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  • Sublinear Extra Space MergeSort

    - by hulkmeister
    I am reviewing basic algorithms from a book called Algorithms by Robert Sedgewick, and I came across a problem in MergeSort that I am, sad to say, having difficulty solving. The problem is below: Sublinear Extra Space. Develop a merge implementation that reduces that extra space requirement to max(M, N/M), based on the following idea: Divide the array into N/M blocks of size M (for simplicity in this description, assume that N is a multiple of M). Then, (i) considering the blocks as items with their first key as the sort key, sort them using selection sort; and (ii) run through the array merging the first block with the second, then the second block with the third, and so forth. The problem I have with the problem is that based on the idea Sedgewick recommends, the following set of arrays will not be sorted: {0, 10, 12}, {3, 9, 11}, {5, 8, 13}. The algorithm I use is the following: Divide the full array into subarrays of size M. Run Selection Sort on each of the subarrays. Merge each of the subarrays using the method Sedgwick recommends in (ii). (This is where I encounter the problem of where to store the results after the merge.) This leads to wanting to increase the size of the auxiliary space needed to handle at least two subarrays at a time (for merging), but based on the specifications of the problem, that is not allowed. I have also considered using the original array as space for one subarray and using the auxiliary space for the second subarray. However, I can't envision a solution that does not end up overwriting the entries of the first subarray. Any ideas on other ways this can be done? NOTE: If this is suppose to be on StackOverflow.com, please let me know how I can move it. I posted here because the question was academic.

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  • android customize gallery focus problem

    - by Faisal khan
    Gallery With reference to the following link http://www.anddev.org/novice-tutorials-f8/a-android-widget-gallery-example-t332-60.html In above link they are actually animating selected item of the gallery but i want to change the picture when it is selected, for that i am having following code. Problem is when i use roller ball to scroll gallery from left to right or right to left to right after scroll on image focus automatically shift to next widget. public class SizingGallery extends Gallery{ public SizingGallery(Context context, AttributeSet attrs) { super(context, attrs); } @Override protected boolean getChildStaticTransformation(View child, Transformation t) { t.clear(); ImageView selectedChild = (ImageView) getSelectedView(); ImageView iv = (ImageView) child; BrowseMapCategoryRow cr = (BrowseMapCategoryRow) iv.getTag(); //Following line change the image resource that causing defocus gallery iv.setImageResource((iv == selectedChild)?cr.getSelectedImgSrc():cr.getUnSelectedImgSrc()); return true; } }

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  • Combinatorics grouping problem

    - by Harry Pap
    I'm looking for an algorithm in c# that solves a combinatorics problem: Assume i have the objects 1,2,3,4 I want to get all possible ways to group these object in multiple groups, that each time contain all objects. Order is not important. Example: <1,2,3,4 <1,2 / 3,4 <1,3 / 2,4 <1,4 / 3,2 <1,2,3 / 4 <1,2,4 / 3 <1,3,4 / 2 <2,3,4 / 1 <1 / 2 / 3 / 4 In the first case there is one group that contain all 4 objects. Next are cases with 2 groups that contain all objects in many different ways. The last case is 4 groups, that each one contains only one object.

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  • RSA Factorization problem

    - by dada
    At class we found this programming problem, and currently, we have no idea how to solve it. The positive integer n is given. It is known that n = p * q, where p and q are primes, p<=q and |q-k*p|<10^5 for some given positive integer k. You must find p and q. Input: 35 1 121 1 1000730021 9 Output: 5 * 7 11 * 11 10007 * 100003 It's not a homework, we are just trying to solve some interesting problems. If you have some ideas, please post them here so we can try something, thanks.

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  • GLOBAL problem with javascript

    - by Syom
    There is some problem, i can't understand anyway. look at this code please <script type="text/javascript"> function math(x) { var y; y = x*10; alert(y); } </script> <input type="button" onclick="math(0.011)"> What must be alerted after i click on button? i think 0.11, but no, it alerts 0.10999999999999999 explain please this behavior. thanks in advance

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  • HTML list wrapping problem

    - by Daniel
    I have a HTML list with this style: font-weight: bold; padding: 0px; margin: 0px; list-style-type: none; display: block; width:700px; font-size: 14px; white-space: pre-wrap; and the cells have this style: display: inline; and I have spacer cells between each cell with this style: padding-right: 20px; display: inline; My problem is that when the list is too long for its 700 pixels, it wraps. I want this, but I dont want the objects to be on two separate lines. I have tried the CSS white-space property, but nothing seems to work. Any ideas?

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  • Is it hard problem?

    - by Lukasz Lew
    I can't solve it: You are given 8 integers: A, B, C representing a line on a plane with equation A*x + B*y = C a, b, c representing another line x, y representing a point on a plane The two lines are not parallel therefore divide plane into 4 pieces. Point (x, y) lies inside of one these pieces. Problem: Write a fast algorithm that will find a point with integer coordinates in the same piece as (x,y) that is closest to the cross point of the two given lines. Note: This is not a homework, this is old Euler-type task that I have absolutely no idea how to approach.

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  • Problem with bluetooth service in J2ME don't discoverable

    - by Fran
    Hi! I try to create a service with: LocalDevice localDevice = LocalDevice.getLocalDevice(); localDevice.setDiscoverable(DiscoveryAgent.GIAC); String url = "btl2cap://localhost:"+uuid.toString()+";name="+name+";authorize=true;authenticate=true;encrypt=true"; L2CAPConnectionNotifier notifier = (L2CAPConnectionNotifier)Connector.open(url); ServiceRecord = localDevice.getRecord(notifier); // Set some attributes // ... conn = notifier.acceptAndOpen(); //... I run this code on a Nokia 5800 and Nokia 2760, with 5800 I can see 2760, but not vice versa, I don't know what is the problem, I have think security problems... Any ideas? Thanks!

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  • htaccess hotlinking problem

    - by DesperateWebDev
    Hi! Iam fighting following problem with little success. I want to block hotlinking to images in static folder from other domains than my_domain.com htaccess looks like this: RewriteEngine on RewriteCond %{HTTP_REFERER} !^$ RewriteCond %{HTTP_REFERER} !^http://(www\.)?my_domain\.com [NC] RewriteRule \.(gif|jpe?g|js|css)$ - [F,NC,L] RewriteRule ^(favicon\.ico)$ static/$1 [L] RewriteCond $1 !^(index\.php|static|robots\.txt|7e3b7a5bafcb0fa8e8dfe3ea6aca9186\.txt) RewriteRule ^(.*)$ /index.php/$1 [L] Page is on CodeIgniter and it have static folder so images can be loaded for ex: http://www.mydomain.com/static/somepic.jpg but users are linking from other sites and eat my bandwidth fast. Presented above htaccess doesnt work and I have NO idea why :( Please help!

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  • problem solving [closed]

    - by Suresh S
    Problem Statement The Sports Associations in India (SAI) wants to choose 2 teams of 4 people each to send to Asian games. There are 13 people who want to be members of the teams. The SAI tries grouping them in various ways to see which athletes perform well together. Each grouping gets one test run on the test track and their time is recorded. Your task is to help the SAI choose two disjoint teams of 4 such that the sum of their practice times is minimal. Input There will be several input instances. The first line of each instance gives the total number of practice runs. This will be followed by n lines. Each of those lines will contain 5 numbers: p1 p2 p3 p4 t t is the time taken (in milliseconds) by the team consisting of p1, p2, p3 and p4. The time taken will not be more than 2 minutes. The end of the input will be indicated by a line with n=0. Output Output the best total and the two teams that you choose. If it is impossible to choose two disjoint teams from the test runs given, output -1. Sample Input 6 1 2 3 4 30000 10 11 12 13 15000 5 6 7 8 37800 1 5 10 12 20000 5 6 9 11 43000 1 9 12 13 11000 3 1 4 7 9 10000 3 5 7 11 17890 6 7 12 13 20000 0 Sample Output 45000 -1 Input to the problem 40 2 8 11 9 15532 1 13 11 9 57629 10 12 1 5 43406 6 10 1 2 43904 8 3 4 11 12473 6 12 5 11 19826 3 9 10 11 48347 6 12 13 1 45854 5 4 9 7 34452 9 8 12 2 5596 4 10 2 7 6778 3 6 8 5 32858 13 12 8 6 42457 12 9 2 5 49530 6 8 10 7 51453 1 3 11 9 18620 6 2 5 11 5153 4 1 9 8 37336 10 5 1 12 59524 4 5 3 2 1318 2 13 6 8 7839 12 4 9 5 30697 4 10 13 1 25249 4 2 9 13 52359 8 11 1 9 36437 7 5 11 6 58522 9 1 12 6 58837 7 6 8 5 37826 13 1 11 3 1841 11 3 5 13 50000 2 8 7 12 10137 1 4 12 5 32558 8 5 6 7 39021 1 7 10 13 5979 9 2 11 6 29661 13 12 9 7 7219 12 1 11 9 37354 5 1 10 9 47948 8 1 2 10 11071 2 11 1 8 3074 80 3 5 8 10 37873 1 2 3 5 27633 10 13 3 11 8645 13 1 9 6 2167 5 11 13 8 30862 8 7 9 6 47591 3 11 13 8 33823 2 13 7 5 36668 12 3 11 6 53711 6 13 3 7 52412 3 6 7 5 3850 1 5 11 12 35483 1 7 6 10 50943 11 3 6 8 40191 12 8 13 7 4529 4 10 5 1 43280 4 12 10 5 35142 12 4 5 10 37242 9 7 13 2 2661 3 9 2 10 453 3 8 12 9 12479 3 10 11 5 30047 9 1 11 2 40883 6 5 1 2 8774 11 7 9 1 37701 8 3 4 6 32970 4 12 7 10 55109 8 11 13 12 44713 2 10 8 5 37763 13 10 12 2 53628 7 2 5 10 53197 3 2 1 11 14916 1 2 3 10 50756 3 13 5 6 6959 10 6 1 4 2948 4 7 13 9 14146 8 13 10 2 16784 3 2 6 5 30337 1 6 7 8 14239 2 6 11 5 13749 12 1 10 5 30827 4 6 11 8 18780 9 10 8 5 6336 7 9 1 3 3101 10 3 4 13 56678 7 6 3 8 8258 11 7 12 6 19046 13 6 9 8 46356 9 5 11 13 56570 9 1 10 5 6193 8 6 9 11 16854 3 7 4 9 53573 8 12 10 1 28135 10 3 8 4 31411 11 1 3 12 34534 8 6 4 13 3527 1 6 10 9 52307 11 7 1 12 2886 12 11 1 6 17659 13 5 6 8 48834 11 2 1 10 52951 3 9 13 7 21054 1 5 11 9 14507 11 5 12 4 42040 1 6 12 7 46414 5 12 3 10 26239 6 10 7 8 40762 8 11 6 10 38538 13 1 10 7 31140 9 10 13 4 34164 13 6 7 12 49696 6 13 3 5 36003 8 9 13 6 58409 3 10 7 9 20693 2 1 11 12 22653 5 8 4 7 49888 5 3 2 11 29911 8 12 6 9 30964 8 3 13 6 23597 4 1 6 7 31657 4 6 8 7 13 33639 13 8 10 3 27863 5 2 1 12 1408 4 11 1 12 59010 63 10 11 9 8 23611 10 8 6 11 12410 4 6 7 9 44390 8 4 1 6 16543 1 2 8 10 37452 11 12 6 13 28968 11 12 2 8 59617 1 9 11 2 28631 11 6 5 1 27251 2 7 10 4 42503 7 8 10 3 13673 9 13 11 7 30308 6 1 12 9 4888 13 1 9 8 19475 8 7 3 5 34187 8 1 12 3 46266 6 10 12 5 32855 3 7 13 1 38427 2 5 13 3 59487 6 11 1 13 2098 1 4 13 6 22239 13 7 12 3 28703 12 3 7 4 32 9 8 2 13 35271 10 13 6 12 36422 12 6 9 8 44303 1 9 13 11 22962 11 13 6 12 39518 5 6 13 11 47909 4 13 1 8 10654 11 8 12 4 31956 7 12 9 13 35923 4 9 3 2 34736 13 2 10 1 22945 7 10 8 13 36947 1 4 12 13 19432 7 12 13 4 48718 9 5 13 11 18827 11 2 1 12 45444 8 12 6 13 33175 4 2 11 13 56186 2 9 3 11 33218 12 13 8 1 50727 13 1 8 2 48138 7 1 5 3 1926 6 4 10 1 40997 11 3 1 4 26033 6 10 13 1 40988 11 12 5 4 25199 4 3 1 10 23498 3 6 12 7 24306 13 10 12 3 53255 3 13 4 12 14517 7 10 9 3 29925 9 11 12 13 28333 3 5 13 6 13602 13 12 9 6 10394 8 4 12 6 57471 9 3 4 7 34723 11 9 5 3 38480 12 9 10 11 48048 4 3 6 7 31884 2 10 4 5 57654 86 1 6 5 13 56577 6 8 2 5 20429 11 13 9 3 2243 3 1 10 12 55231 9 5 7 8 29964 5 11 8 1 29624 6 9 3 1 43055 12 13 10 8 52132 10 8 4 1 5729 7 3 6 8 53097 11 12 7 1 18711 12 7 6 13 44397 10 12 5 7 53574 5 3 4 13 27078 11 2 5 10 43623 3 7 1 8 57350 10 12 4 9 19752 5 13 9 3 59380 4 7 13 6 32575 7 5 6 11 13593 13 7 12 6 38282 13 7 6 2 45430 6 2 5 10 38082 2 11 13 7 53557 10 6 7 13 40461 6 11 7 1 22007 4 7 2 3 22386 9 7 11 10 35337 2 6 11 7 4129 6 13 5 3 31813 1 11 6 9 11749 5 11 8 13 21858 5 12 9 11 2470 13 10 6 11 14503 8 4 1 3 10783 1 10 12 7 47116 11 1 8 10 25034 8 1 4 9 23350 3 10 1 9 56717 13 2 8 12 5825 12 3 13 7 35628 10 6 1 12 26901 2 13 3 5 2775 1 8 9 7 1294 7 13 12 2 48170 11 9 13 1 34311 9 6 3 13 30663 8 3 10 6 5853 1 10 2 4 19880 9 2 3 12 48990 3 7 11 4 51558 8 13 2 4 9698 9 4 5 1 6834 3 4 12 2 20941 11 3 9 7 40108 13 11 2 4 2594 8 9 10 13 12242 1 8 10 5 42413 7 1 11 3 17779 1 5 8 3 6934 4 9 8 11 10235 8 11 10 2 18879 11 4 8 2 12691 9 7 5 2 44947 3 2 5 4 30042 2 7 12 4 27185 6 5 10 1 28695 12 9 1 5 53813 8 12 9 3 24719 6 1 4 11 22716 1 13 10 8 39981 12 11 5 2 22412 6 11 2 4 14457 4 11 5 3 39658 10 11 2 1 33056 1 3 6 9 16958 6 11 12 7 50779 8 10 6 13 24824 7 10 1 13 35692 13 4 8 9 32885 7 6 4 3 10948 4 5 7 1 36875 5 10 6 7 58746 10 7 8 12 39453 8 4 12 1 46674 11 3 1 8 48103 0

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  • Windows Domain Chaos - Any Solving Approach

    - by Chake
    we are running an old Window 2003 Server as Domain Controller (DC2003). To safely migrate to Windows 2008 R2 we added a 2008 R2 (DC2008R2) to the domain as domain controller (adprep etc.). After dcpromo on DC2008R2 everything seemed to be ok. The new DC appeared under the "Domain Controlelrs" node. It wasn't checked at this time, if DC2008R2 can REALLY act as domain controller. Later we tried to shutdown DC2003 and ran into a total mess with non functional Exchange and Team Foundation Services. After that I got the job to fix... First i thought it could be an Problem with DC2008R2. So I removed it as Domain Controller and installed a new Windows 2008 R8 Server DC2008R2-2. I ran into similar Problems. I tried a bunch of stuff, but nothign helped. I won't list it, maybe I made an mistake, so I'm willing to redo it with your suggestions. To have a starting point I tried the best practise analyser whicht ended up with 24 "Compatible" and 26 "Not Compatible" tests. From these 26 tests 19 read the same. (I'm translating from german, so that may to be the exact wording) Problem: Using the Best Practise Analyser for Active Directory Domain Services (Active Directory Domain Services Best Practices Analyzer, AD DS BPA) no data can be be gathered using the name of the forest and the domain controller DC2008R2-2. I appreciate any suggestions, this really bothers me.

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  • Hashtable comparator problem

    - by user288245
    Hi guys i've never written a comparator b4 and im having a real problem. I've created a hashtable. Hashtable <String, Objects> ht; Could someone show how you'd write a comparator for a Hashtable? the examples i've seen overide equals and everything but i simply dont have a clue. The code below is not mine but an example i found, the key thing in hashtables means i cant do it like this i guess. public class Comparator implements Comparable<Name> { private final String firstName, lastName; public void Name(String firstName, String lastName) { if (firstName == null || lastName == null) throw new NullPointerException(); this.firstName = firstName; this.lastName = lastName; } public String firstName() { return firstName; } public String lastName() { return lastName; } public boolean equals(Object o) { if (!(o instanceof Name)) return false; Name n = (Name)o; return n.firstName.equals(firstName) && n.lastName.equals(lastName); } public int hashCode() { return 31*firstName.hashCode() + lastName.hashCode(); } public String toString() { return firstName + " " + lastName; } public int compareTo(Name n) { int lastCmp = lastName.compareTo(n.lastName); return (lastCmp != 0 ? lastCmp : firstName.compareTo(n.firstName)); } }

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  • postgres stored procedure problem

    - by easyrider
    Hi all, Ich have a problem in postgres function: CREATE OR REPLACE FUNCTION getVar(id bigint) RETURNS TABLE (repoid bigint, suf VARCHAR, nam VARCHAR) AS $$ declare rec record; BEGIN FOR rec IN (WITH RECURSIVE children(repoobjectid,variant_of_object_fk, suffix, variantname) AS ( SELECT repoobjectid, variant_of_object_fk, '' as suffix,variantname FROM b2m.repoobject_tab WHERE repoobjectid = id UNION ALL SELECT repo.repoobjectid, repo.variant_of_object_fk, suffix || '..' , repo.variantname FROM b2m.repoobject_tab repo, children WHERE children.repoobjectid = repo.variant_of_object_fk) SELECT repoobjectid,suffix,variantname FROM children) LOOP RETURN next; END LOOP; RETURN; END; It can be compiled, but if y try to call it select * from getVar(18) I got 8 empty rows with 3 columns. If i execute the following part of procedure with hard-coded id parameter: WITH RECURSIVE children(repoobjectid,variant_of_object_fk, suffix, variantname) AS ( SELECT repoobjectid, variant_of_object_fk, '' as suffix,variantname FROM b2m.repoobject_tab WHERE repoobjectid = 18 UNION ALL SELECT repo.repoobjectid, repo.variant_of_object_fk, suffix || '..' , repo.variantname FROM b2m.repoobject_tab repo, children WHERE children.repoobjectid = repo.variant_of_object_fk) SELECT repoobjectid,suffix,variantname FROM children I got exactly, what i need 8 rows with data: repoobjectid suffix variantname 18 19 .. for IPhone 22 .. for Nokia 23 .... OS 1.0 and so on. What is going wrong ? Please help. Thanx in advance

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  • Problem with width in percentage in mozilla

    - by lam3r4370
    I have problem with width in percentage in mozilla. Firefox:http://img155.imageshack.us/i/prolemwidthper.png/ Opera:http://img209.imageshack.us/i/logowpopera.png/ Code: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="content-type" content="text/html; charset=iso-8859-1"> <meta name="author" content="adminite"> <title>Untitled 2</title> <style> #cont { width:99.8%; height:125px; border:1px solid red; background-color:#1ea1de; margin: 0px 0px 0px 0px; }</style> </head> <body> <div id="cont"> </div> </body> </html>

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  • Problem in linking an nasm code

    - by Stefano
    I'm using a computer with an Intel Core 2 CPU and 2GB of RAM. The SO is Ubuntu 9.04. When I try to compile this code: ;programma per la simulazione di un terminale su PC, ottenuto utilizzando l'8250 ;in condizione di loopback , cioè Tx=Rx section .code64 section .data TXDATA EQU 03F8H ;TRASMETTITORE RXDATA EQU 03F8H ;RICEVITORE BAUDLSB EQU 03F8H ;DIVISORE DI BAUD RATE IN LSB BAUDMSB EQU 03F9H ;DIVISORE DI BAUD RATE IN MSB INTENABLE EQU 03F9H ;REGISTRO DI ABILITAZIONE DELL'INTERRUZIONE INTIDENTIF EQU 03FAH ;REGISTRO DI IDENTIFICAZIONE DELL'INTERRUZIONE LINECTRL EQU 03FBH ;REGISTRO DI CONTROLLO DELLA LINEA MODEMCTRL EQU 03FCH ;REGISTRO DI CONTROLLO DEL MODEM LINESTATUS EQU 03FDH ;REGISTRO DI STATO DELLA LINEA MODEMSTATUS EQU 03FEH ;REGISTRO DI STATO DEL MODEM BAUDRATEDIV DW 0060H ;DIVISOR: LOW=60, HIGH=00 -BAUD =9600 COUNTERCHAR DB 0 ;CHARACTER COUNTER ;DW 256 DUP (?) section .text global _start _start: ;PROGRAMMAZIONE 8250 MOV DX,LINECTRL MOV AL,80H ;BIT 7=1 PER INDIRIZZARE IL BAUD RATE OUT DX,AL MOV DX,BAUDLSB MOV AX,BAUDRATEDIV ;DEFINISCO FATTORE DI DIVISIONE OUT DX,AL MOV DX,BAUDMSB MOV AL,AH OUT DX,AL ;MSB MOV DX,LINECTRL MOV AL,00000011B ;8 BIT DATO, 1 STOP, PARITA' NO OUT DX,AL MOV DX,MODEMCTRL MOV AL,00010011B ;BIT 4=0 PER NO LOOPBACK OUT DX,AL MOV DX,INTENABLE XOR AL,AL ;DISABILITO TUTTI GLI INTERRUPTS OUT DX,AL CICLO: MOV DX,LINESTATUS IN AL,DX ;LEGGO IL REGISTRO DI STATO DELLA LINEA TEST AL,00011110B ;VERIFICO GLI ERRORI (4 TIPI) JNE ERRORI TEST AL,01H ;VERIFICO Rx PRONTO JNE LEGGOCHAR TEST AL,20H ;VERIFICO Tx VUOTO JE CICLO ;SE SI ARRIVA A QUESTO PUNTO ALLORA L'8250 è PRONTO PER TRASMETTERE UN NUOVO CARATTERE MOV AH,1 INT 80H JE CICLO ;SE SI ARRIVA A QUESTO PUNTO SIGNIFICA CHE ESISTE UN CARATTERE DA TASTIERA MOV AH,0 INT 80H ;Al CONTIENE IL CARATTERE DELLA TASTIERA MOV DX,3F8H OUT DX,AL JMP CICLO LEGGOCHAR: MOV AL,[COUNTERCHAR] INC AL CMP AL,15 JE FINE MOV [COUNTERCHAR],AL MOV DX,TXDATA IN AL,DX ;AL CONTIENE IL CARATTERE RICEVUTO AND AL,7FH ;POICHè VI SONO 7 BIT DI DATO ;VISUALIZZAZIONE DEL CARATTERE MOV BX,0 MOV AH,14 INT 80H POP AX CMP AL,0DH ;CONTROLLO SE RETURN JNE CICLO ;CAMBIO RIGA DI VISUALIZZAZIONE MOV AL,0AH MOV BX,0 MOV AH,14 ;INT 10H INT 80H JMP CICLO ;GESTIONE ERRORI ERRORI: MOV DX,3F8H IN AL,DX MOV AL,'?' MOV BX,0 MOV AH,14 INT 80H JMP CICLO FINE: XOR AH,AH MOV AL,03 INT 80H When I compile this code "NASM -f bin UARTLOOP.asm", the compiler can create the UARTLOOP.o file without any error. When I try to link the .o file with "ld UARTLOOP.o" it tells: UARTLOOP.o: In function `_start': UARTLOOP.asm:(.text+0xd): relocation truncated to fit: R_X86_64_16 against `.data' Have u got some ideas to solve this problem? Thx =)

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  • How to build a web site which gives a sub-domain dynamically to every registered user?

    - by coderex
    Suppose i have a site and i wish to give a sub-domain for each registered users. like my site http://site.com/ and the test-user is a user registered on my site and site want to make sub-domain for that user. Like http://test-user.site.com Like http://test-user1.site.com for test-user1. Hop you understood the requirement. How can i create a sub-domain using my sites back-end. or dynamically while register

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  • Binary file reading problem

    - by ScReYm0
    Ok i have problem with my code for reading binary file... First i will show you my writing code: void book_saving(char *file_name, struct BOOK *current) { FILE *out; BOOK buf; out = fopen(file_name, "wb"); if(out != NULL) { printf_s("Writting to file..."); do { if(current != NULL) { strcpy(buf.catalog_number, current->catalog_number); strcpy(buf.author, current->author); buf.price = current->price; strcpy(buf.publisher, current->publisher); strcpy(buf.title, current->title); buf.price = current->year_published; fwrite(&buf, sizeof(BOOK), 1, out); } current = current->next; }while(current != NULL); printf_s("Done!\n"); fclose(out); } } and here is my "version" for reading it back: int book_open(struct BOOK *current, char *file_name) { FILE *in; BOOK buf; BOOK *vnext; int count; int i; in = fopen("west", "rb"); printf_s("Reading database from %s...", file_name); if(!in) { printf_s("\nERROR!"); return 1; } i = fread(&buf,sizeof(BOOK), 1, in); while(!feof(in)) { if(current != NULL) { current = malloc(sizeof(BOOK)); current->next = NULL; } strcpy(current->catalog_number, buf.catalog_number); strcpy(current->title, buf.title); strcpy(current->publisher, buf.publisher); current->price = buf.price; current->year_published = buf.year_published; fread(&buf, 1, sizeof(BOOK), in); while(current->next != NULL) current = current->next; fclose(in); } printf_s("Done!"); return 0; } I just need to save my linked list in binary file and to be able to read it back ... please help me. The program just don't read it or its crash every time different situation ...

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  • One configuration per domain name on the same application. How to easily access config values from m

    - by Aymeric
    Hi, I run a Ruby on Rails website that have multiple domain names. I have a "Website" table in the database that stores the configuration values related to each domain name: Website - domain - name - tagline - admin_email - etc... At the moment, I load the website object at the start of each request (before_filter) in my ApplicationController: @website = Website.find_by_domain(request.host) The problem is when I need to access the @website object from my models methods. I would like to avoid to have to pass @website everywhere. The best solution would be to have something similar to APP_CONFIG but per domain name. def sample_model_property - - "#{@website.name} is a great website!" end How would you do it?

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  • How do I do a cross domain GET of an XML feed in a WordPress plugin?

    - by MM.
    I would like to use AJAX to display dynamic content via my wordpress plugin. The data source is an xml feed from a remote domain (not owned by me). I have tried using JQuery plugins that use YQL to do cross domain Ajax calls; however, they are geared towards json and tend to return the data to me in a mangled state. My question is, is there a way of obtaining an xml feed using ajax from a remote domain?

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  • Amazon SimpleDB - Is there a way to list all Attributes in a Domain?

    - by beer-drinker
    Hi, I'm using C# and the AWSSDK library form Amazon to test a few things in SimpleDB. All going well so far. However, I am trying to come up with a neat way of retrieving all Attributes that are applicable to a Domain. This is proving to be tricky without having to retrieve an Item, and obviously I can get the list of attributes then. But what if I have 100,000 Items in a Domain. Let's say the first 70,000 Items in a "Person" Domain have: FirstName, LastName, Address And then I hit a Item that has FirstName, LastName, Address, Phone And then I hit another Item around the 80,000 mark which has: FirstName, LastName, Email, Phone In the above example, for the Person Domain, how would I get a list that contains: FirstName, LastName, Address, Email, Phone ...without performing a ridiculous number of select statements? Many thanks!

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  • Is checkdnsrr() function good enough to establish domain (in)availability?

    - by Stipe
    I want to create simple script to check domain availability. Can anybody tell me is this function enough to check domain availability before user can register: <?php $recordexists = checkdnsrr("www.google.com", "ANY"); if ($recordexists) echo "The domain name has been taken. Sorry!"; else echo "The domain name is available!"; ?> or should I go with some other whois script like http://www.mrscripts.co.uk/index.php?op=lite

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  • Moving SharePoint 2010 to a new domain

    - by Chris
    I have a small SharePoint 2010 farm (1 WFE / App Server & 1 SQL server) Our organisation is currently mirgrating to our holding company's global domain, so we now have a new local DC on site with trusts between the current domain and the new domain. I am going to need to move our SP Farm to the new domain and possibly rename servers to fit into the global naming convention (we are trying to avoid this at the moment, but might become a requirement) If there a way to script (stsadm / powershell) the user profiles and permission accross to the new domain? and on the server side, is it as simple as joining the servers to the new domain and updating all the service / farm accounts to accounts on new domain? I have googled this a bit, but everything I have found so far refers to MOSS 2007 or earlier. Any help / advise would be appreciated.

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  • How to host Exchange mailboxes for another organisation outside of domain?

    - by Jon
    We have a branch office out in another country who currently have their own domain and AD and Exchange Server. We want to look at hosting their Exchange mailboxes so that we can improve presence information through the use of Calenders etc. Whats the best way to do this? Simple VPN connection? Or is there a way to for them to keep their own Exchange Server and mailboxes but view and edit our calenders?

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