharField(max_length=255, blank=True) label = models.ForeignKey(Category_info, verbose_name = 'Category_info', db_column = 'language_id', to_field = 'node_id', null = True) I get this error because the foreign key uses as db_column language_id. If I will delete it, my object will be saved properly. I dont quite understand whats going on and since I have defined almost all of my models this way, I fear its totally wrong or maybe I just missunderstood it... Any ideas? Regards

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  • Prepopulate drop-box according to another drop-box choice in Django Admin

    - by onorua
    I have models like this: class User(models.Model): Switch = models.ForeignKey(Switch, related_name='SwitchUsers') Port = models.ForeignKey(Port) class Switch(models.Model): Name = models.CharField(max_length=50) class Port(models.Model): PortNum = models.PositiveIntegerField() Switch = models.ForeignKey(Switch, related_name = "Ports") When I'm in Admin interface and choose Switch from Switches available, I would like to have Port prepopulated accordingly with Ports from the related Switch. As far as I understand I need to create some JS script to prepopulate it. Unfortunately I don't have this experience, and I would like to keep things simple as it possible and don't rewrite all Django admin interface. Just add this functionality for one Field. Could you please help me with my problem? Thank you.

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  • Django: Geocoding an address on form submission?

    - by User
    Trying to wrap my head around django forms and the django way of doing things. I want to create a basic web form that allows a user to input an address and have that address geocoded and saved to a database. I created a Location model: class Location(models.Model): address = models.CharField(max_length=200) city = models.CharField(max_length=100) state = models.CharField(max_length=100, null=True) postal_code = models.CharField(max_length=100, null=True) country = models.CharField(max_length=100) latitude = models.DecimalField(max_digits=18, decimal_places=10, null=True) longitude = models.DecimalField(max_digits=18, decimal_places=10, null=True) And defined a form: class LocationForm(forms.ModelForm): class Meta: model = models.Location exclude = ('latitude','longitude') In my view I'm using form.save() to save the form. This works and saves an address to the database. I created a module to geocode an address. I'm not sure what the django way of doing things is, but I guess in my view, before I save the form, I need to geocode the address and set the lat and long. How do I set the latitude and longitude before saving?

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  • Trying and expand the contrib.auth.user model and add a "relatipnships" manage

    - by dotty
    I have the following model setup. from django.db import models from django.contrib.auth.models import User class SomeManager(models.Manager): def friends(self): # return friends bla bla bla class Relationship(models.Model): """(Relationship description)""" from_user = models.ForeignKey(User, related_name='from_user') to_user = models.ForeignKey(User, related_name='to_user') has_requested_friendship = models.BooleanField(default=True) is_friend = models.BooleanField(default=False) objects = SomeManager() relationships = models.ManyToManyField(User, through=Relationship, symmetrical=False) relationships.contribute_to_class(User, 'relationships') Here i take the User object and use contribute_to_class to add 'relationships' to the User object. The relationship show up, but if call User.relationships.friends it should run the friends() method, but its failing. Any ideas how i would do this? Thanks

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  • Django admin page dropdowns

    - by zen
    I am building a high school team application using Django. Here is my working models file: class Directory(models.Model): school = models.CharField(max_length=60) website = models.URLField() district = models.SmallIntegerField() conference = models.ForeignKey(Conference) class Conference(models.Model): conference_name = models.CharField(max_length=50) url = models.URLField() class Meta: ordering = ['conference_name'] When I open my admin pages and go to edit a school's conference the drop down looks like this: <select> <option value="1">Conference Object</option> <option value="2">Conference Object</option> <select> How do I replace "Conference Object" with the conference_name?

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  • DJANGO complex modelling

    - by SledgehammerPL
    Hello. I have such model now: receipt contains components. component contain product. The difference between component and product is, that component has quantity and measure unit: eg. component is 100g sugar - sugar is a product. So I need to make lots of components to satisfy different recipes - 100g sugar is not equal 200g sugar I wonder if I can remodel it to kick off components - in pure sql it's rather easy, but I'm trying to USE django - not making workarounds. class Receipt(models.Model): name = models.CharField(max_length=128) (...) components = models.ManyToManyField(Component) class Component(models.Model): quantity = models.FloatField(max_length=9) unit = models.ForeignKey(Unit) product = models.ForeignKey(Product) class Product(models.Model): name = models.CharField(max_length = 128) TIA

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  • Database Error django

    - by Megan
    DatabaseError at /admin/delmarva/event/ no such column: delmarva_event.eventdate I created a class in my models.py file: from django.db import models from django.contrib.auth.models import User class Event(models.Model): eventname = models.CharField(max_length = 100) eventdate = models.DateField() eventtime = models.TimeField() address = models.CharField(max_length = 200) user = models.ForeignKey(User) def __unicode__(self): return self.eventname and now when i try to view my events in my admin or my main_page it gives me the error that there is no eventdate. I tried syncing the db again but nothing changed. Also, I hashtagged eventdate out to see if I get a different error and then it states that delmarva_event.eventtime does not exist as well. I It is weird because it does not have a problem with eventname. Any suggestions would be greatly appreciated!

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  • Deleting files associated with model - django

    - by alexBrand
    I have the following code in one of my models class PostImage(models.Model): post = models.ForeignKey(Post, related_name="images") # @@@@ figure out a way to have image folders per user... image = models.ImageField(upload_to='images') image_infowindow = models.ImageField(upload_to='images') image_thumb = models.ImageField(upload_to='images') image_web = models.ImageField(upload_to='images') description = models.CharField(max_length=100) order = models.IntegerField(null=True) IMAGE_SIZES = { 'image_infowindow':(70,70), 'image_thumb':(100,100), 'image_web':(640,480), } def delete(self, *args, **kwargs): # delete files.. self.image.delete(save=False) self.image_thumb.delete(save=False) self.image_web.delete(save=False) self.image_infowindow.delete(save=False) super(PostImage, self).delete(*args, **kwargs) I am trying to delete the files when the delete() method is called on PostImage. However, the files are not being removed. As you can see, I am overriding the delete() method, and deleting each ImageField. For some reason however, the files are not being removed.

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  • How to design Models the correct way: Object-oriented or "Package"-oriented?

    - by ajsie
    I know that in OOP you want every object (from a class) to be a "thing", eg. user, validator etc. I know the basics about MVC, how they different parts interact with each other. However, i wonder if the models in MVC should be designed according to the traditional OOP design, that is to say, should every model be a database/table/row (solution 2)? Or is the intention more like to collect methods that are affecting the same table or a bunch of related tables (solution 1). example for an Address book module in CodeIgniter, where i want be able to "CRUD" a Contact and add/remove it to/from a CRUD-able Contact Group. Models solution 1: bunching all related methods together (not real object, rather a "package") class Contacts extends Model { function create_contact() {) function read_contact() {} function update_contact() {} function delete_contact() {} function add_contact_to_group() {} function delete_contact_from_group() {} function create_group() {} function read_group() {} function update_group() {} function delete_group() {} } Models solution 2: the OOP way (one class per file) class Contact extends Model { private $name = ''; private $id = ''; function create_contact() {) function read_contact() {} function update_contact() {} function delete_contact() {} } class ContactGroup extends Model { private $name = ''; private $id = ''; function add_contact_to_group() {} function delete_contact_from_group() {} function create_group() {} function read_group() {} function update_group() {} function delete_group() {} } i dont know how to think when i want to create the models. and the above examples are my real tasks for creating an Address book. Should i just bunch all functions together in one class. then the class contains different logic (contact and group), so it can not hold properties that are specific for either one of them. the solution 2 works according to the OOP. but i dont know why i should make such a dividing. what would the benefits be to have a Contact object for example. Its surely not a User object, so why should a Contact "live" with its own state (properties and methods). you experienced guys with OOP/MVC, please shed a light on how one should think here in this very concrete task.

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  • Doctrine MYSQL 150+ tables: generating models works, but not vice-versa?

    - by ropstah
    I can generate my models and schema.yml file based on an existing database. But when I try to do it the other way around using Doctrine::createTablesFromModels() i get an error: Syntax error or access violation: 1064 So either of these works: Doctrine::generateYamlFromDb(APPPATH . 'models/yaml'); Doctrine::generateYamlFromModels(APPPATH . 'models/yaml', APPPATH . 'models'); Doctrine::generateModelsFromYaml(APPPATH . 'models/yaml', APPPATH . 'models', array('generateTableClasses' => true)); Doctrine::generateModelsFromDb(APPATH . 'models', array('default'), array('generateTableClasses' => true)); But this fails (it drops/creates the database and around 50 tables): Doctrine::dropDatabases(); Doctrine::createDatabases(); Doctrine::createTablesFromModels(); The partially outputted SQL query shows that the error is around the Notification object which looks like this: Any leads would be highly appreciated! <?php // Connection Component Binding Doctrine_Manager::getInstance()->bindComponent('Notification', 'default'); /** * BaseNotification * * This class has been auto-generated by the Doctrine ORM Framework * * @property integer $n_auto_key * @property integer $type * @property string $title * @property string $message * @property timestamp $entry_date * @property timestamp $update_date * @property integer $u_auto_key * @property integer $c_auto_key * @property integer $ub_auto_key * @property integer $o_auto_key * @property integer $notified * @property integer $read * @property integer $urgence * * @package ##PACKAGE## * @subpackage ##SUBPACKAGE## * @author ##NAME## <##EMAIL##> * @version SVN: $Id: Builder.php 6820 2009-11-30 17:27:49Z jwage $ */ abstract class BaseNotification extends Doctrine_Record { public function setTableDefinition() { $this->setTableName('Notification'); $this->hasColumn('n_auto_key', 'integer', 4, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => true, 'autoincrement' => true, 'length' => '4', )); $this->hasColumn('type', 'integer', 1, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '1', )); $this->hasColumn('title', 'string', 50, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '50', )); $this->hasColumn('message', 'string', null, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '', )); $this->hasColumn('entry_date', 'timestamp', 25, array( 'type' => 'timestamp', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '25', )); $this->hasColumn('update_date', 'timestamp', 25, array( 'type' => 'timestamp', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => false, 'autoincrement' => false, 'length' => '25', )); $this->hasColumn('u_auto_key', 'integer', 4, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '4', )); $this->hasColumn('c_auto_key', 'integer', 4, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => false, 'autoincrement' => false, 'length' => '4', )); $this->hasColumn('ub_auto_key', 'integer', 4, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => false, 'autoincrement' => false, 'length' => '4', )); $this->hasColumn('o_auto_key', 'integer', 4, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => false, 'autoincrement' => false, 'length' => '4', )); $this->hasColumn('notified', 'integer', 1, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'default' => '0', 'notnull' => true, 'autoincrement' => false, 'length' => '1', )); $this->hasColumn('read', 'integer', 1, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'default' => '0', 'notnull' => true, 'autoincrement' => false, 'length' => '1', )); $this->hasColumn('urgence', 'integer', 1, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'default' => '0', 'notnull' => true, 'autoincrement' => false, 'length' => '1', )); } public function setUp() { parent::setUp(); } }

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