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  • SP Gridview link button column not working

    - by Dilse Naaz
    Hi I have one sharepoint custom page application which is rendering from a user control. In the user control page, i had used SPGridview for displaying data. My first column is Title Column (link button column), when the user click on the link, then one popup window will open with corresponding data. But the problem is the link button is not working properly. But this application is working as fine in asp.net application. My code is shown below.. <asp:UpdatePanel runat="server" ID="UpdatePanel2"> <ContentTemplate> <SharePoint:SPGridView ID="dgApplicationBox" CellPadding="0" Height="100%" runat="server" ForeColor="Black" Font-Size="10px" Font-Names="Verdana" AutoGenerateColumns="False" AllowPaging="True" Width="100%" BorderStyle="None" BorderWidth="0px" PageSize="10" BorderColor="White" BackColor="White" OnRowDataBound="dgApplicationBox_RowDataBound" DataKeyNames="ApplicationID" OnSelectedIndexChanged="dgApplicationBox_SelectedIndexChanged" OnPageIndexChanging="dgApplicationBox_PageIndexChanging" CssClass="ms-listviewtable" AlternatingRowStyle-CssClass="ms-alternating"> <SelectedRowStyle Font-Bold="True" ForeColor="Black" BackColor="#CE5D5A"></SelectedRowStyle> <EditRowStyle Font-Size="10px" Font-Names="Verdana,Arial,Helvetica,sans-serif"></EditRowStyle> <HeaderStyle Font-Size="11px" Height="20px" Font-Bold="True" ForeColor="Black" BackColor="#E7E8EC"> </HeaderStyle> <PagerStyle HorizontalAlign="Center" ForeColor="#414E61" Font-Size="5px" Font-Names="arial" Height="10px" BackColor="#EBF3FF"></PagerStyle> <RowStyle /> <Columns> <asp:TemplateField HeaderText="Title" HeaderStyle-CssClass="ms-vb"> <ItemTemplate> <asp:LinkButton ID="lbtnSubject" Text='<%# Bind("UDF5") %>' runat="server" OnClick="lbtnSubject_Click"></asp:LinkButton> </ItemTemplate> <HeaderStyle HorizontalAlign="Left" CssClass="ms-vh2" Font-Bold="true" /> <ItemStyle HorizontalAlign="Left" CssClass="ms-vb2" /> </asp:TemplateField> <asp:TemplateField HeaderText="Request No."> <ItemTemplate> <asp:Label ID="lblReqNo" Text='<%# Bind("UDF1") %>' runat="server" /> </ItemTemplate> <HeaderStyle HorizontalAlign="Left" CssClass="ms-vh2" Font-Bold="true" /> <ItemStyle HorizontalAlign="Left" CssClass="ms-vb2" /> </asp:TemplateField> <asp:BoundField DataField="CreatedOn" HeaderText="Created On" DataFormatString="{0:MM/dd/yyyy}" HeaderStyle-HorizontalAlign="Left" ItemStyle-HorizontalAlign="Left"> <HeaderStyle CssClass="ms-vh2" Font-Bold="true"></HeaderStyle> <ItemStyle CssClass="ms-vb2"></ItemStyle> </asp:BoundField> <asp:BoundField DataField="Name" HeaderText="Form Type" HeaderStyle-HorizontalAlign="Left" ItemStyle-HorizontalAlign="Left"> <HeaderStyle CssClass="ms-vh2" Font-Bold="true"></HeaderStyle> <ItemStyle CssClass="ms-vb2"></ItemStyle> </asp:BoundField> <asp:TemplateField HeaderText="History"> <HeaderStyle CssClass="ms-vh2" Font-Bold="true"></HeaderStyle> <ItemStyle HorizontalAlign="Center" VerticalAlign="Middle" Width="21px" CssClass="ms-vb2"> </ItemStyle> <ItemTemplate> <asp:LinkButton ID="lbtnView" runat="server" OnClick="lbtnView_Click" >View</asp:LinkButton> </ItemTemplate> </asp:TemplateField> <asp:TemplateField HeaderText="Application Id" Visible="False"> <ItemTemplate> <asp:Label ID="lblApplicationId" runat="server" Text='<%# Bind("ApplicationId") %>'></asp:Label> </ItemTemplate> <HeaderStyle HorizontalAlign="Left" CssClass="ms-vh2" Font-Bold="true" /> <ItemStyle HorizontalAlign="Left" CssClass="ms-vb2" /> </asp:TemplateField> </Columns> </SharePoint:SPGridView> </ContentTemplate> </asp:UpdatePanel> when the user click on the link button, this code will works.. try { clearSession(); Session["DigitalSignature"] = null; Button btnDetails = sender as Button; DataTable dt = (DataTable)dgApplicationBox.DataSource; GridViewRow gvRow = (GridViewRow)(sender as LinkButton).Parent.Parent; Session["AppId"] = ((Label)gvRow.FindControl("lblApplicationId")).Text; string subject = ((LinkButton)gvRow.FindControl("lbtnSubject")).Text; WFInfo objWFInfo = new WFInfo(); objWFInfo.InitWorkflowProperty(Convert.ToInt32(Session["AppId"].ToString()), Session["CurrentUser"].ToString()); Session["FormId"] = objWFInfo.FormID.ToString(); string strFilname = objWFInfo.GetFormName(objWFInfo.ApplicationCategoryID.ToString()); string WindowName = strFilname; strFilname += ".aspx"; Session["CategoryId"] = objWFInfo.ApplicationCategoryID.ToString(); //pnlSubmitModal_ModalPopupExtender.Show(); ScriptManager.RegisterStartupScript(this, this.GetType(), "starScript", "popUpWindow('" + strFilname + "?tittle=" + subject + "', 800, 690,'" + WindowName + "');", true); this.Controls.Add(new LiteralControl("<script>alert('hi');</script>")); if (Session["CurrentUser"] != null) { ApplicationForm objApplication = new ApplicationForm(); objApplication.markRead(Convert.ToInt32(Session["AppId"].ToString()), Session["CurrentUser"].ToString()); } bindFolderData(); } If i click on the link button, there will be only post back occuring. but not the popup window open.. Please help me for resolving this problem. thanks in advance..

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  • jquery ajax call from link loaded with ajax

    - by Jay
    //deep linking $("document").ready(function(){ contM = $('#main-content'); contS = $('#second-content'); $(contM).hide(); $(contM).addClass('hidden'); $(contS).hide(); $(contS).addClass('hidden'); function loadURL(URL) { //console.log("loadURL: " + URL); $.ajax({ url: URL, type: "POST", dataType: 'html', data: {post_loader: 1}, success: function(data){ $(contM).html(data); $(contM).animW(); } }); } // Event handlers $.address.init(function(event) { //console.log("init: " + $('[rel=address:' + event.value + ']').attr('href')); }).change(function(event) { $.ajax({ url: $('[rel=address:' + event.value + ']').attr('href'), type: "POST", dataType: 'html', data: {post_loader: 1}, success: function(data){ $(contM).html(data); $(contM).animW(); }}); //console.log("change"); }) $('.update-main a').live('click', function(){ loadURL($(this).attr('href')); }); $(".update-second a").live('click', function() { var link = $(this); $.ajax({ url: link.attr("href"), dataType: 'html', data: {post_loader: 1}, success: function(data){ $(contS).html(data); $(contS).animW(); }}); }); }); I'm using jquery and the 'addresses' plugin to load content with ajax and maintain pagination. The problem I'm having is some content loads with links which are intended to load content into a secondary window. I'm using the .live() method to allow jquery to listen for new links loaded into the primary content div. This works until the .ajax() method is called for these fresh links loaded with ajax, where the method begins, but follows the original link before data can be received. I'm assuming the problem is in the client-side scripting, but it may be a problem with the call made to the server. I'm using the wordpress loop to parse the url and generate the html loaded via jquery. Thanks for any tips!

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  • (Enterprise GlassFish v3 build 11) Communication link problem (MySQL DB)

    - by user312853
    I get a communication link failure while application tries to establish a connection with DB. [#|2010-04-08T20:09:57.825+0300|SEVERE|glassfish3.0|javax.enterprise.system.std.com.sun.enterprise.v3.services.impl|_ThreadID=24;_ThreadName=Thread-1;|Cannot connect to database server = com.mysql.jdbc.exceptions.jdbc4.CommunicationsException: Communications link failure The last packet sent successfully to the server was 0 milliseconds ago. The driver has not received any packets from the server.|#] Precisely at this string: Statement s = conn.createStatement(); where conn is defined as follows: private static java.sql.Connection conn; For this app I have set a connection pool with default parameters and currently it (app) uses both JPA and direct JDBC queries. Recreation of connection pool gave nothing, connection pool ping gave next message: Ping Connection Pool for pool is Failed. Ping failed Exce ption - Connection could not be allocated because: Communications lin k failure%%%EOL%%%%%%EOL%%%The last packet sent successfully to the s erver was 0 milliseconds ago. The driver has not received any packets from the server. Please check the server.log for more details.%%%EOL %%%Ping failed Exception - Connection could not be allocated because: Communications link failure and flushing the connection pool gave: com.sun.enterprise.admin.cli.CommandException: remote failure: Failed to flush connection pool ... However I can connect to the database from a terminal. Besides I have the same app working on my local machine with identical connection pool settings. Any one has an idea on whats going on or how to solve the trouble?

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  • In wicket, combine wicket:link with IAuthorizationStrategy

    - by seanizer
    Hi everybody. I use an IAuthorizationStrategy in wicket to limit access to certain pages. However, I also use html menus like this one: <div class="siteMenu"> <wicket:link> <a href="Page1.html" class="siteMenuLink"> <wicket:message key="pages.page1.title" /> </a> <a href="Page2.html" class="siteMenuLink"> <wicket:message key="pages.page2.title" /> </a> <a href="Page3.html" class="siteMenuLink"> <wicket:message key="pages.page3.title" /> </a> </wicket:link> </div> , that are automatically picked up and expanded using the wicket:link mechanism (like here: http://wicket.apache.org/examplenavomatic.html ). However, the IAuthorizationStrategy may not allow one or more of these target pages, so I may end up either with lots of links that lead to "permission denied" pages or lots of deactivated links (i.e. em tags or the like), neither of which is pretty. I could of course write an IComponentInstantiationListener that checks all BookmarkableLinks to see whether their target is accessible through the IAuthorizationStrategy and renders them invisible otherwise, but I wonder if there is an out-of-the-box solution to this problem. For clarification: I only use the isInstantiationAuthorized() method of IAuthorizationStrategy.

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  • Button_to uses POST Link_to uses GET, why? ROR

    - by JZ
    I've ran into a ror problem using the link_to. Why does my link to use the GET method and my button_to use the POST method, after I specified my "method"="post" within the link_to parameters? View: <%= button_to "pdf", :action => 'getquote' %> <%= link_to 'pdf', {:controller => 'inventories', :action => 'getquote', :method => :post } %> Controller Method: def getquote @cart = find_cart respond_to do |format| format.pdf end end Terminal Output (Button/Link, respectively): Processing InventoriesController#getquote (for 127.0.0.1 at 2010-01-30 01:38:02) [POST] Parameters: {"action"=>"getquote", "authenticity_token"=>"D2cwnHyTHgomdUM3wXBBXlOe4NQLmv1Srn0paLbExpQ=", "controller"=>"inventories"} Processing InventoriesController#show (for 127.0.0.1 at 2010-01-30 01:39:07) [GET] Parameters: {"method"=>"post", "action"=>"show", "id"=>"getquote", "controller"=>"inventories"}

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  • Link to Hotmail / Windows Live email compose -- maintaining BCC

    - by Curtis Gibby
    My app creates a mailto-esque link that takes the end user to a Hotmail compose screen with various attributes pre-filled. Most of the functionality I need is working: to, cc, subject, body. However, Hotmail seems to be stripping out any BCC attributes that I pass into the URL. For example, this link works as advertised: http://mail.live.com/mail/EditMessageLight.aspx?n=&[email protected]&[email protected];%[email protected]&subject=the%20subject&body=the%20body I get the one email address in the To field and two in the CC field. But when I try the exact same URL except substituting "bcc" for "cc", the two addresses are nowhere to be found. http://mail.live.com/mail/EditMessageLight.aspx?n=&[email protected]&[email protected];%[email protected]&subject=the%20subject&body=the%20body This link format is posted all over the web (along with a variation like http://mail.live.com/default.aspx?rru=compose%3f[attributes] ), but none of the various settings that I've tried actually work to bring in the BCC addresses. I need the BCC so that the email recipients are not given each others' email addresses. My versions of this url for regular old mailto, along with Gmail and Yahoo Mail, work perfectly. Surprise surprise.

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  • Aligning a link to the bottom right of a table...in css

    - by IP
    I need to align "Click here" to the bottom right of this table...but in CSS it seems impossible Adding the link as a row or into the footer of the table is no an option <html xmlns="http://www.w3.org/1999/xhtml" > <head> <title></title> <style type="text/css"> #link { float:right; } div { border:solid black; } table { border: solid red; } </style> </head> <body> <div> <table> <tr> <td>Fish fish fish fish fish fish fish fish fish fish fish fish fish fish fish fish fish fish fish fish fish</td> </tr> </table> <a href="." id="link">Click me</a> </div> </body> </html> Any ideas?

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  • PHP Dynamic Breadcrumb, small modification

    - by Adrian M.
    Hello, I got this code from someone and it works very well, I just want to remove the link from the last element of the array: //get rid of empty parts $crumbs = array_filter($crumbs); $result = array(); $path = ''; foreach($crumbs as $crumb){ $path .= '/' . $crumb; $name = ucfirst(str_replace(array(".php","_"),array(""," "), $crumb)); $result[] = "<a href=\"$path\">$name</a>"; } print implode(' > ', $result); This will output for example: Content Common File I just want a to remove the link from the last item - "File" to be just plain text.. I tried myself to count the array items and then if the array item is the last one then to print as plain text the last item.. but I'm still noob, I haven't managed to get a proper result.. Thank you!

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  • Associated models in Rails?

    - by dannymcc
    Hi Everyone, In my rails application I have two models called Kases and Notes. They work in the same way comments do with blog posts, I.e. each Kase entry can have multiple notes attached to it. I have got everything working, but for some reason I cannot get the destroy link to work for the Notes. I think I am overlooking something that is different with associated models to standard models. Notes Controller class NotesController < ApplicationController # POST /notes # POST /notes.xml def create @kase = Kase.find(params[:kase_id]) @note = @kase.notes.create!(params[:note]) respond_to do |format| format.html { redirect_to @kase } format.js end end end Kase Model class Kase < ActiveRecord::Base validates_presence_of :jobno has_many :notes Note Model class Note < ActiveRecord::Base belongs_to :kase end In the Kase show view I call a partial within /notes called _notes.html.erb: Kase Show View <div id="notes"> <h2>Notes</h2> <%= render :partial => @kase.notes %> <% form_for [@kase, Note.new] do |f| %> <p> <h3>Add a new note</h3> <%= f.text_field :body %><%= f.submit "Add Note" %> </p> <% end %> </div> /notes/_note.html.erb <% div_for note do %> <div id="sub-notes"> <p> <%= h(note.body) %><br /> <span style="font-size:smaller">Created <%= time_ago_in_words(note.created_at) %> ago on <%= note.created_at %></span> </p> <%= link_to "Remove Note", kase_path(@kase), :confirm => 'Are you sure?', :method => :delete, :class => 'important' %> </div> <% end %> As you can see, I have a Remove Note destroy link, but that destroys the entire Kase the note is associated with. How do I make the destroy link remove only the note? <%= link_to "Remove Note", kase_path(@kase), :confirm => 'Are you sure?', :method => :delete, :class => 'important' %> Any help would, as always, be greatly appreciated! Thanks, Danny

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  • PHP Dynamic Breadcrumb

    - by Adrian M.
    Hello, I got this code from someone and it works very well, I just want to remove the link from the last element of the array: //get rid of empty parts $crumbs = array_filter($crumbs); $result = array(); $path = ''; foreach($crumbs as $crumb){ $path .= '/' . $crumb; $name = ucfirst(str_replace(array(".php","_"),array(""," "), $crumb)); $result[] = "<a href=\"$path\">$name</a>"; } print implode(' > ', $result); This will output for example: Content Common File I just want a to remove the link from the last item - "File" to be just plain text.. I tried myself to count the array items and then if the array item is the last one then to print as plain text the last item.. but I'm still noob, I haven't managed to get a proper result.. Thank you!

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  • Does anyone knows the algorithm how Facebook detects the images when adding a link

    - by Edelcom
    When you add a link to your Facebook page, after some processing, Facebook presents you a next/prev button to choose an image linked to the url your are inserting. Obviously, Facebook reads the html-page and displays the images found on the url you insert. Does anyone knows what algorithm Facebook uses to decide what images to show ? If I insert a link to : http://www.staplijst.be/lachende-wandelaars-aalter-aktivia-003.asp, only 11 images are detected. The one I want, the one at the top right corner, is not included in the list. If I insert a link to http://www.staplijst.be/stichting-kennedymars-rijsbergen-zundert-nederland-knblo-nl-81996.asp, 19 images are displayed (including the one I want (the one at the right top corner of the text area). Both pages are build using asp code but are functionally the same. I thought that it has something to do with the image size, but can't find any deciding factor there. I will investigate some furhter, because if I know what Facebook is looking for, I can make sure that the correct images are included on the page (since they are dynamic pages build with classic asp). But if anyone has any idea ? Help would be appreciated.

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  • Getting broken link error whle Using App Engine service accounts

    - by jade
    I'm following this tutorial https://developers.google.com/bigquery/docs/authorization#service-accounts-appengine Here is my main.py code import httplib2 from apiclient.discovery import build from google.appengine.ext import webapp from google.appengine.ext.webapp.util import run_wsgi_app from oauth2client.appengine import AppAssertionCredentials # BigQuery API Settings SCOPE = 'https://www.googleapis.com/auth/bigquery' PROJECT_NUMBER = 'XXXXXXXXXX' # REPLACE WITH YOUR Project ID # Create a new API service for interacting with BigQuery credentials = AppAssertionCredentials(scope=SCOPE) http = credentials.authorize(httplib2.Http()) bigquery_service = build('bigquery', 'v2', http=http) class ListDatasets(webapp.RequestHandler): def get(self): datasets = bigquery_service.datasets() listReply = datasets.list(projectId=PROJECT_NUMBER).execute() self.response.out.write('Dataset list:') self.response.out.write(listReply) application = webapp.WSGIApplication( [('/listdatasets(.*)', ListDatasets)], debug=True) def main(): run_wsgi_app(application) if __name__ == "__main__": main() Here is my app.yaml file code application: bigquerymashup version: 1 runtime: python api_version: 1 handlers: - url: /favicon\.ico static_files: favicon.ico upload: favicon\.ico - url: .* script: main.py And yes i have added app engine service account name in google api console Team tab with can edit permissions. When upload the app and try to access the link it says Oops! This link appears to be broken. Ealier i ran this locally and tried to access it using link localhost:8080.Then i thought may be running locally might be giving the error so i uploaded my code to http://bigquerymashup.appspot.com/ but still its giving error.

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  • helink dll to executable

    - by user353707
    How can I link the .dll file to an executable? I do not have the source for the dll nor executable. The two files operate on a 64-bit system. When the executable is ported from another system, I get "The application failed to initialize properly (0xc0150002). Click OK to Terminate the program. Here's a list of the files \l2server\L2Server.exe \l2server\l2serverx64-dll.dll \l2server\Sabotage64.dll L2Server requires l2serverx64-dll.dll to execute. What i'm trying to do is to link Sabotage64.dll with L2Server.exe I used CFF Explorer as a rebuilder to no luck :(

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  • Javascript/jQuery: programmatically follow a link

    - by Dan
    In Javascript code, I would like to programmatically cause the browser to follow a link that's on my page. Simple case: <a id="foo" href="mailto:[email protected]">something</a> function goToBar() { $('#foo').trigger('follow'); } This is hypothetical as it doesn't actually work. And no, triggering click doesn't do it. I am aware of window.location and window.open but these differ from native link-following in some ways that matter to me: a) in the presence of a <base /> element, and b) in the case of mailto URLs. The latter in particular is significant. In Firefox at least, calling window.location.href = "mailto:[email protected]" causes the window's unload handlers to fire, whereas simply clicking a mailto link does not, as far as I can tell. I'm looking for a way to trigger the browser's default handling of links, from Javascript code. Does such a mechanism exist? Toolkit-specific answers also welcome (especially for Gecko).

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  • Making a Function-Activated Link Appear Without Having to Refresh Browser

    - by John
    Hello, I'm trying to use the code below to make the <a href='http://www...com/.../footervote.php'>Vote</a> link appear if a user logs in and a user shows up in the function getEditorsList(). The vote link only appears if the browser is refreshed. Any idea how I could make the vote link appear without having to refresh the browser? Thanks in advance, John index.php: <?php require_once "header.php"; //content include "login.php"; // more content require_once "footer.php"; ?> In header.php: <?php error_reporting(0); session_start(); require_once ('db_connect.inc.php'); require_once ("function.inc.php"); $seed="0dAfghRqSTgx"; $domain = "...com"; $editors = getEditorsList(); foreach($editors as $editor) { $editorids[] = $editor['loginid']; } if(in_array($_SESSION['loginid'], $editorids)) { echo "<div class='footervote'><a href='http://www...com/.../footervote.php'>Vote</a></div>"; } ?> login.php: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } ?>

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  • What am i doing wrong with this in asp.net-mvc?

    - by Pandiya Chendur
    I gave this in my site.master <li><%= Html.ActionLink("Material", "Index", "Material")%></li> But my link doesnt seem to get my material controller Index method... I have this in my global asax file, public static void RegisterRoutes(RouteCollection routes) { routes.IgnoreRoute("{resource}.axd/{*pathInfo}"); routes.MapRoute( "Default", "{controller}/{action}/{id}", new { controller = "Home", action = "Index", id = "" } ); routes.MapRoute( "Default", "{controller}/{action}/{id}", new { controller = "Material", action = "Index", id = "" } ); } My controller: public class MaterialController : Controller { // // GET: /Material/ Material material = new Material(); public ActionResult Index() { var materials = material.FindAllMaterials(); return View(); } } What am i doing wrong.... When i click the link i get The resource cannot be found. error.. Any suggestion...

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  • resend confirm instructions via devise

    - by Paul 'Whippet' McGuane
    what im trying to achieve is that when an admin views a list of members, they can click a link to resend the instructions on how to confirm that members accounts. this is the code im using to try and achieve this = link_to 'Resend Confirmation', confirmation_path(:user => {:email => user.email}), :remote => :true im hoping that this would allow me to pass the users email through to the link have it then sent to that user though the issue im getting is Could not find a valid mapping for {:user=>{:email=>"[email protected]"}}

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  • Pass Element value to $ajax->link in cakephp

    - by TwoThumbs
    I need to pass the value of an element to an $ajax-link without using a form/submit structure. (because I have a dynamically set number of clickable links through which I am triggering the action) I used to do this in Ruby using the Prototype javascript function $F like this: <%= link_to_remote "#{item.to_s}", :url => { :action => :add_mpc }, :with => "'category=' + $F('mpc_category')" -%> But this does not seem to work in Cakephp: <?php echo $ajax->link(substr($vehicle['vehicles']['year'], -2), array('action' => 'add_mpc', 'category' => '$F("mpc_category")'), array('update' => 'results', 'position' => 'top')); ?> PHP sees $F as a variable instead of a call to javascript. I'm not too familiar with Javascript, but is there another way to pass the value of the 'mpc_category' input element to the controller through this link? I have been looking for a couple days and can't find anyone dealing with this specific issue. Thanks for any assistance. Edit: fixed syntax in php statement.

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  • Paypal Sandbox 2014 Non US test account Sign Up proper link

    - by Flood Gravemind
    Ok I had a Paypal Sandbox account a year ago. I am developing a new site for a client and when I try to Login it won't recognize my email address. I tried forgot my password forgot password still nothing. So I guessed that maybe due to inactivity for such a long time they may have deleted my account. So then I try to Sign Up for a new one. I entered my details 3 times now and spent 6 hours trying to figure out what is the proper link to do this. Then I went to another Sandbox link which required me to entered a US Zip code and its a dead end. I am not even sure which Paypal account I signed up for those three times. No email nothing at all. I am a Non US developer and the FAQ link for Non US developers just points to their REST API. Can someone please guide me to the proper Paypal Sandbox Setup for Non US developers including the proper sign up links please. And I know Stackoverflow does not like rants but from my experience dealing with Paypal, GTA 6 should make a satirical Paypal company in their next Game with Paypal Developer Rampage mode for the main protagonist who also happens to be a Developer. EDIT: REST API does not include UK :(

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  • Issues with an image link

    - by user1462362
    Two days ago I spontaneously bought myself a domain. The day before that, I hardly even knew what a domain really was. Since then, I've been trying to teach myself HTML for the very first time. Basically what I'm trying to say is, I'm very new - and will probably be poor in my explanations. I just succeeded in making an 'image-button', sorta. It's where I make a button-like image and then use it as navigation on my website (just like a regular link). My issue is that the link 'border' itself is bigger than the image, so you can press an inch outside the image itself and it will work. How do I make the invisible link 'border' the same size as the button? This is my site: http://www.djeveln.com On the test page (djeveln.com/test) is where I test things. There's the button I'm talking about, in case you can't understand my explanation very well. Here's my HTML: Here is the CSS I use for the image position and size: img.TestButton { /* Dette linker til selve størrelsen av knappen (bildet)*/ position: absolute; width: 100px; height: 75px; top: 400px; right: 250px; } Hope you can help me! :P

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  • CSS: image link, change on hover

    - by AP257
    I have an image that is a link. I want to show a different image when the user hovers over the link. Currently I'm using this code: <a href="http://twitter.com/me" title="Twitter link"> <div id="twitterbird" class="sidebar-poster"></div></a> div.sidebar-poster { margin-bottom: 10px; background-position: center top; background-repeat: no-repeat; width: 160px; } #twitterbird { background-image: url('twitterbird.png'); } #twitterbird:hover { background-image: url('twitterbird_hover.png'); } But I'm having loads of problems: the div isn't picking up the CSS rules (the element just isn't showing the related CSS rules when I view it in Firebug). Perhaps this is because (as I know) this is invalid HTML: you can't put an <a> around a <div>. However, if I switch to <span> then it seems I get bigger problems, because you can't set a height and width on a span reliably. Help! How can I do this better?

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  • PHP & MySQL delete image link problem

    - by IMAGE
    I'm trying to create a delete image link if the image is present and when the user clicks the delete image link it should delete the image. But for some reason this is not working can someone help me fix the delete image link problem? Thanks! Here is the PHP code. if (isset($_POST['delete_image'])) { $img_dir = "../members/" . $user_id . "/images/thumbs/"; $img_thmb = "../members/" . $user_id . "/images/"; $image_name = $row['image']; if(file_exists($img_dir . $image_name)){ if(unlink($img_dir.$image_name) && unlink($img_thmb.$image_name)){ $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli, "DELETE FROM users* WHERE image_id = '.$image_id.' AND user_id = '$user_id'"); }else{ echo '<p class="error">Sorry unable to delete image file!</p>'; } } } if(isset($_POST['image']) || !empty($image)) { echo '<a href="'. $_POST['delete_image'] .'">Delete Image</a>'; }

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  • Samba: share home directories when home directories are symbolic links

    - by Owen
    I have set up a new Ubuntu 9.10 system for five users. In the system is a large LVM volume where all the data is to be kept. The main system disk is not for this purpose, so I attempted to move the home directories using usermod -d /var/data/username -m And started creating my shares for these new home locations. But then I thought: hey, Samba has built-in home directory sharing! So I enabled that, and it didn't work. The shares were not published to the network. Only the share for user 'owen' was published; his folder hadn't been moved. So I thought: maybe Samba home sharing only works for default home locations, so how about I move the home directories back to where they were, and then make them symlinks. root@boxenmkiv:/home# ls -l total 4 lrwxrwxrwx 1 brett brett 25 2010-04-03 08:48 brett -> /var/data/brett/ lrwxrwxrwx 1 carly carly 23 2010-04-03 08:48 carly -> /var/data/carly/ lrwxrwxrwx 1 dave dave 21 2010-04-03 08:48 dave -> /var/data/dave/ lrwxrwxrwx 1 kate kate 23 2010-04-03 08:47 kate -> /var/data/kate/ drwxr-xr-x 4 owen owen 4096 2010-04-03 08:44 owen Like so. Still no go. The only users share which is published to the network is 'owen' who as you can see above has not had his home directory moved. I have also added the following to my smb.conf [global] follow symlinks = yes wide symlinks = yes unix extensions = no With no luck. Am I going about doing this the entirely wrong way? Should I just give up and manually create shares for the users? Thanks in advance.

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  • Cannot change permissions in symlinked dropbox directory in Ubuntu 10.10

    - by Reactor5
    Title pretty much says it all, but here's what I'm doing... ls -l produces this... drwx------ 1 brian brian 4096 2010-12-28 14:19 foldername -rw------- 1 brian brian 0 2010-12-28 15:54 index.html after typing something like chmod o=rx index.html the output of ls -l is the same. This happens whether or not I'm in the original location or the symlink location. However, as a further twist, the output of chmod -v o=rx index.html is the following: mode of `index.html' changed to 0605 (rw----r-x) The location is also being symlinked to by apache. What's going on with my permissions?

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  • Why are symbolic links not working in MySQL?

    - by Eno
    I'm having an issue, I searched a lot but I'm not sure if it's related to a previous security patch. On the last version of MySQL on Debian Lenny ( 5.0.51a-24 ) I need to share one table between two db, those two db are in the same path ( /var/lib/mysql/db1 & db2 ). I created symbolic links for db2 pointing to the table in db1. When I query the same table from db2 I get this : 'ERROR 1030 (HY000): Got error 140 from storage engine' This is how it looks : test-lan:/var/lib/mysql/test3# ls -alh drwx------ 2 mysql mysql 4.0K 2010-08-30 13:28 . drwxr-xr-x 6 mysql mysql 4.0K 2010-08-30 13:29 .. lrwxrwxrwx 1 mysql mysql 28 2010-08-30 13:28 blbl.frm -> /var/lib/mysql/test/blbl.frm lrwxrwxrwx 1 mysql mysql 28 2010-08-30 13:28 blbl.MYD -> /var/lib/mysql/test/blbl.MYD lrwxrwxrwx 1 mysql mysql 28 2010-08-30 13:28 blbl.MYI -> /var/lib/mysql/test/blbl.MYI -rw-rw---- 1 mysql mysql 65 2010-08-30 13:24 db.opt I really need those symlinks, is there a way to make them working like before ? ( old MySQL-server is fine ) Thanks,

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