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  • Show different sub-sets of a view model's properties in an edit view

    - by Martin R-L
    In the context of C# 4, ASP.NET MVC 2, and NHibernate; I've got the following scenario: Let's assume an entity Product that have an association to ProductType. In a product edit view; how do I implement that only a sub-set of the product's properties are shown based on the ProductType association in an elegant and DRY way? I.e., different properties shall be shown for different values of a property of the ProductType. Use a product view model builder, and from different view models automagically generate the view with my own Html.EditorForModel() (including drop-downs and other stuff not out-of-the-box)? Attribute the properties of one view model and use the Html.EditorForModel() way aforementioned? Use one model, but implement different web controls (view strategies) (can it be done DRY?)? Something else entirely?

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  • Child view adds itself to another view every time when I show dialog

    - by user565447
    A child view had joined the main view. I don't want it to be so. Look at the screenshot. But I want that the dialog has appeared and it disappeared, and the view of the dialog didn't join itself to main view. After I called dialog, the view of the it joined every time and it looked like this: _http://s014.radikal.ru/i329/1101/cc/4ce75c9e8ae2.jpg _http://i075.radikal.ru/1101/00/f1b132b07e25.jpg But the normal view must look like this: _http://i016.radikal.ru/1101/64/0b2a4718cd0e.jpg Why it happens?

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  • Creating a button on a View from a second View

    - by BigJoke
    Hi, I have this app I'm working on, which on a second view asks (textfield) the name for a button to be created on first view. After specifying the name and pressing OK button, the first view pops up (as demanded) but there's no new button, although created indeed. Can I use the following code in a second view method, to "refresh" the first view before presenting itself. What's wrong with this code? Any other approach? Thank you. -(void)initWithView:(View1Controller *)aSuperview { theSuperview = aSuperview; } - (IBAction)itemNameButton { ... CGRect rectang; rectang = CGRectMake(0, 0, 320, 460);// just in case [theSuperview.view setNeedsDisplayInRect:rectang]; ... }

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  • django/python: is one view that handles two separate models a good idea?

    - by clime
    I am using django multi-table inheritance: Video and Image are models derived from Media. I have implemented two views: video_list and image_list, which are just proxies to media_list. media_list returns images or videos (based on input parameter model) for a certain object, which can be of type Event, Member, or Crag. It alters its behaviour based on input parameter action, which can be either "edit" or "view". The problem is that I need to ask whether the input parameter model contains Video or Image in media_list so that I can do the right thing. Similar condition is also in helper method media_edit_list that is called from the view. I don't particularly like it but the only alternative I can think of is to have separate logic for video_list and image_list and then probably also separate helper methods for videos and images: video_edit_list, image_edit_list, video_view_list, image_view_list. So four functions instead of just two. That I like even less because the video functions would be very similar to the respective image functions. What do you recommend? Here is extract of relevant parts: http://pastebin.com/07t4bdza. I'll also paste the code here: #urls url(r'^media/images/(?P<rel_model_tag>(event|member|crag))/(?P<rel_object_id>\d+)/(?P<action>(view|edit))/$', views.video_list, name='image-list') url(r'^media/videos/(?P<rel_model_tag>(event|member|crag))/(?P<rel_object_id>\d+)/(?P<action>(view|edit))/$', views.image_list, name='video-list') #views def image_list(request, rel_model_tag, rel_object_id, action): return media_list(request, Image, rel_model_tag, rel_object_id, action) def video_list(request, rel_model_tag, rel_object_id, action): return media_list(request, Video, rel_model_tag, rel_object_id, action) def media_list(request, model, rel_model_tag, rel_object_id, action): rel_model = tag_to_model(rel_model_tag) rel_object = get_object_or_404(rel_model, pk=rel_object_id) if model == Image: star_media = rel_object.star_image else: star_media = rel_object.star_video filter_params = {} if rel_model == Event: filter_params['media__event'] = rel_object_id elif rel_model == Member: filter_params['media__members'] = rel_object_id elif rel_model == Crag: filter_params['media__crag'] = rel_object_id media_list = model.objects.filter(~Q(id=star_media.id)).filter(**filter_params).order_by('media__date_added').all() context = { 'media_list': media_list, 'star_media': star_media, } if action == 'edit': return media_edit_list(request, model, rel_model_tag, rel_model_id, context) return media_view_list(request, model, rel_model_tag, rel_model_id, context) def media_view_list(request, model, rel_model_tag, rel_object_id, context): if request.is_ajax(): context['base_template'] = 'boxes/base-lite.html' return render(request, 'media/list-items.html', context) def media_edit_list(request, model, rel_model_tag, rel_object_id, context): if model == Image: get_media_record = get_image_record else: get_media_record = get_video_record media_list = [get_media_record(media, rel_model_tag, rel_object_id) for media in context['media_list']] if context['star_media']: star_media = get_media_record(star_media, rel_model_tag, rel_object_id) star_media['starred'] = True else: star_media = None json = simplejson.dumps({ 'star_media': star_media, 'media_list': media_list, }) return HttpResponse(json, content_type=json_response_mimetype(request)) # models class Media(models.Model, WebModel): title = models.CharField('title', max_length=128, default='', db_index=True, blank=True) event = models.ForeignKey(Event, null=True, default=None, blank=True) crag = models.ForeignKey(Crag, null=True, default=None, blank=True) members = models.ManyToManyField(Member, blank=True) added_by = models.ForeignKey(Member, related_name='added_images') date_added = models.DateTimeField('date added', auto_now_add=True, null=True, default=None, editable=False) def __unicode__(self): return self.title def get_absolute_url(self): return self.image.url if self.image else self.video.embed_url class Image(Media): image = ProcessedImageField(upload_to='uploads', processors=[ResizeToFit(width=1024, height=1024, upscale=False)], format='JPEG', options={'quality': 75}) thumbnail_1 = ImageSpecField(source='image', processors=[SmartResize(width=178, height=134)], format='JPEG', options={'quality': 75}) thumbnail_2 = ImageSpecField(source='image', #processors=[SmartResize(width=256, height=192)], processors=[ResizeToFit(height=164)], format='JPEG', options={'quality': 75}) class Video(Media): url = models.URLField('url', max_length=256, default='') embed_url = models.URLField('embed url', max_length=256, default='', blank=True) author = models.CharField('author', max_length=64, default='', blank=True) thumbnail = ProcessedImageField(upload_to='uploads', processors=[ResizeToFit(width=1024, height=1024, upscale=False)], format='JPEG', options={'quality': 75}, null=True, default=None, blank=True) thumbnail_1 = ImageSpecField(source='thumbnail', processors=[SmartResize(width=178, height=134)], format='JPEG', options={'quality': 75}) thumbnail_2 = ImageSpecField(source='thumbnail', #processors=[SmartResize(width=256, height=192)], processors=[ResizeToFit(height=164)], format='JPEG', options={'quality': 75}) class Crag(models.Model, WebModel): name = models.CharField('name', max_length=64, default='', db_index=True) normalized_name = models.CharField('normalized name', max_length=64, default='', editable=False) type = models.IntegerField('crag type', null=True, default=None, choices=crag_types) description = models.TextField('description', default='', blank=True) country = models.ForeignKey('country', null=True, default=None) #TODO: make this not null when db enables it latitude = models.FloatField('latitude', null=True, default=None) longitude = models.FloatField('longitude', null=True, default=None) location_index = FixedCharField('location index', length=24, default='', editable=False, db_index=True) # handled by db, used for marker clustering added_by = models.ForeignKey('member', null=True, default=None) #route_count = models.IntegerField('route count', null=True, default=None, editable=False) date_created = models.DateTimeField('date created', auto_now_add=True, null=True, default=None, editable=False) last_modified = models.DateTimeField('last modified', auto_now=True, null=True, default=None, editable=False) star_image = models.OneToOneField('Image', null=True, default=None, related_name='star_crags', on_delete=models.SET_NULL) star_video = models.OneToOneField('Video', null=True, default=None, related_name='star_crags', on_delete=models.SET_NULL)

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  • Use the output of a command as input of the next command

    - by r2b2
    so i call this php script from the command line : /usr/bin/php /var/www/bims/index.php "projects/output" and it's output is : file1 file2 file3 What I would like to do is get this output and feed to the "rm" command but i think im not doing it right : /usr/bin/php /var/www/bims/index.php "projects/output" | rm My goal is to delete whatever file names the php script outputs. What should be the proper way to do this? Thanks!

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  • iPhone - Dismiss modal view by a UITabBarController

    - by ncohen
    Hi everyone, I've got into a very strange problem. I created my own UITabBarController to customize it and it works pretty well... except for the modal views. When I dismiss the modal view (present/dismiss from the UITabBarController) with an animation, it waits until the animation did finished and goes to the first controller of the tab bar! Why does the controller change? and how can I fix it? Thanks PS: My UITabBarController view is on the main window and has a UITabBar on it. The controllers (which are managed by the tab bar) are on the main window over the tab bar controller view with a shorter height. When I present the modal view, I bring the tab bar controller view to front.

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  • how to find which package certain command belongs to on centos?

    - by hugemeow
    for example i can easily find locate command belongs to mlocate.i386 package. yum search locate mlocate.i386 : An utility for finding files by name [mirror@home /]$ rpm -qa | grep locate mlocate-0.15-1.el5.1 yum search updatedb Loaded plugins: fastestmirror, protectbase 0 packages excluded due to repository protections =========================================== Matched: updatedb =========================================== mlocate.i386 : An utility for finding files by name but it's not so easy to find which package free command belongs to: yum search free // this command just returns too much informationy rpm -qa | grep free freetype-2.2.1-31.el5_8.1 // obviously not the package by which free command is installed so is there any convinent way to know which package a specific command belongs to on linux? for example centos or some other distributions:)

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  • How to rename files in a folder using the ls command output as a pipe ?

    - by user1179459
    I am using GNU/Linux and BASH shell, What i wanted to do is in server is to i need to be able to download the files stating with B* and D* and then rename them to ~B* and ~D*(same file name just ~ in-front) i wrote following which works fine for the downloading part ideally i would like it to use ls command output as well but dont know how to do that. cd inbox get D* get B* ls B*|rename $0 ~B.* bye Any idea ? ideally what i would like to do is ls command to send the list of files one by one to the get command and then the once the get command is completed i want rename command executed renaming the server files

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  • Creating a command that compress a file and save it on a usb, but cannot detect the usb in linux.

    - by Lance
    First of all I can't detect the USB on linux using the command line. I check the directory dev and still cannot find the usb. used the df command to check the usb. I plug and typed df and then unplug and typed df again and nothing changed. We are using a server(telnet) to use the command line of linux on a windows 7 OS. The second problem I have is how can I execute the bash script that I have made. It seems that I cant put my .sh file in /usr/bin/ I would like to make my command executable in all directories like a normal command. Sorry, im still newbie at this things. This is what I get on staying on Windows too much. Sorry for my english. Thank you in advance.

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  • Is the console command cd a wildcard of sorts? [closed]

    - by Spiritios
    I was wondering while developing some application (though this is not a development question) if the cd command used in Windows is a wildcard or cross-platform command of sorts. I looked up on table with comands for Unix/Linux and MAC OS X and it turns out that it seems to be there. I am not a multi-os user, so I ask if anyone with experience in different OSes can tell me: If this command really exists and works If it has the same functionality (change directory) If there are any problems with its use If in any OS there is another command-line command that does the same in a better/more elaborate/more frequetly used way. Thanks in advance! (P.S.I am not 100% sure if this question belongs to this site or some other stackexchange site...) (P.P.S Any help in tagging this will be appreciated!)

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  • How can I get command prompt to merge my files in name order?

    - by Anastasia
    I'm using the copy command in command prompt to merge all the files in a directory, for a number of directories. The problem is, I need to edit the first file in each directory before I merge. This means that when I put in the command "copy /b *.mp3 name.mp3", the joined file has part 2 at the start and part 1 at the end, presumably because it was created last. Is there a way of using the copy command so that the files merge in name order? Each folder has a different number of parts, anywhere from 2 to 1000 so I don't want to list each file with a "+" in between. Ideally, I'd like to find something to insert into the copy command I'm already using. Otherwise, is there a way of rearranging the files in a folder so that if you enter "DIR", part 1 shows up first even if it was edited last? I'm using Windows 7 by the way.

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  • MVC keeping the PartialView in its own context - ignore the main view holding the partial view

    - by Mike
    I'm looking at the partialview components of the MVC Framework. i want my partial view to be handled in its own action and for the rest of the view to handle itself, but i'm getting an exception because the main page is not getting its view fired. Am i going around this the wrong way? My Main View (Jobs/Index.aspx): <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<MvcApplication3.Models.JobViewModel>" %> <asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server"> <% Html.RenderPartial("JobListing", Model.Jobs); %> </asp:Content> The partialview (Jobs/JobListing.ascx): <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<List<MvcApplication3.Models.Job>>" %> <table> <tr> <td> Job Title </td> <td> Job Location</td> </tr> <% foreach (var job in Model) { %> <tr> <td> <%= job.Title %> </td> <td> <%= job.Location %> </td> </tr> <% } %> <% Html.BeginForm("DoSomeStuff", "Job", null, FormMethod.Post); %> <%= Html.TextBox("SomeInfo") %> <button type="submit" id="submit" /> <% Html.EndForm(); %> The main controller for both the main view (Index) and the partialview (DoSomeStuff()) public class JobController : Controller { public ActionResult Index() { JobProvider provider = new JobProvider(Session); JobViewModel vm = new JobViewModel(); vm.Jobs = provider.GetJobs(); return View(vm); } public PartialViewResult DoSomeStuff() { return PartialView("JobListing"); } } As you can see in the partial view, it has its own form that posts to the Action called DoSomeStuff(). i want this action to handle any data submitted from that form. but when the form is submitted the main action (Index) does not fire and then i get an exception as the Model (.Models.JobViewModel) is not passed to the view that the partialview (JobListings) lives in. basically what im saying is, if i have a myview.aspx with lots of html.RenderPartialView('apartialview') that have forms in them, can i get it so these forms post to their own actions and the main view (with what ever model it inherits) is handled as well. Rather then having all the form submitting code in the main action for the view. am i do this wrong?

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  • SQL RENAME TABLE command

    - by Nano HE
    Hello. I can run RENAME TABLE student TO student_new ; The command is same and easy to follow. Is there a methods to rename a lot of tables in simple command. Assume all the tables belog to the same DB name. I don't need write a lot of code as below? RENAME TALBE pre_access TO pre_new_access; RENAME TALBE pre_activities TO pre_new_activities; RENAME TALBE pre_activityapplies TO pre_new_activityapplies; RENAME TALBE pre_adminactions TO pre_new_adminactions; RENAME TALBE pre_admincustom TO pre_new_admincustom; RENAME TALBE pre_admingroups TO pre_new_admingroups; RENAME TALBE pre_adminnotes TO pre_new_adminnotes; ... (there are still so many tables need to be renamed)

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  • Adding programatically a command to a listbox in WPF

    - by ajtp
    In my WPF application there is a listbox with items. The listbox is populated via a xmldataprovider from XAML and then binding it to Itemssource property of the listbox. Well, from XAML, I bind a comand to the listbox by doing: <ListBox.CommandBindings> <CommandBinding Command="{x:Static local:mainApp.MyCmd}" CanExecute="CanExecute" Executed ="Executed" /> </ListBox.CommandBindings> but I don't know how to programatically bind a command to each listboxitem. How to do it? Thanks in advance.

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  • Missing output when running system command in perl/cgi file

    - by aladine
    I need to write a CGI program and it will display the output of a system command: script.sh echo "++++++" VAR=$(expect -c " spawn ssh -o StrictHostKeyChecking=no $USER@$HOST $CMD match_max 100000 expect \"*?assword:*\" send -- \"$PASS\r\" send -- \"\r\" expect eof ") echo $VAR echo "++++++" In CGI file: my $command= "ksh ../cgi-bin/script.sh"; my @output= `$command`; print @output; Finally, when I run the CGI file in unix, the $VAR is a very long string including \n and some delimiters. However, when I run on web server, the output is ++++++ ++++++ So $VAR is missing when passing in the web interface/browser. I know maybe the problem is $VAR is very long string. But anyway, is there anyway to solve this problem except writing the output to a file then retrieve it from browser? Thanks if you are interested in my question.

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  • How do you reset a USB device from the command line?

    - by Casey
    Is it possible to reset the connection of a USB device, without physically disconnecting/connecting from the PC? Specifically, my device is a digital camera. I'm using gphoto2, but lately I get "device read errors", so I'd like to try to do a software-reset of the connection. From what I can tell, there are no kernel modules being loaded for the camera. The only one that looks related is usbhid.

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  • How to pass filename to StandardInput (Process) in C#?

    - by Cosmo
    Hello Guys! I'm using the native windows application spamc.exe (SpamAssassin - sawin32) from command line as follows: C:\SpamAssassin\spamc.exe -R < C:\email.eml Now I'd like to call this process from C#: Process p = new Process(); p.StartInfo.UseShellExecute = false; p.StartInfo.RedirectStandardOutput = true; p.StartInfo.RedirectStandardInput = true; p.StartInfo.FileName = @"C:\SpamAssassin\spamc.exe"; p.StartInfo.Arguments = @"-R"; p.Start(); p.StandardInput.Write(@"C:\email.eml"); p.StandardInput.Close(); Console.Write(p.StandardOutput.ReadToEnd()); p.WaitForExit(); p.Close(); The above code just passes the filename as string to spamc.exe (not the content of the file). However, this one works: Process p = new Process(); p.StartInfo.UseShellExecute = false; p.StartInfo.RedirectStandardOutput = true; p.StartInfo.RedirectStandardInput = true; p.StartInfo.FileName = @"C:\SpamAssassin\spamc.exe"; p.StartInfo.Arguments = @"-R"; p.Start(); StreamReader sr = new StreamReader(@"C:\email.eml"); string msg = sr.ReadToEnd(); sr.Close(); p.StandardInput.Write(msg); p.StandardInput.Close(); Console.Write(p.StandardOutput.ReadToEnd()); p.WaitForExit(); p.Close(); Could someone point me out why it's working if I read the file and pass the content to spamc, but doesn't work if I just pass the filename as I'd do in windows command line?

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  • Windows Command Line

    - by Markus O'Reilly
    Does anyone know how to break out of a for loop when it's typed directly into the windows command-line? I know you can use gotos and labels to break out of it when it's in a batch file, but I can't find anything about breaking out of one on the command line. Here's a simple example: C:> for /l %i in (1,0,1) do @ping -n 1 google.com || (echo ^G & msg user "Google is down!" & QUIT) This should infinitely ping google.com. If it ever fails, it beeps (echo ^G), displays a message box to the user "user" that says "Google is down!", and QUITs. I don't know how to do the quit part though. I guess I could do something like taskkill /f /im cmd.exe, but I was looking for something more elegant. Any tips?

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  • DOS batch command to read some info from text file

    - by Ray
    Hello All, I am trying to read some info from a text file by using windows command line, and save it to a variable just like "set info =1234" Below is the content of the txt file, actually I just need the revision number, and the location of it is always the same line 5, and from column 11 to 15. In the sample it's 1234, and I am wondering is there a way to save it to a variable in Dos command line. Thanks a lot! svninfo.txt: Path: . URL: https://www.abc.com Repository Root: https://www.abc.com/svn Repository UUID: 12345678-8b61-fa43-97dc-123456789 Revision: 1234 Node Kind: directory Schedule: normal Last Changed Author: abc Last Changed Rev: 1234 Last Changed Date: 2010-04-01 18:19:54 -0700 (Thu, 01 Apr 2010)

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  • route view for new IPs?

    - by Clear.Cache
    The route view method is not working for me telnet route-views.routeviews.org (logged in with user "rviews") route-viewsshow ip bgp 173.244.44.0 | inc 10464 route-viewsshow ip bgp 173.244.44.0 % Network not in table route-views Am I doing something wrong?

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  • How can I make Eclipse work (bash permission)?

    - by Binarylife
    Well , I've tried to compile and install Eclipse 3.6.2 using the instructions in : How to update Eclipse 3.5.2 to 3.6.2? . But Eclipse doesn't open. user@s-HP-550:~$ eclipse bash: /usr/bin/eclipse: Permission denied Edit : user@s-HP-550:~$ ls -l /usr/bin/eclipse -rw-r--r-- 1 root root 70 2011-06-12 18:15 /usr/bin/eclipse user@s-HP-550:~$ file /usr/bin/eclipse /usr/bin/eclipse: POSIX shell script text executable

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  • Command line switches parsed out of executable's path

    - by Roger Pate
    Why do Windows programs parse command-line switches out of their executable's path? (The latter being what is commonly known as argv[0].) For example, xcopy: C:\Temp\foo>c:/windows/system32/xcopy.exe /f /r /i /d /y * ..\bar\ Invalid number of parameters C:\Temp\foo>c:\windows\system32\xcopy.exe /f /r /i /d /y * ..\bar\ C:\Temp\foo\blah -> C:\Temp\bar\blah 1 File(s) copied What behavior should I follow in my own programs? Are there many users that expect to type command-line switches without a space (e.g. program/? instead of program /?), and should I try to support this, or should I just report an error and exit immediately? What other caveats do I need to be aware of? (In addition to Anon.'s comment below that "debug/program" runs debug.exe from PATH even if "debug\program.exe" exists.)

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  • /SUBSYSTEM:Windows program will not write to command line

    - by user144182
    I have a mixed mode C++-CLI program in Visual Studio 2005 that is set to use the /SUBSYSTEM:Windows. Generally speaking it is a graphical application that is launched from its shortcut or through the filetype registered to it. However, there is a rare occasion where a user will want to run it from the command line with arguments. I can access the arguments just fine, its when it comes to writing to the console, in response to the program being launched from the command line with arguments, where I don't see Console::WriteLine having any effect. What am I doing wrong?

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