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• What sorts of tools make a Django Developer valuable? [closed]

  - by MrOodles

  I am a Django Consultant and I want to increase the value that I provide to clients. My first question was an epic failure according to the FAQ. So I'll try again before I delete it. What types of tools should a Django developer have in his tool belt to increase the value to the client? Would a collection of project templates be useful? Are there open-source project templates available that can be forked and altered? Is there a proper way to configure templates to include dependencies for certain types of projects? What about deployment scripts using tools like Puppet or Chef? Does it make a lot of sense to fork Django apps on GitHub and make contributions to open source projects there? Would clients percieve extra value in programmers that are contributing to open source projects? Are there industry best practices for implementing continuous integration in a Django project? I want the answer to be open ended, as I'm at the beginning of my research. I am curious to know what sorts of tools other Django consultants use on a daily and per-project basis, and how they use them.

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• Show models.ManyToManyField as inline, with the same form as models.ForeignKey inline

  - by Kristian

  I have a model similar to the following (simplified): models.py class Sample(models.Model): name=models.CharField(max_length=200) class Action(models.Model): samples=models.ManyToManyField(Sample) title=models.CharField(max_length=200) description=models.TextField() Now, if Action.samples would have been a ForeignKey instead of a ManyToManyField, when I display Action as a TabularInline in Sample in the Django Admin, I would get a number of rows, each containing a nice form to edit or add another Action. However; when I display the above as an inline using the following: class ActionInline(admin.TabularInline): model=Action.samples.through I get a select box listing all available actions, and not a nifty form to create a new Action. My question is really: How do I display the ManyToMany relation as an inline with a form to input information as described? In principle it should be possible since, from the Sample's point of view, the situation is identical in both cases; Each Sample has a list of Actions regardless if the relation is a ForeignKey or a ManyToManyRelation. Also; Through the Sample admin page, I never want to choose from existing Actions, only create new or edit old ones.

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• CharField values disappearing after save (readonly field)

  - by jamida

  I'm implementing simple "grade book" application where the teacher would be able to update the grades w/o being allowed to change the students' names (at least not on the update grade page). To do this I'm using one of the read-only tricks, the simplest one. The problem is that after the SUBMIT the view is re-displayed with 'blank' values for the students. I'd like the students' names to re-appear. Below is the simplest example that exhibits this problem. (This is poor DB design, I know, I've extracted just the relevant parts of the code to showcase the problem. In the real example, student is in its own table but the problem still exists there.) models.py class Grade1(models.Model): student = models.CharField(max_length=50, unique=True) finalGrade = models.CharField(max_length=3) class Grade1OForm(ModelForm): student = forms.CharField(max_length=50, required=False) def __init__(self, *args, **kwargs): super(Grade1OForm,self).__init__(*args, **kwargs) instance = getattr(self, 'instance', None) if instance and instance.id: self.fields['student'].widget.attrs['readonly'] = True self.fields['student'].widget.attrs['disabled'] = 'disabled' def clean_student(self): instance = getattr(self,'instance',None) if instance: return instance.student else: return self.cleaned_data.get('student',None) class Meta: model=Grade1 views.py from django.forms.models import modelformset_factory def modifyAllGrades1(request): gradeFormSetFactory = modelformset_factory(Grade1, form=Grade1OForm, extra=0) studentQueryset = Grade1.objects.all() if request.method=='POST': myGradeFormSet = gradeFormSetFactory(request.POST, queryset=studentQueryset) if myGradeFormSet.is_valid(): myGradeFormSet.save() info = "successfully modified" else: myGradeFormSet = gradeFormSetFactory(queryset=studentQueryset) return render_to_response('grades/modifyAllGrades.html',locals()) template <p>{{ info }}</p> <form method="POST" action=""> <table> {{ myGradeFormSet.management_form }} {% for myform in myGradeFormSet.forms %} {# myform.as_table #} <tr> {% for field in myform %} <td> {{ field }} {{ field.errors }} </td> {% endfor %} </tr> {% endfor %} </table> <input type="submit" value="Submit"> </form>

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• Kohana 3: Auth module

  - by Thomas

  Hi, i'm trying to learn the Kohana's Auth module but login method always return false. Controller: <?php defined('SYSPATH') OR die('No Direct Script Access'); class Controller_Auth extends Controller { public function action_index() { if($_POST) { $this->login(); } $this->template = View::factory('login'); echo $this->template; } private function login() { $user = ORM::factory('user'); $data = array('username' => 'wilson', 'password' => '123'); if(!$user->login($data)) { echo 'FAILED!'; } } private function logout() { } } ?> Model: <?php defined('SYSPATH') or die('No direct script access.'); class Model_User extends Model_Auth_User { } ?>

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• working on lists in python

  - by owca

  I'm trying to make a small modification to django lfs project, that will allow me to deactivate products with no stocks. Unfortunatelly I'm just beginning to learn python, so I have big trouble with its syntax. That's what I'm trying to do. I'm using method 'has_variants' which returns true if product has any. Then I'm building a list from variants for this product. Next for every product in this list (I've called it 'set') I check it's stock and set bool variable 'inactive' to true if product has no stocks and to false if there are any. Finally if 'inactive' is false I'm setting self.active to 0. Code fails in line with: set[] = s How to correct it ? def deactivate(self): """If there are no stocks, deactivate the product. Used in last step of checkout. """ if self.has_variants(): for s in self.variants.filter(active=True): set[] = s for var in set: if var.get_stock_amount() == 0: inactive = True else: inactive = False else: if self.get_stock_amount() == 0: inactive = True if inactive: self.active = False return 0 error log : Traceback (most recent call last): File "manage.py", line 11, in <module> execute_manager(settings) File "/home/purplecow/rails/purpledev/site-packages/django/core/management/__i nit__.py", line 362, in execute_manager utility.execute() File "/home/purplecow/rails/purpledev/site-packages/django/core/management/__i nit__.py", line 303, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/home/purplecow/rails/purpledev/site-packages/django/core/management/bas e.py", line 195, in run_from_argv self.execute(*args, **options.__dict__) File "/home/purplecow/rails/purpledev/site-packages/django/core/management/bas e.py", line 213, in execute translation.activate('en-us') File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/_ _init__.py", line 73, in activate return real_activate(language) File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/_ _init__.py", line 43, in delayed_loader return g['real_%s' % caller](*args, **kwargs) File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/t rans_real.py", line 205, in activate _active[currentThread()] = translation(language) File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/t rans_real.py", line 194, in translation default_translation = _fetch(settings.LANGUAGE_CODE) File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/t rans_real.py", line 180, in _fetch app = import_module(appname) File "/home/purplecow/rails/purpledev/site-packages/django/utils/importlib.py" , line 35, in import_module __import__(name) File "/home/purplecow/rails/purpledev/lfs/caching/__init__.py", line 1, in <mo dule> from listeners import * File "/home/purplecow/rails/purpledev/lfs/caching/listeners.py", line 10, in < module> from lfs.cart.models import Cart File "/home/purplecow/rails/purpledev/lfs/cart/models.py", line 8, in <module> from lfs.catalog.models import Product File "/home/purplecow/rails/purpledev/lfs/catalog/__init__.py", line 1, in <mo dule> from listeners import * File "/home/purplecow/rails/purpledev/lfs/catalog/listeners.py", line 5, in <m odule> from lfs.catalog.models import PropertyGroup File "/home/purplecow/rails/purpledev/lfs/catalog/models.py", line 589 set[] = s ^ SyntaxError: invalid syntax

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• How to prevent HTTP 304 in Django test server

  - by Augusto Men

  I have a couple of projects in Django and alternate between one and another every now and then. All of them have a /media/ path, which is served by django.views.static.serve, and they all have a /media/css/base.css file. The problem is, whenever I run one project, the requests to base.css return an HTTP 304 (not modified), probably because the timestamp hasn't changed. But when I run the other project, the same 304 is returned, making the browser use the file cached by the previous project (and therefore, using the wrong stylesheet). Just for the record, here are the middleware classes: MIDDLEWARE_CLASSES = ( 'django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.middleware.transaction.TransactionMiddleware', ) I always use the default address http://localhost:8000. Is there another solution (other than using different ports - 8001, 8002, etc.)?

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• Django 1.2 object level permissions - third party solutions?

  - by mawimawi

  Since Django 1.2 final is almost out, I am curious if there are already projects that use the new object level permissions / row level permissions system. [django-authority][1] which is a possible solution for Django up to 1.1 has not been updated for a while, and does not (yet) use the new permissions system. It seems to me that Django-Authority is in a comatose state. Does someone know about upcoming or maybe even finished solutions? I'd appreciate any good links to active projects with at least some downloadable content very much. [1]: http://packages.python.org/django-authority/ django-authority

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• django urls.py regex isn't working

  - by Phil

  This is for Django 1.2.5 and Python 2.7 on Wamp Server running apache version 2.2.17. My problem is that the my URLConf in urls.py isn't redirecting, it's just throwing a 404 error. urls.py: from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: #from django.contrib import admin #admin.autodiscover() urlpatterns = patterns('', (r'^app/$', include('app.views.index')), # Uncomment the admin/doc line below to enable admin documentation: #(r'^admin/doc/', include('django.contrib.admindocs.urls')), # Uncomment the next line to enable the admin: #(r'^admin/', include(admin.site.urls)), ) views.py from django.http import HttpResponse def index(request): return HttpResponse("Hello World") I'm getting the following error: ImportError at /app/ No module named index I'm stumped as I'm only learning Django, can anybody see something wrong with my code? Here's my PythonPath: ['C:\Windows\system32\python27.zip', 'C:\Python27\Lib', 'C:\Python27\DLLs', 'C:\Python27\Lib\lib-tk', 'C:\wamp\bin\apache\Apache2.2.17', 'C:\wamp\bin\apache\apache2.2.17\bin', 'C:\Python27', 'C:\Python27\lib\site-packages', 'c:\wamp\www\seetwo']

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• Must See Conference Videos for Python/Django Developers

  - by Koobz

  There's lots of good conference videos online regarding Python and Django development. Instead of watching ST:TNG at the computer, I figure it'd more productive to hone my knowledge . Fire away with some of your most inspiring and educational Python, Django, or simply programming related talks. Provide an explanation of why you found the talk useful. Examples: James Bennet on Re-usable Apps - Got me to take a serious look at django apps. Put together a fairly robust site in two days afterwards with django-cms, django-photologue, django-contact-form. Good advice on when your app is crossing boundaries and why it's good to err on the site of 'make it a separate app.'

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• Trouble using South with Django and Heroku

  - by Dan

  I had an existing Django project that I've just added South to. I ran syncdb locally. I ran manage.py schemamigration app_name locally I ran manage.py migrate app_name --fake locally I commit and pushed to heroku master I ran syncdb on heroku I ran manage.py schemamigration app_name on heroku I ran manage.py migrate app_name on heroku I then receive this: $ heroku run python notecard/manage.py migrate notecards Running python notecard/manage.py migrate notecards attached to terminal... up, run.1 Running migrations for notecards: - Migrating forwards to 0005_initial. > notecards:0003_initial Traceback (most recent call last): File "notecard/manage.py", line 14, in <module> execute_manager(settings) File "/app/lib/python2.7/site-packages/django/core/management/__init__.py", line 438, in execute_manager utility.execute() File "/app/lib/python2.7/site-packages/django/core/management/__init__.py", line 379, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/app/lib/python2.7/site-packages/django/core/management/base.py", line 191, in run_from_argv self.execute(*args, **options.__dict__) File "/app/lib/python2.7/site-packages/django/core/management/base.py", line 220, in execute output = self.handle(*args, **options) File "/app/lib/python2.7/site-packages/south/management/commands/migrate.py", line 105, in handle ignore_ghosts = ignore_ghosts, File "/app/lib/python2.7/site-packages/south/migration/__init__.py", line 191, in migrate_app success = migrator.migrate_many(target, workplan, database) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 221, in migrate_many result = migrator.__class__.migrate_many(migrator, target, migrations, database) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 292, in migrate_many result = self.migrate(migration, database) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 125, in migrate result = self.run(migration) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 99, in run return self.run_migration(migration) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 81, in run_migration migration_function() File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 57, in <lambda> return (lambda: direction(orm)) File "/app/notecard/notecards/migrations/0003_initial.py", line 15, in forwards ('user', self.gf('django.db.models.fields.related.ForeignKey')(to=orm['auth.User'])), File "/app/lib/python2.7/site-packages/south/db/generic.py", line 226, in create_table ', '.join([col for col in columns if col]), File "/app/lib/python2.7/site-packages/south/db/generic.py", line 150, in execute cursor.execute(sql, params) File "/app/lib/python2.7/site-packages/django/db/backends/util.py", line 34, in execute return self.cursor.execute(sql, params) File "/app/lib/python2.7/site-packages/django/db/backends/postgresql_psycopg2/base.py", line 44, in execute return self.cursor.execute(query, args) django.db.utils.DatabaseError: relation "notecards_semester" already exists I have 3 models. Section, Semester, and Notecards. I've added one field to the Notecards model and I cannot get it added on Heroku. Thank you.

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• Making Django ignore string literals

  - by James

  UPDATE: It turns out this is a deeper question than I thought at first glance - the issue is that python is replacing the string literals before they ever get to django. I will do more investigating and update this if I find a solution. I'm using django to work with LaTeX templates for report generation, and am running into a lot of problems with the way Django replaces parts of strings. Specficially, I've run into two problems where I try to insert a variable containing latex code. The first was that it would replace HTML characters, such as the less than symbol, with their HTML codes, which are of course gibberish to a LaTeX interpreter. I fixed this by setting the context to never autoescape, like so: c = Context(inputs) c.autoescape = False However, I still have my second issue, which is that Django replaces string literals with their corresponding characers, so a double backslash becomes \, and \b becomes a backspace. How can I force Django to leave these characters in place, so inputs['variable'] = '{\bf this is code} \\' won't get mangled when I use {{variable}} to reference it in the django template?

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• Which Django 1.2.x multilingual application to use?

  - by mawimawi

  There are a couple of different applications for internationalized content in Django. As of now I only have used http://code.google.com/p/django-multilingual/ in my production environments, but I wonder if there are "better" solutions for my wishes. What my staff users need is the following: An object is being created by a staff user in any language (e.g. "de") This object should be displayed in the german version of the website. When a staff user translates the object into a different language (e.g. "fr"), then the page must be visible in the french version as well. If an object is not translated in the visitor's currently selected language (e.g. "en"), then calling the objects url shall raise a 404 Error (or even better a notice that the object is only available in the languages "de" and "fr", and the visitor might be able to select one of the languages) My staff users are working in the admin interface, so the multilingual application must support this as well. I don't really care whether the multilingual app uses a single table with many fields (like title_en, title_de, title_fr) or a foreign key to a related table (as it is implemented in django-multlingual). I only want it to have a good admin interface and no "default" language, because some content might be available just in "de", and some other just in "fr" and "en". And the most important issue of course is compatibility with Django 1.2.x. What are your experiences and preferred apps, and why?

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• What are the options for overriding Django's cascading delete behaviour?

  - by Tom

  Django models generally handle the ON DELETE CASCADE behaviour quite adequately (in a way that works on databases that don't support it natively.) However, I'm struggling to discover what is the best way to override this behaviour where it is not appropriate, in the following scenarios for example: ON DELETE RESTRICT (i.e. prevent deleting an object if it has child records) ON DELETE SET NULL (i.e. don't delete a child record, but set it's parent key to NULL instead to break the relationship) Update other related data when a record is deleted (e.g. deleting an uploaded image file) The following are the potential ways to achieve these that I am aware of: Override the model's delete() method. While this sort of works, it is sidestepped when the records are deleted via a QuerySet. Also, every model's delete() must be overridden to make sure Django's code is never called and super() can't be called as it may use a QuerySet to delete child objects. Use signals. This seems to be ideal as they are called when directly deleting the model or deleting via a QuerySet. However, there is no possibility to prevent a child object from being deleted so it is not usable to implement ON CASCADE RESTRICT or SET NULL. Use a database engine that handles this properly (what does Django do in this case?) Wait until Django supports it (and live with bugs until then...) It seems like the first option is the only viable one, but it's ugly, throws the baby out with the bath water, and risks missing something when a new model/relation is added. Am I missing something? Any recommendations?

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• why does django-registration use an "activation window" for activating accounts?

  - by bharal

  i'm using django-registration, which is a django lib that helps with users registering on a django-built website. All well and dandy, except that it insists i have an "activation email" associated with all new users. It defaults to a 7 day window, after which, if someone signed up (and we then sent an email to confirm their email address) but didn't click on the link in the sent email within the 7 days, then they cannot sign up. Instead, they need to do the whole process all over again. I'm sure this is a concept that exists generally in web design, because why would django-registration make its own arbitrary signup process up? Anyway, the question is why? What do i gain by having the peace of mind knowing that all the users of my site are the kind of go-getters that click on registration emails with 7 days of receiving them? Why should i sleep easier knowing that my database isn't filled with users who, for whatever reason, clicked through to sign up but didn't actually want to sign up? cheers!

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• how to specify open id realm in openid4java 0.9.5

  - by Salvin Francis

  my url @ development : http://192.168.0.1:8888/com.company.MyEntryPoint/MyEntrypoint.html my url @ live env : http://www.example.com/com.company.MyEntryPoint/MyEntrypoint.html I need users to authenticate using open id, this is how i want my realm to be: *.company.MyEntryPoint I wrote a simple code to specify realm: AuthRequest authReq = manager.authenticate( discovered, returnToUrl, "*.company.MyEntryPoint" ); it does not work. Exception: org.openid4java.message.MessageException: 0x301: Realm verification failed (2) for: *.company.MyEntryPoint at org.openid4java.message.AuthRequest.validate(AuthRequest.java:354) at org.openid4java.message.AuthRequest.createAuthRequest(AuthRequest.java:101) at org.openid4java.consumer.ConsumerManager.authenticate(ConsumerManager.java:1073) Of all the combinations I tried, curiously, the following worked: AuthRequest authReq = manager.authenticate( discovered, returnToUrl, "http://localhost:8888/com.capgent.MyEntryPoint" ); This does not solves my issue but rather complicates it :) According to google and open id spec it should have worked complete code snippet: List discoveries = manager.discover(clientUrl); DiscoveryInformation discovered = manager.associate(discoveries); AuthRequest authReq = manager.authenticate(discovered, returnToUrl,"*.company.MyEntryPoint"); FetchRequest fetch = FetchRequest.createFetchRequest(); fetch.addAttribute("email", "http://schema.openid.net/contact/email", true); fetch.addAttribute("country", "http://axschema.org/contact/country/home", true); fetch.addAttribute("firstname", "http://axschema.org/namePerson/first", true); fetch.addAttribute("lastname", "http://axschema.org/namePerson/last", true); fetch.addAttribute("language", "http://axschema.org/pref/language", true); authReq.addExtension(fetch); String returnStr; if (!discovered.isVersion2()) { returnStr = authReq.getDestinationUrl(true); } else { returnStr = authReq.getDestinationUrl(false); } What am I doing wrong over here ?

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• How to generate the right password format for Apache2 authentication in use with DBD and MySQL 5.1?

  - by Walkman

  I want to authenticate users for a folder from a MySQL 5.1 database with AuthType Basic. The passwords are stored in plain text (they are not really passwords, so doesn't matter). The password format for apache however only allows for SHA1, MD5 on Linux systems as described here. How could I generate the right format with an SQL query ? Seems like apache format is a binary format with a lenght of 20, but the mysql SHA1 function return 40 long. My SQL query is something like this: SELECT CONCAT('{SHA}', BASE64_ENCODE(SHA1(access_key))) FROM user_access_keys INNER JOIN users ON user_access_keys.user_id = users.id WHERE name = %s where base64_encode is a stored function (Mysql 5.1 doesn't have TO_BASE64 yet). This query returns a 61 byte BLOB which is not the same format that apache uses. How could I generate the same format ? You can suggest other method for this too. The point is that I want to authenticate users from a MySQL5.1 database using plain text as password.

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• Python-MySQLdb problem: wrong ELF class: ELFCLASS32

  - by jsalonen

  As part of trying out django CMS (http://www.django-cms.org/), I'm struggling with getting Python-MySQLdb to work (http://pypi.python.org/pypi/MySQL-python/). I have installed Django CMS and all of its dependencies (Python 2.5, Django, django-south, MySQL server) I'm trying out the example code within Django CMS code with MySQL as chosen database type When I execute python manage.py syncdb, the following error occurs: django.core.exceptions.ImproperlyConfigured: Error loading MySQLdb module: /root/.python-eggs/MySQL_python-1.2.3c1-py2.5-linux-i686.egg-tmp/_mysql.so: wrong ELF class: ELFCLASS32 I have been able to trace the problem specifically to python-mySQLdb (as also visible in the stack trace). Other than that, I am completely puzzled. I don't have a clue what ELFCLASS32 means, or what ELF class is anyway. I suspect that this error could have something to do with the fact that I am running 64-bit version of Debian 5 (on a VPS). Any good ideas how to troubleshoot?

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• django app using amazon aws s3 storage in stead of DB?

  - by farble1670

  new to python here so bear with me ... i'm looking at django for a rapid prototype to a photo sharing app with an amazon aws s3 storage back end. however, as far as i can tell, django is tailored toward the typical database MVC type of pattern. is there a way to for example provide a custom django model implementation that talks to s3 in stead of a DB? a custom DB engine? would either of these be practical, or am i looking in the wrong direction? thanks.

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• Storing hierarchical (parent/child) data in Python/Django: MPTT alternative?

  - by Parand

  I'm looking for a good way to store and use hierarchical (parent/child) data in Django. I've been using django-mptt, but it seems entirely incompatible with my brain - I end up with non-obvious bugs in non-obvious places, mostly when moving things around in the tree: I end up with inconsistent state, where a node and its parent will disagree on their relationship. My needs are simple: Given a node: find its root find its ancestors find its descendants With a tree: easily move nodes (ie. change parent) My trees will be smallish (at most 10k nodes over 20 levels, generally much much smaller, say 10 nodes with 1 or 2 levels). I have to think there has to be an easier way to do trees in python/django. Are there other approaches that do a better job of maintaining consistency?

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• Right way to have a thread in parallel to django project on wsgi.

  - by Enrico Carlesso

  Hi guys. I'm writing a django project, and I need to have a parallel thread which performs certain tasks. The project will be deployed in Apache2.2 with mod_wsgi. Actually my implementation consists on a thread with a while True - Sleep which is called from my django.wsgi file. Is this implementation correct? Two problems raises: does django.wsgi get called only once? Will I have just that instance of the thread running? And second, I need to "manually" visit at least a page to have the Thread run. Is there a workaround? Does anyone has some hints on better solutions? Thanks in advance.

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• What's the best and most recent social authentication plugin for Django?

  - by Fedor

  There are plenty of them out there but a lot of them are old - can anyone recommend a plugin which they recently implemented? The only thing I really care about is gmail/yahoo, facebook and twitter are optional.

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• Django admin panel doesn't work after modify default user model.

  - by damienix

  I was trying to extend user profile. I founded a few solutions, but the most recommended was to create new user class containing foreign key to original django.contrib.auth.models.User class. I did it with this so i have in models.py: class UserProfile(models.Model): user = models.ForeignKey(User, unique=True) website_url = models.URLField(verify_exists=False) and in my admin.py from django.contrib import admin from someapp.models import * from django.contrib.auth.admin import UserAdmin # Define an inline admin descriptor for UserProfile model class UserProfileInline(admin.TabularInline): model = UserProfile fk_name = 'user' max_num = 1 # Define a new UserAdmin class class MyUserAdmin(UserAdmin): inlines = [UserProfileInline, ] # Re-register UserAdmin admin.site.unregister(User) admin.site.register(User, MyUserAdmin) And now when I'm trying to create/edit user in admin panel i have an error: "Unknown column 'content_userprofile.id' in 'field list'" where content is my appname. I was trying to add line AUTH_PROFILE_MODULE = 'content.UserProfile' to my settings.py but with no effect. How to tell panel admin to know how to correctly display fields in user form?

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• Django - The included urlconf doesn't have any patterns in it

  - by unsorted

  My website, which was working before, suddenly started breaking with the error "ImproperlyConfigured at / The included urlconf resume.urls doesn't have any patterns in it" The project base is called resume. In settings.py I have set ROOT_URLCONF = 'resume.urls' Here's my resume.urls, which sits in the project root directory. from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # Example: # (r'^resume/', include('resume.foo.urls')), # Uncomment the admin/doc line below and add 'django.contrib.admindocs' # to INSTALLED_APPS to enable admin documentation: (r'^admin/doc/', include('django.contrib.admindocs.urls')), # Uncomment the next line to enable the admin: (r'^admin/', include(admin.site.urls)), (r'^accounts/login/$', 'django.contrib.auth.views.login'), #(r'^employer/', include(students.urls)), (r'^ajax/', include('urls.ajax')), (r'^student/', include('students.urls')), (r'^club/(?P<object_id>\d+)/$', 'resume.students.views.club_detail'), (r'^company/(?P<object_id>\d+)/$', 'resume.students.views.company_detail'), (r'^program/(?P<object_id>\d+)/$', 'resume.students.views.program_detail'), (r'^course/(?P<object_id>\d+)/$', 'resume.students.views.course_detail'), (r'^career/(?P<object_id>\d+)/$', 'resume.students.views.career_detail'), (r'^site_media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': 'C:/code/django/resume/media'}), ) Anyone know what's wrong? This is driving me crazy. Thanks,

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• Settings module not found deploying django on a shared server

  - by mcanes

  I'm trying to deploy my django project on a shared hosting as describe here I have my project on /home/user/www/testa I'm using this script #!/usr/bin/python import sys, os sys.path.append("/home/user/bin/python") sys.path.append('/home/user/www/testa') os.chdir("/home/user/www/testa") os.environ['DJANGO_SETTINGS_MODULE'] = "settings.py" from django.core.servers.fastcgi import runfastcgi runfastcgi(method="threaded", daemonize="false") And here's the error I get when trying to run it from shell: WSGIServer: missing FastCGI param REQUEST_METHOD required by WSGI! WSGIServer: missing FastCGI param SERVER_NAME required by WSGI! WSGIServer: missing FastCGI param SERVER_PORT required by WSGI! WSGIServer: missing FastCGI param SERVER_PROTOCOL required by WSGI! Traceback (most recent call last): File "build/bdist.linux-i686/egg/flup/server/fcgi_base.py", line 558, in run File "build/bdist.linux-i686/egg/flup/server/fcgi_base.py", line 1118, in handler File "/home/user/lib/python2.4/site-packages/django/core/handlers/wsgi.py", line 230, in __call__ self.load_middleware() File "/home/user/lib/python2.4/site-packages/django/core/handlers/base.py", line 33, in load_middleware for middleware_path in settings.MIDDLEWARE_CLASSES: File "/home/user/lib/python2.4/site-packages/django/utils/functional.py", line 269, in __getattr__ self._setup() File "/home/usr/lib/python2.4/site-packages/django/conf/__init__.py", line 40, in _setup self._wrapped = Settings(settings_module) File "/home/user/lib/python2.4/site-packages/django/conf/__init__.py", line 75, in __init__ raise ImportError, "Could not import settings '%s' (Is it on sys.path? Does it have syntax errors?): %s" % (self.SETTINGS_MODULE, e) ImportError: Could not import settings 'settings.py' (Is it on sys.path? Does it have syntax errors?): No module named settings.py Content-Type: text/html Unhandled Exception Unhandled Exception An unhandled exception was thrown by the application. What am I doing wrong? Running the script from the browser just gives me an internal server error.

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• Django Image Upload: IOErrno2 Could not find path -- and yet it's saving the image there anyway?

  - by Rob

  I have an issue where the local version of django is handling image upload as expected but my server is not. Note: I am using a Django Container on MediaTemple.net (grid server) Here is my code. def view_settings(request): <snip> if request.POST: success_msgs = () mForm = MainProfileForm(request.POST, request.FILES, instance = mProfile) pForm = ChangePasswordForm(request.POST) eForm = ChangeEmailForm(request.POST) if mForm.is_valid(): m = mForm.save(commit = False) if mForm.cleaned_data['avatar']: m.avatar = upload_photo(request.FILES['avatar'], settings.AVATAR_SAVE_LOCATION) m.save() success_msgs += ('profile pictured updated',) <snip> def upload_photo(data,saveLocation): savePath = os.path.join(settings.MEDIA_ROOT, saveLocation, data.name) destination = open(savePath, 'wb+') for chunk in data.chunks(): destination.write(chunk) destination.close() return os.path.join(saveLocation, data.name) Here's where it gets whacky and I was hoping someone could shed a light on this error, because either a) it's the wrong error code, or b) something is happening with the file before it's completely handled. To recap, the file was actually uploaded to the server in the intended directory - and yet this err msg continues to persist. IOError at /user/settings [Errno 2] No such file or directory: u'/home/user66666/domains/example.com/html/media/images/avatars/DSC03852.JPG' Environment: Request Method: POST Request URL: http://111.111.111.111:2011/user/settings Django Version: 1.0.2 final Python Version: 2.4.4 Installed Applications: ['django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'ctrlme', 'usertools', 'easy_thumbnails'] Installed Middleware: ('django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware') Traceback: File "/home/user6666/containers/django/leonidas/usertools/views.py" in view_settings m.avatar = upload_photo(request.FILES['avatar'], settings.AVATAR_SAVE_LOCATION) File "/home/user666666/containers/django/leonidas/usertools/functions.py" in upload_photo destination = open(savePath, 'wb+')

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