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  • Different meaning in the mysql code?

    - by Emre Saracoglu
    $result=mysql_query("select * from dosyabegeni where veri_id='" . get_custom_field('dwcode') . "'"); Not Working It says the number and the screen, but the application does not work veri_id='" . get_custom_field('dwcode') . "'"); veri_id='" . echo get_custom_field('dwcode') . "'"); Working veri_id='HelloTest'"); veri_id='1234567890'"); veri_id='" . $_GET['test'] . "'"); Main Codes <?php include('/home/emre2010/public_html/EntegreOz/DosyaBegeni/config.php'); $result=mysql_query("select * from dosyabegeni where veri_id='" .get_custom_field('dwcode') . "'"); while($row = mysql_fetch_array($result)) { $sira_id=$row['sira_id']; $veri_id=$row['veri_id']; $begeni=$row['begeni']; ?> <div class="reviewbox"> <div class="summarywrap"> <div class="summarywrapinner"> <div class="summary"> <div class="reviewsection"><div class="rating points"> <a href="#" class="begeni" id="<?php echo $sira_id; ?>"> <span style="color:#fff;" align="center"> <?php echo $begeni; ?> </span> </a> <p class="ratingtext">completed!</p></div> </div><div class="clear"></div> <div class="clear"></div> </div> <div class="ratingsummary"></div> <div class="clear"></div> </div> <div class="clear"></div> </div> What's the problem?

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  • actionscript 2.0 input text box

    - by user1769760
    So, here's what I'm trying to do, and I, frankly, believe it should be obvious, but I can't figure it out. I am creating a very simple Artificial Intelligence simulation. And in this simulation there's an input box at the bottom of the screen (called "input" exactly). "input" has a variable in its properties that is called "inbox" (exactly). Using a key listener the script calls up a function when the enter button is pressed. This function has 2 if statements and an else statement which dictate the responses of the AI (named "nistra"). The problem is this, When I type in what I want to say, and hit enter, it always uses the second response ("lockpick" in the code below). I have tried variations on the code but I still don't see the solution. I believe the problem is that the "typein" variable holds all the format information from the text box as well as the variable, but I could be wrong, that information is in here as well, underneath the code itself. Any help I can get would be greatly appreciated. var typein = ""; //copies the text from inbox into here, this is what nistra responds to var inbox = ""; //this is where the text from the input text box goes var respond = ""; //nistra's responses go here my_listener = new Object(); // key listener my_listener.onKeyDown = function() { if(Key.isDown(13)) //enter button pressed { typein = inbox; // moves inbox into typein nistraresponse(); // calles nistra's responses } //code = Key.getCode(); //trace ("Key pressed = " + code); } Key.addListener(my_listener); // key listener ends here nistraresponse = function() // nistra's responses { trace(typein); // trace out what "typein" holds if(typein = "Hello") // if you type in "Hello" { respond = "Hello, How are you?"; } if(typein = "lockpick") // if you type in "lockpick" { respond = "Affirmative"; } else // anything else { respond = "I do not understand the command, please rephrase"; } cntxtID = setInterval(clearnistra, 5000); // calls the function that clears out nistra's response box so that her responses don't just sit there } clearnistra = function() // clears her respond box { respond = ""; clearInterval(cntxtID); } // "typein" traces out the following <TEXTFORMAT LEADING="2"><P ALIGN="CENTER"><FONT FACE="Times New Roman" SIZE="20" COLOR="#FF0000" LETTERSPACING="0" KERNING="0">test</FONT></P></TEXTFORMAT>

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  • Yii file upload issue

    - by user1289853
    Couple of months ago,I developed a simple app using YII,one of the feature was to upload file. The feature was working well in my dev machine,couple of days ago client found the file upload feature is not working in his server since deployment. And after that I test my dev machine that was not working too. My controller looks: public function actionEntry() { if (!Yii::app()->user->isGuest) { $model = new TrackForm; if (isset($_POST['TrackForm'])) { $entry = new Track; try { $entry->product_image = $_POST['TrackForm']['product_image']; $entry->product_image = CUploadedFile::getInstance($model, 'product_image'); if ($entry->save()) { if ($entry->product_image) { $entry->product_image->saveAs($entry->product_image->name, '/trackshirt/uploads'); } } $this->render('success', array('model' => $model)); // redirect to success page } } catch (Exception $e) { echo 'Caught exception: ', $e->getMessage(), "\n"; } } else { $this->render('entry', array('model' => $model)); } } } Model is like below: <?php class Track extends CActiveRecord { public static function model($className=__CLASS__) { return parent::model($className); } public function tableName() { return 'product_details'; } } My view looks: <?php $form = $this->beginWidget('CActiveForm', array( 'id' => 'hide-form', 'enableClientValidation' => true, 'clientOptions' => array( 'validateOnSubmit' => true, ), 'htmlOptions' => array('enctype' => 'multipart/form-data'), )); ?> <p class="auto-style2"><strong>Administration - Add New Product</strong></p> <table align="center" style="width: 650px"><td class="auto-style3" style="width: 250px">Product Image</td> <td> <?php echo $form->activeFileField($model, 'product_image'); ?> </td> </tr> </table> <p class="auto-style1"> <div style="margin-leftL:-100px;"> <?php echo CHtml::submitButton('Submit New Product Form'); ?> </div> <?php $this->endWidget(); ?> Any idea where is the problem?I tried to debug it but every time it returns Null. Thanks.

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  • Line graph disappears after new line is added

    - by tonystinge
    I am having trouble uploading a large .csv file to my HIGHCHART graph. I've been able to graph an 85KB up to 1486 lines by 9 (I) columns. Here is an example: TimeStamp Temp_1_01 Temp_1_02 Temp_2_01 Temp_2_02 Temp_3_01 Temp_3_02 Temp_4_01 Temp_4_02 5/15/2014, 3:25 408 487 63 84 67 91 63 78 5/15/2014 3:30 408 487 63 84 67 91 63 78 5/15/2014 3:35 407 489 63 84 67 91 63 78 5/15/2014 3:40 408 488 63 84 67 91 63 78 5/15/2014 3:44 408 488 63 84 67 91 63 78 ... 5/22/2014 9:40 483 421 0 93 76 95 72 89 When I add a new line the line graph disappears. Any suggestions? Here is the javascript: $.get('Dropbox/geo/sites/GC_Room/loveland.csv', function(data) { // Split the lines var lines = data.split('\n'); var i = 0; var csvData = []; // Iterate over the lines and add categories or series $.each(lines, function(lineNo, line) { csvData[i] = line.split(','); i = i + 1; }); var columns = csvData[0]; var categories = [], series = []; for(var colIndex=0,len=columns.length; colIndex<len; colIndex++) { //first row data as series's name var seriesItem= { data:[], name:csvData[0][colIndex] }; for(var rowIndex=1,rowCnt=csvData.length; rowIndex<rowCnt; rowIndex++) { //first column data as categories, if (colIndex == 0) { categories.push(csvData[rowIndex][0]); } else if(parseFloat(csvData[rowIndex][colIndex])) // <-- here { seriesItem.data.push(parseFloat(csvData[rowIndex][colIndex])); } }; //except first column if(colIndex>0)series.push(seriesItem); } // Create the chart var chart = new Highcharts.Chart( { chart: { alignTick: false, renderTo: 'LANE_METALS', type: 'line' }, title: { text: 'Monthly Average Temperature', x: -20 //center }, subtitle: { text: 'Source: LANE METALS', x: -20 }, xAxis: { categories: categories, labels: { step: 200, text: 'Time', }, tickWidth: 0 }, yAxis: { title: { text: 'Temperature (\xB0C)' }, min: 0 }, tooltip: { formatter: function() { return '<b>'+ this.series.name +'</b><br/>'+ this.x +': '+ this.y +'\xB0C'; } }, legend: { layout: 'vertical', //backgroundColor: '#FFFFFF', //floating: true, align: 'left', //x: 100, verticalAlign: 'top', //y: 70, borderWidth: 0 }, plotOptions: { area: { turboThreshold: 0, stacking: 'normal', lineColor: '#666666', lineWidth: 1, marker: { lineWidth: 1, lineColor: '#666666' } } }, series: series }); });

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  • Div not filling width of floated container (css expert needed

    - by Rayden
    I know there are many variations of this question posted, but none I've found quite provide an answer that works for this case. I basically have two left floated divs. Inside those two divs are div headers and tabled content. I want the Div headers (Hour/Minute) to stretch to the width of the tabled content, but they only do this in FF and Chrome, not IE7. IE7 is my works official browser so the one I need it to work with the most. Here is the CSS: #ui-timepicker-div { padding:0.2em; } #ui-timepicker-hours { float:left; } #ui-timepicker-minutes { margin:0 0 0 0.2em; float:left; } .ui-timepicker .ui-timepicker-header { padding:0.2em 0; } .ui-timepicker .ui-timepicker-title { line-height:1.8em; text-align:center; } .ui-timepicker table { margin:0.15em 0 0 0; font-size:.9em; border-collapse:collapse; } .ui-timepicker td { padding:1px; width:2.2em; } .ui-timepicker th, .ui-timepicker td { border:0; } .ui-timepicker td a { display:block; padding:0.2em 0.3em 0.2em 0.5em; text-align:right; text-decoration:none; } Here is the HTML (did not include tabled content): <div style="position: absolute; top: 252.667px; left: 648px; z-index: 1; display: none;" class="ui-timepicker ui-widget ui-widget-content ui-helper-clearfix ui-corner-all" id="ui-timepicker-div"> <div id="ui-timepicker-hours"> <div class="ui-timepicker-header ui-widget-header ui-helper-clearfix ui-corner-all"> <div class="ui-timepicker-title">Hour</div> </div> <table class="ui-timepicker"> </table> </div> <div id="ui-timepicker-minutes"> <div class="ui-timepicker-header ui-widget-header ui-helper-clearfix ui-corner-all"> <div class="ui-timepicker-title">Minutes</div> </div> <table class="ui-timepicker"> </table> </div> </div>

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  • Image change on mouseover with jQuery..

    - by playahabana
    Hi, I am a comlete beginner to pretty much all things web design and am trying to construct my first website. I am attempting to hand code it without the ue of a CMS in order to learn as much as possible as quickly as possible. I am trying to make an imge change on mouseover for my top nav menu, and have the following jQuery functions: $(document).ready(function(){ $(".navlist img").each(function) { rollsrc = $(this).attr("src"); rollON = rollsrc.replace(/.jpg$/ig,"_link.png"); $("<img>").attr("src",rollON); $(".navlist a").mouseover(function(){ }); imgsrc= $(this).children("img").attr("src"); matches = imgsrc.match(/_link.png); if (!matches) { imgsrcON = imgsrc.replace(/.jpg$/ig,"_link.png"); $(this).children("img").attr("src", imagesrcON); } $(".navlist a").mouseout(function(){ $(this).children("img").attr("src", imgsrc); }); }); my html is as follows: <div id="nav"> <ul class="navmenu"> <li><a href="index.html"><img class="swap" src="images/links/home.jpg" alt="Home" border="none"></a></li> <li><a href="#"><img class="swap" src="images/links/ourbar.jpg" alt="Our Bar" border="none"></a> <ul class="navdrop"> <li ><a href="#"><img class="swap" src="images/links/cockteles.jpg" alt="Our Cocktails" border="none"></a></li> <li ><a href="#"><img class="swap" src="images/links/celebrate.jpg" alt="Celebrate in Style" border="none"></a></li> </ul> </li> <li><a href="#"><img class="swap" src="images/links/ourcigars.jpg" alt="Our Cigars" border="none"></a> <ul class="navdrop"> <li><a href="#"><img class="swap" src="images/links/edicionlimitadas.jpg" alt="Edition Limitadas" border="none"></a></li> <li><a href="our_cigars.html"><img class="swap" src="images/links/cigartasting.jpg" alt="Cigar Tastings" border="none"></a></li> </ul> </li> <li><a href="#"><img class="swap" src="images/links/personalcigar.jpg" alt="Personal Cigar Roller" border="none"></a></li> <li><a href="our_cigars.html"><img class="swap" src="images/links/photogallery.jpg" alt="Photo Gallery" border="none"></a></li> <li><a href="#"><img class="swap" src="images/links/contactus.jpg" alt="Contact Us" border="none"></a></li> </ul></div></div><!--end banner--> the image src for the alt image is in the form eg."images/links/home_link.png" and is the same for every image. I have checked this and checked this, could some body please give me a pointer as to where I am going wrong? Or a pointer to a tutorial for this effect? I have looked at a few and this seems to be the best for what I am attempting, but as I said I don't really know what I'm doing so any advice gratefully received.....

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  • PHP - not sure how to ask - regarding variables and $_POST

    - by Phil
    I have a PHP form. The form works but I'm trying to test to see if a value other than the first item has been selected. I can't figure out how to write the If statement. $products = array( '' => 1, 'Item 2' => 2, 'Item 3' => 3, 'Item 4' => 4, 'Item 5' => 5, 'Item 6' => 6 ); $html = generateSelect('products', $products); function generateSelect($name = '', $options = array()) { $html = '<select name="'.$name.'">'; foreach ($options as $option => $value) { $html .= '<option value='.$value.'>'.$option.'</option>'; } $html .= '</select>'; return $html; } In my table, the drop down box is displayed: <tr> <td style="width:{$left_col_width}; text-align:left; vertical-align:center; padding:{$cell_padding}; font-weight:bold; {$product[3]}">{$product[0]}</td> <td style="text-align:left; vertical-align:top; padding:{$cell_padding};"><select name="{$product[1]}"> <option value="1"></option> <option value="2">Item 2</option> <option value="3">Item 3</option> <option value="4">Item 4</option> <option value="5">Item 5</option> <option value="6">Item 6</option> </select></td> </tr> I use the following if statement to check to see if someone has entered a phone number. if they have not entered a phone number, then the "Phone:" text turns red. How do I do an if statement similar to this to verify that someone has selected a product option from the drop down box? if(!empty($_POST['phone'])) { $phone[2] = clean_var($_POST['phone']); if (function_exists('htmlspecialchars')) $phone[2] = htmlspecialchars($phone[2], ENT_QUOTES); } else { $error = 1; $phone[3] = 'color:#d20128;'; } it seems simple but I can't figure it out.

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  • Creating a multiplatform webapp with HTML5 and Google maps

    - by Bart L.
    I'm struggling how to develop a webapp for Android and iOS. My first app was a simple todo app which was easy to test in my browser and it only used html, javascript and css. However, I have to create an app which uses Google Maps Api to get the location. I created a simple html5 page to test which places a marker on a map. It works fine when testing it on my local server. But when I create an .apk file for Android, the app doesn't work. So I'm wondering, isn't it possible to use it like this? Do I have the use the phonegap libraries to use their geolocation library? And if so, how do you handle the development of a webapp in phonegap for multiple OS? Do you have to install an Android environment and an iOS environment to each include the right phonegap library and to test them properly? Update: I use the following code on my webserver and it works perfectly. When I upload it in a zip-folder to the photogap cloud and install the APK file on my phone, it doesn't work. <!DOCTYPE html> <html> <head> <meta charset="utf-8"> <title>Simple Geo test</title> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.8/jquery.min.js"></script> </head> <body> <script type="text/javascript" src="http://maps.google.com/maps/api/js?sensor=true"></script> <script> function success(position) { var mapcanvas = document.createElement('div'); mapcanvas.id = 'mapcontainer'; mapcanvas.style.height = '200px'; mapcanvas.style.width = '200px'; document.querySelector('article').appendChild(mapcanvas); var coords = new google.maps.LatLng(position.coords.latitude, position.coords.longitude); var options = { zoom: 15, center: coords, mapTypeControl: false, navigationControlOptions: { style: google.maps.NavigationControlStyle.SMALL }, mapTypeId: google.maps.MapTypeId.ROADMAP }; var map = new google.maps.Map(document.getElementById("mapcontainer"), options); var marker = new google.maps.Marker({ position: coords, map: map, title:"You are here!" }); } if (navigator.geolocation) { navigator.geolocation.getCurrentPosition(success); } else { error('Geo Location is not supported'); } </script> <article></article> </body> </html>

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  • Simple jquery Fade Slideshow fails on certain browsers

    - by cmay
    So I have a simple slideshow on my website which just shows one image then shows another until it reaches the end or the user hits skip in which case it shows index.html. The site is served on apache2 with Django. The slideshow works perfectly on most machines, but certain machines it shows some images twice and other images not at all and the timing is off. I am using jquery 1.4.3. Below is the section of html where I push the image urls from the database to the javascript {% for image in latest_images %} {% thumbnail image.image_file "800x600" crop="center" as im %} <script>FadeImageList.push("{{im.url}}");</script> {% endthumbnail %} {% endfor %} Below is the full javascript file var FadeImageList = []; var fadeDuration = 2000; var fadeImgID = '#slideShow'; var homePageID = '#homePage'; var menuID = '#menu'; var skipFlag = 0; $(document).ready(function(){ $(homePageID).fadeOut(50); PlaySlideshow(FadeImageList); }); var PlaySlideshow = function(FadeImageList){ var newImgSrc = FadeImageList.shift(); $('#skip').click(function(){$('#loader').show();skipFlag = 1;}); if(((typeof(newImgSrc) !== "string") || (skipFlag === 1))){ EndSlideShow(); return; } else{ $(fadeImgID).fadeOut(fadeDuration,function(){ $(fadeImgID).attr('src', newImgSrc); $(fadeImgID).fadeIn(fadeDuration,function(){ PlaySlideshow(FadeImageList); }); }); } }; var EndSlideShow = function(fadeSettings){ $(fadeImgID).fadeOut(400,function(){ $(homePageID).fadeIn(400); $("#skip").fadeOut(400); $('#loader').hide(); }); }; The strange thing is I've had it work and fail on identically version numbered browsers on the same os but on different machines. It consistently either works or fails on a machine. I've had it fail in ie 7,8 firefox 3.6.3 and chrome. I've also had it succeed in ie6,7,8 firefox 3.6.3,3.4.2,3.1 and chrome.

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  • How do I create a class in Javascript?

    - by William
    This is what I got so far, and it's not working at all :( <!DOCTYPE html> <html lang="en"> <head> <title>Class Test</title> <meta charset="utf-8" /> <style> body { text-align: center; background-color: #ffffff;} #box { position: absolute; left: 610px; top: 80px; height: 50px; width: 50px; background-color: #ff0000; color: #000000;} </style> <script type="text/javascript"> document.onkeydown=function(event){keyDown(event)}; document.onkeyup=function(event){keyUp(event)}; var box = 0; function Player () { var speed = 5; var x = 50; var y = 50; } function update() { box.style.left = this.x + "px"; box.style.top = this.y + "px"; box.innerHTML = "<h6 style=\"margin: 0px 0px 0px 0px; padding: 0px 0px 0px 0px;\">X: "+ this.x + "<br /> Y: " + this.y + "</h6>"; } var player = new Player(); var keys = new Array(256); var i = 0; for (i = 0;i <= 256; i++){ keys[i] = false; } function keyDown(event){ keys[event.keyCode] = true; } function keyUp(event){ keys[event.keyCode] = false; } function update(){ if(keys[37]) player.x -= player.speed; if(keys[39]) player.x += player.speed; player.update(); } setInterval(update, 1000/60); </script> </head> <body> <div id="box" ></div> <script type="text/javascript"> box = document.getElementById('box'); box.innerHTML = "<h6 style=\"margin: 0px 0px 0px 0px; padding: 0px 0px 0px 0px;\">X: "+ player.x + "<br /> Y: " + player.y + "</h6>"; </script> </body> </html>

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  • refactoring this function in Java

    - by Joel
    Hi folks, I'm learning Java, and I know one of the big complaints about newbie programmers is that we make really long and involved methods that should be broken into several. Well here is one I wrote and is a perfect example. :-D. public void buildBall(){ /* sets the x and y value for the center of the canvas */ double i = ((getWidth() / 2)); double j = ((getHeight() / 2)); /* randomizes the start speed of the ball */ vy = 3.0; vx = rgen.nextDouble(1.0, 3.0); if (rgen.nextBoolean(.05)) vx = -vx; /* creates the ball */ GOval ball = new GOval(i,j,(2 *BALL_RADIUS),(2 * BALL_RADIUS)); ball.setFilled(true); ball.setFillColor(Color.RED); add(ball); /* animates the ball */ while(true){ i = (i + (vx* 2)); j = (j + (vy* 2)); if (i > APPLICATION_WIDTH-(2 * BALL_RADIUS)){ vx = -vx; } if (j > APPLICATION_HEIGHT-(2 * BALL_RADIUS)){ vy = -vy; } if (i < 0){ vx = -vx; } if (j < 0){ vy = -vy; } ball.move(vx + vx, vy + vy); pause(10); /* checks the edges of the ball to see if it hits an object */ colider = getElementAt(i, j); if (colider == null){ colider = getElementAt(i + (2*BALL_RADIUS), j); } if (colider == null){ colider = getElementAt(i + (2*BALL_RADIUS), j + (2*BALL_RADIUS)); } if (colider == null){ colider = getElementAt(i, j + (2*BALL_RADIUS)); } /* If the ball hits an object it reverses direction */ if (colider != null){ vy = -vy; /* removes bricks when hit but not the paddle */ if (j < (getHeight() -(PADDLE_Y_OFFSET + PADDLE_HEIGHT))){ remove(colider); } } } You can see from the title of the method that I started with good intentions of "building the ball". There are a few issues I ran up against: The problem is that then I needed to move the ball, so I created that while loop. I don't see any other way to do that other than just keep it "true", so that means any other code I create below this loop won't happen. I didn't make the while loop a different function because I was using those variables i and j. So I don't see how I can refactor beyond this loop. So my main question is: How would I pass the values of i and j to a new method: "animateBall" and how would I use ball.move(vx + vx, vy + vy); in that new method if ball has been declared in the buildBall method? I understand this is probably a simple thing of better understanding variable scope and passing arguments, but I'm not quite there yet...

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  • Why am I getting ClassNotFoundExpection when I have properly imported said class and am looking at it in its directory?

    - by Strider
    This is my Javac compiling statement: javac -cp "C:\java\code\j3D\j3dcore.jar;C:\java\code\j3D\j3dutils.jar;C:\java\code\j3D\vecmath.jar" Simple.java compiles with no problems. The three jar files (j3dcore, j3dutils, and vecmath) are the essential jar's for my program (or at least I am led to believe according to this official tutorial on J3D For the record I ripped this code almost line from line from this pdf file. jar files are correctly located in referenced locations When I run my Simple program, (java Simple) I am greeted with Exception in thread "main" java.lang.NoClassDefFoundError: javax/media/j3d/Cavas3d Caused by: java.lang.ClassNotFoundExpection: javax.media.j3d.Canvas3D Currently I am staring directly at this Canvas3D.class that is located within j3dcore.jar\javax\media\j3d\ wtfisthis.jpg Here is the source code: //First java3D Program import java.applet.Applet; import java.awt.BorderLayout; import java.awt.Frame; import java.awt.event.*; import com.sun.j3d.utils.applet.MainFrame; import com.sun.j3d.utils.universe.*; import com.sun.j3d.utils.geometry.ColorCube; import javax.media.j3d.*; import javax.vecmath.*; import java.awt.GraphicsConfiguration; public class Simple extends Applet { public Simple() { setLayout(new BorderLayout()); GraphicsConfiguration config = SimpleUniverse.getPreferredConfiguration(); Canvas3D canvas3D = new Canvas3D(config); add("Center", canvas3D); BranchGroup scene = createSceneGraph(); scene.compile(); // SimpleUniverse is a Convenience Utility class SimpleUniverse simpleU = new SimpleUniverse(canvas3D); // This moves the ViewPlatform back a bit so the // objects in the scene can be viewed. simpleU.getViewingPlatform().setNominalViewingTransform(); simpleU.addBranchGraph(scene); } // end of HelloJava3Da (constructor) public BranchGroup createSceneGraph() { // Create the root of the branch graph BranchGroup objRoot = new BranchGroup(); // Create a simple shape leaf node, add it to the scene graph. // ColorCube is a Convenience Utility class objRoot.addChild(new ColorCube(0.4)); return objRoot; } public static void main(String args[]){ Simple world = new Simple(); } }` Did I import correctly? Did I incorrectly reference my jar files in my Javac statement? If I clearly see Canvas3D within its correct directory why cant java find it? The first folder in both j3dcore.jar and vecmath.jar is "javax". Is the compiler getting confused? If the compiler is getting confused how do I specify where to find that exact class when referencing it within my source code?

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  • CSS / HTML - Image will not show up

    - by weka
    Ugh, ok. I've been up all night working this thing and now an image won't show. It's so darn annoying. Trying to get this .png image to show up on a simple PHP webpage. I just wanna go to sleep X_X CSS: <style> .achievement { position:relative; width:500px; background:#B5B5B5; float:left; padding:10px; margin-bottom:10px; } .icon { float:left; width:32px; height:32px; background: url("images/trophy.php") no-repeat center; padding:05px; border:4px solid #4D4D4D; } .ptsgained { position:absolute; top:0; right:0; background:#79E310; color:#fff; font-family:Tahoma; font-weight:bold; font-size:12px; padding:5px; } .achievement h1 { color:#454545; font-size:12pt; font-family:Georgia; font-weight:none; margin:0;padding:0; } .achievement p { margin:0;padding:0; font-size:12px; font-family:Tahoma; color:#1C1C1C; } .text { margin-left:10px; float:left; } </style> HTML: <div class="achievement"> <span class="ptsgained">+10</span> <div class="icon"></div> <div class="text"><h1>All Around Submitter</h1> <p>Submit and have approved content in all 6 areas.</p> </div> </div> What am I doing wrong, guys? :\

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  • Google maps api v3: geocoding multiple addresses and infowindow

    - by user2536786
    I am trying to get infowindow for multiple addresses. Its creating markers but when I click on markers, infowindow is not popping up. Please help and see what could be wrong in this code. Rest all info is fine only issue is with infowindow not coming up. <!DOCTYPE html> <html> <head> <meta http-equiv="content-type" content="text/html; charset=UTF-8" /> <title>Google Maps Multiple Markers</title> <script src="http://maps.google.com/maps/api/js?sensor=false" type="text/javascript"></script> </head> <body> <div id="map" style="height: 800px;"></div> <script type="text/javascript"> var locations = [ ['Bondi Beach', '850 Bay st 04 Toronto, Ont'], ['Coogee Beach', '932 Bay Street, Toronto, ON M5S 1B1'], ['Cronulla Beach', '61 Town Centre Court, Toronto, ON M1P'], ['Manly Beach', '832 Bay Street, Toronto, ON M5S 1B1'], ['Maroubra Beach', '606 New Toronto Street, Toronto, ON M8V 2E8'] ]; var map = new google.maps.Map(document.getElementById('map'), { zoom: 10, center: new google.maps.LatLng(43.253205,-80.480347), mapTypeId: google.maps.MapTypeId.ROADMAP }); var infowindow = new google.maps.InfoWindow(); var geocoder = new google.maps.Geocoder(); var marker, i; for (i = 0; i < locations.length; i++) { geocoder.geocode( { 'address': locations[i][1]}, function(results, status) { //alert(status); if (status == google.maps.GeocoderStatus.OK) { //alert(results[0].geometry.location); map.setCenter(results[0].geometry.location); marker = new google.maps.Marker({ position: results[0].geometry.location, map: map }); google.maps.event.addListener(marker, 'mouseover', function() { infowindow.open(marker, map);}); google.maps.event.addListener(marker, 'mouseout', function() { infowindow.close();}); } else { alert("some problem in geocode" + status); } }); } </script> </body> </html>

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  • PHP timeslot booking*

    - by boyee007
    regarding of this question.. PHP Booking timeslot I tried 'GROUP BY' id_timeslot still didnt work, as its only showing the booked timeslot not available i tried that solution, but give me an error and not quite understand how to use 'coelence' table timeslot (id_timeslot integer); table doctor (id_doctor integer); table bookslot (id_bookslot, id_doctor, id_timeslot integer); insert into doctor (id_doctor) values (1 = doc_A), (2 = doc_B), (3 = doc_C); insert into TimeSlot (id_timeslot) values (1 = 10:00:00), (2 = 10:15:00), (3 = 10:30:00), (4 = 10:45:00); insert into bookslot (id_doctor,id_timeslot) values (1,1), (1,5), (2,1), (2,4), (3,1); Join mysql table $q = $mysqli->query("SELECT * FROM bookslot RIGHT JOIN timeslot ON bookslot.id_timeslot = timeslot.id_timeslot LEFT JOIN doctor ON bookslot.id_doctor = doctor.id_doctor "); echoing result and checking if it matches todays date or else set available while($r = $q->fetch_array(MYSQLI_ASSOC)) : echo '<tr>'; echo '<td align="center">' . $r['times'] . '</td>'; if($r['booked_date'] == date('Y-m-d') && $r['id_doctor'] == 1): echo '<td><a href="#available" class="booked">booked</a></td>'; else : echo '<td><a href="#" class="available">available</a></td>'; endif; if($r['booked_date'] == date('Y-m-d') && $r['id_doctor'] == 2): echo '<td><a href="#available" class="booked">booked</a></td>'; else : echo '<td><a href="#" class="available">available</a></td>'; endif; if($r['booked_date'] == date('Y-m-d') && $r['id_doctor'] == 3): echo '<td><a href="#available" class="booked">booked</a></td>'; else : echo '<td><a href="#" class="available">available</a></td>'; endif; echo '</tr>'; endwhile; result from webpage and i want the result look like: id_timeslot doc_A doc_B doc_C ---------------------------------------------- 1 booked booked booked 2 available available available 3 available available available 4 available booked available 5 booked available available Any other solution please!

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  • how to check if there is one selected radio button among the group?

    - by assehj
    Good day... I am here again to ask your idea on solving this problem. I have displayed questions using while loop. Each questions have 5 radio buttons each. The problem is, I have to check if one among the group of radio button is clicked. How to do this one using php or javascript? I have here my sample program.. Thanks in advance... $ctr = 1; $partIDTemp = ""; while($rowItems = mysql_fetch_array($resultItems)){ if( $partIDTemp != $rowItems['partID'] ){ if($ctr != 1) echo "<tr ></tr>"; echo "<tr style='font-family: Arial, Helvetica, sans-serif; font-weight:bold'><td colspan='3'>" . $rowItems['description'] . "</td></tr>"; } echo "<tr bgcolor=white style='font-family: Arial, Helvetica, sans-serif;'><td align='center'>" . $ctr . "</td>"; $rows =$rowItems['WPID']; echo "<td>" . $rowItems['descriptions']. "</td>"; $response = "response_".$rows; echo "<td><input type='radio' name='$response' value='5' /> <input type='radio' name='$response' value='4' /> <input type='radio' name='$response' value='3' /> <input type='radio' name='$response' value='2' /> <input type='radio' name='$response' value='1' /> </td>"; $ctr++; $partIDTemp = $rowItems['partID']; }

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  • How to add Items to GridView in C# Windows Store App (Win8)

    - by flexage
    To keep things simple let's just say I have a c# Windows Store Project for Windows 8 that has the following items: GridView (PlatformsGrid) List«PlatformSearchResult» (allPlatforms) DataTemplate (PlatformDataTemplate) in standardstyles.xaml allPlatforms is a collection of "PlatformSearchResult"objects populated from an online API, and has the following 3 properties: ID Name Alias I am able to add a new item to the gridview for each object that exists in my allPlatforms collection, however the items are blank and do not show the data from my objects. A quick summary of the current code looks like this: XAML Markup: <!-- Platforms Content --> <GridView x:Name="PlatformsGrid" Grid.Row="1" CanReorderItems="True" CanDragItems="True" ItemTemplate="{StaticResource PlatformDataTemplate}" > <GridView.ItemsPanel> <ItemsPanelTemplate> <WrapGrid MaximumRowsOrColumns="2" VerticalChildrenAlignment="Top" HorizontalChildrenAlignment="Center" /> </ItemsPanelTemplate> </GridView.ItemsPanel> </GridView> Data Template <!-- Platform Item Template --> <DataTemplate x:Key="PlatformDataTemplate"> <Grid Background="#FF939598" Height="250" Width="250"> <Image Source="/SampleImage.png" Stretch="UniformToFill"/> <StackPanel Orientation="Vertical" Background="#CC000000" Height="90" VerticalAlignment="Bottom"> <TextBlock Text="{Binding Name}" Margin="10,3,0,0" Width="242" Height="62" TextTrimming="WordEllipsis" TextWrapping="Wrap" HorizontalAlignment="Left"/> <TextBlock Text="{Binding Alias}" Margin="10,2,0,0" Width="186" Height="14" TextTrimming="WordEllipsis" HorizontalAlignment="Left" FontSize="9" Opacity="0.49"/> </StackPanel> </Grid> </DataTemplate> Controlling Function private async void FetchItemInfo_Loaded(object sender, RoutedEventArgs e) { // Get List of Top Games List<PlatformSearchResult> allPlatforms = new List<PlatformSearchResult>(); allPlatforms = await GamesDB.GetPlatforms(); // Dynamically Create Platform Tiles foreach (PlatformSearchResult platform in allPlatforms) { PlatformsGrid.DataContext = platform; PlatformsGrid.Items.Add(platform); } } How do I get the added items to show the appropriate object properties (ignoring the image for now), I'm just interested in populating the content of the TextBlocks. I appreciate any help anyone can provide! Thanks, Alex.

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  • vertical align img

    - by JK36
    I have a div called "images" which has a width of 277px. Within that div I have 9 images in it, just stored as tags. I've got the images to float left and line up quite nicely within my div, but I would like the images to align vertically, as some are portrait and others are landscape. I know I can do this if I enclose each image in a div, but the plugin I use to launch the gallery won't recognise which image is being fired, so i need to enclose them as just within the tags. This is the code I have, if someone can help me just align the images horizontally and vertically. I don't want the images to be skewed. #images_box a { float:left; padding:9px; width: 70px; height: 70px; text-align: center; vertical-align: middle; display: table-cell; } my data <div id="images"> <a class="fancybox" rel="gallery1" href="http://farm8.staticflickr.com/7069/7060779347_fbee5aae15_b.jpg" title="morning after[explored] (mariosworld343)"> <img src="http://farm8.staticflickr.com/7069/7060779347_fbee5aae15_m.jpg" alt="" /> </a> <a class="fancybox" rel="gallery1" href="http://farm8.staticflickr.com/7234/7047458501_46a2203733_b.jpg" title="Self confined... (TVidhya)"> <img src="http://farm8.staticflickr.com/7234/7047458501_46a2203733_m.jpg" alt="" /> </a> <a class="fancybox" rel="gallery1" href="http://farm8.staticflickr.com/7053/6918451990_20fa76f338_b.jpg" title="kleiner schrittmacher (KatjaGiersig)"> <img src="http://farm8.staticflickr.com/7053/6918451990_20fa76f338_m.jpg" alt="" /> </a> <a class="fancybox" rel="gallery1" href="http://farm8.staticflickr.com/7121/7059981833_abe404f4a0_b.jpg" title="(caro diario.)"> <img src="http://farm8.staticflickr.com/7121/7059981833_abe404f4a0_m.jpg" alt="" /> </a> </div>

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  • CSS submenus for a horizontal menu

    - by kalaivani
    This is the CSS I'm currently using to produce a horizontal menu. Does anyone have any suggestions on how to go about extending it to allow for submenus? /* CSS Document */ .rhm1{ width:780px; height:64px; margin:0 auto; background:url(images/rhm1_bg.gif) repeat-x; } .rhm1-left{ background:url(images/rhm1_l.gif) no-repeat; width:15px; height:64px; float:left; } .rhm1-right{ background:url(images/rhm1_r.gif) no-repeat; width:15px; height:64px; float:right; } .rhm1-bg{ background:url(images/rhm1_bg.gif) repeat-x; height:64px; } .rhm1-bg ul{ list-style:none; margin:0 auto; } .rhm1-bg li{ float:left; list-style:none; } .rhm1-bg li a{ float:left; display:block; color:#ffe8cc; text-decoration:none; font:12px 'Lucida Sans', sans-serif; font-weight:bold; padding:0 0 0 18px; height:64px; line-height:40px; text-align:center; cursor:pointer; } .rhm1-bg li a span{ float:left; display:block; padding:0 32px 0 18px; } .rhm1-bg li.current a{ color:#fff; background:url(images/rhm1_hover_l.gif) no-repeat left 5px; } .rhm1-bg li.current a span{ color:#fff; background:url(images/rhm1_hover_r.gif) no-repeat right 5px; } .rhm1-bg li a:hover{ color:#fff; background:url(images/rhm1_hover_l.gif) no-repeat left 5px; } .rhm1-bg li a:hover span{ color:#fff; background:url(images/rhm1_hover_r.gif) no-repeat right 5px; }

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  • Problem with table in php

    - by user225269
    I'm trying to create a table in php that would show the data on the mysql database based on the check box that is checked by the user. As you can see in this screen shot, it will have problems when you did not check on a checkbox before the one that will be the last: http://www.mypicx.com/04282010/1/ Here is my code: if($_POST['general'] == 'ADDRESS'){ $result2 = mysql_query("SELECT * FROM student WHERE ADDRESS='$saddress'"); ?> <table border='1'> <tr> <th>IDNO</th> <th>YEAR</th> <th>SECTION</th> <?php if ( $ShowLastName ) echo "<th>LASTNAME</th>" ?> <?php if ( $ShowFirstName ) echo "<th>FIRSTNAME</th>" ?> <?php if ( $ShowMidName ) echo "<th>MIDNAME</th>" ?> <?php if ( $ShowAddress ) echo "<th>ADDRESS</th>" ?> <?php if ( $ShowGender ) echo "<th>GENDER</th>" ?> <?php if ( $ShowReligion ) echo "<th>RELIGION</th>" ?> <?php if ( $ShowBday ) echo "<th>BIRTHDAY</th>" ?> <?php if ( $ShowContact ) echo "<th>CONTACT</th>" ?> </tr> <?php while($row = mysql_fetch_array($result2)) {?> <tr> <td><?php echo $row['IDNO']?> </td> <td><?php echo $row['YEAR'] ?> </td> <td><?php echo $row['SECTION'] ?></td> <td><?php if ( $ShowLastName ) echo $row['LASTNAME'] ?></td> <td><?php if ( $ShowFirstName ) echo $row['FIRSTNAME'] ?></td> <td><?php if ( $ShowMidName ) echo $row['MI'] ?></td> <td><?php if ( $ShowAddress ) echo $row['ADDRESS'] ?></td> <td><?php if ( $ShowGender ) echo $row['GENDER'] ?></td> <td><?php if ( $ShowReligion ) echo $row['RELIGION'] ?></td> <td><?php if ( $ShowBday ) echo $row['BIRTHDAY'] ?></td> <td><?php if ( $ShowContact ) echo $row['S_CONTACTNUM'] ?></td> </tr> <?PHP } ?> </table> <?PHP } mysql_close($con); ?> What can you recommend so that the output will not look like this when you one of the checkbox before a checkbox is not clicked: http://www.mypicx.com/04282010/2/

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  • Why does my ping command (Windows) results alternate between "timeout" and "network is not reachable"?

    - by Sopalajo de Arrierez
    My Windows is in Spanish, so I will have to paste console outputs in that language (I think that translating without knowing the exact terms used in english versions could give worse results than leaving it as it appears on screen). This is the issue: when pinging a non-existent IP from a WinXP-SP3 machine (clean Windows install, just formatted), I get sometimes a "Timeout" result, and sometimes a "network is not reachable" message. This is the result of: ping 192.168.210.1 Haciendo ping a 192.168.210.1 con 32 bytes de datos: Tiempo de espera agotado para esta solicitud. Respuesta desde 80.58.67.86: Red de destino inaccesible. Respuesta desde 80.58.67.86: Red de destino inaccesible. Tiempo de espera agotado para esta solicitud. Estadísticas de ping para 192.168.210.1: Paquetes: enviados = 4, recibidos = 2, perdidos = 2 (50% perdidos), Tiempos aproximados de ida y vuelta en milisegundos: Mínimo = 0ms, Máximo = 0ms, Media = 0ms 192.168.210.1 does not exist on the network. DHCP client is enabled, and the computer gets assigned those network config by the router. My IP: 192.168.11.2 Netmask: 255.255.255.0 Gateway: 192.168.11.1 DNS: 80.58.0.33/194.224.52.36 This is the output from "route print command": =========================================================================== Rutas activas: Destino de red Máscara de red Puerta de acceso Interfaz Métrica 0.0.0.0 0.0.0.0 192.168.11.1 192.168.11.2 20 127.0.0.0 255.0.0.0 127.0.0.1 127.0.0.1 1 192.168.11.0 255.255.255.0 192.168.11.2 192.168.11.2 20 192.168.11.2 255.255.255.255 127.0.0.1 127.0.0.1 20 192.168.11.255 255.255.255.255 192.168.11.2 192.168.11.2 20 224.0.0.0 240.0.0.0 192.168.11.2 192.168.11.2 20 255.255.255.255 255.255.255.255 192.168.11.2 192.168.11.2 1 255.255.255.255 255.255.255.255 192.168.11.2 3 1 Puerta de enlace predeterminada: 192.168.11.1 =========================================================================== Rutas persistentes: ninguno The output of: ping 1.1.1.1 Haciendo ping a 1.1.1.1 con 32 bytes de datos: Tiempo de espera agotado para esta solicitud. Tiempo de espera agotado para esta solicitud. Tiempo de espera agotado para esta solicitud. Tiempo de espera agotado para esta solicitud. Estadísticas de ping para 1.1.1.1: Paquetes: enviados = 4, recibidos = 0, perdidos = 4 1.1.1.1 does not exist on the network. and the output of: ping 10.1.1.1 Haciendo ping a 10.1.1.1 con 32 bytes de datos: Respuesta desde 80.58.67.86: Red de destino inaccesible. Tiempo de espera agotado para esta solicitud. Tiempo de espera agotado para esta solicitud. Respuesta desde 80.58.67.86: Red de destino inaccesible. Estadísticas de ping para 10.1.1.1: Paquetes: enviados = 4, recibidos = 2, perdidos = 2 (50% perdidos), 10.1.1.1 does not exist on the network. I can do some aproximate translation of what you demand if necessary. I have another computers in the same network (WinXP-SP3 and Win7-SP1), and they have, too, this problem. Gateway (Router): Buffalo WHR-HP-GN (official Buffalo firmware, not DD-WRT). I have some Linux (Debian/Kali) machine in my network, so I tested things on it: ping 192.168.210.1 PING 192.168.210.1 (192.168.210.1) 56(84) bytes of data. From 80.58.67.86 icmp_seq=1 Packet filtered From 80.58.67.86 icmp_seq=2 Packet filtered From 80.58.67.86 icmp_seq=3 Packet filtered From 80.58.67.86 icmp_seq=4 Packet filtered to the non-existing 1.1.1.1 : ping 1.1.1.1 PING 1.1.1.1 (1.1.1.1) 56(84) bytes of data. ^C --- 1.1.1.1 ping statistics --- 153 packets transmitted, 0 received, 100% packet loss, time 153215ms (no response after waiting a few minutes). and the non-existing 10.1.1.1: ping 10.1.1.1 PING 10.1.1.1 (10.1.1.1) 56(84) bytes of data. From 80.58.67.86 icmp_seq=20 Packet filtered From 80.58.67.86 icmp_seq=22 Packet filtered From 80.58.67.86 icmp_seq=23 Packet filtered From 80.58.67.86 icmp_seq=24 Packet filtered From 80.58.67.86 icmp_seq=25 Packet filtered What is going on here? I am posing this question mainly for learning purposes, but there is another reason: when all pings are returning "timeout", it creates an %ERRORLEVEL% value of 1, but if there is someone of "Network is not reachable" type, %ERRORLEVEL% goes to 0 (no error), and this could be inappropriate for a shell script (we can not use ping to detect, for example, if the network is down due to loss of contact with the gateway).

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  • problem with logout script in php

    - by user225269
    I'm a beginner in php, and I am trying to create a login and logout. But I am having problems in logging out. My logout just calls for the login form which is this: <? session_start(); session_destroy(); ?> <table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form name="form1" method="post" action="checklogin.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="3"><strong>Member Login </strong></td> </tr> <tr> <td width="78">Username</td> <td width="6">:</td> <td width="294"><input name="myusername" type="text" id="myusername"></td> </tr> <tr> <td>Password</td> <td>:</td> <td><input name="mypassword" type="text" id="mypassword"></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login"></td> </tr> </table> </td> </form> </tr> </table> My problem is, when I try to press the back button in the browser. Whoever user is using it can still access what is not supposed to be accessed when a user hasn't logged in. Do I need to add a code on the user page? I have this code on the user page: <? session_start(); if(!session_is_registered(myusername)){ header("location:main_login.php"); } ?> What can you recommend that I would do so that a script will prompt to enter the username and password again when a user clicks on the back button.

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  • ModalPopupExtender with thmbnail (problem in javascript)

    - by arny
    this is the code,it is not working in Firefox,Chrome,to show full size image unless user click on image for couple of times, I basically replace the thmbnail image with full size image in javascript, here is my code, TransitionDuration="50" FramesPerSecond="40" RequireOpenedPane="false" SelectedIndex="-1" SuppressHeaderPostbacks="true" HeaderCssClass="accordionHeader" ContentCssClass="accordionContent" OnItemDataBound="Accordion1_ItemDataBound" OnItemCommand="Accordion1_ItemCommand" ' ' Width="90px" Height="70px" onclick="togglePopupImage2(this);" CssClass="thumbnail" BorderColor="Navy" BorderStyle="Solid" BorderWidth="1" <table> <tr> <td style="background-color: #2E4d7B; height: 15px; color: White; font: arial bold 12px; padding: 5px"> <label id="imgText" runat="server"> </label> </td> </tr> <tr> <td> <asp:Image ID="imgPopup" CssClass="imgpopup" runat="server" /> </td> </tr> <tr> <td align="center" style="background-color: #2E4d7B; height: 25px;"> <asp:Button ID="btnCancel" runat="server" Text="Close" CssClass="closeimage"/> </td> </tr> </table> </asp:Panel> And javascript code: function togglePopupImage2(thumbnail2) { var imageurl = thumbnail2.src; var temp = new Array(); temp = imageurl.split('.'); var imagepopup = temp[0].substring(0, temp[0].length - 3) + "." + temp[1]; var img = new Image(); img.src = imagepopup; $get('ctl00_MainContentCPH_UserInterfaceID').style.visibility = 'visible'; $get('ctl00_MainContentCPH_imgPopup').src = img.src; //alert(img.src); if (img.width > 750) { if (screen.width == '1024' || screen.width == '800') { $get('ctl00_MainContentCPH_imgPopup').width = 550; //to show the picture in 1024 or 800 resolutions } else { $get('ctl00_MainContentCPH_imgPopup').width = 750; } } else { $get('ctl00_MainContentCPH_imgPopup').width = img.width; } if (img.height > 568) { if (screen.width == '1024' || screen.width == '800') { $get('ctl00_MainContentCPH_imgPopup').height = 350; //to show the picture in 1024 or 800 resolutions } else { $get('ctl00_MainContentCPH_imgPopup').height = 568; } } else { $get('ctl00_MainContentCPH_imgPopup').height = img.height; } // } } Please find the error and let me know what is the right way to achieve this? Thanks in advance

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  • Unexpected output while using Microsoft Visual Studio 2008 (Express Edition) C++ Command Line Tool

    - by Sujith S Pillai
    One of my friends sent this code to me, saying it doesn't work as expected: #include<stdio.h> void main() { int a [10] ={23, 100, 20, 30, 25, 45, 40, 55, 43, 42}; int sizeOfInput = sizeof(a)/sizeof(int); int b, outer, inner, c; printf("Size is : %d \n", sizeOfInput); printf("Values before bubble sort are : \n"); for ( b = 0; b < sizeOfInput; b++) printf("%d\n", a[b]); printf("End of values before bubble sort... \n"); for ( outer = sizeOfInput; outer > 0; outer-- ) { for ( inner = 0 ; inner < outer ; inner++) { printf ( "Comparing positions: %d and %d\n",inner,inner+1); if ( a[inner] > a[inner + 1] ) { int tmp = a[inner]; a[inner] = a [inner+1]; a[inner+1] = tmp; } } printf ( "Bubble sort total array size after inner loop is %d :\n",sizeOfInput); printf ( "Bubble sort sizeOfInput after inner loop is %d :\n",sizeOfInput); } printf ( "Bubble sort total array size at the end is %d :\n",sizeOfInput); for ( c = 0 ; c < sizeOfInput; c++) printf("Element: %d\n", a[c]); } I am using Micosoft Visual Studio Command Line Tool for compiling this on a Windows XP machine. cl /EHsc bubblesort01.c My friend gets the correct output on a dinosaur machine (code is compiled using TCC there). My output is unexpected. The array mysteriously grows in size, in between. If you change the code so that the variable sizeOfInput is changed to sizeOfInputt, it gives the expected results! A search done at Microsoft Visual C++ Developer Center doesn't give any results for "sizeOfInput". I am not a C/C++ expert, and am curious to find out why this happens - any C/C++ experts who can "shed some light" on this? Unrelated note: I seriously thought of rewriting the whole code to use quicksort or merge sort before posting it here. But, after all, it is not Stooge sort...

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  • Different data for different dates

    - by nsw1475
    I am making a web page which will allow users to input and view data for different dates, and to change the date, there are two buttons, one of which will display the previous day, and one which will show the next day. I know that I can do this by submitting forms and reloading the page every time they press one of these buttons, but I would rather use javascript and not have to submit a form, but I am having troubles getting it to work. Currently, I have the two buttons, and the date stored in a PHP variable, as shown in my code below: <script> function init() { <? $nutrDate = $this->parseDate(date('m/d/Y')); ?> } function nutrPrevDay() { <? $nutrDate = mktime(0, 0, 0, date('m',$nutrDate), date('d',$nutrDate)-1, date('Y',$nutrDate)); ?> alert("<? echo(date("m/d/y", $nutrDate)) ?>"); } function nutrNextDay() { <? $nutrDate = mktime(0, 0, 0, date('m',$nutrDate), date('d',$nutrDate)+1, date('Y',$nutrDate)); ?> } window.onload = init; </script> <p style="text-align:center; font-size:14px; color:#03F"> <button onclick="nutrPrevDay()" style="width:200px" >< Show Previous Day</button> <? echo(date('m/d/Y', $nutrDate)) ?> <button onclick="nutrNextDay()" style="width:200px">Show Next Day ></button> </p> I have the alert in the nutrPrevDay() only as debugging. What happens is when I click on the button, the alert shows that the day is correctly decreased (for example from May 17 to May 16), but only decreases one day, and not one day for every click. Also, I do not know how to make the text on the page (created by the line ) change to display the new date after a button is clicked. So here are my questions: 1) Is it possible to dynamically change data (such as text, and in the future, SQL queries) on a page using javascript without having to reload a page when clicking on a button? 2) If possible, how can I make those changes? 3) How can I fix this so that it will increment and decrement through dates every time a button is clicked?

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