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  • Retractable button bar using animations

    - by AndroidDev
    I want to create a button bar that is retractable: when the user clicks on a special "handle" button, the button bar should slide out of view partially so only the handle remains visible. When the bar is in retracted state only the handle is visible. Clicking on the handle should "slide out" the button bar so it is completely visible again. Ideally, the bar would start out in retracted state. I have tried some approaches using TranslateAnimation, including using a layout animation or calling "View.startAnimation" when the handle is clicked, but no luck so far. Do you guys have any tips how to approach this? Is there any decent documentation out there regarding Android animations? The documentation I find is sketchy at best. For instance, I found examples that cause a view to slide into view automatically using TranslateAnimation and a LayoutAnimationController when calling "addView", but when I call removeView no animation seems to be triggered at all, even if I set an animation that should create the opposite motion.

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  • C Programming arrays, I dont understand how I would go about making this program, If anyone can just guide me through the basic outline please :) [on hold]

    - by Rashmi Kohli
    Problem The temperature of a car engine has been measured, from real-world experiments, as shown in the table and graph below: Time (min) Temperature (oC) 0 20 1 36 2 61 3 68 4 77 5 110 Use linear regression to find the engine’s temperature at 1.5 minutes, 4.3 minutes, and any other time specified by the user. Background In engineering, many times we measure several data points in an experiment, but then we need to predict a value that we have not measured which lies between two measured values, such as the problem statement above. If the relation between the measured parameters seems to be roughly linear, then we can use linear regression to find the relationship between those parameters. In the graph of the problem statement above, the relation seems to be roughly linear. Hence, we can apply linear regression to the above problem. Assuming y {y0, y1, …yn-1} has a linear relation with x {x0, x1, … xn-1}, we can say that: y = mx+b where m and b can be found with linear regression as follows: For the problem in this lab, using linear regression gives us the following line (in blue) compared to the measured curve (in red). As you can see, there is usually a difference between the measured values and the estimated (predicted) values. What linear regression does is to minimize those differences and still give us a straight line (blue). Other methods, such as non-linear regression, are also possible to achieve higher accuracy and better curve fitting. Requirements Your program should first print the table of the temperatures similar to the way it’s printed in the problem statement. It should then calculate the temperature at minute 1.5 and 4.3 and show the answers to the user. Next, it should prompt the user to enter a time in minutes (or -1 to quit), and after reading the user’s specified time it should give the value of the engine’s temperature at that time. It should then go back to the prompt. Hints •Use a one dimensional array to store the temperature values given in the problem statement. •Use functions to separate tasks such as calculating m, calculating b, calculating the temperature at a given time, printing the prompt, etc. You can then give your algorithm as well as you pseudo code per function, as opposed to one large algorithm diagram or one large sequence of pseudo code.

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  • A marketing view of SQLBits

    - by simonsabin
    One of the most enjoyable things about SQLBits is reading all the blog posts/reviews after the event. We are normally fortunate enough not to have pissed anyone off and so the posts are generally positive. Most pieces are from attendees however this piece is from a wife of a sponsor http://iknowmarketing.wordpress.com/2012/04/02/events-community-vs-commercial/ . Its a nice piece for us as it highlights how we work and that how we focus on making the event personal for all those involved. We deal...(read more)

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  • Render different view depending on the type of the data

    - by Miau
    Hi there So lets suppose we have an action in a controller that looks a bit like this: public ViewResult SomeAction(int id) { var data = _someService.GetData(id); ... //create new view model based on the data here return View(viewModel); } What I m trying to figure out is the best way to render a diferent view based on the type fo the data. the "_someService.GetData method returns an data that knows its out type (ie not only you can do typeof(data) but also you can do data.DataType and you ll get an enum value so I could achieve what I m trying to do doing something kinda like this public ViewResult SomeAction(int id) { var data = _someService.GetData(id); //I m mapping fields to the viewModel here var viewModel = GetViewModel(data); swtich(data.DataType) case DataType.TypeOne: return View("TypeOne", viewModel); break; ... } But this does not seem to be the nicest way, (I dont event know if it would work) Is this the way to go? Should I use some sort of RenderPartial Aproach? after all , waht will change in the view is mostly the order of the data (ie the rest of the view would be quite similar) Cheers

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  • Assigning Object to View, big MySQL resultset.

    - by A Finn
    Hello (Sorry for my bad English) Is it bad practice to assign object to view and call its methods in there? I use smarty as my template engine. In my controller I could do like this 1# $this->view->assign("name", $this->model->getName); and in my view <p>{$name}</p> OR 2# $this->view->assign("Object", $this->model); and in my view <p>{$Report->getName()}</p> Well my biggest problem is that I have to handle a big amount of data coming out from the MySQL and I thought that if I would made a method that would print out the data while looping mysql_fetch_row. Well at least I know that using html-tags in the model is a bad thing to do. So I would assign the object to the view to get the result to the right position on the page.. Reading a mysql-result to an array first may cause memory problems am I right? So what is the solution doing things MVC style.. And yes Im using a framework of my own.

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  • Defining EditText imeOptions when using InputMethodManager.showSoftInput(View, int, ResultReceiver)

    - by TuomasR
    In my application I have a custom view which requires some text input. As the view in itself doesn't contain any actual views (it's a Surface with custom drawing being done), I have a FrameLayout which contains the custom view and underneath it an EditText -view. When the user does a specific action, the custom view is hidden and the EditText takes over for user input. This works fine, but android:imeOptions seem to be ignored for this view. I'm currently doing this: InputMethodManager inputMethodManager = (InputMethodManager)parent.getSystemService(Context.INPUT_METHOD_SERVICE); EditText t = (EditText)parent.findViewById(R.id.DummyEditor); t.setImeOptions(EditorInfo.IME_ACTION_DONE); inputMethodManager.showSoftInput(t, 0, new ResultReceiver(mHandler) { @Override protected void onReceiveResult( int resultCode, Bundle resultData) { // We're done System.out.println("Editing done : " + ((EditText)parent.findViewById(R.id.DummyEditor)).getText()); } } ); It seems that the setImeOptions(EditorInfo.IME_ACTION_DONE) has no effect. I've also tried adding the option to the layout XML with android:imeOptions="actionDone". No help. Any ideas?

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  • Android camera being landscaped in some devices

    - by nala4ever
    Im new to Android and I tried a tutorial for camera API. The tutorial works fine. When I use HTC desire I can see the camera view in both portrait and landscape, but when I use Samsung Galaxy I get a the camera view only in a landscaped view. I tried the following code to rotate the camera view as well.. Camera.Parameters parameters = camera.getParameters(); parameters.setRotation(90); then the camera doesn't work as expected. (screen splits into 4 and not clear). Does anyone have an idea for this issue ? Thanks.

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  • View, Control, Instruct with iTalc

    <b>Linux.com:</b> "If you work in an educational or training environment where you instruct users on the ins and outs of using computers, or you need to be able to (for whatever reason) control the PC user's use of a machine, the tools available are often quite expensive or quite difficult to use. Neither is the case in the Linux environment, where tools like iTalc are available."

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  • For a 1view/scene to 2view/scene app, what application should I choose in Xcode?

    - by Tony Xu
    The question may be simple to some others, but I have been struggling with this for a while. The app I want would be like this: first scene/view with two big buttons (no toolbar item), click each one to get into two new scenes. So totally three scenes. In Xcode, what application should I choose? And in storyboard how/should I drag/draw? Thanks. Update: thanks for the link, the big-number-user. I actually read that tutorial before I asked. A little update on what I got so far: 1, I selected "single view", so there's view controller 1 (VC1) in the storyboard. 2, dragged a navigation controller (NC), and move the initial view arrow pointing to NC 3, control-drag to link NC and VC1, selected "relationship segue root view controller" when some small dialog popup. IS THIS CORRECT? 4, created two additional VC, VC3 and VC4, control-drag link each to NC. selected "push", IS THIS CORRECT? 5, in VC1, I added two buttons, showVC3 and showVC4. NOW I DON'T KNOW how to add IBAction to button showVC3 and showVC4. I tried to control-drag it to ViewController.m file @interface and @end section, but failed. What should I do next?

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  • SQL VIEW Basics

    SQL Views are essential for the database developer. However, it is common to see them misued, or neglected. Joe Celko tackles an introduction to the subject, but there is something about the topic that makes it likely that even the experienced developer will find out something new from reading it. Get smart with SQL Backup ProGet faster, smaller backups with integrated verification.Quickly and easily DBCC CHECKDB your backups. Learn more.

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  • Android setContentView operation

    - by stormin986
    I've read that it's important to call setContentView() early in an activity since it builds the view objects that may be manipulated by subsequent code in onCreate(). In terms of lifecycle, does the view get drawn to screen as soon as setContentView() is called, or does it allow the onCreate() function to build/populate the information in the view objects, and wait to actually draw it after onCreate() completes? Thanks!

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  • SQL View: Beyond the Basics

    Joe Celko delves into the main uses of views, explains how the WITH CHECK OPTION works, and demonstrates how the INSTEAD OF trigger can be used in those cases where views cannot be updatable. What are your servers really trying to tell you? Find out with new SQL Monitor 3.0, an easy-to-use tool built for no-nonsense database professionals.For effortless insights into SQL Server, download a free trial today.

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  • MVC validation error with strongly typed view

    - by Remnant
    I have a simple form that I would like to validate on form submission. Note I have stripped out the html for ease of viewing <%=Html.TextBox("LastName", "")%> //Lastname entry <%=Html.ValidationMessage("LastName")%> <%=Html.TextBox("FirstName", "")%>//Firstname entry <%=Html.ValidationMessage("FirstName")%> <%=Html.DropDownList("JobRole", Model.JobRoleList)%> //Dropdownlist of job roles <% foreach (var record in Model.Courses) // Checkboxes of different courses for user to select { %> <li><label><input type="checkbox" name="Courses" value="<%=record.CourseName%>" /><%= record.CourseName%></label></li> <% } %> On submission of this form I would like to check that both FirstName and LastName are populated (i.e. non-zero length). In my controller I have: public ActionResult Submit(string FirstName, string LastName) { if (FirstName.Trim().Length == 0) ModelState.AddModelError("FirstName", "You must enter a first name"); if (LastName.Trim().Length == 0) ModelState.AddModelError("LastName", "You must enter a first name"); if (ModelState.IsValid) { //Update database + redirect to action } return View(); //If ModelState not valid, return to View and show error messages } Unfortunately, this code logic produces an error that states that no objects are found for JobRole and Courses. If I remove the dropdownlist and checkboxes then all works fine. The issue appears to be that when I return the View the view is expecting objects for the dropwdownlist and checkboxes (which is sensible as that is what is in my View code) How can I overcome this problem? Things I have considered: In my controller I could create a JobRoleList object and Course object to pass to the View so that it has the objects to render. The issue with this is that it will overwrite any dropdownlist / checkbox selections that the user has already made. In the parameters of my controller method Submit I could aslo capture the JobRoleList object and Course object to pass back to the View. Again, not sure this would capture any items the user has already selected. I have done much googling and reading but I cannot find a good answer. When I look at examples in books or online (e.g. Nerddinner) all the validation examples involve simple forms with TextBox inputs and don't seems to show instances with multiple checkboxes and dropdownlists. Have I missed something obvious here? What would be best practice in this situation? Thanks

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  • MVC Partial View Not Refreshing when using JSON data

    - by 40-Love
    I have a dropdown that I'm using to refresh a div with checkboxes. I am trying to figure out why my view is not refreshing if I pass in data in JSON format. If I pass in just a regular string, the view refreshes. If I pass in JSON data, the view does not refresh. If I step through the code in the Partial view, I can see the correct number of records are being passed in, however the view doesn't get refreshed with the correct number of checkboxes. I tried to add some cache directives, it didn't work. This doesn't work: $(function () { $('#ddlMoveToListNames').change(function () { var item = $(this).val(); var selectedListID = $('#ddlListNames').val(); var checkValues = $('input[name=c]:checked').map(function () { return $(this).val(); }).toArray(); $.ajax({ url: '@Url.Action("Test1", "WordList")', type: 'POST', cache: false, data: JSON.stringify({ words: checkValues, moveToListID: item, selectedListID: selectedListID }), dataType: 'json', contentType: 'application/json; charset=utf-8', success: function (result) { } }) .done(function (partialViewResult) { $("#divCheckBoxes").replaceWith(partialViewResult); }); }); }); This works: $(function () { $('#ddlMoveToListNames').change(function () { var item = $(this).val(); var selectedListID = $('#ddlListNames').val(); var checkValues = $('input[name=c]:checked').map(function () { return $(this).val(); }).toArray(); $.ajax({ url: '@Url.Action("Test1", "WordList")', type: 'POST', cache: false, data: { selectedListID: item }, success: function (result) { } }) .done(function (partialViewResult) { $("#divCheckBoxes").replaceWith(partialViewResult); }); }); }); Partial View: @model WLWeb.Models.MyModel <div id="divCheckBoxes"> @foreach (var item in Model.vwWordList) { @Html.Raw("<label><input type='checkbox' value='" + @Html.DisplayFor(modelItem => item.Word) + "' name='c'> " + @Html.DisplayFor(modelItem => item.Word) + "</label>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;"); } </div> Controller: [AcceptVerbs(HttpVerbs.Post)] [OutputCache(NoStore = true, Duration = 0, VaryByParam = "*")] public PartialViewResult Test1(MyModel vm, string[] words, string moveToListID, string selectedListID) { int listNameID = Convert.ToInt32(moveToListID); List<vwWordList> lst = db.vwWordLists.Where(s => s.Word.StartsWith("wa") && s.ListID == listNameID).ToList(); vm.vwWordList = lst; return PartialView("Partial1", vm); } View: @Html.DropDownListFor(x => Model.FilterViewModel.MoveToListNameID, Model.FilterViewModel.MoveToListNameList, new { @id = "ddlMoveToListNames", style = "width:100px;" })

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  • UIVIewController not released when view is dismissed

    - by Nelson Ko
    I have a main view, mainWindow, which presents a couple of buttons. Both buttons create a new UIViewController (mapViewController), but one will start a game and the other will resume it. Both buttons are linked via StoryBoard to the same View. They are segued to modal views as I'm not using the NavigationController. So in a typical game, if a person starts a game, but then goes back to the main menu, he triggers: [self dismissViewControllerAnimated:YES completion:nil ]; to return to the main menu. I would assume the view controller is released at this point. The user resumes the game with the second button by opening another instance of mapViewController. What is happening, tho, is some touch events will trigger methods on the original instance (and write status updates to them - therefore invisible to the current view). When I put a breakpoint in the mapViewController code, I can see the instance will be one or the other (one of which should be released). I have tried putting a delegate to the mainWindow clearing the view: [self.delegate clearMapView]; where in the mainWindow - (void) clearMapView{ gameWindow = nil; } I have also tried self.view=nil; in the mapViewController. The mapViewController code contains MVC code, where the model is static. I wonder if this may prevent ARC from releasing the view. The model.m contains: static CanShieldModel *sharedInstance; + (CanShieldModel *) sharedModel { @synchronized(self) { if (!sharedInstance) sharedInstance = [[CanShieldModel alloc] init]; return sharedInstance; } return sharedInstance; } Another post which may have a lead, but so far not successful, is UIViewController not being released when popped I have in ViewDidLoad: // checks to see if app goes inactive - saves. [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(resignActive) name:UIApplicationWillResignActiveNotification object:nil]; with the corresponding in ViewDidUnload: [[NSNotificationCenter defaultCenter] removeObserver:self name:UIApplicationWillResignActiveNotification object:nil]; Does anyone have any suggestions? EDIT: - (void) prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender{ NSString *identifier = segue.identifier; if ([identifier isEqualToString: @"Start Game"]){ gameWindow = (ViewController *)[segue destinationViewController]; gameWindow.newgame=-1; gameWindow.delegate = self; } else if ([identifier isEqualToString: @"Resume Game"]){ gameWindow = (ViewController *)[segue destinationViewController]; gameWindow.newgame=0; gameWindow.delegate = self;

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  • ImageView place at center on click in gallery view

    - by TGMCians
    i used gallery view in which i place multiple imageview dynamically but on click imageview place at center and second question how to start first imageview from left of screen. I do not want to change the place until user scroll horizontally by finger . Is there any way to achieve this. Please help for this.. private class ImageAdapter extends BaseAdapter{ public ImageAdapter() { //To set blank at bottom and make visible TextView textView = (TextView)findViewById(R.id.textView2); textView.setVisibility(View.VISIBLE); //To set the visibility visible of gallery myGallery.setVisibility(View.VISIBLE); } public int getCount() { return ProductItemArray.Image_URL.length; } public Object getItem(int position) { return null; } public long getItemId(int position) { return 0; } public View getView(int position, View arg1, ViewGroup arg2) { ImageView bottomImageView = new ImageView(context); if(Helper.isTablet(context)) bottomImageView.setLayoutParams(new Gallery.LayoutParams(VirtualMirrorActivity.convertDpToPixel(100, context), VirtualMirrorActivity.convertDpToPixel(100, context))); else bottomImageView.setLayoutParams(new Gallery.LayoutParams(VirtualMirrorActivity.convertDpToPixel(80, context), VirtualMirrorActivity.convertDpToPixel(80, context))); UrlImageViewHelper.setUrlDrawable(bottomImageView, ProductItemArray.Image_URL[position]); bottomImageView.setBackgroundResource(R.layout.border); return bottomImageView; } } myGallery.setAdapter(new ImageAdapter()); myGallery.setSelection(1); myGallery.setOnItemClickListener(new OnItemClickListener() { @Override public void onItemClick(AdapterView<?> parent, View view, final int position, long arg3) { linearLayout.removeView(frameImageView); Thread newThread = new Thread(new Runnable() { public void run() { URL url_1 = null; try { isAlreadyExistInWishlist = false; VMProductListPaging.productUrl = ProductItemArray.Image_small_URL[position]; VMProductListPaging.productId = ProductItemArray.productId[position]; VMProductListPaging.productName = ProductItemArray.product_Name[position]; url_1 = new URL(ProductItemArray.Image_small_URL[position]); bmp = BitmapFactory.decodeStream(url_1.openConnection().getInputStream()); isExecuted = true; bitmapHandler.sendMessage(bitmapHandler.obtainMessage()); } catch (Exception e) { //Toast.makeText(context,"Sorry!! This link appears to be broken",Toast.LENGTH_LONG).show(); } } }); newThread.start(); } }); Layout.xml <Gallery android:id="@+id/galleryView" android:layout_width="fill_parent" android:layout_height="wrap_content" android:spacing="5dp" android:layout_below="@+id/sendPhoto" android:layout_marginTop="10dp" android:visibility="gone"/>

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  • Prevent Explorer From Expanding Network Folders when in Folders View

    - by Chris
    When you are browsing a network share and there are over 1000 folders in the root (like at work), is there a way to prevent Explorer from expanding all the Folders when you have the "Folders" view enabled? Explorer will open the folder your double clicked on, and show that in the right navigation pane, and it's great, but wait about five seconds and the rest of the folder list pops into view, I'd rather that not happen. There is only one folder I'm interested in (or have access to), and it's annoying waiting for Explorer to load the rest of the files.

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  • Mac OS X: Finder view options?

    - by trolle3000
    Hi there. In OS X 10.6, Finder usually looks something like this: The Finder window looks like that when you double-click on most folders or drives. However, whenever I mount a Truecrypt Volume and double-click that, it looks like this: Is there any way to default to the first view option for all types of folders? I tried view options in Finder, but it didn't seem to work.

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  • BIND split-view DNS config problem

    - by organicveggie
    We have two DNS servers: one external server controlled by our ISP and one internal server controlled by us. I'd like internal requests for foo.example.com to map to 192.168.100.5 and external requests continue to map to 1.2.3.4, so I'm trying to configure a view in bind. Unfortunately, bind fails when I attempt to reload the configuration. I'm sure I'm missing something simple, but I can't figure out what it is. options { directory "/var/cache/bind"; forwarders { 8.8.8.8; 8.8.4.4; }; auth-nxdomain no; # conform to RFC1035 listen-on-v6 { any; }; }; zone "." { type hint; file "/etc/bind/db.root"; }; zone "localhost" { type master; file "/etc/bind/db.local"; }; zone "127.in-addr.arpa" { type master; file "/etc/bind/db.127"; }; zone "0.in-addr.arpa" { type master; file "/etc/bind/db.0"; }; zone "255.in-addr.arpa" { type master; file "/etc/bind/db.255"; }; view "internal" { zone "example.com" { type master; notify no; file "/etc/bind/db.example.com"; }; }; zone "example.corp" { type master; file "/etc/bind/db.example.corp"; }; zone "100.168.192.in-addr.arpa" { type master; notify no; file "/etc/bind/db.192"; }; I have excluded the entries in the view for allow-recursion and recursion in an attempt to simplify the configuration. If I remove the view and just load the example.com zone directly, it works fine. Any advice on what I might be missing?

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