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  • Trouble setting up PATH for Java on Debian

    - by milkmansrevenge
    I am trying to get Oracle Java 7 update 3 working correctly on Debian 6. I have downloaded and set up the files in /usr/java/jre1.7.0_03. I have also set the following two lines at the end of /etc/bash.bashrc: export JAVA_HOME=/usr/java/jre1.7.0_03 export PATH=$PATH:$JAVA_HOME/bin Logging in as other users and root is fine, Java can be found: chris@mc:~$ java -version java version "1.7.0_03" Java(TM) SE Runtime Environment (build 1.7.0_03-b04) Java HotSpot(TM) 64-Bit Server VM (build 22.1-b02, mixed mode) However there are two cases where Java cannot be found as detailed below. Note that both of these worked fine when I have previously installed OpenJDK Java 6 via aptitude, but I need Oracle Java 7 for various reasons. Most importantly, I cannot run commands as another user via su, despite the PATH showing that Java should be present. The user was created with adduser chris root@mc:~# su chris -c "echo $PATH" /usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/java/jre1.7.0_03/bin:/bin root@mc:~# su chris -c "java -version" bash: java: command not found root@mc:~# su chris -c "/usr/java/jre1.7.0_03/bin/java -version" java version "1.7.0_03" ... How can it be in the PATH but not be found? Update 05/04/2012: explained by Daniel, to do with it being a non-interactive shell so files such as /etc/profile and /etc/bash.bashrc are not executed. Doing a full swap to that user and running Java works: root@mc:~# su chris chris@mc:/root$ java -version java version "1.7.0_03" ... I run a script on start up which exhibits similar but slightly different problems. The script is located in /etc/init.d/start-mystuff.sh and calls a jar: #!/bin/bash # /etc/init.d/start-mystuff.sh java -jar /opt/Mars.jar I can confirm that the script runs on start up and the exit code is 127, which indicates command not found. Inserting a line to print/save the PATH shows that it is: /sbin:/usr/sbin:/bin:/usr/bin This second problem isn't as important because I can just point directly to the Java executable in the script, but I am still curious! I have tried setting the full PATH and JAVA_HOME explicitly in /etc/environment which didn't help. I have also tried setting them in /etc/profile which doesn't seem to help either. I have tried logging in and out again after setting PATH in the various locations (duh!). Anyway, long post for what will probably have a simple one line solution :( Any help with this would be greatly appreciated, I have spent far too long trying to fix it by myself. Motivation The first problem may seem obscure but in my system I have users that are not allowed SSH access yet I still want to run processes as them. I have a ton of scripts operating in this way and don't want to have to change them all.

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  • Find all records in database that are within a certain distance of a set of lat and long points

    - by Mike L
    I've seen all the examples and here's what I got so far. my table is simple: schools (table name) - School_ID - lat - long - county - extrainfo here's my code: <?php $con = mysql_connect("xxx","xxx","xxx"); if (!$con) { die('Could not connect: ' . mysql_error()); } else {} mysql_select_db("xxx", $con); $latitude = "36.265541"; $longitude = "-119.207153"; $distance = "1"; //miles $qry = "SELECT *, (3958.75 * ACOS(SIN(" . $latitude . " / 57.2958)*SIN(lat / 57.2958)+COS(" . $latitude . " / 57.2958)*COS(lat / 57.2958)*COS(long / 57.2958 - " . $longitude . " / 57.2958))) as distance FROM schools WHERE (3958.75 * ACOS(SIN(" . $latitude . " / 57.2958)*SIN(lat / 57.2958)+COS(" . $latitude . " / 57.2958)*COS(lat / 57.2958)*COS(long / 57.2958 - " . $longitude . " / 57.2958))) <= " . $distance; $results = mysql_query($qry); if (mysql_num_rows($results) > 0) { while($row = mysql_fetch_assoc($results)) { print_r($row); } } else {} mysql_close($con); ?> but I get this error when I try to run it: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource

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  • while I scroll between the layout it takes too long to be able to scroll between the gallerie's pictures. Is there any way to reduce this time?

    - by Mateo
    Hello, this is my first question here, though I've being reading this forum for quite a while. Most of the answers to my doubts are from here :) Getting back on topic. I'm developing an Android application. I'm drawing a dynamic layout that are basically Galleries, inside a LinearLayout, inside a ScrollView, inside a RelativeLayout. The ScrollView is a must, because I'm drawing a dynamic amount of galleries that most probably will not fit on the screen. When I scroll inside the layout, I have to wait 3/4 seconds until the ScrollView "deactivates" to be able to scroll inside the galleries. What I want to do is to reduce this time to a minimum. Preferably I would like to be able to scroll inside the galleries as soon as I lift my finger from the screen, though anything lower than 2 seconds would be great as well. I've being googling around for a solution but all I could find until now where layout tutorials that didn't tackle this particular issue. I was hoping someone here knows if this is possible and if so to give me some hints on how to do so. I would prefer not to do my own ScrollView to solve this. But if that is the only way I would appreciate some help because I'm not really sure how would I solve this issue by doing that. this is my layout: public class PicturesL extends Activity implements OnClickListener, OnItemClickListener, OnItemLongClickListener { private ArrayList<ImageView> imageView = new ArrayList<ImageView>(); private StringBuilder PicsDate = new StringBuilder(); private CaWaApplication application; private long ListID; private ArrayList<Gallery> gallery = new ArrayList<Gallery>(); private ArrayList<Bitmap> Thumbails = new ArrayList<Bitmap>(); private String idioma; private ArrayList<Long> Days = new ArrayList<Long>(); private long oldDay; private long oldThumbsLoaded; private ArrayList<Long> ThumbailsDays = new ArrayList<Long>(); private ArrayList<ArrayList<Long>> IDs = new ArrayList<ArrayList<Long>>(); @Override public void onCreate(Bundle savedInstancedState) { super.onCreate(savedInstancedState); RelativeLayout layout = new RelativeLayout(this); ScrollView scroll = new ScrollView(this); LinearLayout realLayout = new LinearLayout(this); ArrayList<TextView> texts = new ArrayList<TextView>(); Button TakePic = new Button(this); idioma = com.mateloft.cawa.prefs.getLang(this); if (idioma.equals("en")) { TakePic.setText("Take Picture"); } else if (idioma.equals("es")) { TakePic.setText("Sacar Foto"); } RelativeLayout.LayoutParams scrollLP = new RelativeLayout.LayoutParams(RelativeLayout.LayoutParams.FILL_PARENT, RelativeLayout.LayoutParams.FILL_PARENT); layout.addView(scroll, scrollLP); realLayout.setOrientation(LinearLayout.VERTICAL); realLayout.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.FILL_PARENT)); scroll.addView(realLayout); TakePic.setId(67); TakePic.setOnClickListener(this); application = (CaWaApplication) getApplication(); ListID = getIntent().getExtras().getLong("listid"); getAllThumbailsOfID(); LinearLayout.LayoutParams TakeLP = new LinearLayout.LayoutParams(LinearLayout.LayoutParams.WRAP_CONTENT, LinearLayout.LayoutParams.WRAP_CONTENT); realLayout.addView(TakePic); oldThumbsLoaded = 0; int galler = 100; for (int z = 0; z < Days.size(); z++) { ThumbailsManager croppedThumbs = new ThumbailsManager(Thumbails, oldThumbsLoaded, ThumbailsDays.get(z)); oldThumbsLoaded = ThumbailsDays.get(z); texts.add(new TextView(this)); texts.get(z).setText("Day " + Days.get(z).toString()); gallery.add(new Gallery(this)); gallery.get(z).setAdapter(new ImageAdapter(this, croppedThumbs.getGallery(), 250, 175, true, ListID)); gallery.get(z).setOnItemClickListener(this); gallery.get(z).setOnItemLongClickListener(this); gallery.get(z).setId(galler); galler++; realLayout.addView(texts.get(z)); realLayout.addView(gallery.get(z)); } Log.d("PicturesL", "ListID: " + ListID); setContentView(layout); } private void getAllThumbailsOfID() { ArrayList<ModelPics> Pictures = new ArrayList<ModelPics>(); ArrayList<String> ThumbailsPath = new ArrayList<String>(); Pictures = application.dataManager.selectAllPics(); long thumbpathloaded = 0; int currentID = 0; for (int x = 0; x < Pictures.size(); x++) { if (Pictures.get(x).walkname == ListID) { if (Days.size() == 0) { Days.add(Pictures.get(x).day); oldDay = Pictures.get(x).day; IDs.add(new ArrayList<Long>()); currentID = 0; } if (oldDay != Pictures.get(x).day) { oldDay = Pictures.get(x).day; ThumbailsDays.add(thumbpathloaded); Days.add(Pictures.get(x).day); IDs.add(new ArrayList<Long>()); currentID++; } StringBuilder tpath = new StringBuilder(); tpath.append(Pictures.get(x).path.substring(0, Pictures.get(x).path.length() - 4)); tpath.append("-t.jpg"); IDs.get(currentID).add(Pictures.get(x).id); ThumbailsPath.add(tpath.toString()); thumbpathloaded++; if (x == Pictures.size() - 1) { Log.d("PicturesL", "El ultimo de los arrays, tamaño: " + Days.size()); ThumbailsDays.add(thumbpathloaded); } } } for (int y = 0; y < ThumbailsPath.size(); y++) { Thumbails.add(BitmapFactory.decodeFile(ThumbailsPath.get(y))); } } I had a memory leak on another activity when screen orientation changed that was making it slower, now it is working better. The scroller is not locking up. But sometimes, when it stops scrolling, it takes a few seconds (2/3) to disable itself. I just want it to be a little more dynamic, is there any way to override the listener and make it stop scrolling ON_ACTION_UP or something like that? I don't want to use the listview because I want to have each gallery separated by other views, now I just have text, but I will probably separate them with images with a different size than the galleries. I'm not really sure if this is possible with a listadapter and a listview, I assumed that a view can only handle only one type of object, so I'm using a scrollview of a layout, if I'm wrong please correct me :) Also this activity works as a preview or selecting the pictures you want to view in full size and manage their values. So its working only with thumbnails. Each one weights 40 kb. Guessing that is very unlikely that a user gets more than 1000~1500 pictures in this view, i thought that the activity wouldn't use more than 40~50 mb of ram in this case, adding 10 more if I open the fullsized view. So I guessed as well most devices are able to display this view in full size. If it doesn't work on low-end devices my plan was to add an option in the app preferences to let user chop this view according to some database values. And a last reason is that during most of this activity "life-cycle" (the app has pics that are relevant to the view, when it ends the value that selects which pictures are displayed has to change and no more pictures are added inside this instance of this activity); the view will be unpopulated, so most of the time showing everything wont cost much, just at the end of its cycle That was more or less what I thought at the time i created this layout. I'm open to any sort of suggestion or opinion, I just created this layout a few days ago and I'm trying to see if it can work right, because it suits my app needs. Though if there is a better way i would love to hear it Thanks Mateo

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  • how to generate unique numbers less than 8 characters long.

    - by loudiyimo
    hi I want to generate unique id's everytime i call methode generateCustumerId(). The generated id must be 8 characters long or less than 8 characters. This requirement is necessary because I need to store it in a data file and schema is determined to be 8 characters long for this id. Option 1 works fine. Instead of option 1, I want to use UUID. The problem is that UUID generates an id which has to many characters. Does someone know how to generate a unique id which is less then 99999999? option 1 import java.util.HashSet; import java.util.Random; import java.util.Set; public class CustomerIdGenerator { private static Set<String> customerIds = new HashSet<String>(); private static Random random = new Random(); // XXX: replace with java.util.UUID public static String generateCustumerId() { String customerId = null; while (customerId == null || customerIds.contains(customerId)) { customerId = String.valueOf(random.nextInt(89999999) + 10000000); } customerIds.add(customerId); return customerId; } } option2 generates an unique id which is too long public static String generateCustumerId() { String ownerId = UUID.randomUUID().toString(); System.out.println("ownerId " + ownerId); return ownerId }

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  • Store a signed long int (32bit) as 4 octets?

    - by Doori Bar
    I managed to get a unsigned long int octets-representation (BE) by reading IPv4 methods, and I managed to read about how signed integers are using the MSB as the sign indicator, which makes 00 00 00 00 to be 0, while 7F FF FF FF is 2147483647. But I can't manage how to do the same for signed long integers? #include <stdio.h> #include <string.h> int main (void) { unsigned long int intu32; unsigned char octets[4]; intu32 = 255; octets[3] = (intu32) & 255; octets[2] = (intu32 >> 8) & 255; octets[1] = (intu32 >> 16) & 255; octets[0] = (intu32 >> 24) & 255; printf("(%d)(%d)(%d)(%d)\n", octets[0], octets[1], octets[2], octets[3]); intu32 = (octets[0] << 24) | (octets[1] << 16) | (octets[2] << 8) | octets[3]; printf("intu32:%lu\n", intu32); return 0; } Thanks in advance, Doori bar

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  • C related, store a signed long int (32bit) as 4 octets?

    - by Doori Bar
    I managed to get a unsigned long int octets-representation (BE) by reading IPv4 methods, and I managed to read about how signed integers are using the MSB as the sign indicator, which makes 00 00 00 00 to be 0, while 7F FF FF FF is 2147483647. But I can't manage how to do the same for signed long integers? #include <stdio.h> #include <string.h> int main (void) { unsigned long int intu32; unsigned char octets[4]; intu32 = 255; octets[3] = (intu32) & 255; octets[2] = (intu32 >> 8) & 255; octets[1] = (intu32 >> 16) & 255; octets[0] = (intu32 >> 24) & 255; printf("(%d)(%d)(%d)(%d)\n", octets[0], octets[1], octets[2], octets[3]); intu32 = (octets[0] << 24) | (octets[1] << 16) | (octets[2] << 8) | octets[3]; printf("intu32:%lu\n", intu32); return 0; } Thanks in advance, Doori bar

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  • Why does my computer slow down after being on too long?

    - by RoboShop
    I'm sure everyone has experienced it - if you leave a computer on too long, every once in a while, it needs a fresh reboot. I have a laptop, and I only hibernate it, but every week or two, I'm going to need to restart otherwise it will just slow down (usually when windows update makes me restart) I was wondering though... why? What are some of the things that occur that eat up memory that can seemingly not be freed unless I reboot the OS. In addition, are there any programs I can get that can free up this memory and keep the computer alive for longer? Preferably for windows 7.

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  • How long does a MacBook Pro battery last on a single charge?

    - by Click Upvote
    On the official apple website it says that all Macbook pro batteries last for 7 hours, and 8 hours on the 17" macbook pro. However when I called my local apple retailer and asked him, he said the battery has a 'stand by' time of 7 hours, but if I were doing something like using an IDE to program and not watching videos, etc it could last upto 5-6 hours. When I asked him about why the official site says 7 hours, he said yes but he didn't want to lie to me, and actually the battery only lasts 5-6 hours. Does anyone who owns a macbook pro shed any light on this, such as how long the battery will actually last? I'll be buying a 15" macbook pro.

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  • Are there mapping utilities out there that will let me import geo position data (lat/long) and plot the points on a map?

    - by GregH
    I have a data file with a bunch of lat/long positions. Is there any mapping software out there (google maps, etc) that will allow me to import the positions from the file and plot them on a map? I would be this can be done through google maps but I'm not sure how to do it. I just want something that I can use quickly with a minimal amount of programming to do. I don't need to annotate anything. Just view where the points are on the map. I'm just wondering if there is something already available out there to import into google maps.

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  • For how long do I need to store the logs?

    - by mindas
    I will soon be running an internet-based public service which will physically be hosted in the UK on a virtual server. The virtual server is provided by the ISP. I was wondering if there is/are any legal requirement(s) to keep access logs, and if yes - for how long? There is a Wikipedia article that touches this subject but I'm afraid my brain just can't grasp the legislative gibberish. I believe there's EU law and there's UK law; and I do need to comply to both, right? Can somebody explain this in pure layman's terms?

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  • My website is infected, I restored a backup of the uninfected files, how long will it take to un-mark as dangerous?

    - by Cyclone
    My website www.sagamountain.com was recently infected by a malware distributor (or at least I think it may have been). I have removed all external content, google ads, firefly chat, etc. I uploaded a backup from a few weeks ago, when there was no issue. I patched the SQL injection hole. Now, how long will it take to unmark it as dangerous? Where can I contact google? I am not sure if this is the right place to post it, but since it may have been a server issue I may as well. Can sites inject base64 code via a virus on the whole server, or is it only via sql injection? Thanks for the help, viruses freak me out. Is there an online virus scanner that can scan my page and tell me what is wrong?

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  • Make shortened and long urls play together on the same domain (RewriteRule).

    - by Renato Renato
    Long story short, I want to have both example.com/aJ5 and example.com/any-other-url working together. I'm using apache and not very good at writing regex. I have already a global RewriteRule which sends everything to the app entry point. What I need is to tell apache if length($path) is <= 5 chars then rewrite to another location. I know I can use {1,5} like syntax in regex, but don't really know if it's what I'm looking for. I'd like to implement this at web-server level rather than php level. Any help is appreciated.

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  • How long will the serial port be around for?

    - by Andy
    It seems that the serial port has a remarkable ability to stick around. You might call it the hardware equivalent of Windows XP. Despite pretty much physically disappearing from laptops and the like, the need to use a serial port still exists, even if it means using a converter of some sort. It is very much a legacy piece of hardware, and yet so many devices and instruments still use it. I use it myself daily in my work with PLC's, HMI's, barcode readers, etc. In my opinion, I don't think it is going anywhere soon, but how long do you think it has got before joining the museum? Do you think it ever will?

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  • Computers "applying computer settings" for a long time on start-up...why?

    - by tombull89
    Hello. Might be a bit of a slong shot but I'm stumped, along with the ICT Manager for the school I'm working it. In one of the IT rooms when you switch a computer on it will boot through BIOS fine, but when it gets to "applying computer settings" it can hang for a long time (~15 minutes). If you unplug the computer from the network it starts up fine, gets to the login screen, then you can plug the network cable in and it will work fine. I don't think it's anything to do with the fact we've been coming close to running out of IP addresses or a problem with our DHCP. Microsoft KB says apply the latest service pack, which we've done, and check a service. Servers and domian controllers are S2003, Computers and Desktops are XP. Does anybody have any thoughts on what to try?

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  • Does the mplayer-mozilla plugin have a problem with long DIVX videos or is this a problem with the U

    - by creamcheese
    Pretty consistently when I'm watching a long DIVX movie in the browser on Karmic - say 2 hours or so - the mplayer-mozilla player stops after a half-hour or an hour and resets back to 0, so I have to reload the whole movie again over the web. It happens repeatedly so I never get past the half-way point in the DIVX version of the movie - I have to watch a flash version instead. I don't know if this is an mplayer issue or a Firefox memory issue. Anyone have any idea how to resolve this?

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  • Resizing partition in Windows 7: how long does it take?

    - by PaulJ
    Okay, maybe this is me worrying about nothing, but... I have a 500 Gb. external drive where I want to create a second partition. I plug it into my Windows 7 box, use Disk Manager and pick the "Shrink Volume" option. It says that the maximum amount to shrink is around 150 Gb. I hit "OK" and it starts working... and it's been going on for about half an hour. The light of the external HD is constantly working. Disk Manager is greyed out and has the "does not respond" message on the top bar; basically, it's behaving as a non-responding application. Is this normal for a drive of this size, or did the application hang? How long would it typically take for a drive like this to resize its partition?

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  • update terminal title from standard output of long running command?

    - by Sam Hasler
    I'd like to change the title of a terminal window during a long running command (for example: git svn fetch) with values greped from the output, whilst still writing to standard output. Is this possible using named pipes or tee and xargs? I'm thinking something like git svn fetch | sed "s/^\(r\d*\).*$/ \"\\\033]0;\"\1\"\\\007\"/" | xargs -l1 echo -ne based on: http://tldp.org/HOWTO/Xterm-Title-3.html Update: getting this to work would be enough: (echo "r9" ; echo "r10") | sed "s/^\(r\d*\).*$/ \"\\\033]0;\"\1\"\\\007\"/" | xargs -l1 echo -ne Update 2: This almost does what I want. I see r10, but not r9: (echo "r9" ; sleep 1 ; echo "r10") | sed "s/^\(r[0-9]*\)\.*$/\\\033]0;\1\\\007/" | xargs -0 echo -ne

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  • For how long do I need to store the logs?

    - by mindas
    I will soon be running an internet-based public service which will physically be hosted in the UK on a virtual server. The virtual server is provided by the ISP. I was wondering if there is/are any legal requirement(s) to keep access logs, and if yes - for how long? There is a Wikipedia article that touches this subject but I'm afraid my brain just can't grasp the legislative gibberish. I believe there's EU law and there's UK law; and I do need to comply to both, right? Can somebody explain this in pure layman's terms?

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  • How long until the chirping stops or what can I do to make it stop?

    - by MadBurn
    I know computers, I have been fixing them and building them for over a decade... but I don't know the exact electronics of them. My personal desktop PC is making an irregular, but constant, extremely high pitched chirping noise. I know this could be my hard drive, but I've heard that noise before and I believe this is a capacitor or part of the electronics. This noise is right at the edge of my hearing and I can feel it more than I can hear it. After a while, it starts to give me a headache and makes me physically sick. How long will this last? Is there anything I can do to fix it (short of replacing the entire motherboard)?

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  • Why are my DNS Lookups so long (300+ms) when accessing my web site?

    - by Travis
    I'm running a Fedora 11 server with Apache 2. I'm trying to optimize so things are as fast as possible from the server side, and I'm noticing (via Firebug for Firefox) that upon loading the homepage of one of the sites on the web server that for every file it loads (HTML, CSS, JavaScript, GIF, PNG, JPG, etc.), it does a DNS lookup. All of the files it is looking up are local to the server, so I'm surprised to see it even do a DNS lookup. Also, each of these lookups is in the 150-450ms range, which is way too high for my liking. I've tried adjusting /etc/resolve.conf to use Google's Public DNS servers. I restarted the network service and tapped the page again, but the numbers didn't go down. I've reverted back to the default DNS servers since I didn't see any gain. Any ideas on what is causing it to: a) do the dns lookup in the first place, and b) take so long when doing the actual lookup? Thanks in advance.

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  • Why are my log in times taking so long in Linux?

    - by Jamie
    In recent weeks, login times on my Ubuntu server have started timing out; both through SSH and the local command line console. Examination of the /var/auth.log yields nothing interesting. How can I diagnose long log in times on my Ubuntu server? I should mention, also, that no updates have been performed since the problem has started, and that the /, /boot/ and /usr/ file systems are mounted as readonly. [Edit] This is a stand alone machine, so it doesn't authenticate with Active Directory, LDAP etc. Also, the login prompt is responsive, as is the password prompt. Upon typing the password then CR, I'll timeout. After four a five tries, I will be able to login, although I'm worried this will start taking longer.

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  • When XP is asleep for a long time LAN reports code 43, gives up the ghost.

    - by seeanimal
    This one's got me stumped. Whenever the system is asleep for a long time, e.g overnight, the LAN driver reports error code 43 ("a problem") and turns itself off. This has being going on for months, but I never caught the problem until now. The owner merely shuttles back to a restore point I set her when the machine worked. Previously (without knowing exactly what was happening) I have tried everything to resolve this. Manually resetting the TCP/IP, fiddling with the driver Wake From LAN settings, DIFFERENT drivers, etc. etc. The solution is easy, uninstalling and reinstalling the driver. Understandably, though, the user is uncomfortable with this operation and the problem persists. What's causing it and how to stop it recurring? Any ideas? Thanks in advance to this great community. XP home SP3, Marvell Yukon 88E8056 PCI-E Gigabit Ethrnet Controller, version 10.22.7.3 (yk51x86.sys)

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  • How to run long time process on Udev event?

    - by neclude
    (sorry for my bad english) I want run ppp connection when my usb modem is connect. so i use next udev rule: ACTION=="add", SUBSYSTEM=="tty", ATTRS{idVendor}=="16d8",\ RUN+="/usr/local/bin/newPPP.sh $env{DEVNAME}" (my modem appear in /dev as ttyACM0) newPPP.sh: #!/bin/bash /usr/bin/pon prov $1 >/dev/null 2>&1 & Problem: udev event fire, newPPP.sh running, BUT newPPP.sh process will be killed after ~4-5s. ppp not have time to connect. (in it params is timeout 10s for dial up). How can i run long time process, that will not be killed? (I was try nohup. It don't work too.) System: Arch Linux

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  • How long is the Windows 8 activation period if I do not connect to the internet?

    - by Moab
    This is not a duplicate of this question, since the OP had already connected to the internet. I installed Windows 8 Consumer Retail and was not connected to the internet, and remain unconnected so it cannot automatically activate. How long can I use Windows 8 this way (never connected to the internet) and without activating the license? I want documentation links, not just an answer you think is true or read somewhere, back up any statements with clear documentation please. Answers related to Vista-W7 activation or commands used in Vista-W7 to check license status are not acceptable as Microsoft completely changed activation technologies for windows 8.

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  • Fundamental types

    - by smerlin
    I always thought the following types are "fundamental types", so i thought my anwser to this question would be correct, but surprisingly it got downvoted... Searching the web, i found this. So, IBM says aswell those types are fundamental types.. Well how do you interpret the Standard, are following types (and similar types), "fundamental types" according to the c++ standard ? unsigned int signed char long double long long long long int unsigned long long int

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