Search Results

Search found 18661 results on 747 pages for 'linq to mysql'.

Page 448/747 | < Previous Page | 444 445 446 447 448 449 450 451 452 453 454 455  | Next Page >

• Deleting a user > need to also delete their project, and then activities for that project? (PHP, MyS

  - by Jamie

  Hi guys, Really stuck with this... basically my system has 4 tables; users, projects, user_projects and activities. The user table has a usertype field which defines whether or not they are admin or user (by an integer)... An admin can create a project, create an acitivity for the project and assign a user (limited access user) an activity. Therefore, this setup means that an admin is never directly associated with an activity (instead a project). When my head admin user deletes an admin, I need all projects and activities (for their projects) to be deleted also. My delete script for a user is simple so far and works, but I'm having trouble on how to gain the projectID in order to know which activities to remove (associated with the projects which are about to be deleted): $userid = $_GET['userid']; $query = "DELETE FROM users WHERE userid=".$userid; $result = mysql_query($sql, $connection) or die("Error: ".mysql_error()); $query = "DELETE FROM projects WHERE userid=".$userid; $result = mysql_query($sql, $connection) or die("Error: ".mysql_error()); $query = "DELETE FROM userprojects WHERE userid=".$userid; $result = mysql_query($sql, $connection) or die("Error: ".mysql_error()); $query = "DELETE FROM activities WHERE projectid=".$projectid; $result = mysql_query($sql, $connection) or die("Error: ".mysql_error()); Now the first three queries execute fine, obviously because the userid is being retrieved successfully. However the 4th and final query I know is wrong, because there is no projectid to be gained from anywhere, however I put it there to help understand what I am trying to get!! :D Im guessing that i would need something like 'WHERE projectid=' then something to gather the removed projects from the userid which can be related to the activities for that project(s)!! Its a simple concept but I'm having trouble...please excuse any bad code as I am learning also. Thanks for any help!

  Read the article

• Missing Password check

  - by AAA

  I am using the code below, it checks for empty fields and verifies email, but even if the password is correct it won't login. the password has been inserted with md5 protection, below is the code. I am new to this so please bare with me. Thanks! PHP: session_start(); //Checks if there is a login cookie if(isset($_COOKIE['ID_my_site'])) //if there is, it logs you in and directes you to the members page { $email = $_COOKIE['ID_my_site']; $pass = $_COOKIE['Key_my_site']; $check = mysql_query("SELECT * FROM accounts WHERE email = '$email'")or die(mysql_error()); while($info = mysql_fetch_array( $check )) { if ($pass != $info['password']) { } else { header("Location: home.php"); } } } //if the login form is submitted if (isset($_POST['submit'])) { // if form has been submitted // makes sure they filled it in if(!$_POST['email'] | !$_POST['password']) { die('You did not fill in a required field.'); } // checks it against the database if (!get_magic_quotes_gpc()) { $_POST['email'] = addslashes($_POST['email']); } $check = mysql_query("SELECT * FROM accounts WHERE email = '".$_POST['email']."'")or die(mysql_error()); //Gives error if user dosen't exist $check2 = mysql_num_rows($check); if ($check2 == 0) { die('That user does not exist in our database. <a href=add.php>Click Here to Register</a>'); } while($info = mysql_fetch_array( $check )) { $_POST['password'] = stripslashes($_POST['password']); $info['password'] = stripslashes($info['password']); $_POST['password'] = md5($_POST['password']); //gives error if the password is wrong if ($_POST['password'] != $info['password']) { die('Incorrect password, please try again.'); } else { // if login is ok then we add a cookie $_POST['email'] = stripslashes($_POST['email']); $hour = time() + 3600; setcookie(ID_my_site, $_POST['email'], $hour); setcookie(Key_my_site, $_POST['password'], $hour); //then redirect them to the members area header("Location: home.php"); } } } else { // if they are not logged in <form action="<?php echo $_SERVER['PHP_SELF']?>" method="post"> <table border="0"> <tr><td colspan=2><h1>Login</h1></td></tr> <tr><td>email:</td><td> <input type="text" name="email" maxlength="40"> </td></tr> <tr><td>Password:</td><td> <input type="password" name="password" maxlength="50"> </td></tr> <tr><td colspan="2" align="right"> <input type="submit" name="submit" value="Login"> </td></tr> </table> </form> } Here is the registration code: PHP: // here we encrypt the password and add slashes if needed $_POST['password'] = md5($_POST['password']); if (!get_magic_quotes_gpc()) { $_POST['password'] = mysql_escape_string($_POST['password']); $_POST['email'] = mysql_escape_string($_POST['email']); $_POST['full_name'] = mysql_escape_string($_POST['full_name']); $_POST['user_url'] = mysql_escape_string($_POST['user_url']); } // now we insert it into the database $insert = "INSERT INTO accounts (Uniquer, Full_name, Email, Password, User_url) VALUES ('".$uniquer."','".$_POST['full_name']."', '".$_POST['email']."','".$_POST['password']."', '".$_POST['user_url']."')"; $add_member = mysql_query($insert); After using ini_set function i got to see the error, i am getting this message but not sure what it means: Notice: Undefined index: password in /var/www/domain.com/htdocs/login.php on line 103 Notice: Use of undefined constant password - assumed 'password' in /var/www/domain.com/htdocs/login.php on line 11

  Read the article

• Tricky SQL query involving consecutive values

  - by Gabriel

  I need to perform a relatively easy to explain but (given my somewhat limited skills) hard to write SQL query. Assume we have a table similar to this one: exam_no | name | surname | result | date ---------+------+---------+--------+------------ 1 | John | Doe | PASS | 2012-01-01 1 | Ryan | Smith | FAIL | 2012-01-02 <-- 1 | Ann | Evans | PASS | 2012-01-03 1 | Mary | Lee | FAIL | 2012-01-04 ... | ... | ... | ... | ... 2 | John | Doe | FAIL | 2012-02-01 <-- 2 | Ryan | Smith | FAIL | 2012-02-02 2 | Ann | Evans | FAIL | 2012-02-03 2 | Mary | Lee | PASS | 2012-02-04 ... | ... | ... | ... | ... 3 | John | Doe | FAIL | 2012-03-01 3 | Ryan | Smith | FAIL | 2012-03-02 3 | Ann | Evans | PASS | 2012-03-03 3 | Mary | Lee | FAIL | 2012-03-04 <-- Note that exam_no and date aren't necessarily related as one might expect from the kind of example I chose. Now, the query that I need to do is as follows: From the latest exam (exam_no = 3) find all the students that have failed (John Doe, Ryan Smith and Mary Lee). For each of these students find the date of the first of the batch of consecutively failing exams. Another way to put it would be: for each of these students find the date of the first failing exam that comes after their last passing exam. (Look at the arrows in the table). The resulting table should be something like this: name | surname | date_since_failing ------+---------+-------------------- John | Doe | 2012-02-01 Ryan | Smith | 2012-01-02 Mary | Lee | 2012-01-04 Ann | Evans | 2012-02-03 How can I perform such a query? Thank you for your time.

  Read the article

• PDO::fetchAll vs. PDO::fetch in a loop

  - by Byron

  Just a quick question. Is there any performance difference between using PDO::fetchAll() and PDO::fetch() in a loop (for large result sets)? I'm fetching into objects of a user-defined class, if that makes any difference. My initial uneducated assumption was that fetchAll might be faster because PDO can perform multiple operations in one statement while mysql_query can only execute one. However I have little knowledge of PDO's inner workings and the documentation doesn't say anything about this, and whether or not fetchAll() is simply a PHP-side loop dumped into an array. Any help?

  Read the article

• Failing to install activerecord-jdbcmysql-adapter gem

  - by Phil Sturgeon

  I am trying to follow the basic "Create a blog in 20 minutes" Rails screencast but have hit a stumbling block already. When I try to rake db:migrate I get errors about the gem activerecord-jdbcmysql-adapter not being installed. When I try to install it, I am told it doesn't exist. If I try to simply gem install mysql I get all sorts of madness appearing. I am running this on Mac OS X 10.6.2 and my installation was all done through gem. My basic setup works (Hello world!). Here is the error log: $ rake db:migrate (in /Users/xxxx/Sites/blog) rake aborted! Please install the jdbcmysql adapter: gem install activerecord-jdbcmysql-adapter (no such file to load -- active_record/connection_adapters/jdbcmysql_adapter) (See full trace by running task with --trace) $ sudo gem install activerecord-jdbcmysql-adapter ERROR: could not find gem activerecord-jdbcmysql-adapter locally or in a repository $ sudo gem install mysql Password: Building native extensions. This could take a while... ERROR: Error installing mysql: ERROR: Failed to build gem native extension. /opt/local/bin/ruby extconf.rb checking for mysql_query() in -lmysqlclient... no checking for main() in -lm... yes checking for mysql_query() in -lmysqlclient... no checking for main() in -lz... yes checking for mysql_query() in -lmysqlclient... no checking for main() in -lsocket... no checking for mysql_query() in -lmysqlclient... no checking for main() in -lnsl... no checking for mysql_query() in -lmysqlclient... no checking for main() in -lmygcc... no checking for mysql_query() in -lmysqlclient... no * extconf.rb failed * Could not create Makefile due to some reason, probably lack of necessary libraries and/or headers. Check the mkmf.log file for more details. You may need configuration options. Provided configuration options: --with-opt-dir --without-opt-dir --with-opt-include --without-opt-include=${opt-dir}/include --with-opt-lib --without-opt-lib=${opt-dir}/lib --with-make-prog --without-make-prog --srcdir=. --curdir --ruby=/opt/local/bin/ruby --with-mysql-config --without-mysql-config --with-mysql-dir --without-mysql-dir --with-mysql-include --without-mysql-include=${mysql-dir}/include --with-mysql-lib --without-mysql-lib=${mysql-dir}/lib --with-mysqlclientlib --without-mysqlclientlib --with-mlib --without-mlib --with-mysqlclientlib --without-mysqlclientlib --with-zlib --without-zlib --with-mysqlclientlib --without-mysqlclientlib --with-socketlib --without-socketlib --with-mysqlclientlib --without-mysqlclientlib --with-nsllib --without-nsllib --with-mysqlclientlib --without-mysqlclientlib --with-mygcclib --without-mygcclib --with-mysqlclientlib --without-mysqlclientlib Gem files will remain installed in /opt/local/lib/ruby/gems/1.8/gems/mysql-2.8.1 for inspection. Results logged to /opt/local/lib/ruby/gems/1.8/gems/mysql-2.8.1/ext/mysql_api/gem_make.out

  Read the article

• Retreive a value inside a stored procedure and use it inside that stored procedure

  - by sai

  delimiter // CREATE DEFINER=root@localhost PROCEDUREgetData(IN templateName VARCHAR(45),IN templateVersion VARCHAR(45),IN userId VARCHAR(45)) BEGIN set @version = CONCAT("SELECT saveOEMsData_answersVersion FROMsaveOEMsData WHERE saveOEMsData_templateName = '",templateName,"' ANDsaveOEMsData_templateVersion = ",templateVersion," AND saveOEMsData_userId= ",userId); PREPARE s1 from @version; EXECUTE S1; END // delimiter ; I am retreiving saveOEMsData_answersVersion, but I have to use it in an IF loop, as in if the version == 1, then I would use a query, else I would use something else. But I am not able to use the version. Could someone help with this?? I am only able to print but not able to use the version for data manipulation. The procedure works fine but I am unable to proceed to next step which is the if condition. The if condition would have something like the below mentioned. IF(ver == 1) THEN SELECT "1"; END IF;

  Read the article

• How do I export a large table into 50 smaller csv files of 100,000 records each

  - by Eddie

  I am trying to export one field from a very large table - containing 5,000,000 records, for example - into a csv list - but not all together, rather, 100,000 records into each .csv file created - without duplication. How can I do this, please? I tried SELECT field_name FROM table_name WHERE certain_conditions_are_met INTO OUTFILE /tmp/name_of_export_file_for_first_100000_records.csv LINES TERMINATED BY '\n' LIMIT 0 , 100000 that gives the first 100000 records, but nothing I do has the other 4,900,000 records exported into 49 other files - and how do I specify the other 49 filenames? for example, I tried the following, but the SQL syntax is wrong: SELECT field_name FROM table_name WHERE certain_conditions_are_met INTO OUTFILE /home/user/Eddie/name_of_export_file_for_first_100000_records.csv LINES TERMINATED BY '\n' LIMIT 0 , 100000 INTO OUTFILE /home/user/Eddie/name_of_export_file_for_second_100000_records.csv LINES TERMINATED BY '\n' LIMIT 100001 , 200000 and that did not create the second file... what am I doing wrong, please, and is there a better way to do this? Should the LIMIT 0 , 100000 be put Before the first INTO OUTFILE statement, and then repeat the entire command from SELECT for the second 100,000 records, etc? Thanks for any help. Eddie

  Read the article

• Database design for very large amount of data

  - by Hossein

  Hi, I am working on a project, involving large amount of data from the delicious website.The data available is at files are "Date,UserId,Url,Tags" (for each bookmark). I normalized my database to a 3NF, and because of the nature of the queries that we wanted to use In combination I came down to 6 tables....The design looks fine, however, now a large amount of data is in the database, most of the queries needs to "join" at least 2 tables together to get the answer, sometimes 3 or 4. At first, we didn't have any performance issues, because for testing matters we haven't had added too much data in the database. No that we have a lot of data, simply joining extremely large tables does take a lot of time and for our project which has to be real-time is a disaster.I was wondering how big companies solve these issues.Looks like normalizing tables just adds complexity, but how does the big company handle large amounts of data in their databases, don't they do the normalization? thanks

  Read the article

• UTF-8 character encoding battles json_encode()

  - by Dave Jarvis

  Quest I am looking to fetch rows that have accented characters. The encoding for the column (NAME) is latin1_swedish_ci. The Code The following query returns Abord â Plouffe using phpMyAdmin: SELECT C.NAME FROM CITY C WHERE C.REGION_ID=10 AND C.NAME_LOWERCASE LIKE '%abor%' ORDER BY C.NAME LIMIT 30 The following displays expected values (function is called db_fetch_all( $result )): while( $row = mysql_fetch_assoc( $result ) ) { foreach( $row as $value ) { echo $value . " "; $value = utf8_encode( $value ); echo $value . " "; } $r[] = $row; } The displayed values: 5482 5482 Abord â Plouffe Abord â Plouffe The array is then encoded using json_encode: $rows = db_fetch_all( $result ); echo json_encode( $rows ); Problem The web browser receives the following value: {"ID":"5482","NAME":null} Instead of: {"ID":"5482","NAME":"Abord â Plouffe"} (Or the encoded equivalent.) Question The documentation states that json_encode() works on UTF-8. I can see the values being encoded from LATIN1 to UTF-8. After the call to json_encode(), however, the value becomes null. How do I make json_encode() encode the UTF-8 values properly? One possible solution is to use the Zend Framework, but I'd rather not if it can be avoided.

  Read the article

• Can't find my.cnf file so I can enable InnoDB - is there another way?

  - by Jared

  Hey all, I am trying to Magento running on a share server, and am having difficulty. When I look at the engines in PHPmyAdmin, I get InnoDB DISABLED. So I look in /etc/, and there is no my.cnf file. There is a ftpquota and a .boxtrapper file, but nothing else. I know I can probably create a new one, but this is a server that hosts a lot of sites. I'm afraid I will mess someone up. So is there a way to maybe create a my.cnf file that only enable InnoDB and doesn't effect anything else? Or is there another way to enable it?

  Read the article

• Getting Phing's dbdeploy task to automatically rollback on delta error

  - by Gordon

  I am using Phing's dbdeploy task to manage my database schema. This is working fine, as long as there is no errors in the queries of my delta files. However, if there is an error, dbdeploy will just run the delta files up to the query with the error and then abort. This causes me some frustration, because I have to manually rollback the entry in the changelog table then. If I don't, dbdeploy will assume the migration was successful on a subsequent try. So the question is, is there any way to get dbdeploy use transactions or can you suggest any other way to have phing rollback automatically when an error occurs? Note: I'm not that proficient with Phing, so if this involves writing a custom task, any example code or a url with further information is highly appreciated. Thanks

  Read the article

• Modify Wordpress SQL Query to pull from within a category

  - by Levi

  Hi I am using a wordpress plugin called "kf most read" which stores a count of how many times a post was read, and lets you output a list of most read posts. This works well. The issue is, I am trying to pull the most read posts, but only the most read posts within the current category you are viewing. I am close to clueless when it comes to sql. Here us what the plugin is currently using to pull the most read posts: $sql = "SELECT count(mr.post_ID) as totHits, p.ID, p.post_title from $wpdb-posts p JOIN {$wpdb-prefix}kf_most_read mr on mr.post_ID = p.ID where mr.hit_ts = '".(time() - ( 86400 * $period))."' GROUP BY mr.post_ID order by totHits desc, ID ASC LIMIT $limit"; How could I incorporate the below query which pulls from a specific category into the above? $sql .= "LEFT JOIN $wpdb-term_taxonomy ON($wpdb-term_relationships.term_taxonomy_id = $wpdb-term_taxonomy.term_taxonomy_id)" ; $sql .= "WHERE $wpdb-term_taxonomy.term_id IN ($currentcat)" ; $sql .= "AND $wpdb-term_taxonomy.taxonomy = 'category'" ; Any Help on this would be much appreciated.

  Read the article

• (Doctrine-Ubuntu) Get error: doctrine-cli.php: command not found

  - by meyosef

  Hi, (Doctrine-Ubuntu) I run $ doctrine-cli.php command and get doctrine-cli.php: command not found. P

  Read the article

• Update multiple rows with known keys without inserting new rows if nonexistent keys are found

  - by Kirzilla

  Hello, Let's imagine that we have table items... table: items item_id INT PRIMARY AUTO_INCREMENT title VARCHAR(255) views INT Let's imagine that it is filled with something like (1, item-1, 10), (2, item-2, 10), (3, item-3, 15) I want to make multi update view for this items from data taken from this array [item_id] = [views] '1' => '50', '2' => '60', '3' => '70', '5' => '10' IMPORTANT! Please note that we have item_id=5 in array, but we don't have item_id=5 in database. I can use INSERT ... ON DUPLICATE KEY UPDATE, but this way image_id=5 will be inserted into talbe items. How to avoid inserting new key? I just want item_id=5 be skipped because it is not in table. Of course, before execution I can select existing keys from items table; then compare with keys in array; delete nonexistent keys and perform INSERT ... ON DUPLICATE KEY UPDATE. But maybe there is some more elegant solutions? Thank you.

  Read the article

• Naming conventions and field naming question for CakePHP

  - by jphenow

  Okay so two questions very related: 1) Does following the naming convention for classes, controllers, database fields, etc. affect the framework's ability to work the way it was intended? (I'm a little new to working with a framework from the beginning of app development) 2) This question is more important if 1 is a yes. Say I have a table, A, that has 2 foreign keys pointing at the same table, B, but different entries (they're like edges of a graph that point at two vertices) how would I follow the naming convention of their database fields? All I can think to do is something like vertex_1_id and vertex_2_id but I don't know how the framework would handle that if the naming conventions are necessary for its functioning correctly.

  Read the article

• Comparing fields of one table to other fields of another table

  - by chupinette

  Hello! I have a function called add_item which actually inserts values in a field item_name of temporary table called temp having fields temp_id and item_name. I have another table calleed item which consists of fields item_id, item_name, price. I have another table called quotation which consists of fields q_id, item_id,item_name,price. Now I cant figure out how do i compare the item_name from temp to the field item_name from item. And then, insert the values of item in quoatation table. Can anyone guide me please?

  Read the article

• Query that ignore the spaces.

  - by xRobot

  What's the best way to run a query so that spaces in the fields are ignored? For example the following queries.... SELECT * FROM mytable WHERE username = "JohnBobJones" SELECT * FROM mytable WHERE username = "John Bob Jones" . would find the following entries: John Bob Jones JohnBob Jones JohnBobJones . I am using php or python but I think this doesn't matter.

  Read the article

• Need Advice on building the database. all in one table or split?

  - by Ibrahim Azhar Armar

  hello, i am developing an application for a real-estate company. the problem i am facing is about implementing the database. however i am just confused on which way to adopt i would appreciate if you could help me out in reasoning the database implementation. here is my situation. a) i have to store the property details in the database. b) the properties have approximately 4-5 categories to which it will belong for ex : resedential, commnercial, industrial etc. c) now the categories have sub-categories. for example. a residential category will have sub category such as. Apartment / Independent House / Villa / Farm House/ Studio Apartment etc. and hence same way commercial and industrial or agricultural will too have sub-categories. d) each sub-categories will have to store the different values. like a resident will have features like Bedrooms/ kitchens / Hall / bathroom etc. the features depends on the sub categories. for an example on how i would want to implement my application you can have a look at this site. http://www.magicbricks.com/bricks/postProperty.html i could possibly think of the solution like this. a) create four to five tables depending upon the categories which will be existing(the problem is categories might increase in the future). b) create different tables for all the features, location, price, description and merge the common property table into one. for example all the property will have the common entity such as location, total area, etc. what would you advice for me given the current situation. thank you

  Read the article

• Drupal db_query error need help

  - by Gobi

  Hi drupal pals, im using drupal 6.15 and doing my first project in drupal . i got an issue while running the below query with db_query i have drupal,delhi keywords in column 'tag' with table name tagging. db_query(SELECT * FROM {tagging} WHERE tag LIKE '%drup%') wont retrieve the correct output. it show null but the query modified like this, db_query(SELECT * FROM {tagging} WHERE tag LIKE 'drup%') retrieve "drupal" as output finally i used the php core mysql_query mysql_query(SELECT * FROM tagging WHERE tag LIKE '%drup%') it retrieve the exact n correct output "drupal" . is any one have solution , Thanxs, Gobi

  Read the article

• Zend_Table_Db and Zend_Paginator and Zend_Paginator_Adapter_DbSelect

  - by Uffo

  I have the following query: $this->select() ->where("`name` LIKE ?",'%'.mysql_escape_string($name).'%') Now I have the Zend_Paginator code: $paginator = new Zend_Paginator( // $d is an instance of Zend_Db_Select new Zend_Paginator_Adapter_DbSelect($d) ); $paginator->getAdapter()->setRowCount(200); $paginator->setItemCountPerPage(15) ->setPageRange(10) ->setCurrentPageNumber($pag); $this->view->data = $paginator; As you see I'm passing the data to the view using $this->view->data = $paginator Before I didn't had $paginator->getAdapter()->setRowCount(200);I could determinate If I have any data or not, what I mean with data, if the query has some results, so If the query has some results I show the to the user, if not, I need to show them a message(No results!) But in this moment I don't know how can I determinate this, since count($paginator) doesn't work anymore because of $paginator->getAdapter()->setRowCount(200);and I'm using this because it taks about 7 sec for Zend_Paginator to count the page numbers. So how can I find If my query has any results?

  Read the article

• Database design in blogging systems

  - by Peter

  As a learning exercise I'm trying to put myself a blogging system. The goal is to code something that will let me create multiple blogs, like blogger.com or wordpress.com, but much simplified. I would like to ask you, what do you think is best database design for this type of script. Is it better to have one big table, containing posts from all blogs of all users (like friendfeed) or would it be better to create separate table for each blog's posts? Big thanks in advance for your help, Peter.

  Read the article

• Python MySQLdb placeholders syntax

  - by ensnare

  I'd like to use placeholders as seen in this example: cursor.execute (""" UPDATE animal SET name = %s WHERE name = %s """, ("snake", "turtle")) Except I'd like to have the query be its own variable as I need to insert a query into multiple databases, as in: query = """UPDATE animal SET name = %s WHERE name = %s """, ("snake", "turtle")) cursor.execute(query) cursor2.execute(query) cursor3.execute(query) What would be the proper syntax for doing something like this?

  Read the article

• PHP throws 'Allowed memory exhausted' errors while migrating data in Drupal.

  - by Stan

  I'm trying to setup a tiny sandbox on a local machine to play around with Drupal. I created a few CCK types; in order to create a few nodes I wrote the following script: chdir('C:\..\drupal'); require_once '.\includes\bootstrap.inc'; drupal_bootstrap(DRUPAL_BOOTSTRAP_FULL); module_load_include('inc', 'node', 'node.pages'); $node = array('type' => 'my_type'); $link = mysql_connect(..); mysql_select_db('my_db'); $query_bldg = ' SELECT stuff FROM table LIMIT 10 '; $result = mysql_query($query_bldg); while ($row = mysql_fetch_object($result)) { $form_state = array(); $form_state['values']['name'] = 'admin'; $form_state['values']['status'] = 1; $form_state['values']['op'] = t('Save'); $form_state['values']['title'] = $row->val_a; $form_state['values']['my_field'][0]['value'] = $row->val_b; ## About another dozen or so of similar assignments... drupal_execute('node_form', $form_state, (object)$node); } Here are a few relevant lines from php_errors.log: [12-Jun-2010 05:02:47] PHP Notice: Undefined index: REMOTE_ADDR in C:\..\drupal\includes\bootstrap.inc on line 1299 [12-Jun-2010 05:02:47] PHP Notice: Undefined index: REMOTE_ADDR in C:\..\drupal\includes\bootstrap.inc on line 1299 [12-Jun-2010 05:02:47] PHP Warning: session_start(): Cannot send session cookie - headers already sent by (output started at C:\..\drupal\includes\bootstrap.inc:1299) in C:\..\drupal\includes\bootstrap.inc on line 1143 [12-Jun-2010 05:02:47] PHP Warning: session_start(): Cannot send session cache limiter - headers already sent (output started at C:\..\drupal\includes\bootstrap.inc:1299) in C:\..\drupal\includes\bootstrap.inc on line 1143 [12-Jun-2010 05:02:47] PHP Warning: Cannot modify header information - headers already sent by (output started at C:\..\drupal\includes\bootstrap.inc:1299) in C:\..\drupal\includes\bootstrap.inc on line 709 [12-Jun-2010 05:02:47] PHP Warning: Cannot modify header information - headers already sent by (output started at C:\..\drupal\includes\bootstrap.inc:1299) in C:\..\drupal\includes\bootstrap.inc on line 710 [12-Jun-2010 05:02:47] PHP Warning: Cannot modify header information - headers already sent by (output started at C:\..\drupal\includes\bootstrap.inc:1299) in C:\..\drupal\includes\bootstrap.inc on line 711 [12-Jun-2010 05:02:47] PHP Warning: Cannot modify header information - headers already sent by (output started at C:\..\drupal\includes\bootstrap.inc:1299) in C:\..\drupal\includes\bootstrap.inc on line 712 [12-Jun-2010 05:02:47] PHP Notice: Undefined index: REMOTE_ADDR in C:\..\drupal\includes\bootstrap.inc on line 1299 [12-Jun-2010 05:02:48] PHP Fatal error: Allowed memory size of 239075328 bytes exhau sted (tried to allocate 261904 bytes) in C:\..\drupal\includes\form.inc on line 488 [12-Jun-2010 05:03:22] PHP Fatal error: Allowed memory size of 239075328 bytes exhausted (tried to allocate 261904 bytes) in C:\..\drupal\includes\form.inc on line 488 [12-Jun-2010 05:04:34] PHP Fatal error: Allowed memory size of 262144 bytes exhausted (tried to allocate 261904 bytes) in Unknown on line 0 At this point any action php takes results in the last error shown above. I tried increasing the value of memory_limit in php.ini before the final Fatal error which obviously didn't help. How can the error be eliminated? Am I on a correct path to migrating data into Drupal or should the cck tables be operated on directly? Windows XP PHP 5.3.2 VC6 Apache 2.2

  Read the article

• remote database connection with my iphone application using cocos2d

  - by Rana

  MCPResult *theResult; MCPConnection *mySQLConnection; //initialize connection string vars NSString *dbURL = @"192.168.0.16"; NSString *userName = @""; NSString *pass = @""; int port = 3306; //open connection to database mySQLConnection = [[MCPConnection alloc] initToHost: dbURL withLogin:userName password:pass usingPort:port]; if ([mySQLConnection isConnected]) { NSLog(@"The connection to database was successfull"); } else { NSLog(@"The connection to database was failed"); } //selection to database if([mySQLConnection selectDB:@"blackjack_DB"]) { NSLog(@"Database found"); } else { NSLog(@"Database not found"); } //selection to Table theResult = [mySQLConnection queryString:@"select * from test"]; //theResult = [mySQLConnection queryString:@"select * from test where id='1'"]; //theResult = [mySQLConnection queryString:@"select id from test"]; //theResult = [mySQLConnection queryString:@"select name from test where pass='main_pass'"]; NSArray *m= [theResult fetchRowAsArray]; NSLog(@"%@", m); NSLog(@"%@", [m objectAtIndex:2]); Use this code for connecting & receive information from remotedatabase. And also use some framework. AppKit.framework, Cocoa.framework, Carbon.framework, MCPKit_bundled.framework. But stile i didn't connect my application with remort database.

  Read the article

• LIMIT then RAND rather than RAND then LIMIT

  - by Larry

  I'm using full text search to pull rows. I order the rows based on score (ORDER BY SCORE) , then of the top 20 rows (LIMIT 20), I want to rand (RAND) the result set. So for any specific search term, I want to randomly show 5 of the top 20 results. My workaround is code based- where I put the top 20 into an array then randomly select 5. Is there sql way to do this?

  Read the article

< Previous Page | 444 445 446 447 448 449 450 451 452 453 454 455  | Next Page >