Search Results

Search found 25171 results on 1007 pages for 'number recognition'.

Page 40/1007 | < Previous Page | 36 37 38 39 40 41 42 43 44 45 46 47  | Next Page >

  • Excel plugin: Finding a Chart's Source Data Number Format String

    - by Jack
    I'm currently working on a plugin for excel (using VB.net--not VBA) that will attempt (among other things) to recognize the format of the source data of a chart and configure the chart's series' number format strings appropriately. That is, yearly data should always be two numbers, monthly data should always be a 3-letter month followed by a 2-digit year, etc. The goal is to have a uniform representation across all charts for monthly data, annual data, daily data, etc. My question is this: how do I find the number format string for the cells (or any cell that is part of that series, as I will be assuming all cells that make up a particular series have the same format) that represent the source data for the chart? Note: I can assume that the chart will always point to a range of cells (not, for example, an array of data).

    Read the article

  • Given a number N, find the number of ways to write it as a sum of two or more consecutive integers

    - by hilal
    Here is the problem (Given a number N, find the number of ways to write it as a sum of two or more consecutive integers) and example 15 = 7+8, 1+2+3+4+5, 4+5+6 I solved with math like that : a + (a + 1) + (a + 2) + (a + 3) + ... + (a + k) = N (k + 1)*a + (1 + 2 + 3 + ... + k) = N (k + 1)a + k(k+1)/2 = N (k + 1)*(2*a + k)/2 = N Then check that if N divisible by (k+1) and (2*a+k) then I can find answer in O(N) time Here is my question how can you solve this by dynamic-programming ? and what is the complexity (O) ? P.S : excuse me, if it is a duplicate question. I searched but I can find

    Read the article

  • Random generates same number in java

    - by user1613360
    This is my java code. import java.io.*; import java.util.*; import java.util.concurrent.TimeUnit; class search { private int numelem; private int[] input=new int[100]; public void setNumofelem() { System.out.println("Enter the total numebr of elements"); Scanner yz=new Scanner(System.in); numelem=yz.nextInt(); } public void randomnumber() throws Exception { int max=500,min=1,n=numelem; Random rand = new Random(); for (int j=0;j < n;j++) { input[j]=rand.nextInt(max)+1; } } public void printinput() { int b=numelem,t=0; while(true) if(b!=0) { System.out.print(" "+input[t]); b--; t++; } else break; } } public class mycode { public static void main(String args[]) throws Exception { search a=new search(); a.setNumofelem(); a.randomnumber(); a.printinput(); } } Now the function randomnumber() just returns the same number.The function executes perfectly if I execute it as a separate java program but fails miserably if I call it using an object.I have also tried the following variations but nothing works everything return the same number. Variation 1: public void randomnumber() throws Exception { int max=500,min=1,n=numelem; Random rand = new Random(); for (int j=0;j < n;j++) { TimeUnit.SECONDS.sleep(1); input[j]=rand.nextInt(max)+1; } } Variation 2: public void randomnumber() throws Exception { int max=500,min=1,n=numelem; Random rand = new Random(); for (int j=0;j < n;j++) { rand.setSeed(System.nanoTime()); input[j]=rand.nextInt(max)+1; } } Variation 3: public void randomnumber() throws Exception { int max=500,min=1,n=numelem; Random rand = new Random(); for (int j=0;j < n;j++) { TimeUnit.SECONDS.sleep(1); rand.setSeed(System.nanoTime()); input[j]=rand.nextInt(max)+1; } } Sample input/Output: Enter the number of elements: 5 23 23 23 23 23 23

    Read the article

  • Find maximum number of logged on users in SQL

    - by lleto
    Hi, I want to keep tabs on the number of concurrent users of my application. I therefore log a time_start and a time_stop. If I now want to query the database for the maximum number of logged on users and return the start date, how would I do that. The table looks like this: id | time_start | time_stop ----+---------------------+--------------------- 1 | 2010-03-07 05:40:59 | 2010-03-07 05:41:33 2 | 2010-03-07 06:50:51 | 2010-03-07 10:50:51 3 | 2010-02-21 05:20:00 | 2010-03-07 12:23:44 4 | 2010-02-19 08:21:12 | 2010-03-07 12:37:28 5 | 2010-02-13 05:52:13 | Where time_stop is empty the user is still logged on. In this case I would expect to see 2010-03-07 returned, since all users (5) were logged on at that moment. However if I would run the query with 'where time_start BETWEEN '2010-02-17' AND '2010-02-23' I would expect to see 2010-02-21 with a maximum of 2. Is this possible direct in SQL (using postgres) or do I need to parse the results in PHP? Thanks, lleto

    Read the article

  • Validate decimal number in (known) national format

    - by Álvaro G. Vicario
    PHP has many built-in functions to validate numbers but they all expect input in computer format: 1234.56. I need to validate stuff like 1,234.56 (English) or 1.234,56 (Spanish), together with some typical attributes (accepted range, max number of decimals, etc.). I started writing my own function but I soon got lost. It's easy to read the user input into a float variable but I want to be able to detect numbers with invalid formats like 1,23456.7 or 1..25. Do you have any recommendation on the subject? (Decimal and thousand characters are known beforehand and it's okay to hard-code digit groups as three, there's no need to cover Indian number format.)

    Read the article

  • Why is the code adding 7 if the number is not >= 0

    - by Hugo Dozois
    I've got this program in MIPS assembly which comes from a C code that does the simple average of the eigth arguments of the function. average8: addu $4,$4,$5 addu $4,$4,$6 addu $4,$4,$7 lw $2,16($sp) #nop addu $4,$4,$2 lw $2,20($sp) #nop addu $4,$4,$2 lw $2,24($sp) #nop addu $4,$4,$2 lw $2,28($sp) #nop addu $2,$4,$2 bgez $2,$L2 addu $2,$2,7 $L2: sra $2,$2,3 j $31 When the number is positve, we directly divided by 8 (shift by 3 bits), but when the number is negative, we first addu 7 then do the division. My question is why do we add 7 to $2 when $2 is not >= 0 ? EDIT : Here is the C code : int average8(int x1, int x2, int x3, int x4, int x5, int x6, int x7, int x8) { return (x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8) / 8; } note : the possible loss in the division since we are using ints instead of floats or doubles is not important in this case.

    Read the article

  • How to use SQL trigger to record the affected column's row number

    - by Freeman
    I want to have an 'updateinfo' table in order to record every update/insert/delete operations on another table. In oracle I've written this: CREATE TABLE updateinfo ( rnumber NUMBER(10), tablename VARCHAR2(100 BYTE), action VARCHAR2(100 BYTE), UPDATE_DATE date ) DROP TRIGGER TRI_TABLE; CREATE OR REPLACE TRIGGER TRI_TABLE AFTER DELETE OR INSERT OR UPDATE ON demo REFERENCING NEW AS NEW OLD AS OLD FOR EACH ROW BEGIN if inserting then insert into updateinfo(rnumber,tablename,action,update_date ) values(rownum,'demo', 'insert',sysdate); elsif updating then insert into updateinfo(rnumber,tablename,action,update_date ) values(rownum,'demo', 'update',sysdate); elsif deleting then insert into updateinfo(rnumber,tablename,action,update_date ) values(rownum,'demo', 'delete',sysdate); end if; -- EXCEPTION -- WHEN OTHERS THEN -- Consider logging the error and then re-raise -- RAISE; END TRI_TABLE; but when checking updateinfo, all rnumber column is zero. is there anyway to retrieve the correct row number?

    Read the article

  • Number of times a file (e.g., PDF) was accessed on a server

    - by Ivan
    I have a small website with several PDFs free for download. I use StatCounter to observe the number of page loads. It also shows me the number of my PDF downloads, but it considers only those downloads where a user clicks on the link from my website. But what's with the "external" access to the PDFs (e.g., directly from Google search)? How I can count those? Is there any possibility to use a tool such as StatCounter? Thanks.

    Read the article

  • C++ arrays select square number and make new vector

    - by John Smith
    I have to see which of the following from a vector is a square number then make another vector with only the square numbers For example: (4,15,6,25,7,81) the second will be (4,25,81) 4,25,81 because 2x2=4 5x5=25 and 9x9=81 I started like this: { int A[100],n,r,i; cout<<"Number of elements="; cin>>n; for(i=1;i<=n;i++) { cout<<"A["<<i<<"]="; cin>>A[i]; } for(i=1;i<=n;i++) { r=sqrt(A[i]); if(r*r==A[i]) } return 0; } but I am not really sure how to continue

    Read the article

  • Javascript large number array compression

    - by gatapia
    Hi All, I've got a javascript application that sends a large amount of numerical data down the wire. This data is then stored in a database. I am having size issues (too much bandwidth, database getting too big). I am now ready to sacrifice some performance for compression. I was thinking of implementing a base 62 number.toString(62) and parseInt(compressed, 62). This would certainly reduce the size of the data but before I go ahead and do this I thought I would put it to the folks here as I know there must be some outside the box solution I have not considered. The basic specs are: - Compress large number arrays into strings for JSONP transfer (So I think UTF is out) - Be relatively fast, look I'm not expecting same performance as I have now but I also don't want gzip compression either. Any ideas would be greatly appreciated. Thanks Guido Tapia

    Read the article

  • How to count the number of listitems in an asp.bulletedlist with JavaScript

    - by Andy5
    Hi I have an asp:bulletedlist control, which sits inside a div tag, and I need to count the number of list items inside the control. Searching the internet, and noting the fact the html given back by the items is a list i.e. <li>, I thought I could use an example of: var listcontrol = document.getElementById('BulletedList1'); var countItems = listcontrol.getElementByTagName('li').length; However, when I do this, it throws and error saying that no object exists for this control. So, my problem is, and because I must do this clientside because I want to use this to set the height of the div tag, is how do you count the number of items inside a asp:bulletedlist control with javascript?

    Read the article

  • Pseudorandom Number Generation with Specific Non-Uniform Distributions

    - by carnun
    Hello all, I'm writing a program that simulates various random walks (with differing distributions). At each timestep, I need randomly generated, two dimensional step distances and angles from the distribution of the random walk. I'm hoping someone can check my understanding of how to generate these random numbers. As I understand it I can use Inverse Transform Sampling as follows: If f(x) is the pdf of our random walk that has a non-uniform distribution, and y is a random number from a uniform distribution. Then if we let f(x) = y and solve to find x then we have a random number from the non-uniform distribution. Is this a feasible solution?

    Read the article

  • Convert a number from string to integer without using inbuilt function

    - by Raja
    I am trying this technique but error is coming. Please help me to convert a number from string to integer. #include<iostream> using namespace std; int main() { char *buffer[80]; int a; cout<<"enter the number"; cin.get(buffer,79); char *ptr[80] = &buffer; while(*ptr!='\0') { a=(a*10)+(*ptr-48); } cout<<"the value"<<a; delete ptr[]; return 0; } Errors are: error C2440: 'initializing' : cannot convert from 'char ()[80]' to 'char *[80]' error C2440: '=' : cannot convert from 'char *' to 'int'

    Read the article

  • Print number series in java

    - by user1898282
    I have to print the series shown below in java: ***1*** **2*2** *3*3*3* 4*4*4*4 My current implementation is: public static void printSeries(int number,int numberOfCharsinEachLine){ String s="*"; for(int i=1;i<=number;i++){ int countOfs=(numberOfCharsinEachLine-(i)-(i-1))/2; if(countOfs<0){ System.out.println("Can't be done"); break; } for(int j=0;j<countOfs;j++){ System.out.print(s); } System.out.print(i); for(int k=1;k<i;k++){ System.out.print(s); System.out.print(i); } for(int j=0;j<countOfs;j++){ System.out.print(s); } System.out.println(); } } But there are lot of for loops, so I'm wondering whether this can be done in a better way or not?

    Read the article

  • Dividing a list in specific number of sublists

    - by Surya
    I want to divide a list in "a specific number of" sublists. That is, for example if I have a list List(34, 11, 23, 1, 9, 83, 5) and the number of sublists expected is 3 then I want List(List(34, 11), List(23, 1), List(9, 83, 5)). How do I go about doing this? I tried grouped but it doesn't seem to be doing what I want. PS: This is not a homework question. Kindly give a direct solution instead of some vague suggestions.

    Read the article

  • Special simple random number generator

    - by psihodelia
    How to create a function, which on every call generates a random integer number? This number must be most random as possible (according to uniform distribution). It is only allowed to use one static variable and at most 3 elementary steps, where each step consists of only one basic arithmetic operation of arity 1 or 2. Example: int myrandom(void){ static int x; x = some_step1; x = some_step2; x = some_step3; return x; } Basic arithmetic operations are +,-,%,and, not, xor, or, left shift, right shift, multiplication and division. Of course, no rand(), random() or similar staff is allowed.

    Read the article

  • MySql Query to return number of photos in each album

    - by GivenPie
    MY table is set up like this, all I need to do is call a query to my Photos table. I have PhotoID as the primary key and GalleryID as the foreign key to Gallery. How can I could the number of unique PhotoID's for each multiple GalleryIDs. So to speak there are may duplicate GalleryIDs because there are many photos in a gallery. So I just need to could the number of unique PhotoIDs associated with that GalleryID. Can it be done in one query?

    Read the article

< Previous Page | 36 37 38 39 40 41 42 43 44 45 46 47  | Next Page >