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  • SQL server - climb up in the tree structure

    - by Vytas999
    Hello. I have some sql table, named Object, which saves tree data in fields ObjectID, ParentID, and others. I have implemented recurse procedure, which select everything down by objectID from tree, like this: 1. 1.1. 1.2. 1.2.1. ... Now o need to "Climb up" - by some ObjectID i need to select everything Up, like this: 1.2.1. 1.2. 1. How i can do that? In example, my "down" procedure looks like: ALTER PROCEDURE [dbo].[Object_SelectDownByRoot_Simple] @ObjectID int AS WITH tree (ObjectID, ParentID, ObjectName, ObjectCode) AS ( SELECT ObjectID, ParentID, ObjectName, ObjectCode FROM dbo.[ObjectQ] ofs WHERE( ObjectID = @ObjectID ) UNION ALL SELECT ofs.ObjectID, ofs.ParentID, ofs.ObjectName, ofs.ObjectCode FROM dbo.[ObjectQ] ofs JOIN tree ON tree.ObjectID = ofs.ParentID ) SELECT ObjectID, ParentID, ObjectName, ObjectCode FROM tree

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  • how do i supply data to my gwt tree

    - by molleman
    Hello, So i need to create a tree with tree items for my gwt project. i am using the composite pattern to store all the information i need to be placed within a tree. A User has a root Folder that extends Hierarchy, this root Folder then has a list of Hierarchy objects, that can be FileLocations or Folders. Trouble i am having is building my tree based on this pattern. this data is all stored using hibernate in a mysql database How would i be able to implement this as a tree in gwt. Also the tree item that i create would have to reference back to the object so i can rename or move it.

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  • On Windows 7, dir or tree can't show unicode characters, even starting cmd with cmd /U

    - by ????
    On Windows 7, dir or tree can't show unicode characters, even starting cmd with cmd /U So I would press Window Key + R to run something, and type in cmd /U so that the content might handle Unicode. And then using dir or tree /F, the content in Unicode won't show as Unicode. (in Window Explorer (file manager), the Unicode will show) Is there a way to handle it? To get Unicode characters to test your filenames, you can go to http://news.google.com/news?edchanged=1&ned=tw and you will be able to get many Unicode characters there (UTF-8)

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  • Pure functional bottom up tree algorithm

    - by Axel Gneiting
    Say I wanted to write an algorithm working on an immutable tree data structure that has a list of leaves as its input. It needs to return a new tree with changes made to the old tree going upwards from those leaves. My problem is that there seems to be no way to do this purely functional without reconstructing the entire tree checking at leaves if they are in the list, because you always need to return a complete new tree as the result of an operation and you can't mutate the existing tree. Is this a basic problem in functional programming that only can be avoided by using a better suited algorithm or am I missing something?

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  • Correcting tree from messed up file tree in NTFS partition

    - by Fullmooninu
    It's a real messed situation, but I'm quite at the end of my options. It's my personal hardrive, so it's very important for me, and yes, I have no backup =( The short story: 1) I have two discs. One with Windows, and another where I had a bit of empty space at the front of the disk, so i could install Linux. The rest was occupied by a 1.8TB NTFS partition filled with data. 2) I installed Linux, and after a while realized there was not enough space for everything, so I tried using Gparted, and told it to re-size the NTFS partition, to a lesser size. 3) The system jammed. I had to reboot and broke the Resizing operation. Here's what I did to fix it: a) Rebooted into Linux Live, and used Testdisk,to deep analyze the disk, and recover the possible partitions. It found several versions of the NTFS partitions, probably made during the resizing. I told Testdisk to open every one of them, and only one could list its files. When trying to open the other options on Testdisk, it showed an error message. I assumed the one without errors, to be the correct one, and I told Testdisk to recover the partition, and write a new MBR. b) The partition had errors, and Linux has a NTFS fixing tool, used it, but the system still had errors. c) So I booted into windows and use chkdsk to correct all errors in the partition. d) Everything seems fine, but now, back in Windows, when I open one file, it opens another file, or part of another file. As in, some files took up the position of other files. What I think happened is that I recovered an old tree, and not the most current one. And that one just happened to be intact, while the most recent one was damaged. As such, the files that were moved during the failed resizing, were now, during the automatic correction, assumed wrongly to be in their correct places. So when I open a file, it tries to open another one. Radiohead - Creep.mp3 will open and it will actually be a bit from another song, or even code from a jpg. Some files seem to be all right, but others have seemed to have had their position taken by others. Anyone knows of something really powerful that can help me solve this?

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  • Array "tree" creation from db table

    - by Tural Teyyuboglu
    Trying to create array tree for db driven navigation. Getting following errur: array_key_exists() expects exactly 2 parameters, 1 given on line if (!array_key_exists($tree[$parent]['children'][$id])) Function looks like that $tree = array(); $sql = "SELECT id, parent, name FROM menu WHERE parent ... etc.... "; $results = mysql_query($sql) or die(mysql_error()); while(list($id, $parent, $name) = mysql_fetch_assoc($results)) { $tree[$id] = array('name' => $name, 'children' => array(), 'parent' => $parent); if (!array_key_exists($tree[$parent]['children'][$id])) { $tree[$parent]['children'][$id] = $id; } } Db structure How can I fix that? Whats wrong in this function?

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  • Most efficient Implementation a Tree in C++

    - by Topo
    I need to write a tree where each element may have any number of child elements, and because of this each branch of the tree may have any length. The tree is only going to receive elements at first and then it is going to use exclusively for iterating though it's branches in no specific order. The tree will have several million elements and must be fast but also memory efficient. My plan makes a node class to store the elements and the pointers to its children. When the tree is fully constructed, it would be transformed it to an array or something faster and if possible, loaded to the processor's cache. Construction and the search on the tree are two different problems. Can I focus on how to solve each problem on the best way individually? The construction of has to be as fast as possible but it can use memory as it pleases. Then the transformation into a format that give us speed when iterating the tree's branches. This should preferably be an array to avoid going back and forth from RAM to cache in each element of the tree. So the real question is which is the structure to implement a tree to maximize insert speed, how can I transform it to a structure that gives me the best speed and memory?

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  • Counting leaf nodes in hierarchical tree

    - by timn
    This code fills a tree with values based their depths. But when traversing the tree, I cannot manage to determine the actual number of children. node-cnt is always 0. I've already tried node-parent-cnt but that gives me lots of warnings in Valgrind. Anyway, is the tree type I've chosen even appropriate for my purpose? #include <string.h> #include <stdio.h> #include <stdlib.h> #ifndef NULL #define NULL ((void *) 0) #endif // ---- typedef struct _Tree_Node { // data ptr void *p; // number of nodes int cnt; struct _Tree_Node *nodes; // parent nodes struct _Tree_Node *parent; } Tree_Node; typedef struct { Tree_Node root; } Tree; void Tree_Init(Tree *this) { this->root.p = NULL; this->root.cnt = 0; this->root.nodes = NULL; this->root.parent = NULL; } Tree_Node* Tree_AddNode(Tree_Node *node) { if (node->cnt == 0) { node->nodes = malloc(sizeof(Tree_Node)); } else { node->nodes = realloc( node->nodes, (node->cnt + 1) * sizeof(Tree_Node) ); } Tree_Node *res = &node->nodes[node->cnt]; res->p = NULL; res->cnt = 0; res->nodes = NULL; res->parent = node; node->cnt++; return res; } // ---- void handleNode(Tree_Node *node, int depth) { int j = depth; printf("\n"); while (j--) { printf(" "); } printf("depth=%d ", depth); if (node->p == NULL) { goto out; } printf("value=%s cnt=%d", node->p, node->cnt); out: for (int i = 0; i < node->cnt; i++) { handleNode(&node->nodes[i], depth + 1); } } Tree tree; int curdepth; Tree_Node *curnode; void add(int depth, char *s) { printf("%s: depth (%d) > curdepth (%d): %d\n", s, depth, curdepth, depth > curdepth); if (depth > curdepth) { curnode = Tree_AddNode(curnode); Tree_Node *node = Tree_AddNode(curnode); node->p = malloc(strlen(s)); memcpy(node->p, s, strlen(s)); curdepth++; } else { while (curdepth - depth > 0) { if (curnode->parent == NULL) { printf("Illegal nesting\n"); return; } curnode = curnode->parent; curdepth--; } Tree_Node *node = Tree_AddNode(curnode); node->p = malloc(strlen(s)); memcpy(node->p, s, strlen(s)); } } void main(void) { Tree_Init(&tree); curnode = &tree.root; curdepth = 0; add(0, "1"); add(1, "1.1"); add(2, "1.1.1"); add(3, "1.1.1.1"); add(4, "1.1.1.1.1"); add(2, "1.1.2"); add(0, "2"); handleNode(&tree.root, 0); }

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  • Tab bar controller inside a navigation controller, or sharing a navigation root view

    - by Daniel Dickison
    I'm trying to implement a UI structured like in the Tweetie app, which behaves as so: the top-level view controller seems to be a navigation controller, whose root view is an "Accounts" table view. If you click on any account, it goes to the second level, which has a tab bar across the bottom. Each tab item shows a different list and lets you drill down further (the subsequent levels don't show the tab bar). So, this seems like the implementation hierarchy is: UINavigationController Accounts: UITableViewController UITabBarController Tweets: UITableViewController Detail view of a tweet/user/etc Replies: UITableViewController ... This seems to work[^1], but appears to be unsupported according to the SDK documentation for -pushViewController:animated: (emphasis added): viewController: The view controller that is pushed onto the stack. It cannot be an instance of tab bar controller. I would like to avoid private APIs and the like, but I'm not sure why this usage is explicitly prohibited even when it seems to work fine. Anyone know the reason? I've thought about putting the tab bar controller as the main controller, with each of the tabs containing separate navigation controllers. The problem with this is that each nav controller needs to share a single root view controller (namely the "Accounts" table in Tweetie) -- this doesn't seem to work: pushing the table controller to a second nav controller seems to remove it from the first. Not to mention all the book-keeping when selecting a different account would probably be a pain. How should I implement this the Right Way? [^1]: The tab bar controller needs to be subclassed so that the tab bar controller's navigation item at that level stays in sync with the selected tab's navigation item, and the individual tab's table controller's need to push their respective detail views to self.tabBarController.navigationController instead of self.navigationController.

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  • Updating a Minimum spanning tree when a new edge is inserted

    - by Lynette
    Hello, I've been presented the following problem in University: Let G = (V, E) be an (undirected) graph with costs ce = 0 on the edges e € E. Assume you are given a minimum-cost spanning tree T in G. Now assume that a new edge is added to G, connecting two nodes v, tv € V with cost c. a) Give an efficient algorithm to test if T remains the minimum-cost spanning tree with the new edge added to G (but not to the tree T). Make your algorithm run in time O(|E|). Can you do it in O(|V|) time? Please note any assumptions you make about what data structure is used to represent the tree T and the graph G. b)Suppose T is no longer the minimum-cost spanning tree. Give a linear-time algorithm (time O(|E|)) to update the tree T to the new minimum-cost spanning tree. This is the solution I found: Let e1=(a,b) the new edge added Find in T the shortest path from a to b (BFS) if e1 is the most expensive edge in the cycle then T remains the MST else T is not the MST It seems to work but i can easily make this run in O(|V|) time, while the problem asks O(|E|) time. Am i missing something? By the way we are authorized to ask for help from anyone so I'm not cheating :D Thanks in advance

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  • Display a tree dijit using zend framework

    - by churris43
    I am trying to display a tree of categories and subcategories by using dijits with zend framework. Haven't been able to find a good example. This is what I've got: Basically I got the following code as my action: class SubcategoriesController extends Zend_Controller_Action{ ..... public function loadtreeAction() { Zend_Dojo::enableView($this->view); Zend_Layout::getMvcInstance()->disableLayout(); //Creating a sample tree of categories and subcategories $a["cat1"]["id"] = "id1"; $a["cat1"]["name"] = "Category1"; $a["cat1"]["type"] = "category"; $subcat1 = array("id" => "Subcat1","name" => "Subcategory1" , "type" => "subcategory"); $subcat2 = array("id" => "Subcat12","name" => "Subcategory12" , "type" => "subcategory"); $a["cat1"]["children"] = array($subcat1,$subcat2); $treeObj = new Zend_Dojo_Data('id', $a); $treeObj->setLabel('name'); $this->view->tree = $treeObj->toJson(); } .... } And on my view: <?php $this->dojo()->requireModule('dojo.data.ItemFileReadStore'); $this->dojo()->requireModule('dijit.Tree'); $this->dojo()->requireModule('dojo.parser'); ?> <div dojoType="dojo.data.ItemFileReadStore" url="/Subcategories/loadtree" jsId="store"></div> <div dojoType="dijit.tree.ForestStoreModel" jsId="treeModel" store="store" rootId="root" rootLabel="List of Categories" childrenAttrs="children" query="{type:'category'}"></div> <div dojoType="dijit.Tree" model="treeModel" labelAttrs="ListOfCategories"></div> It doesn't even seem to try to load the tree at all. Any help is appreciated

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  • Reduced Tree View in NetBeans IDE 7.2

    - by Geertjan
    Right-click within the Projects window in NetBeans IDE 7.2 and from the "View Java Packages As" menu, you can now choose "Reduced Tree".I never really understood the difference between "Reduced Tree" and the already existing "Tree". But it makes sense when you see it. Here's Reduced Tree view: And here's Tree view, where you can see that the "actions" and "nodes" packages above each have their own top level package nodes, which takes up more space than the above: What's cool is that your selected package view is persisted across restarts of the IDE. To be complete, here's the List view, which is the third option you have in the "View Java Packages As" menu: Seems to me like the new Reduced Tree view combines the best of the Tree view with the best of the List view! Related issue: http://netbeans.org/bugzilla/show_bug.cgi?id=53192

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  • Silverlight Navigation Menu

    - by Justin
    I am using the Silverlight Business Application Template. The navigation consists of a few HyperlinkButtons in a StackPanel. I would like to create a more robust navigation menu (multilevel) with dropdowns and such. Telerik has one for silverlight (http://demos.telerik.com/silverlight/#Menu/FirstLook) I don't want to use Telerik control because its too expensive and I have tons of problems with Telerik. I've Googled it but including "Navigation" in my search seems to only include results about the navigation framework. Anyway, anyone have a good example?

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  • Sharepoint create site navigation through programming

    - by Sachin
    Hi All, I have a requirement in sharepoint where I want to Create the top link navigation based on excel file. Means The site navigation structure (along with parent site subsite under parent site) is mention in excel file. I need to read that structure and based on modify the navigation in sharepoint. Please can any one tell me is it possible to configure navigation in such a way. If yes then please tell me how to achive it. FYI: I am using MOSS 2007. thanks in advance sachin katkar

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  • JSF Navigation issue Facelets and Beans

    - by ortho
    Hi, I have an issue with navigation in my simple jsf system. I have MainBean that has two methods: public String register() and public String login(). I have played with faces-config.xml for several hours and I feel like I miss something very important because I think like I have tried all simple solutions so far :). I have added the mysql connector (jdbc) to Tomcat's lib folder and I am able to register the table to mySQL databse. It even allows my users to log in to the page. The only problem is that I can't use navigation in any other page than login.xhtml. Seems like navigation is only active on this one. I tried to use * but is no joy. I am sure that there is a simple fix for that and someone will come up with correct solution soon. Let's skip all the mysql part and try to fix the navigation issue please. faces-config.xml: http://java.sun.com/xml/ns/javaee/web-facesconfig_1_2.xsd" version="1.2" com.sun.facelets.FaceletViewHandler mainBean dk.itu.beans.MainBean session registerBean dk.itu.beans.RegisterBean session /login.xhtml success /welcome.xhtml failure /login_failed.xhtml sign /register.xhtml /login_failed.xhtml back /login.xhtml Here the last navigation-rule from login_failed.xhtml does not work at all. login.xhtml (which is the main - starting view): login_failed.xhtml: Here I tried many options. I used action="#{mainBean.register})" method that returns "sign" string and none of these worked. There is one more file (not specified in faces-config.xml file, because did not work either - but going from login.xhtml by button works fine. I tried to manage navigation from login_failed.xhtml first, then I will apply the same rool for registration to come back to login page when customer registers his nick name). register.xhtml: Basicaly mainBean.register now calls the database and returns string, but obviously it doesn't navigate to any view (but gives an entry to database). I believe it is simple fix for most of the experienced web developers and any help will be greately appreciated. I use eclipse, tomcat 6 and Widows Vista if that helps :) Thank you in advance. Kindest regards.

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  • Best solution for managing navigation (and marking currently active item) in CakePHP

    - by Nathan
    So I have been looking around for a couple hours for a solid solution to handling site navigation in CakePHP. Over the course of a dozen projects, I have rigged together something that works for each one, but what I'm looking for is ideally a CakePHP plugin that handles the following: Navigation Model Component for handing off to the view Element View Helper for displaying the navigation (with control over sublevels displayed and automatically determining the "active" item based on URL and/or controller/model/slug Admin pages for managing a tree of navigation Any suggestions for an all-in-one solution or even the individual components would be very appreciated! Or even suggestions on how you have handled it in the past

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  • check if a tree is a binary search tree

    - by TimeToCodeTheRoad
    I have written the following code to check if a tree is a Binary search tree. Please help me check the code: Pair p{ boolean isTrue; int min; int max; } public boo lean isBst(BNode v){ return isBST1(v).isTrue; } public Pair isBST1(BNode v){ if(v==null) return new Pair(true, INTEGER.MIN,INTEGER.MAX); if(v.left==null && v.right==null) return new Pair(true, v.data, v.data); Pair pLeft=isBST1(v.left); Pair pRight=isBST1(v.right); boolean check=pLeft.max<v.data && v.data<= pRight.min; Pair p=new Pair(); p.isTrue=check&&pLeft.isTrue&&pRight.isTrue; p.min=pLeft.min; p.max=pRight.max; return p; } Note: This function checks if a tree is a binary search tree

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  • how does NTFS actually work with B-tree ?

    - by bakra
    To improve performance, NTFS directories use a special data management structure called a B-tree. "B-tree" concept here refers to a "tree of storage units" that hold the contents of an individual directory. What I don't understand is where on the disk is this tree stored? Its surely not created every-time we reboot...that would take lots of time. and since its a tree(dynamic Data structure) unlike arrays it will grow. so space needs to be allocated every-time it grows. so how is this "dynamic meta-data" stored ?

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  • Accessing selected node of richfaces tree from Javascript

    - by kazanaki
    Hello This should be a very simple question. I have a richfaces tree that is rendered using JSF. When the user clicks on a node I want a javascript function to run. Nothing more nothing less. No redirects, no re-submit, no-rerender, no Ajax. Just plain old Javascript. I have seen the onselected attribute of the tree and it indeed fires a Javascript method. But of course I want to know which node was clicked. Here is what I have so far <head> <script type="text/javascript"> function documentClicked(nodeRef) { alert("Node is "+nodeRef); } </script> </head> <rich:tree switchType="client" value="#{ajaxDocumentTree.rootNode}" var="document" onselected="documentClicked()" > <rich:treeNode iconLeaf="../images/tree/doc.gif" icon="../images/tree/doc.gif"> <h:outputText value="#{doc.friendlyName}" /> </rich:treeNode> But this does not work because nodeRef is undefined. I expected that the first argument of the callback would be the selected node but this is not the case. So the question is this: How do I fire a Javascript function with the selected node from a richfaces tree?

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  • JQGrid tree - passing additional parameters when tree is expanded

    - by PHP thinker
    I have a JQGRid tree. It loads data click by click, not all at once. Typically, JQGRid passes 4 standard tree parameters with each call - row (level, parent, is leaf, is expanded). How can I pass more parameters that I will take from the row being expanded? E.g. data from Name column should be passed in AJAX call too. There doesn't seem to be OnExpand event or similar.

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  • Implementing an automatic navigation mesh generation for 2d top down map?

    - by J2V
    I am currently in the middle of implementing an A* pathfinding for enemies. In order to implement the actual A* logic, I need a navigation mesh for my map. I am working on a 2D top down rpg map. The world is static, meaning there is no requirement for dynamic runtime mesh generation. My world objects are pixel based, not tile based and have associated data with them such as scale, rotation, origin etc. I will obviously need some vertex data being generated from my world objects, maybe create a polygon generation from color data? I could create a colormap with objects for my whole map, but I have no idea how to begin creating nav mesh polygons. How would an actual navigation mesh generation look like with this kind of available information? Can anyone maybe point to some great resources? I have looked into some 3D nav mesh tools, but they seem kind of overly complex for my situation and also have a lot of their req data available from models. Thanks a lot in advance! I have been trying to get my head around it for some time now.

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  • SL 3 navigation not working!

    - by Silver Gun
    Hey Guys I converted all my existing Silverlight app UserControls to Pages so I could use the Navigation Framework. Anyway so I created a UserControl called MyFrame, which would host all the pages. In my App.xaml.cs I have the following to make sure that MyFrame is loaded when the App loads: private void Application_Startup(object sender, StartupEventArgs e) { this.RootVisual = new MyFrame(); } My UriMapper class resides in App.xaml and looks like the following: <navcore:UriMapper x:Key="uriMapper"> <navcore:UriMapping Uri="Login" MappedUri="Login.xaml"> </navcore:UriMapper> Within my 'MyFrame' class, I have the following <StackPanel Orientation="Horizontal"> <StackPanel Orientation="Vertical"> <HyperlinkButton Tag="Login" Content="Login" Click="HyperlinkButton_Click" /> </StackPanel> <StackPanel Orientation="Vertical"> <navigation:Frame x:Name="ContentFrame" Style="{StaticResource ContentFrameStyle}" /> </StackPanel> </StackPanel> And within the callback for my HyperlinkButton's event handler, I have the following: private void HyperlinkButton_Click(object sender, RoutedEventArgs e) { ContentFrame.Navigate(new Uri((sender as HyperlinkButton).Tag.ToString(), UriKind.Relative)); } The Login.xaml file is in my root folder (right under Project). This navigation does not seem to work! The exception I get reads like so: Navigation is only supported to relative URIs that are fragments, or begin with '/', or which contain ';component/'. Parameter name: uri The Login page does not load. There is no problem with Login.xaml as when I set this.RootVisual = new Login(); the page loads just fine. I also tried setting the NavigateUri attribute of the HyperlinkButton to "Login." No cigar. I'll appreciate any help! Thanks a lot in advance

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  • Android - Temporal & Ancestral Navigation with ViewPager & Fragments

    - by rascuache
    I'm trying to work out the best way to implement the 'ancestral' and 'temporal' navigation (utilising the up button and back buttons), for a music player I'm working on. Currently, the user is presented with a viewpager, and can page between three main fragments (ArtistMain, AlbumMain and SongMain). Upon choosing an item inside that view, a fragment transaction occurs, and the viewpager goes out of view, replaced by a new fragment (AlbumSub, Songsub or player, depending on where the user came from). The user can then navigate deeper, until a song is chosen, and then they are taken to the 'player' screen. I guess the question is: How do I implement all of this conditional navigation? I'm fairly new to android and programming in general, and I just can't seem to come up with an efficient way to achieve this. At the moment, as each fragment is brought into view, the app is checking to see where the user just came from, and then determines where the user should be taken if back or home is called. This means I have a booleans like "fromArtistMain", "fromAlbumSub", and I'm checking for things like "fromSongSub && fromPlayer".. it's all turning into a bit of a mess. I've drawn a diagram (in paint, sorry!!), to depict the navigation I'm trying to achieve. The yellow represents the 'up' button press, the red is the 'back' button press, and blue is just normal navigation. The green arrows are meant to represent the view paging: Any advice is welcome. It might take something really simple that I've just overlooked. Thanks for your time.

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