Search Results

Search found 19109 results on 765 pages for 'canonical url'.

Page 371/765 | < Previous Page | 367 368 369 370 371 372 373 374 375 376 377 378  | Next Page >

  • how to handle out of memory error?

    - by UMMA
    dear friends, i am using following code to display bitmap in my imageview. when i try to load image of size for example bigger than 1.5MB it give me error any one suggest me solution? try { URL aURL = new URL(myRemoteImages[val]); URLConnection conn = aURL.openConnection(); conn.connect(); InputStream is = null; try { is= conn.getInputStream(); }catch(IOException e) { return 0; } int a= conn.getConnectTimeout(); BufferedInputStream bis = new BufferedInputStream(is); Bitmap bm; try { bm = BitmapFactory.decodeStream(bis); }catch(Exception ex) { bis.close(); is.close(); return 0; } bis.close(); is.close(); img.setImageBitmap(bm); } catch (IOException e) { return 0; } return 1; Log cat 06-14 12:03:11.701: ERROR/AndroidRuntime(443): Uncaught handler: thread main exiting due to uncaught exception 06-14 12:03:11.861: ERROR/AndroidRuntime(443): java.lang.OutOfMemoryError: bitmap size exceeds VM budget 06-14 12:03:11.861: ERROR/AndroidRuntime(443): at android.graphics.BitmapFactory.nativeDecodeStream(Native Method)

    Read the article

  • Apply a Quartz filter while saving PDF under Mac OS X 10.6.3

    - by olpa
    Using Mac OS X API, I'm trying to save a PDF file with a Quartz filter applied, just like it is possible from the "Save As" dialog in the Preview application. So far I've written the following code (using Python and pyObjC, but it isn't important for me): -- filter-pdf.py: begin from Foundation import * from Quartz import * import objc page_rect = CGRectMake (0, 0, 612, 792) fdict = NSDictionary.dictionaryWithContentsOfFile_("/System/Library/Filters/Blue \ Tone.qfilter") in_pdf = CGPDFDocumentCreateWithProvider(CGDataProviderCreateWithFilename ("test .pdf")) url = CFURLCreateWithFileSystemPath(None, "test_out.pdf", kCFURLPOSIXPathStyle, False) c = CGPDFContextCreateWithURL(url, page_rect, fdict) np = CGPDFDocumentGetNumberOfPages(in_pdf) for ip in range (1, np+1): page = CGPDFDocumentGetPage(in_pdf, ip) r = CGPDFPageGetBoxRect(page, kCGPDFMediaBox) CGContextBeginPage(c, r) CGContextDrawPDFPage(c, page) CGContextEndPage(c) -- filter-pdf.py: end Unfortunalte, the filter "Blue Tone" isn't applied, the output PDF looks exactly as the input PDF. Question: what I missed? How to apply a filter? Well, the documentation doesn't promise that such way of creating and using "fdict" should cause that the filter is applied. But I just rewritten (as far as I can) sample code /Developer/Examples/Quartz/Python/filter-pdf.py, which was distributed with older versions of Mac (meanwhile, this code doesn't work too): ----- filter-pdf-old.py: begin from CoreGraphics import * import sys, os, math, getopt, string def usage (): print ''' usage: python filter-pdf.py FILTER INPUT-PDF OUTPUT-PDF Apply a ColorSync Filter to a PDF document. ''' def main (): page_rect = CGRectMake (0, 0, 612, 792) try: opts,args = getopt.getopt (sys.argv[1:], '', []) except getopt.GetoptError: usage () sys.exit (1) if len (args) != 3: usage () sys.exit (1) filter = CGContextFilterCreateDictionary (args[0]) if not filter: print 'Unable to create context filter' sys.exit (1) pdf = CGPDFDocumentCreateWithProvider (CGDataProviderCreateWithFilename (args[1])) if not pdf: print 'Unable to open input file' sys.exit (1) c = CGPDFContextCreateWithFilename (args[2], page_rect, filter) if not c: print 'Unable to create output context' sys.exit (1) for p in range (1, pdf.getNumberOfPages () + 1): #r = pdf.getMediaBox (p) r = pdf.getPage(p).getBoxRect(p) c.beginPage (r) c.drawPDFDocument (r, pdf, p) c.endPage () c.finish () if __name__ == '__main__': main () ----- filter-pdf-old.py: end

    Read the article

  • how to dispaly image in grid view reading imageUrl from xml using sax parser in android

    - by Pramod kuamr
    thanks for answer but i am able to read xml file from url but i need if in xml imageUrl is there so show in grid view ..this is my xml file and read URL <?xml version="1.0" encoding="UTF-8"?> <channels> <channel> <name>ndtv</name> <logo>http://a3.twimg.com/profile_images/670625317/aam-logo--twitter.png</logo> <description>this is a news Channel</description> <rssfeed>ndtv.com</rssfeed> </channel> <channel> <name>star news</name> <logo>http://a3.twimg.com/profile_images/740897825/AndroidCast-350_normal.png</logo> <description>this is a newsChannel</description> <rssfeed>starnews.com</rssfeed> </channel> </channels>

    Read the article

  • Using AJAX to get a specific DOM Element (using Javascript, not jQuery)

    - by Matt Frost
    How do you use AJAX (in plain JavaScript, NOT jQuery) to get a page (same domain) and display just a specific DOM Element? (Such as the DOM element marked with the id of "bodyContent"). I'm working with MediaWiki 1.18, so my methods have to be a little less conventional (I know that a version of jQuery can be enabled for MediaWiki, but I don't have access to do that so I need to look at other options). I apologize if the code is messy, but there's a reason I need to build it this way. I'm mostly interested in seeing what can be done with the Javascript. Here's the HTML code: <div class="mediaWiki-AJAX"><a href="http://www.domain.com/whatever"></a></div> Here's the Javascript I have so far: var AJAXs = document.getElementsByClassName('mediaWiki-AJAX'); if (AJAXs.length > 0) { for (var i = AJAXs.length - 1; i >= 0; i--) { var URL = AJAXs[i].getElementsByTagName('a')[0].href; xmlhttp = new XMLHttpRequest(); xmlhttp.onreadystatechange = function() { if (xmlhttp.readyState == 4 && xmlhttp.status == 200) { AJAXs[i].innerHTML = xmlhttp.responseText; } } xmlhttp.open('GET',URL,true); xmlhttp.send(); } }

    Read the article

  • Android App - disappearance of app GUI

    - by Radek Šimko
    I'm trying to create a simple app, whose main task is to open the browser on defined URL. I've created first Activity: public class MyActivity extends Activity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); //setContentView(R.layout.main); Intent myIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("http://my.url.tld")); startActivity(myIntent); } Here's my AndroidManifest.xml: <manifest ...> <application ...> <activity android:name=".MyActivity" ...> <intent-filter> <action android:name="android.intent.action.MAIN"/> <category android:name="android.intent.category.LAUNCHER"/> </intent-filter> </activity> This code is fully functional, but before it opens the browser, it displays a black background - blank app GUI. I didn't figured out, how to go directly do the browser (without displaying the GUI). Anyone knows?

    Read the article

  • Really frustrated: Help writing a sample twitter app

    - by Jack
    I have installed WAMP. I have enable cURL in php.ini. I want to implement a twitter app that posts a new status message for a user. Here's my code <?php function updateTwitter($status) { $username = 'xxxxxx'; $password = 'xxxx'; $url = 'http://twitter.com/statuses/update.xml'; $postargs = 'status='.urlencode($status); $responseInfo=array(); $ch = curl_init($url); curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 2); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_PROXY,"localhost:80"); curl_setopt ($ch, CURLOPT_POST, true); // Give CURL the arguments in the POST curl_setopt ($ch, CURLOPT_POSTFIELDS, $postargs); // Set the username and password in the CURL call curl_setopt($ch, CURLOPT_USERPWD, $username.':'.$password); // Set some cur flags (not too important) $response = curl_exec($ch); if($response === false) { echo 'Curl error: ' . curl_error($ch); } else { echo 'Operation completed without any errors<br/>'; } // Get information about the response $responseInfo=curl_getinfo($ch); // Close the CURL connection curl_close($ch); // Make sure we received a response from Twitter if(intval($responseInfo['http_code'])==200){ // Display the response from Twitter echo $response; }else{ // Something went wrong echo "Error: " . $responseInfo['http_code']; } curl_close($ch); } updateTwitter("Just finished a sweet tutorial on http://brandontreb.com"); ?> I am getting the following output Operation completed without any errors Error: 404 Please help.

    Read the article

  • PHP & cUrl - POST problems in while loop.

    - by Max Hoff
    I have a while loop, with cUrl inside. (I can't use curl_multi for various reasons.) The problem is that cUrl seems to save the data it POSTS after each loop traversal. For instance, if parameter X is One the first loop through, and if it's Two the second loop through, cUrl posts: "One,Two". It should just POST "Two".(This is despite closing and unsetting the curl handle.) Here's a simplified version of the code (with unecessary info stripped out): while(true){ // code to form the $url. this code is local to the loop. so the variables should be "erased" and made new for each loop through. $ch = curl_init(); $userAgent = 'Googlebot/2.1 (http://www.googlebot.com/bot.html)'; curl_setopt($ch,CURLOPT_USERAGENT, $userAgent); curl_setopt($ch,CURLOPT_URL,$url); curl_setopt($ch,CURLOPT_POST,count($fields)); curl_setopt($ch,CURLOPT_POSTFIELDS,$fields_string); curl_setopt($ch, CURLOPT_FAILONERROR, true); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true); curl_setopt($ch, CURLOPT_AUTOREFERER, true); curl_setopt($ch, CURLOPT_RETURNTRANSFER,true); curl_setopt($ch, CURLOPT_TIMEOUT, 10); $html = curl_exec($ch); curl_close($ch); unset($ch); $dom = new DOMDocument(); @$dom->loadHTML($html); $xpath = new DOMXPath($dom); $resultTable = $xpath->evaluate("/html/body//table"); // $resultTable is 20 the first time through the loop, and 0 everytime thereafter becauset he POSTing doesn't work right with the "saved" parameters. What am I doing wrong here?

    Read the article

  • UISplitView's DetailView not changing its content

    - by Knodel
    I have an iPad app with a UISplitView. In the Root View I have a two level UITableView (it takes its content from a plist). In the Detail View I have a UIWebView. - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { //Get the dictionary of the selected data source. NSDictionary *dictionary = [self.tableDataSource objectAtIndex:indexPath.row]; //Get the children of the present item. NSArray *Children = [dictionary objectForKey:@"Children"]; RootViewController *rvController = [[RootViewController alloc] init]; rvController.CurrentTitle = [dictionary objectForKey:@"Title"]; rvController.CurrentLevel = +1; //Push the new table view on the stack [self.navigationController pushViewController:rvController animated:YES]; rvController.tableDataSource = Children; NSString *name = [NSString stringWithFormat:@"%@.rtfd.zip", rvController.CurrentTitle ]; NSString* resourcePath = [[NSBundle mainBundle] resourcePath]; NSString* sourceFilePath = [resourcePath stringByAppendingPathComponent:name]; NSURL* url = [NSURL fileURLWithPath:sourceFilePath isDirectory:NO]; NSURLRequest* request = [NSURLRequest requestWithURL:url]; [detailViewController.webView loadRequest:request]; } That's how I want the UIWebView's content to be changed. If I name the .rtfd.zip file the same as a first level cell of the UITableView, it works, UIWebView's content changes. But this doesn't work with the second level UITableView. What am I doing wrong? Thanks in advance!

    Read the article

  • Yii user rights extension

    - by jailed abroad
    i have installed the yii rights extension and here is my code after installation, database tables are created after installation. 'modules'=>array( // uncomment the following to enable the Gii tool 'rights'=>array( 'superuserName'=>'Admin', // Name of the role with super user privileges. 'authenticatedName'=>'Authenticated', //// Name of the authenticated user role. 'userIdColumn'=>'id',// Name of the user id column in the database. 'userNameColumn'=>'username', // Name of the user name column in the database. 'enableBizRule'=>true, // Whether to enable authorization item business rules. 'enableBizRuleData'=>false, //Whether to enable data for business rules. 'displayDescription'=>true, // Whether to use item description instead of name. ' // Key to use for setting success flash messages. 'flashErrorKey'=>'RightsError', / Key to use for setting error flash messages. // 'install'=>true, // Whether to install rights. 'baseUrl'=>'/rights', // Base URL for Rights. Change if module is nested. 'layout'=>'rights.views.layouts.main', // Layout to use for displaying Rights. 'appLayout'=>'application.views.layouts.main', //Application layout. 'cssFile'=>'rights.css', // Style sheet file to use for Rights. ' 'install'=>false, // Whether to enable installer. 'debug'=>false, ), 'gii'=>array( 'class'=>'system.gii.GiiModule', 'password'=>'1234', // If removed, Gii defaults to localhost only. Edit carefully to taste. 'ipFilters'=>array('127.0.0.1','::1'), ), ), But when i type url http://localhost/rightsTest/index.php/rights then it says There must be at least one superuser! I have tried many things but unable to find answer. Thanks for your help.

    Read the article

  • parser 2.1 and 2.2

    - by yaniv
    hi i using the follwing Code to retrive XML element text using getElementsByTagName this code success in 2.2 and Failed in 2.1 any idea ? URL metafeedUrl = new URL("http://x..../Y.xml") URLConnection connection ; connection= metafeedUrl.openConnection(); HttpURLConnection httpConnection = (HttpURLConnection)connection ; int resposnseCode= httpConnection.getResponseCode() ; if (resposnseCode == HttpURLConnection.HTTP_OK) { InputStream in = httpConnection.getInputStream(); DocumentBuilderFactory dbf ; dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); // Parse the Earthquakes entry Document dom = db.parse(in); Element docEle = dom.getDocumentElement(); //ArrayList<Album> Albums = new ArrayList<Album>(); /* Returns a NodeList of all descendant Elements with a given tag name, in document order.*/ NodeList nl = docEle.getElementsByTagName("entry"); if (nl!=null && nl.getLength() > 0) { for (int i = 0; i < nl.getLength(); i++) { Element entry = (Element)nl.item(i); /* Now on every property in Entry **/ Element title =(Element)entry.getElementsByTagName("title").item(0); *Here i Get an Error* String album_Title = title.getTextContent(); Element id =(Element)entry.getElementsByTagName("id").item(0); String album_id = id.getTextContent(); //

    Read the article

  • How to read properties file in Greek using Java

    - by Subhendu Mahanta
    I am trying to read from a properties file which have keys in English & values in greek.My code is like this: public class I18NSample { static public void main(String[] args) { String language; String country; if (args.length != 2) { language = new String("el"); country = new String("GR"); } else { language = new String(args[0]); country = new String(args[1]); } Locale currentLocale; ResourceBundle messages; currentLocale = new Locale(language, country); messages = ResourceBundle.getBundle("MessagesBundle",currentLocale, new CustomClassLoader("E:\\properties")); System.out.println(messages.getString("greetings")); System.out.println(messages.getString("inquiry")); System.out.println(messages.getString("farewell")); } } import java.io.File; import java.net.MalformedURLException; import java.net.URL; public class CustomClassLoader extends ClassLoader { private String path; public CustomClassLoader(String path) { super(); this.path = path; } @Override protected URL findResource(String name) { File f = new File(path + File.separator + name); try { return f.toURL(); } catch (MalformedURLException e) { e.printStackTrace(); } return super.findResource(name); } } MessagesBundle_el_GR.properties greetings=??µ. ?a??et? farewell=ep?f. a?t?? inquiry=t? ???e?s, t? ???ete I am compiling like this javac -encoding UTF8 CustomClassLoader.java javac -encoding UTF8 I18Sample.java When I run this I get garbled output.If the properies file is in English,French or German it works fine. Please help. Regards, Subhendu

    Read the article

  • UITableView Inactive Until Scroll iPhone

    - by dubbeat
    HI, I'm trying to find the cause of some annoying behaviour with my UITableView. In each cell of my table (10 of them ) I asynchronously load an image. The problem is, is that if I don't touch the app at all the imageviews will permanently show a loading icon. However as soon as I scroll a cell off the screen and back on again the image shows straight away. What could be causing this "stuck in the mud" behaviour? Is there a way to force whatever gets called when the list is scrolled to make the needed update happen? #define ASYNC_IMAGE_TAG 9999 #define LABEL_TAG 8888 // Customize the appearance of table view cells. - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { PromoListItem *promo = [promoList objectAtIndex:indexPath.row]; static NSString *CellIdentifier = @"Cell"; AsyncImageView *asyncImageView = nil; UILabel *label = nil; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; CGRect frame; frame.origin.x = 0; frame.origin.y = 0; frame.size.width = 100; frame.size.height = 100; asyncImageView = [[[AsyncImageView alloc] initWithFrame:frame] autorelease]; asyncImageView.tag = ASYNC_IMAGE_TAG; [cell.contentView addSubview:asyncImageView]; frame.origin.x = 110; frame.size.width =100; label = [[[UILabel alloc] initWithFrame:frame] autorelease]; label.tag = LABEL_TAG; [cell.contentView addSubview:label]; cell.accessoryType = UITableViewCellAccessoryDisclosureIndicator; } else { asyncImageView = (AsyncImageView *) [cell.contentView viewWithTag:ASYNC_IMAGE_TAG]; label = (UILabel *) [cell.contentView viewWithTag:LABEL_TAG]; } NSURL *url = [NSURL URLWithString:promo.imgurl]; [asyncImageView loadImageFromURL:url]; label.text = promo.artistname; return cell; }

    Read the article

  • Java webapp: how to implement a web bug (1x1 pixel)?

    - by NoozNooz42
    In the accepted answer in the following question, a SO regular with 13K+ rep suggests to use a "web bug" (non-cacheable 1x1 img) to be able to track requests in the logs: http://stackoverflow.com/questions/1784893 How can I do this in Java? Basically, I've got two issues: how to make sure the 1x1 image is not cacheable (how to set the header)? how to make sure the query for these 1x1 image will appear in the logs? I'm looking for exact piece of code because I know how to write a .jsp/servlet and I know how to serve an 1x1 image :) My question is really about the exact .jsp/servlet that I should write and how/what needs to be done so that Tomcat logs the request. For example I plan to use the following mapping: <servlet-mapping> <servlet-name>WebBugServlet</servlet-name> <url-pattern>/webbug*</url-pattern> </servlet-mapping> and then use an img tag referencing a "webbug.png" (or .gif), so how do I write the .jsp/servlet? What/where should I look for in the logs?

    Read the article

  • Testing for interface implementation in WCF/SOA

    - by rabidpebble
    I have a reporting service that implements a number of reports. Each report requires certain parameters. Groups of logically related parameters are placed in an interface, which the report then implements: [ServiceContract] [ServiceKnownType(typeof(ExampleReport))] public interface IService1 { [OperationContract] void Process(IReport report); } public interface IReport { string PrintedBy { get; set; } } public interface IApplicableDateRangeParameter { DateTime StartDate { get; set; } DateTime EndDate { get; set; } } [DataContract] public abstract class Report : IReport { [DataMember] public string PrintedBy { get; set; } } [DataContract] public class ExampleReport : Report, IApplicableDateRangeParameter { [DataMember] public DateTime StartDate { get; set; } [DataMember] public DateTime EndDate { get; set; } } The problem is that the WCF DataContractSerializer does not expose these interfaces in my client library, thus I can't write the generic report generating front-end that I plan to. Can WCF expose these interfaces, or is this a limitation of the serializer? If the latter case, then what is the canonical approach to this OO pattern? I've looked into NetDataContractSerializer but it doesn't seem to be an officially supported implementation (which means it's not an option in my project). Currently I've resigned myself to including the interfaces in a library that is common between the service and the client application, but this seems like an unnecessary extra dependency to me. Surely there is a more straightforward way to do this? I was under the impression that WCF was supposed to replace .NET remoting; checking if an object implements an interface seems to be one of the most basic features required of a remoting interface?

    Read the article

  • How can I properly handle 404s in ASP.NET MVC?

    - by Brian
    I am just getting started on ASP.NET MVC so bear with me. I've searched around this site and various others and have seen a few implementations of this. EDIT: I forgot to mention I am using RC2 Using URL Routing: routes.MapRoute( "Error", "{*url}", new { controller = "Errors", action = "NotFound" } //404s ); The above seems to take care of requests like this (assuming default route tables setup by initial MVC project): "/blah/blah/blah/blah" Overriding HandleUnknownAction() in the controller itself: //404s - handle here (bad action requested protected override void HandleUnknownAction(string actionName) { ViewData["actionName"] = actionName; View("NotFound").ExecuteResult(this.ControllerContext); } However the previous strategies do not handle a request to a Bad/Unknown controller. For example, I do not have a "/IDoNotExist", if I request this I get the generic 404 page from the web server and not my 404 if I use routing + override. So finally, my question is: Is there any way to catch this type of request using a route or something else in the MVC framework itself? OR should I just default to using Web.Config customErrors as my 404 handler and forget all this? I assume if I go with customErrors I'll have to store the generic 404 page outside of /Views due to the Web.Config restrictions on direct access. Anyway any best practices or guidance is appreciated.

    Read the article

  • What techniques can be used to detect so called "black holes" (a spider trap) when creating a web crawler?

    - by Tom
    When creating a web crawler, you have to design somekind of system that gathers links and add them to a queue. Some, if not most, of these links will be dynamic, which appear to be different, but do not add any value as they are specifically created to fool crawlers. An example: We tell our crawler to crawl the domain evil.com by entering an initial lookup URL. Lets assume we let it crawl the front page initially, evil.com/index The returned HTML will contain several "unique" links: evil.com/somePageOne evil.com/somePageTwo evil.com/somePageThree The crawler will add these to the buffer of uncrawled URLs. When somePageOne is being crawled, the crawler receives more URLs: evil.com/someSubPageOne evil.com/someSubPageTwo These appear to be unique, and so they are. They are unique in the sense that the returned content is different from previous pages and that the URL is new to the crawler, however it appears that this is only because the developer has made a "loop trap" or "black hole". The crawler will add this new sub page, and the sub page will have another sub page, which will also be added. This process can go on infinitely. The content of each page is unique, but totally useless (it is randomly generated text, or text pulled from a random source). Our crawler will keep finding new pages, which we actually are not interested in. These loop traps are very difficult to find, and if your crawler does not have anything to prevent them in place, it will get stuck on a certain domain for infinity. My question is, what techniques can be used to detect so called black holes? One of the most common answers I have heard is the introduction of a limit on the amount of pages to be crawled. However, I cannot see how this can be a reliable technique when you do not know what kind of site is to be crawled. A legit site, like Wikipedia, can have hundreds of thousands of pages. Such limit could return a false positive for these kind of sites. Any feedback is appreciated. Thanks.

    Read the article

  • JSF works only with the .xhtml ending

    - by ThreeFingerMark
    Hello, i start with the programming of a JSF Website. At the moment all files have the .xhtml ending. When i go to http://localhost:8080/myProject/start.jsf everything is all right. But when i rename the file from start.xhtml to start.jsf i became a NoClassDefFound Error. What is my mistake? <servlet-name>Faces Servlet</servlet-name> <servlet-class>javax.faces.webapp.FacesServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>Faces Servlet</servlet-name> <url-pattern>*.jsf</url-pattern> </servlet-mapping> <context-param> <param-name>javax.faces.PROJECT_STAGE</param-name> <param-value>Development</param-value> </context-param>

    Read the article

  • Losing URI segments when paginating with CodeIgniter

    - by Danny Herran
    I have a /payments interface where the user should be able to filter via price range, bank, and other stuff. Those filters are standard select boxes. When I submit the filter form, all the post data goes to another method called payments/search. That method performs the validation, saves the post values into a session flashdata and redirects the user back to /payments passing the flashdata name via URL. So my standard pagination links with no filters are exactly like this: payments/index/20/ payments/index/40/ payments/index/60/ And if you submit the filter form, the returning URL is: payments/index/0/b48c7cbd5489129a337b0a24f830fd93 This works just great. If I change the zero for something else, it paginates just fine. The only issue however is that the << 1 2 3 4 page links wont keep the hash after the pagination offset. CodeIgniter is generating the page links ignoring that additional uri segment. My uri_segment config is already set to 3: $config['uri_segment'] = 3; I cannot set the page offset to 4 because that hash may or may not exists. Any ideas of how can I solve this? Is it mandatory for CI to have the offset as the last segment in the uri? Maybe I am trying an incorrect approach, so I am all ears. Thank you folks.

    Read the article

  • PHP: Best solution for links breaking in a mod_rewrite app

    - by psil
    I'm using mod rewrite to redirect all requests targeting non-existent files/directories to index.php?url=* This is surely the most common thing you do with mod_rewrite yet I have a problem: Naturally, if the page url is "mydomain.com/blog/view/1", the browser will look for images, stylesheets and relative links in the "virtual" directory "mydomain.com/blog/view/". Problem 1: Is using the base tag the best solution? I see that none of the PHP frameworks out there use the base tag, though. I'm currently having a regex replace all the relative links to point to the right path before output. Is that "okay"? Problem 2: It is possible that the server doesn't support mod_rewrite. However, all public files like images, stylesheets and the requests collector index.php are located in the directory /myapp/public. Normally mod_rewrite points all request to /public so it seems as if public was actually the root directory too all users. However if there is no mod_rewrite, I then have to point the users to /public from the root directory with a header() call. That means, however that all links are broken again because suddenly all images, etc. have to be called via /public/myimage.jpg Additional info: When there is no mod_rewrite the above request would look like this: mydomain.com/public/index.php/blog/view/1 What would be the best solutions for both problems?

    Read the article

  • CSS background images not showing in IE?

    - by Kevin
    In IE8 and below, I'm doing this <ul class="dependants_list" style="border-bottom: dashed 1px #53a1dc"> <li class="dependants_summary"> <strong>Name:</strong> De Silva, Angelina<br /> <strong>Gender:</strong> Female<br /> <strong>Date of birth:</strong> 7/3/2009<br /> </li> <form action="/Dependant/Delete/11413" method="get"><input class="delete btn" id="Delete_this_Profile" name="Delete_this_Profile" type="submit" value="Delete this Profile" /> </form><form action="/Dependant/Edit/11413" method="get"><input class="edit btn" id="Modify_this_Profile" name="Modify_this_Profile" type="submit" value="Modify this Profile" /> </form><br /><hr style="display:none" /> and the CSS for it is: .dependants_summary { overflow: hidden; margin-bottom: 10px; padding-right: 0px; padding-left: 85px; padding-top: 5px; padding-bottom: 5px; width: 430px; float: left; font: 120% Arial, Helvetica, sans-serif; } .dependants_list { padding: 0; } .dependants_list li:nth-child(odd) { background: #fff url("../images/dependant_male.png") no-repeat scroll 8px 9px; } .dependants_list li:nth-child(even) { background: #c9e3f4 url("../images/dependant_male.png") no-repeat scroll 8px 9px; } The images are not being shown in IE, but they are in ffox and chrome

    Read the article

  • NSString writeToFile operation couldn't be completed

    - by Chonch
    Hey, I have an xml file in my application bundle. I want to copy it to the documents folder at installation and then, every time the app launches, get the newest version of this file from the Internet. I use this code: // Check if the file exists in the documents folder NSString *documentsPath = [NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES) objectAtIndex:0]; if (![[NSFileManager defaultManager] fileExistsAtPath:[documentsPath stringByAppendingPathComponent:@"fileName.xml"]]) // If not, copy it there (from the bundle) [[NSFileManager defaultManager] copyItemAtPath:[[[NSBundle mainBundle] resourcePath] stringByAppendingPathComponent:@"OriginalFile.xml"] toPath:[documentsPath stringByAppendingPathComponent:@"fileName.xml"] error:nil]; // Get the newest version of the file from the server NSURL *url=[[NSURL alloc] initWithString:@"http://www.sitename.com/webservice.asmx/webserviceName"]; NSString *results = [[NSString alloc] initWithContentsOfURL:url]; // Replace the current version with the newest one, only if it is valid if (results != nil) [results writeToFile:[documentsPath stringByAppendingPathComponent:@"fileName.xml"] atomically:NO encoding:NSStringEncodingConversionAllowLossy error:nil]; The problem is that the writeToFile command always returns NO and the file's contents remain identical to the original file I included in my app bundle. I checked the value of results and it's correct. I also made sure that the app does perform the writeToString command, but still, it always returns NO. Can anybody tell me what I'm doing wrong? Thanks,

    Read the article

  • Update database settings in properties file in Spring

    - by mvg
    Hi all, I am trying to create a Database Manager page which shows the database details on page load and updates the database settings when the user press submit I followed this tutorial and set the database settings in properties file. I managed to update the database settings in properties file programmatically. When I retrieved the database settings using the following code DriverManagerDataSource databaseSource = (DriverManagerDataSource)context.getBean("dataSource"); databaseSource.getUsername(); I managed to get the old value and unable to get the new value This is the mapping in applicationContext.xml file <bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"> <property name="location"> <value>classpath:/bundle/database.properties</value> </property> </bean> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="${jdbc.driverClassName}" /> <property name="url" value="${jdbc.url}" /> <property name="username" value="${jdbc.username}" /> <property name="password" value="${jdbc.password}" /> </bean> I checked the properties file and found it to be updated with the latest input. What am I missing? Thanks in advance P.S I am using JSF1.2 with Spring 3 Update Just making my requirement simple. I am creating a setparate dbsettings page, so that when user wishes to connect to different database he/she can just enter the details in dbsettings page and connect

    Read the article

  • How we Can post Video and Image in ASIHTTPRequest ?

    - by GhostRider
    I want to post one image to my webservice and one video too , but problem is that when it go to video part it give me Excess-bad Error NSString *url = [NSString stringWithFormat:@"http://example.com/add_videoxml.php"]; networkQueue = [[ASINetworkQueue alloc] init]; [networkQueue cancelAllOperations]; [networkQueue setShowAccurateProgress:YES]; //[networkQueue setUploadProgressDelegate:progressBar]; [networkQueue setDelegate:self]; [networkQueue setRequestDidFinishSelector:@selector(requestFinished:)]; [networkQueue setRequestDidFailSelector: @selector(requestFailed:)]; request= [[ASIFormDataRequest alloc] initWithURL:[NSURL URLWithString:url]] ; [request setPostValue:@"284" forKey:@"id"]; [request setPostValue:@"show" forKey:@"show"]; [request addRequestHeader:@"Content-Type" value:@"multipart/form-data;boundary=---------------------------1842378953296356978857151853"]; NSData *imgData=UIImageJPEGRepresentation(userImage, 0.9); if(imgData != nil){ [request setFile:imgData withFileName:@"Loveatnight" andContentType:@"image/jpeg" forKey:@"image"]; } //[request addRequestHeader:@"Content-Type" // value:@"multipart/form-data;boundary=---------------------------1842378953296356978857151853"]; if(videoData != nil){ [request setFile:videoData withFileName:@"Loveishard" andContentType:@"image/jpeg" forKey:@"uploadfile"]; }// error is come on that line [request setTimeOutSeconds:500]; //NSLog(@"%@",request); [networkQueue addOperation:request]; [networkQueue go]; Added by the OP [request setFile:videoData withFileName:@"Loveishard" andContentType:@"video/quicktime" forKey:@"uploadfile"]; i use this becuase my video formate is mov , but it again give error

    Read the article

  • curl not returning content length header

    - by Michael P. Shipley
    Trying to get image file size using curl but content length header is not returned: $url ="http://www.collegefashion.net/wp-content/plugins/feed-comments-number/image.php?1263"; $fp = curl_init(); curl_setopt($fp, CURLOPT_NOBODY, true); curl_setopt($fp, CURLOPT_RETURNTRANSFER, 1); curl_setopt($fp, CURLOPT_FAILONERROR,1); curl_setopt($fp, CURLOPT_REFERER,''); curl_setopt($fp, CURLOPT_URL, $url); curl_setopt($fp, CURLOPT_HEADER,1); curl_setopt($fp, CURLOPT_USERAGENT,'Mozilla/5.0'); $body = curl_exec($fp); var_dump($body): HTTP/1.1 200 OK Date: Sun, 02 May 2010 02:50:20 GMT Server: Apache/2.0.63 (CentOS) X-Powered-By: W3 Total Cache/0.8.5.2 X-Pingback: http://www.collegefashion.net/xmlrpc.php Cache-Control: no-cache, must-revalidate Expires: Sat, 26 Jul 1997 05:00:00 GMT Content-Type: image/png It works via ssh though: curl -i http://www.collegefashion.net/wp-content/plugins/feed-comments-number/image.php?1263 HTTP/1.1 200 OK Date: Sun, 02 May 2010 03:38:43 GMT Server: Apache/2.0.63 (CentOS) X-Powered-By: W3 Total Cache/0.8.5.2 X-Pingback: http://www.collegefashion.net/xmlrpc.php Cache-Control: no-cache, must-revalidate Expires: Sat, 26 Jul 1997 05:00:00 GMT Content-Length: 347 Content-Type: image/png

    Read the article

  • Configurating JOOMLA's e-mail notification for new account

    - by Dion
    I'm using Joomla 1.5 to create a local site for my office. The site will be accessed locally via intranet, and my PC will be the localhost for the site. I'm using a Login pluggin, so that anyone who wanted to enter the site should create an account. In JOOMLA, all user who created their account for the first time will receive a notification e-mail like : "Hello pras, You have been added as a User to Information Center by an Administrator. This e-mail contains your username and password to log in to http://localhost/yaddayadda/ Username: hadisuryo.prasetio Password: xxxx Please do not respond to this message as it is automatically generated and is for information purposes only." but if the user click the URL in the mail, which is, "localhost/yaddayadda/" they will not be directed to my site, but to their own PC's localhost.... My question is : How can I Modified the e-mail or the site configuration so that the URL will not be "localhost/yaddayadda/" anymore, but will be "(My-IP adress)/yaddayadda" I'm not going to host my site to a web hosting service, just using my PC as a host. I've been trying to trace on each config and .ini files...it seems that i have to do something with the "JURI" function or the "$mosConfig_live_site" on the backlink.php file $mosConfig_absolute_path = JPATH_SITE; $mosConfig_live_site = JURI :: base(); $url_array = explode('/', $_SERVER['REQUEST_URI']); Can anyone give me assistance ? Thank You

    Read the article

< Previous Page | 367 368 369 370 371 372 373 374 375 376 377 378  | Next Page >