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  • PHP upload to GoDaddy hosted site

    - by 105894384987190582154
    Hi, relatively new to both hosting and PHP, so apologies for (probably) missing the obvious, but… I built a page which would allow file uploads to my site, following the example laid out here: W3Schools PHP upload exercise Through the File Manage on my Godaddy hosting, I created a folder named ’upload’ so that the file would land there after being uploaded through the page I had built. Part of the returned page that appears after submitted the file reads: Temp file: d:temptmpphpE4C9.tmp Stored in: upload/testfile.txt which would indicate that the file has been sucesscully uploaded given the code in the example. However, I cannot see the file in the ’upload’ folder via my File Manage, or anywhere else on the hosting of my site (as far as I can see). I also cannot see the ’temp’ folder anywhere either… Any help or clarification would be greatly appreciated. Thanks Tim

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  • Django Show M2M field in both model forms

    - by John
    Hi I am using the forms.ModelForm to create my form. I want to be able to show the manytomany field in both model forms, how do I do this? If the manytomany relationship is defined in the model it is fine and just appears but if it is not in the model (but is still linked via the other model) it does not appear. Hope this makes sense. How can I make it show up? Thanks

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  • Django: Proper place to unregister ModelAdmins

    - by lazerscience
    Sometimes I need to UNREGISTER some ModelAdmins from the admin site, because I don't want them to be there as they are, eg. if I'm using the Sites framework, and I dont want it to appear in the admin. It's no big deal to e.g. call admin.site.unregister(Site) to do so. In most cases I put it in admin.py of some related app that I have made, but sometimes I end up putting it in a place that hasn't much to do with the original app; another possibility would be making a "dummy app" and put it there... Does anybody know a more descent place where these calls can live?

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  • Django: How/Where to store a value for a session without unnecessary DB hits

    - by GerardJP
    Hi all, I have an extended userprofile with AUTH_PROFILE_MODULE (ref: http://tinyurl.com/yhracqq) I would like to set a user.is_guru() method similar to user.is_active(). This would results for al views (or rather templates) to e.g. disable/enable certain user messages, displaying of widgets, etc. The boolean is stored in the extended user profile model, but I want to avoid hitting the DB for every view. So the questions is .. Do I use a context_processor, a template tag, session_dict or what have you to, possible cached, store this info for the duration of the users visit. Note: I dont have performance issues, so it's definitely filed under premature optimization. I just want to avoid generating extra work in the future :). Any pointers are very welcome. Thanx and greetz! Gerard.

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  • Django: Template should render 'description' not actual value

    - by Till Backhaus
    Hi, in a Model I have a CharField with choices: class MyModel(models.Model): THE_CHOICES=( ('val',_(u'Value Description')), ) ... myfield=models.CharField(max_length=3,choices=THE_CHOICES Now in the template I access an instance of MyModel: {{ my_instance.myfield }} Of course the gives me val instead of Value Description. How do I get the description? Thanks in advance!

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  • Django updating a single model

    - by Hellnar
    Hello How can I use the update() method on a single model which I retrieved via Queryset.get() ? It seems like model. Model doesn't have an update() method yet I cannot invoke .save() as I have a pre-save signals which messes things up. EDIT: An idea would be passing some parameter to the save method and catching it at the pre_save signal, so that I can understand the purpose, how can this be done ? Thanks

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  • Django Getting RequestContext in custom tag

    - by greggory.hz
    I'm trying to create a custom tag. Inside this custom tag, I want to be able to have some logic that checks if the user is logged in, and then have the tag rendered accordingly. This is what I have: class UserActionNode(template.Node): def __init__(self): pass def render(self, context): if context.user.is_authenticated(): return render_to_string('layout_elements/sign_in_register.html'); else: return render_to_string('layout_elements/logout_settings.html'); def user_actions(parser, test): return UserActionNode() register.tag('user_actions', user_actions) When I run this, I get this error: Caught AttributeError while rendering: 'Context' object has no attribute 'user' The view that renders this looks like this: return render_to_response('start/home.html', {}, context_instance=RequestContext(request)) Why doesn't the tag get a RequestContext object instead of the Context object? How can I get the tag to receive the RequestContext instead of the Context? EDIT: Whether or not it's possible to get a RequestContext inside a custom tag, I'd still be interested to know the "correct" or best way to determine a user's authentication state from within the custom tag. If that's not possible, then perhaps that kind of logic belongs elsewhere? Where?

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  • Django Form field initial value on failed validation

    - by John
    Hi, how do I set the value of a field element after a form has been submitted but has failed validation? e.g. if form.is_valid(): form.save() else: form.data['my_field'] = 'some different data' I don't really want to put it in the view though and would rather have it as part of the form class. Thanks

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  • django updating m2m field

    - by Marconi
    I have a model service and a ModelForm named Service which I use to add and update the service model. The model looks like this: class Service(models.Model): categories = models.ManyToManyField(Category) The categories field is displayed as a tag with that allows multiple selection. It works well when I'm adding a new record but when I'm updating it, only one service is showing up on the request.POST['categories'] even if I selected multiple categories. I tried dumping the request object and I can see that the categories is showing something like: u'categories': [u'3', u'4', u'2'] I tried calling the request._get_post() and it did return only 1 category, hence the request.POST['categories'] returns only 1. Anybody who knows what's happening and how to fix it?

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  • Django ModelAdmin.save_model() -vs- ModelAdmin.save_formset()

    - by anonymous coward
    I want to ensure that a user editing a particular model is saved in that models updated_by (FK User) field. I'm using mostly ModelForms (not necessarily the built in Admin), and wondering: In what cases would I need to override ModelAdmin.save_model() or ModelAdmin.save_formset()? Or, is that doing it wrong? If it's just the models' save() method that needs to be overridden, is there a proper way to access the request object there?

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  • How can I disable a model field in a django form

    - by jammon
    I have a model like this: class MyModel(models.Model): REGULAR = 1 PREMIUM = 2 STATUS_CHOICES = ((REGULAR, "regular"), (PREMIUM, "premium")) name = models.CharField(max_length=30) status = models.IntegerField(choices = STATUS_CHOICES, default = REGULAR) class MyForm(forms.ModelForm): class Meta: model = models.MyModel In a view I initialize one field and try to make it non-editable: myform = MyForm(initial = {'status': requested_status}) myform.fields['status'].editable = False But the user can still change that field. What's the real way to accomplish what I'm after?

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  • Uploading File Problem in PHP on Drupal

    - by Nitz
    I don't know why but i had written clear cut code for uploading file in my page. i had written like this... on the client side. <form id="recipeform" onsubmit="return checkAll()" action="submit.php" method="post" class="niceform" enctype="multipart/form-data"> <input name="uploaded" type="file" /> And on submit.php... i am writting like this..... $target = "newupload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)){ echo "The file ". basename( $_FILES['uploaded']['name']). " has been uploaded"; } else{ echo "Sorry, there was a problem uploading your file."; } simple code but then also i can't able to upload the file.. And i had made my webiste in Drupal. Thanks in advance. www.panchjanyacorp.com

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  • How to properly set path to media files in Django

    - by sasquatch90
    Hello. I've got a new project, and currently I'm trying to set it correctly. But somehow I can't make my media files work. Here's my current setting : MEDIA_ROOT = os.path.normpath( '/home/budzyk/rails/fandrive/site_media/' ) templates setting work on the other hand : TEMPLATE_DIRS = ( "/home/budzyk/rails/fandrive/templates", ) Catalog with media files is ../fandrive/site-media/ so why it's not working ? Here's my base.html template with styles imported, and firebug window when my page is loaded : <head> <title>{% block title %}{% endblock %}</title> <meta http-equiv="Content-type" content="text/html;charset=UTF-8" /> <link rel="stylesheet" type="text/css" href="{{ MEDIA_URL }}css/style.css" /> {% block pagecss %}{% endblock %} <script type="text/javascript" src="{{ MEDIA_URL }}jquery/jquery-1.4.2.min.js"></script> </head> <body> <div id="wrapper"> http://img237.imageshack.us/img237/4909/21205809.jpg

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  • Function pointers in javascript using django

    - by Hulk
    Is this a valid function pointer code below, In views , def change(request): dict={} function_ptr="create()" dict.update({'function_ptr' : function_ptr}) return render_to_response('mpjt/create.html',context_instance=RequestContext(request,{'dict': dict})) In create.html $(document).ready(function() { var a = '{{dict.function_ptr}}' func_ptr(a); function create() { alert('got respponse'); } }); Thanks..

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  • Updating several records at once using Django

    - by 47
    I want to create a list of records with checkboxes on the left side....kinda like the inbox in Gmail. Then if a user selects some or all of these checkboxes, then the selected record(s) can be updated (only one field will be updated BTW), possibly by clicking a button. I'm stuck on how to do this though....ideas?

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  • photo upload with codeigniter

    I know there are many tutorials online, but I could not make them work :( maybe something particularly wrong with my system :/ My Controller localpath is: /localhost/rl/applications/backend/controller/ Controller: function do_upload() { $config['upload_path'] = './uploads/'; $config['allowed_types'] = 'gif|jpg|png'; $config['max_size'] = '100'; $config['max_width'] = '1024'; $config['max_height'] = '768'; $this->load->library('upload', $config); if ( ! $this->upload->do_upload()) { $error = array('error' => $this->upload->display_errors()); $this->load->view('add_image', $error); } else { $data = array('upload_data' => $this->upload->data()); $data['id'] = $this->input->post['id_work']; $this->load->view('add_image', $data); } } My View localpath is: /localhost/rl/applications/backend/view/ View: echo form_open_multipart('do_upload'); <ul class="frm"> <li><label>File: *</label><input type="file" name="userfile" class="frmlmnt" size="50" /></li> <li><label></label><input type="submit" class="btn" value="Upload" /></li> </ul> </form> Maybe I do something wrong with path

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  • Generating all possible subsets of a given QuerySet in Django

    - by Glen
    This is just an example, but given the following model: class Foo(models.model): bar = models.IntegerField() def __str__(self): return str(self.bar) def __unicode__(self): return str(self.bar) And the following QuerySet object: foobar = Foo.objects.filter(bar__lt=20).distinct() (meaning, a set of unique Foo models with bar <= 20), how can I generate all possible subsets of foobar? Ideally, I'd like to further limit the subsets so that, for each subset x of foobar, the sum of all f.bar in x (where f is a model of type Foo) is between some maximum and minimum value. So, for example, given the following instance of foobar: >> print foobar [<Foo: 5>, <Foo: 10>, <Foo: 15>] And min=5, max=25, I'd like to build an object (preferably a QuerySet, but possibly a list) that looks like this: [[<Foo: 5>], [<Foo: 10>], [<Foo: 15>], [<Foo: 5>, <Foo: 10>], [<Foo: 5>, <Foo: 15>], [<Foo: 10>, <Foo: 15>]] I've experimented with itertools but it doesn't seem particularly well-suited to my needs. I think this could be accomplished with a complex QuerySet but I'm not sure how to start.

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  • Django templatetag "order of processing"

    - by Jason Persampieri
    I am trying to write a set of template tags that allow you to easily specify js and css files from within the template files themselves. Something along the lines of {% requires global.css %}, and later in the request, {% get_required_css %}. I have this mostly working, but there are a couple of issues. We'll start with the 'timing' issues. Each template tag is made up of two steps, call/init and render. Every call/init happens before any render procedure is called. In order to guarantee that all of the files are queued before the {% get_required_css %} is rendered, I need to build my list of required files in the call/init procedures themselves. So, I need to collect all of the files into one bundle per request. The context dict is obviously the place for this, but unfortunately, the call/init doesn't have access to the context variable. Is this making sense? Anyone see a way around this (without resorting to a hack-y global request object)? Another possibility to store these in a local dict but they would still need to be tied to the request somehow... possibly some sort of {% start_requires %} tag? But I have no clue how to make that work either.

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  • Django admin default filter

    - by h3
    I know I already managed to do this but can't remember how nor I can't find any documentation about this.. How can apply a filter by default on a object list view in the admin ? I have an app which list quotes and those quotes have a status (ex: accepted, rejected, on hold ..). I want the filter set on status='accepted' by default that is..

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  • Crossed import in django

    - by Kuhtraphalji
    On example, i have 2 apps: alpha and beta in alpha/models.py import of model from beta.models and in beta/models.py import of model from alpha.models manage.py validate says that ImportError: cannot import name ModelName how to solve this problem?

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  • jQuery recursive function to upload many files while giving the user some feedback

    - by checcco
    Hi guys, I'm trying to write a jQuery function to let users upload many files at once. Here's the function I thought to give the user some feedback about the upload process progress. function uploadFiles(numbersOfFiles, start) { $("#info").html(start + " files uploaded"); $.post('upload.php', { start: start }, function (data) { start += 5; if (start < numbersOfFiles) { $("#info").html(start + " files uploaded"); uploadFiles(numbersOfFiles, start); } else { $("#info").html("All files have been uploaded"); } }); } The function calls a php script to upload 5 files, then if there are more files to upload it calls the script again. The whole process works. I've tried it with 100 files. The only thing that doesn't work is the #info div updating. The div get updated the first time and then again only to show "All files have been uploaded". So there's no feedback for the user about the uploading process. I can't understand why... Any help?

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  • Django ForeignKey _set on an inherited model

    - by neolaser
    I have two models Category and Entry. There is another model ExtEntry that inherits from Entry class Category(models.Model): title = models.CharField('title', max_length=255) description = models.TextField('description', blank=True) ... class Entry(models.Model): title = models.CharField('title', max_length=255) categories = models.ManyToManyField(Category) ... class ExtEntry(Entry): groups= models.CharField('title', max_length=255) value= models.CharField('title', max_length=255) ... I am able to use the Category.entry_set but I want to be able to do Category.blogentry_set but it is not available. If this is not available,then I need another method to get all ExtEntryrelated to one particular Category Thanks

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  • Django Custom Admin

    - by Harry
    Hello there Currently I have an app with a save method in its models.py . So I would like to change this so the models does not do the save() method, but rather have a separate view that will do this in die admin site. Can you please direct me in the correct direction? Thank you

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