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  • Function keys require Fn modifer. How can I make them default?

    - by RickMeasham
    On my Dell Studio 15, the function keys, by default, do things like switch the radio on/off or change the brightness or sound. To use them as function keys I have to hold down the Fn modifier. I use function keys as function keys a lot more often than I want to change the volume or brightness. Am I missing an obvious setting somewhere in the control panel (Vista Uber Extreme Something)?

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  • Why android app does not recognize GPRS, WiFi upon changing data connection

    - by Maxood
    If i turn off WiFi, i’m not able to open the app ( this is with no data connection, even without data connection it should display cached items ) If i tun off WiFi and turn on GPRS the app cannot recognize this and gives the error page no Wifi/GPRS connection. if i restart the phone with GPRS on the app works fine till i change data connection type. if i restart the phone with WiFi on the app works fine till i change the data connection type. whenever i change the data connection type i have to restart the phone so the app can recognize the connection type. Why my android app does not recognize WiFi, GPRS upon changing data connection in real time?

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  • Program seems to get stuck ?

    - by Frank
    I have a Java program, I did some change and the strange thing is no matter what I do now, it will output the same result before my change, I looked into my system (Windows Vista), and clicked on "Generate a system health report", the result says : Symptom : A service is reported as having an unexpected error code Cause : One or more services has failed. The service did not stop gracefully, suggesting the service may have crashed or one of its components stopped in an unsupported way. Details : Service exited with code not equal to 0 or 1077 Resolution : Restart the service It doesn't say which service, and I defragmented my drives a few times, it still gave me the same report. I also checked my memory, it says no problem with ram. Everything else is ok, I re-started the windows a few times, got more free space on my C: drive, yet the Java program is still not responding to my new changes, unless I intentionally make a mistake, it gives me compile error, but if it can compile successfully, it still gives me the results before the change. What can I do to fix this ? Frank

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  • How to have a dynamic theme color in WPF

    - by Ingó Vals
    In WPF I have a few resource dictionaries and in them styles for my panels and controls in my app. I'm reusing the same colors again and again. I actually have 5 colors and they give my app a good color-scheme. However if I wan't to change the theme I have to go into the RD's and change each and every color there. I would like to somewhere have the colors set but don't know how or where. I tried to put a color tag in one RD but as soon as I referenced it in the same RD Visual Studio crashed. Also the best solution would be that I could have the color as a dynamic setting in the app itself so users could even change it themselves.

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  • How do I detect when a cell's value has changed in Silverlight?

    - by jvenema
    Hey folks, I'm working in Silverlight, trying to figure out how to set a grid cell font color based on the contents of the cell. I have an ObservableCollection bound to a DataGrid, and my items implement INotifyPropertyChanged so the grid updates as I change the values; it's all working perfectly, including letting me sort items and keep the sorting while I update the underlying items. I know I can use the LoadingRow event to change colors, but the only way I can get the event to fire is by changing the grids datasource, in which case my sorting goes out the window. So, what I really want is a way to either 1) loop the rows in the datagrid, find the cell I need, and change it's color or 2) implement a custom column that I can use to dynamically set the color. The problem is how to actually do either of those things :) All suggestions welcome.

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  • jQuery if checkbox is checked to toggle classes

    - by Lynx
    I am needed to change my jQuery code up. Instead of the label toggling the class and showing the icon I need it to where if the checkbox is checked to show to toggle those classes. I have tried prop and is but I couldn't get them to work properly. The reason for the change is I want to preload data into the form and if it's going to be checked those toggles need to reflect that change. http://jsfiddle.net/70fbLooL/2/ EDIT Seems to be confusion as to exactly what I am trying to do. The fiddle I provided works perfectly fine. The problem is if I want to call the form from server-side and pre-populate the form the checkbox toggles will not show that they are checked because it's based on the clicked function. I need it to be based on if the checkbox equal true or checked. That way if the value equals true from the server-side call it will toggle those classes and look like it's checked.

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  • When Intel/AMD plan to use new CPU sockets? [closed]

    - by psihodelia
    It is very expensive always to use most modern hardware especially buying new mainboard if only a new CPU is desired. It would be much better if one knows whether and when major CPU producers plan to change CPU sockets. Do you know when it is planed to change sockets the next time? I am particularly interested in not buying Intel i7 CPU if a new CPU will be released soon with not compatible pins.

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  • Fulfilling strange requirements with CSS (kind of simulating frames)

    - by Bernhard V
    Hi! I'm struggling to find a way to code a site according to our strange requirements. The site should be displayed correctly in all browsers from IE6 to Opera. The website is structured in three parts. It contains a header at the top, a navigation on the left an the rest of the screen should be filled with the content section. The following picture should help you better understand my description. Here comes the kicker: Each of the three sections should be scrollable separately and no browser scrollbar should appear. The page should be displayed similar as if it would use frames. Of course, on a big enough screen, no scroll bars should appear. It doesn't matter which way is used to display the site, although frames aren't an option an divs would be preferred. There are two conditions: The site should always fill the whole browser screen. The header and the content section should reach to the right border of the page, and the navigation as well as the content to the bottom. As soon as the site is scaled down -- whether due to resizing the browser window or due to a smaller resolution -- a scrollbar for every single section should appear, but no "browser scrollbar" for the whole page. The header should always retain it's height and the navigation always it's width. Do you know a way how all this can be achieved? Yours Bernhard

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  • How to allow users to customize a DAL

    - by rsteckly
    Hi, I'm working in ASP.NET in an application where often users want to add fields or change field names. I'd like to be able to have an xml schema in place that is parsed and a dynamic object model created from it that can be accessed throughout the application. My initial reaction is that this is not realistic. I think there is flexibility about the dynamic nature of it. I think the people I'm trying to build this for wouldn't mind recompiling. Even if the app recompiled, I don't know how to abstract away enough in my code access the data to allow for users changing property names, etc. How can you write LINQ when the properties might change? In short, there's two questions here: 1) is there a way to dynamically generate an object model of the database and 2) is there a way to abstract away enough so that code accessing the database doesn't break when properties change?

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  • Auto-detected mouse - disable 3rd button enumation

    - by viraptor
    I'd like to disable the 3rd button emulation in ubuntu 9.10. Normally, I'd just change the option in xorg.conf and it would go away - but how do I deal with an autodetected mouse? For example, I've got a mouse I connect to USB and it has the emulation enabled by default. How do I change it in that case?

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  • Add user in CentOS 5

    - by Ron
    I created a new user in my CentOS web server with useradd. Added a password with passwd. But I can't log in with the user via SSH. I keep getting 'access denied'. I checked to make sure that the password was assigned and that the account is active. /var/log/secure shows the following error: Aug 13 03:41:40 server1 su: pam_unix(su:auth): authentication failure; logname= uid=500 euid=0 tty=pts/0 ruser=rwade rhost= user=root Please help, Thanks Thanks for the responses so far: I should add that it is a VPS on a remote computer, fresh out of the box. I can log in as the root user quite fine. I can also su to the new user, but I cannot log in as the new user. Here is my sshd_config file: # $OpenBSD: sshd_config,v 1.73 2005/12/06 22:38:28 reyk Exp $ # This is the sshd server system-wide configuration file. See # sshd_config(5) for more information. # This sshd was compiled with PATH=/usr/local/bin:/bin:/usr/bin # The strategy used for options in the default sshd_config shipped with # OpenSSH is to specify options with their default value where # possible, but leave them commented. Uncommented options change a # default value. #Port 22 #Protocol 2,1 Protocol 2 #AddressFamily any #ListenAddress 0.0.0.0 #ListenAddress :: # HostKey for protocol version 1 #HostKey /etc/ssh/ssh_host_key # HostKeys for protocol version 2 #HostKey /etc/ssh/ssh_host_rsa_key #HostKey /etc/ssh/ssh_host_dsa_key # Lifetime and size of ephemeral version 1 server key #KeyRegenerationInterval 1h #ServerKeyBits 768 # Logging # obsoletes QuietMode and FascistLogging #SyslogFacility AUTH SyslogFacility AUTHPRIV #LogLevel INFO # Authentication: #LoginGraceTime 2m #PermitRootLogin yes #StrictModes yes #MaxAuthTries 6 #RSAAuthentication yes #PubkeyAuthentication yes #AuthorizedKeysFile .ssh/authorized_keys # For this to work you will also need host keys in /etc/ssh/ssh_known_hosts #RhostsRSAAuthentication no # similar for protocol version 2 #HostbasedAuthentication no # Change to yes if you don't trust ~/.ssh/known_hosts for # RhostsRSAAuthentication and HostbasedAuthentication #IgnoreUserKnownHosts no # Don't read the user's ~/.rhosts and ~/.shosts files #IgnoreRhosts yes # To disable tunneled clear text passwords, change to no here! #PasswordAuthentication yes #PermitEmptyPasswords no PasswordAuthentication yes # Change to no to disable s/key passwords #ChallengeResponseAuthentication yes ChallengeResponseAuthentication no # Kerberos options #KerberosAuthentication no #KerberosOrLocalPasswd yes #KerberosTicketCleanup yes #KerberosGetAFSToken no # GSSAPI options #GSSAPIAuthentication no GSSAPIAuthentication yes #GSSAPICleanupCredentials yes GSSAPICleanupCredentials yes # Set this to 'yes' to enable PAM authentication, account processing, # and session processing. If this is enabled, PAM authentication will # be allowed through the ChallengeResponseAuthentication mechanism. # Depending on your PAM configuration, this may bypass the setting of # PasswordAuthentication, PermitEmptyPasswords, and # "PermitRootLogin without-password". If you just want the PAM account and # session checks to run without PAM authentication, then enable this but set # ChallengeResponseAuthentication=no #UsePAM no UsePAM yes # Accept locale-related environment variables AcceptEnv LANG LC_CTYPE LC_NUMERIC LC_TIME LC_COLLATE LC_MONETARY LC_MESSAGES AcceptEnv LC_PAPER LC_NAME LC_ADDRESS LC_TELEPHONE LC_MEASUREMENT AcceptEnv LC_IDENTIFICATION LC_ALL #AllowTcpForwarding yes #GatewayPorts no #X11Forwarding no X11Forwarding yes #X11DisplayOffset 10 #X11UseLocalhost yes #PrintMotd yes #PrintLastLog yes #TCPKeepAlive yes #UseLogin no #UsePrivilegeSeparation yes #PermitUserEnvironment no #Compression delayed #ClientAliveInterval 0 #ClientAliveCountMax 3 #ShowPatchLevel no #UseDNS yes #PidFile /var/run/sshd.pid #MaxStartups 10 #PermitTunnel no #ChrootDirectory none # no default banner path #Banner /some/path # override default of no subsystems Subsystem sftp /usr/libexec/openssh/sftp-server

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  • Set default system audio output port (for all accounts)

    - by Ludwik Trammer
    The default output audio port Ubuntu doesn't work on my system. It should be "Analog Mono Output/Amplifier", instead of "Analog Output/Amplifier". I can easily change that in sound preferences, just by choosing the right port in the "Output" tab. The problem is this would only apply to a single account, and I would like to change it system-wide, so it applies to all accounts on the system (I have more than 100 users...). I'm after 2 hours of Googling, so any help would be appreciated.

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  • LINQ to SQL -- Can't modify return type of stored procedure.

    - by Kyle Ryan
    When I drag a particular stored procedure into the VS 2008 dbml designer, it shows up with Return Type set to "none", and it's read only so I can't change it. The designer code shows it as returning an int, and if I change that manually, it just gets undone on the next build. But with another (nearly identical) stored procedure, I can change the return type just fine (from "Auto Generated Type" to what I want.) I've run into this problem on two separate machines. Any idea what's going on? Here's the stored procedure that works: USE [studio] GO /****** Object: StoredProcedure [dbo].[GetCourseAnnouncements] Script Date: 05/29/2009 09:44:51 ******/ SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER OFF GO CREATE PROCEDURE [dbo].[GetCourseAnnouncements] @course int AS SELECT * FROM Announcements WHERE Announcements.course = @course RETURN And this one doesn't: USE [studio] GO /****** Object: StoredProcedure [dbo].[GetCourseAssignments] Script Date: 05/29/2009 09:45:32 ******/ SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER OFF GO CREATE PROCEDURE [dbo].[GetCourseAssignments] @course int AS SELECT * FROM Assignments WHERE Assignments.course = @course ORDER BY date_due ASC RETURN

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  • Javascript Problem! Not changing the css style

    - by mathew
    I have this code in JavaScript: function change() { document.getElementById("mem").className = 'gif'; } The fig and gif are like this: a.fig { background: #FFFFFF; } a.gif { background: #000099 ; } and the function is used like this <a class ="fig" id ="mem" onClick="javascript:change()" href="users" > Where the only difference between gif and fig in CSS is that they have different background colors. The problem is that the change is only noticeable in just a second and it is not permanent! Any ideas?

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  • Setting Manager path in Tomcat6

    - by Tom
    Hi gurus I want to switch context path to Manager app in Tomcat6 http://tomcat.apache.org/tomcat-6.0-doc/manager-howto.html I change $CATALINA_BASE/conf/[enginename]/[hostname]/manager.xml to: <Context path="/adm" docBase="${catalina.home}/webapps/manager" privileged="true" antiResourceLocking="false" antiJARLocking="false"> notice to: path="/adm", but manager app is always in /manager. Please, how can I change manager path in Tomcat6? Thanks a lot. Tom

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  • rotating circle with swipe question

    - by Joe
    Okay so I'm making something that basically works as a knob, but only half on the screen -- so I just need horizontal swipes to cause it to rotate. I have it nearly all sorted with one exception: if you change direction of your swipe in mid-swipe, the rotation doesn't change direction. I even can see the problem, but not sure what to do about a solution. So in my touchesMoved, I get the swipe into radians in the predictable way: CGFloat radians = atan2f(location.y - centerY, location.x - centerX); I then store radians, add/subtract it to previous rotation and then give the result to the CATransform3D. So the prob is that even though the swipe changes direction, there is a "balance" which doesn't allow an immediate change of direction. Does this make any sense?

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  • deactivate ' pin to start ' on Application List page when pinning an app via code using C#?

    - by Ahmed Ali
    i'm creating a windows phone app ,where i've put a button to pin the app to start screen , but when press and hold the app icon on application list screen i find that the pin to start option can be used ShellTile TileToFind = ShellTile.ActiveTiles.FirstOrDefault(x => x.NavigationUri.ToString().Contains("MainPage.xaml")); // Create the Tile if we didn't find that it already exists. if (TileToFind == null) { // Create the Tile object and set some initial properties for the Tile. // The Count value of 12 shows the number 12 on the front of the Tile. Valid values are 1-99. // A Count value of 0 indicates that the Count should not be displayed. StandardTileData NewTileData = new StandardTileData { BackgroundImage = new Uri("300.png", UriKind.Relative), Title = "apptitle", BackTitle = "title", BackContent = "testing ", BackBackgroundImage = null }; // Create the Tile and pin it to Start. This will cause a navigation to Start and a deactivation of our app. ShellTile.Create(new Uri("/MainPage.xaml", UriKind.Relative), NewTileData); } else { MessageBox.Show("Already Pinned"); } how can i disable the user from pinning the application again from application list screen

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  • Calling subactivity from subactivity

    - by yogsma
    I have three activities in my android app. First activity is main application screen which gives option to open second screen containing second activity. But when I click on the button on second activity which was supposed to open third activity screen, I get "Application has stopped unexpectedly" error. <?xml version="1.0" encoding="utf-8"?> <manifest xmlns:android="http://schemas.android.com/apk/res/android" package="org.anddev.android.SampleApp" android:versionCode="1" android:versionName="1.0"> <application android:icon="@drawable/icon" android:label="@string/app_name"> <activity android:name=".FirstActivity" android:label="@string/app_name"> <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> <activity android:name=".SecondActivity" android:label="@string/app_name" > </activity> <activity android:name=".ThirdActivity" android:label="@string/app_name" > </activity> </application>

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  • Add user in CentOS 5

    - by Ron
    I created a new user in my CentOS web server with useradd. Added a password with passwd. But I can't log in with the user via SSH. I keep getting 'access denied'. I checked to make sure that the password was assigned and that the account is active. /var/log/secure shows the following error: Aug 13 03:41:40 server1 su: pam_unix(su:auth): authentication failure; logname= uid=500 euid=0 tty=pts/0 ruser=rwade rhost= user=root Please help, Thanks Thanks for the responses so far: I should add that it is a VPS on a remote computer, fresh out of the box. I can log in as the root user quite fine. I can also su to the new user, but I cannot log in as the new user. Here is my sshd_config file: # $OpenBSD: sshd_config,v 1.73 2005/12/06 22:38:28 reyk Exp $ # This is the sshd server system-wide configuration file. See # sshd_config(5) for more information. # This sshd was compiled with PATH=/usr/local/bin:/bin:/usr/bin # The strategy used for options in the default sshd_config shipped with # OpenSSH is to specify options with their default value where # possible, but leave them commented. Uncommented options change a # default value. #Port 22 #Protocol 2,1 Protocol 2 #AddressFamily any #ListenAddress 0.0.0.0 #ListenAddress :: # HostKey for protocol version 1 #HostKey /etc/ssh/ssh_host_key # HostKeys for protocol version 2 #HostKey /etc/ssh/ssh_host_rsa_key #HostKey /etc/ssh/ssh_host_dsa_key # Lifetime and size of ephemeral version 1 server key #KeyRegenerationInterval 1h #ServerKeyBits 768 # Logging # obsoletes QuietMode and FascistLogging #SyslogFacility AUTH SyslogFacility AUTHPRIV #LogLevel INFO # Authentication: #LoginGraceTime 2m #PermitRootLogin yes #StrictModes yes #MaxAuthTries 6 #RSAAuthentication yes #PubkeyAuthentication yes #AuthorizedKeysFile .ssh/authorized_keys # For this to work you will also need host keys in /etc/ssh/ssh_known_hosts #RhostsRSAAuthentication no # similar for protocol version 2 #HostbasedAuthentication no # Change to yes if you don't trust ~/.ssh/known_hosts for # RhostsRSAAuthentication and HostbasedAuthentication #IgnoreUserKnownHosts no # Don't read the user's ~/.rhosts and ~/.shosts files #IgnoreRhosts yes # To disable tunneled clear text passwords, change to no here! #PasswordAuthentication yes #PermitEmptyPasswords no PasswordAuthentication yes # Change to no to disable s/key passwords #ChallengeResponseAuthentication yes ChallengeResponseAuthentication no # Kerberos options #KerberosAuthentication no #KerberosOrLocalPasswd yes #KerberosTicketCleanup yes #KerberosGetAFSToken no # GSSAPI options #GSSAPIAuthentication no GSSAPIAuthentication yes #GSSAPICleanupCredentials yes GSSAPICleanupCredentials yes # Set this to 'yes' to enable PAM authentication, account processing, # and session processing. If this is enabled, PAM authentication will # be allowed through the ChallengeResponseAuthentication mechanism. # Depending on your PAM configuration, this may bypass the setting of # PasswordAuthentication, PermitEmptyPasswords, and # "PermitRootLogin without-password". If you just want the PAM account and # session checks to run without PAM authentication, then enable this but set # ChallengeResponseAuthentication=no #UsePAM no UsePAM yes # Accept locale-related environment variables AcceptEnv LANG LC_CTYPE LC_NUMERIC LC_TIME LC_COLLATE LC_MONETARY LC_MESSAGES AcceptEnv LC_PAPER LC_NAME LC_ADDRESS LC_TELEPHONE LC_MEASUREMENT AcceptEnv LC_IDENTIFICATION LC_ALL #AllowTcpForwarding yes #GatewayPorts no #X11Forwarding no X11Forwarding yes #X11DisplayOffset 10 #X11UseLocalhost yes #PrintMotd yes #PrintLastLog yes #TCPKeepAlive yes #UseLogin no #UsePrivilegeSeparation yes #PermitUserEnvironment no #Compression delayed #ClientAliveInterval 0 #ClientAliveCountMax 3 #ShowPatchLevel no #UseDNS yes #PidFile /var/run/sshd.pid #MaxStartups 10 #PermitTunnel no #ChrootDirectory none # no default banner path #Banner /some/path # override default of no subsystems Subsystem sftp /usr/libexec/openssh/sftp-server

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  • Having a problem getting my ActionListeners, Handlers, and GUI to communicate.

    - by badpanda
    So I am trying to get my GUI to work. When I run the code below, it does nothing, and I'm sure I'm probably just doing something dumb, but I am completely stuck... public void actionPerformed(ActionEvent e){ UI.getInstance().sS++; if((UI.getInstance().sS %2) != 0){ UI.getInstance().startStop.setName("STOP"); UI.getInstance().change.setEnabled(false); }else if(UI.getInstance().sS%2 == 0){ UI.getInstance().startStop.setName("START"); UI.getInstance().change.setEnabled(true); } } public void setStartListener(StartHandler e){ this.startStop.addActionListener(e); } sS is an int that increments every time the button startStop is clicked. change is also a button.

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  • Ubuntu 12.4 - Terminal - Huge/Large text on each command line [closed]

    - by gotqn
    Possible Duplicate: Is it possible to change my terminal window prompt text? I have been using "Ubuntu 12.4" for few days now (no previous Linux experiences at all) and I have noticed that the symbols on each command line more then this in many examples in the network. For example, I have: And I want to remove the "gotqn-System-Product-Name" part, because it is taking too much space? What should I do to change this?

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  • How to deserialize implementation classes in OSGi

    - by Daniel Schneller
    In an eRCP OSGi based application the user can push a button and go to a lock screen similar to that of Windows or Mac OS X. When this happens, the current state of the application is serialized to a file and control is handed over to the lock screen. In this mobile application memory is very tight, so we need to get rid of the original view/controller when the lock screen comes up. This works fine and we end up with a binary serialized file. Once the user logs back in, the file is read in again and the original state of the application restored. This works fine as well, except when the controller that was serialized contained a reference to an object which comes from a different bundle. In my concrete case the original controller (from bundle A) can call a web service and gets a result back. Nothing fancy, just some Strings and Numbers in a simple value holder class. However the controller only sees this as a Result interface; the actual runtime object (ResultImpl) is defined and created in a different bundle (bundle B, the webservice client implementation) and returned via a service call. When the deserialization now tries to thaw the controller from the file, it throws a ClassNotFound exception, complaining about not being able to deserialize the result object, because deserialization is called from bundle A, which cannot see the ResultImpl class from bundle B. Any ideas on how to work around that? The only thing I could come up with is to clone all the individual values into another object, defined in the controller's bundle, but this seems like quite a hassle.

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  • SSH: Configure ssh_config to use specific key file for a specific server fingerprint

    - by Penthi
    I have a key based login for a server. The IP and DNS of the server can change, because it is hosted on Amazon. Is there a way to configure the ssh client config to use the specific key file for this server only, when the fingerprint of the server matches? In other words: Normaly servers are matched by IP or DNS in the ssh client config. I want to do this by fingerprint, becaus IP and DNS can change.

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