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  • c++ Mixing printf, cout with wprintf, wcout

    - by Bo Jensen
    I know you should not mix printing with printf,cout and wprintf,wcout, but have a hard time finding a good answer why and if it is possible to get round it. The problem is I use a external library that prints with printf and my own uses wcout. If I do a simple example it works fine, but from my full application it simply does not print the printf statements. If this is really a limitation, then there would be many libraries out there which can not work together with wide printing applications. Any insight on this is more than welcome.

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  • warning: format ‘%s’ expects type ‘char *’, but argument 2 has type ‘int’

    - by pyz
    code: #include <stdio.h> #include <stdlib.h> #include <netdb.h> #include <sys/socket.h> int main(int argc, char **argv) { char *ptr, **pptr; struct hostent *hptr; char str[32]; //ptr = argv[1]; ptr = "www.google.com"; if ((hptr = gethostbyname(ptr)) == NULL) { printf("gethostbyname error for host:%s\n", ptr); } printf("official hostname:%s\n", hptr->h_name); for (pptr = hptr->h_aliases; *pptr != NULL; pptr++) printf(" alias:%s\n", *pptr); switch (hptr->h_addrtype) { case AF_INET: case AF_INET6: pptr = hptr->h_addr_list; for (; *pptr != NULL; pptr++) printf(" address:%s\n", inet_ntop(hptr->h_addrtype, *pptr, str, sizeof(str))); break; default: printf("unknown address type\n"); break; } return 0; } compiler output below: zhumatoMacBook:CProjects zhu$ gcc gethostbynamedemo.c gethostbynamedemo.c: In function ‘main’: gethostbynamedemo.c:31: warning: format ‘%s’ expects type ‘char *’, but argument 2 has type ‘int’

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  • problem with printf() function

    - by Syom
    i have the variable $a = 5; i want to show it in binary form, with length, equal 8, with writing * at white spaces, just like this, like this * * * * *101 here the script $number = 5; printf("%*8b", $number); it doesn't work with *, but if "0"-s it works printf("%08b", $number); //returns 00000101 why it doesn't work with *?

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  • C puzzle: Output of printf should be '5' always

    - by pragadheesh
    Hi, I found this puzzle in a C aptitude paper. void change() { //write something in this function so that output of printf in main function //should always give 5.you can't change the main function } int main() { int i = 5; change(); i = 10; printf("%d", i); return 0; } Any solutions.?

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  • Space as grouping separator in printf

    - by blekione
    I know how to use comma in printf as grouping separator to print value in format like 1,000,000.00 to print it that way I'm using command System.out.printf ("%,.2f", value); but how to use space as grouping separator to format value like 1 000 000.00 I tried to find solution but solutions with using DecimalFormat look at now to complicate for me (beginner level). Is there as easy way as in example with comma to do it?

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  • scanf a byte then print it out?

    - by Sarah
    I've searched around to see if I can find this answer but I can't seem to (please let me know if I'm wrong). I am trying to use scanf to read in a byte, an unsigned int and a char in one .c file and I am trying to access this byte in a different .c file and print it out. (I have already checked to make sure I have included all the appropriate parameters everywhere) But I keep getting errors. The warnings are: database.c: In function ‘addCitizen’: database.c:23:2: warning: format ‘%hhu’ expects argument of type ‘int’, but argument 2 has type ‘byte *’ [-Wformat] database.c:24:2: warning: format ‘%u’ expects argument of type ‘unsigned int’, but argument 2 has type ‘int *’ [-Wformat] database.c:25:2: warning: format ‘%c’ expects argument of type ‘int’, but argument 2 has type ‘char *’ [-Wformat] where I'm scanf'ing: // Request loop while (count-- != 0) { while (1){ // Get values from the user int error = scanf ("%79s %hhu %u %c", tname, &tdist, &tyear, &tgender); addCitizen(db, tname, &tdist, &tyear, &tgender); where I'm printing: void addCitizen(Database *db, char *tname, byte *tdist, int *tyear, char *tgender){ //needs to find the right place in memory to put this stuff and then put it there printf("\nName is: %79s\n", tname); printf("District is: %hhu\n", tdist); printf("Year of birth is: %u\n", tyear); printf("Gender is:%c\n", tgender); I'm not sure where I'm going wrong?

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  • In C what is the difference between null and a new line character? Guys help please [migrated]

    - by Siddhartha Gurjala
    Whats the conceptual difference and similarity between NULL and a newline character i.e between '\0' and '\n' Explain their relevance for both integer and character data type variables and arrays? For reference here is an example snippets of a program to read and write a 2d char array PROGRAM CODE 1: int main() { char sort(),stuname(),swap(),(*p)(),(*q)(); int n; p=stuname; q=swap; printf("Let the number of students in the class be \n"); scanf("%d",&n); fflush(stdin); sort(p,q,n); return 0; } char sort(p1,q1,n1) char (*p1)(),(*q1)(); int n1; { (*p1)(n1); (*q1)(); } char stuname(int nos) // number of students { char name[nos][256]; int i,j; printf("Reading names of %d students started--->\n\n",nos); name[0][0]='k'; //initialising as non NULL charecter for(i=0;i<nos;i++) // nos=number of students { printf("Give name of student %d\n",i); for(j=0;j<256;j++) { scanf("%c",&name[i][j]); if(name[i][j]=='\n') { name[i][j]='\0'; j=257; } } } printf("\n\nWriting student names:\n\n"); for(i=0;i<nos;i++) { for(j=0;j<256&&name[i][j]!='\0';j++) { printf("%c",name[i][j]); } printf("\n"); } } char swap() { printf("Will swap shortly after getting clarity on scanf and %c"); } The above code is working good where as the same logic given with slight diff is not giving appropriate output. Here's the code PROGRAM CODE 2: #include<stdio.h> int main() { char sort(),stuname(),swap(),(*p)(),(*q)(); int n; p=stuname; q=swap; printf("Let the number of students in the class be \n"); scanf("%d",&n); fflush(stdin); sort(p,q,n); return 0; } char sort(p1,q1,n1) char (*p1)(),(*q1)(); int n1; { (*p1)(n1); (*q1)(); } char stuname(int nos) // number of students { char name[nos][256]; int i,j; printf("Reading names of %d students started--->\n\n",nos); name[0][0]='k'; //initialising as non NULL charecter for(i=0;i<nos;i++) // nos=number of students { printf("Give name of student %d\n",i); ***for(j=0;j<256&&name[i][j]!='\0';j++)*** { scanf("%c",&name[i][j]); /*if(name[i][j]=='\n') { name[i][j]='\0'; j=257; }*/ } } printf("\n\nWriting student names:\n\n"); for(i=0;i<nos;i++) { for(j=0;j<256&&name[i][j]!='\0';j++) { printf("%c",name[i][j]); } printf("\n"); } } char swap() { printf("Will swap shortly after getting clarity on scanf and %c"); } Here one more instance of same program not giving proper output given below PROGRAM CODE 3: #include<stdio.h> int main() { char sort(),stuname(),swap(),(*p)(),(*q)(); int n; p=stuname; q=swap; printf("Let the number of students in the class be \n"); scanf("%d",&n); fflush(stdin); sort(p,q,n); return 0; } char sort(p1,q1,n1) char (*p1)(),(*q1)(); int n1; { (*p1)(n1); (*q1)(); } char stuname(int nos) // number of students { char name[nos][256]; int i,j; printf("Reading names of %d students started--->\n\n",nos); name[0][0]='k'; //initialising as non NULL charecter for(i=0;i<nos;i++) // nos=number of students { printf("Give name of student %d\n",i); ***for(j=0;j<256&&name[i][j]!='\n';j++)*** { scanf("%c",&name[i][j]); /*if(name[i][j]=='\n') { name[i][j]='\0'; j=257; }*/ } name[i][i]='\0'; } printf("\n\nWriting student names:\n\n"); for(i=0;i<nos;i++) { for(j=0;j<256&&name[i][j]!='\0';j++) { printf("%c",name[i][j]); } printf("\n"); } } char swap() { printf("Will swap shortly after getting clarity on scanf and %c"); } Why the program code 2 and program code 3 are not working as expected as that of the code 1?

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  • Convert ieee 754 float to hex with c - printf

    - by Michael
    Ideally the following code would take a float in IEEE 754 representation and convert it into hexadecimal void convert() //gets the float input from user and turns it into hexadecimal { float f; printf("Enter float: "); scanf("%f", &f); printf("hex is %x", f); } I'm not too sure what's going wrong. It's converting the number into a hexadecimal number, but a very wrong one. 123.1443 gives 40000000 43.3 gives 60000000 8 gives 0 so it's doing something, I'm just not too sure what. Help would be appreciated

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  • [C] this code, its work fine and return what i want, but its hangs before print it ??

    - by Rami Jarrar
    I make this program :: #include<stdio.h> char *raw_input(char *msg); main() { char *s; *s = *raw_input("Message Here Is: "); printf("Return Done.."); printf(s); } char *raw_input(char *msg){ char *d; printf("%s", msg); scanf("%s",&d); return d; } What this do is, it print my message and scan for input from the user, then print it,, but whats the problem in print the input from the user ??? Update:: I need the raw_input func. call be like this without any extra *s = *raw_input("Message Here"); I dont want to use this :: raw_input("Message Here Is: ", d); .... Just want to return the string that the user will enter .

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  • [C] this code, its work fine and return what i want, but its hang before print it ??

    - by Rami Jarrar
    I make this program :: #include<stdio.h> char *raw_input(char *msg); main() { char *s; *s = *raw_input("Message Here Is: "); printf("Return Done.."); printf(s); } char *raw_input(char *msg){ char *d; printf("%s", msg); scanf("%s",&d); return d; } What this do is, it print my message and scan for input from the user, then print it,, but whats the problem in print the input from the user ???

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  • Reading a variable messes it up?!?!

    - by EpsilonVector
    We have the following line of code: printf("%d\n", toc->runlist.next); printf("%d\n", toc->runlist.next); These are the definitions: typedef struct thread_overview_control{ int id[NR_UTHREADS]; list_t runlist; int active_counter; int main_thread; int need_resched; } thread_overview_control; thread_overview_control* toc; What I'm trying to do is implement user threads. For some reason the output of the above code at the point where our test run crushes is: 12345678 //some address 0 //NOW IT'S NULL?!?!?! How can this happen?? All we do is read a variable. And the strange thing is, without printf's there are no crashes. What's going on?

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  • use printf("text %d", number) type format to assign value to variable

    - by rksprst
    I would like to use the syntax that printf uses, using the %d, %s and adding values after to assign a value to a char[]. Is this possible? e.g. Given an output of: printf("now: %d-%d-%d %d:%d:%d\n", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min, tm.tm_sec); I'd like to assign that to char[] output; How can this be done? I tried: sprintf(output, "now: %d-%d-%d %d:%d:%d\n", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min, tm.tm_sec); but that didn't seem to work. Is sprintf used differently... or is that not what I should be using? Thanks!

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  • How to ANSI-C cast from unisigned int * to char *?

    - by user314290
    I want these two print functions to do the same thing: unsigned int Arraye[] = {0xffff,0xefef,65,66,67,68,69,0}; char Arrage[] = {0xffff,0xefef,65,66,67,68,69,0}; printf("%s", (char*)(2+ Arraye)); printf("%s", (char*)(2+ Arrage)); where Array is an unsigned int. Normally, I would change the type but, the problem is that most of the array is numbers, although the particular section should be printed as ASCII.

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  • How do I use multiple precisions in prinft()?

    - by Tommy
    Looking at the information under the heading "Precision can be omitted or be any of:". The example: printf("%.*s", 3, "abcdef"); works, outputting:abc (truncating the rest of the string.) Now, I would like to have a string with multiple parameters formatted (truncated): printf("%.*s", "%.*s", 3, 3, "abcdef", "xyz123"); but the program crashes. What is the correct syntax? Thank You.

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  • printf and Console.WriteLine - problems with Console.SetOut?

    - by Matt Jacobsen
    i have a bunch of Console.WriteLines in my code that I can observe at runtime. I communicate with a native library that I also wrote. I'd like to stick some printf's in the native library and observe them too. I don't see them at runtime however. I've created a convoluted hello world app to demonstrate my problem. When the app runs, I can debug into the native library and see that the hello world is called. The output never lands in the textwriter though. Note that if the same code is run as a console app then everything works fine. C#: [DllImport("native.dll")] static extern void Test(); StreamWriter writer; public Form1() { InitializeComponent(); writer = new StreamWriter(@"c:\output.txt"); writer.AutoFlush = true; System.Console.SetOut(writer); } private void button1_Click(object sender, EventArgs e) { Test(); } and the native part: __declspec(dllexport) void Test() { printf("Hello World"); } Despite my earlier ramblings (see edits) I actually think this is a problem in C# (or rather my understanding of it).

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  • What does * address(found in printf) mean in assembly?

    - by Mask
    Disassembling printf doesn't give much info: (gdb) disas printf Dump of assembler code for function printf: 0x00401b38 <printf+0>: jmp *0x405130 0x00401b3e <printf+6>: nop 0x00401b3f <printf+7>: nop End of assembler dump. (gdb) disas 0x405130 Dump of assembler code for function _imp__printf: 0x00405130 <_imp__printf+0>: je 0x405184 <_imp__vfprintf+76> 0x00405132 <_imp__printf+2>: add %al,(%eax) How is it implemented under the hood? Why disassembling doesn't help? What does * mean before 0x405130?

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  • The code works but when using printf it gives me a weird answer. Help please [closed]

    - by user71458
    //Programmer-William Chen //Seventh Period Computer Science II //Problem Statement - First get the elapsed times and the program will find the //split times for the user to see. // //Algorithm- First the programmer makes the prototype and calls them in the //main function. The programmer then asks the user to input lap time data. //Secondly, you convert the splits into seconds and subtract them so you can //find the splits. Then the average is all the lap time's in seconds. Finally, //the programmer printf all the results for the user to see. #include <iostream> #include <stdlib.h> #include <math.h> #include <conio.h> #include <stdio.h> using namespace std; void thisgetsElapsedTimes( int &m1, int &m2, int &m3, int &m4, int &m5, int &s1, int &s2, int &s3, int &s4, int &s5); //this is prototype void thisconvertstoseconds ( int &m1, int &m2, int &m3, int &m4, int &m5, int &s1, int &s2, int &s3, int &s4, int &s5, int &split1, int &split2, int &split3, int &split4, int &split5);//this too void thisfindsSplits(int &m1, int &m2, int &m3, int &m4, int &m5, int &split1, int &split2, int &split3, int &split4, int &split5, int &split6, int &split7, int &split8, int &split9, int &split10);// this is part of prototype void thisisthesecondconversation (int &split1M, int &split2M, int &split3M, int &split4M, int &split5M, int &split1S,int &split2S, int &split3S, int &split4S, int &split5S, int &split1, int &split2, int &split3, int &split4, int &split5);//this gets a value void thisfindstheaverage(double &average, int &split1, int &split2, int &split3, int &split4, int &split5);//and this void thisprintsstuff( int &split1M, int &split2M, int &split3M, int &split4M, int &split5M, int &split1S, int &split2S, int &split3S, int &split4S, int &split5S, double &average); //this prints int main(int argc, char *argv[]) { int m1, m2, m3, m4, m5, s1, s2, s3, s4, s5, split1, split2, split3, split4, split5, split1M, split2M, split3M, split4M, split5M, split1S, split2S, split3S, split4S, split5S; int split6, split7, split8, split9, split10; double average; char thistakescolon; thisgetsElapsedTimes ( m1, m2, m3, m4, m5, s1, s2, s3, s4, s5); thisconvertstoseconds ( m1, m2, m3, m4, m5, s1, s2, s3, s4, s5, split1, split2, split3, split4, split5); thisfindsSplits ( m1, m2, m3, m4, m5, split1, split2, split3, split4, split5, split6, split7, split8, split9, split10); thisisthesecondconversation ( split1M, split2M, split3M, split4M, split5M, split1S, split2S, split3S, split4S, split5S, split1, split2, split3, split4, split5); thisfindstheaverage ( average, split1, split2, split3, split4, split5); thisprintsstuff ( split1M, split2M, split3M, split4M, split5M, split1S, split2S, split3S, split4S, split5S, average); // these are calling statements and they call from the main function to the other functions. system("PAUSE"); return 0; } void thisgetsElapsedTimes(int &m1, int &m2, int &m3, int &m4, int &m5, int &s1, int &s2, int &s3, int &s4, int &s5) { char thistakescolon; cout << "Enter the elapsed time:" << endl; cout << " Kilometer 1 "; cin m1 thistakescolon s1; cout << " Kilometer 2 "; cin m2 thistakescolon s2; cout << " Kilometer 3 " ; cin m3 thistakescolon s3; cout << " Kilometer 4 "; cin m4 thistakescolon s4; cout << " Kilometer 5 "; cin m5 thistakescolon s5; // this gets the data required to get the results needed for the user to see // . } void thisconvertstoseconds (int &m1, int &m2, int &m3, int &m4, int &m5, int &s1, int &s2, int &s3, int &s4, int &s5, int &split1, int &split2, int &split3, int &split4, int &split5) { split1 = (m1 * 60) + s1;//this converts for minutes to seconds for m1 split2 = (m2 * 60) + s2;//this converts for minutes to seconds for m2 split3 = (m3 * 60) + s3;//this converts for minutes to seconds for m3 split4 = (m4 * 60) + s4;//this converts for minutes to seconds for m4 split5 = (m5 * 60) + s5;//this converts for minutes to seconds for m5 } void thisfindsSplits (int &m1, int &m2, int &m3, int &m4, int &m5,int &split1, int &split2, int &split3, int &split4, int &split5, int &split6, int &split7, int &split8, int &split9, int &split10)//this is function heading { split6 = split1; //this is split for the first lap. split7 = split2 - split1;//this is split for the second lap. split8 = split3 - split2;//this is split for the third lap. split9 = split4 - split3;//this is split for the fourth lap. split10 = split5 - split4;//this is split for the fifth lap. } void thisfindstheaverage(double &average, int &split1, int &split2, int &split3, int &split4, int &split5) { average = (split1 + split2 + split3 + split4 + split5)/5; // this finds the average from all the splits in seconds } void thisisthesecondconversation (int &split1M, int &split2M, int &split3M, int &split4M, int &split5M, int &split1S,int &split2S, int &split3S, int &split4S, int &split5S, int &split1, int &split2, int &split3, int &split4, int &split5) { split1M = split1 * 60; //this finds the split times split1S = split1M - split1 * 60; //then this finds split2M = split2 * 60; //and all of this split2S = split2M - split2 * 60; //does basically split3M = split3 * 60; //the same thing split3S = split3M - split3 * 60; //all of it split4M = split4 * 60; //it's also a split4S = split4M - split4 * 60; //function split5M = split5 * 60; //and it finds the splits split5S = split5M - split5 * 60; //for each lap. } void thisprintsstuff (int &split1M, int &split2M, int &split3M, int &split4M, int &split5M, int &split1S, int &split2S, int &split3S, int &split4S, int &split5S, double &average)// this is function heading { printf("\n kilometer 1 %d" , ":02%d",'split1M','split1S'); printf("\n kilometer 2 %d" , ":02%d",'split2M','split2S'); printf("\n kilometer 3 %d" , ":02%d",'split3M','split3S'); printf("\n kilometer 4 %d" , ":02%d",'split4M','split4S'); printf("\n kilometer 5 %d" , ":02%d",'split5M','split5S'); printf("\n your average pace is ",'average',"per kilometer \n", "William Chen\n"); // this printf so the programmer // can allow the user to see // the results from the data gathered. }

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  • printf and Console.WriteLine

    - by Matt Jacobsen
    Hi, i have a bunch of Console.WriteLines in my code that I can observe at runtime. I communicate with a native library that I also wrote. I'd like to stick some printf's in the native library and observe them too. I don't see them at runtime however. What am I doing wrong? Cheers, Matt

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  • Printf in assembler doesn't print

    - by Gaim
    Hi there, I have got a homework to hack program using buffer overflow ( with disassambling, program was written in C++, I haven't got the source code ). I have already managed it but I have a problem. I have to print some message on the screen, so I found out address of printf function, pushed address of "HACKED" and address of "%s" on the stack ( in this order ) and called that function. Called code passed well but nothing had been printed. I have tried to simulate the environment like in other place in the program but there has to be something wrong. Do you have any idea what I am doing wrong that I have no output, please? Thanks a lot EDIT: This program is running on Windows XP SP3 32b, written in C++, Intel asm there is the "hack" code CPU Disasm Address Hex dump Command Comments 0012F9A3 90 NOP ;hack begins 0012F9A4 90 NOP 0012F9A5 90 NOP 0012F9A6 89E5 MOV EBP,ESP 0012F9A8 83EC 7F SUB ESP,7F ;creating a place for working data 0012F9AB 83EC 7F SUB ESP,7F 0012F9AE 31C0 XOR EAX,EAX 0012F9B0 50 PUSH EAX 0012F9B1 50 PUSH EAX 0012F9B2 50 PUSH EAX 0012F9B3 89E8 MOV EAX,EBP 0012F9B5 83E8 09 SUB EAX,9 0012F9B8 BA 1406EDFF MOV EDX,FFED0614 ;address to jump, it is negative because there mustn't be 00 bytes 0012F9BD F7DA NOT EDX 0012F9BF FFE2 JMP EDX ;I have to jump because there are some values overwritten by the program 0012F9C1 90 NOP 0012F9C2 0090 00000000 ADD BYTE PTR DS:[EAX],DL 0012F9C8 90 NOP 0012F9C9 90 NOP 0012F9CA 90 NOP 0012F9CB 90 NOP 0012F9CC 6C INS BYTE PTR ES:[EDI],DX ; I/O command 0012F9CD 65:6E OUTS DX,BYTE PTR GS:[ESI] ; I/O command 0012F9CF 67:74 68 JE SHORT 0012FA3A ; Superfluous address size prefix 0012F9D2 2069 73 AND BYTE PTR DS:[ECX+73],CH 0012F9D5 203439 AND BYTE PTR DS:[EDI+ECX],DH 0012F9D8 34 2C XOR AL,2C 0012F9DA 2066 69 AND BYTE PTR DS:[ESI+69],AH 0012F9DD 72 73 JB SHORT 0012FA52 0012F9DF 74 20 JE SHORT 0012FA01 0012F9E1 3120 XOR DWORD PTR DS:[EAX],ESP 0012F9E3 6C INS BYTE PTR ES:[EDI],DX ; I/O command 0012F9E4 696E 65 7300909 IMUL EBP,DWORD PTR DS:[ESI+65],-6F6FFF8D 0012F9EB 90 NOP 0012F9EC 90 NOP 0012F9ED 90 NOP 0012F9EE 31DB XOR EBX,EBX ; hack continues 0012F9F0 8818 MOV BYTE PTR DS:[EAX],BL ; writing 00 behind word "HACKED" 0012F9F2 83E8 06 SUB EAX,6 0012F9F5 50 PUSH EAX ; address of "HACKED" 0012F9F6 B8 3B8CBEFF MOV EAX,FFBE8C3B 0012F9FB F7D0 NOT EAX 0012F9FD 50 PUSH EAX ; address of "%s" 0012F9FE B8 FFE4BFFF MOV EAX,FFBFE4FF 0012FA03 F7D0 NOT EAX 0012FA05 FFD0 CALL EAX ;address of printf This code is really ugly because I am new in assembler and there mustn't be null bytes because of buffer-overflow bug

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  • Print numbers sequentially using printf with filling zeroes

    - by Werner
    Hi, in C++, using printf I want to print a sequence of number, so I get, from a "for" loop; 1 2 ... 9 10 11 and I create files from those numbers. But when I list them using "ls" I get 10 11 1 2 .. so instead of trying to solve the problem using bash, I wonder how could I print; 0001 0002 ... 0009 0010 0011 and so on Thanks

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