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  • how to display fixed dropdown in django admin?

    - by FurtiveFelon
    Hi all, I would like to display priority information in a drop down. Currently i am using a integer field to store the priority, but i would like to display high/medium/low instead of letting user type in a priority. A way to approximate this is to use a Priority database which stores 3 elements, 1:high, 2:medium, 3:low, but it seems like an overkill. Any easier way would be much appreciated! Jason

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  • Django: How can I protect against concurrent modification of data base entries

    - by Ber
    If there a way to protect against concurrent modifications of the same data base entry by two or more users? It would be acceptable to show an error message to the user performing the second commit/save operation, but data should not be silently overwritten. I think locking the entry is not an option, as a user might use the "Back" button or simply close his browser, leaving the lock for ever.

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  • Django get_FOO_display and distinct()

    - by datakid
    I've seen answers to both halves of my question, but I can't work out how to marry the two. I have a book model, and a translatedBook model. The translatedBook has a langage set up as model choices in the usual way: LANGUAGES = ( (u'it', u'Italian'), (u'ja', u'Japanese'), (u'es', u'Spanish'), (u'zh-cn', u'Simplified Chinese'), (u'zh-tw', u'Traditional Chinese'), (u'fr', u'French'), (u'el', u'Greek'), (u'ar', u'Arabic'), (u'bg', u'Bulgarian'), (u'bn', u'Bengali'), etc I know that to get "Italian" I have to do translatedBook.get_language_display on a Book object. But how do I get a list of distinct languages in their long format? I've tried: lang_avail = TargetText.objects.values('language').distinct().order_by('language') lang_avail = TargetText.objects.distinct().order_by('language').values('language'). lang_avail = TargetText.objects.all().distinct('language').order_by('language') but I can't seem to get what I want - which is a list like: "English, Italian, Simplified Chinese, Spanish" The final lang_avail listed above didn't return the list of 5, it returned the list of 355 (ie, # of books) with multiple repeats....

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  • Django comments form validation, check if the comment is from authenticated user

    - by Headcrab
    I wanted to add reCaptcha to the comment form, but only for non-authenticated users. I've created my own comments app, using reCaptcha more or less according to this post, except that I don't have any (explicit) view function to post the comment, but instead I check captcha as a part of form validation process. Everything works fine so far. Now, how do I disable reCaptcha for a logged in user? Removing all reCaptcha-related fields in the template is no problem, but how do I validate the form, not checking captcha if the comment if from an authenticated user? Alternatively, is there a way to use two different comment form classes, depending on whether the user is authenticated or not?

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  • How to create relationship between two tables with revisions using Entity Framework

    - by Chris Ridenour
    So I am in the process of redesigning a small database (and potentially a much larger one) but want to show the value of using revisions / history of the business objects. I am switching the data from Access to MSSQL 2008. I am having a lot of internal debate on what version of "revision history" to use in the design itself - and thought I had decided to add a "RevisionId" to all tables. With this design - adding a RevisionId to all tables we would like tracked - what would be the best way to create Navigational Properties and Relationships between two tables such as | Vendor | VendorContact | where a Vendor can have multiple contacts. The Contacts themselves will be under revision. Will it require custom extensions or am I over thinking this? Thanks in advance.

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  • Django Generating RSS feed with description

    - by Issy
    Hey Guys, I am trying to generate a full rss feed, however when loading the feed in Mail, it just shows the title, with a read more link at the bottom. I have tried several different options. But none seem to work. I would like to generate the feed with a combination of several feeds in my modl. Here is the code i have tried: class LatestEvents(Feed): description_template = "events_description.html" def title(self): return "%s Events" % SITE.name def link(self): return '/events/' def items(self): events = list(Event.objects.all().order_by('-published_date')[:5]) return events author_name = 'Latest Events' def item_pubdate(self, item): return item.published_date And in my template which is stored in TEMPLATE_ROOT/feeds/ {{ obj.description|safe }} <h1>Event Location Details</h1> {{ obj.location|safe }} Even if i hard code the description it does not work.

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  • django related_name for field clashes.

    - by Absolute0
    I am getting a field clash in my models: class Visit(models.Model): user = models.ForeignKey(User) visitor = models.ForeignKey(User) Error: One or more models did not validate: profiles.visit: Accessor for field 'user' clashes with related field 'User.visit_set'. Add a related_name argument to the definition for 'user'. profiles.visit: Accessor for field 'visitor' clashes with related field 'User.visit_set'. Add a related_name argument to the definition for 'visitor'. what would be a sensible 'related_field' to use on visitor field? This model basically represents the visits that take place to a particular user's profile. Also should I replace any of the ForeignKey's with a ManyToManyField? The logic is a bit confusing. Edit: This seems to fix it, but I am unsure if its what I want. :) class Visit(models.Model): user = models.ForeignKey(User) visitor = models.ForeignKey(User, related_name='visitors')

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  • Django left join m2m field.

    - by duder
    Here's my Model: class User(models.Model): pass class Item(models.Model): pass class ItemVote(models.Model): user = models.ForeignKey(User) item = models.ForeignKey(Item) vote = models.BooleanField() I want to retrieve a list of Items, and I want to know if the current user has voted for each Item. How do I alter my query object so that it will generate sql similar to: SELECT ... FROM items LEFT OUTER JOIN item_votes ON (item_votes.user_id = ? AND item_votes.item_id = items.id)

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  • Django nested formsets

    - by dragoon
    Hi, I have an edit object view that contains a formset(one or many if this matters), now I want to create a page that can display multiple edit object forms and submit it in a single form. What is the correct way to achieve this task?

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  • How to cutomize a modelform widget in django 1.1?

    - by muudscope
    I'm trying to modify a django form to use a textarea instead of a normal input for the "address" field in my house form. The docs seem to imply this changed from django 1.1 (which I'm using) to 1.2. But neither approach is working for me. Here's what I've tried: class HouseForm(forms.ModelForm): address = forms.Textarea() # Should work with django 1.1, but doesn't class Meta: model = House #widgets = { 'address': forms.Textarea() } # 1.2 style - doesn't work either.

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  • Django Piston - how can I create custom methods?

    - by orokusaki
    I put my questions in the code comments for clarity: from piston.handler import AnonymousBaseHandler class AnonymousAPITest(AnonymousBaseHandler): fields = ('update_subscription',) def update_subscription(self, request, months): # Do some stuff here to update a subscription based on the # number of months provided. # How the heck can I call this method? return {'msg': 'Your subscription has been updated!'} def read(self, request): return { 'msg': 'Why would I need a read() method on a fully custom API?' }

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  • django admin site - filtering available objects for user

    - by JPG
    I have models that belong to some 'group' (Company class). I want to add users, who will also belong to a one group and should be able to edit/manage/add objects with membership in associated group. something like: class Company() class Something() company = ForeignKey(Company) user Microsoft_admin company = ForeignKey(Company) and this user should only see and edit objects belonging to associated Company in the Admin Interface. How to acomplish that?

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  • How to make Django work with unsupported MySQL drivers such as gevent-mysql or Concurrence's MySQL d

    - by Continuation
    I'm interested in running Django on an async framework like Concurrence or gevent. Both frameworks come with its own async MySQL driver. Problem is Django only officially supports MySQLdb. What do I need to do to make Django work with the MySQL drivers that come with gevent or Concurrence? Is there a step-by-step guide somewhere that I can follow? Is this a major undertaking? Thanks.

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  • Specifying different initial values for fields in inherited models (django)

    - by Shawn Chin
    Question : What is the recommended way to specify an initial value for fields if one uses model inheritance and each child model needs to have different default values when rendering a ModelForm? Take for example the following models where CompileCommand and TestCommand both need different initial values when rendered as ModelForm. # ------ models.py class ShellCommand(models.Model): command = models.Charfield(_("command"), max_length=100) arguments = models.Charfield(_("arguments"), max_length=100) class CompileCommand(ShellCommand): # ... default command should be "make" class TestCommand(ShellCommand): # ... default: command = "make", arguments = "test" I am aware that one can used the initial={...} argument when instantiating the form, however I would rather store the initial values within the context of the model (or at least within the associated ModelForm). My current approach What I'm doing at the moment is storing an initial value dict within Meta, and checking for it in my views. # ----- forms.py class CompileCommandForm(forms.ModelForm): class Meta: model = CompileCommand initial_values = {"command":"make"} class TestCommandForm(forms.ModelForm): class Meta: model = TestCommand initial_values = {"command":"make", "arguments":"test"} # ------ in views FORM_LOOKUP = { "compile": CompileCommandFomr, "test": TestCommandForm } CmdForm = FORM_LOOKUP.get(command_type, None) # ... initial = getattr(CmdForm, "initial_values", {}) form = CmdForm(initial=initial) This feels too much like a hack. I am eager for a more generic / better way to achieve this. Suggestions appreciated. Other attempts I have toyed around with overriding the constructor for the submodels: class CompileCommand(ShellCommand): def __init__(self, *args, **kwargs): kwargs.setdefault('command', "make") super(CompileCommand, self).__init__(*args, **kwargs) and this works when I try to create an object from the shell: >>> c = CompileCommand(name="xyz") >>> c.save() <CompileCommand: 123> >>> c.command 'make' However, this does not set the default value when the associated ModelForm is rendered, which unfortunately is what I'm trying to achieve. Update 2 (looks promising) I now have the following in forms.py which allow me to set Meta.default_initial_values without needing extra code in views. class ModelFormWithDefaults(forms.ModelForm): def __init__(self, *args, **kwargs): if hasattr(self.Meta, "default_initial_values"): kwargs.setdefault("initial", self.Meta.default_initial_values) super(ModelFormWithDefaults, self).__init__(*args, **kwargs) class TestCommandForm(ModelFormWithDefaults): class Meta: model = TestCommand default_initial_values = {"command":"make", "arguments":"test"}

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  • Django display manytomany field in form when definition is on other model

    - by John
    Hi I have the definition for my manytomany relationship on one model but want to display the field on the form of my other model. How do I do this? for example: # classes class modelA(models.Model): name = models.CharField(max_length=300) manytomany = models.ManyToManyField(modelA) class modelB(models.Model): name = models.CharField(max_length=300) # forms class modelBForm(forms.ModelForm): class Meta: model = modelB If I then used modelBForm it would show a select box with the models from modelA rather than just name. Thanks

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  • How do I restrict foreign keys choices to related objects only in django

    - by Jeff Mc
    I have a two way foreign relation similar to the following class Parent(models.Model): name = models.CharField(max_length=255) favoritechild = models.ForeignKey("Child", blank=True, null=True) class Child(models.Model): name = models.CharField(max_length=255) myparent = models.ForeignKey(Parent) How do I restrict the choices for Parent.favoritechild to only children whose parent is itself? I tried class Parent(models.Model): name = models.CharField(max_length=255) favoritechild = models.ForeignKey("Child", blank=True, null=True, limit_choices_to = {"myparent": "self"}) but that causes the admin interface to not list any children.

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  • django join-like expansion of queryset

    - by jimbob
    I have a list of Persons each which have multiple fields that I usually filter what's upon, using the object_list generic view. Each person can have multiple Comments attached to them, each with a datetime and a text string. What I ultimately want to do is have the option to filter comments based on dates. class Person(models.Model): name = models.CharField("Name", max_length=30) ## has ~30 other fields, usually filtered on as well class Comment(models.Model): date = models.DateTimeField() person = models.ForeignKey(Person) comment = models.TextField("Comment Text", max_length=1023) What I want to do is get a queryset like Person.objects.filter(comment__date__gt=date(2011,1,1)).order_by('comment__date') send that queryset to object_list and be able to only see the comments ordered by date with only so many objects on a page. E.g., if "Person A" has comments 12/3/11, 1/2/11, 1/5/11, "Person B" has no comments, and person C has a comment on 1/3, I would see: "Person A", 1/2 - comment "Person C", 1/3 - comment "Person A", 1/5 - comment I would strongly prefer not to have to switch to filtering based on Comments.objects.filter(), as that would make me have to largely repeat large sections of code in the both the view and template. Right now if I tried executing the following command, I will get a queryset returning (PersonA, PersonC, PersonA), but if I try rendering that in a template each persons comment_set will contain all their comments even if they aren't in the date range. Ideally they're would be some sort of functionality where I could expand out a Person queryset's comment_set into a larger queryset that can be sorted and ordered based on the comment and put into a object_list generic view. This normally is fairly simple to do in SQL with a JOIN, but I don't want to abandon the ORM, which I use everywhere else.

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  • Seeding many to many tables with Entity Framework

    - by Doozer1979
    I have a meeting entity and a users entity which have a many to many relationship. I'm using Autopoco to create seed data for the Users and meetings How do i seed the UserMeetings linking table that is created by EntityFramework with seed data? The linking table has two fields in it; User_Id, and Meeting_ID. I'm looping through the list of users that autopoco creates and attaching a random number of meetings Here's what i've got so far. foreach (var user in userList) { var rand = new Random(); var amountOfMeetingsToAdd = rand.Next(1, 300); for (var i = 0; i <= amountOfMeetingsToAdd; i++) { var randomMeeting = rand.Next(1, MeetingRecords); //Error occurs on This line user.Meetings.Add(_meetings[randomMeeting]); } } I got an 'Object reference not set to an instance of an object.' even though the meeting record that i'm trying to attach does exist. For info all this is happening prior to me saving the context to the DB.

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  • Validating an Autocomplete field in Django

    - by anonymous coward
    I have models similar to the following: class Band(models.Model): name = models.CharField(unique=True) class Event(models.Model): name = models.CharField(max_length=50, unique=True) bands = models.ManyToManyField(Band) and essentially I want to use the validation capability offered by a ModelForm that already exists for Event, but I do not want to show the default Multi-Select list (for 'bands') on the page, because the potential length of the related models is extremely long. I have the following form defined: class AddEventForm(ModelForm): class Meta: model = Event fields = ('name', ) Which does what is expected for the Model, but of course, validation could care less about the 'bands' field. I've got it working enough to add bands correctly, but there's no correct validation, and it will simply drop bad band IDs. What should I do so that I can ensure that at least one (correct) band ID has been sent along with my form? For how I'm sending the band-IDs with auto-complete, see this related question: http://stackoverflow.com/questions/1528059/

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  • Django extending user model and displaying form

    - by MichalKlich
    Hello, I am writing website and i`d like to implement profile managment. Basic thing would be to edit some of user details by themself, like first and last name etc. Now, i had to extend User model to add my own stuff, and email address. I am having troubles with displaying form. Example will describe better what i would like achieve. This is mine extended user model. class UserExtended(models.Model): user = models.ForeignKey(User, unique=True) kod_pocztowy = models.CharField(max_length=6,blank=True) email = models.EmailField() This is how my form looks like. class UserCreationFormExtended(UserCreationForm): def __init__(self, *args, **kwargs): super(UserCreationFormExtended, self).__init__(*args, **kwargs) self.fields['email'].required = True self.fields['first_name'].required = False self.fields['last_name'].required = False class Meta: model = User fields = ('username', 'first_name', 'last_name', 'email') It works fine when registering, as i need allow users to put username and email but when it goes to editing profile it displays too many fields. I would not like them to be able to edit username and email. How could i disable fields in form? Thanks for help.

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  • How insert 2 different forms on the same page in Django

    - by xRobot
    I have to insert 2 forms in the same page: 1) Registration form 2) Login form . So if I use this in the views.py: if request.method == 'POST': form = registrationForm(request.POST) if form.is_valid(): form.save() return render_to_response('template.html', { 'form': form, }) I will get error by submitting one of two forms. How can I distinguish the 2 forms submitting in the views ?

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  • Django design question: extending User to make users that can't log in

    - by jobrahms
    The site I'm working on involves teachers creating student objects. The teacher can choose to make it possible for a student to log into the site (to check calendars, etc) OR the teacher can choose to use the student object only for record keeping and not allow the student to log in. In the student creation form, if the teacher supplies a username and a password, it should create an object of the first kind - one that can log in, i.e. a regular User object. If the teacher does not supply a username/password, it should create the second type. The other requirement is that the teacher should be able to go in later and change a non-logging-in student to the other kind. What's the best way to design for this scenario? Subclass User and make username and password not required? What else would this affect?

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  • django form creation on init

    - by John
    Hi, How can I add a field in the form init function? e.g. in the code below I want to add a profile field. class StaffForm(forms.ModelForm): def __init__(self, user, *args, **kwargs): if user.pk == 1: self.fields['profile'] = forms.CharField(max_length=200) super(StaffForm, self).__init__(*args, **kwargs) class Meta: model = Staff I know I can add it just below the class StaffForm.... line but I want this to be dynamic depending on what user is passed in so can't do it this way. Thanks

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