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  • JPA @OneToMany and composite PK

    - by Fleuri F
    Good Morning, I am working on project using JPA. I need to use a @OneToMany mapping on a class that has three primary keys. You can find the errors and the classes after this. If anyone has an idea! Thanks in advance! FF javax.persistence.PersistenceException: No Persistence provider for EntityManager named JTA_pacePersistence: Provider named oracle.toplink.essentials.PersistenceProvider threw unexpected exception at create EntityManagerFactory: javax.persistence.PersistenceException javax.persistence.PersistenceException: Exception [TOPLINK-28018] (Oracle TopLink Essentials - 2.0.1 (Build b09d-fcs (12/06/2007))): oracle.toplink.essentials.exceptions.EntityManagerSetupException Exception Description: predeploy for PersistenceUnit [JTA_pacePersistence] failed. Internal Exception: Exception [TOPLINK-7220] (Oracle TopLink Essentials - 2.0.1 (Build b09d-fcs (12/06/2007))): oracle.toplink.essentials.exceptions.ValidationException Exception Description: The @JoinColumns on the annotated element [private java.util.Set isd.pacepersistence.common.Action.permissions] from the entity class [class isd.pacepersistence.common.Action] is incomplete. When the source entity class uses a composite primary key, a @JoinColumn must be specified for each join column using the @JoinColumns. Both the name and the referenceColumnName elements must be specified in each such @JoinColumn. at oracle.toplink.essentials.internal.ejb.cmp3.EntityManagerSetupImpl.predeploy(EntityManagerSetupImpl.java:643) at oracle.toplink.essentials.ejb.cmp3.EntityManagerFactoryProvider.createEntityManagerFactory(EntityManagerFactoryProvider.java:196) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:110) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:83) at isd.pacepersistence.common.DataMapper.(Unknown Source) at isd.pacepersistence.server.MainServlet.getDebugCase(Unknown Source) at isd.pacepersistence.server.MainServlet.doGet(Unknown Source) at javax.servlet.http.HttpServlet.service(HttpServlet.java:718) at javax.servlet.http.HttpServlet.service(HttpServlet.java:831) at org.apache.catalina.core.ApplicationFilterChain.servletService(ApplicationFilterChain.java:411) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:290) at org.apache.catalina.core.StandardContextValve.invokeInternal(StandardContextValve.java:271) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:202) There is the source code of my classes : Action : @Entity @Table(name="action") public class Action { @Id @GeneratedValue(strategy=GenerationType.IDENTITY) private int num; @ManyToOne(cascade= { CascadeType.PERSIST, CascadeType.MERGE, CascadeType.REFRESH }) @JoinColumn(name="domain_num") private Domain domain; private String name; private String description; @OneToMany @JoinTable(name="permission", joinColumns= { @JoinColumn(name="action_num", referencedColumnName="action_num", nullable=false, updatable=false) }, inverseJoinColumns= { @JoinColumn(name="num") }) private Set<Permission> permissions; public Action() { } Permission : @SuppressWarnings("serial") @Entity @Table(name="permission") public class Permission implements Serializable { @EmbeddedId private PermissionPK primaryKey; @ManyToOne @JoinColumn(name="action_num", insertable=false, updatable=false) private Action action; @ManyToOne @JoinColumn(name="entity_num", insertable=false, updatable=false) private isd.pacepersistence.common.Entity entity; @ManyToOne @JoinColumn(name="class_num", insertable=false, updatable=false) private Clazz clazz; private String kondition; public Permission() { } PermissionPK : @SuppressWarnings("serial") @Entity @Table(name="permission") public class Permission implements Serializable { @EmbeddedId private PermissionPK primaryKey; @ManyToOne @JoinColumn(name="action_num", insertable=false, updatable=false) private Action action; @ManyToOne @JoinColumn(name="entity_num", insertable=false, updatable=false) private isd.pacepersistence.common.Entity entity; @ManyToOne @JoinColumn(name="class_num", insertable=false, updatable=false) private Clazz clazz; private String kondition; public Permission() { }

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  • JPA @ManyToOne and composite PK

    - by Fleuri F
    Good Morning, I am working on project using JPA. I need to use a @ManyToOne mapping on a class that has three primary keys. You can find the errors and the classes after this. If anyone has an idea! Thanks in advance! FF javax.persistence.PersistenceException: No Persistence provider for EntityManager named JTA_pacePersistence: Provider named oracle.toplink.essentials.PersistenceProvider threw unexpected exception at create EntityManagerFactory: javax.persistence.PersistenceException javax.persistence.PersistenceException: Exception [TOPLINK-28018] (Oracle TopLink Essentials - 2.0.1 (Build b09d-fcs (12/06/2007))): oracle.toplink.essentials.exceptions.EntityManagerSetupException Exception Description: predeploy for PersistenceUnit [JTA_pacePersistence] failed. Internal Exception: Exception [TOPLINK-7220] (Oracle TopLink Essentials - 2.0.1 (Build b09d-fcs (12/06/2007))): oracle.toplink.essentials.exceptions.ValidationException Exception Description: The @JoinColumns on the annotated element [private java.util.Set isd.pacepersistence.common.Action.permissions] from the entity class [class isd.pacepersistence.common.Action] is incomplete. When the source entity class uses a composite primary key, a @JoinColumn must be specified for each join column using the @JoinColumns. Both the name and the referenceColumnName elements must be specified in each such @JoinColumn. at oracle.toplink.essentials.internal.ejb.cmp3.EntityManagerSetupImpl.predeploy(EntityManagerSetupImpl.java:643) at oracle.toplink.essentials.ejb.cmp3.EntityManagerFactoryProvider.createEntityManagerFactory(EntityManagerFactoryProvider.java:196) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:110) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:83) at isd.pacepersistence.common.DataMapper.(Unknown Source) at isd.pacepersistence.server.MainServlet.getDebugCase(Unknown Source) at isd.pacepersistence.server.MainServlet.doGet(Unknown Source) at javax.servlet.http.HttpServlet.service(HttpServlet.java:718) at javax.servlet.http.HttpServlet.service(HttpServlet.java:831) at org.apache.catalina.core.ApplicationFilterChain.servletService(ApplicationFilterChain.java:411) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:290) at org.apache.catalina.core.StandardContextValve.invokeInternal(StandardContextValve.java:271) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:202) There is the source code of my classes : Action : @Entity @Table(name="action") public class Action { @Id @GeneratedValue(strategy=GenerationType.IDENTITY) private int num; @ManyToOne(cascade= { CascadeType.PERSIST, CascadeType.MERGE, CascadeType.REFRESH }) @JoinColumn(name="domain_num") private Domain domain; private String name; private String description; @OneToMany @JoinTable(name="permission", joinColumns= { @JoinColumn(name="action_num", referencedColumnName="action_num", nullable=false, updatable=false) }, inverseJoinColumns= { @JoinColumn(name="num") }) private Set<Permission> permissions; public Action() { } Permission : @SuppressWarnings("serial") @Entity @Table(name="permission") public class Permission implements Serializable { @EmbeddedId private PermissionPK primaryKey; @ManyToOne @JoinColumn(name="action_num", insertable=false, updatable=false) private Action action; @ManyToOne @JoinColumn(name="entity_num", insertable=false, updatable=false) private isd.pacepersistence.common.Entity entity; @ManyToOne @JoinColumn(name="class_num", insertable=false, updatable=false) private Clazz clazz; private String kondition; public Permission() { } PermissionPK : @SuppressWarnings("serial") @Entity @Table(name="permission") public class Permission implements Serializable { @EmbeddedId private PermissionPK primaryKey; @ManyToOne @JoinColumn(name="action_num", insertable=false, updatable=false) private Action action; @ManyToOne @JoinColumn(name="entity_num", insertable=false, updatable=false) private isd.pacepersistence.common.Entity entity; @ManyToOne @JoinColumn(name="class_num", insertable=false, updatable=false) private Clazz clazz; private String kondition; public Permission() { }

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  • Asp.net mvc, view with multiple updatable parts - how?

    - by DerDres
    I have started doing asp.net mvc programming and like it more everyday. Most of the examples I have seen use separate views for viewing and editing details of a specific entity. E.g. - table of music albums linking to separate 'detail' and 'update' views [Action] | Title | Artist detail, update | Uuuh Baby | Barry White detail, update | Mr Mojo | Barry White With mvc how can I achieve a design where the R and the U (CRUD) are represented in a single view, and furthermore where the user can edit separate parts of the view, thus limiting the amount of data the user can edit before saving? Example mockup - editing album detials: I have achieved such a design with ajax calls, but Im curious how to do this without ajax. Parts of my own take on this can be seen below. I use a flag (enum EditCode) indicating which part of the view, if any, that has to render a form. Is such a design in accordance with the framework, could it be done more elegantly? AlbumController public class AlbumController : Controller { public ActionResult Index() { var albumDetails = from ManageVM in state.AlbumState.ToList() select ManageVM.Value.Detail; return View(albumDetails); } public ActionResult Manage(int albumId, EditCode editCode) { (state.AlbumState[albumId] as ManageVM).EditCode = (EditCode)editCode; ViewData["albumId"] = albumId; return View(state.AlbumState[albumId]); } [HttpGet] public ActionResult Edit(int albumId, EditCode editCode) { return RedirectToAction("Manage", new { albumId = albumId, editCode = editCode }); } // edit album details [HttpPost] public ActionResult EditDetail(int albumId, Detail details) { (state.AlbumState[albumId] as ManageVM).Detail = details; return RedirectToAction("Manage", new { albumId = albumId, editCode = EditCode.NoEdit });// zero being standard } // edit album thought [HttpPost] public ActionResult EditThoughts(int albumId, List<Thought> thoughts) { (state.AlbumState[albumId] as ManageVM).Thoughts = thoughts; return RedirectToAction("Manage", new { albumId = albumId, editCode = EditCode.NoEdit });// zero being standard } Flag - EditCode public enum EditCode { NoEdit, Details, Genres, Thoughts } Mangae view <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<MvcApplication1.Controllers.ManageVM>" %> <asp:Content ID="Content1" ContentPlaceHolderID="TitleContent" runat="server"> Manage </asp:Content> <asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server"> <h2>Manage</h2> <% if(Model.EditCode == MvcApplication1.Controllers.EditCode.Details) {%> <% Html.RenderPartial("_EditDetails", Model.Detail); %> <% }else{%> <% Html.RenderPartial("_ShowDetails", Model.Detail); %> <% } %> <hr /> <% if(Model.EditCode == MvcApplication1.Controllers.EditCode.Thoughts) {%> <% Html.RenderPartial("_EditThoughts", Model.Thoughts); %> <% }else{%> <% Html.RenderPartial("_ShowThoughts", Model.Thoughts); %> <% } %>

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  • i have made a from and want to connect it to a oracle 10g data base using php.can you please assume

    - by nachiket-panse
    http://www.freecsstemplates.org Released for free under a Creative Commons Attribution 2.5 License -- Sitename.com by Free Css Templates MANAGEMEINT INFORMATION SYSTEM   <p class="style2">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;REGISTRY ENTRY FORM </p> <form id="form2" method="post" action=""> <p align="center">&nbsp;</p> <p align="center"><span class="style3">JOB DESCRIPTION :</span>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <textarea name="textarea"></textarea> </p> <p align="center"><span class="style3">QUANTITY :</span>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <input type="text" name="textfield5" /> </p> <p align="center">&nbsp;<span class="style3">CONTACT PERSON </span>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <input type="text" name="textfield3" /> </p> <p align="center">&nbsp;</p> <p align="center"><span class="style3">DIVISION CODE: <textarea name="textarea3"></textarea> </span></p> <p align="center"><span class="style3">ACCEPTANCE DATE </span>: <input type="text" name="textfield4" /> </p> <p align="center"><span class="style3">REFERENCE NUMBER :</span> <input type="text" name="textfield2" /> </p> <p align="center"><span class="style3">CLASSIFICATION :</span>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <input type="text" name="textfield" /></p> <p align="center">&nbsp;</p> <p align="center"><span class="style3">CUMULATIVE COST: </span> <select name="select"> </select> </p> <p align="center"><span class="style3">PLANNING ENGR: </span> <textarea name="textarea2"></textarea> </p> <p align="center"><span class="style3">PLANNING: </span> <input type="text" name="textfield6" /> </p> <p align="center"> <span class="style3">FILL THE COMPLETION DATE: </span> <input type="text" name="textfield7" /> </p> <p align="center"><span class="style3">REMARKS: </span> <input type="text" name="textfield8" /> </p> <p align="center">&nbsp;</p> <p align="center"> <input type="submit" name="SAVE" value="SAVE" /> <input type="submit" name="Submit2" value="LIST" /> <input type="submit" name="Submit" value="ADD" /> <input type="submit" name="Submit3" value="CANCEL" /> <input type="submit" name="BACK" value="BACK" /></p> <p align="center">&nbsp;</p> <p align="center">&nbsp;</p> <p align="center">&nbsp;</p> <p align="center">&nbsp;</p> <p align="center">&nbsp;</p> </form> <p align="center" class="style2">&nbsp;</p>

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  • is it possible to lock oracle 10g database table with ADO.NET?

    - by matti
    I have a table that contains a maximum value that needs to be get and set by multiple programs. How can I lock the table for a while when old value is got and new is updated in C#? In other words: string sql = "lock table MaxValueTable in exclusive mode"; using (DbCommand cmd = cnctn.CreateCommand()) { cmd.CommandText = sql; // execute command somehow!! } maxValue = GetMaxValue(); SetMaxValue(maxValue + X); sql = "lock table MaxValueTable in share mode"; using (DbCommand cmd = cnctn.CreateCommand()) { cmd.CommandText = sql; // execute command somehow!! }

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  • Is there equivalences between Microsoft and Oracle/Sun technologies?

    - by Junior Mayhé
    Hello is it possible to say what are the Microsoft equivalents technologies compared to Sun? For example: Microsoft | Sun --------------------------------------------------------------- Visual Studio | Eclipse? IIS | Apache? ASP.NET | JSP, JSF ? SQL Server | Java DB ? ADO.NET Entity Data Model | ??? ASP.NET MVC | ??? Windows Presentation Foundation | Java FX? Windows Communication Foundation | ??? ASP.NET AJAX Toolkit | ??? Reporting Services/RDLC | ??? LINQ to SQL Classes | ??? Windows Forms | ???

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  • How to test if a string is inside a list of predinfined list of string in oracle pl/sql

    - by drupalspring
    I define a list a string which contains different country codes ( for example , USA ,CHINA ,HK ,JPN) How can I check that if a input variable equal to one of the country of the country list in pl/sql . I use the following code to test it but fail, how can I revise it? declare country_list CONSTANT VARCHAR2(200) := USA,CHINA,HK,JPN; input VARCHAR2(200); begin input := 'JPN'; IF input IN (country_list) DBMS_OUTPUT.PUT_LINE('It is Inside'); else DBMS_OUTPUT.PUT_LINE('It is not Inside'); END IF; end;

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  • How to convert rows returned by a query into columns in oracle?

    - by Piyush Lohana
    I have to display the results of the below query as columns. select to_char(sysdate + 1 - rownum,'MON-YYYY') as d from all_objects where trunc(sysdate + 1 - rownum,'MM') = trunc(to_date(:from_date,'MON-YYYY'),'MM') minus select to_char(sysdate + 1 - rownum,'MON-YYYY') as d from all_objects where trunc(sysdate + 1 - rownum,'MM') trunc(to_date(':to_date','MON-YYYY'),'MM') Please help me in figuring that out.

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  • ORACLE:- 'SELECT ORDER BY ASC' but 'USA' always first.

    - by Robert
    I have to write a drop down query for countries. But USA should always be first. The rest of the countries are in alphabetical order I tried the following query SELECT countries_id ,countries_name FROM get_countries WHERE countries_id = 138 UNION SELECT countries_id ,countries_name FROM get_countries WHERE countries_id != 138 ORDER BY 2 ASC

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  • PHP: How do I find (Oracle) parameters in a SQL query?

    - by Bartb
    Suppose you have a string: "SELECT * FROM TABLE WHERE column1 = :var1 AND column2 = :var2" Now, how do I get an array with all the variables like so: Array ( [0] => :var1 [1] => :var2 ) I've tried it with PHP's preg_match_all, but I struggle with the regex. $varcount = preg_match_all("/ :.+ /", $sql, $out);

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  • ORACLE:- 'SELECT ODER BY ASC' but 'USA' always first.

    - by Robert
    I have to write a drop down query for countries. But USA hould always be first. The rest of the countries are in alphabetical order I tried the following query SELECT countries_id ,countries_name FROM get_countries WHERE countries_id = 138 UNION SELECT countries_id ,countries_name FROM get_countries WHERE countries_id != 138 ORDER BY 2 ASC

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  • SUSE 12.1 Apache startup after oci8 installation

    - by DKSan
    I have got a virtual server running opensuse 11.4 with apache, php, oracle instantclient, and oci installed through pecl. The steps it took for me to have it up and running on 11.4 were: # Install instantclient rpm -Uvh oracle-instantclient11.2-basic-11.2.0.2.0.x86_64.rpm rpm -Uvh oracle-instantclient11.2-devel-11.2.0.2.0.x86_64.rpm # Install OCI8 through pecl pecl install oci8 # add oci8 to modules vi /etc/php5/conf.d/oci8.ini extension=oci8.so # add LD_LIBRARY_PATH to apache vi /etc/sysconfig/apache2 # add to bottom of script export LD_LIBRARY_PATH="/usr/lib/oracle/11.2/client64/lib" # restart Apache /etc/init.d/apache2 restart Celebrating the same procedure on a fresh installation of OpenSUSE 12.1 results in apache throwing the following message at startup: PHP Warning: PHP Startup: Unable to load dynamic library '/usr/lib64/php5/extensions/oci8.so' - libnnz11.so: cannot open shared object file: No such file or directory in Unknown on line 0 I can't get any explanation, why it is working for 11.4 and in 12.1 it stops working. Can someone please point me in the right direction..

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  • GConf error and gnome does not load properly in RHEL 5.3

    - by Tim
    Hello, I am using Red Hat Enterprise Linux 5.3 . I created a user oracle on the system, using the following command useradd -g oinstall -G dba,oper -d /home/oracle oracle Now, when i try to login as the user oracle, GNOME does not load properly and i get popup box error message like the following GConf error:Failed to contact configuration server;some possible causes are that you need to enable TCP/IP for ORBit,or your have NFS locks due to a system crash.(Details-/:IOR file'/tmp/gcofd-cheetahman/tock/ior' not opened successfully,no gconfd located:Permission denied 2: IOR file /tmp/gconfd-cheetahman/lock/ior not opened succesfully no gconfd located: Permission denied) Any way to fix this ? Thank You

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  • what is uninstall procedure for software installed via "make install" on CentOS 6.2

    - by gkdsp
    I installed OCILIB on my CentOS 6.2 server some time ago, and now I want to install a newer version. The vendor requires an uninstall, but doesn't provide instructions. I'm guessing that's because it's trivial for people with a Linux background. http://orclib.sourceforge.net/doc/html/group_g_install.html If I installed this software using: step 1: # ./configure --with-oracle-headers-path=/usr/include/oracle/11.2/client64 --with-oracle-lib-path=/usr/lib/oracle/11.2/client64/lib step 2: # make step 3: # su root step 4: # make install step 5: # gcc -g -DOCI_IMPORT_LINKAGE -DOCI_CHARSET_ANSI -L/usr/lib/oracle/11.2/client64/lib -lclntsh -L/usr/local/lib -locilib conn.c -o conn How would I go about uninstalling this? I tried following this http://www.cyberciti.biz/faq/delete-uninstall-software-linux-commands/ but nothing was found on my disk using rpm -qa *oci* or yum list *oci*. Maybe since it wasn't installed with yum or rpm then I shouldn't expect either of these to find it. Are there generic instructions for uninstalling software on Linux that I could use, or do the instructions really depend on the specific software? Any help much appreciated.

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  • Virtual Machine with Bridged Adapter to Centos not accepting ssh from host machine [migrated]

    - by javadba
    I have a bridged connection on VirtualBox from os/x 10.8.5 host to Centos 5.8 client. But I suspect this is more of a general issue than specific to the host and precise version of linux. Shown below are the networking info from the VirtualBox and from within the guest sshd is running on port 22: [root@oracle-linux ~]# ps -ef | grep sshd | grep -v grep root 3103 1 0 20:22 ? 00:00:00 /usr/sbin/sshd root 14994 3103 0 21:23 ? 00:00:00 sshd: root@pts/1 Port 22 listening: [root@oracle-linux ~]# netstat -an | grep 22 | grep tcp | grep LIST tcp 0 0 0.0.0.0:22 0.0.0.0:* LISTEN tcp 0 0 127.0.0.1:2207 0.0.0.0:* LISTEN tcp 0 0 127.0.0.1:2208 0.0.0.0:* LISTEN tcp 0 0 :::22 :::* LISTEN Here are ip addresses, still on the guest os: [root@oracle-linux ~]# ip addr 1: lo: <LOOPBACK,UP,LOWER_UP> mtu 16436 qdisc noqueue link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00 inet 127.0.0.1/8 scope host lo inet6 ::1/128 scope host valid_lft forever preferred_lft forever 2: eth0: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc pfifo_fast qlen 1000 link/ether 08:00:27:b9:e5:79 brd ff:ff:ff:ff:ff:ff inet 10.0.15.100/24 brd 10.0.15.255 scope global eth0 inet6 fe80::a00:27ff:feb9:e579/64 scope link valid_lft forever preferred_lft forever 3: eth1: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc pfifo_fast qlen 1000 link/ether 08:00:27:b4:86:8a brd ff:ff:ff:ff:ff:ff inet 10.0.3.15/24 brd 10.0.3.255 scope global eth1 inet6 fe80::a00:27ff:feb4:868a/64 scope link valid_lft forever preferred_lft forever [root@oracle-linux ~]# I can ssh to the guest from the guest: root@oracle-linux ~]# ssh 10.0.3.15 The authenticity of host '10.0.3.15 (10.0.3.15)' can't be established. RSA key fingerprint is ef:08:19:72:95:4d:e5:28:af:f3:6f:54:07:84:ba:04. Are you sure you want to continue connecting (yes/no)? yes Warning: Permanently added '10.0.3.15' (RSA) to the list of known hosts. [email protected]'s password: Last login: Mon Oct 21 21:24:12 2013 from 10.0.15.100 But can NOT ssh from the host to the guest: 18:27:04/shared:11 $ssh [email protected] ssh: connect to host 10.0.15.100 port 22: Operation timed out lost connection Here is bridged connection infO; BTW I looked into other answers, and one of them mentioned doing service iptables stop That did not help. Adapter 2 is a NAT, shown below In case NAT is causing any issues, i shut it down and restarted networking. [root@oracle-linux ~]# /etc/init.d/network restart Shutting down interface eth0: [ OK ] Shutting down interface eth1: Still No joy.. 18:27:04/shared:11 $ssh [email protected] ssh: connect to host 10.0.15.100 port 22: Operation timed out lost connection

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  • Solaris Administration Web GUI?

    - by Robert C
    I recently installed Solaris 11 x86 text install (http://www.oracle.com/technetwork/server-storage/solaris11/downloads/index.html?ssSourceSiteId=ocomen) to be used as a file server running ZFS. I noticed that I'm given the bare minimum in terms of packages. Is there an official oracle web GUI for managing ZFS? I ran a netstat and it doesn't appear to have installed any webserver thats listening. I saw something from a couple years ago, but apparently it's not packaged or maintained anymore (https://blogs.oracle.com/talley/entry/manage_zfs_from_your_browser). I tried pkg install network-console, but it says that the package isn't available for my platform. Any ideas? I'd like to stick with Oracle Solaris instead of the open source alternatives, if possible.

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