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  • Dell Docking Station Doesn’t Detect USB Mouse and Keyboard

    - by Ben Griswold
    I’ve found myself in this situation with multiple Dell docking stations and multiple Dell laptops running various Windows operating systems.  I don’t know why the docking station stops recognizing my USB mouse and keyboard – it just does.  It’s black magic.  The last time around I just starting plugging the mouse and keyboard into the docked laptop directly and went about my business (as if I wasn’t completing missing out on a couple of the core benefits of using a docking station.)  I guess that’s what happens when you forget how you got yourself out of the mess the last time around.  I had been in this half-assed state for a couple of weeks now, but a coworker fortunately got themselves in and out of the same pickle this morning.  Procrastinate long enough and the solution will just come to you, right? Here’s how to get yourself out of this mess: Undock your computer Unplug your docking station Count to an arbitrary number greater than 12.  (Not sure this is really required, but…) Plug your docking station back in Redock your machine I put my machine to sleep before taking the aforementioned actions.  My coworker completely shutdown his laptop instead.  The steps worked on both of our Win 7 machines this morning and, who knows, it might just work for you too. 

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  • Project Euler 18: (Iron)Python

    - by Ben Griswold
    In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 18.  As always, any feedback is welcome. # Euler 18 # http://projecteuler.net/index.php?section=problems&id=18 # By starting at the top of the triangle below and moving # to adjacent numbers on the row below, the maximum total # from top to bottom is 23. # # 3 # 7 4 # 2 4 6 # 8 5 9 3 # # That is, 3 + 7 + 4 + 9 = 23. # Find the maximum total from top to bottom of the triangle below: # 75 # 95 64 # 17 47 82 # 18 35 87 10 # 20 04 82 47 65 # 19 01 23 75 03 34 # 88 02 77 73 07 63 67 # 99 65 04 28 06 16 70 92 # 41 41 26 56 83 40 80 70 33 # 41 48 72 33 47 32 37 16 94 29 # 53 71 44 65 25 43 91 52 97 51 14 # 70 11 33 28 77 73 17 78 39 68 17 57 # 91 71 52 38 17 14 91 43 58 50 27 29 48 # 63 66 04 68 89 53 67 30 73 16 69 87 40 31 # 04 62 98 27 23 09 70 98 73 93 38 53 60 04 23 # NOTE: As there are only 16384 routes, it is possible to solve # this problem by trying every route. However, Problem 67, is the # same challenge with a triangle containing one-hundred rows; it # cannot be solved by brute force, and requires a clever method! ;o) import time start = time.time() triangle = [ [75], [95, 64], [17, 47, 82], [18, 35, 87, 10], [20, 04, 82, 47, 65], [19, 01, 23, 75, 03, 34], [88, 02, 77, 73, 07, 63, 67], [99, 65, 04, 28, 06, 16, 70, 92], [41, 41, 26, 56, 83, 40, 80, 70, 33], [41, 48, 72, 33, 47, 32, 37, 16, 94, 29], [53, 71, 44, 65, 25, 43, 91, 52, 97, 51, 14], [70, 11, 33, 28, 77, 73, 17, 78, 39, 68, 17, 57], [91, 71, 52, 38, 17, 14, 91, 43, 58, 50, 27, 29, 48], [63, 66, 04, 68, 89, 53, 67, 30, 73, 16, 69, 87, 40, 31], [04, 62, 98, 27, 23, 9, 70, 98, 73, 93, 38, 53, 60, 04, 23]] # Loop through each row of the triangle starting at the base. for a in range(len(triangle) - 1, -1, -1): for b in range(0, a): # Get the maximum value for adjacent cells in current row. # Update the cell which would be one step prior in the path # with the new total. For example, compare the first two # elements in row 15. Add the max of 04 and 62 to the first # position of row 14.This provides the max total from row 14 # to 15 starting at the first position. Continue to work up # the triangle until the maximum total emerges at the # triangle's apex. triangle [a-1][b] += max(triangle [a][b], triangle [a][b+1]) print triangle [0][0] print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')

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  • Introduction to Lean Software Development and Kanban Systems

    - by Ben Griswold
    Last year I took myself through a crash course on Lean Software Development and Kanban Systems in preparation for an in-house presentation.  I learned a bunch.  In this series, I’ll be sharing what I learned with you.   If your career looks anything like mine, you have probably been affiliated with a company or two which pushed requirements gathering and documentation to the nth degree. To add insult to injury, they probably added planning process (documentation, requirements, policies, meetings, committees) to the extent that it possibly retarded any progress. In my opinion, the typical company resembles the quote from Tom DeMarco. It isn’t enough just to do things right – we also had to say in advance exactly what we intended to do and then do exactly that. In the 1980s, Toyota turned the tables and revolutionize the automobile industry with their approach of “Lean Manufacturing.” A massive paradigm shift hit factories throughout the US and Europe. Mass production and scientific management techniques from the early 1900’s were questioned as Japanese manufacturing companies demonstrated that ‘Just-in-Time’ was a better paradigm. The widely adopted Japanese manufacturing concepts came to be known as ‘lean production’. Lean Thinking capitalizes on the intelligence of frontline workers, believing that they are the ones who should determine and continually improve the way they do their jobs. Lean puts main focus on people and communication – if people who produce the software are respected and they communicate efficiently, it is more likely that they will deliver good product and the final customer will be satisfied. In time, the abstractions behind lean production spread to logistics, and from there to the military, to construction, and to the service industry. As it turns out, principles of lean thinking are universal and have been applied successfully across many disciplines. Lean has been adopted by companies including Dell, FedEx, Lens Crafters, LLBean, SW Airlines, Digital River and eBay. Lean thinking got its name from a 1990’s best seller called The Machine That Changed the World : The Story of Lean Production. This book chronicles the movement of automobile manufacturing from craft production to mass production to lean production. Tom and Mary Poppendieck, that is.  Here’s one of their books: Implementing Lean Software Thinking: From Concept to Cash Our in-house presentations are supposed to run no more than 45 minutes.  I really cranked and got through my 87 slides in just under an hour. Of course, I had to cheat a little – I only covered the 7 principles and a single practice. In the next part of the series, we’ll dive into Principle #1: Eliminate Waste. And I am going to be a little obnoxious about listing my Lean and Kanban references with every series post.  The references are great and they deserve this sort of attention. 

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  • Configure SQL Server to Allow Remote Connections

    - by Ben Griswold
    Okay. This post isn’t about configuring SQL to allow remote connections, but wait, I still may be able to help you out. "A network-related or instance-specific error occurred while establishing a connection to SQL Server. The server was not found or was not accessible. Verify that the instance name is correct and that SQL Server is configured to allow remote connections. (provider: Named Pipes Provider, error: 40 – Could not open a connection to SQL Server)" I love this exception. It summarized the issue and leads you down a path to solving the problem.  I do wish the bit about allowing remote connections was left out of the message though. I can’t think of a time when having remote connections disabled caused me grief.  Heck, I can’t ever remember how to enable remote connections unless I Google for the answer. Anyway, 9 out of 10 times, SQL Server simply isn’t running.  That’s why the exception occurs.  The next time this exception pops up, open up the services console and make sure SQL Server is started.  And if that’s not the problem, only then start digging into the other possible reasons for the failure.

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  • T4Toolbox and Visual Studio 2010

    - by Ben Griswold
    I’ve been using the T4Toolbox to help generate my ASP.NET MVC models and scaffolding for a while now.  Another developer tried using my generator project last week and ran into troubles due to a breaking change around the RenderCore() and TransformText() methods in support for VS 2010.  If you upgraded to the latest version of T4Toolbox and receive a build error similar to the following, you are probably in the same boat: GeneratedTextTransformation.[Template].RenderCore(): no suitable method found to override We took the easy way out.  I had him uninstall the latest version of T4Toolbox and install version 9.7.25.1 which my templates were initially coded against.  For now, that worked great, but it sounds like I’ll be doing some rework of the 20+ templates in my project to support Visual Studio 2010 when we migrate later this month.

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  • SVN Export or Recursively Remove .SVN Folders

    - by Ben Griswold
    I shared this script with a coworker yesterday. It doesn’t do much; it recursively deletes .svn folders from a source tree.  It comes in handy if you want to share your codebase or you get in a terrible spot with SVN and you just want to start all over. Just blow away all svn artifacts and use your mulligan. It’s true. You can nearly get the same result using the SVN export command which copies your source sans the .svn folders to an alternate location.  The catch is an export only includes those files/folders which exist under version control.  If you want a clean copy of your source – versioned or not – export just might not do. The contents of the .cmd file include the following: for /f "tokens=* delims=" %%i in (’dir /s /b /a:d *.svn’) do ( rd /s /q "%%i" ) Just download and drop the unzipped “SVN Cleanup.cmd” file into the root of the project, execute and away you go.  If you search around enough, I know you can find similar scripts and approaches elsewhere, but I’m still uploading my script for completeness and future reference. Download SVN Cleanup

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  • Database Connectivity Test with UDL File

    - by Ben Griswold
    I bounced around between projects a lot last week.  What each project had in common was the need to validate at least one SQL connection.  Whether you have SQL tools like SSMS installed or not, this is a very easy task if you are aware of the UDL (Universal Data Link) files.  Create a new file and name it anything as long as it has the .udl extension. Open the file, choose a provider: Click Next >> or navigate to the Connection Tab to provide connection information.  Once you provide server and login credentials, the database list will populate.  At this point, you know the connection is valid. but go ahead and click the Test Connection button anyway. On the final tab, you can provide extra connection information like Application Name which can come in handy.  The All tab is beneficial if you want to build a valid connection string to include in your own applications.  If you save the file and then open in Notepad, you’ll find that said connection string: Provider=SQLOLEDB.1;Integrated Security=SSPI;Persist Security Info=False;Initial Catalog=master;Data Source=(local);Application Name=TestApp I hope this tip helps save you some time.  How do you test if you don’t have SSMS installed?

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  • Forced Learning

    - by Ben Griswold
    If you ask me, it can be a little intimidating to stand in front of a group and walkthrough anything remotely technical. Even if you know “Technical Thingy #52” inside and out, public speaking can be unsettling.  And if you don’t have your stuff together, well, it can be downright horrifying. With that said, if given the choice, I still like to schedule myself to present on unfamiliar topics. Over the past few months, I’ve talked about Aspect-Oriented Programming, Functional Programming, Lean Software Development and Kanban Systems, Domain-Driven Design and Behavior Driven Development.  What do these topics have in common? You guessed it: I was truly interested in them. I had only a superficial understanding of each. Huh?  Why in the world would I ever want to to put myself in that intimidating situation? Actually, I rarely want to put myself into that situation but I often do as I like the results.  There’s nothing remotely clever going on here.  All I’m doing is putting myself into a compromising situation knowing that I’ll likely work myself out of it by learning the topic prior to the presentation.  I’m simply time-boxing myself to learn something new while knowing there are negative repercussions if I fall short. So, I end up doing tons of research and I learn bunches to ensure I have my head firmly wrap around the material before my talk. I’m not saying I become an expert overnight (or over a couple of weeks) but I’ll definitely know enough to be confident and comfortable and I’ll know more than enough to ensure the audience will learn a thing or two from me. It’s forced learning and though it might sound a little scary to some, it works for me. Now I could very easily rename this post to something like Fear Is My Motivator because, in a sense, fear of failure and embarrassment is what’s driving my learning. However, I’m the guy signing up for the presentation and since the entire process is self-imposed I’m not sure Fear deserves too much credit.  Anyway…

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  • Project Euler 15: (Iron)Python

    - by Ben Griswold
    In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 15.  As always, any feedback is welcome. # Euler 15 # http://projecteuler.net/index.php?section=problems&id=15 # Starting in the top left corner of a 2x2 grid, there # are 6 routes (without backtracking) to the bottom right # corner. How many routes are their in a 20x20 grid? import time start = time.time() def factorial(n): if n == 0: return 1 else: return n * factorial(n-1) rows, cols = 20, 20 print factorial(rows+cols) / (factorial(rows) * factorial(cols)) print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')

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  • ReSharper File Location

    - by Ben Griswold
    By default, the ReSharper cache is stored in the solution folder.  It’s one extra folder and one extra .user file.  It’s no big deal but it does clutter up your solution a bit – especially since the files provide no real value. I prefer to store the ReSharper cache in the system Temp folder.  This setting is available by visiting ReSharper > Options > Environment > General. Just update where you’d like to store the ReSharper cache and you’re good to go.  Note, the .user file continues to linger around the solution folder but at least the _ReSharper.SolutionName folder is moved out of sight.

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  • Oracle E-Business Suite 12 Certified on Oracle Linux 6 (x86-64)

    - by John Abraham
    Oracle E-Business Suite Release 12 (12.1.1 and higher) is now certified on 64-bit Oracle Linux 6 with the Unbreakable Enterprise Kernel (UEK). New installations of the E-Business Suite R12 on this OS require version 12.1.1 or higher. Cloning of existing 12.1 Linux environments to this new OS is also certified using the standard Rapid Clone process. There are specific requirements to upgrade technology components such as the Oracle Database (to 11.2.0.3) and Fusion Middleware as necessary for use on Oracle Linux 6. These and other requirements are noted in the Installation and Upgrade Notes (IUN) below. Certification for other Linux distros still underway Certifications of Release 12 with 32-bit Oracle Linux 6, 32-bit and 64-bit Red Hat Enterprise Linux (RHEL) 6 and the Red Hat default kernel are in progress. References Oracle E-Business Suite Installation and Upgrade Notes Release 12 (12.1.1) for Linux x86-64 (My Oracle Support Document 761566.1) Cloning Oracle Applications Release 12 with Rapid Clone (My Oracle Support Document 406982.1) Interoperability Notes Oracle E-Business Suite Release 12 with Oracle Database 11g Release 2 (11.2.0) (My Oracle Support Document 1058763.1) Oracle Linux website

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  • Project Euler 9: (Iron)Python

    - by Ben Griswold
    In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 9.  As always, any feedback is welcome. # Euler 9 # http://projecteuler.net/index.php?section=problems&id=9 # A Pythagorean triplet is a set of three natural numbers, # a b c, for which, # a2 + b2 = c2 # For example, 32 + 42 = 9 + 16 = 25 = 52. # There exists exactly one Pythagorean triplet for which # a + b + c = 1000. Find the product abc. import time start = time.time() product = 0 def pythagorean_triplet(): for a in range(1,501): for b in xrange(a+1,501): c = 1000 - a - b if (a*a + b*b == c*c): return a*b*c print pythagorean_triplet() print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')

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  • Project Euler 5: (Iron)Python

    - by Ben Griswold
    In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 5.  As always, any feedback is welcome. # Euler 5 # http://projecteuler.net/index.php?section=problems&id=5 # 2520 is the smallest number that can be divided by each # of the numbers from 1 to 10 without any remainder. # What is the smallest positive number that is evenly # divisible by all of the numbers from 1 to 20? import time start = time.time() def gcd(a, b): while b: a, b = b, a % b return a def lcm(a, b): return a * b // gcd(a, b) print reduce(lcm, range(1, 20)) print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')

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  • Project Euler 14: (Iron)Python

    - by Ben Griswold
    In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 14.  As always, any feedback is welcome. # Euler 14 # http://projecteuler.net/index.php?section=problems&id=14 # The following iterative sequence is defined for the set # of positive integers: # n -> n/2 (n is even) # n -> 3n + 1 (n is odd) # Using the rule above and starting with 13, we generate # the following sequence: # 13 40 20 10 5 16 8 4 2 1 # It can be seen that this sequence (starting at 13 and # finishing at 1) contains 10 terms. Although it has not # been proved yet (Collatz Problem), it is thought that all # starting numbers finish at 1. Which starting number, # under one million, produces the longest chain? # NOTE: Once the chain starts the terms are allowed to go # above one million. import time start = time.time() def collatz_length(n): # 0 and 1 return self as length if n <= 1: return n length = 1 while (n != 1): if (n % 2 == 0): n /= 2 else: n = 3*n + 1 length += 1 return length starting_number, longest_chain = 1, 0 for x in xrange(1, 1000001): l = collatz_length(x) if l > longest_chain: starting_number, longest_chain = x, l print starting_number print longest_chain # Slow 31 seconds print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')

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  • Objective-C Moving UIView along a curved path

    - by PruitIgoe
    I'm not sure if I am approaching this the correct way. In my app, when a user touches the screen I capture the point and create an arc from a fixed point to that touch point. I then want to move a UIView along that arc. Here's my code: ViewController.m //method to "shoot" object - KIP_Projectile creates the arc, KIP_Character creates the object I want to move along the arc ... //get arc for trajectory KIP_Projectile* vThisProjectile = [[KIP_Projectile alloc] initWithFrame:CGRectMake(51.0, fatElvisCenterPoint-30.0, touchPoint.x, 60.0)]; vThisProjectile.backgroundColor = [UIColor clearColor]; [self.view addSubview:vThisProjectile]; ... KIP_Character* thisChar = [[KIP_Character alloc] initWithFrame:CGRectMake(51, objCenterPoint-5, imgThisChar.size.width, imgThisChar.size.height)]; thisChar.backgroundColor = [UIColor clearColor]; thisChar.charID = charID; thisChar.charType = 2; thisChar.strCharType = @"Projectile"; thisChar.imgMyImage = imgThisChar; thisChar.myArc = vThisProjectile; [thisChar buildImage]; [thisChar traceArc]; in KIP_Projectile I build the arc using this code: - (CGMutablePathRef) createArcPathFromBottomOfRect : (CGRect) rect : (CGFloat) arcHeight { CGRect arcRect = CGRectMake(rect.origin.x, rect.origin.y + rect.size.height - arcHeight, rect.size.width, arcHeight); CGFloat arcRadius = (arcRect.size.height/2) + (pow(arcRect.size.width, 2) / (8*arcRect.size.height)); CGPoint arcCenter = CGPointMake(arcRect.origin.x + arcRect.size.width/2, arcRect.origin.y + arcRadius); CGFloat angle = acos(arcRect.size.width / (2*arcRadius)); CGFloat startAngle = radians(180) + angle; CGFloat endAngle = radians(360) - angle; CGMutablePathRef path = CGPathCreateMutable(); CGPathAddArc(path, NULL, arcCenter.x, arcCenter.y, arcRadius, startAngle, endAngle, 0); return path; } - (void)drawRect:(CGRect)rect { CGContextRef currentContext = UIGraphicsGetCurrentContext(); _myArcPath = [self createArcPathFromBottomOfRect:self.bounds:30.0]; CGContextSetLineWidth(currentContext, 1); CGFloat red[4] = {1.0f, 0.0f, 0.0f, 1.0f}; CGContextSetStrokeColor(currentContext, red); CGContextAddPath(currentContext, _myArcPath); CGContextStrokePath(currentContext); } Works fine. The arc is displayed with a red stroke on the screen. In KIP_Character, which has been passed it's relevant arc, I am using this code but getting no results. - (void) traceArc { CGMutablePathRef myArc = _myArc.myArcPath; // Set up path movement CAKeyframeAnimation *pathAnimation = [CAKeyframeAnimation animationWithKeyPath:@"position"]; pathAnimation.calculationMode = kCAAnimationPaced; pathAnimation.fillMode = kCAFillModeForwards; pathAnimation.removedOnCompletion = NO; pathAnimation.path = myArc; CGPathRelease(myArc); [self.layer addAnimation:pathAnimation forKey:@"savingAnimation"]; } Any help here would be appreciated.

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  • Language Club

    - by Ben Griswold
    We started a language club at work this week.  Thus far, we have a collective interest in a number of languages: Python, Ruby, F#, Erlang, Objective-C, Scala, Clojure, Haskell and Go. There are more but these 9 received the most votes. During the first few meetings we are going to determine which language we should tackle first. To help make our selection, each member will provide a quick overview of their favored language by answering the following set of questions: Why are you interested in learning “your” language(s). (There’s lots of work, I’m an MS shill, It’s hip and  fun, etc) What type of language is it?  (OO, dynamic, functional, procedural, declarative, etc) What types of problems is your language best suited to solve?  (Algorithms over big data, rapid application development, modeling, merely academic, etc) Can you provide examples of where/how it is being used?  If it isn’t being used, why not?  (Erlang was invented at Ericsson to provide an extremely fault tolerant, concurrent system.) Quick history – Who created/sponsored the language?  When was it created?  Is it currently active? Does the language have hardware support (an attempt was made at one point to create processor instruction sets specific to Prolog), or can it run as an interpreted language inside another language (like Ruby in the JVM)? Are there facilities for programs written in this language to communicate with other languages?  How does this affect its utility? Does the language have a IDE tool support?  (Think Eclipse or Visual Studio) How well is the language supported in terms of books, community and documentation? What’s the number one things which differentiates the language from others?  (i.e. Why is it cool?) How is the language applicability to us as consultants?  What would the impact be of using the language in terms of cost, maintainability, personnel costs, etc.? What’s the number one things which differentiates the language from others?  (i.e. Why is it cool?) This should provide an decent introduction into nearly a dozen languages and give us enough context to decide which single language deserves our undivided attention for the weeks to come.  Stay tuned for the winner…

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  • XNA - Drawing 2D Primitives (Boxes) and Understanding Matrices in Computer Graphics

    - by MintyAnt
    I have two issues which I wish to solve by creating 2D primitives in XNA. In my game, I wish to have a "debug mode" which will draw a red box around all hitboxes in the game (Red outline, transparent inside). This would allow us to see where the hitboxes are being drawn AND still have the sprite graphics being drawn. I wish to further understand how matrices work within computer graphics. I have a basic theoretical grasp of how they work, but I really just want to apply some of my knowledge or find a good tutorial on it. To do this, I wish to draw my own 2D primitives (With Vertex3's) and apply different transormation matrices to them. I was trying to find a tutorial on drawing primitives using Direct3D, but most tutorials are only for c++, and just tell me to use XNA's Spritebatch. I wish to have more control over my program than just with Spritebatch. Any Help on using Direct3D or any other suggestions would greatly be appreciated. Thank you.

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  • A deque based on binary trees

    - by Greg Ros
    This is a simple immutable deque based on binary trees. What do you think about it? Does this kind of data structure, or possibly an improvement thereof, seem useful? How could I improve it, preferably without getting rid of its strengths? (Not in the sense of more operations, in the sense of different design) Does this sort of thing have a name? Red nodes are newly instantiated; blue ones are reused. Nodes aren't actually red or anything, it's just for emphasis.

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  • Project Euler 8: (Iron)Python

    - by Ben Griswold
    In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 8.  As always, any feedback is welcome. # Euler 8 # http://projecteuler.net/index.php?section=problems&id=8 # Find the greatest product of five consecutive digits # in the following 1000-digit number import time start = time.time() number = '\ 73167176531330624919225119674426574742355349194934\ 96983520312774506326239578318016984801869478851843\ 85861560789112949495459501737958331952853208805511\ 12540698747158523863050715693290963295227443043557\ 66896648950445244523161731856403098711121722383113\ 62229893423380308135336276614282806444486645238749\ 30358907296290491560440772390713810515859307960866\ 70172427121883998797908792274921901699720888093776\ 65727333001053367881220235421809751254540594752243\ 52584907711670556013604839586446706324415722155397\ 53697817977846174064955149290862569321978468622482\ 83972241375657056057490261407972968652414535100474\ 82166370484403199890008895243450658541227588666881\ 16427171479924442928230863465674813919123162824586\ 17866458359124566529476545682848912883142607690042\ 24219022671055626321111109370544217506941658960408\ 07198403850962455444362981230987879927244284909188\ 84580156166097919133875499200524063689912560717606\ 05886116467109405077541002256983155200055935729725\ 71636269561882670428252483600823257530420752963450' max = 0 for i in xrange(0, len(number) - 5): nums = [int(x) for x in number[i:i+5]] val = reduce(lambda agg, x: agg*x, nums) if val > max: max = val print max print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')

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  • Cannot dual Windows XP and Ubuntu

    - by Fabio Machado
    I am new to Ubuntu and at the moment I am trying to get Ubuntu 12.10 to one of my machines. The machine is a Pentium 4 @ 3.06, 2Gb RAM, 200GB Hard Drive and a NVidia GeForce 8800 GT. A few days ago, I tried Ubuntu without installing and it worked perfectly. Yesterday, I decided to formatted the hard drive and divide my hard drive into four partitions: 1 for the XP, 1 for Ubuntu, 1 for swamp and 1 where I will have my documents. Everything went great, I installed XP and then Ubuntu but I did something wrong on the partition window (Ubunto partion window) that I ended up without boot loader. This morning, I formatted everything again, installed XP and when I went to install Ubuntu (with the same DVD as before) the problems started. First, I had a black screen with a msg written with white text saying something like: unable to find a medium containing a live file system. After I burned another CD and tried again, I got stuck at the red dots (loading screen). I then went online and I read somewhere that it could be the CD, so I checked the integrity of the CD and everything was fine. I also unplugged all USBs connected to the computer and nothing changed. I goggled further options to try to solve my problem and some users suggested that people having these types of problems should try the alternate installation, which if I am not wrong is for networks. I then tried to install and yes the installation process was different from the normal CD, but it did get stuck on a page where it was doing something, like: ...finding ethd0 and it was stuck on the 100%. I tried USB installation as well and it also got stuck at the red dots (I do not have USB 3.0 on the computer in question). I have burned 5 different CD's and all at low speed. I checked the integrity and all are fine. I downloaded other distribution as well as other versions of Ubuntu and I still cannot install or even run the Live CD of Ubuntu or any other distribution. What is really annoying me is that everything was working perfectly before, when I first tried to install Ubuntu. Anyway, any help is welcome. Edit: My boot load is normal, no errors and all the hardware is working fine. I forgot to mention that after the loading screen (red dots) gets stuck, the DVD drive and the hard drive goes into idle state. I also restored the default values of the BIOS and no luck.

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  • Managing .NET External Dependencies

    - by Ben Griswold
    Noah and I continue our screencast series by sharing our approach to managing external dependencies referenced within a .NET solution.  This is another introductory episode but you might find a hidden gem in the short 4-minute clip.  ELMAH (Error Logging Modules and Handlers) is the external dependencies we are focusing on in the presentation.  If you are not familiar with ELMAH, this episode may be worth your time.   YouTube - Managing .NET External Dependencies This is one of our first screencasts.  If you have feedback, I’d love to hear it.

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  • Project Euler 52: Ruby

    - by Ben Griswold
    In my attempt to learn Ruby out in the open, here’s my solution for Project Euler Problem 52.  Compared to Problem 51, this problem was a snap. Brute force and pretty quick… As always, any feedback is welcome. # Euler 52 # http://projecteuler.net/index.php?section=problems&id=52 # It can be seen that the number, 125874, and its double, # 251748, contain exactly the same digits, but in a # different order. # # Find the smallest positive integer, x, such that 2x, 3x, # 4x, 5x, and 6x, contain the same digits. timer_start = Time.now def contains_same_digits?(n) value = (n*2).to_s.split(//).uniq.sort.join 3.upto(6) do |i| return false if (n*i).to_s.split(//).uniq.sort.join != value end true end i = 100_000 answer = 0 while answer == 0 answer = i if contains_same_digits?(i) i+=1 end puts answer puts "Elapsed Time: #{(Time.now - timer_start)*1000} milliseconds"

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  • Oracle E-Business Suite 12 Certified on Additional Linux Platforms

    - by John Abraham
    As a follow up to our original certification announcement regarding Oracle Linux 6, Oracle E-Business Suite Release 12 (12.1.1 and higher) is now certified on the following additional Linux x86/x86-64 operating systems: Oracle Linux 6 (32-bit) Red Hat Enterprise Linux 6 (32-bit) Red Hat Enterprise Linux 6 (64-bit) Novell SUSE Linux Enterprise Server (SLES) version 11 (64-bit) New installations of the E-Business Suite on these operating systems require version 12.1.1 of the Release 12 media.  Cloning of existing 12.1 Linux environments to this new OS is also certified using the standard Rapid Clone process. There are specific requirements to upgrade technology components such as the Oracle Database (to 11gR2) and Fusion Middleware as necessary. These and other requirements are noted in the Installation and Upgrade Notes (IUN) below. References Oracle E-Business Suite Installation and Upgrade Notes Release 12 (12.1.1) for Linux x86-64 (My Oracle Support Document 761566.1) Oracle E-Business Suite Installation and Upgrade Notes Release 12 (12.1.1) for Linux x86 (My Oracle Support Document 761564.1) Cloning Oracle Applications Release 12 with Rapid Clone (My Oracle Support Document 406982.1) Interoperability Notes Oracle E-Business Suite Release 12 with Oracle Database 11g Release 2 (11.2.0) (My Oracle Support Document 1058763.1) Oracle Linux website

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  • Project Euler 12: (Iron)Python

    - by Ben Griswold
    In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 12.  As always, any feedback is welcome. # Euler 12 # http://projecteuler.net/index.php?section=problems&id=12 # The sequence of triangle numbers is generated by adding # the natural numbers. So the 7th triangle number would be # 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28. The first ten terms # would be: # 1, 3, 6, 10, 15, 21, 28, 36, 45, 55, ... # Let us list the factors of the first seven triangle # numbers: # 1: 1 # 3: 1,3 # 6: 1,2,3,6 # 10: 1,2,5,10 # 15: 1,3,5,15 # 21: 1,3,7,21 # 28: 1,2,4,7,14,28 # We can see that 28 is the first triangle number to have # over five divisors. What is the value of the first # triangle number to have over five hundred divisors? import time start = time.time() from math import sqrt def divisor_count(x): count = 2 # itself and 1 for i in xrange(2, int(sqrt(x)) + 1): if ((x % i) == 0): if (i != sqrt(x)): count += 2 else: count += 1 return count def triangle_generator(): i = 1 while True: yield int(0.5 * i * (i + 1)) i += 1 triangles = triangle_generator() answer = 0 while True: num = triangles.next() if (divisor_count(num) >= 501): answer = num break; print answer print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')

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  • Simple 2d game pathfinding

    - by Kooi Nam Ng
    So I was trying to implement a simple pathfinding on iOS and but the outcome seems less satisfactory than what I intended to achieve.The thing is units in games like Warcraft and Red Alert move in all direction whereas units in my case only move in at most 8 directions as these 8 directions direct to the next available node.What should I do in order to achieve the result as stated above?Shrink the tile size? The screenshot intended for illustration. Those rocks are the obstacles whereas the both ends of the green path are the starting and end of the path.The red line is the path that I want to achieve. http://i.stack.imgur.com/lr19c.jpg

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