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  • Need some help with onClick and an if/else issue...

    - by Adam
    I have a menu with seven items. If you click the first item, div one shows. If you click any other item (2 through 7) div two shows. That's what I'm looking to do. I'm new at all this but am pretty sure it's an if/else function, such that if I click on <a id="1">, show the first div, else show the second div. I suppose I can do a hide/show to get back to the first div. I'm going to keep poking around, but if I can't find it, any help is surely appreciated.

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  • How to make Solution Explorer behave after clearing search?

    - by stijn
    I currently have a VS installation with no extensions to see how that works out. For navigation that means making heavy use of Ctrl+; aka Search Solution Explorer. While the search itself is ok, it has one major drawback for me that makes it a pain to use for me (both with keyboard and mouse): Solution with two projects, one collapsed, one opened: Use Ctrl+; and start typing until match found from collapsed project What I want now is to simply clear the search and return to the previous view. Seems like a pretty standard requirement, no? But there seems to be no such functionality built in. Problem with the current commands that come close (pressing Esc, clicking Back or Home buttons in Solution Explorer Toolbar) is all the same: they have the extremely annoying behaviour that they insist on suddenly uncollapsing the previously collapsed project and track the match found! (Btw the Track Active Item in Solution Explorer option is turned of in the options). This makes no sense from a UX point of view? You select some kind of 'undo' command, the search box clears which is expected, but then suddenly there's an item visible from a previous search: So if the collapsed project has like 50 items in it, solution explorer is now useless visually since it litters the screen with stuff you don't want to see, and worse you have to manually collapse the project again to return to the previous view. Is there a way around this? I thought maybe keyboard shortcuts for Back/Home would be different, but the commands do not seem to be registered. I looked into EnvDTE80.DTE2.ToolWindows.SolutionExplorer but it has no properties/methods that have anything to do with this issue. And somewhere in the tree there is a Microsoft.VisualStudio.PlatformUI.SolutionPivotNavigator which is probably the class responsible for this behaviour, but I have no idea how to access it?

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  • Apply Quaternion to Camera in libGDX

    - by Alex_Hyzer_Kenoyer
    I am trying to rotate my camera using a Quaternion in libGDX. I have a Quaternion created and being manipulated but I have no idea how to apply it to the camera, everything I've tried hasn't moved the camera at all. Here is how I set up the rotation Quaternion: public void rotateX(float amount) { tempQuat.set(tempVector.set(1.0f, 0.0f, 0.0f), amount * MathHelper.PIOVER180); rotation = rotation.mul(tempQuat); } public void rotateY(float amount) { tempQuat.set(tempVector.set(0.0f, 1.0f, 0.0f), amount * MathHelper.PIOVER180); rotation = tempQuat.mul(rotation); } Here is how I am trying to update the camera (Same update method as the original libGDX version but I added the part about the rotation matrix to the top): public void update(boolean updateFrustum) { float[] matrix = new float[16]; rotation.toMatrix(matrix); Matrix4 m = new Matrix4(); m.set(matrix); camera.view.mul(m); //camera.direction.mul(m).nor(); //camera.up.mul(m).nor(); float aspect = camera.viewportWidth / camera.viewportHeight; camera.projection.setToProjection(Math.abs(camera.near), Math.abs(camera.far), camera.fieldOfView, aspect); camera.view.setToLookAt(camera.position, tempVector.set(camera.position).add(camera.direction), camera.up); camera.combined.set(camera.projection); Matrix4.mul(camera.combined.val, camera.view.val); if (updateFrustum) { camera.invProjectionView.set(camera.combined); Matrix4.inv(camera.invProjectionView.val); camera.frustum.update(camera.invProjectionView); } }

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  • iPhone SDK math - pythagorean theorem problem!

    - by Flafla2
    Just as a practice, I am working on an app that solves the famous middle school pythagorean theorem, a squared + b squared = c squared. Unfortunately, the out-coming answer has, in my eyes, nothing to do with the actual answer. Here is the code used during the "solve" action. - (IBAction)solve { int legoneint; int legtwoint; int hypotenuseint; int lonesq = legoneint * legoneint; int ltwosq = legtwoint * legtwoint; int hyposq = hypotenuseint * hypotenuseint; hyposq = lonesq + ltwosq; if ([legone.text isEqual:@""]) { legtwoint = [legtwo.text intValue]; hypotenuseint = [hypotenuse.text intValue]; answer.text = [NSString stringWithFormat:@"%d", legoneint]; self.view.backgroundColor = [UIColor blackColor]; } if ([legtwo.text isEqual:@""]) { legoneint = [legone.text intValue]; hypotenuseint = [hypotenuse.text intValue]; answer.text = [NSString stringWithFormat:@"%d", legtwoint]; self.view.backgroundColor = [UIColor blackColor]; } if ([hypotenuse.text isEqual:@""]) { legoneint = [legone.text intValue]; legtwoint = [legtwo.text intValue]; answer.text = [NSString stringWithFormat:@"%d", hypotenuseint]; self.view.backgroundColor = [UIColor blackColor]; } } By the way, legone, legtwo, and hypotenuse all represent the UITextField that corresponds to each mathematical part of the right triangle. Answer is the UILabel that tells, you guessed it, the answer. Does anyone see any flaws in the program? Thanks in advance!

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  • implementing stretchable dialog borders in iphone sdk

    - by Joey
    Hi, I want to implement dialog borders that scale to the size I require the dialog to be. Perhaps there is a better more conventional name for this sort of thing. If there is, if someone would edit the title, that'd be great. Anyhow, I'd like to do this so I can have dialogs of any size without the visual artifacts that come with scaling border art to small, large, or wacky unproportional dimentions. I have a few ideas on how this is done, but am not sure which is better for iphone. I have a few questions. 1) Should I make a containing view object that basically overloads its drawRect method and draws the images where they should be at their appropriate scale when the method is called, or should I main a containing view object that simply contains 8 UIImageViews? I suspect the latter approach won't work if I need to actively scale the resulting dialog class like in an animation. 1b) If overloading drawRect is the way to go, does someone have some sample code or a link to an example that demonstrates drawing an image directly from drawRect()? 2) Is it generally better to create a) a 3 x 3 image where the segments are in their appropriate 1x1 grid of the image? If so, is it simple to draw from a portion of this image onto my target view in drawRect (if the former assumption is correct that I should use drawRect)? b) The pieces separately in 8 different files?

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  • C# method generic params parameter bug?

    - by Mike M
    Hey, I appears to me as though there is a bug/inconsistency in the C# compiler. This works fine (first method gets called): public void SomeMethod(string message, object data); public void SomeMethod(string message, params object[] data); // .... SomeMethod("woohoo", item); Yet this causes "The call is ambiguous between the following methods" error: public void SomeMethod(string message, T data); public void SomeMethod(string message, params T[] data); // .... SomeMethod("woohoo", (T)item); I could just use the dump the first method entirely, but since this is a very performance sensitive library and the first method will be used about 75% of the time, I would rather not always wrap things in an array and instantiate an iterator to go over a foreach if there is only one item. Splitting into different named methods would be messy at best IMO. Thoughts?

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  • Android Video Layout and backbutton to activity

    - by Marcjc
    I have an application where you can click on a button, this takes you to a new activity with four new buttons, listen, bio, ringtone, and watch. My watch button kicks off the following code: Button cmd_watchme = (Button)this.findViewById(R.id.watch); cmd_watchme.setOnClickListener(new View.OnClickListener() { public void onClick(View view) { setContentView(R.layout.tvvideo); VideoView video=(VideoView)findViewById(R.id.VideoView); MediaController mediaController = new MediaController(andy.this); mediaController.setAnchorView(video); video.setMediaController(mediaController); video.setVideoURI(videopath); video.start(); } }); After the video is displayed I am trying to get the backbutton on the phone itself to take the user back to the four button selection activity, listen, bio, ringtone, and watch. Question is, how do i do this? I was figuring if there was a way to change the ContentView after the video is displayed back to the main one for the four button page but could not figure it out. When I press the backbutton on the device, it takes me two levels up to the main selection activity not the four button activity. I hope this was somewhat clear. Thanks for any help.

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  • What issues ensue from having multiple versions of Office installed?

    - by Michael Sorens
    My ultimate question is embodied in the title but I thought it might be helpful to others if I detail what instigated my inquiry and my examination of the problem. To me, the first rule of software updates is Primum non nocere -- first, do no harm. So with my Windows 7 system containing both Office 2003 and Office 2010 I blithely proceeded to install this month's updates from Microsoft, containing updates for both versions of Office. While Microsoft officially does not recommend running multiple versions (see, for example, Running Multiple Versions of Microsoft Excel it is possible; I have had two versions installed for a year or more and have never run into an issue before. One thing that is always mentioned is installation order, i.e., the one you want to open files by default should be installed last. I wanted 2010 as my default so I had indeed installed 2003 first then, years later, 2010. So with this round of Windows updates, either it installed patches to 2010 before 2003, knocking out the file association, or the 2003 patch was more comprehensive, in the sense of touching the file association while the 2010 did not. In any case, after updates, double-clicking a .xls file opened 2003 rather than 2010. Web search indicated either: Use the file associations control panel to re-associate .xls files with the correct version of excel. I looked at this first, but it showed what seemed to be an unversioned "Excel" associated with .xls files so I did not check further. (This turned out to be an error on my part; more later.) Re-install versions in the desired order; I find this unreasonable. Run the repair option of the Office installer on the desired version; still seems more work than one should need. Run excel from the command line with "/regserver" on the one to be the default and "/unregserver" on the other. Good idea, but further search indicated that neither 2007 nor 2010 support "/regserver" contrary to some posts (e.g. Default Program With Multiple Versions Installed). Since this was a Windows Update issue and Microsoft provides free support for such, I inquired there as well, but succeeded only in getting the suggestion to uninstall all other versions, period; not acceptable to me. What worked for me was going back to the file associations control panel and manually selected the Office 2010 version of Excel. While it appeared no different in the control panel, it did fix the double-click issue. So if all it takes is this simple fix after an update, I can live with that. What I am wondering is: Has anyone seen any other problems related to having multiple versions of Office installed?

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  • Favorite Linux Variety and why?

    - by Cenoc
    Right now I have Fedora dual booted with Windows 7. The reasoning behind that is just because windows was the first OS I ever used and has some essential software, and Fedora is the first linux distribution I tried, but I would like to hear the argument for other distros, as I may be looking to switch. Thanks ahead of time.

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  • How to play mpg/3gp 5 sec video at start of application?

    - by Asad Ahmed
    I am developing an application in which i want to play a short 5 seconds video at the startup. which is the best format 3gp, mpg or something else? i have generated a title activity. I wanted to play the video before title. Help please!!! Below is the code of my title activity. public class Title extends Activity { @Override protected void onCreate(Bundle savedInstanceState) { // TODO Auto-generated method stub super.onCreate(savedInstanceState); setContentView(R.layout.title); setTitle("M.I.S.T"); this.setTitleColor(Color.BLUE); View title = getWindow().findViewById(android.R.id.title); View titleBar = (View) title.getParent(); titleBar.setBackgroundColor(Color.YELLOW); Thread timer = new Thread(){ public void run(){ try{ sleep(3000); }catch (InterruptedException e){ e.printStackTrace(); }finally{ Intent open= new Intent("com.congestion6.asad.MENU"); startActivity(open); } } }; timer.start(); } protected void onPause() { // TODO Auto-generated method stub super.onPause(); finish(); } }

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  • Haskell - Parsec Parsing <p> element

    - by Martin
    I'm using Text.ParserCombinators.Parsec and Text.XHtml to parse an input like this: This is the first paragraph example\n with two lines\n \n And this is the second paragraph\n And my output should be: <p>This is the first paragraph example\n with two lines\n</p> <p>And this is the second paragraph\n</p> I defined: line= do{ ;t<-manyTill (anyChar) newline ;return t } paragraph = do{ t<-many1 (line) ;return ( p << t ) } But it returns: <p>This is the first paragraph example\n with two lines\n\n And this is the second paragraph\n</p> What is wrong? Any ideas? Thanks!

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  • Transferring Data Directly between 2 Connections in Indy (TIdContext)

    - by killercode
    ive a sever running TIdTCPServer, and Client Using Web Browser (or any other software) to Communicate, i dunno the protocol, but what im trying to do is to Send The Data between the client and another Connection (Both Connected to the same TIdTCPServer) for example the data sent by the first client is transmitted to the second client, and the data sent by the second client is transmitted to the first client, like a proxy (i cant really use a proxy server since its just this one condition) and the TIdTCPServer should still be receiving other clients and processing their data. i stumbled upon the first line of code, since TIdContext.Connection.Socket.ReadLn requires a Delimiter, and the Client's Protocol is unknown to the server. any ideas? thanks.

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  • How do you test a command object in a grails controller integration test?

    - by egervari
    I'm new to grails. How do I test a form command object to make sure that it's working? Here's some setup code in a test. When I try to do it, I get the following exceptions: Error occurred creating command object. org.codehaus.groovy.grails.web.servlet.mvc.exceptions.ControllerExecutionException: Error occurred creating command object. at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) .... Caused by: groovy.lang.MissingPropertyException: No such property: password for class: project.user.RegistrationForm Possible solutions: password Here is my test case. As you can see, I set "password" on the params map... void testSaveWhenDataIsCorrect() { controller.params.emailAddress = "[email protected]" controller.params.password = "secret" controller.params.confirmPassword = "secret" controller.save() assertEquals "success", redirectArgs.view ... } Here's the controller action, that adds the command object as a closure parameter: def save = { RegistrationForm form -> if(form.hasErrors()) { render view: "create", model: [form: form] } else { def user = new User(form.properties) user.password = form.encryptedPassword if(user.save()) { redirect(action: "success") } else { render view: "create", model: [form: form] } } } Here's the command object itself... and note that it DOES have a "password" field... class RegistrationForm { def springSecurityService String emailAddress String password String confirmPassword String getEncryptedPassword() { springSecurityService.encodePassword(password) } static constraints = { emailAddress(blank: false, email: true) password(blank: false, size:4..10) confirmPassword(blank: false, validator: { password != confirmPassword }) } } I'm totally lost in the non-intuitive way to do controllers... Please help.

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  • web ui controls and ASP.NET MVC

    - by ognjenb
    Why will not fill View page of this controller method public ActionResult Person() { testEntities6 testPersons = new testEntities6(); IQueryable<person> persons; DropDownLst.Items.Clear(); DropDownLst.Items.Add("proba"); persons = from i in testPersons.person select i; return View(persons); } and include namespaces: using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.Mvc; using System.Web.Mvc.Ajax; using MvcKVteam.Models; using System.Web.UI; using System.Web.UI.WebControls; using System.Web.UI.WebControls.WebParts; using System.Web.UI.HtmlControls; In view page I put this code: <asp:DropDownList ID="IbekoIngDropDownLst" runat="server"> </asp:DropDownList>

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  • On wordpress.com how to set a category as front page?

    - by Shashank Sawant
    I first referred to a link explaining how to set a page as your front page. What I want is to set a category of my blogs as my front page display. Hoping for an answer, I went to the following link: http://en.forums.wordpress.com/topic/1-category-as-front-page?replies=4 It effectively redirects me to my first link. Though I can make a page on wordpress.com and set it as my front page, I still haven't understood how to set one of my blog categories as my front display.

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  • Parsing an Open XML doc via styled blocks

    - by Chris B. Behrens
    I'm working with docx docs, and I need to parse a document into sections on the basis of headings styled with the "heading 1" style. So if I had a doc like this (markup is pseudocode): <doc> <title style>Doc Title</title style> <heading1>First Section</heading1> ... <heading2>Second Section</heading2> ... <heading3>Third Section</heading3> ... </doc> I'd want to break this into a doc with four sections, the first being the content that precedes the first section. I figure that this is probably pretty simple once you're familiar with Open XML, but I am not. TIA.

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  • facebook open graph meta property og:type of 'website'. The property 'object-name' requires an object of og:type 'object-name'

    - by chinmayahd
    in cake php 1.3 in view ctp i have follow code: $url = 'http://example.com/exmp/explus/books/view/'.$book['Book']['id']; echo $this->Html->meta(array('property' => 'fb:app_id', 'content' => '*******'),'',array('inline'=>false)); echo $this->Html->meta(array('property' => 'og:type', 'content' => 'book'),'',array('inline'=>false)); echo $this->Html->meta(array('property' => 'og:url', 'content' => $url ),'',array('inline'=>false)); echo $this->Html->meta(array('property' => 'og:title', 'content' => $book['Book']['title']),'',array('inline'=>false)); echo $this->Html->meta(array('property' => 'og:description', 'content' => $book['Book']['title']),'',array('inline'=>false)); $imgurl = '../image/'.$book['Book']['id']; echo $this->Html->meta(array('property' => 'og:image', 'content' => $imgurl ),'',array('inline'=>false)); ?> and it gives the following error when i am posting it' { "error": { "message": "(#3502) Object at URL http://example.com/exmp/explus/books/view/234' has og:type of 'website'. The property 'book' requires an object of og:type 'book'. ", "type": "OAuthException", "code": 3502 } } is any one know how to solve it?

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  • gparted dont figure any partition

    - by radi
    hi all , i am trying to install ununtu 10.04 lts on my laptop , first i installed it inside windows and when it boot for first time i got the error message "dont find root file system , try partition table to fix the problem " . and when i want to install it on a single partition (normally) and when it told me to chose a partition i dont find any partition (entire disk) . i have 2 primary partitions and 3 logical partitions . please help me thanks .

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  • How do I perform a flip and grow animation like in iPhoto 09?

    - by Austin
    I'm developing a Cocoa application and want to be able to click a button in one of the views in my NSCollectionView and have a details view flip open and position to the middle of the screen like it does in iPhoto 09 when you click the "i" in the bottom-right hand corner of a photo. The photo "flips" and grows, centered on the window to reveal details about the photo. I'm guessing they're using Core Animation to achieve this. I've been looking at the Lemur Flip example, but when I try to modify it to add repositioning code to the animation, it throws off the flip. Here is the positioning code I've added to the - (IBAction)flip:(id)sender; code of LemurFlip: ... [CATransaction begin]; { NSSize supersize = contentView.frame.size; // Size of window content view NSSize subsize = frontView.frame.size; // Size of view we're flipping out if(!frontView.isHidden) { // Move views to middle of the window [[backView animator] setFrameOrigin:NSMakePoint((supersize.width / 2) - (subsize.width / 2), (supersize.height / 2) - (subsize.height / 2))]; [[frontView animator] setFrameOrigin:NSMakePoint((supersize.width / 2) - (subsize.width / 2), (supersize.height / 2) - (subsize.height / 2))]; } else { // Return views to point of origin [[backView animator] setFrameOrigin:NSMakePoint(0, 0)]; [[frontView animator] setFrameOrigin:NSMakePoint(0, 0)]; } [hiddenLayer addAnimation:[self _flipAnimationWithDuration:flipDuration isFront:NO] forKey:@"flipGroup"]; [visibleLayer addAnimation:[self _flipAnimationWithDuration:flipDuration isFront:YES] forKey:@"flipGroup"]; } [CATransaction commit]; ... Is there a good example of how to do this or some rules for combining these sort of animations?

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  • Need Associated ID Added to a While Loop (php)

    - by user319361
    Been trying to get my head around while loops for the last few days but the code seems very inefficient for what Im trying to achieve. I'm assuming I'm overcomplicating this though nothing I've tried seems to work. Each topic in my forum can have related topic IDs stored in a seperate table. A post ID is also stored in this table, as that specific post references why they are considered related. DB Table contains only: topic_id, related_id, post_id // Get related IDs and post IDs for current topic being viewed $result = $db->query('SELECT related_id, post_id FROM related_topics WHERE topic_id='.$id.''); // If related topics found, put both of the IDs into arrays if ($db->num_rows($result)) { while($cur_related = mysql_fetch_array($result)){ $reltopicarray[] = $cur_related['related_id']; $relpost[] = $cur_related['post_id']; } // If the first array isnt empty, get some additional info about each related ID from another table if(!empty($reltopicarray)) { $pieces = $reltopicarray; $glued = "\"".implode('", "', $pieces)."\""; $fetchtopics = $db->query('SELECT id, subject, author, image, etc FROM topics WHERE id IN('.$glued.')'); } // Print each related topic while($related = mysql_fetch_array($fetchtopics)){ ?> <a href="view.php?id=<?php echo $related['id']; ?>"><?php echo $related['subject']; ?></a> by <?php echo $related['author']; ?> // Id like to show the Post ID below (from the array in the first while loop) // The below link doesnt work as Im outside the while loop by this point. <br /><a href="view.php?post_id=<?php echo $cur_related['post_id']; ?>">View Relationship</a> <?php } ?> The above currently works, however I'm trying to also display the post_id link below each related topic link, as shown above. Would be greatful if someone can lend a hand. Thanks :)

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  • Testing a (big) collection retrieved from a db

    - by Bas
    I'm currently doing integration testing on a live database and I have the following sql statement: var date = DateTime.Parse("01-01-2010 20:30:00"); var result = datacontext.Repository<IObject>().Where(r => r.DateTime > date).First(); Assert.IsFalse(result.Finished); I need to test if the results retrieved from the statement, where the given date is less then the date of the object, have Finished set to False. I do not know how many results I get back and currently I'm getting the first object of the list and check if that object has Finished set to false. I know testing only the first item of the list is not valid testing, as a solution for that I could iterate through the list and check all items on Finished, but putting logic in a Test is kinda going against the concept of writing 'good' tests. So my question is: Does anyone have a good solution of how to properly test the results of this list?

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  • What is the space character for the browser?

    - by Hiro Protagonist
    echo "\n\s\s\s\s\s\s" . "<div id='data-load' data-load='" . $load . "'></div>"; \n works for adding a return in...I tried \s logically for space but this does not work. Keep mind, I don't want this rendered in the browser view...but in the source view ( when you click view-source )...I'm trying to put my html in to a readable form. echo "&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp\n" . "<div id='data-path' data-path='" . $path . "'></div>"; This does not work either. I am composing HTML from PHP... echo " \n" . "<div id='data-load' data-load='" . $load . "'></div>"; This does not work either. Actual Code: public static function setUniversals() { $shared_object = new Shared(); if ( $shared_object->getLoadOn() == 1 ) { $load = 'server'; } else { $load = 'client'; } if( getcwd() === '/home/foo/public_html/develop' ) { $path = 'development'; } else { $path = 'production'; } $shared_object = new Shared(); echo "\n"; echo "\n " . "<div id='data-path' data-path='" . $path . "'></div>"; echo "\n " . "<div id='data-load' data-load='" . $load . "'></div>"; }

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  • Gparted doesn't detect any partitions

    - by radi
    I am trying to install Ubuntu 10.04 LTS on my laptop. First I installed it inside Windows and when it boots for first time I got the error message "couldn't find root filesystem , try partition table to fix the problem " . When I want to install it on a single partition (normally) and when it told me to chose a partition I don't find any partition (entire disk) . I have 2 primary partitions and 3 logical partitions. How can I proceed with the install ?

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  • FTP passive mode with limited port range?

    - by Phil Keeling
    I am running FileZilla FTP Server with passive mode enabled, and due to firewall constraints I have to limit the passive mode port range to only 6 ports. My question is how would FileZilla handle any situation where more than 6 concurrent FTP connections are active and want to passively upload a file. Would it queue the connections and prioritise them in a first in, first out manner? I'm not too familiar with FTP so any insight would be appreciated.

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  • get all words using java

    - by hussain
    i want to know how to get all word using java String first[]={"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"}; String second[]={"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"}; String ch =""; String total[]; for(int i = 0;i<26;i++) { for(int j = 0;j<26;j++) { ch+=first[i]+first[j]; System.out.println(ch); } } i get only 576 words only by this program but the 26! words is 4.03291461 × 1026 how to write the program in java thanks and advance

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