Search Results

Search found 4421 results on 177 pages for 'dynamically'.

Page 41/177 | < Previous Page | 37 38 39 40 41 42 43 44 45 46 47 48  | Next Page >

  • java class creation dynamically and make it accessible across the network different jvms i.e. serial

    - by inj.rav
    Hi. I have a requirement of creating java classes dynamically and make it accessible different jvms across the network. I tried to use reflection and javassist tool,but nothing worked. Let me explain the scenario we are using Coherence distributed cache. It has a power of doing aggregation/filtering in parallel across the cluster. For example if a class has [dynamic class] has amount variable and getAmount/setAmount methods. Then if we execute COHERENCE queries, it will start process in parallel across the cluster. I tried to create classes at run time by using javassist and reflection. I am able to access it from single JVM, but when I tried to access the same class from other jvm [through coherence cluster]. I am getting exception of class not found [as remote jvm is not having idea of this class].I can over come this by creating same class dynamically on remote jvm also and access the methods. But coherence in built methods/functions are not able to find the class. could some one help me on this matter

    Read the article

  • Dynamically writing out li with jquery. Element is not clickable after being written

    - by estern
    I have have a a function that when a checkbox is checked i dynamically write out an li into a ol that is empty. Code: $(":checkbox").click(function() { var checkedState = $(this).is(':checked'); if (checkedState == true) { var productName = $(this).attr("title"); $("#selectedProductsList").append("<li class=\"productList " + this + "\"><p class=\"removeIcon\"><img src=\"images/remove-icon.png\" alt=\"Remove Product\" /></p><span class=\"productName\">"+ productName +"</span></li>"); }; }); Then when that writes out there is a remove icon that will remove the item from the ol when clicked. This remove icon has a class of removeIcon which can be seen in the dynamic li above. I have a function that processes the remove call and then does some actions: Code: $('.removeIcon').click(function() { alert("starting"); }); Right now i have the remove action just trying to alert a message that it got called. But it seems that it is not getting into the function. Is there a certain way that i need to access these dynamic li's other then the .click method? I saw this post: Dynamically Inserted DOM Elements are not Clickable using $.click() Where they added .live vs .click but this doesn't seem to work either. Any ideas?

    Read the article

  • Why would dynamically changing the stroke type of a GestureOverlayView cause unusual behaviour?

    - by Rob Kent
    I recently introduced multi-stroke gestures into my application. This is a preference so I set the StrokeType dynamically in Activity.OnCreate. What I have discovered is that if you change the StrokeType so that it is different to the setting in the layout file, it changes the behaviour of the GestureOverlayView in the following way. The normal behaviour is that you draw a gesture and it stays on the screen after it is drawn. When you change the stroke type dynamically however, any gesture drawn on the screen disappears immediately after the OnGestureEnded event has fired. I reloaded the sample GesturesBuilder application and confirmed it has the same problem if you add the second line shown here: GestureOverlayView overlay = (GestureOverlayView) findViewById(R.id.gestures_overlay); overlay.setGestureStrokeType(GestureOverlayView.GESTURE_STROKE_TYPE_SINGLE); overlay.addOnGestureListener(new GesturesProcessor()); } The default in the layout is MULTIPLE but changing it to single changes the behaviour. If you keep the above line but set it to what it already is, the behaviour is not affected. Is this a bug in the Android gestures library and does anyone know a workaround? Note that this is on an HTC Magic so it could also be a handset issue.

    Read the article

  • Adding UIView on top of all views dynamically during runtime?

    - by Easwaramoorthy Kanagaraj
    Team, I am trying to bring a menu in top of all visible views during runtime. This menu should be easily addable and removable dynamically in certain conditions. To do this, I have tried adding a button view to the UIWindow as a subview during runtime. UIButton *button = [UIButton buttonWithType:UIButtonTypeRoundedRect]; [button addTarget:self action:nil forControlEvents:UIControlEventTouchDown]; [button setTitle:@"Show View" forState:UIControlStateNormal]; button.frame = CGRectMake(80.0, 210.0, 160.0, 40.0); [window addSubview:button]; [window makeKeyAndVisible]; [window bringSubviewToFront:button]; But it doesnt worked. Also I have tried to place this button in the root view controller, but no luck again. Edit - Note: This code is not from a UIViewController. I am trying to build a library this will be in that library code. Use case be like you could post NSNotification to enable and disable this menu dynamically during runtime. Please suggest. Thanks !

    Read the article

  • How to add Button to WPF Datagrid column dynamically ?

    - by Ramanji
    Hi .. Is there any way to dynamically add a button control(along with column name) to WPFDataGrid column,?? By clicking on header button,pop-up will open . this button generation is dynamic one ,which will be decided from code-behind, for some column headers need to add,for some not needed to add.

    Read the article

  • How can I load style resources from a dynamically loaded Silverlight application (XAP)?

    - by Tom
    I've followed Tim Heuer's video for dynamically loading other XAP's (into a 'master' Silverlight application), as well as some other links to tweak the loading of resources and am stuck on the particular issue of loading style resources from within the dynamically loaded XAP (i.e. the contents of Assets\Styles.xaml). When I run the master/hosting applcation, it successfully streams the dynamic XAP and I can read the deployment info etc. and load the assembly parts. However, when I actuall try to create an instance of a form from the Dynamic XAP, it fails with Cannot find a Resource with the Name/Key LayoutRootGridStyle which is in it's Assets\Styles.xaml file (it works if I run it directly so I know it's OK). For some reason these don't show up as application resources - not sure if I've totally got the wrong end of the stick, or am just missing something? Code snippet below (apologies it's a bit messy - just trying to get it working first) ... '' # Here's the code that reads the dynamic XAP from the web server ... '' #... wCli = New WebClient AddHandler wCli.OpenReadCompleted, AddressOf OpenXAPCompleted wCli.OpenReadAsync(New Uri("MyTest.xap", UriKind.Relative)) '' #... '' #Here's the sub that's called when openread is completed '' #... Private Sub OpenXAPCompleted(ByVal sender As Object, ByVal e As System.Net.OpenReadCompletedEventArgs) Dim sManifest As String = New StreamReader(Application.GetResourceStream(New StreamResourceInfo(e.Result, Nothing), New Uri("AppManifest.xaml", UriKind.Relative)).Stream).ReadToEnd Dim deploymentRoot As XElement = XDocument.Parse(sManifest).Root Dim deploymentParts As List(Of XElement) = _ (From assemblyParts In deploymentRoot.Elements().Elements() Select assemblyParts).ToList() Dim oAssembly As Assembly = Nothing For Each xElement As XElement In deploymentParts Dim asmPart As AssemblyPart = New AssemblyPart() Dim source As String = xElement.Attribute("Source").Value Dim sInfo As StreamResourceInfo = Application.GetResourceStream(New StreamResourceInfo(e.Result, "application/binary"), New Uri(source, UriKind.Relative)) If source = "MyTest.dll" Then oAssembly = asmPart.Load(sInfo.Stream) Else asmPart.Load(sInfo.Stream) End If Next Dim t As Type() = oAssembly.GetTypes() Dim AppClass = (From parts In t Where parts.FullName.EndsWith(".App") Select parts).SingleOrDefault() Dim mykeys As Array If Not AppClass Is Nothing Then Dim a As Application = DirectCast(oAssembly.CreateInstance(AppClass.FullName), Application) For Each strKey As String In a.Resources.Keys If Not Application.Current.Resources.Contains(strKey) Then Application.Current.Resources.Add(strKey, a.Resources(strKey)) End If Next End If Dim objectType As Type = oAssembly.GetType("MyTest.MainPage") Dim ouiel = Activator.CreateInstance(objectType) Dim myData As UIElement = DirectCast(ouiel, UIElement) Me.splMain.Children.Add(myData) Me.splMain.UpdateLayout() End Sub '' #... '' # And here's the line that fails with "Cannot find a Resource with the Name/Key LayoutRootGridStyle" '' # ... System.Windows.Application.LoadComponent(Me, New System.Uri("/MyTest;component/MainPage.xaml", System.UriKind.Relative)) '' #... any thoughts?

    Read the article

  • How to build a web site which gives a sub-domain dynamically to every registered user?

    - by coderex
    Suppose i have a site and i wish to give a sub-domain for each registered users. like my site http://site.com/ and the test-user is a user registered on my site and site want to make sub-domain for that user. Like http://test-user.site.com Like http://test-user1.site.com for test-user1. Hop you understood the requirement. How can i create a sub-domain using my sites back-end. or dynamically while register

    Read the article

  • Is it possible to dynamically discover tables in an Entity Framework model ?

    - by Scott Davies
    Hi, I have co-workers working on an Entity Framework model that changes structure (entities), over time as software development progresses. I've written some utilities that interact with the tables within the model, but I'd like to have the code dynamically discover the tables. Is there a way I can do this ? Perhaps with ADO.NET to get the table names and then store them in a collection ? Thanks, Scott

    Read the article

  • Dynamically Forming a JSON object traversion without using eval.

    - by Matt Willhite
    Given I have the following: (which is dynamically generated and varies in length) associations = ["employer", "address"]; Trying to traverse the JSON object, and wanting to form something like the following: data.employer.address or data[associations[0]][association[1]] Without doing this: eval("data."+associations.join('.')); Finally, I may be shunned for saying this, but is it okay to use eval in an instance like this? Just retrieving data.

    Read the article

  • Which languages are dynamically typed and compiled (and which are statically typed and interpreted)?

    - by Skilldrick
    In my reading on dynamic and static typing, I keep coming up against the assumption that statically typed languages are compiled, while dynamically typed languages are interpreted. I know that in general this is true, but I'm interested in the exceptions. I'd really like someone to not only give some examples of these exceptions, but try to explain why it was decided that these languages should work in this way.

    Read the article

  • It's possible to create variable to hold fields of class dynamically???

    - by yossharel
    hi all, In my 'Person' class, I have some fields like 'firstname','lastname','nickname' and so on. I want to write code to search dynamically, sometimes by 'firstname' and sometimes by 'nickname' field. The code I want to write, should be like this: Object someVariable = "firstname"; Person result = ListOfPerson.Where(p => p.someVariable = "exp").FirstOrDefault(); Can anyone Know if it's possible?

    Read the article

  • onselect in one combo it changes data dynamically in other combo?

    - by ajay
    Hello sir I am new to the jsp and ajax world. my problem is If i select one combo option then it should change the other combo options dynamically without submit button press. for example if i select the country then it should shows their states in other combo. I am using servlet & JSP and MS-ACCESS as backend. please reply as soon as possible. THANKING YOU....

    Read the article

  • How to format and add new numbers dynamically to hidden field?

    - by Bartek
    I get from server into client side only pure number IDs, how to add dynamically it to html hidden field so that looks like array or JSON format (I mean: ["32","33","34"]), so that in next step I can receive on serwer and parse? Hidden field contains on start only blank brackets []. My current code override hidden field from [] to e.g. "32": $("#myHiddenField").val(JSON.stringify(data.result[0].newid));

    Read the article

  • Dynamically loading jQuery library from a custom component and ensuring only one instance.

    - by Paul Lucas
    Say I have a web component that uses jQuery and I want to distribute it as a packaged component. I need a way to ensure that the jQuery library is available on or after the page loads, but I also want to check that the containing html page, or another unknown component that may reference jQuery hasn't already added the library to the page. At the moment the best example I've seen is this http://www.squidoo.com/load-jQuery-dynamically It would need a little tweaking, but I was wondering if there were any other best practices.

    Read the article

  • How do I dynamically reference incremented properties in C#?

    - by Jeff Blankenburg
    I have properties called reel1, reel2, reel3, and reel4. How can I dynamically reference these properties by just passing an integer (1-4) to my method? Specifically, I am looking for how to get an object reference without knowing the name of the object. In Javascript, I would do: temp = eval("reel" + tempInt); and temp would be equal to reel1, the object. Can't seem to figure this simple concept out in C#.

    Read the article

  • How can I dynamically hide a button from a view?

    - by jpm
    I would like to dynamically hide a button in one of my views, depending on a certain condition. I tried adding some code to the view controller's -viewWillAppear method, to make the button hidden before displaying the actual view, but I still don't know how to do that. I have a reference to the button through an IBOutlet, but I'm not sure how to move forward from here. For reference, this is a UIBarButtonItem instance.

    Read the article

  • How do I Print a dynamically created Flex component/chart that is not being displayed on the screen?

    - by Adam Jones
    I have a several chart components that I have created in Flex. Basically I have set up a special UI that allows the user to select which of these charts they want to print. When they press the print button each of the selected charts is created dynamically then added to a container. Then I send this container off to FlexPrintJob. i.e. private function prePrint():void { var printSelection:Box = new Box(); printSelection.percentHeight = 100; printSelection.percentWidth = 100; printSelection.visible = true; if (this.chkMyChart1.selected) { var rptMyChart1:Chart1Panel = new Chart1Panel(); rptMyChart1.percentHeight = 100; rptMyChart1.percentWidth = 100; rptMyChart1.visible = true; printSelection.addChild(rptMyChart1); } print(printSelection); } private function print(container:Box):void { var job:FlexPrintJob; job = new FlexPrintJob(); if (job.start()) { job.addObject(container, FlexPrintJobScaleType.MATCH_WIDTH); job.send(); } } This code works fine if the chart is actually displayed somewhere on the page but adding it dynamically as shown above does not. The print dialog will appear but nothing happens when I press OK. So I really have two questions: Is it possible to print flex components/charts when they are not visible on the screen? If so, how do I do it / what am I doing wrong? UPDATE: Well, at least one thing wrong is my use of the percentages in the width and height. Using percentages doesn't really make sense when the Box is not contained in another object. Changing the height and width to fixed values actually allows the printing to progress and solves my initial problem. printSelection.height = 100; printSelection.width = 100; But a new problem arises in that instead of seeing my chart, I see a black box instead. I have previously resolved this issue by setting the background colour of the chart to #FFFFFF but this doesn't seem to be working this time. UPDATE 2: I have seen some examples on the adobe site that add the container to the application but don't include it in the layout. This looks like the way to go. i.e. printSelection.includeInLayout = false; addChild(printSelection);

    Read the article

< Previous Page | 37 38 39 40 41 42 43 44 45 46 47 48  | Next Page >