Search Results

Search found 6394 results on 256 pages for 'regular expressions'.

Page 37/256 | < Previous Page | 33 34 35 36 37 38 39 40 41 42 43 44  | Next Page >

  • SQLAlchemy DetachedInstanceError with regular attribute (not a relation)

    - by haridsv
    I just started using SQLAlchemy and get a DetachedInstanceError and can't find much information on this anywhere. I am using the instance outside a session, so it is natural that SQLAlchemy is unable to load any relations if they are not already loaded, however, the attribute I am accessing is not a relation, in fact this object has no relations at all. I found solutions such as eager loading, but I can't apply to this because this is not a relation. I even tried "touching" this attribute before closing the session, but it still doesn't prevent the exception. What could be causing this exception for a non-relational property even after it has been successfully accessed once before? Any help in debugging this issue is appreciated. I will meanwhile try to get a reproducible stand-alone scenario and update here. Update: This is the actual exception message with a few stacks: File "/home/hari/bin/lib/python2.6/site-packages/SQLAlchemy-0.6.1-py2.6.egg/sqlalchemy/orm/attributes.py", line 159, in __get__ return self.impl.get(instance_state(instance), instance_dict(instance)) File "/home/hari/bin/lib/python2.6/site-packages/SQLAlchemy-0.6.1-py2.6.egg/sqlalchemy/orm/attributes.py", line 377, in get value = callable_(passive=passive) File "/home/hari/bin/lib/python2.6/site-packages/SQLAlchemy-0.6.1-py2.6.egg/sqlalchemy/orm/state.py", line 280, in __call__ self.manager.deferred_scalar_loader(self, toload) File "/home/hari/bin/lib/python2.6/site-packages/SQLAlchemy-0.6.1-py2.6.egg/sqlalchemy/orm/mapper.py", line 2323, in _load_scalar_attributes (state_str(state))) DetachedInstanceError: Instance <ReportingJob at 0xa41cd8c> is not bound to a Session; attribute refresh operation cannot proceed The partial model looks like this: metadata = MetaData() ModelBase = declarative_base(metadata=metadata) class ReportingJob(ModelBase): __tablename__ = 'reporting_job' job_id = Column(BigInteger, Sequence('job_id_sequence'), primary_key=True) client_id = Column(BigInteger, nullable=True) And the field client_id is what is causing this exception with a usage like the below: Query: jobs = session \ .query(ReportingJob) \ .filter(ReportingJob.job_id == job_id) \ .all() if jobs: # FIXME(Hari): Workaround for the attribute getting lazy-loaded. jobs[0].client_id return jobs[0] This is what triggers the exception later out of the session scope: msg = msg + ", client_id: %s" % job.client_id

    Read the article

  • How do I extract a postcode from one column in SSIS using regular expression

    - by Aphillippe
    I'm trying to use a custom regex clean transformation (information found here ) to extract a post code from a mixed address column (Address3) and move it to a new column (Post Code) Example of incoming data: Address3: "London W12 9LZ" Incoming data could be any combination of place names with a post code at the start, middle or end (or not at all). Desired outcome: Address3: "London" Post Code: "W12 9LZ" Essentially, in plain english, "move (not copy) any post code found from address3 into Post Code". My regex skills aren't brilliant but I've managed to get as far as extracting the post code and getting it into its own column using the following regex, matching from Address3 and replacing into Post Code: Match Expression: (?<stringOUT>([A-PR-UWYZa-pr-uwyz]([0-9]{1,2}|([A-HK-Ya-hk-y][0-9]|[A-HK-Ya-hk-y][0-9] ([0-9]|[ABEHMNPRV-Yabehmnprv-y]))|[0-9][A-HJKS-UWa-hjks-uw])\ {0,1}[0-9][ABD-HJLNP-UW-Zabd-hjlnp-uw-z]{2}|([Gg][Ii][Rr]\ 0[Aa][Aa])|([Ss][Aa][Nn]\ {0,1}[Tt][Aa]1)|([Bb][Ff][Pp][Oo]\ {0,1}([Cc]\/[Oo]\ )?[0-9]{1,4})|(([Aa][Ss][Cc][Nn]|[Bb][Bb][Nn][Dd]|[BFSbfs][Ii][Qq][Qq]|[Pp][Cc][Rr][Nn]|[Ss][Tt][Hh][Ll]|[Tt][Dd][Cc][Uu]|[Tt][Kk][Cc][Aa])\ {0,1}1[Zz][Zz]))) Replace Expression: ${stringOUT} So this leaves me with: Address3: "London W12 9LZ" Post Code: "W12 9LZ" My next thought is to keep the above match/replace, then add another to match anything that doesn't match the above regex. I think it might be a negative lookahead but I can't seem to make it work. I'm using SSIS 2008 R2 and I think the regex clean transformation uses .net regex implementation. Thanks.

    Read the article

  • regular expression for indian vehicle number

    - by I Like PHP
    i need validation for indian vehicle NUMBER here are condition list let expression is (x)(y)(z)(m)(a)(b)(c) 1. (x) contains only alphabets of length 2. 2. (y) may be - or single space ' ' 3. (z) contains only numbers of length 2 4. (m) may be or , or single space ' ' 5. length of (a) can be 2 or 3. contains alphanumeric value with minimum one alphabetic character. 6. (b) may be - or single space ' ' ( similar to (y) ) 7. (c) contains only numbers of length 4 i show you the various examples of vehicle number valid number RJ-14,NL-1234 RJ-01,4M-5874 RJ-07,14M-2345 RJ 07,3M 2345 RJ-07,3M-8888 RJ 07 4M 2345 RJ 07,4M 2933 invalid number RJ-07 3M 1234 ( both (y) and (b) should be same). RJ-07 M3-1234 ((a) must ends with alphabat). rj-07 M3-123 ( length of (c) must be 4).

    Read the article

  • Matching Regular Expression in Javascript and PHP problem...

    - by Frankie
    I can't figure out how to get the same result from my Javscript as I do from my PHP. In particular, Javascript always leaves out the backslashes. Please ignore the random forward and backslashes; I put them there so that I can cover my basis on a windows system or any other system. Output: Input String: "/root\wp-cont ent\@*%'i@$@%$&^(@#@''mage6.jpg:" /root\wp-content\image6.jpg (PHP Output) /rootwp-contentimage6.jpg (Javscript Output) I would appreciate any help! PHP: <?php $path ="/root\wp-cont ent\@*%'i@$@%$&^(@#@''mage6.jpg:"; $path = preg_replace("/[^a-zA-Z0-9\\\\\/\.-]/", "", $path); echo $path; ?> Javascript: <script type="text/javascript"> var path = "/root\wp-cont ent\@*%'i@$@%$&^(@#@''mage6.jpg:"; //exact same string as PHP var regx = /[^a-zA-Z0-9\.\/-]/g; path = path.replace(regx,""); document.write("<br>"+path); </script>

    Read the article

  • Bash: Extract Range with Regular Expressioin (maybe sed?)

    - by sixtyfootersdude
    I have a file that is similar to this: <many lines of stuff> SUMMARY: <some lines of stuff> END OF SUMMARY I want to extract just the stuff between SUMMARY and END OF SUMMARY. I suspect I can do this with sed but I am not sure how. I know I can modify the stuff in between with this: sed "/SUMMARY/,/END OF SUMMARY/ s/replace/with/" fileName (But not sure how to just extract that stuff). I am Bash on Solaris.

    Read the article

  • How to use regular expression in lxml xpath?

    - by Arty
    I'm using construction like this: doc = parse(url).getroot() links = doc.xpath("//a[text()='some text']") But I need to select all links which have text beginning with "some text", so I'm wondering is there any way to use regexp here? Didn't find anything in lxml documentation

    Read the article

  • C# differences between Windows Mobile and regular Windows

    - by Matt
    Are there many differences between Windows and Windows Mobile as far as C# programming is concerned? I can write some moderately complicated programs in C#, but I'm not sure if it would just run perfectly on a Windows smartphone, or if something has to be done to port it. If so, is there a tool that will automatically revise code to make it mobile-compatible? The reason I ask is that the new Windows mobile 7 will only support a few methods of app development, one of which is C#. Also, do smartphones with non-windows operating systems have C# support available? Or can C# code be converted to Symbian or iPhone or whatever? Thanks for any help you can provide.

    Read the article

  • regular expression to get the filename from urls

    - by robert
    if i have a textbox with severals urls rapidshare.com/files/379028801/Fringe.S02E19.HDTV.XviD-LOL.avi rapidshare.com/files/379182651/Fringe.S02E19.720p.HDTV.X264-DIMENSION.mkv rapidshare.com/files/379180004/Fringe.S02E19.720p.HDTV.X264-DIMENSION.part1.rar rapidshare.com/files/379180444/Fringe.S02E19.720p.HDTV.X264-DIMENSION.part2.rar rapidshare.com/files/379181251/Fringe.S02E19.720p.HDTV.X264-DIMENSION.part3.rar rapidshare.com/files/379181743/Fringe.S02E19.720p.HDTV.X264-DIMENSION.part4.rar i need a the files name and its urls textbox2.text = Fringe.S02E19.HDTV.XviD-LOL.avi from here rapidshare.com/files/379028801/Fringe.S02E19.HDTV.XviD-LOL.avi Fringe.S02E19.720p.HDTV.X264-DIMENSION.part1.rar from here rapidshare.com/files/379180004/Fringe.S02E19.720p.HDTV.X264-DIMENSION.part1.rar and so on Thanks :)

    Read the article

  • Regular expression to validate a Google Analytics UA Number

    - by Otis
    It's not 100 percent clear to me that the Google Analytics UA Numbers are always 6 digits, a dash, and 2 digits as Google often mentions in their documentation. There are frequent counter-examples that use fewer than 6 for the account portion and 1-4 for the profile. All of the examples always show numbers but it's not even clear that they can't be letters. Does anyone know if Google has published a regex that exactly matches allowable UA Numbers? I'm adding this feature to the admin console of an application I work on and would like to validate the user input.

    Read the article

  • Regular Expression Help in .NET

    - by Matt H.
    I have a simple pattern I am trying to match, any characters captured between parenthesis at the end of an HTML paragraph. I am running into trouble any time there is additional parentheticals in that paragraph: i.e. If the input string is "..... (321)</p" i want to get the value (321) However, if the paragraph has this text: "... (123) (321)</p" my regex is returning "(123) (321)" (everything between the opening "(" and closing ")" I am using the regex pattern "\s(.+)</p" How can I grab the correct value (using VB.NET) This is what I'm doing so far: Dim reg As New Regex("\s\(.+\)</P>", RegexOptions.IgnoreCase) Dim matchC As MatchCollection = reg.Matches(su.Question) If matchC.Count > 0 Then Dim lastMatch As Match = matchC(matchC.Count - 1) Dim DesiredValue As String = lastMatch.Value End If

    Read the article

  • Regular expression for email

    - by Nadeem
    I tried the reg expression ^([a-zA-Z0-9_.-])+@([a-zA-Z0-9_.-])+\.([a-zA-Z])+([a-zA-Z])+ for the email validation. Since I want the user to allow submitting even with the empty email address. So I changed the reg ex to (^([a-zA-Z0-9_.-])+@([a-zA-Z0-9_.-])+\.([a-zA-Z])+([a-zA-Z])+)? But this expression accepts any email address without any validation.

    Read the article

  • python regular expression for domain names

    - by user230911
    I am trying use the following regression to extract domain name from a text, but it just produce nothing, what's wrong with it? I don't know if this is suitable to ask this "fix code" question, maybe I should read more. I just want to save some time. Thanks pat_url = re.compile(r''' (?:https?://)* (?:[\w]+[\-\w]+[.])* (?P<domain>[\w\-]*[\w.](com|net)([.](cn|jp|us))*[/]*) ''') print re.findall(pat_url,"http://www.google.com/abcde") I want the output to be google.com

    Read the article

  • xml regular expression/regex OR operator

    - by Naz Haque
    Hi am trying to use a regeX to read through my document to identify currency types whether they're $,£ or a €. The regex I've created doesn't seem to work, somebody please advise me what it should be. I'd really appreciate the help: The regEX I've created ("\$|£|€]")is in a simpleType within my XSD file used for validating a document. The code is show after the colon, please note to display on stackoverflow I've had to remove the open/close tags (<): xs:simpleType name="currencyType" xs:restriction base="utf8-string" xs:length value="1" / xs:pattern value="[\$|£|€]"/ /xs:restriction /xs:simpleType

    Read the article

  • Respect regular onsubmit handlers from jQuery.submit

    - by orip
    I want a jQuery form submit handler to respect any previous submit handlers, including ones added with onsubmit. I'm trying to detect the previous handler's return value but can't seem to do it: <form><input type="submit" /></form> <script type="text/javascript"> $('form')[0].onsubmit = function() { return false; }; // called first $('form').submit(function(e) { console.log(e.result); // undefined console.log(e.isDefaultPrevented()); // false console.log(e.isPropagationStopped()); // false console.log(e.isImmediatePropagationStopped()); // false }); </script> Is there a way to do this?

    Read the article

  • Regular Expression Longes Possible Matching

    - by syker
    So I have an input string which is a directory addres: Example: ProgramFiles/Micro/Telephone And I want to match it against a list of words very strictly: Example: Tel|Tele|Telephone I want to match against Telephone and not Tel. Right now my reg looks like this: my( $output ) = ( $input =~ m/($list)/o ); The regex above will match against Tel. What can I do to fix it?

    Read the article

  • PHP Regular Expression

    - by saturngod
    I want to change &lt;lang class='brush:xhtml'&gt;test&lt;/lang&gt; to <pre class='brush:xhtml'>test</pre> my code like that. <?php $content="&lt;lang class='brush:xhtml'&gt;test&lt;/lang&gt;"; $pattern=array(); $replace=array(); $pattern[0]="/&lt;lang class=([A-Za-z='\":])* &lt;/"; $replace[0]="<pre $1>"; $pattern[1]="/&lt;lang&gt;/"; $replace[1]="</pre>"; echo preg_replace($pattern, $replace,$content); ?> but it's not working. How to change my code or something wrong in my code ?

    Read the article

  • vim regular expression

    - by chappar
    I have following text in a file 23456789 When i tried to replace the above text using command 1,$s/\(\d\)\(\d\d\d\)\(\d\d\)*\>/\3\g I am getting 89. Should't it be 6789? Can anyone tell me why it is 89.

    Read the article

  • Simple java regular expression replace question.

    - by Yang
    I have a simple xml file and I want to remove everything before the first tag. ..... item1 .... The following java code is not working: String cleanxml = rawxml.replace("^[\\s\\S]+<item>", ""); What is the correct way to do this? And how do I address the non-greedy issue? Sorry I'm a C# programmer.

    Read the article

  • Racket regular-expression matching

    - by Inaimathi
    I'm trying to create a regex that matches the inverse of a certain string type (so, strings not ending in ".js", for example). According to the documentation, that should be the expression #rx"(?!\\.js$)", but it doesn't seem to work. To test it out, I have this function: (define (match-test regex) (map (lambda (text) (regexp-match? regex text)) '("foo.js" "bar.css" "baz.html" "mumble.gif" "foobar"))) (match-test #rx"\\.js$") returns (#t #f #f #f #f) as expected, but (match-test #rx"(?!\\.js$)") returns (#t #t #t #t #t), where I would expect (#f #t #t #t #t). What am I doing wrong, and how do I actually get a regex in Racket to express the idea "match anything which does not contain [x]"?

    Read the article

< Previous Page | 33 34 35 36 37 38 39 40 41 42 43 44  | Next Page >