Search Results

Search found 2376 results on 96 pages for 'spring roo'.

Page 4/96 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

  • Why do I get a NullPointerException when initializing Spring

    - by niklassaers
    Hi guys, I've got a problem running a batch job on my server, whereas it runs fine from Eclipse on my development workstation. I've got my Spring environment set up using Roo, made an entity, and make a batch that does some work, and test it well on my develompent box. I initialize my context and do the work, but when I run my batch on the server, the context isn't initialized properly. Here's the code: public class TestBatch { private static ApplicationContext context; @SuppressWarnings("unchecked") public static void main(final String[] args) { context = new ClassPathXmlApplicationContext("/META-INF/spring/applicationContext.xml"); try { @SuppressWarnings("unused") TestBatch app = new TestBatch(); } catch (Exception ex) { ex.printStackTrace(); } } public void TestBatch() { /** Do Something using the context **/ } } And here's the log and exception: 2010-02-16 11:54:16,072 [main] INFO org.springframework.context.support.ClassPathXmlApplicationContext - Refreshing org.springframework.context.support.ClassPathXmlApplicationContext@6037fb1e: startup date [Tue Feb 16 11:54:16 CET 2010]; root of context hierarchy Exception in thread "main" java.lang.ExceptionInInitializerError at org.springframework.context.support.AbstractRefreshableApplicationContext.createBeanFactory(AbstractRefreshableApplicationContext.java:194) at org.springframework.context.support.AbstractRefreshableApplicationContext.refreshBeanFactory(AbstractRefreshableApplicationContext.java:127) at org.springframework.context.support.AbstractApplicationContext.obtainFreshBeanFactory(AbstractApplicationContext.java:458) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:388) at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:139) at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:83) at tld.mydomain.myproject.batch.TestBatch.main(TestBatch.java:51) Caused by: java.lang.NullPointerException at org.springframework.beans.factory.support.DefaultListableBeanFactory.<clinit>(DefaultListableBeanFactory.java:103) ... 7 more Any idea or hints as to what's going on? My classpath is set to $PROJECTHOME/target/classes, and all my dependencies are in $PROJECTHOME/target/lib, and I execute using "export CLASSPATH=$PROJECTHOME/target/classes; java -Djava.endorsed.dirs=$PROJECTHOME/target/lib tld.mydomain.myproject.batch.TestBatch" Is there anything in my setup that looks very wrong? When I run this from Eclipse, no problems, but when I deploy it on the server where I want to run it and run it as described above, I get this problem. Because it runs from Eclipse, I believe my config files are all right, but how can I debug what's causing this? Perhaps I have some config errors or a mismatch between the server and the development workstation after all? Or is this a really weird way of saying file not found, and if so, how do I make sure it finds the correct file?? I'm really looking forward to hearing your suggestions as to how to tackle this problem. Cheers Nik

    Read the article

  • Access and modify attributes/objects which are not part of the form backing bean

    - by spa
    I use Spring MVC (via Spring Roo) to build a small web application for administering persons. In the page for creating a person the bean Person is used as form backing object (key "person" in the model map). <form:form action="${form_url}" method="POST" modelAttribute="person"> I would like to add some attributes to the model map which can be altered by the user in the creation form. Basically, I try to add a Boolean, so that I can control which page is displayed next after the user presses the submit button. I try to modify the Boolean (key "myBoolean" in the model map) using a simple checkbox: <form:checkbox id="_myboolean_id" path="myBoolean"/> However, as I am new to Spring MVC I have some difficulties here. The Boolean object is not an attribute of the form backing object. So if I try to access it the following exception is thrown (of course): Invalid property 'myBoolean' of bean class [de.cm.model.Person]: Bean property 'myBoolean' is not readable or has an invalid getter method: Does the return type of the getter match the parameter type of the setter? Is there are way to access a value of the model map directly? The only solution I can imagine right now is a kind of wrapper object around the class Person and my additional attributes which is used as a new form backing object. However, this is more work for a IMHO simple task. Do you have a better solution?

    Read the article

  • Spring ROO issue with UrlRewrite in STS (eclipse)

    - by user224270
    Hi. I'm having trouble figuring out how to solve this issue. I have a file called: "urlrewrite.xml" which was automatically generated by spring ROO after running the "controller" command in ROO Shell. However, I still get the following error: "Referenced file contains errors (http://tuckey.org/res/dtds/urlrewrite3.0.dtd). For more information, right click on the message in the Problems View and select "Show Details..." Here's the content of the urlrewrite.xml file: <?xml version="1.0" encoding="utf-8"?> <!DOCTYPE urlrewrite PUBLIC "-//tuckey.org//DTD UrlRewrite 3.0//EN" "http://tuckey.org/res/dtds/urlrewrite3.0.dtd"> <urlrewrite default-match-type="wildcard"> <rule> <from>/resources/**</from> <to last="true">/resources/$1</to> </rule> <rule> <from>/static/WEB-INF/**</from> <set type="status">403</set> <to last="true">/static/WEB-INF/$1</to> </rule> <rule> <from>/static/**</from> <to last="true">/$1</to> </rule> <rule> <from>/</from> <to last="true">/app/index</to> </rule> <rule> <from>/app/**</from> <to last="true">/app/$1</to> </rule> <rule> <from>/**</from> <to>/app/$1</to> </rule> <outbound-rule> <from>/app/**</from> <to>/$1</to> </outbound-rule> </urlrewrite> Any thoughts on how to get rid of this error?

    Read the article

  • Spring ROO issue with UrlRewrite in STS (eclipse)

    - by user224270
    I'm having trouble figuring out how to solve this issue. I have a file called: "urlrewrite.xml" which was automatically generated by spring ROO after running the "controller" command in ROO Shell. However, I still get the following error: "Referenced file contains errors (http://tuckey.org/res/dtds/urlrewrite3.0.dtd). For more information, right click on the message in the Problems View and select "Show Details..." Here's the content of the urlrewrite.xml file: <?xml version="1.0" encoding="utf-8"?> <!DOCTYPE urlrewrite PUBLIC "-//tuckey.org//DTD UrlRewrite 3.0//EN" "http://tuckey.org/res/dtds/urlrewrite3.0.dtd"> <urlrewrite default-match-type="wildcard"> <rule> <from>/resources/**</from> <to last="true">/resources/$1</to> </rule> <rule> <from>/static/WEB-INF/**</from> <set type="status">403</set> <to last="true">/static/WEB-INF/$1</to> </rule> <rule> <from>/static/**</from> <to last="true">/$1</to> </rule> <rule> <from>/</from> <to last="true">/app/index</to> </rule> <rule> <from>/app/**</from> <to last="true">/app/$1</to> </rule> <rule> <from>/**</from> <to>/app/$1</to> </rule> <outbound-rule> <from>/app/**</from> <to>/$1</to> </outbound-rule> </urlrewrite> Any thoughts on how to get rid of this error?

    Read the article

  • Grails/Roo for a .Net developer

    - by Kynth
    I am currently picking up Grails and Roo to expand my skills and to have a bit of fun. The vast majority of training materials appear aimed at new developers or Java developers. Does anyone know of any guides, resources or have any tips and anecdotes for translating existing development experience with .Net (C#/ASP.Net/Asp.Net MVC)?

    Read the article

  • Spring maven libraries

    - by Calm Storm
    I would like to know why some of the libraries are not released during a normal release cycle. For example, from http://repo2.maven.org/maven2/org/springframework/ while spring-core have 3.0.3-RELEASE, spring-remoting and spring-jmx were released only in 2.0.8. Can someone tell me what this would mean? I agree that if there are no changes in the component say spring-jmx then they don't have to release it, but since 90% of the world uses Maven for dependency management can they not just re-release the same libs (of spring-remoting and spring-jmx?) I ask this because I declare my deps like, <dependency> <groupId>org.springframework</groupId> <artifactId>spring-core</artifactId> <version>${spring.version}</version> </dependency> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-remoting</artifactId> <version>${spring.version}</version> </dependency> and I would prefer supplying one spring.version instead of keeping version numbers upto date for all components? The four libraries of interest to me are spring-dao, spring-support, spring-jmx, spring-remoting

    Read the article

  • Non-managed by Spring web-application and jar file with Spring features

    - by EugeneP
    My idea is to create a .jar file that contains Services managed by Spring, that should be got by getBean() I want to put it to WEB-INF/lib of a Web-app Then in web-app Servlets I want to get use of the functionality of a Jar file. 1 Idea. Create classes that encapsulate invokation to Spring Context (getBean() etc) So then, I suppose there'll be no problem in using those in Servlets through jar import. Only thing, what kind of context I should use inside .jar to get beans so that it worked after packing into jar? ApplicationContext or what? 2 Idea. Is there another simple solution how to pack into jar and then use Services in a non-managed by Spring environment?

    Read the article

  • Uploading multiple files using Spring MVC 3.0.2 after HiddenHttpMethodFilter has been enabled

    - by Tiny
    I'm using Spring version 3.0.2. I need to upload multiple files using the multiple="multiple" attribute of a file browser such as, <input type="file" id="myFile" name="myFile" multiple="multiple"/> (and not using multiple file browsers something like the one stated by this answer, it indeed works I tried). Although no versions of Internet Explorer supports this approach unless an appropriate jQuery plugin/widget is used, I don't care about it right now (since most other browsers support this). This works fine with commons fileupload but in addition to using RequestMethod.POST and RequestMethod.GET methods, I also want to use other request methods supported and suggested by Spring like RequestMethod.PUT and RequestMethod.DELETE in their own appropriate places. For this to be so, I have configured Spring with HiddenHttpMethodFilter which goes fine as this question indicates. but it can upload only one file at a time even though multiple files in the file browser are chosen. In the Spring controller class, a method is mapped as follows. @RequestMapping(method={RequestMethod.POST}, value={"admin_side/Temp"}) public String onSubmit(@RequestParam("myFile") List<MultipartFile> files, @ModelAttribute("tempBean") TempBean tempBean, BindingResult error, Map model, HttpServletRequest request, HttpServletResponse response) throws IOException, FileUploadException { for(MultipartFile file:files) { System.out.println(file.getOriginalFilename()); } } Even with the request parameter @RequestParam("myFile") List<MultipartFile> files which is a List of type MultipartFile (it can always have only one file at a time). I could find a strategy which is likely to work with multiple files on this blog. I have gone through it carefully. The solution below the section SOLUTION 2 – USE THE RAW REQUEST says, If however the client insists on using the same form input name such as ‘files[]‘ or ‘files’ and then populating that name with multiple files then a small hack is necessary as follows. As noted above Spring 2.5 throws an exception if it detects the same form input name of type file more than once. CommonsFileUploadSupport – the class which throws that exception is not final and the method which throws that exception is protected so using the wonders of inheritance and subclassing one can simply fix/modify the logic a little bit as follows. The change I’ve made is literally one word representing one method invocation which enables us to have multiple files incoming under the same form input name. It attempts to override the method protected MultipartParsingResult parseFileItems(List fileItems, String encoding) {} of the abstract class CommonsFileUploadSupport by extending the class CommonsMultipartResolver such as, package multipartResolver; import java.io.UnsupportedEncodingException; import java.util.HashMap; import java.util.Iterator; import java.util.List; import java.util.Map; import javax.servlet.ServletContext; import org.apache.commons.fileupload.FileItem; import org.springframework.util.StringUtils; import org.springframework.web.multipart.MultipartException; import org.springframework.web.multipart.MultipartFile; import org.springframework.web.multipart.commons.CommonsMultipartFile; import org.springframework.web.multipart.commons.CommonsMultipartResolver; final public class MultiCommonsMultipartResolver extends CommonsMultipartResolver { public MultiCommonsMultipartResolver() { } public MultiCommonsMultipartResolver(ServletContext servletContext) { super(servletContext); } @Override @SuppressWarnings("unchecked") protected MultipartParsingResult parseFileItems(List fileItems, String encoding) { Map<String, MultipartFile> multipartFiles = new HashMap<String, MultipartFile>(); Map multipartParameters = new HashMap(); // Extract multipart files and multipart parameters. for (Iterator it = fileItems.iterator(); it.hasNext();) { FileItem fileItem = (FileItem) it.next(); if (fileItem.isFormField()) { String value = null; if (encoding != null) { try { value = fileItem.getString(encoding); } catch (UnsupportedEncodingException ex) { if (logger.isWarnEnabled()) { logger.warn("Could not decode multipart item '" + fileItem.getFieldName() + "' with encoding '" + encoding + "': using platform default"); } value = fileItem.getString(); } } else { value = fileItem.getString(); } String[] curParam = (String[]) multipartParameters.get(fileItem.getFieldName()); if (curParam == null) { // simple form field multipartParameters.put(fileItem.getFieldName(), new String[] { value }); } else { // array of simple form fields String[] newParam = StringUtils.addStringToArray(curParam, value); multipartParameters.put(fileItem.getFieldName(), newParam); } } else { // multipart file field CommonsMultipartFile file = new CommonsMultipartFile(fileItem); if (multipartFiles.put(fileItem.getName(), file) != null) { throw new MultipartException("Multiple files for field name [" + file.getName() + "] found - not supported by MultipartResolver"); } if (logger.isDebugEnabled()) { logger.debug("Found multipart file [" + file.getName() + "] of size " + file.getSize() + " bytes with original filename [" + file.getOriginalFilename() + "], stored " + file.getStorageDescription()); } } } return new MultipartParsingResult(multipartFiles, multipartParameters); } } What happens is that the last line in the method parseFileItems() (the return statement) i.e. return new MultipartParsingResult(multipartFiles, multipartParameters); causes a compile-time error because the first parameter multipartFiles is a type of Map implemented by HashMap but in reality, it requires a parameter of type MultiValueMap<String, MultipartFile> It is a constructor of a static class inside the abstract class CommonsFileUploadSupport, public abstract class CommonsFileUploadSupport { protected static class MultipartParsingResult { public MultipartParsingResult(MultiValueMap<String, MultipartFile> mpFiles, Map<String, String[]> mpParams) { } } } The reason might be - this solution is about the Spring version 2.5 and I'm using the Spring version 3.0.2 which might be inappropriate for this version. I however tried to replace the Map with MultiValueMap in various ways such as the one shown in the following segment of code, MultiValueMap<String, MultipartFile>mul=new LinkedMultiValueMap<String, MultipartFile>(); for(Entry<String, MultipartFile>entry:multipartFiles.entrySet()) { mul.add(entry.getKey(), entry.getValue()); } return new MultipartParsingResult(mul, multipartParameters); but no success. I'm not sure how to replace Map with MultiValueMap and even doing so could work either. After doing this, the browser shows the Http response, HTTP Status 400 - type Status report message description The request sent by the client was syntactically incorrect (). Apache Tomcat/6.0.26 I have tried to shorten the question as possible as I could and I haven't included unnecessary code. How could be made it possible to upload multiple files after Spring has been configured with HiddenHttpMethodFilter? That blog indicates that It is a long standing, high priority bug. If there is no solution regarding the version 3.0.2 (3 or higher) then I have to disable Spring support forever and continue to use commons-fileupolad as suggested by the third solution on that blog omitting the PUT, DELETE and other request methods forever. Just curiously waiting for a solution and/or suggestion. Very little changes to the code in the parseFileItems() method inside the class MultiCommonsMultipartResolver might make it to upload multiple files but I couldn't succeed in my attempts (again with the Spring version 3.0.2 (3 or higher)).

    Read the article

  • What other libraries or tools would you add to a Spring/Hibernate stack for improved rapid applicati

    - by CaptainAwesomePants
    My team at work maintains a fairly large webapp written on top of Spring and Hibernate. We're about to start making some fairly large scale changes to the site, and we're enamored with the rapid application development speeds allowed by some other frameworks, like Rails. We haven't really changed our stack much in the last year or two, and I'm wondering what new tools, approaches, and libraries might be out there to help speed up webapp development.

    Read the article

  • Spring-JSON Used in Spring MVC

    - by Mark Estrada
    Hi, I came across the library Spring-JSON while looking to add Ajax Support in my spring mvc webapp 2.5. My question is, has anybody here have used this library and what are your experiences? Is there any better alternative than this?

    Read the article

  • spring security login pages?

    - by es11
    I have some confusion with how spring security works: In my application, I need to have a login page for users after which they are redirected back the page from where they came. I went through a few spring security tutorials and read some articles, and the examples work by securing a certain page on a site (managed by the <intercept url ..> tag). Then Spring security will generate a login page (or you can specify your own) in order to access the secured page. I am confused because I don't want to necessary secure a given page on my site: I want a login page for users to log into after which they have access to elevated features of the site (through spring security's authorization features). My question is: given what I described, what would be the strategy to create this login page which, after login, would grant the logged in user the appropriate authorities? The hack I thought of would be to create a simple JSP page who's only function is to redirect back to the previous page. Then I would use Spring Security to secure that JSP page. But it seems like there should be a better way of doing this... Thanks

    Read the article

  • Learning Spring MVC For web-projects

    - by John
    I have looked at Spring MVC a few times briefly, and got the basic ideas. However whenever I look closely it seems to require you already know a whole load of 'core Spring'. The book I have for instance has a few hundred pages before it gets onto Spring MVC... which seems a lot to wade through. I'm used to being able to jump in, but there's so much bean-related stuff and XML, it just looks like a mass of data to consume. Does it simplify if you put the time in, or is Spring just a much bigger framework than I thought? is it possible to learn this side of it in isolation?

    Read the article

  • Autocompletion in Eclipse for Roo project

    - by niklassaers
    Hi guys, I've got a Roo project where I've made a couple of entities, and when I load up the project in Eclipse it loads up fine, but if I i.e. make an instance MyEntity entity and then write entity. I don't get any of my properties (i.e. getMyField) in the autocompletion list. If I write entity.getMyField() it compiles fine, that is taken care of by the aspects. How do I enable autocompletion for functions generated by the aspects? Cheers Nik

    Read the article

  • Spring MVC -> Wicket Integration

    - by Jeff
    Hey everyone, I'm working on porting part of an existing Spring MVC application over to Wicket. I used the wicket-spring library to get the initial integration working, but now I'm stuck with the best way to integrate my Spring Security implementation. I was wondering if anyone could give me some advice on the best way to handle this. Thanks in advance for the help.

    Read the article

  • Spring HandlerInterceptor or Spring Security to protect resource

    - by richever
    I've got a basic Spring Security 3 set up using my own login page. My configuration is below. I have the login and sign up page accessible to all as well as most everything else. I'm new to Spring Security and understand that if a user is trying to access a protected resource they will be taken to the defined login page. And upon successful login they are taken to some other page, home in my case. I want to keep the latter behavior; however, I'd like specify that if a user tries to access certain resources they are taken to the sign up page, not the login page. Currently, in my annotated controllers I check the security context to see if the user is logged in and if not I redirect them to the sign up page. I only do this currently with two urls and no others. This seemed redundant so I tried creating a HandlerInterceptor to redirect for these requests but realized that with annotations, you can't specify specific requests to be handled - they all are. So I'm wondering if there is some way to implement this type of specific url handling in Spring Security, or is going the HandlerInterceptor route my only option? Thanks! <http auto-config="true" use-expressions="true"> <intercept-url pattern="/login*" access="permitAll"/> <intercept-url pattern="/signup*" access="permitAll"/> <intercept-url pattern="/static/**" filters="none" /> <intercept-url pattern="/" access="permitAll"/> <form-login login-page="/login" default-target-url="/home"/> <logout logout-success-url="/home"/> <anonymous/> <remember-me/> </http>

    Read the article

  • Trouble getting started with Spring Roo and GWT

    - by Abdel Olakara
    Hi all, I am trying to get started with SpringRoo and GWT after seeing the keynote.. unfortunately I am stuck at this issue. I successfully created the project using Roo and added the persistence, the entities and when I perform the command "perform package" I get this error: 23/5/10 12:10:13 AM AST: [ERROR] ApplicationEntityTypesProcessor cannot be resolved 23/5/10 12:10:13 AM AST: [ERROR] ApplicationEntityTypesProcessor cannot be resolved to a type 23/5/10 12:10:13 AM AST: [WARN] advice defined in org.springframework.mock.staticmock.AnnotationDrivenStaticEntityMockingControl has not been applied [Xlint:adviceDidNotMatch] 23/5/10 12:10:13 AM AST: [WARN] advice defined in org.springframework.mock.staticmock.AbstractMethodMockingControl has not been applied [Xlint:adviceDidNotMatch] 23/5/10 12:10:13 AM AST: Build errors for helloroo; org.apache.maven.lifecycle.LifecycleExecutionException: Failed to execute goal org.codehaus.mojo:aspectj-maven-plugin:1.0:compile (default) on project helloroo: Compiler errors : error at import tp.gwt.request.ApplicationEntityTypesProcessor; I see this in the Maven console and cannot complete the build..I know there is some jar missing but how and why? because I downloaded all the latest version including GWT milestone release. Any idea why this error is occurring? How do I resolve this issue? Thanks in Advance, Abdel Olakara

    Read the article

  • Spring's EntityManager not persisting

    - by Fernando Camargo
    Well, my project was using EJB and JPA (with Hibernate), but I had to switch to Spring. Everything was working well before that. The EJB used to inject the EntityManager, controled the transaction, etc. Ok, when I switched to Spring, I had a lot of problems because I'm new on Spring. But after everything is running, I have the problem: the data is never saved on database. I configured my Spring to control the transactions, I have spring beans used in JSF, that has spring services that do the hard work. This services have a EntityManager injected and use @Transactional REQUIRED. This services pass the EntityManager to a DAO that call entityManager.persist(bean). The selects appears to work well, the JTA transaction appears to work well to (I saw in log), but the entity is not saved! Here is the log: INFO: [Pronatec] - 04/04/2012 11:30:20 - [DEBUG] org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter: doFilterInternal() (linha 136): Opening JPA EntityManager in OpenEntityManagerInViewFilter INFO: [Pronatec] - 04/04/2012 11:30:20 - [DEBUG] org.springframework.beans.factory.support.DefaultListableBeanFactory: doGetBean() (linha 245): Returning cached instance of singleton bean 'transactionManager' INFO: [Pronatec] - 04/04/2012 11:30:20 - [DEBUG] org.springframework.orm.hibernate3.HibernateTransactionManager: getTransaction() (linha 365): Creating new transaction with name [br.org.cni.pronatec.controller.service.MontanteServiceImpl.adicionarValor]: PROPAGATION_REQUIRED,ISOLATION_DEFAULT; '' INFO: [Pronatec] - 04/04/2012 11:30:20 - [DEBUG] org.springframework.orm.hibernate3.HibernateTransactionManager: doBegin() (linha 493): Opened new Session [org.hibernate.impl.SessionImpl@2b2fe2f0] for Hibernate transaction INFO: [Pronatec] - 04/04/2012 11:30:20 - [DEBUG] org.springframework.orm.hibernate3.HibernateTransactionManager: doBegin() (linha 504): Preparing JDBC Connection of Hibernate Session [org.hibernate.impl.SessionImpl@2b2fe2f0] INFO: [Pronatec] - 04/04/2012 11:30:20 - [DEBUG] org.springframework.orm.hibernate3.HibernateTransactionManager: doBegin() (linha 569): Exposing Hibernate transaction as JDBC transaction [com.sun.gjc.spi.jdbc40.ConnectionHolder40@3bcd4840] INFO: [Pronatec] - 04/04/2012 11:30:20 - [DEBUG] org.springframework.orm.jpa.ExtendedEntityManagerCreator$ExtendedEntityManagerInvocationHandler: doJoinTransaction() (linha 383): Joined JTA transaction INFO: Hibernate: select hibernate_sequence.nextval from dual INFO: [Pronatec] - 04/04/2012 11:30:20 - [DEBUG] org.springframework.orm.hibernate3.HibernateTransactionManager: processCommit() (linha 752): Initiating transaction commit INFO: [Pronatec] - 04/04/2012 11:30:20 - [DEBUG] org.springframework.orm.hibernate3.HibernateTransactionManager: doCommit() (linha 652): Committing Hibernate transaction on Session [org.hibernate.impl.SessionImpl@2b2fe2f0] INFO: [Pronatec] - 04/04/2012 11:30:20 - [DEBUG] org.springframework.orm.hibernate3.HibernateTransactionManager: doCleanupAfterCompletion() (linha 734): Closing Hibernate Session [org.hibernate.impl.SessionImpl@2b2fe2f0] after transaction INFO: [Pronatec] - 04/04/2012 11:30:20 - [DEBUG] org.springframework.orm.hibernate3.SessionFactoryUtils: closeSession() (linha 800): Closing Hibernate Session INFO: [Pronatec] - 04/04/2012 11:30:20 - [DEBUG] org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter: doFilterInternal() (linha 154): Closing JPA EntityManager in OpenEntityManagerInViewFilter INFO: [Pronatec] - 04/04/2012 11:30:20 - [DEBUG] org.springframework.orm.jpa.EntityManagerFactoryUtils: closeEntityManager() (linha 343): Closing JPA EntityManager In the log, I see it commiting the transaction, but I don't see the insert query (the Hibernate is printing any query). I also see that the Hibernate lookup to get the next value of the sequence ID. But after that, it never really inserts. Here is the spring context configuration: <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="persistenceUnitName" value="PronatecPU" /> <property name="persistenceXmlLocation" value="classpath:META-INF/persistence.xml" /> <property name="loadTimeWeaver"> <bean class="org.springframework.instrument.classloading.InstrumentationLoadTimeWeaver"/> </property> <property name="jpaProperties"> <props> <prop key="hibernate.transaction.factory_class">org.hibernate.transaction.JTATransactionFactory</prop> </props> </property> </bean> <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager" > <property name="transactionManagerName" value="java:/TransactionManager" /> <property name="userTransactionName" value="UserTransaction" /> <property name="entityManagerFactory" ref="entityManagerFactory" /> </bean> <bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" /> <tx:annotation-driven transaction-manager="transactionManager" /> Here is my persistence.xml: <?xml version="1.0" encoding="UTF-8"?> <persistence version="1.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"> <persistence-unit name="PronatecPU" transaction-type="JTA"> <provider>org.hibernate.ejb.HibernatePersistence</provider> <jta-data-source>jdbc/pronatec</jta-data-source> <class>br.org.cni.pronatec.model.bean.AgendamentoBuscaSistec</class> <class>br.org.cni.pronatec.model.bean.AgendamentoExportacaoZeus</class> <class>br.org.cni.pronatec.model.bean.AgendamentoImportacaoZeus</class> <class>br.org.cni.pronatec.model.bean.Aluno</class> <class>br.org.cni.pronatec.model.bean.Curso</class> <class>br.org.cni.pronatec.model.bean.DepartamentoRegional</class> <class>br.org.cni.pronatec.model.bean.Dof</class> <class>br.org.cni.pronatec.model.bean.Escola</class> <class>br.org.cni.pronatec.model.bean.Inconsistencia</class> <class>br.org.cni.pronatec.model.bean.Matricula</class> <class>br.org.cni.pronatec.model.bean.Montante</class> <class>br.org.cni.pronatec.model.bean.ParametrosVingentes</class> <class>br.org.cni.pronatec.model.bean.TipoCurso</class> <class>br.org.cni.pronatec.model.bean.Turma</class> <class>br.org.cni.pronatec.model.bean.UnidadeFederativa</class> <class>br.org.cni.pronatec.model.bean.ValorAssistenciaEstudantil</class> <class>br.org.cni.pronatec.model.bean.ValorHora</class> <exclude-unlisted-classes>true</exclude-unlisted-classes> <properties> <property name="current_session_context_class" value="thread"/> <property name="hibernate.show_sql" value="true"/> <property name="hibernate.format_sql" value="true"/> <property name="hibernate.dialect" value="org.hibernate.dialect.OracleDialect"/> <property name="hibernate.transaction.manager_lookup_class" value="org.hibernate.transaction.SunONETransactionManagerLookup"/> <property name="hibernate.hbm2ddl.auto" value="update"/> </properties> </persistence-unit> </persistence> Here is my service that is injected in the managed bean: @Service @Scope("prototype") @Transactional(propagation= Propagation.REQUIRED) public class MontanteServiceImpl { // more code @PersistenceContext(unitName="PronatecPU", type= PersistenceContextType.EXTENDED) private EntityManager entityManager; // more code // The method that is called by another public method that do something before private void salvarMontante(Montante montante) { montante.setDataTransacao(new Date()); MontanteDao montanteDao = new MontanteDao(entityManager); montanteDao.salvar(montante); } // more code } My MontanteDao inherits from a base DAO, like this: public class MontanteDao extends BaseDao<Montante> { public MontanteDao(EntityManager entityManager) { super(entityManager); } } And the method that is called in BaseDao is this: public void salvar(T bean) { entityManager.persist(bean); } Like you can see, it just pick the injected entityManager and call the persist() method. The transaction is being controlled by the Spring, like is printed in the log, but the insert query is never printed in log and it is never saved. I'm sorry about my bad english. Thanks in advance for who helps.

    Read the article

  • Spring Security ACL: NotFoundException from JDBCMutableAclService.createAcl

    - by user340202
    Hello, I've been working on this task for too long to abandon the idea of using Spring Security to achieve it, but I wish that the community will provide with some support that will help reduce the regret that I have for choosing Spring Security. Enough ranting and now let's get to the point. I'm trying to create an ACL by using JDBCMutableAclService.createAcl as follows: [code] public void addPermission(IWFArtifact securedObject, Sid recipient, Permission permission, Class clazz) { ObjectIdentity oid = new ObjectIdentityImpl(clazz.getCanonicalName(), securedObject.getId()); this.addPermission(oid, recipient, permission); } @Override @Transactional(propagation = Propagation.REQUIRED, isolation = Isolation.READ_UNCOMMITTED, readOnly = false) public void addPermission(ObjectIdentity oid, Sid recipient, Permission permission) { SpringSecurityUtils.assureThreadLocalAuthSet(); MutableAcl acl; try { acl = this.mutableAclService.createAcl(oid); } catch (AlreadyExistsException e) { acl = (MutableAcl) this.mutableAclService.readAclById(oid); } // try { // acl = (MutableAcl) this.mutableAclService.readAclById(oid); // } catch (NotFoundException nfe) { // acl = this.mutableAclService.createAcl(oid); // } acl.insertAce(acl.getEntries().length, permission, recipient, true); this.mutableAclService.updateAcl(acl); } [/code] The call throws a NotFoundException from the line: [code] // Retrieve the ACL via superclass (ensures cache registration, proper retrieval etc) Acl acl = readAclById(objectIdentity); [/code] I believe this is caused by something related to Transactional, and that's why I have tested with many TransactionDefinition attributes. I have also doubted the annotation and tried with declarative transaction definition, but still with no luck. One important point is that I have used the statement used to insert the oid in the database earlier in the method directly on the database and it worked, and also threw a unique constraint exception at me when it tried to insert it in the method. I'm using Spring Security 2.0.8 and IceFaces 1.8 (which doesn't support spring 3.0 but definetely supprorts 2.0.x, specially when I keep caling SpringSecurityUtils.assureThreadLocalAuthSet()). My AppServer is Tomcat 6.0, and my DB Server is MySQL 6.0 I wish to get back a reply soon because I need to get this task off my way

    Read the article

  • Request size limitation when using MultipartHttpServletRequest of Spring 3.0

    - by Spiderman
    I'd like to know what is the size limitation if I upload list of files in one client's form submition using HTTP multipart content type. On the server side I am using Spring's MultipartHttpServletRequest to handle the request. mM questions: Is there should be different file size limitation and total request size limitation or file size is the only limitation and the request is capable of uploading 100s of files as lonng as they are not too large. Doest the Spring request wrapper read the complete request and store it in the JAVA heap memory or it store temporaray files of it to be able to use big quota. Is the use of reading the httpservlet request in streaming would change the size limitation than using complete http request read at-once by the application server. What is the bottleneck of this process - Java heap size, the quota of the filesystem on which my web-server runs, the maximum allowed BLOB size that the DataBase in which I am gonna save the file alows? or Spring internal limitations? Related threads that still don't have exact answer to this: does-spring-framework-support-streaming-mode-in-mutlipart-requests is-there-a-way-to-get-raw-http-request-stream-from-java-servlet-handler how-to- drop-body-of-a-request-after-checking-headers-in-servlet apache-commons-fileupload-throws-malformedstreamexception

    Read the article

  • Custom bean instantiation logic in Spring MVC

    - by Michal Bachman
    I have a Spring MVC application trying to use a rich domain model, with the following mapping in the Controller class: @RequestMapping(value = "/entity", method = RequestMethod.POST) public String create(@Valid Entity entity, BindingResult result, ModelMap modelMap) { if (entity== null) throw new IllegalArgumentException("An entity is required"); if (result.hasErrors()) { modelMap.addAttribute("entity", entity); return "entity/create"; } entity.persist(); return "redirect:/entity/" + entity.getId(); } Before this method gets executed, Spring uses BeanUtils to instantiate a new Entity and populate its fields. It uses this: ... ReflectionUtils.makeAccessible(ctor); return ctor.newInstance(args); Here's the problem: My entities are Spring managed beans. The reason for this is to inject DAOs on them. Instead of calling new, I use EntityFactory.createEntity(). When they're retrieved from the database, I have an interceptor that overrides the public Object instantiate(String entityName, EntityMode entityMode, Serializable id) method and hooks the factories into that. So the last piece of the puzzle missing here is how to force Spring to use the factory rather than its own BeanUtils reflective approach? Any suggestions for a clean solution? Thanks very much in advance.

    Read the article

  • New to Java and Spring. What are some good design principles for an inexperienced java developer like me?

    - by Imtiaz Ahmad
    I am learning Java and have written a few small useful programs. I am new to spring but have managed to understand the concept of dependency injection for decoupling. I'm trying to applying that in my development work in an enterprise setting. What are the 3 most important design patterns I should master (not for interview purposes but ones that I will use every day in as a good java developer)? Also what are some good java design considerations and practices in coding specifically in Java? My goal is write good decoupled and coherent programs that are easy to maintain that don't make me standout as a java rookie. Stuff like not beginning my package names with com. have already made me precariously visible in my team. But they know I have 2 years of coding experience and its not in java.

    Read the article

  • Spring-json problem in Liferay with Spring 2.5

    - by Jesus Benito
    Hi all, I am trying to use the library spring-json.1.3.1 in a project that has been done with Liferay 5.1.2 which includes Spring 2.5. Following the project website instructions, I managed to make the request hit in my controller, but at the moment of returning the json object back through the modelAndView object it fails with the following error: java.lang.IllegalArgumentException at com.liferay.portlet.MimeResponseImpl.setContentType(MimeResponseImpl.java:162) I have checked Liferays source code, and it checks that contentType that its being set is in a harcoded list,if it not it will throw a IllegalArgumentException that it is exactly what os happening. This is my view resolver code: <bean id="xmlFileViewResolver" class="org.springframework.web.servlet.view.XmlViewResolver"> /WEB-INF/context/views.xml 1 My views.xml code: <beans> <bean name="jsonView" class="org.springframework.web.servlet.view.json.JsonView"/> And my controller: @SuppressWarnings("unchecked") @Override public ModelAndView handleRenderRequest(RenderRequest arg0, RenderResponse arg1) throws Exception { Map model = new HashMap(); model.put("firstname", "Peter"); model.put("secondname", "Schmitt"); return new ModelAndView("jsonView", model); } Any ideas?

    Read the article

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >