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  • Making an efficient algorithm

    - by James P.
    Here's my recent submission for the FB programming contest (qualifying round only requires to upload program output so source code doesn't matter). The objective is to find two squares that add up to a given value. I've left it as it is as an example. It does the job but is too slow for my liking. Here's the points that are obviously eating up time: List of squares is being recalculated for each call of getNumOfDoubleSquares(). This could be precalculated or extended when needed. Both squares are being checked for when it is only necessary to check for one (complements). There might be a more efficient way than a double-nested loop to find pairs. Other suggestions? Besides this particular problem, what do you look for when optimizing an algorithm? public static int getNumOfDoubleSquares( Integer target ){ int num = 0; ArrayList<Integer> squares = new ArrayList<Integer>(); ArrayList<Integer> found = new ArrayList<Integer>(); int squareValue = 0; for( int j=0; squareValue<=target; j++ ){ squares.add(j, squareValue); squareValue = (int)Math.pow(j+1,2); } int squareSum = 0; System.out.println( "Target=" + target ); for( int i = 0; i < squares.size(); i++ ){ int square1 = squares.get(i); for( int j = 0; j < squares.size(); j++ ){ int square2 = squares.get(j); squareSum = square1 + square2; if( squareSum == target && !found.contains( square1 ) && !found.contains( square2 ) ){ found.add(square1); found.add(square2); System.out.println( "Found !" + square1 +"+"+ square2 +"="+ squareSum); num++; } } } return num; }

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  • How to control manager class in Blackberry

    - by Keng
    Dear All, I have a problem when creating a UI on Blackberry. First, i try to create a ChatLayoutManager class extended from Manager class. My layout has three component: topfield, mainfield and bottom field. public class ChatLayoutManager extends Manager { private Field bottomField; private Field mainField; private Field titleField; public ChatLayoutManager(long style) { super(style); } protected void sublayout(int width, int height) { setExtent(width, height); int y = 0; if (bottomField != null) { layoutChild(bottomField, width, height); // This goes at the bottom of the screen setPositionChild(bottomField, 0, height-bottomField.getHeight()); height -= bottomField.getHeight(); } if (titleField != null) { layoutChild(titleField, width, height); // This goes at the top of the screen setPositionChild(titleField, 0, 0); height -= titleField.getHeight(); y += titleField.getHeight(); } if (mainField != null) { layoutChild(mainField, width, height); // This goes just below the title field (if any) setPositionChild(mainField, 0, y); } } public void setMainField(Field f) { mainField = f; add(f); } public void setBottomField(Field f) { bottomField = f; add(f); } public void setTitleField(Field f) { titleField = f; add(f); } Then i create another field (ChatField) extended from manager to add to mainfield in the ChatLayoutManager class which i have created above. public class ChatField extends Manager{ private Field _contentField[]; protected ChatField(){ super(Manager.HORIZONTAL_SCROLL | Manager.VERTICAL_SCROLL); } // TODO Auto-generated constructor stub} protected synchronized void sublayout(int width, int height) { // TODO Auto-generated method stub setExtent(width, height); int x = 0; int y = 0; if(_contentField.length > 0){ for(int i = 0 ;i<_contentField.length; i++){ //if(getManager() == this){ this.layoutChild(_contentField[i], _contentField[i].getWidth(), _contentField[i].getHeight()); this.setPositionChild(_contentField[i], x, y); if(_contentField[i++]!= null){ if ((_contentField[i].getWidth() + _contentField[i].getWidth()) >= width){ x = 0; y += _contentField[i].getHeight(); } else{ x += _contentField[i].getWidth(); } } //} } } } public void setContentField(Field field[]){ _contentField = field; } } And now, when i create some fields(such as TextField, BitmapField ...) added to ChatField, the program has an error "Field is not a child of this manager". The reason is when the framework invokes the sublayout function of the ChatField class , when sublayout starts calling layoutChild function the manager of field is not ChatField but ChatlayoutManager. I've experience hard time trying to resolve this problem, still I have no solution. Anybody can give me some suggestions? I really appreciate.

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  • Paging in MVC + Jquery

    - by kart
    Dear all, I need to add paging for my users view page, i got all the datas using Json to show in the table..i need to add paging and and also i can able to change number of users to show in a particular page. any simple Jquery plugin or source code will be very much helpful to me. thanks in advance, K

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  • scrollTop in defferent browers.

    - by zjm1126
    shortcut.add("up",function() { alert( document.body.scrollTop) if (document.documentElement&& typeof document.documentElement.scrollTop=='number'){ document.documentElement.scrollTop-=100 } else if (document.body) { document.body.scrollTop-=100 } }) shortcut.add("down",function() { if (document.documentElement&&typeof document.documentElement.scrollTop=='number' ){ document.documentElement.scrollTop+=100 } else if (document.body) { document.body.scrollTop+=100 } }) it can running in firefox,but not in chrome and safari thanks

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  • Mysql - Rank field for a query

    - by Mark
    How can I add a field that contains a rows rank within the result set of a query? Initially I used php to rank my results as it was all on a single page. Now I have added multiple pages so now even though I am on the second page the first result on the page is still '1st'. Obviously I could multiply the page number by the number of results per page and add the result number but I imagine there is a better way within the query. Thanks,

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  • Should you always write code for else cases that "can never happen"?

    - by johnswamps
    Take some code like if (person.IsMale()) { doGuyStuff(); } else { doGirlOtherStuff(); } (Yes, I realize this is bad OO code, it's an example) Should this be written so that to explicitly check if person.isFemale(), and then add a new else that throws an exception? Or maybe you're checking values in an enum, or something like that. You think that no one will add new elements to the enum, but who knows? "Can never happen" sounds like famous last words.

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  • python tarfile adding files without directory hiearchy

    - by theactiveactor
    When I invoke add() on a tarfile object with a file path, the file is added to the tarball with directory hiearchy associated .In other words, if I unzip the tarfile the directories in the original dir hiearchy are reproduced. Is there a way to simply add a plainfile without directory info that untarring the resulting tarball produce a flat list of files?

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  • How to set an onClick attribute that would load dynamic content?

    - by konzepz
    This code is suppose to add an onClick event to each of the a elements, so that clicking on the element would load the content of the page dynamically into a DIV. Now, I got this far - It will add the onClick event, but how can I load the dynamic content? $(document.body).ready(function () { $("li.cat-item a").each(function (i) { this.setAttribute('onclick','alert("[load content dynamically into #preview]")'); }); }); Thank you.

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  • How to create multiple inputs in yii + Q&A admin page

    - by user1764357
    In yii, i am developing page for Creating Question with multiple options using forms. So i have two tables Question QuestionId Question optionId Option OptionId Option To create multiple options, option field should be provided with add button so that after clicking add button, it should display new textbox control to get the new option. All these options displayed in a gridview. So can you please help me. I am very new to yii.

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  • Missing Test Settings template in VS2010 Ultimate

    - by JustLoren
    I'm attempting to add a Test Settings file to my Unit Tests project in VS2010. All websites seem to simply say "Go to Add New Item Installed Templates Test Settings". However, I don't have Test Settings as an option in my Installed Templates (nor does searching for them online turn up any results). Can someone point me in the right direction for what I need to do?

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  • Use of metadatatype in linq-to-sql

    - by jess
    Hi, I had asked this question http://stackoverflow.com/questions/2442149/adding-more-attributes-to-linq-to-sql-entity Now, when I add Browsable attribute to generated entity in designer,it works.But,when I use the MetaDataType approach,and add Browsable attribute in partial class,it does not work "I added a MetaDataType class, and added browsable attribute to property,but seems to have no effect"

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  • C++ character to int

    - by Vit
    Hi, what happens when you cin letter to int variable? I tried simple code to add 2 int numbers, first read them, than add them. But when I enter letter, it just fails and prints tons of numbers to screen. But what causes this error? I mean, I expected it to load and use ASCII code of that letter.

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  • clean after incomplete / interrupted setup

    - by lm
    I have following question : If setup of some application A was interrupted , and name of it does not appear in Add| Remove program list .I tryed to use Windows Installer CleanUp Utility of Microsoft but if the item does not appear in Add | Remove , the Utility cannot be used . What is right way to remove remaining items from the system ? Your information will be very helpful . Thanks in advance

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  • Find Label Control in Repeater Asp.net

    - by user2769165
    I am using repeater and I want to find the label control in my repeater. here is my code <asp:Repeater ID="friendRepeater" runat="server"> <table cellpadding="0" cellspacing="0"> <ItemTemplate> <tr style=" width:700px; height:120px;"> <td> <div style=" padding-left:180px;"> <div id="leftHandPost" style="float:left; width:120px; height:120px; border: medium solid #cdaf95; padding-top:5px;"> <div id="childLeft" style=" padding-left:5px;"> <div id="photo" style=" border: thin solid black; width:100px;height:100px;"> <asp:Image id="photoImage" runat="server" ImageUrl='<%# String.Concat("Images/", Eval("Picture")) %>' Width="100px" Height="100px" /> </div> </div><!--childLeft--> </div><!--leftHandPost--> </div> </td> <td> <div id="rightHandPost" style=" float:right; padding-right:260px;"> <div id="childRight" style="width:400px; height:120px; border: medium solid #cdaf95; padding-top:5px; padding-left:10px;"> <strong><asp:Label id="lblName" runat="server"><%# Eval("PersonName") %></asp:Label></strong><br /> <div style=" float:right; padding-right:10px;"><asp:Button runat="server" Text="Add" onClick="add" /></div><br /> <asp:Label id="lblID" runat="server"><%# Eval("PersonID") %></asp:Label><br /> <asp:Label id="lblEmail" runat="server"><%# Eval("Email") %></asp:Label> </div><!--childRight--> </div><!--rightHandPost--> </td> </tr> </ItemTemplate> <AlternatingItemTemplate> <tr style=" width:700px; height:120px;"> <td> <div style=" padding-left:180px;"> <div id="Div1" style="float:left; width:120px; height:120px; border: medium solid #cdaf95; padding-top:5px;"> <div id="Div2" style="padding-left:5px;"> <div id="Div3" style=" border: thin solid black; width:100px;height:100px;"> <asp:Image id="photoImage" runat="server" ImageUrl='<%# String.Concat("Images/", Eval("Picture")) %>' Width="100px" Height="100px" /> </div> </div><!--childLeft--> </div><!--leftHandPost--> </div> </td> <td> <div id="Div4" style=" float:right; padding-right:260px;"> <div id="Div5" style="width:400px; height:120px; border: medium solid #cdaf95; padding-top:5px; padding-left:10px;"> <strong><asp:Label id="lblName" runat="server"><%# Eval("PersonName")%></asp:Label></strong> <div style=" float:right; padding-right:10px;"><asp:Button id="btnAdd" runat="server" Text="Add" onClick="add"></asp:Button></div><br /> <br /> <asp:Label id="lblID" runat="server"><%# Eval("PersonID") %></asp:Label><br /> <asp:Label id="lblEmail" runat="server"><%# Eval("Email") %></asp:Label> </div><!--childRight--> </div><!--rightHandPost--> </td> </tr> </AlternatingItemTemplate> <FooterTemplate> </table> </FooterTemplate> </asp:Repeater> Here is the code behind for the add button. protected void add(object sender, EventArgs e) { DateTime date = DateTime.Now; System.Web.UI.WebControls.Label la = (System.Web.UI.WebControls.Label)friendRepeater.FindControl("PersonID"); String id = la.Text; try { MySqlConnection connStr = new MySqlConnection(); connStr.ConnectionString = "Server = localhost; Database = healthlivin; Uid = root; Pwd = khei92;"; String insertFriend = "INSERT INTO contactFriend(friendID, PersonID, PersonIDB, date) values (@id, @personIDA, @personIDB, @date)"; MySqlCommand cmdInsertStaff = new MySqlCommand(insertFriend, connStr); cmdInsertStaff.Parameters.AddWithValue("@id", "F000004"); cmdInsertStaff.Parameters.AddWithValue("@personIDA", "M000001"); cmdInsertStaff.Parameters.AddWithValue("@personIDB", id); cmdInsertStaff.Parameters.AddWithValue("@date", date); connStr.Open(); cmdInsertStaff.ExecuteNonQuery(); MessageBox.Show("inserted"); connStr.Close(); } catch (Exception ex) { MessageBox.Show(ex.ToString()); } } I have get the error of Object reference not set to an instance of an object. I think is because there are no value in the Label. The Find Control are not working. May I know how can fix this problem? Thank you very much

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  • I am working with Visual Studio 2008. Actually there is References folder missing

    - by Azhar
    I am working with Visual Studio 2008. Actually there is References folder missing in its solution explorer. When I create a New web Application it has References folder but when I add new .aspx file it also adds .aspx.designer.cs file with it and its does not show master page option in add dialogue. but in the old web application it shows the master page option where master page file is already added. whats the difference between these two solutions.

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  • DataGridView formatting

    - by Vadim
    I have a DGV with columns "code" and "name". Depends of lenght of a code I want to add tabulation to the "name" cells, to show structure of a data. Like that in this picture: How is it better to do? I think there is a better way then just loop for all rows and add spaces in front of names, right?

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  • git repository sync between computers, when moving around?

    - by Johan
    Hi Let's say that I have a desktop pc and a laptop, and sometimes I work on the desktop and sometimes I work on the laptop. What is the easiest way to move a git repository back and forth? I want the git repositories to be identical, so that I can continue where I left of at the other computer. I would like to make sure that I have the same branches and tags on both of the computers. Thanks Johan Note: I know how to do this with SubVersion, but I'm curious on how this would work with git. If it is easier, I can use a third pc as classical server that the two pc:s can sync against. Note: Both computers are running Linux. Update: So let's try XANI:s idea with a bare git repo on a server, and the push command syntax from KingCrunch. In this example there is two clients and one server. So let's create the server part first. ssh user@server mkdir -p ~/git_test/workspace cd ~/git_test/workspace git --bare init So then from one of the other computers I try to get a copy of the repo with clone: git clone user@server:~/git_test/workspace/ Initialized empty Git repository in /home/user/git_test/repo1/workspace/.git/ warning: You appear to have cloned an empty repository. Then go into that repo and add a file: cd workspace/ echo "test1" > testfile1.txt git add testfile1.txt git commit testfile1.txt -m "Added file testfile1.txt" git push origin master Now the server is updated with testfile1.txt. Anyway, let's see if we can get this file from the other computer. mkdir -p ~/git_test/repo2 cd ~/git_test/repo2 git clone user@server:~/git_test/workspace/ cd workspace/ git pull And now we can see the testfile. At this point we can edit it with some more content and update the server again. echo "test2" >> testfile1.txt git add testfile1.txt git commit -m "Test2" git push origin master Then we go back to the first client and do a git pull to see the updated file. And now I can move back and forth between the two computers, and add a third if I like to.

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  • JQuery addclass to another div (but not parent) if no data is found

    - by Danny
    I have this to add a class to the main table that the report is in if there is no data returned. $('#report-area table td:contains("Sorry, your search did not return any data")').parents('#reportArea').addClass('no-report-data') However, I have another div area "#report-footer" but it's not inside #report-area. I'd like to also add the .no-report-data class to "#report-footer" as well but in this case I don't think the .parents selector will work. Is there another selector I can use to do this?

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  • Cannot find MediaPlayer.framework

    - by manateeman
    Hi Working with iPhone simulator 3.1.3 - Trying to add a framework to my project - MediaPlayer.framework. I tried the "Add existing framework" method - but cannot find the file in folder "Frameworks". Am I looking in the wrong place? Wrong filename? Wrong space/time continuum? I also did a search for the file - to no avail. Not in /System/Library/Frameworks/ Do I have to download it?

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  • MySql Alter Syntax error with mulitple FK

    - by acidzombie24
    If i do the first one i have no problem. When i do addition i get a syntax error. What is wrong with the syntax? The error says syntax error near [entire 2nd line] alter table `ban_Status` add FOREIGN KEY (`banned_user`) REFERENCES `user_data`(`id`) alter table `ban_Status` add FOREIGN KEY (`banned_user`) REFERENCES `user_data`(`id`), FOREIGN KEY (`banning_user`) REFERENCES `user_data`(`id`), FOREIGN KEY (`unban_user`) REFERENCES `user_data`(`id`)

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  • Custom warning in Xcode

    - by maximumnamelength
    I'm working on an API library and I'd like to add a few warnings that would appear when another developers builds the app if an optional apikey is not included. It should be buildable w/o the key (since it's optional) so I can't just add a syntax error to force a build error. I know Xcode supports TODO and FIXME but those aren't really highlighted anywhere major. Any other thoughts on how to approach this?

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  • How to handle form data in cakephp

    - by Vinay
    i have a form for adding people object ,i want to add as many people without saving people in database,after clicking add people form submit button,the same form should appear without saving the form data to database,instead it should save to the session.please explain in detail if possible with the help of a example to do this, i have not found any tutorial which explains cakephp session in detail.

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  • Drupal menu permissions question

    - by Luke
    I'm creating an admin module for my client that gives then access to some administration functionality concerning their content. I'm starting off my adding some permissions in my module by implementing hook_perm: function mymodule_perm() { return array( 'manage projects', ); } I can then create my menu by adding to the admin section that already exists: function mymodule_menu() { $items['admin/projects'] = array( 'title' => 'Projects', 'description' => 'Manage your projects.', 'page callback' => 'manage_projects_overview', 'access callback' => 'user_access', 'access arguments' => array('manage projects'), 'type' => MENU_NORMAL_ITEM, 'weight' => -100, ); $items['admin/projects/add'] = array( 'title' => 'Add project', 'access arguments' => array('manage projects'), 'page callback' => 'mymodule_projects_add', 'type' => MENU_NORMAL_ITEM, 'weight' => 1, ); return $items; } This will add a Projects section to the Administration area with an Add project sub section. All good. The behavior I want is that my client can only see the Projects section when they log in. I've accomplished this by ticking the "manage projects" permission for authenticated users. Now to give my client actual access to the Administration area I also need to tick "access administration pages" under the "system module" in the users permissions section. This works great, when I log in as my client I can only see the Projects section in the Administration area. There is one thing though, I my Navigation menu shown in the left column I can see the following items: - Administer - Projects - Content management - Site building - Site configuration - User management I was expecting only the see Administer and Projects, not the other ones. When I click e.g. Content Management I get a Content Management titled page with no options. Same for Site Building, Site Configuration and User Management. What's really odd is that Reports is not being shown which is also a top level Administration section. Why are these other items, besides my Projects section, being shown and how can I make them stop from appearing if I'm not logged in as administrator?

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  • How to create collection object in vbscript?

    - by Onnesh
    what should be the parameter for create object the following code dim a set a=CreateObject("Collection") //getting a runtime error saying ActiveX //component can't create object: 'Collection a.add(CreateObject("Collection")) a.Items(0).Add(1) MsgBox(a.Items(0).count) MsgBox(a.Items(0).Item(0))

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