Search Results

Search found 4773 results on 191 pages for 'django orm'.

Page 39/191 | < Previous Page | 35 36 37 38 39 40 41 42 43 44 45 46  | Next Page >

• How to save links in Django

  - by xRobot

  I have a simple Blog model with a TextFields. What is the best way to save link ? 1) Saving link in the database in this form: http://www.example.com and then using some filter in the template to trasform it in form: <a rel="nofollow" href="http://www.example.com>http://www.example.com</a> 2) Saving link in the database directly in this form: <a rel="nofollow" href="http://www.example.com>http://www.example.com</a>

  Read the article

• Django: common template subsections

  - by Parand

  What's a good way to handle commonly occurring subsections of templates? For example, there is a sub-header section that's used across 4 different pages. The pages are different enough to not work well with template inheritance (ie. "extends" doesn't fit well). Is "include" the recommended method here? It feels a bit heavyweight, requiring each subsection or snippet to be in its own file. Are there any performance issues in using include or is it smart about forming template from the subsections (ie. if I make extensive use of it, do I pay any penalties)? I think what I'm looking for is something like template tags, but without the programming - a simple way to create a library of html template tags I can sprinkle in other templates.

  Read the article

• Default FileField names for Django files

  - by Adam Nelson

  I have a model: class Example(models.Model): unique_hash = models.CharField(max_length=32,unique=True) content = models.FileField(upload_to='source',blank=True,verbose_name="HTML Content File") I would like to be able to set the content filename to default to a callable, but I don't see any way to have the callable reference unique_hash (or vice versa). Is this possible?

  Read the article

• How to retrieve items from a django queryset?

  - by sharataka

  I'm trying to get the video element in a queryset but am having trouble retrieving it. user_channel = Everything.objects.filter(profile = request.user, playlist = 'Channel') print user_channel[0] #returns the first result without error print user_channel[0]['video'] #returns error Models.py: class Everything(models.Model): profile = models.ForeignKey(User) playlist = models.CharField('Playlist', max_length = 2000, null=True, blank=True) platform = models.CharField('Platform', max_length = 2000, null=True, blank=True) video = models.CharField('VideoID', max_length = 2000, null=True, blank=True) video_title = models.CharField('Title of Video', max_length = 2000, null=True, blank=True) def __unicode__(self): return u'%s %s %s %s %s' % (self.profile, self.playlist, self.platform, self.video, self.video_title)

  Read the article

• Django menu item sorting

  - by doktorno

  Hi i've got MenuItem model : MenuItem(models.Model) name=models.CharField(max_length=50) url = models.URLField() position = models.IntegerField() Class Meta: ordering =['position'] then i'm retriving it by MenuItem.objects.all() My question is how can i make any user friendly interface in admin panel to allow sorting MenuItems - for example list with + and - buttons to move MenuItem up and down ....

  Read the article

• django overwrite form clean method

  - by John

  Hi, When overwriting a form clean method how do you know if its failed validation on any of the fields? e.g. in the form below if I overwrite the clean method how do I know if the form has failed validation on any of the fields? class PersonForm(forms.Form): title = Forms.CharField(max_length=100) first_name = Forms.CharField(max_length=100) surname = Forms.CharField(max_length=100) password = Forms.CharField(max_length=100) def clean(self, value): cleaned_data = self.cleaned_data IF THE FORM HAS FAILED VALIDATION: self.data['password'] = 'abc' raise forms.ValidationError("You have failed validation!") ELSE: return cleaned_data Thanks

  Read the article

• Django Find Out if User is Authenticated in Custom Tag

  - by greggory.hz

  I'm trying to create a custom tag. Inside this custom tag, I want to be able to have some logic that checks if the user is logged in, and then have the tag rendered accordingly. This is what I have: def user_actions(context): request = template.Variable('request').resolve(context) return { 'auth': request['user'].is_athenticated() } register.inclusion_tag('layout_elements/user_actions.html', takes_context=True)(user_actions) When I run this, I get this error: Caught VariableDoesNotExist while rendering: Failed lookup for key [request] in u'[{}]' The view that renders this ends like this: return render_to_response('start/home.html', {}, context_instance=RequestContext(request)) Why doesn't the tag get a RequestContext object instead of the Context object? How can I get the tag to receive the RequestContext instead of the Context? EDIT: Whether or not it's possible to get a RequestContext inside a custom tag, I'd still be interested to know the "correct" or best way to determine a user's authentication state from within the custom tag. If that's not possible, then perhaps that kind of logic belongs elsewhere? Where?

  Read the article

• I want to select the distict value from models field and then update them (django)

  - by qulzam

  I have models... class Item(models.Model): name = models.CharField('Item Name', max_length = 30) item_code = models.CharField(max_length = 10) color = models.CharField(max_length = 150, null = True, blank = True) size = models.CharField(max_length = 30, null = True, blank = True) fabric_code = models.CharField(max_length = 30, null = True, blank = True) I have values in Item. in Item model name field has the similar values..(but the other values of record are change). I want to select the name field values distinctly(ie similar values select only ones). in one box(like combo box). What kind of form or views i use??

  Read the article

• How do I set prifix to django contrib tables names?

  - by Software Enthusiastic

  HI One of my requirement is to have prefix on all the tables of the django based project (Because db is hosted on shared server). I have used db_table Meta option to set the prefix for the tables which I have created. Now my query is how do I set the prefix for tables provided by django.contrib. Instead of auth_group django should create prefix_auth_group.... How do I do that? Thank you very much...

  Read the article

• reverse many to many fields in Django + count them

  - by cleliodpaula

  I'm trying to figure out how to solve this class Item(models.Model): type = models.ForeignKey(Type) name = models.CharField(max_lenght = 10) ... class List(models.Model): items = models.ManyToManyField(Item) ... I want to count how many an Item appears in another Lists, and show on template. view def items_by_list(request, id_): list = List.objects.get(id = id_) qr = list.items.all() #NOT TESTED num = [] i = 0 for item in qr: num[i] = List.objects.filter(items__id = item__id ).count() #FINISH NOT TESTED c = {} c.update(csrf(request)) c = {'request':request, 'list' : qr, 'num' : num} return render_to_response('items_by_list.html', c, context_instance=RequestContext(request)) template {% for dia in list %} <div class="span4" > <div> <h6 style="color: #9937d8">{{item.type.description}}</h6> <small style="color: #b2e300">{{ item.name }}</small> <small style="color: #b2e300">{{COUNT HOW MANY TIMES THE ITEM APPEAR ON OTHER LISTS}}</small> </div> {% endfor %} This seems to be easy, but I could not implement yet. If anyone has some glue to me, please help me. Thanks in advance.

  Read the article

• Django template CSS/IMG is "off" in the URL

  - by erimar77

  I have /path/to/my/theme/static/css/frontend.css which is called by base.html <link rel="stylesheet" type="text/css" href="{{ STATIC_URL }}css/frontend.css" media="all" /> In which I've got a background for the header: #header-wrapper min-width: 960px; height: 150px; background: transparent url(img/header-bg.png) repeat-x center bottom; } The file is /path/to/my/theme/static/img I've run manage.py collectstatic to gather the files and almost everything looks correct except the link generated looks like: http://example.com/static/css/img/header-bg.png In which the image does not show, because the correct URL is: http://example.com/static/img/header-bg.png Where am I going wrong??

  Read the article

• Do something every 3 loops in django-templates?

  - by eos87

  hi people, I wanna make change in css class every 3 loops. In the first three I want to use the CSS class A, in the next three I want to use the CSS class B, in the next three I want to use the CSS class A again and so on. can anyone help? Thanks

  Read the article

• django flatpage redirects

  - by Joe

  I want to make sure all of my flatpages have the "www" subdomain and redirect to it if they don't. I've looked at some middlewares that redirect to www, but 1. they usually redirect all urls to www and 2. the ones I've found don't work with flatpages. I don't want all of my site urls to redirect to include the www subdomian, just the flatpages. Anyone know how I should go about doing this? Thanks

  Read the article

• Django forms: prepopulate form with request.user and url parameter

  - by Malyo

  I'm building simple Course Management App. I want Users to sign up for Course. Here's sign up model: class CourseMembers(models.Model): student = models.ForeignKey(Student) course = models.ForeignKey(Course) def __unicode__(self): return unicode(self.student) Student model is extended User model - I'd like to fill the form with request.user. In Course model most important is course_id, which i'm passing into view throught URL parameter (for example http://127.0.0.1:8000/courses/course/1/). What i want to achieve, is to generate 'invisible' (so user can't change the inserted data) form with just input, but containing request.user and course_id parameter.

  Read the article

• Permission to view, but not to change! - Django

  - by RadiantHex

  Hi folks, is it possible to give users the permission to view, but not to change or delete. currently in the only permissions I see are "add", "change" and "delete"... but there is no "read/view" in there. I really need this as some users will only be able to consult the admin panel, in order to see what has been added in. Help would be amazing!

  Read the article

• How to loop X times in Django?

  - by Mark

  I have user reviews on my site. Each review has a rating of 1-5 stars. I want to print that many stars. How do I do it? I only see {% for X in Y %} which lets you iterate over a list, but not a certain number of times.

  Read the article

• Django model data consistency

  - by Mark

  When creating a form, you can define a bunch of methods, clean_xyz, to make sure the data gets forced into the correct format. Is there any way to do this on a model level? Perhaps I can override the field setters somehow? I want it so that if I write something like my_address.postal_code = 'a1b2c3' It will automatically get formatted into A1B 2C3. Perhaps throw an exception if it can't be converted. That way I know I'll never have any malformed data in the database.

  Read the article

• Apache mod_wsgi error: ImportError: No module named django.core.handlers.wsgi

  - by bigmac

  I am using Python 2.7 with mod_python 3.3.1 and mod_wsgi 3.3. I get an Internal Server Error and this stack trace in the apache logs: [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] import django.core.handlers.wsgi [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] ImportError: No module named django.core.handlers.wsgi [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] mod_wsgi (pid=4463): Target WSGI script '/home/one/codebase/campman/wsgi_handler.py' cannot be loaded as Python module. [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] mod_wsgi (pid=4463): Exception occurred processing WSGI script '/home/one/codebase/campman/wsgi_handler.py'. [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] Traceback (most recent call last): [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] File "/home/one/codebase/campman/wsgi_handler.py", line 13, in <module> [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] import django.core.handlers.wsgi [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] ImportError: No module named django.core.handlers.wsgi

  Read the article

• Apache mod_wsgi error: ImportError: No module named django.core.handlers.wsgi

  - by bigmac

  I am using Python 2.7 with mod_python 3.3.1 and mod_wsgi 3.3. I get an Internal Server Error and this stack trace in the apache logs: [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] import django.core.handlers.wsgi [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] ImportError: No module named django.core.handlers.wsgi [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] mod_wsgi (pid=4463): Target WSGI script '/home/one/codebase/campman/wsgi_handler.py' cannot be loaded as Python module. [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] mod_wsgi (pid=4463): Exception occurred processing WSGI script '/home/one/codebase/campman/wsgi_handler.py'. [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] Traceback (most recent call last): [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] File "/home/one/codebase/campman/wsgi_handler.py", line 13, in <module> [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] import django.core.handlers.wsgi [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] ImportError: No module named django.core.handlers.wsgi

  Read the article

• How to debug slow queries in Django+Postgres

  - by lacker

  My database queries from Django are starting to take 1-2 seconds and I'm having trouble figuring out why. Not too big a site, about 1-2 requests per second (that hit Django; static files are just served from nginx.) The thing that confuses me is, I can replicate the slowness in the Django shell using debug mode. But when I issue the exact same queries at an sql prompt they are fast. It takes about a second for a query to return, but when I check connection.queries it reports the time as under 10 ms. Here's an example (from the Django shell): >>> p = PlayerData.objects.get(uid="100000521952372") >>> a = time.time(); p.save(); print time.time() - a 1.96812295914 >>> for d in connection.queries: print d["time"] ... 0.002 0.000 0.000 How can I figure out where this extra time is being spent? I'm using Apache+mod_wsgi in daemon mode, but this happens with just the django shell as well, so I figure it is not apache-related.

  Read the article

• Running multiple FCGI/Django on Nginx for load sharing

  - by Barry

  I am running a web-service on Nginx/FastCGI/Django. Our processing time is fairly long and CPU intensive and I would like to be able to run multiple processes of Django/FastCGI to share the load. How do I set Nginx to rout requests from a single source to multiple instances of Django/FastCGI? (I can run the multiple instances on multiple ports/sockets, but I don't know how to make Nginx share the processing load between them.) Any help much appreciated.

  Read the article

• How can Django/WSGI and PHP share / on Apache?

  - by Mark Snidovich

  I have a server running an established PHP site, as well as some Django apps. Currently, a VirtualHost set up for PHP listens on port 80, and requests to certain directories are proxied to a VirtualHost set up for Django with WSGI. I'd like to change it so Django handles anything not existing as a PHP script or static file. For example, / -parsed by PHP as index.php /page.php -parsed as PHP normally /images/border.jpg -served as a static file /johnfreep -handled by Django (interpreted by urls.py) /pages/john -handled by Django /(anything else) - handled by Django I have a few ideas. It seems the options are 'php first' or 'wsgi first'. set up Django on port 80, and set Apache to skip all the known PHP, CSS or image files. Maybe using SetHandler? Anything else goes to Django to be parsed by urls.py. Set up a script referring everything to Django as a 404 handler on PHP. So, if a file is not found for a name, it sends the request path to a VirtualHost running Django to be parsed.

  Read the article

• Problem with deploying django application on mod_wsgi

  - by Shehzad009

  Hello, I seem to have a problem deploying django with mod_wsgi. In the past I've used mod_python but I want to make the change. I have been using Graham Dumpleton notes here http://code.google.com/p/modwsgi/wiki/IntegrationWithDjango1, but it still seem to not work. I get a Internal Server Error. django.wsgi file: import os import sys sys.path.append('/var/www/html') sys.path.append('/var/www/html/c2duo_crm') os.environ['DJANGO_SETTINGS_MODULE'] = 'c2duo_crm.settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() WSGIScriptAlias / /var/www/html/c2duo_crm/apache/django.wsgi Apache httpd file: <Directory /var/www/html/c2duo_crm/apache> Order allow,deny Allow from all </Directory> In my apache error log, it says I have this error This is not all of it, but I've got the most important part: [Errno 13] Permission denied: '/.python-eggs' [Thu Mar 03 14:59:25 2011] [error] [client 127.0.0.1] [Thu Mar 03 14:59:25 2011] [error] [client 127.0.0.1] The Python egg cache directory is currently set to: [Thu Mar 03 14:59:25 2011] [error] [client 127.0.0.1] [Thu Mar 03 14:59:25 2011] [error] [client 127.0.0.1] /.python-eggs [Thu Mar 03 14:59:25 2011] [error] [client 127.0.0.1] [Thu Mar 03 14:59:25 2011] [error] [client 127.0.0.1] Perhaps your account does not have write access to this directory? You can [Thu Mar 03 14:59:25 2011] [error] [client 127.0.0.1] change the cache directory by setting the PYTHON_EGG_CACHE environment [Thu Mar 03 14:59:25 2011] [error] [client 127.0.0.1] variable to point to an accessible directory.

  Read the article

• Django apache + mod_wsgi with virtualenv

  - by ArgsKwargs

  I have some questions running multiple Django sites on a VPS I have a server that uses openPanel to automatically create VirtualHosts within apache2. My ideal situation is that I would have multiple virtualenvs with different dependencies installed so the python dist-packages directory isn't contaminated for different Django sites. For example: /home/user/virtualenv1 /home/user/virtualenv2 My django applications reside at /var/www, so For example: /var/www/djangosite1 /var/www/djangosite2 Now I've read upon openPanel docs and figured out the best thing todo is create a django.conf file inside the mydomain.com.inc folder, which looks something like: /etc/apache2/openpanel.d/mydomain.com.inc/django.conf DocumentRoot /var/www/djangosite1/project WSGIScriptAlias / /var/www/djangosite1/project/wsgi.py WSGIDaemonProcess mydomain python-path=/home/user/virtualenv1/lib/python2.6/site-packages <Directory /var/www/djangosite1/project> Order allow,deny Allow from all </Directory> Alias /static /var/www/djangosite1/project/static-root Now my problem is that this setup seems unable to find the virtualenv site-packages thus not recognizing any dependencies available in the given virtualenv Also, commenting out this line doesn't seem to break or change a thing: WSGIDaemonProcess mydomain python-path=/home/user/virtualenv1/lib/python2.6/site-packages For example: > service apache2 start ImportError: No module named South When I install South outside the virtualenv everything works

  Read the article

• MediaTemple Django Bad Gateway

  - by Eeyore

  I have a site running on GS server on MediaTemple. It's Django/PostgreSQL setup. For some reason from time to time I get Bad Gateway error and I can't figure out what's causing it. What can cause this error? What else can I do to find the cause of the problem? url.access-deny = ( "~", ".inc" ) fastcgi.server = ( "/main.fcgi" => ( "main" => ( "socket" => "/var/tmp/" + appname + ".sock", # don't change this "check-local" => "disable", ) ) ) alias.url = ( "/media/" => "/home/xxx/data/python/django/django/contrib/admin/media/", "/static/" => "/home/xxx/containers/django/site/static/", ) url.rewrite-once = ( "^(/media.*)$" => "$1", "^(/static.*)$" => "$1", "^/favicon\.ico$" => "/media/favicon.ico", "^(/.*)$" => "/main.fcgi$1", ) server.error-handler-404 = "/main.fcgi"

  Read the article

< Previous Page | 35 36 37 38 39 40 41 42 43 44 45 46  | Next Page >