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  • jquery 'tablesorter' zebra widget do sort all column unnecessarily!

    - by I Like PHP
    i m using jQuery tablsorter plugin, it's working perfect,but now problem is ... i want to enable sorting only on 1'st and 3'rd column, and i also want to show different color of alternate row. i used widgets:[zebra], but using widget zebra, it enables sorting on all column as well as images(asc.gif,desc.gif,bg.gif) is also appearing on all headers whereas i only want these on only first and 3rd column how to use zebra widget with specific column sorting not the whole columns sorting here is my code <script type="text/javascript"> $(document).ready(function() { $("#managerTable").tablesorter({widgets: ['zebra']}, {sortList:[[0,0]],headers:{2:{sorter:false},4:{sorter:false}} }); }); </script>

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  • How do I sort an internationalized i18n table with symfony and doctrine?

    - by Maurizio
    I would like to display a list of records from an internationalized table using sfDoctrinePager. Not all the records have been translated to all the languages supported by the application, so I had to implement a fallback mechanism for some fields (by overriding the getFoo() function in the Bar.class.php, as explained in another post here). I have different fallback list for each culture. Everything works fine until when it comes to sorting the records in alphabetical order. I'm sorting the records at the SQL (Dql) level, by adding an -orderBy('t.name') to the query: $q = Doctrine::getTable('Foo') ->createQuery('f') ->leftJoin('f.Translation t') ->orderBy('t.name') But here come the troubles: the list gets not sorted correctly, regardless of the active culture. I get rather better results when I limit the translations to the active culture, like this: ->leftJoin('f.Translation t WITH lang = ?', $request->getParameter('sf_culture'); Then the sorting is correct, as far as all the translations exist for the active culture. If a translation does not exist and I have to take the name from the fallback language, the record will be displayed at the very beginning of the list (I understand this happens because the value for the current culture is null). My question is: is there a best practice for getting internationalized fields (needing fallbacks) sorted correctly with doctrine and sfDoctrinePager? Thank you in advance.

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  • Sorting/Paginating/Filtering Complex Multi-AR Object Tables in Rails

    - by Matt Rogish
    I have a complex table pulled from a multi-ActiveRecord object array. This listing is a combined display of all of a particular user's "favorite" items (songs, messages, blog postings, whatever). Each of these items is a full-fledged AR object. My goal is to present the user with a simplified search, sort, and pagination interface. The user need not know that the Song has a singer, and that the Message has an author -- to the end user both entries in the table will be displayed as "User". Thus, the search box will simply be a dropdown list asking them which to search on (User name, created at, etc.). Internally, I would need to convert that to the appropriate object search, combine the results, and display. I can, separately, do pagination (mislav will_paginate), sorting, and filtering, but together I'm having some problems combining them. For example, if I paginate the combined list of items, the pagination plugin handles it just fine. It is not efficient since the pagination is happening in the app vs. the DB, but let's assume the intended use-case would indicate the vast majority of the users will have less than 30 favorited items and all other behavior, server capabilities, etc. indicates this will not be a bottleneck. However, if I wish to sort the list I cannot sort it via the pagination plugin because it relies on the assumption that the result set is derived from a single SQL query, and also that the field name is consistent throughout. Thus, I must sort the merged array via ruby, e.g. @items.sort_by{ |i| i.whatever } But, since the items do not share common names, I must first interrogate the object and then call the correct sort by. For example, if the user wishes to sort by user name, if the sorted object is a message, I sort by author but if the object is a song, I sort by singer. This is all very gross and feels quite un-ruby-like. This same problem comes into play with the filter. If the user filters on the "parent item" (the message's thread, the song's album), I must translate that to the appropriate collection object method. Also gross. This is not the exact set-up but is close enough. Note that this is a legacy app so changing it is quite difficult, although not impossible. Also, yes there is some DRY that can be done, but don't focus on the style or elegance of the following code. Style/elegance of the SOLUTION is important, however! :D models: class User < ActiveRecord::Base ... has_and_belongs_to_many :favorite_messages, :class_name => "Message" has_and_belongs_to_many :favorite_songs, :class_name => "Song" has_many :authored_messages, :class_name => "Message" has_many :sung_songs, :class_name => "Song" end class Message < ActiveRecord::Base has_and_belongs_to_many :favorite_messages belongs_to :author, :class_name => "User" belongs_to :thread end class Song < ActiveRecord::Base has_and_belongs_to_many :favorite_songs belongs_to :singer, :class_name => "User" belongs_to :album end controller: def show u = User.find 123 @items = Array.new @items << u.favorite_messages @items << u.favorite_songs # etc. etc. @items.flatten! @items = @items.sort_by{ |i| i.created_at } @items = @items.paginate :page => params[:page], :per_page => 20 end def search # Assume user is searching for username like 'Bob' u = User.find 123 @items = Array.new @items << u.favorite_messages.find( :all, :conditions => "LOWER( author ) LIKE LOWER('%bob%')" ) @items << u.favorite_songs.find( :all, :conditions => "LOWER( singer ) LIKE ... " ) # etc. etc. @items.flatten! @items = @items.sort_by{ |i| determine appropriate sorting based on user selection } @items = @items.paginate :page => params[:page], :per_page => 20 end view: #index.html.erb ... <table> <tr> <th>Title (sort ASC/DESC links)</th> <th>Created By (sort ASC/DESC links))</th> <th>Collection Title (sort ASC/DESC links)</th> <th>Created At (sort ASC/DESC links)</th> </tr> <% @items.each |item| do %> <%= render { :partial => "message", :locals => item } if item.is_a? Message %> <%= render { :partial => "song", :locals => item } if item.is_a? Song %> <%end%> ... </table> #message.html.erb # shorthand, not real ruby print out message title, author name, thread title, message created at #song.html.erb # shorthand print out song title, singer name, album title, song created at

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  • SSRS 2008 Interactive Sorting in Sub-Report not working as expected

    - by Ray J
    I have a (parent) report that has a list. The details group of this list contains one sub-report. So basically if the list has 10 records (rows) the sub-report is executed 10 times. The problem seems to be with interactive sorting in the Sub-Report. It has 4 columns with interactive sorting enabled. When I run the parent report and try to sort columns SSRS "remembers" the previous sort column and sorts by multiple columns at the same time. For example if I sort by Col A then click to sort by Col B, SSRS will preserve the sorting of Col A (and the direction) and then apply the sorting to Col B. However I simply want to sort by Col B and do not want to Col A to be part of the sort. When I try this directly with the sub-report everything works as expected. Any ideas why this is happening?

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  • PHP Nested classes work... sort of?

    - by SeanJA
    So, if you try to do a nested class like this: //nestedtest.php class nestedTest{ function test(){ class E extends Exception{} throw new E; } } You will get an error Fatal error: Class declarations may not be nested in [...] but if you have a class in a separate file like so: //nestedtest2.php class nestedTest2{ function test(){ include('e.php'); throw new E; } } //e.php class E Extends Exception{} So, why does the second hacky way of doing it work, but the non-hacky way of doing it does not work?

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  • Using Entity Framework, how do I specify a sort on a navagation property?

    - by Jared
    I have two tables: [Category], [Item]. They are connected by a join table: [CategoryAndItem]. It has two primary key fields: [CategoryKey], [ItemKey]. Foreign keys exist appropriately and Entity has no problem pulling this in and creating the correct navigation properties that connect the entity objects. Basically each category can have multiple items, and items can be in multiple categories. The problem is that the order of items is specified per category, so that a particular item might be third in one category but fifth in another. In the past, I have added a [Sequence] field to the join table and modified the stored procedure to handle it. But since Entity is replacing my stored procedures, I need to figure out how to make Entity handle the sequence. Any suggestions?

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  • Does this data structure have a name? Sort of a "linked matrix"?

    - by Bob
    Let's say I wanted similar functionality to a doubly linked list but needed a matrix instead so that each node was structured like this: public class Node { Node Up, Down, Left, Right; object Value; } Is there a name for such a structure? I've looked through this Wikipedia listing of data structures but didn't see anything similar. Unless I just missed it.

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  • How to sort some values from an array in a controller in Rails?

    - by Alfred Nerstu
    I've got a links array that I'm saving to a database. The problem is that the records aren't saved in the order of the array ie links[1] is saved before links[2] and so on... This is a example from the view file: <p> <label for="links_9_label">Label</label> <input id="links_9_name" name="links[9][name]" size="30" type="text" /> <input id="links_9_url" name="links[9][url]" size="30" type="text" /> </p> And this is my controller: def create @links = params[:links].values.collect { |link| @user.links.new(link) } respond_to do |format| if @links.all?(&:valid?) @links.each(&:save!) flash[:notice] = 'Links were successfully created.' format.html { redirect_to(links_url) } else format.html { render :action => "new" } end end end Thanks in advance! Alfred

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  • List<> of objects, different types, sort and pull out types individually?

    - by Brazos
    I've got a handful of products, any, all, or none of which may be associated with a specific submission. All 7 products are subclasses of the class Product. I need to store all the products associated with a submission, and then retrieve them and their field data on my presentation layer. I've been using a List, and List, but when I use the OfType, I throw an error saying that I can't implicitly convert systems.generic.IEnumerable to type 'Product'. I've tried to cast, but to no avail. When I use prodlist.OfType<EPL>(); there are no errors, but when I try and store that in an instance of EPL "tempEpl", I get the aforementioned cast-related error. What gives? Code below. ProductService pserv = new ProductService(); IList<object> prodlist = pserv.getProductById(x); EPL tempEpl = new EPL(); if ((prodlist.OfType<EPL>()) != null) { tempEpl = prodlist.OfType<EPL>(); // this throws a conversion error. } the Data layer List<object> TempProdList = new List<object>(); conn.Open(); SqlCommand EplCmd = new SqlCommand(EPLQuery, conn); SqlDataReader EplRead = null; EplRead = EplCmd.ExecuteReader(); EPL TempEpl = new EPL(); if (EplRead.Read()) { TempEpl.Entity1 = EplRead.GetString(0); TempEpl.Employees1 = EplRead.GetInt32(1); TempEpl.CA1 = EplRead.GetInt32(2); TempEpl.MI1 = EplRead.GetInt32(3); TempEpl.NY1 = EplRead.GetInt32(4); TempEpl.NJ1 = EplRead.GetInt32(5); TempEpl.PrimEx1 = EplRead.GetInt32(6); TempEpl.EplLim1 = EplRead.GetInt32(7); TempEpl.EplSir1 = EplRead.GetInt32(8); TempEpl.Premium1 = EplRead.GetInt32(9); TempEpl.Wage1 = EplRead.GetInt32(10); TempEpl.Sublim1 = EplRead.GetInt32(11); TempProdList.Add(TempEpl); }

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  • How do I sort feeds returned from Google Reader?

    - by Ed Marty
    When I query Google Reader for the list of subscriptions for a user, it seems to be returned in a fixed order, no matter what the order is as shown at google.com/reader. (see http://www.google.com/reader/api/0/subscription/list for the list I'm talking about) Each subscription returns a 'sortid', which Google Reader uses when the user rearranges subscriptions, by sending back a concatenation of all sortids in the new order after rearranging is finished. However, that sortid never changes. So my question is this: How do I actually get the order the subscriptions are supposed to be in? I've been using http://code.google.com/p/pyrfeed/wiki/GoogleReaderAPI as a reference, but it is lacking in this department, and I haven't found anything anywhere else either.

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  • How to sort a list so that managers are always ahead of their subordinates (How do I do a topologica

    - by James Black
    I am working on a project using Groovy, and I would like to take an array of employees, so that no manager follows their subordinates in the array. The reason being that I need to add people to a database and I would prefer not to do it in two passes. So, I basically have: <employees> <employee> <employeeid>12</employeeid> <manager>3</manager> </employee> <employee> <employeeid>1</employeeid> <manager></manager> </employee> <employee> <employeeid>3</employeeid> <manager>1</manager> </employee> </employees> So, it should be sorted as such: employeeid = 1 employeeid = 3 employeeid = 12 The first person should have a null for managers. I am thinking about a binary tree representation, but I expect it will be very unbalanced, and I am not certain the best way to do this using Groovy properly. Is there a way to do this that isn't going to involve using nested loops?

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  • What sort of object is this and how to use it?

    - by Gary
    What would be the correct name for this type of array? There are 3 main sections and 4 sub-parts consisting of "issuedTime" "text" "url" and "validToTime", how do you start to convert this to an object? If there was only 1 main section, it would be fairly simple to do however with 3 main parts and no identification for each main section has me scratching my head as where to start. Any advise appreciated. [{ "issuedTime":"7:13pm Sunday 13 June 2010", "text":"\nAmended 7:10pm.\n\nText text and more text\n", "url":"\/folder\/fc\/name.png", "validToTime":"12:00am Monday 14 June 2010" },{ "issuedTime":"8:33pm Sunday 13 June 2010", "text":"\nText and more text.\n", "url":"\/folder\/fc\/name.png", "validToTime":"12:00pm Monday 14 June 2010" },{ "issuedTime":"10:40am Sunday 13 June 2010", "text":"\nAnd even more text.", "url":"\/folder\/fc\/name.png", "validToTime":"12:00am Tuesday 15 June 2010" } ]

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  • acts-as-taggable-on: find tags with name LIKE, sort by tag_counts?

    - by James
    Hi I'm using the rails plugin acts-as-taggable-onand I'm trying to find the top 5 most used tags whose names match and partially match a given query. When I do User.skill_counts.order('count DESC').limit(5).where('name LIKE ?', params[:query]) This return the following error: ActiveRecord::StatementInvalid: SQLite3::SQLException: ambiguous column name: name: SELECT tags.*, COUNT(*) AS count FROM "tags" INNER JOIN users ON users.id = taggings.taggable_id LEFT OUTER JOIN taggings ON tags.id = taggings.tag_id AND taggings.context = 'skills' WHERE (taggings.taggable_type = 'User') AND (taggings.taggable_id IN(SELECT users.id FROM "users")) AND (name LIKE 'asd') GROUP BY tags.id, tags.name HAVING COUNT(*) > 0 ORDER BY count DESC LIMIT 5 But when I do User.skill_counts.first.name this returns "alliteration" I'd appreciate any help on this matter.

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  • Is this a bad version of the Merge Sort algorithm?

    - by SebKom
    merge1(int low, int high, int S[], U[]) { int k = (high - low + 1)/2 for q (from low to high) U[q] = S[q] int j = low int p = low int i = low + k while (j <= low + k - 1) and (i <= high) do { if ( U[j] <= U[i] ) { S[p] := U[j] j := j+1 } else { S[p] := U[i] i := i+1 } p := p+1 } if (j <= low + k - 1) { for q from p to high do { S[q] := U[j] j := j+1 } } } merge_sort1(int low, int high, int S[], U[]) { if low < high { int k := (high - low + 1)/2 merge_sort1(low, low+k-1, S, U) merge_sort1(low+k, high, S, U) merge1(low, high, S, U) } } I am really sorry for the terrible formating, as you can tell I am not a regular visitor here. So, basically, this is on my lecture notes. I find it quite confusing in general but I understand the biggest part of it. What I don't understand is the need of the "if (j <= low + k - 1)" part. It looks like it checks if there are any elements "left" in the left part. Is that even possible when mergesorting?

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  • Possible to sort via two time stamps and display same row twice.

    - by jamiethompson90
    I'm looking at creating a time table solution. I have a task sheet that looks like Area 1 item 1 startTime endTime Area 1 item1 startTime endTime I wish to create a display where I can view what even is happening next, either endTime or startTime i.e. Newcastle reel 16:45 18:45 Newcastle reel2 17:45 19:45 would output Newcastle reel 16:45 Newcastle reel 17:45 Newcastle reel 18:45 Newcastle reel 19:45 More so, I would like to detect if the time is a startTime or an endTime would I have to enter two rows for each activity (time,area,item, start|end). I can make the interface to the creation of two rows. I just wondered if there was a better solution. Any input is appreciated, Thanks, Jamie

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  • How to properly sort MPTT hierarchy data into multidimensional array ?

    - by DiegoMax
    Helo there, im trying to figure out how to write a function that returns a multidimensional array, based on the data below: I know how to write the function using the "category_parent" value, but im just trying to write a function that can create a multidimensional array by JUST using the left and right keys. Any help greatly appreciated! array(71) { [0]=> array(9) { ["id"]=> string(1) "1" ["category_name"]=> string(6) "Rubros" ["category_parent"]=> string(1) "0" ["category_slug"]=> string(6) "rubros" ["category_image"]=> NULL ["category_totals"]=> NULL ["category_lft"]=> string(1) "1" ["category_rgt"]=> string(3) "142" } [1]=> array(9) { ["id"]=> string(4) "1000" ["category_name"]=> string(12) "Restaurantes" ["category_parent"]=> string(1) "1" ["category_slug"]=> string(12) "restaurantes" ["category_image"]=> string(16) "restaurantes.png" ["category_totals"]=> string(1) "1" ["category_lft"]=> string(1) "2" ["category_rgt"]=> string(2) "13" } [2]=> array(9) { ["id"]=> string(1) "3" ["category_name"]=> string(21) "Restaurantes de Campo" ["category_parent"]=> string(4) "1000" ["category_slug"]=> string(21) "restaurantes-de-campo" ["category_image"]=> NULL ["category_totals"]=> string(1) "1" ["category_lft"]=> string(1) "3" ["category_rgt"]=> string(1) "4" } [3]=> array(9) { ["id"]=> string(2) "37" ["category_name"]=> string(25) "Restaurantes en la Ciudad" ["category_parent"]=> string(4) "1000" ["category_slug"]=> string(19) "restaurantes-ciudad" ["category_image"]=> string(0) "" ["category_totals"]=> string(1) "6" ["category_lft"]=> string(1) "5" ["category_rgt"]=> string(1) "6" } [4]=> array(9) { ["id"]=> string(2) "41" ["category_name"]=> string(21) "Servicios de Catering" ["category_parent"]=> string(4) "1000" ["category_slug"]=> string(8) "catering" ["category_image"]=> string(0) "" ["category_totals"]=> string(1) "1" ["category_lft"]=> string(1) "7" ["category_rgt"]=> string(1) "8" } [5]=> array(9) { ["id"]=> string(2) "48" ["category_name"]=> string(10) "Rotiserias" ["category_parent"]=> string(4) "1000" ["category_slug"]=> string(10) "rotiserias" ["category_image"]=> string(0) "" ["category_totals"]=> string(1) "1" ["category_lft"]=> string(1) "9" ["category_rgt"]=> string(2) "10" } [6]=> array(9) { ["id"]=> string(2) "62" ["category_name"]=> string(10) "Pizzerías" ["category_parent"]=> string(4) "1000" ["category_slug"]=> string(9) "pizzerias" ["category_image"]=> string(0) "" ["category_totals"]=> string(1) "1" ["category_lft"]=> string(2) "11" ["category_rgt"]=> string(2) "12" } [7]=> array(9) { ["id"]=> string(1) "2" ["category_name"]=> string(13) "Profesionales" ["category_parent"]=> string(1) "1" ["category_slug"]=> string(13) "profesionales" ["category_image"]=> string(17) "profesionales.png" ["category_totals"]=> string(1) "2" ["category_lft"]=> string(2) "14" ["category_rgt"]=> string(2) "35" } [8]=> array(9) { ["id"]=> string(2) "29" ["category_name"]=> string(11) "Arquitectos" ["category_parent"]=> string(1) "2" ["category_slug"]=> string(11) "arquitectos" ["category_image"]=> NULL ["category_totals"]=> string(1) "0" ["category_lft"]=> string(2) "15" ["category_rgt"]=> string(2) "16" } [9]=> array(9) { ["id"]=> string(2) "30" ["category_name"]=> string(8) "Abogados" ["category_parent"]=> string(1) "2" ["category_slug"]=> string(8) "abogados" ["category_image"]=> NULL ["category_totals"]=> string(1) "6" ["category_lft"]=> string(2) "17" ["category_rgt"]=> string(2) "18" } }

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  • Is there a better way to do SELECT queries in MySQL and sort them in PHP than this way?

    - by Kent
    I am just learning PHP/MySQL, one this I am having to do a lot is displaying data that was previously inserted into the database out to the user's browser. So I am doing this: $select = mysql_query('SELECT * FROM pages'); while ($return = mysql_fetch_assoc($select)) { $title = $return['title']; $author = $return['author']; $content = $return['content']; } then I can use these variables through out the page. Now, doing it the above way isn't an issue when I only have 3 columns in a database but what if I am dealing with a huge database with many more columns. I have a nagging feeling that the pros do it in some more efficient way where they maybe loop through the table they are selecting from to find all columns it has and associate them with variables automatically. Is that the case? or is the above how you guys do it too?

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  • KnockoutJS showing a sorted list by item category

    - by Darksbane
    I just started learning knockout this week and everything has gone well except for this one issue. I have a list of items that I sort multiple ways but one of the ways I want to sort needs to have a different display than the standard list. As an example lets say I have this code var BetterListModel = function () { var self = this; food = [ { "name":"Apple", "quantity":"3", "category":"Fruit", "cost":"$1", },{ "name":"Ice Cream", "quantity":"1", "category":"Dairy", "cost":"$6", },{ "name":"Pear", "quantity":"2", "category":"Fruit", "cost":"$2", },{ "name":"Beef", "quantity":"1", "category":"Meat", "cost":"$3", },{ "name":"Milk", "quantity":"5", "category":"Dairy", "cost":"$4", }]; self.allItems = ko.observableArray(food); // Initial items // Initial sort self.sortMe = ko.observable("name"); ko.utils.compareItems = function (l, r) { if (self.sortMe() =="cost"){ return l.cost > r.cost ? 1 : -1 } else if (self.sortMe() =="category"){ return l.category > r.category ? 1 : -1 } else if (self.sortMe() =="quantity"){ return l.quantity > r.quantity ? 1 : -1 }else { return l.name > r.name ? 1 : -1 } }; }; ko.applyBindings(new BetterListModel()); and the HTML <p>Your values:</p> <ul class="deckContents" data-bind="foreach:allItems().sort(ko.utils.compareItems)"> <li><div style="width:100%"><div class="left" style="width:30px" data-bind="text:quantity"></div><div class="left fixedWidth" data-bind="text:name"></div> <div class="left fixedWidth" data-bind="text:cost"></div> <div class="left fixedWidth" data-bind="text:category"></div><div style="clear:both"></div></div></li> </ul> <select data-bind="value:sortMe"> <option selected="selected" value="name">Name</option> <option value="cost">Cost</option> <option value="category">Category</option> <option value="quantity">Quantity</option> </select> </div> So I can sort these just fine by any field I might sort them by name and it will display something like this 3 Apple $1 Fruit 1 Beef $3 Meat 1 Ice Cream $6 Dairy 5 Milk $4 Dairy 2 Pear $2 Fruit Here is a fiddle of what I have so far http://jsfiddle.net/Darksbane/X7KvB/ This display is fine for all the sorts except the category sort. What I want is when I sort them by category to display it like this Fruit 3 Apple $1 Fruit 2 Pear $2 Fruit Meat 1 Beef $3 Meat Dairy 1 Ice Cream $6 Dairy 5 Milk $4 Dairy Does anyone have any idea how I might be able to display this so differently for that one sort?

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  • Getting text after URL in asp.net / URL Rewriting (sort of!)

    - by alex
    My app is a very simple "one page" type app- It has Default.aspx I'm basically trying to get, for example: www.myappurl.com/this is my text I want to get hold of "this is my text" from the above example. This will be displayed on the page (for now) I didn't really want to have to use any complext url rewriting things for this... (My hosting provider uses IIS6) I tried using a 404 handler, but this is a bit long winded, and i'm using shared hosting, that can't set the "execute url" on custom 404 pages. Any other ideas?

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  • Trouble Upgrading Rails 2 Routes for a Redmine Plugin

    - by user1858628
    I am trying to get a Redmine plugin designed for Rails 2 to work with Rails 3. https://github.com/dalyons/redmine-todos-scrum-plugin I've pretty much fixed most parts, but having no success whatsoever in getting the routes to work. The original routes for Rails 2 are as follows: map.resources :todos, :name_prefix => 'project_', :path_prefix => '/projects/:project_id', :member => {:toggle_complete => :post }, :collection => {:sort => :post} map.resources :todos, :name_prefix => 'user_', :path_prefix => '/users/:user_id', :controller => :mytodos, :member => {:toggle_complete => :post }, :collection => {:sort => :post} map.my_todos 'my/todos', :controller => :mytodos, :action => :index map.connect 'projects/:project_id/todos/show/:id', :controller => "todos", :action => "show" rake routes outputs the following: sort_project_todos POST /projects/:project_id/todos/sort(.:format) {:controller=>"todos", :action=>"sort"} project_todos GET /projects/:project_id/todos(.:format) {:controller=>"todos", :action=>"index"} POST /projects/:project_id/todos(.:format) {:controller=>"todos", :action=>"create"} new_project_todo GET /projects/:project_id/todos/new(.:format) {:controller=>"todos", :action=>"new"} toggle_complete_project_todo POST /projects/:project_id/todos/:id/toggle_complete(.:format) {:controller=>"todos", :action=>"toggle_complete"} edit_project_todo GET /projects/:project_id/todos/:id/edit(.:format) {:controller=>"todos", :action=>"edit"} project_todo GET /projects/:project_id/todos/:id(.:format) {:controller=>"todos", :action=>"show"} PUT /projects/:project_id/todos/:id(.:format) {:controller=>"todos", :action=>"update"} DELETE /projects/:project_id/todos/:id(.:format) {:controller=>"todos", :action=>"destroy"} sort_user_todos POST /users/:user_id/todos/sort(.:format) {:controller=>"mytodos", :action=>"sort"} user_todos GET /users/:user_id/todos(.:format) {:controller=>"mytodos", :action=>"index"} POST /users/:user_id/todos(.:format) {:controller=>"mytodos", :action=>"create"} new_user_todo GET /users/:user_id/todos/new(.:format) {:controller=>"mytodos", :action=>"new"} toggle_complete_user_todo POST /users/:user_id/todos/:id/toggle_complete(.:format) {:controller=>"mytodos", :action=>"toggle_complete"} edit_user_todo GET /users/:user_id/todos/:id/edit(.:format) {:controller=>"mytodos", :action=>"edit"} user_todo GET /users/:user_id/todos/:id(.:format) {:controller=>"mytodos", :action=>"show"} PUT /users/:user_id/todos/:id(.:format) {:controller=>"mytodos", :action=>"update"} DELETE /users/:user_id/todos/:id(.:format) {:controller=>"mytodos", :action=>"destroy"} my_todos /my/todos {:controller=>"mytodos", :action=>"index"} /projects/:project_id/todos/show/:id {:controller=>"todos", :action=>"show"} The nearest I have got for Rails 3 is follows: scope '/projects/:project_id', :name_prefix => 'project_' do resources :todos, :controller => 'todos' do member do post :toggle_complete end collection do post :sort end end end scope '/users/:user_id', :name_prefix => 'user_' do resources :todos, :controller => 'mytodos' do member do post :toggle_complete end collection do post :sort end end end match 'my/todos' => 'mytodos#index', :as => :my_todos match 'projects/:project_id/todos/show/:id' => 'todos#show' rake routes outputs the following: toggle_complete_todo POST /projects/:project_id/todos/:id/toggle_complete(.:format) todos#toggle_complete {:name_prefix=>"project_"} sort_todos POST /projects/:project_id/todos/sort(.:format) todos#sort {:name_prefix=>"project_"} todos GET /projects/:project_id/todos(.:format) todos#index {:name_prefix=>"project_"} POST /projects/:project_id/todos(.:format) todos#create {:name_prefix=>"project_"} new_todo GET /projects/:project_id/todos/new(.:format) todos#new {:name_prefix=>"project_"} edit_todo GET /projects/:project_id/todos/:id/edit(.:format) todos#edit {:name_prefix=>"project_"} todo GET /projects/:project_id/todos/:id(.:format) todos#show {:name_prefix=>"project_"} PUT /projects/:project_id/todos/:id(.:format) todos#update {:name_prefix=>"project_"} DELETE /projects/:project_id/todos/:id(.:format) todos#destroy {:name_prefix=>"project_"} POST /users/:user_id/todos/:id/toggle_complete(.:format) mytodos#toggle_complete {:name_prefix=>"user_"} POST /users/:user_id/todos/sort(.:format) mytodos#sort {:name_prefix=>"user_"} GET /users/:user_id/todos(.:format) mytodos#index {:name_prefix=>"user_"} POST /users/:user_id/todos(.:format) mytodos#create {:name_prefix=>"user_"} GET /users/:user_id/todos/new(.:format) mytodos#new {:name_prefix=>"user_"} GET /users/:user_id/todos/:id/edit(.:format) mytodos#edit {:name_prefix=>"user_"} GET /users/:user_id/todos/:id(.:format) mytodos#show {:name_prefix=>"user_"} PUT /users/:user_id/todos/:id(.:format) mytodos#update {:name_prefix=>"user_"} DELETE /users/:user_id/todos/:id(.:format) mytodos#destroy {:name_prefix=>"user_"} my_todos /my/todos(.:format) mytodos#index /projects/:project_id/todos/show/:id(.:format) todos#show I am guessing that I am not using :name_prefix correctly, resulting in duplicate paths which are then omitted. Any help would be greatly appreciated.

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