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  • Project Euler #14 and memoization in Clojure

    - by dbyrne
    As a neophyte clojurian, it was recommended to me that I go through the Project Euler problems as a way to learn the language. Its definitely a great way to improve your skills and gain confidence. I just finished up my answer to problem #14. It works fine, but to get it running efficiently I had to implement some memoization. I couldn't use the prepackaged memoize function because of the way my code was structured, and I think it was a good experience to roll my own anyways. My question is if there is a good way to encapsulate my cache within the function itself, or if I have to define an external cache like I have done. Also, any tips to make my code more idiomatic would be appreciated. (use 'clojure.test) (def mem (atom {})) (with-test (defn chain-length ([x] (chain-length x x 0)) ([start-val x c] (if-let [e (last(find @mem x))] (let [ret (+ c e)] (swap! mem assoc start-val ret) ret) (if (<= x 1) (let [ret (+ c 1)] (swap! mem assoc start-val ret) ret) (if (even? x) (recur start-val (/ x 2) (+ c 1)) (recur start-val (+ 1 (* x 3)) (+ c 1))))))) (is (= 10 (chain-length 13)))) (with-test (defn longest-chain ([] (longest-chain 2 0 0)) ([c max start-num] (if (>= c 1000000) start-num (let [l (chain-length c)] (if (> l max) (recur (+ 1 c) l c) (recur (+ 1 c) max start-num)))))) (is (= 837799 (longest-chain))))

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  • Project Euler #119 Make Faster

    - by gangqinlaohu
    Trying to solve Project Euler problem 119: The number 512 is interesting because it is equal to the sum of its digits raised to some power: 5 + 1 + 2 = 8, and 8^3 = 512. Another example of a number with this property is 614656 = 28^4. We shall define an to be the nth term of this sequence and insist that a number must contain at least two digits to have a sum. You are given that a2 = 512 and a10 = 614656. Find a30. Question: Is there a more efficient way to find the answer than just checking every number until a30 is found? My Code int currentNum = 0; long value = 0; for (long a = 11; currentNum != 30; a++){ //maybe a++ is inefficient int test = Util.sumDigits(a); if (isPower(a, test)) { currentNum++; value = a; System.out.println(value + ":" + currentNum); } } System.out.println(value); isPower checks if a is a power of test. Util.sumDigits: public static int sumDigits(long n){ int sum = 0; String s = "" + n; while (!s.equals("")){ sum += Integer.parseInt("" + s.charAt(0)); s = s.substring(1); } return sum; } program has been running for about 30 minutes (might be overflow on the long). Output (so far): 81:1 512:2 2401:3 4913:4 5832:5 17576:6 19683:7 234256:8 390625:9 614656:10 1679616:11 17210368:12 34012224:13 52521875:14 60466176:15 205962976:16 612220032:17

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  • Interpretation of empty User-agent

    - by Amit Agrawal
    How should I interpret a empty User-agent? I have some custom analytics code and that code has to analyze only human traffic. I have got a working list of User-agents denoting human traffic, and bot traffic, but the empty User-agent is proving to be problematic. And I am getting lots of traffic with empty user agent - 10%. Additionally - I have crafted the human traffic versus bot traffic user agent list by analyzing my current logs. As such I might be missing a lot of entries in there. Is there a well maintained list of user agents denoting bot traffic, OR the inverse a list of user agents denoting human traffic?

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  • C++ Euler-Problem 14 Program Freezing

    - by Tim
    I'm working on Euler Problem 14: http://projecteuler.net/index.php?section=problems&id=14 I figured the best way would be to create a vector of numbers that kept track of how big the series was for that number... for example from 5 there are 6 steps to 1, so if ever reach the number 5 in a series, I know I have 6 steps to go and I have no need to calculate those steps. With this idea I coded up the following: #include <iostream> #include <vector> #include <iomanip> using namespace std; int main() { vector<int> sizes(1); sizes.push_back(1); sizes.push_back(2); int series, largest = 0, j; for (int i = 3; i <= 1000000; i++) { series = 0; j = i; while (j > (sizes.size()-1)) { if (j%2) { j=(3*j+1)/2; series+=2; } else { j=j/2; series++; } } series+=sizes[j]; sizes.push_back(series); if (series>largest) largest=series; cout << setw(7) << right << i << "::" << setw(5) << right << series << endl; } cout << largest << endl; return 0; } It seems to work relatively well for smaller numbers but this specific program stalls at the number 113382. Can anyone explain to me how I would go about figuring out why it freezes at this number? Is there some way I could modify my algorithim to be better? I realize that I am creating duplicates with the current way I'm doing it: for example, the series of 3 is 3,10,5,16,8,4,2,1. So I already figured out the sizes for 10,5,16,8,4,2,1 but I will duplicate those solutions later. Thanks for your help!

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  • Real User Experience Insight: Oracle’s Approach to User Experience

    - by JuergenKress
    This self-study course is the first in a series about Oracle Real User Experience Insight. Intended for a broad, general audience, this course begins with a discussion on why user experience is important, followed by Oracle’s approach to user experience. Next, several use cases for Real User Experience Insight is presented. The course ends by showing how Real User Experience Insight is integrated with Oracle Enterprise Manager 12c. This course is a suggested prerequisite for the other two self-studies in this series, one that focuses on basic navigation, data structures and workflows, and the other that focuses on best practices in deployment. SOA & BPM Partner Community For regular information on Oracle SOA Suite become a member in the SOA & BPM Partner Community for registration please visit  www.oracle.com/goto/emea/soa (OPN account required) If you need support with your account please contact the Oracle Partner Business Center. Blog Twitter LinkedIn Mix Forum Technorati Tags: real user experience,education,training,SOA Community,Oracle SOA,Oracle BPM,Community,OPN,Jürgen Kress

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  • enabling a user (created with adduser command) for lightdm graphical login

    - by Basile Starynkevitch
    I just installed Ubuntu 12.04 AMD64 on a new (empty) hard disk (because the previous crashed) Since I am quite familiar with Debian, I created two accounts with the adduser command. Since I am also having an NFSv3 file system, I explictly gave user ids when creating them (for simplicity, I keep the same user id on the home server, running Debian; the user names contain digits; I'm not using LDAP), e.g. # grep bethy /etc/passwd bethy46:x:501:501:Bethy XXX,,,06123456:/home/bethy:/bin/bash # grep bethy /etc/group bethy64:x:501: # grep bethy /etc/shadow bethy46:$6$vQ-wmuchmorethings-2o/:15479:0:99999:7:: Of course /home/bethy exists The actual user name is slightly different, and I am not showing the real entries (for obvious privacy reasons) However, these users don't appear at graphical login prompt (lightdm). And they exist in the system, they have entries in /etc/passwd & /etc/shadow and I (partly) restored their /home I've got no specific user config under /etc/lightdm ; file /etc/lightdm/users.conf mentions # NOTE: If you have AccountsService installed on your system, then LightDM # will use this instead and these settings will be ignored but I have no idea of how to deal with AccountsService thru the command line As you probably guessed, I really dislike doing administrative tasks thru a graphical interface; I much prefer the command line What did I do wrong? How can a user entry not appear in lightdm graphical login? (I need to have my wife's user entry apparent for graphical login). I am not asking how to hide a user, but how to show it in lightdm graphical prompt work-around As I have been told in comments by Nirmik and by Enzotib, lightdm probably don't show any users of uid less than 1024. So I changed all the uid to be more than 8200 (including on the Debian NFS server) and this made all the users visible at the graphical prompt. It is a pain that such a threshold is not really documented.

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  • Project Euler #15

    - by Aistina
    Hey everyone, Last night I was trying to solve challenge #15 from Project Euler: Starting in the top left corner of a 2×2 grid, there are 6 routes (without backtracking) to the bottom right corner. How many routes are there through a 20×20 grid? I figured this shouldn't be so hard, so I wrote a basic recursive function: const int gridSize = 20; // call with progress(0, 0) static int progress(int x, int y) { int i = 0; if (x < gridSize) i += progress(x + 1, y); if (y < gridSize) i += progress(x, y + 1); if (x == gridSize && y == gridSize) return 1; return i; } I verified that it worked for a smaller grids such as 2×2 or 3×3, and then set it to run for a 20×20 grid. Imagine my surprise when, 5 hours later, the program was still happily crunching the numbers, and only about 80% done (based on examining its current position/route in the grid). Clearly I'm going about this the wrong way. How would you solve this problem? I'm thinking it should be solved using an equation rather than a method like mine, but that's unfortunately not a strong side of mine. Update: I now have a working version. Basically it caches results obtained before when a n×m block still remains to be traversed. Here is the code along with some comments: // the size of our grid static int gridSize = 20; // the amount of paths available for a "NxM" block, e.g. "2x2" => 4 static Dictionary<string, long> pathsByBlock = new Dictionary<string, long>(); // calculate the surface of the block to the finish line static long calcsurface(long x, long y) { return (gridSize - x) * (gridSize - y); } // call using progress (0, 0) static long progress(long x, long y) { // first calculate the surface of the block remaining long surface = calcsurface(x, y); long i = 0; // zero surface means only 1 path remains // (we either go only right, or only down) if (surface == 0) return 1; // create a textual representation of the remaining // block, for use in the dictionary string block = (gridSize - x) + "x" + (gridSize - y); // if a same block has not been processed before if (!pathsByBlock.ContainsKey(block)) { // calculate it in the right direction if (x < gridSize) i += progress(x + 1, y); // and in the down direction if (y < gridSize) i += progress(x, y + 1); // and cache the result! pathsByBlock[block] = i; } // self-explanatory :) return pathsByBlock[block]; } Calling it 20 times, for grids with size 1×1 through 20×20 produces the following output: There are 2 paths in a 1 sized grid 0,0110006 seconds There are 6 paths in a 2 sized grid 0,0030002 seconds There are 20 paths in a 3 sized grid 0 seconds There are 70 paths in a 4 sized grid 0 seconds There are 252 paths in a 5 sized grid 0 seconds There are 924 paths in a 6 sized grid 0 seconds There are 3432 paths in a 7 sized grid 0 seconds There are 12870 paths in a 8 sized grid 0,001 seconds There are 48620 paths in a 9 sized grid 0,0010001 seconds There are 184756 paths in a 10 sized grid 0,001 seconds There are 705432 paths in a 11 sized grid 0 seconds There are 2704156 paths in a 12 sized grid 0 seconds There are 10400600 paths in a 13 sized grid 0,001 seconds There are 40116600 paths in a 14 sized grid 0 seconds There are 155117520 paths in a 15 sized grid 0 seconds There are 601080390 paths in a 16 sized grid 0,0010001 seconds There are 2333606220 paths in a 17 sized grid 0,001 seconds There are 9075135300 paths in a 18 sized grid 0,001 seconds There are 35345263800 paths in a 19 sized grid 0,001 seconds There are 137846528820 paths in a 20 sized grid 0,0010001 seconds 0,0390022 seconds in total I'm accepting danben's answer, because his helped me find this solution the most. But upvotes also to Tim Goodman and Agos :) Bonus update: After reading Eric Lippert's answer, I took another look and rewrote it somewhat. The basic idea is still the same but the caching part has been taken out and put in a separate function, like in Eric's example. The result is some much more elegant looking code. // the size of our grid const int gridSize = 20; // magic. static Func<A1, A2, R> Memoize<A1, A2, R>(this Func<A1, A2, R> f) { // Return a function which is f with caching. var dictionary = new Dictionary<string, R>(); return (A1 a1, A2 a2) => { R r; string key = a1 + "x" + a2; if (!dictionary.TryGetValue(key, out r)) { // not in cache yet r = f(a1, a2); dictionary.Add(key, r); } return r; }; } // calculate the surface of the block to the finish line static long calcsurface(long x, long y) { return (gridSize - x) * (gridSize - y); } // call using progress (0, 0) static Func<long, long, long> progress = ((Func<long, long, long>)((long x, long y) => { // first calculate the surface of the block remaining long surface = calcsurface(x, y); long i = 0; // zero surface means only 1 path remains // (we either go only right, or only down) if (surface == 0) return 1; // calculate it in the right direction if (x < gridSize) i += progress(x + 1, y); // and in the down direction if (y < gridSize) i += progress(x, y + 1); // self-explanatory :) return i; })).Memoize(); By the way, I couldn't think of a better way to use the two arguments as a key for the dictionary. I googled around a bit, and it seems this is a common solution. Oh well.

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  • Oracle WebCenter: Common User Experience Architecture

    - by kellsey.ruppel(at)oracle.com
    You may remember that the key goals of the new release of WebCenter are providing a Modern User Experience, unparalleled Application Integration, converging all the best of the existing portal platforms into WebCenter and delivering a Common User Experience Architecture.  In previous weeks we've provided an overview of Oracle WebCenter and discussed some of the other key goals and this week, we'll focus on how the new release of Oracle WebCenter delivers a Common User Experience Architecture.When Oracle talks about a Common User Experience Architecture, it really focuses on a core set of areas.  First, the way that information is accessed needs to be consistent and extensible so that as requirements change, the applications don't need to be rewritten for every change. Second, this information access layer needs to be securely accessible to any application, site, or any other channel that needs to leverage this information.  Third, there needs to be a consistent presentation layout, Oracle calls it a UI shell, so that all resources can fit together in a useable, productive way.  Fourth, there needs to be a common set of design patterns for how different menus, features, and services fit into this UI Shell for broad and productive usability.  Fifth, there needs to be a set of design patterns for the individual services that plug into this UI shell so that end users can move from one module of the application to another without new learning.  Finally, all of these layers need to be customizable in an easy way that insulates IT from patching and upgrading problems and allows the business owners the agility to quickly change with the market conditions.As Oracle has already announced, we will release our next generation of enterprise applications called Oracle Fusion Applications.  We have thousands of developers building these applications that all had different programming tool experience and UI design experience.  We've educated over 6,000 developers building Oracle Fusion Applications to leverage these Common User Experience Architecture patterns to speed their learning curve of the new Java standards as well as SOA principles to deliver a revolutionary new set of applications.  You could imagine the big challenge with getting all these developers with different backgrounds and different UI design skills to deliver a completely integrated application user experience.  This is why Oracle invested heavily in designing this Common User Experience Architecture, based on Oracle WebCenter and the Oracle Application Development Framework (ADF).  It pulls together the best practices and design patterns that Oracle development required in order to bring Fusion Applications to market and Oracle WebCenter is the user experience layer that all of this is surfaced through.  In this way, customers can quickly brand a deployment for new partnerships without having to redevelop a new site.  Or they can quickly add new options to the UI Shell to enable their line of business managers to quickly adapt to a new competitive product.  And with the core integration of the activities to produce a Business Activity Stream, customers are able to stay on top of all their key business actions when they happen as they happen and more importantly, the system can recommend actions or resources to help act on these activities.And we've authored this whole set of design patterns for Oracle development to take advantage of in delivering Fusion Applications.  We're also applying these design patterns to our existing eBusiness Suite, Peoplesoft, Siebel, and JD Edwards applications so that they can tie in the exact same way that Fusion Applications has been brought together.  This will provide customers with a complete Common User Experience Architecture for their entire ecosystem of applications within their enterprise whether they are from Oracle, another vender, or custom built applications. And this is all provided in the new release of Oracle WebCenter.  These design patterns cover elements around delivering a complete, aggregated menu of all the capabilities that their role allows independent of which application they are trying to access.   It means that as they move from one application to another, they will have a consistent user experience.  And if they are using an Oracle application, any customizations that are made to the application are preserved and managed through upgrades and patches.Be sure to check back this week as we share more information and resources on Oracle's Common User Experience Architecture.

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  • How to write a user story specific to tasks in this case

    - by vignesh
    We have planned to take up an user story say As a player I want to view the game map to know current standings of my team The sprint is for two weeks. We will be able to complete only HTML in two weeks time, this user story will take 4-6 weeks to be completed as we have a shortage of content designing resources. How can we change this user story so that HTML completion can be considered as a done for this user story and we need to take up the integration of this user story in the next sprint? Is it possible to create two different user stories, one for HTML and other for integration, testing, bug fixing etc?

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  • any clue in these logs why keyboard audio and internet are messed up

    - by mmj
    Jun 7 00:01:18 Isis lightdm: pam_unix(lightdm-autologin:session): session opened for user mimi by (uid=0) Jun 7 00:01:18 Isis lightdm: pam_ck_connector(lightdm-autologin:session): nox11 mode, ignoring PAM_TTY :0 Jun 7 00:01:26 Isis polkitd(authority=local): Registered Authentication Agent for unix-session:/org/freedesktop/ConsoleKit/Session1 (system bus name :1.36 [/usr/lib/policykit-1-gnome/polkit-gnome-authentication-agent-1], object path /org/gnome/PolicyKit1/AuthenticationAgent, locale zh_CN.UTF-8) Jun 7 00:01:29 Isis dbus[610]: [system] Rejected send message, 2 matched rules; type="method_call", sender=":1.44" (uid=1000 pid=1763 comm="/usr/lib/indicator-datetime/indicator-datetime-ser") interface="org.freedesktop.DBus.Properties" member="GetAll" error name="(unset)" requested_reply="0" destination=":1.15" (uid=0 pid=1219 comm="/usr/sbin/console-kit-daemon --no-daemon ") Jun 7 00:07:55 Isis sudo: pam_unix(sudo:auth): authentication failure; logname=mimi uid=1000 euid=0 tty=/dev/pts/1 ruser=mimi rhost= user=mimi Jun 7 00:08:11 Isis sudo: mimi : TTY=pts/1 ; PWD=/home/mimi ; USER=root ; COMMAND=/usr/bin/add-apt-repository ppa:colingille/freshlight Jun 7 00:08:11 Isis sudo: pam_unix(sudo:session): session opened for user root by mimi(uid=1000) Jun 7 00:08:32 Isis sudo: pam_unix(sudo:session): session closed for user root Jun 7 00:11:20 Isis sudo: mimi : TTY=pts/1 ; PWD=/home/mimi ; USER=root ; COMMAND=/usr/bin/apt-get install gparted Jun 7 00:11:20 Isis sudo: pam_unix(sudo:session): session opened for user root by mimi(uid=1000) Jun 7 00:11:59 Isis sudo: pam_unix(sudo:session): session closed for user root Jun 7 00:17:02 Isis CRON[2651]: pam_unix(cron:session): session opened for user root by (uid=0) Jun 7 00:17:02 Isis CRON[2651]: pam_unix(cron:session): session closed for user root Jun 7 00:17:32 Isis polkitd(authority=local): Operator of unix-session:/org/freedesktop/ConsoleKit/Session1 successfully authenticated as unix-user:mimi to gain ONE-SHOT authorization for action com.ubuntu.pkexec.gparted for unix-process:2655:96838 [/bin/sh /usr/bin/gparted-pkexec] (owned by unix-user:mimi) Jun 7 00:17:32 Isis pkexec: pam_unix(polkit-1:session): session opened for user root by (uid=1000) Jun 7 00:17:32 Isis pkexec: pam_ck_connector(polkit-1:session): cannot determine display-device Jun 7 00:17:32 Isis pkexec[2657]: mimi: Executing command [USER=root] [TTY=unknown] [CWD=/home/mimi] [COMMAND=/usr/sbin/gparted] Jun 7 00:48:15 Isis polkitd(authority=local): Operator of unix-session:/org/freedesktop/ConsoleKit/Session1 successfully authenticated as unix-user:mimi to gain ONE-SHOT authorization for action com.ubuntu.pkexec.gparted for unix-process:3813:281120 [/bin/sh /usr/bin/gparted-pkexec] (owned by unix-user:mimi) Jun 7 00:48:15 Isis pkexec: pam_unix(polkit-1:session): session opened for user root by (uid=1000) Jun 7 00:48:15 Isis pkexec: pam_ck_connector(polkit-1:session): cannot determine display-device Jun 7 00:48:15 Isis pkexec[3815]: mimi: Executing command [USER=root] [TTY=unknown] [CWD=/home/mimi] [COMMAND=/usr/sbin/gparted] Jun 7 01:17:01 Isis CRON[3960]: pam_unix(cron:session): session opened for user root by (uid=0) Jun 7 01:17:01 Isis CRON[3960]: pam_unix(cron:session): session closed for user root Jun 7 02:08:52 Isis gnome-screensaver-dialog: gkr-pam: unlocked login keyring Jun 7 02:17:01 Isis CRON[4246]: pam_unix(cron:session): session opened for user root by (uid=0) Jun 7 02:17:01 Isis CRON[4246]: pam_unix(cron:session): session closed for user root Jun 7 02:17:05 Isis sudo: mimi : TTY=pts/1 ; PWD=/home/mimi ; USER=root ; COMMAND=/usr/bin/apt-get install unetbootin Jun 7 02:17:05 Isis sudo: pam_unix(sudo:session): session opened for user root by mimi(uid=1000) Jun 7 02:17:57 Isis sudo: pam_unix(sudo:session): session closed for user root Jun 7 02:18:59 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 02:18:59 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 02:18:59 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 02:18:59 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 02:18:59 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 02:18:59 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 02:18:59 Isis sudo: mimi : 3 incorrect password attempts ; TTY=unknown ; PWD=/home/mimi ; USER=root ; COMMAND=/usr/bin/unetbootin 'rootcheck=no' Jun 7 02:18:59 Isis sudo: unable to execute /usr/sbin/sendmail: No such file or directory Jun 7 02:19:26 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 02:19:26 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 02:19:26 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 02:19:26 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 02:19:26 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 02:19:26 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 02:19:26 Isis sudo: mimi : 3 incorrect password attempts ; TTY=unknown ; PWD=/home/mimi ; USER=root ; COMMAND=/usr/bin/unetbootin 'rootcheck=no' Jun 7 02:19:26 Isis sudo: unable to execute /usr/sbin/sendmail: No such file or directory Jun 7 02:33:21 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 02:33:21 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 02:33:21 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 02:33:21 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 02:33:21 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 02:33:21 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 02:33:21 Isis sudo: mimi : 3 incorrect password attempts ; TTY=unknown ; PWD=/home/mimi ; USER=root ; COMMAND=/usr/bin/unetbootin 'rootcheck=no' Jun 7 02:33:21 Isis sudo: unable to execute /usr/sbin/sendmail: No such file or directory Jun 7 02:40:04 Isis sudo: mimi : TTY=pts/1 ; PWD=/home/mimi ; USER=root ; COMMAND=/usr/bin/unetbootin rootcheck=no Jun 7 02:40:04 Isis sudo: pam_unix(sudo:session): session opened for user root by mimi(uid=1000) Jun 7 03:17:01 Isis CRON[5506]: pam_unix(cron:session): session opened for user root by (uid=0) Jun 7 03:17:01 Isis CRON[5506]: pam_unix(cron:session): session closed for user root Jun 7 03:33:24 Isis sudo: pam_unix(sudo:session): session closed for user root Jun 7 03:33:43 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 03:33:43 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 03:33:43 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 03:33:43 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 03:33:43 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 03:33:43 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 03:33:43 Isis sudo: mimi : 3 incorrect password attempts ; TTY=pts/1 ; PWD=/home/mimi ; USER=root ; COMMAND=/usr/bin/unetbootin showall=yes 'rootcheck=no' Jun 7 03:33:43 Isis sudo: unable to execute /usr/sbin/sendmail: No such file or directory Jun 7 04:17:01 Isis CRON[6119]: pam_unix(cron:session): session opened for user root by (uid=0) Jun 7 04:17:01 Isis CRON[6119]: pam_unix(cron:session): session closed for user root Jun 7 04:18:35 Isis polkitd(authority=local): Operator of unix-session:/org/freedesktop/ConsoleKit/Session1 successfully authenticated as unix-user:mimi to gain TEMPORARY authorization for action org.debian.apt.install-or-remove-packages for system-bus-name::1.79 [/usr/bin/python /usr/bin/landscape-client-ui-install] (owned by unix-user:mimi) Jun 7 04:19:11 Isis groupadd[6702]: group added to /etc/group: name=landscape, GID=127 Jun 7 04:19:11 Isis groupadd[6702]: group added to /etc/gshadow: name=landscape Jun 7 04:19:11 Isis groupadd[6702]: new group: name=landscape, GID=127 Jun 7 04:19:11 Isis useradd[6706]: new user: name=landscape, UID=115, GID=127, home=/var/lib/landscape, shell=/bin/false Jun 7 04:19:12 Isis usermod[6711]: change user 'landscape' password Jun 7 04:19:12 Isis chage[6716]: changed password expiry for landscape Jun 7 04:19:37 Isis polkitd(authority=local): Operator of unix-session:/org/freedesktop/ConsoleKit/Session1 FAILED to authenticate to gain authorization for action com.canonical.LandscapeClientSettings.configure for unix-process:6146:1543697 [/usr/bin/python /usr/bin/landscape-client-settings-ui] (owned by unix-user:mimi) Jun 7 04:20:20 Isis polkitd(authority=local): Operator of unix-session:/org/freedesktop/ConsoleKit/Session1 FAILED to authenticate to gain authorization for action com.canonical.LandscapeClientSettings.configure for unix-process:6832:1555313 [/usr/bin/python /usr/bin/landscape-client-settings-ui] (owned by unix-user:mimi) Jun 7 04:21:04 Isis polkitd(authority=local): Operator of unix-session:/org/freedesktop/ConsoleKit/Session1 FAILED to authenticate to gain authorization for action com.ubuntu.languageselector.setsystemdefaultlanguage for unix-process:6827:1555123 [/usr/bin/python /usr/bin/gnome-language-selector] (owned by unix-user:mimi) Jun 7 04:21:08 Isis polkitd(authority=local): Operator of unix-session:/org/freedesktop/ConsoleKit/Session1 FAILED to authenticate to gain authorization for action com.ubuntu.languageselector.setsystemdefaultlanguage for unix-process:6827:1555123 [/usr/bin/python /usr/bin/gnome-language-selector] (owned by unix-user:mimi) Jun 7 04:21:44 Isis polkitd(authority=local): Operator of unix-session:/org/freedesktop/ConsoleKit/Session1 FAILED to authenticate to gain authorization for action org.debian.apt.install-or-remove-packages for system-bus-name::1.87 [/usr/bin/python /usr/bin/gnome-language-selector] (owned by unix-user:mimi) Jun 7 04:22:27 Isis polkitd(authority=local): Operator of unix-session:/org/freedesktop/ConsoleKit/Session1 successfully authenticated as unix-user:mimi to gain TEMPORARY authorization for action com.canonical.LandscapeClientSettings.configure for unix-process:7830:1567424 [/usr/bin/python /usr/bin/landscape-client-settings-ui] (owned by unix-user:mimi) Jun 7 04:25:50 Isis polkitd(authority=local): Operator of unix-session:/org/freedesktop/ConsoleKit/Session1 FAILED to authenticate to gain authorization for action com.ubuntu.languageselector.setsystemdefaultlanguage for unix-process:7876:1584865 [/usr/bin/python /usr/bin/gnome-language-selector] (owned by unix-user:mimi) Jun 7 04:25:52 Isis polkitd(authority=local): Operator of unix-session:/org/freedesktop/ConsoleKit/Session1 FAILED to authenticate to gain authorization for action com.ubuntu.languageselector.setsystemdefaultlanguage for unix-process:7876:1584865 [/usr/bin/python /usr/bin/gnome-language-selector] (owned by unix-user:mimi) Jun 7 05:11:57 Isis polkitd(authority=local): Operator of unix-session:/org/freedesktop/ConsoleKit/Session1 successfully authenticated as unix-user:mimi to gain TEMPORARY authorization for action org.debian.apt.install-or-remove-packages for system-bus-name::1.95 [/usr/bin/python /usr/bin/gnome-language-selector] (owned by unix-user:mimi) Jun 7 05:17:02 Isis CRON[8708]: pam_unix(cron:session): session opened for user root by (uid=0) Jun 7 05:17:02 Isis CRON[8708]: pam_unix(cron:session): session closed for user root Jun 7 05:28:03 Isis lightdm: pam_unix(lightdm-autologin:session): session opened for user mimi by (uid=0) Jun 7 05:28:03 Isis lightdm: pam_ck_connector(lightdm-autologin:session): nox11 mode, ignoring PAM_TTY :0 Jun 7 05:28:17 Isis polkitd(authority=local): Registered Authentication Agent for unix-session:/org/freedesktop/ConsoleKit/Session1 (system bus name :1.32 [/usr/lib/policykit-1-gnome/polkit-gnome-authentication-agent-1], object path /org/gnome/PolicyKit1/AuthenticationAgent, locale en_US.UTF-8) Jun 7 05:28:32 Isis dbus[660]: [system] Rejected send message, 2 matched rules; type="method_call", sender=":1.44" (uid=1000 pid=1736 comm="/usr/lib/indicator-datetime/indicator-datetime-ser") interface="org.freedesktop.DBus.Properties" member="GetAll" error name="(unset)" requested_reply="0" destination=":1.17" (uid=0 pid=1333 comm="/usr/sbin/console-kit-daemon --no-daemon ") Jun 7 06:17:01 Isis CRON[2391]: pam_unix(cron:session): session opened for user root by (uid=0) Jun 7 06:17:02 Isis CRON[2391]: pam_unix(cron:session): session closed for user root Jun 7 06:25:02 Isis CRON[2492]: pam_unix(cron:session): session opened for user root by (uid=0) Jun 7 06:25:02 Isis CRON[2492]: pam_unix(cron:session): session closed for user root Jun 7 07:17:01 Isis CRON[3174]: pam_unix(cron:session): session opened for user root by (uid=0) Jun 7 07:17:01 Isis CRON[3174]: pam_unix(cron:session): session closed for user root Jun 7 07:30:01 Isis CRON[3397]: pam_unix(cron:session): session opened for user root by (uid=0) Jun 7 07:30:01 Isis CRON[3397]: pam_unix(cron:session): session closed for user root Jun 7 08:09:01 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 08:09:01 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 08:09:01 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 08:09:01 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 08:09:01 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 08:09:01 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 08:09:01 Isis sudo: mimi : 3 incorrect password attempts ; TTY=unknown ; PWD=/home/mimi ; USER=root ; COMMAND=/usr/share/checkbox/backend --path=/usr/share/checkbox/scripts:/usr/lib/lightdm/lightdm:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games /tmp/checkboxQbuE6V/input /tmp/checkboxQbuE6V/output Jun 7 08:09:01 Isis sudo: unable to execute /usr/sbin/sendmail: No such file or directory Jun 7 08:09:59 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 08:09:59 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 08:09:59 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 08:09:59 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 08:09:59 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 08:09:59 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 08:09:59 Isis sudo: mimi : 3 incorrect password attempts ; TTY=unknown ; PWD=/home/mimi ; USER=root ; COMMAND=/usr/share/checkbox/backend --path=/usr/share/checkbox/scripts:/usr/lib/lightdm/lightdm:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games /tmp/checkboxQbuE6V/input /tmp/checkboxQbuE6V/output Jun 7 08:09:59 Isis sudo: unable to execute /usr/sbin/sendmail: No such file or directory Jun 7 08:10:55 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 08:10:55 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 08:10:55 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 08:10:55 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 08:10:55 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 08:10:55 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 08:10:55 Isis sudo: mimi : 3 incorrect password attempts ; TTY=unknown ; PWD=/home/mimi ; USER=root ; COMMAND=/usr/share/checkbox/backend --path=/usr/share/checkbox/scripts:/usr/lib/lightdm/lightdm:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games /tmp/checkboxQbuE6V/input /tmp/checkboxQbuE6V/output Jun 7 08:10:55 Isis sudo: unable to execute /usr/sbin/sendmail: No such file or directory Jun 7 08:17:01 Isis CRON[4215]: pam_unix(cron:session): session opened for user root by (uid=0) Jun 7 08:17:01 Isis CRON[4215]: pam_unix(cron:session): session closed for user root Jun 7 09:17:02 Isis CRON[4766]: pam_unix(cron:session): session opened for user root by (uid=0) Jun 7 09:17:02 Isis CRON[4766]: pam_unix(cron:session): session closed for user root Jun 7 10:17:02 Isis CRON[5046]: pam_unix(cron:session): session opened for user root by (uid=0) Jun 7 10:17:02 Isis CRON[5046]: pam_unix(cron:session): session closed for user root Jun 7 11:17:02 Isis CRON[5325]: pam_unix(cron:session): session opened for user root by (uid=0) Jun 7 11:17:02 Isis CRON[5325]: pam_unix(cron:session): session closed for user root Jun 7 12:17:01 Isis CRON[5617]: pam_unix(cron:session): session opened for user root by (uid=0) Jun 7 12:17:01 Isis CRON[5617]: pam_unix(cron:session): session closed for user root Jun 7 13:07:51 Isis gnome-screensaver-dialog: pam_unix(gnome-screensaver:auth): authentication failure; logname= uid=1000 euid=1000 tty=:0.0 ruser= rhost= user=mimi Jun 7 13:07:51 Isis gnome-screensaver-dialog: pam_winbind(gnome-screensaver:auth): getting password (0x00000388) Jun 7 13:07:51 Isis gnome-screensaver-dialog: pam_winbind(gnome-screensaver:auth): pam_get_item returned a password Jun 7 13:07:51 Isis gnome-screensaver-dialog: pam_winbind(gnome-screensaver:auth): request wbcLogonUser failed: WBC_ERR_AUTH_ERROR, PAM error: PAM_USER_UNKNOWN (10), NTSTATUS: NT_STATUS_NO_SUCH_USER, Error message was: No such user Jun 7 13:08:03 Isis gnome-screensaver-dialog: pam_unix(gnome-screensaver:auth): conversation failed Jun 7 13:08:03 Isis gnome-screensaver-dialog: pam_unix(gnome-screensaver:auth): auth could not identify password for [mimi] Jun 7 13:08:03 Isis gnome-screensaver-dialog: pam_winbind(gnome-screensaver:auth): getting password (0x00000388) Jun 7 13:08:08 Isis lightdm: pam_unix(lightdm:session): session opened for user lightdm by (uid=0) Jun 7 13:08:08 Isis lightdm: pam_ck_connector(lightdm:session): nox11 mode, ignoring PAM_TTY :1 Jun 7 13:08:13 Isis lightdm: pam_succeed_if(lightdm:auth): requirement "user ingroup nopasswdlogin" not met by user "mimi" Jun 7 13:08:16 Isis dbus[660]: [system] Rejected send message, 2 matched rules; type="method_call", sender=":1.91" (uid=104 pid=5961 comm="/usr/lib/indicator-datetime/indicator-datetime-ser") interface="org.freedesktop.DBus.Properties" member="GetAll" error name="(unset)" requested_reply="0" destination=":1.17" (uid=0 pid=1333 comm="/usr/sbin/console-kit-daemon --no-daemon ") Jun 7 13:08:18 Isis dbus[660]: [system] Rejected send message, 2 matched rules; type="method_call", sender=":1.98" (uid=104 pid=5999 comm="/usr/lib/indicator-datetime/indicator-datetime-ser") interface="org.freedesktop.DBus.Properties" member="GetAll" error name="(unset)" requested_reply="0" destination=":1.17" (uid=0 pid=1333 comm="/usr/sbin/console-kit-daemon --no-daemon ") Jun 7 13:10:15 Isis lightdm: pam_unix(lightdm:session): session closed for user lightdm Jun 7 13:17:02 Isis CRON[6181]: pam_unix(cron:session): session opened for user root by (uid=0) Jun 7 13:17:02 Isis CRON[6181]: pam_unix(cron:session): session closed for user root Jun 7 13:55:14 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 13:55:14 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 13:55:14 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 13:55:14 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 13:55:14 Isis sudo: pam_unix(sudo:auth): conversation failed Jun 7 13:55:14 Isis sudo: pam_unix(sudo:auth): auth could not identify password for [mimi] Jun 7 13:55:14 Isis sudo: mimi : 3 incorrect password attempts ; TTY=unknown ; PWD=/home/mimi ; USER=root ; COMMAND=/usr/bin/unetbootin 'rootcheck=no' Jun 7 13:55:14 Isis sudo: unable to execute /usr/sbin/sendmail: No such file or directory Jun 7 14:02:33 Isis polkitd(authority=local): Operator of unix-session:/org/freedesktop/ConsoleKit/Session1 FAILED to authenticate to gain authorization for action com.canonical.LandscapeClientSettings.configure for unix-process:6736:3087856 [/usr/bin/python /usr/bin/landscape-client-settings-ui] (owned by unix-user:mimi) Jun 7 14:02:51 Isis polkitd(authority=local): Operator of unix-session:/org/freedesktop/ConsoleKit/Session1 FAILED to authenticate to gain authorization for action com.canonical.LandscapeClientSettings.configure for unix-process:6752:3089992 [/usr/bin/python /usr/bin/landscape-client-settings-ui] (owned by unix-user:mimi) Jun 7 14:03:14 Isis polkitd(authority=local): Operator of unix-session:/org/freedesktop/ConsoleKit/Session1 successfully authenticated as unix-user:mimi to gain TEMPORARY authorization for action com.canonical.LandscapeClientSettings.configure for unix-process:6763:3092515 [/usr/bin/python /usr/bin/landscape-client-settings-ui] (owned by unix-user:mimi) Jun 7 14:17:01 Isis CRON[6933]: pam_unix(cron:session): session opened for user root by (uid=0) Jun 7 14:17:01 Isis CRON[6933]: pam_unix(cron:session): session closed for user root Jun 7 15:17:02 Isis CRON[7611]: pam_unix(cron:session): session opened for user root by (uid=0) Jun 7 15:17:02 Isis CRON[7611]: pam_unix(cron:session): session closed for user root

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  • Project Euler #3

    - by Alex
    Question: The prime factors of 13195 are 5, 7, 13 and 29. What is the largest prime factor of the number 600851475143? I found this one pretty easy, but running the file took an extremely long time, it's been going on for a while and the highest number I've got to is 716151937. Here is my code, am I just going to have a wait or is there an error in my code? //User made class public class Three { public static boolean checkPrime(long p) { long i; boolean prime = false; for(i = 2;i<p/2;i++) { if(p%i==0) { prime = true; break; } } return prime; } } //Note: This is a separate file public class ThreeMain { public static void main(String[] args) { long comp = 600851475143L; boolean prime; long i; for(i=2;i<comp/2;i++) { if(comp%i==0) { prime = Three.checkPrime(i); if(prime==true) { System.out.println(i); } } } } }

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  • Should my dropdown of recently used items show items I no longer have access to

    - by Dan Hibbert
    We are implementing a client for our document management system. Part of this is the checkin screen where one of the fields a user chooses is the folder where the document should be checked into. In our original system, this was represented with a combobox where a user could hand type a folder path or select a path from a list of 5 folders they'd recently used for checking. It is possible that between the time they used the folder and the time they are doing the new checkin the user will no longer have access to the folder. At present, we still show the folder as an option and then, if the user chooses that folder, display an error message when the user submits the check in. We are thinking of removing these recently used folders the user doesn't have access to (we'll make a check when the form is instantiated) because why show an option if we know it will cause a failure (and another dialog message the user has to OK). However, an opposite opinion is that if we remove those folders, the users will think the system has "forgotten" their recent choices and will lose trust in what they are using. I'd like to get some opinions on the better user experience for this problem.

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  • Name user object and user table correctly

    - by Marc
    It's maybe simple but I think about this every time I build a new application. How do you name the class for the current user of the application and for the orm class of the user table? Usually I have something like CurrentUser: Logged-in user, stored in session, info for last activity etc User: ORM Class (C# EF CodeFirst, but it doesn't matter) And yes, they could have the same name in different namespaces, but I don't really like that.

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  • Display user name in reference to user id in django template

    - by Ed
    I expect this is an easy question. For some reason, I don't have a solution yet. I have an object set from django reversion: version_list. Each object in the set has a user id attached to it. How do I grab the user names that correspond to the user ID's? To try to be clearer, if each object in version_list has a name, date, and user id, how can I join the version_list set with the user table to figure out what user id goes with which name? This is done in the view, or the template?

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  • Project Euler #18 - how to brute force all possible paths in tree-like structure using Python?

    - by euler user
    Am trying to learn Python the Atlantic way and am stuck on Project Euler #18. All of the stuff I can find on the web (and there's a LOT more googling that happened beyond that) is some variation on 'well you COULD brute force it, but here's a more elegant solution'... I get it, I totally do. There are really neat solutions out there, and I look forward to the day where the phrase 'acyclic graph' conjures up something more than a hazy, 1 megapixel resolution in my head. But I need to walk before I run here, see the state, and toy around with the brute force answer. So, question: how do I generate (enumerate?) all valid paths for the triangle in Project Euler #18 and store them in an appropriate python data structure? (A list of lists is my initial inclination?). I don't want the answer - I want to know how to brute force all the paths and store them into a data structure. Here's what I've got. I'm definitely looping over the data set wrong. The desired behavior would be to go 'depth first(?)' rather than just looping over each row ineffectually.. I read ch. 3 of Norvig's book but couldn't translate the psuedo-code. Tried reading over the AIMA python library for ch. 3 but it makes too many leaps. triangle = [ [75], [95, 64], [17, 47, 82], [18, 35, 87, 10], [20, 4, 82, 47, 65], [19, 1, 23, 75, 3, 34], [88, 2, 77, 73, 7, 63, 67], [99, 65, 4, 28, 6, 16, 70, 92], [41, 41, 26, 56, 83, 40, 80, 70, 33], [41, 48, 72, 33, 47, 32, 37, 16, 94, 29], [53, 71, 44, 65, 25, 43, 91, 52, 97, 51, 14], [70, 11, 33, 28, 77, 73, 17, 78, 39, 68, 17, 57], [91, 71, 52, 38, 17, 14, 91, 43, 58, 50, 27, 29, 48], [63, 66, 4, 68, 89, 53, 67, 30, 73, 16, 69, 87, 40, 31], [04, 62, 98, 27, 23, 9, 70, 98, 73, 93, 38, 53, 60, 4, 23], ] def expand_node(r, c): return [[r+1,c+0],[r+1,c+1]] all_paths = [] my_path = [] for i in xrange(0, len(triangle)): for j in xrange(0, len(triangle[i])): print 'row ', i, ' and col ', j, ' value is ', triangle[i][j] ??my_path = somehow chain these together??? if my_path not in all_paths all_paths.append(my_path) Answers that avoid external libraries (like itertools) preferred.

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  • Microsoft 2010 Product Tour

    - by dmccollough
    Randy Walker, Co-Founder of the Northwest Arkansas .Net User Group and Microsoft MVP has arranged for a couple of Microsoft experts, Sarika Calla Team Lead on the IDE Team and Kevin Halverson to give presentations on newly released Visual Studio 2010.   June 1 – Bentonville, Arkansas Wal-Mart .Net User Group June 1 – Rogers, Arkansas Northwest Arkansas SQL Server User Group (lunch meeting) June 1 – Springdale, Arkansas Tyson devLoop June 1 – Fayetteville, Arkansas Northwest Arkansas .Net User Group June 2 – Fort Smith, Arkansas Datatronics June 2 – Little Rock, Arkansas Little Rock .Net User Group June 3 – Fort Worth, Texas Fort Worth .Net User Group   Please contact Randy Walker with questions at [email protected].

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  • Gnome 2 style user account settings (how to edit user accounts in Unity)

    - by user104140
    Back in Gnome 2 there was a very useful user account editing gui tool whereby I could easily add or edit a user to a group. For example, I could give a standard user access to something that they hadn't installed or don't have default access too, such as Me-TV. How do I do this in Gnome 3 / Unity? I am not allowed to create the tag "edit user accounts" or similar and there isn't anything similar existing, strangely. I'm guessing there is a totally different way to edit user accounts or no one bothers - perhaps no one shares PCs anymore.

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  • Project Euler Question 14 (Collatz Problem)

    - by paradox
    The following iterative sequence is defined for the set of positive integers: n -n/2 (n is even) n -3n + 1 (n is odd) Using the rule above and starting with 13, we generate the following sequence: 13 40 20 10 5 16 8 4 2 1 It can be seen that this sequence (starting at 13 and finishing at 1) contains 10 terms. Although it has not been proved yet (Collatz Problem), it is thought that all starting numbers finish at 1. Which starting number, under one million, produces the longest chain? NOTE: Once the chain starts the terms are allowed to go above one million. I tried coding a solution to this in C using the bruteforce method. However, it seems that my program stalls when trying to calculate 113383. Please advise :) #include <stdio.h> #define LIMIT 1000000 int iteration(int value) { if(value%2==0) return (value/2); else return (3*value+1); } int count_iterations(int value) { int count=1; //printf("%d\n", value); while(value!=1) { value=iteration(value); //printf("%d\n", value); count++; } return count; } int main() { int iteration_count=0, max=0; int i,count; for (i=1; i<LIMIT; i++) { printf("Current iteration : %d\n", i); iteration_count=count_iterations(i); if (iteration_count>max) { max=iteration_count; count=i; } } //iteration_count=count_iterations(113383); printf("Count = %d\ni = %d\n",max,count); }

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  • Project Euler Problem #11

    - by SoulBeaver
    Source: http://projecteuler.net/index.php?section=problems&id=11 Quick overview: Take a 20x20 grid of numbers and compute the largest product of 4 pairs of numbers in either horizontal, vertical, or diagonal. My current approach is to divide the 20x20 grid up into single rows and single columns and go from there with a much more manageable grid. The code I'm using to divide the rows into rows is void fillRows ( string::const_iterator& fieldIter, list<int>& rowElements, vector<list<int>>& rows ) { int count(0); for( ; fieldIter < field.end(); ++fieldIter ) { if(isdigit(field[*fieldIter])) { rowElements.push_back(toInt(field[*fieldIter])); ++count; } if(count == 40) { rows.push_back(rowElements); count = 0; rowElements.clear(); } } } Short explanation: I have the field set as static const std::string field and I am filling a vector with lists of rows. Why a list? Because the queue doesn't have a clear function. Also practice using STL container lists and not ones I write myself. However, this thing isn't working. Oftentimes I see it omitting a character( function toInt parses the const char as int ) and I end up with 18 rows, two rows short of the 20x20 grid. The length of the rows seem good. Rows: 18 RowElements[0]: 40 (instead of pairs I saved each number individually. Will fix that later) What am I doing wrong?

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  • Project euler problem 45

    - by Peter
    Hi, I'm not yet a skilled programmer but I thought this was an interesting problem and I thought I'd give it a go. Triangle, pentagonal, and hexagonal numbers are generated by the following formulae: Triangle T_(n)=n(n+1)/2 1, 3, 6, 10, 15, ... Pentagonal P_(n)=n(3n-1)/2 1, 5, 12, 22, 35, ... Hexagonal H_(n)=n(2n-1) 1, 6, 15, 28, 45, ... It can be verified that T_(285) = P_(165) = H_(143) = 40755. Find the next triangle number that is also pentagonal and hexagonal. Is the task description. I know that Hexagonal numbers are a subset of triangle numbers which means that you only have to find a number where Hn=Pn. But I can't seem to get my code to work. I only know java language which is why I'm having trouble finding a solution on the net womewhere. Anyway hope someone can help. Here's my code public class NextNumber { public NextNumber() { next(); } public void next() { int n = 144; int i = 165; int p = i * (3 * i - 1) / 2; int h = n * (2 * n - 1); while(p!=h) { n++; h = n * (2 * n - 1); if (h == p) { System.out.println("the next triangular number is" + h); } else { while (h > p) { i++; p = i * (3 * i - 1) / 2; } if (h == p) { System.out.println("the next triangular number is" + h); break; } else if (p > h) { System.out.println("bummer"); } } } } } I realize it's probably a very slow and ineffecient code but that doesn't concern me much at this point I only care about finding the next number even if it would take my computer years :) . Peter

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  • Project Euler, Problem 10 java solution not working

    - by Dennis S
    Hi, I'm trying to find the sum of the prime numbers < 2'000'000. This is my solution in java but I can't seem get the correct answer. Please give some input on what could be wrong and general advice on the code is appreciated. Printing 'sum' gives: 1308111344, which is incorrect. /* The sum of the primes below 10 is 2 + 3 + 5 + 7 = 17. Find the sum of all the primes below two million. */ class Helper{ public void run(){ Integer sum = 0; for(int i = 2; i < 2000000; i++){ if(isPrime(i)) sum += i; } System.out.println(sum); } private boolean isPrime(int nr){ if(nr == 2) return true; else if(nr == 1) return false; if(nr % 2 == 0) return false; for(int i = 3; i < Math.sqrt(nr); i += 2){ if(nr % i == 0) return false; } return true; } } class Problem{ public static void main(String[] args){ Helper p = new Helper(); p.run(); } }

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  • Project euler problem 3 in haskell

    - by shk
    I'm new in Haskell and try to solve 3 problem from http://projecteuler.net/. The prime factors of 13195 are 5, 7, 13 and 29. What is the largest prime factor of the number 600851475143 ? My solution: import Data.List getD :: Int -> Int getD x = -- find deviders let deriveList = filter (\y -> (x `mod` y) == 0) [1 .. x] filteredList = filter isSimpleNumber deriveList in maximum filteredList -- Check is nmber simple isSimpleNumber :: Int -> Bool isSimpleNumber x = let deriveList = map (\y -> (x `mod` y)) [1 .. x] filterLength = length ( filter (\z -> z == 0) deriveList) in case filterLength of 2 -> True _ -> False I try to run for example: getD 13195 > 29 But when i try: getD 600851475143 I get error Exception: Prelude.maximum: empty list Why? Thank you @Barry Brown, I think i must use: getD :: Integer -> Integer But i get error: Couldn't match expected type `Int' with actual type `Integer' Expected type: [Int] Actual type: [Integer] In the second argument of `filter', namely `deriveList' In the expression: filter isSimpleNumber deriveList Thank you.

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  • Project Euler #9 (Pythagorean triplets) in Clojure

    - by dbyrne
    My answer to this problem feels too much like these solutions in C. Does anyone have any advice to make this more lispy? (use 'clojure.test) (:import 'java.lang.Math) (with-test (defn find-triplet-product ([target] (find-triplet-product 1 1 target)) ([a b target] (let [c (Math/sqrt (+ (* a a) (* b b)))] (let [sum (+ a b c)] (cond (> a target) "ERROR" (= sum target) (reduce * (list a b (int c))) (> sum target) (recur (inc a) 1 target) (< sum target) (recur a (inc b) target)))))) (is (= (find-triplet-product 1000) 31875000)))

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  • Project Euler 9 Understanding

    - by DMan
    This question states: A Pythagorean triplet is a set of three natural numbers, a b c, for which, a2 + b2 = c2 For example, 32 + 42 = 9 + 16 = 25 = 52. There exists exactly one Pythagorean triplet for which a + b + c = 1000. Find the product abc. I'm not sure what's it trying to ask you. Are we trying to find a^2+b^2=c^2 and then plug those numbers into a+b+c=1000?

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  • Project Euler, Problem 10 java solution now working

    - by Dennis S
    Hi, I'm trying to find the sum of the prime numbers < 2'000'000. This is my solution in java but I can't seem get the correct answer. Please give some input on what could be wrong and general advice on the code is appreciated. Printing 'sum' gives: 1308111344, which is incorrect. /* The sum of the primes below 10 is 2 + 3 + 5 + 7 = 17. Find the sum of all the primes below two million. */ class Helper{ public void run(){ Integer sum = 0; for(int i = 2; i < 2000000; i++){ if(isPrime(i)) sum += i; } System.out.println(sum); } private boolean isPrime(int nr){ if(nr == 2) return true; else if(nr == 1) return false; if(nr % 2 == 0) return false; for(int i = 3; i < Math.sqrt(nr); i += 2){ if(nr % i == 0) return false; } return true; } } class Problem{ public static void main(String[] args){ Helper p = new Helper(); p.run(); } }

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