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  • Sum in shell script

    - by Dinis Monteiro
    Why can't I create a sum of total words in this script? I get the result something like: 120+130 but it isn't 250 (as I expected)! Is there any reason? #!/bin/bash while [ -z "$count" ] ; do echo -e "request :: please enter file name " echo -e "\n\tfile one : \c" read count itself=counter.sh countWords=`wc -w $count |cut -d ' ' -f 1` countLines=`wc -l $count |cut -d ' ' -f 1` countWords_=`wc -w $itself |cut -d ' ' -f 1` echo "Number of lines: " $countLines echo "Number of words: " $countWords echo "Number of words -script: " $countWords_ echo "Number of words -total " $countWords+$countWords_ done if [ ! -e $count ] ; then echo -e "error :: file one $count doesn't exist. can't proceed." read empty exit 1 fi

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  • BASH SHELL IF ELSE run command in background

    - by bikerben
    I have used the & command before to make a script run another script in the background like so: #!/bin/bash echo "Hello World" script1.sh & script2.sh & echo "Please wait..." But lets say I have another script with an IF ELSE statment and I would like to set an ELIF statement mid flow as a background task witht the & and then carry on with processing the rest of my script knowing that while rest of the ELIF will carry running in the back ground: #!/bin/bash if cond1; then stuff sleep 10 & stuff stuff elif cond2; then something else else echo "foo" fi stuff echo "Hello World" I really hope this makes sense any help would be greatly appreciated.

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  • Shell Script - print selected columns

    - by teepusink
    Hi, I have a txt file with columns separated by tabs and based on that file, I want to create a new file that only contains information from some of the columns. This is what I have now awk '{ print $1, $5 }' filename newfilename That works except that when column 5 contains spaces e.g 123 Street, only 123 shows up and the street is considered as another column. How can I achieve what I'm trying to do? Thanks, Tee

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  • Use matching value of a RegExp to name the output file.

    - by fx42
    I have this file "file.txt" which I want to split into many smaller ones. Each line of the file has an id field which looks like "id:1" for a line belonging to id 1. For each id in the file, I like to create a file named idid.txt and put all lines that belong to this id in that file. My brute force bash script solution reads as follows. count=1 while [ $count -lt 19945 ] do cat file.txt | grep "id:$count " >> ./sets/id$count.txt count='expr $count + 1' done Now this is very inefficient as I have do read through the file about 20.000 times. Is there a way to do the same operation with only one pass through the file? - What I'm probably asking for is a way to use the value that matches for a regular expression to name the associated output file.

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  • Shell Script- each unique user

    - by Dinis Monteiro
    Hi guys I need "for each unique user, report which group they are a member of and when they last logged in" so i have: #!/bin/sh echo "Your initial login:" who | cut -d' ' -f1 | sort | uniq echo "Now is logged:" whoami echo "Group ID:" id -G $whoami case $1 in "-l") last -Fn 10 | tr -s " " ;; *) last -Fn 10 | tr -s " " | egrep -v '(^reboot)|(^$)|(^wtmp a)|(^ftp)' | cut -d" " -f1,5,7 | sort -uM | uniq -c esac My question is: how i can show the each unique user? the script above only show the more recent user logged in the system, but i need all unique users. anyone can help? thanks

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  • How to use a string as a delimiter shell script

    - by Dan
    I am reading a line and am using regex to match it in my script. (/bin/bash) echo $line | grep -E '[Ss][Uu][Bb][Jj][Ee][Cc][Tt]: [Hh][Ee][Ll][Pp]' > /dev/null 2>&1 if [[ $? = "0" && -z $subject ]]; then subject=`echo $line | cut -d: -f2` > /dev/null echo "Was able to grab a SUBJECT $line and the actual subject is -> $subject" >> $logfile fi now my problem is that i use the colon as the delimiter. but sometimes the email will have multiple colons in the subject and so I am not able to grab the whole subject because of that. I am looking for a way to grab everything after the colon following subject. even is there is a way to loop through and check for a colon or what. maybe cut allows you to cut with a string as delimiter? Not sure...any ideas? Thanks!

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  • comparing two files and merge the data

    - by Ganz Ricanz
    I have the below files, total.txt order1,5,item1 order2,6,item2 order3,7,item3 order4,6,item4 order8,9,item8 changed.txt order3,8,item3 order8,12,item8 total.txt is total order data and changed.txt is recently changed data. I want to merge the recent change with total, i want the output as , Output.txt order1,5,item1 order2,6,item2 order3,8,item3 order4,6,item4 order8,12,item8 Note : 2nd column of (3rd & 5th) row of the total.txt is updated with changed.txt file i have used the below nawk to compare the first coulmn, but not able to print it to the output file. Please help on complete the below command nawk -F"," 'NR==FNR {a[$1]=$2;next} ($1 in a) "print??"' total.txt changed.txt

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  • Redirect output of shell script to a file

    - by Buzkie
    I'm trying to redirect the output of my script and it needs to be called inside the script. filename=uname -a filename="$filename" date 2>&1 | tee $filename".txt" That is what I have so far, but it's obviously wrong. I don't know too much SH scripting, so help is appreciated -Alex

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  • appending text to all files that starts with a string

    - by learner135
    How do I append a string to all the files in a directory that starts with a particular string? I tried, cat mysig >> F* But instead of appending contents of mysig to all files starting with F, it creates a file named "F*". Obviously wildcard doesn't seem to work. Any alternatives? Thanks in advance. Edit: Also how do I delete this newly created file "F*" safely?. Using rm F* would delete all the files starting with F which I wouldn't want.

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  • shell script stopped working --- need to rewrite?

    - by OopsForgotMyOtherUserName
    The script below worked on my Mac OS X. I'm now using Ubuntu OS, and the script is no longer working. I'm wondering if there's something that I need to change here? I did change the first line from #!/bin/bash to #!/bin/sh, but it's still throwing up an error.... Essentially, I get an error when I try to run it: Syntax error: end of file unexpected (expecting ")") #!/bin/sh REMOTE='ftp.example.com' USER='USERNAME' PASSWORD='PASSWORD' CMDFILE='/jtmp/rc.ftp' FTPLOG='/jtmp/ftplog' PATTERN='SampFile*' date > $FTPLOG rm $CMDFILE 2>/dev/null LISTING=$(ftp -in $REMOTE <<EOF user $USER $PASSWORD cd download ls $PATTERN quit EOF ) echo "open $REMOTE" >> $CMDFILE echo "user $USER $PASSWORD" >> $CMDFILE echo "verbose" >> $CMDFILE echo "bin" >> $CMDFILE echo "cd download" >> $CMDFILE for FILE in $LISTING do echo "get $FILE" >> $CMDFILE done echo "quit" >> $CMDFILE ftp -in < $CMDFILE >> $FTPLOG 2>&1 rm $CMDFILE

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  • Skipping a line and reading another line in shell script while loop

    - by parameswar
    i have a code which reads a file line by line using a while loop. Inside the while loop, i have certain conditions. Is there a way using which i can skip the current line and read the next line based upon the condition ? Let me be precise: while read Line do //some sample conditions a=$Line if [ "a" == "b" ] //i want to go to the next line from this point. done < **inputfile** Any help would be appreciated.

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  • Shell complains 'cannot execute binary file'

    - by Negai
    Hi everyone, I've playing around with linux and noticed that for some mysterious reason commands like '/bin/sh ' just will not work. Each time I'm trying to start a process it yields 'cannot execute binary file' error message. m@sanctuary:~$ sh sed /bin/sed: /bin/sed: cannot execute binary file When I first launch sh and try to execute sed, it succeeds. I'm starting to loose my wits. It would be just great, if somebody could help me. Thank you.

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  • how to replace strings in file based on values from another file? (example inside)

    - by thaold
    Hi, how to replace strings in file, based on values from another file. Example, 2 files - input, output input: 12345 1 output: (1,'a lot of text', 'some other info',0,null, 12345), (2,'a lot of text', 'some other info',0,null, 12345), (3,'a lot of text', 'some other info',0,null, 12345), (4,'a lot of text', 'some other info',0,null, 12345), (5,'a lot of text', 'some other info',0,null, 12345); Needs to be done: read values from file 'input', and replace all '12345' with '1' in file 'output'. Thanks for help in advance

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  • Shell Screen -X Stuff problems

    - by user1621988
    OPTIONS="java -Xms1024M -Xmx1024M -jar craftbukkit.jar" PROCESS=server01 screen -dmS $PROCESS $OPTIONS nogui # Starting the application screen -x $PROCESS -X stuff `printf "stop\r"` # Closing the application screen -x $PROCESS # Attaching to the terminal of the application Starting the application work fine, however I got problems with stuff 'printf "stop/r"' It seems not to work when I just start up, wait some time and then try to Stop it with command above. But the strange thing is, that IF I did screen -x $PROCESS and detach (ctrl-A & ctrl-D) and then I use the Stop command it does work. So is there a way around to stuff printf without -screen -x the $PROCESS? Thank You in Advance

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  • Can a shell loop do this?

    - by helpwithshell
    Ive seen loops to unzip all zip files in a directory, however, before I run this, I would rather make sure what Im about to run will work right: for i in dir; do cd $i; unzip '*.zip'; rm -rf *.zip; cd ..; done Basically I want it to look at the output of "dir" see all the folders, for each directory cd into it, unzip all the zip archives, then remove them, then cd back and do it again until theres no more. Is this something I should do in a single command or should I consider doing this in perl?

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  • Shell scripting and test expressions

    - by Paul
    Hi, I'm trying to test whether a directory path exists when a file is passed to my script. I use dirname to strip and save the path. I want my script to run only if the path exists. This is my attempt below. FILE=$1 DIRNAME=dirname $FILE if [ -z $DIRNAME ] ; then echo "Error no file path" exit 1 fi But this doesn't work. Actual when there is no file path dirname $FILE still returns "." to DIRNAME, i.e. this directory. So how do i distinguish between "." and "/bla/bla/bla". Thanks.

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  • grep value inside a variable pointing to other variable

    - by Joice
    using : ksh *abc = 1 efg = 2 hgd = 3 not known to me * say if i have Value="abc efg hgd" abc efg hgd all contains some value which i dnt know. Now I want to grep the value contained inside abc. like for i in $Value do grep "echo $(($((echo $i | cut -d'|' -f2))))" done this grep should look for the value inside abc efg hgd grep 1 grep 2 grep 3

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  • Shell script for generating HTML out put

    - by user1638016
    The following script is generating the desired out put but not redirecting the result to /home/myuser/slavedelay.html #!/bin/bash host=<ip> echo $host user=usr1 password=mypass threshold=300 statusok=OK statuscritical=CRITICAL for i in ert7 ert9 do echo "<html>" > /home/myuser/slavedelay.html if [ "$i" == "ert7" ]; then slvdelay=`mysql -u$user -p$password -h<ip> -S /backup/mysql/mysql.sock -e 'show slave status\G' | grep Seconds_Behind_Master | sed -e 's/ *Seconds_Behind_Master: //'` if [ $slvdelay -ge $threshold ]; then echo "<tr><td>$i</td><td>CRITICAL</td>" >> /home/myuser/slavedelay.html echo "<tr><td>$i</td><td>CRITICAL</td>" else echo "<tr><td>$i</td><td>OK</td>" >> /home/myuser/slavedelay.html echo "<tr><td>$i</td><td>OK</td>" fi fi done echo "</html>" >> /home/myuser/slavedelay.html If I cat the output file /home/myuser/slavedelay.html it gives. <html> </html> Execution result : sh slave_delay.sh <tr><td>sdb7</td><td>OK</td>

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