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  • Variable not accessible within an if statment

    - by Chris
    I have a variable which holds a score for a game. My variable is accessible and correct outside of an if statement but not inside as shown below score is declared at the top of the main.cpp and calculated in the display function which also contains the code below cout << score << endl; //works if(!justFinished){ cout << score << endl; // doesn't work prints a large negative number endTime = time(NULL); ifstream highscoreFile; highscoreFile.open("highscores.txt"); if(highscoreFile.good()){ highscoreFile.close(); }else{ std::ofstream outfile ("highscores.txt"); cout << score << endl; outfile << score << std::endl; outfile.close(); } justFinished = true; } cout << score << endl;//works

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  • iPhone SDK Programming - Working with a variable across 2 views

    - by SD
    I have what I hope is a fairly simple question about using the value from a variable across 2 views. I’m new to the iPhone SDK platform and the Model/View/Controller methodology. I’ve got background in VB.Net, some Php, but mostly SQL, so this is new ground for me. I’m building an app that has 3 views. For simplicity’s sake, I’ll call them View1, View2, View3. On View1 I have an NSString variable that I’ve declared in View1.h, and synthesized in View1.m. I’ll call it String1. View1.m uses a UITextField to ask the user for their name and then sets the value of String1 to that name (i.e. "Bill"). I would now like to use the value of String1 in View2. I'm not doing anything other than displaying the value ("Bill"), in a UILabel object in View2. Can someone tell me what the easiest way to accomplish that is? Many thanks in advance….

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  • Variable not accessible within and if statment

    - by Chris
    I have a variable which holds a score for a game. My variable is accessible and correct outside of an if statement but not inside as shown below cout << score << endl; //works if(!justFinished){ cout << score << endl; // doesn't work prints a large negative number endTime = time(NULL); ifstream highscoreFile; highscoreFile.open("highscores.txt"); if(highscoreFile.good()){ highscoreFile.close(); }else{ std::ofstream outfile ("highscores.txt"); cout << score << endl; outfile << score << std::endl; outfile.close(); } justFinished = true; } cout << score << endl;//works

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  • Excel formula for variable fields

    - by awais
    I am looking for a simple formula to do the calculation on two fields that are variable, for e.g., c1 has 100 and c3 has 150 and I want to calculate an increase/decrease percentage, but the trick is the cell values change every month. How do I put the formula to cater for such variation. Appreciate your help. Regards

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  • Variable scoping and the jQuery.getJSON() method

    - by jerome
    The jQuery.getJSON() method seems to ignore the normal rules of scoping within JavaScript. Given code such as this... someObject = { someMethod: function(){ var foo; $.getJSON('http://www.somewhere.com/some_resource', function(data){ foo = data.bar; }); alert(foo); // undefined } } someObject.someMethod(); Is there a best practice for accessing the value of the variable outside of the getJSON scope?

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  • Problems with umlauts in python appdata environvent variable

    - by Heike
    Hi, I can't find a correct way to get the environment variable for the appdata path in python. The problem is that my user name includes special characters (the german ae and ue). I made a workaround wit PyQt for Vista and Windows 7 but it doesn't work for XP Systems. Does anybody know the correct encoding of these environment variables or another solution for this problem? Greetz

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  • anonymous function variable scope [js, ajax]

    - by arthurprs
    $(".delete").click( function() { var thesender = this; $(thesender).text("Del..."); $.getJSON("ajax.php", {}, function(data) { if (data["result"]) $(thesender).remove(); // variable defined outside else alert('Error!'); } ); return false; } ); This can cause problems if user clicks on another ".delete" before the ajax callback is called?

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  • Sql - tablename as variable

    - by BhejaFry
    Hi folks, i am trying to execute this query: declare @tablename varchar(50) set @tablename = 'test' select * from @tablename This produces the following error: Msg 1087, Level 16, State 1, Line 5 Must declare the table variable "@tablename". What's the right way to have table name populated dynamically? TIA

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  • Changing a Variable Out of Scope?

    - by Matrym
    Is there any way to change a variable while out of scope? I know in general, you cannot, but I'm wondering if there are any tricks or overrides. For example, is there any way to make the following work: function blah(){ var a = 1 } a = 2; alert(blah());

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  • PHP echo text if variable is blank

    - by user342391
    I am trying to echo €00.00 if my variable $amount equals zero I have done something wrong can you help?? Code while ($row9 = mysql_fetch_array($result9)) { $amount = $row9['amount']; } //$amount = $amount / 60; //$amount = round($amount, 2); if $amount == 0 echo "<b>Balance: &#8364;00.00</b>"; else echo "<b>Balance: $$amount</b>";

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  • Quarter as a Count variable in SAS.

    - by John
    Hye Guys, I'm busy working on a time series and am trying to find the commands that allow me to insert a quarter count variable. To keep things simple, the third quarter of 1995 (date my observations start) should be quarter -2, the fourth quarter of 1995 should be -1 etc etc uptill 2006 (should be somewhere around 45 by then). My dates are in date9 format, such as 20JUN04 etc.. Anyone who can help me with the commands I need t o let this work in SAS? Thanks

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  • Giving my function access to outside variable

    - by brett
    I have an array outside: $myArr = array(); I would like to give my function access to the array outside it so it can add values to it function someFuntion(){ $myVal = //some processing here to determine value of $myVal $myArr[] = $myVal; } How do I give the function the right scoping to the variable?

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  • jQuery global variable problem

    - by Emanuel
    var id = $(this).children().html(); // id is 5 $.ajax({ url: 'ajax.php?id=' + id, success: function(data) { id = data; // id is 1 } }); if(id == 1){ // id is again 5 ... } Why in the following example I can't reinitialize the id variable? What is wrong? Thanks.

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  • getJSON and variable scope in javascript

    - by nillls
    Hi! In order to make function calls to our back-end php code we've implemented something called an ActionProxy like this: function ActionProxy(action, input, callback){ $.post("ActionProxy.php?method="+action, { data: input}, function(data, textStatus, XMLHttpRequest){ //return data.ResponseWhatever } }); The problem we're having is that using data outside the ActionProxy is impossible due to variable scope limitations (we assume), setting var res = data.ResponseWhatever or return data.ResponseWhatever is pretty futile. How would one handle these responses most appropriately so that functions calling the actionproxy can access the response values?

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