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  • Problem getting weeks in a month with NSCalendar...

    - by AngrySpade
    I am creating a calendar control of sorts... One thing I need to know is how many weeks are there in a Month... So NSCalendar rangeOfUnit:inUnit:forDate Seems to be exactly what I need... Except I am noticing something that seems off and I can't quite figure out why this is happening... The following code... NSCalendar *calendar = [NSCalendar currentCalendar]; NSDateComponents *dateComponents = [[NSDateComponents alloc] init]; [dateComponents setYear: 2010]; [dateComponents setDay: 1]; for (int x=1; x<=12; x++) { [dateComponents setMonth: x]; NSDate *date = [calendar dateFromComponents:dateComponents]; NSLog(@"Date: %@", date); NSRange range = [calendar rangeOfUnit: NSWeekCalendarUnit inUnit: NSMonthCalendarUnit forDate:date]; NSLog(@"%d Weeks in Month %d", range.length, [dateComponents month]); } Is returning the following debug messages... 2010-03-14 13:08:10.350 Scrap[4256:207] Date: 2010-01-01 00:00:00 -0500 2010-03-14 13:08:10.351 Scrap[4256:207] 5 Weeks in Month 1 2010-03-14 13:08:10.352 Scrap[4256:207] Date: 2010-02-01 00:00:00 -0500 2010-03-14 13:08:10.352 Scrap[4256:207] 4 Weeks in Month 2 2010-03-14 13:08:10.353 Scrap[4256:207] Date: 2010-03-01 00:00:00 -0500 2010-03-14 13:08:10.353 Scrap[4256:207] 5 Weeks in Month 3 2010-03-14 13:08:10.354 Scrap[4256:207] Date: 2010-04-01 00:00:00 -0400 2010-03-14 13:08:10.355 Scrap[4256:207] 5 Weeks in Month 4 2010-03-14 13:08:10.356 Scrap[4256:207] Date: 2010-05-01 00:00:00 -0400 2010-03-14 13:08:10.357 Scrap[4256:207] 5 Weeks in Month 5 2010-03-14 13:08:10.358 Scrap[4256:207] Date: 2010-06-01 00:00:00 -0400 2010-03-14 13:08:10.358 Scrap[4256:207] 5 Weeks in Month 6 2010-03-14 13:08:10.359 Scrap[4256:207] Date: 2010-07-01 00:00:00 -0400 2010-03-14 13:08:10.360 Scrap[4256:207] 5 Weeks in Month 7 2010-03-14 13:08:10.361 Scrap[4256:207] Date: 2010-08-01 00:00:00 -0400 2010-03-14 13:08:10.364 Scrap[4256:207] 5 Weeks in Month 8 2010-03-14 13:08:10.364 Scrap[4256:207] Date: 2010-09-01 00:00:00 -0400 2010-03-14 13:08:10.365 Scrap[4256:207] 5 Weeks in Month 9 2010-03-14 13:08:10.366 Scrap[4256:207] Date: 2010-10-01 00:00:00 -0400 2010-03-14 13:08:10.366 Scrap[4256:207] 5 Weeks in Month 10 2010-03-14 13:08:10.367 Scrap[4256:207] Date: 2010-11-01 00:00:00 -0400 2010-03-14 13:08:10.367 Scrap[4256:207] 5 Weeks in Month 11 2010-03-14 13:08:10.369 Scrap[4256:207] Date: 2010-12-01 00:00:00 -0500 2010-03-14 13:08:10.369 Scrap[4256:207] 52 Weeks in Month 12 I cant quite figure out why I get 52 weeks in month 12. Any clues? Edit on 3/20/2010: Seeing as how I couldnt use rangeOfUnit:inUnit:forDate to calculate the number of weeks in a month. I decided to figure out a different way of calculating the same value. I figured I should do this in a non-Gregorian localized way, so I attempted to start with getting the number of days in a week, but I got the result of 28 days in a week. So I started writing more code to figure out why... I wanted to make sure that the type of NSCalendar that I was playing with was in fact what I was supposed to be getting... And that led me to finding some differences... NSCalendar *currentCalendar = [NSCalendar currentCalendar]; NSLog(@"Calendar with 'currentCalendar' Identifier: %@", [currentCalendar calendarIdentifier]); NSCalendar *calendarWithIdentifier = [[[NSCalendar alloc] initWithCalendarIdentifier: NSGregorianCalendar] autorelease]; NSLog(@"Calendar created with identifier Identifier: %@", [calendarWithIdentifier calendarIdentifier]); NSDate *now = [[NSDate alloc] init]; NSDateComponents *currentMonth = [currentCalendar components: NSMonthCalendarUnit | NSYearCalendarUnit fromDate: now]; NSDate *currentMonthDate = [currentCalendar dateFromComponents: currentMonth]; NSRange daysInWeekRange = [currentCalendar rangeOfUnit: NSDayCalendarUnit inUnit: NSWeekCalendarUnit forDate: currentMonthDate]; NSLog(@"CurrentCalendar: Length:%u Location:%u", daysInWeekRange.length, daysInWeekRange.location); currentMonth = [calendarWithIdentifier components: NSMonthCalendarUnit | NSYearCalendarUnit fromDate: now]; currentMonthDate = [calendarWithIdentifier dateFromComponents: currentMonth]; daysInWeekRange = [calendarWithIdentifier rangeOfUnit: NSDayCalendarUnit inUnit: NSWeekCalendarUnit forDate: currentMonthDate]; NSLog(@"GregorianCalendar: Length:%u Location:%u", daysInWeekRange.length, daysInWeekRange.location); And that got me the following log results... 2010-03-20 21:02:27.245 Scrap[52189:207] Calendar with 'currentCalendar' Identifier: gregorian 2010-03-20 21:02:27.246 Scrap[52189:207] Calendar created with identifier Identifier: gregorian 2010-03-20 21:02:27.248 Scrap[52189:207] CurrentCalendar: Length:28 Location:1 2010-03-20 21:02:27.249 Scrap[52189:207] GregorianCalendar: Length:7 Location:1 Taking direction from @CarlNorum's experience, I compiled the code snippet as a 10.6 Cocoa application, and I got the following... 2010-03-20 21:05:35.636 ScrapCocoa[52238:a0f] Calendar with 'currentCalendar' Identifier: gregorian 2010-03-20 21:05:35.636 ScrapCocoa[52238:a0f] Calendar created with identifier Identifier: gregorian 2010-03-20 21:05:35.637 ScrapCocoa[52238:a0f] CurrentCalendar: Length:6 Location:1 2010-03-20 21:05:35.638 ScrapCocoa[52238:a0f] GregorianCalendar: Length:7 Location:1 I saw hope in that creating a NSCalendar Instance explicitly as a Gregorian Calendar would lead to better results in my original problem... So I modified that original code NSCalendar *currentCalendar = [NSCalendar currentCalendar]; NSLog(@"Calendar with 'currentCalendar' Identifier: %@", [currentCalendar calendarIdentifier]); NSCalendar *calendarWithIdentifier = [[[NSCalendar alloc] initWithCalendarIdentifier: NSGregorianCalendar] autorelease]; NSLog(@"Calendar created with identifier Identifier: %@", [calendarWithIdentifier calendarIdentifier]); NSDateComponents *dateComponents = [[[NSDateComponents alloc] init] autorelease]; [dateComponents setYear: 2010]; [dateComponents setDay: 1]; for (int x=1; x<=12; x++) { [dateComponents setMonth: x]; NSDate *date = [currentCalendar dateFromComponents: dateComponents]; NSRange range = [currentCalendar rangeOfUnit: NSWeekCalendarUnit inUnit: NSMonthCalendarUnit forDate: date]; NSLog(@"CurrentCalendar Date: %@", date); NSLog(@"CurrentCalendar: %d Weeks in Month %d", range.length, [dateComponents month]); date = [calendarWithIdentifier dateFromComponents: dateComponents]; range = [calendarWithIdentifier rangeOfUnit: NSWeekCalendarUnit inUnit: NSMonthCalendarUnit forDate: date]; NSLog(@"GregorianCalendar Date: %@", date); NSLog(@"GregorianCalendar: %d Weeks in Month %d", range.length, [dateComponents month]); } Unfortunately using a calendar created that way did not return a different result. 2010-03-20 21:15:40.465 Scrap[52367:207] Calendar with 'currentCalendar' Identifier: gregorian 2010-03-20 21:15:40.466 Scrap[52367:207] Calendar created with identifier Identifier: gregorian 2010-03-20 21:15:40.468 Scrap[52367:207] CurrentCalendar Date: 2010-01-01 00:00:00 -0500 2010-03-20 21:15:40.468 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 1 2010-03-20 21:15:40.469 Scrap[52367:207] GregorianCalendar Date: 2010-01-01 00:00:00 -0500 2010-03-20 21:15:40.470 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 1 2010-03-20 21:15:40.471 Scrap[52367:207] CurrentCalendar Date: 2010-02-01 00:00:00 -0500 2010-03-20 21:15:40.471 Scrap[52367:207] CurrentCalendar: 4 Weeks in Month 2 2010-03-20 21:15:40.472 Scrap[52367:207] GregorianCalendar Date: 2010-02-01 00:00:00 -0500 2010-03-20 21:15:40.473 Scrap[52367:207] GregorianCalendar: 4 Weeks in Month 2 2010-03-20 21:15:40.473 Scrap[52367:207] CurrentCalendar Date: 2010-03-01 00:00:00 -0500 2010-03-20 21:15:40.474 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 3 2010-03-20 21:15:40.475 Scrap[52367:207] GregorianCalendar Date: 2010-03-01 00:00:00 -0500 2010-03-20 21:15:40.475 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 3 2010-03-20 21:15:40.476 Scrap[52367:207] CurrentCalendar Date: 2010-04-01 00:00:00 -0400 2010-03-20 21:15:40.477 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 4 2010-03-20 21:15:40.478 Scrap[52367:207] GregorianCalendar Date: 2010-04-01 00:00:00 -0400 2010-03-20 21:15:40.479 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 4 2010-03-20 21:15:40.480 Scrap[52367:207] CurrentCalendar Date: 2010-05-01 00:00:00 -0400 2010-03-20 21:15:40.480 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 5 2010-03-20 21:15:40.482 Scrap[52367:207] GregorianCalendar Date: 2010-05-01 00:00:00 -0400 2010-03-20 21:15:40.482 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 5 2010-03-20 21:15:40.483 Scrap[52367:207] CurrentCalendar Date: 2010-06-01 00:00:00 -0400 2010-03-20 21:15:40.483 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 6 2010-03-20 21:15:40.484 Scrap[52367:207] GregorianCalendar Date: 2010-06-01 00:00:00 -0400 2010-03-20 21:15:40.485 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 6 2010-03-20 21:15:40.485 Scrap[52367:207] CurrentCalendar Date: 2010-07-01 00:00:00 -0400 2010-03-20 21:15:40.486 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 7 2010-03-20 21:15:40.486 Scrap[52367:207] GregorianCalendar Date: 2010-07-01 00:00:00 -0400 2010-03-20 21:15:40.487 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 7 2010-03-20 21:15:40.488 Scrap[52367:207] CurrentCalendar Date: 2010-08-01 00:00:00 -0400 2010-03-20 21:15:40.488 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 8 2010-03-20 21:15:40.489 Scrap[52367:207] GregorianCalendar Date: 2010-08-01 00:00:00 -0400 2010-03-20 21:15:40.489 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 8 2010-03-20 21:15:40.490 Scrap[52367:207] CurrentCalendar Date: 2010-09-01 00:00:00 -0400 2010-03-20 21:15:40.491 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 9 2010-03-20 21:15:40.491 Scrap[52367:207] GregorianCalendar Date: 2010-09-01 00:00:00 -0400 2010-03-20 21:15:40.492 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 9 2010-03-20 21:15:40.493 Scrap[52367:207] CurrentCalendar Date: 2010-10-01 00:00:00 -0400 2010-03-20 21:15:40.493 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 10 2010-03-20 21:15:40.494 Scrap[52367:207] GregorianCalendar Date: 2010-10-01 00:00:00 -0400 2010-03-20 21:15:40.494 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 10 2010-03-20 21:15:40.495 Scrap[52367:207] CurrentCalendar Date: 2010-11-01 00:00:00 -0400 2010-03-20 21:15:40.496 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 11 2010-03-20 21:15:40.496 Scrap[52367:207] GregorianCalendar Date: 2010-11-01 00:00:00 -0400 2010-03-20 21:15:40.497 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 11 2010-03-20 21:15:40.498 Scrap[52367:207] CurrentCalendar Date: 2010-12-01 00:00:00 -0500 2010-03-20 21:15:40.498 Scrap[52367:207] CurrentCalendar: 52 Weeks in Month 12 2010-03-20 21:15:40.499 Scrap[52367:207] GregorianCalendar Date: 2010-12-01 00:00:00 -0500 2010-03-20 21:15:40.500 Scrap[52367:207] GregorianCalendar: 52 Weeks in Month 12 Compiling the code for Cocoa just for kicks, was actually amusing... As the results are really really different 2010-03-20 21:11:24.610 ScrapCocoa[52313:a0f] Calendar with 'currentCalendar' Identifier: gregorian 2010-03-20 21:11:24.611 ScrapCocoa[52313:a0f] Calendar created with identifier Identifier: gregorian 2010-03-20 21:11:24.613 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-01-01 00:00:00 -0500 2010-03-20 21:11:24.613 ScrapCocoa[52313:a0f] CurrentCalendar: 6 Weeks in Month 1 2010-03-20 21:11:24.614 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-01-01 00:00:00 -0500 2010-03-20 21:11:24.615 ScrapCocoa[52313:a0f] GregorianCalendar: 5 Weeks in Month 1 2010-03-20 21:11:24.616 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-02-01 00:00:00 -0500 2010-03-20 21:11:24.616 ScrapCocoa[52313:a0f] CurrentCalendar: 5 Weeks in Month 2 2010-03-20 21:11:24.617 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-02-01 00:00:00 -0500 2010-03-20 21:11:24.618 ScrapCocoa[52313:a0f] GregorianCalendar: 4 Weeks in Month 2 2010-03-20 21:11:24.619 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-03-01 00:00:00 -0500 2010-03-20 21:11:24.619 ScrapCocoa[52313:a0f] CurrentCalendar: 5 Weeks in Month 3 2010-03-20 21:11:24.620 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-03-01 00:00:00 -0500 2010-03-20 21:11:24.621 ScrapCocoa[52313:a0f] GregorianCalendar: 5 Weeks in Month 3 2010-03-20 21:11:24.622 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-04-01 00:00:00 -0400 2010-03-20 21:11:24.622 ScrapCocoa[52313:a0f] CurrentCalendar: 5 Weeks in Month 4 2010-03-20 21:11:24.623 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-04-01 00:00:00 -0400 2010-03-20 21:11:24.623 ScrapCocoa[52313:a0f] GregorianCalendar: 5 Weeks in Month 4 2010-03-20 21:11:24.624 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-05-01 00:00:00 -0400 2010-03-20 21:11:24.625 ScrapCocoa[52313:a0f] CurrentCalendar: 6 Weeks in Month 5 2010-03-20 21:11:24.625 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-05-01 00:00:00 -0400 2010-03-20 21:11:24.626 ScrapCocoa[52313:a0f] GregorianCalendar: 6 Weeks in Month 5 2010-03-20 21:11:24.627 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-06-01 00:00:00 -0400 2010-03-20 21:11:24.627 ScrapCocoa[52313:a0f] CurrentCalendar: 5 Weeks in Month 6 2010-03-20 21:11:24.628 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-06-01 00:00:00 -0400 2010-03-20 21:11:24.628 ScrapCocoa[52313:a0f] GregorianCalendar: 5 Weeks in Month 6 2010-03-20 21:11:24.629 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-07-01 00:00:00 -0400 2010-03-20 21:11:24.630 ScrapCocoa[52313:a0f] CurrentCalendar: 5 Weeks in Month 7 2010-03-20 21:11:24.630 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-07-01 00:00:00 -0400 2010-03-20 21:11:24.631 ScrapCocoa[52313:a0f] GregorianCalendar: 5 Weeks in Month 7 2010-03-20 21:11:24.632 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-08-01 00:00:00 -0400 2010-03-20 21:11:24.632 ScrapCocoa[52313:a0f] CurrentCalendar: 5 Weeks in Month 8 2010-03-20 21:11:24.633 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-08-01 00:00:00 -0400 2010-03-20 21:11:24.633 ScrapCocoa[52313:a0f] GregorianCalendar: 6 Weeks in Month 8 2010-03-20 21:11:24.634 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-09-01 00:00:00 -0400 2010-03-20 21:11:24.635 ScrapCocoa[52313:a0f] CurrentCalendar: 5 Weeks in Month 9 2010-03-20 21:11:24.636 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-09-01 00:00:00 -0400 2010-03-20 21:11:24.636 ScrapCocoa[52313:a0f] GregorianCalendar: 5 Weeks in Month 9 2010-03-20 21:11:24.637 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-10-01 00:00:00 -0400 2010-03-20 21:11:24.637 ScrapCocoa[52313:a0f] CurrentCalendar: 6 Weeks in Month 10 2010-03-20 21:11:24.638 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-10-01 00:00:00 -0400 2010-03-20 21:11:24.639 ScrapCocoa[52313:a0f] GregorianCalendar: 5 Weeks in Month 10 2010-03-20 21:11:24.640 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-11-01 00:00:00 -0400 2010-03-20 21:11:24.640 ScrapCocoa[52313:a0f] CurrentCalendar: 5 Weeks in Month 11 2010-03-20 21:11:24.641 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-11-01 00:00:00 -0400 2010-03-20 21:11:24.641 ScrapCocoa[52313:a0f] GregorianCalendar: 5 Weeks in Month 11 2010-03-20 21:11:24.642 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-12-01 00:00:00 -0500 2010-03-20 21:11:24.642 ScrapCocoa[52313:a0f] CurrentCalendar: 5 Weeks in Month 12 2010-03-20 21:11:24.643 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-12-01 00:00:00 -0500 2010-03-20 21:11:24.644 ScrapCocoa[52313:a0f] GregorianCalendar: 5 Weeks in Month 12 I think this is when I give up...

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  • Linq IQueryable variables

    - by kevinw
    Hi i have a function that should return me a string but what is is doing is bringing me back the sql expression that i am using on the database what have i done wrong public static IQueryable XMLtoProcess(string strConnection) { Datalayer.HameserveDataContext db = new HameserveDataContext(strConnection); var xml = from x in db.JobImports where x.Processed == false select new { x.Content }; return xml; } this is the code sample this is what i should be getting back <PMZEDITRI TRI_TXNNO="11127" TRI_TXNSEQ="1" TRI_CODE="600" TRI_SUBTYPE="1" TRI_STATUS="Busy" TRI_CRDATE="2008-02-25T00:00:00.0000000-00:00" TRI_CRTIME="54540" TRI_PRTIME="0" TRI_BATCH="" TRI_REF="" TRI_CPY="main" C1="DEPL" C2="007311856/001" C3="14:55" C4="CUB2201" C5="MR WILLIAM HOGG" C6="CS12085393" C7="CS" C8="Blocked drain" C9="Scheme: CIS Home Rescue edi tests" C10="MR WILLIAM HOGG" C11="74 CROMARTY" C12="OUSTON" C13="CHESTER LE STREET" C14="COUNTY DURHAM" C15="" C16="DH2 1JY" C17="" C18="" C19="" C20="" C21="CIS" C22="0018586965 ||" C23="BD" C24="W/DE/BD" C25="EX-DIRECTORY" C26="" C27="/" C28="CIS Home Rescue" C29="CIS Home Rescue Plus Insd" C30="Homeserve Claims Management Ltd|Upon successful completion of this repair the contractor must submit an itemised and costed Homeserve Claims Management Ltd Job Sheet." N1="79.9000" N2="68.0000" N3="11.9000" N4="0" N5="0" N6="0" D1="2008-02-25T00:00:00.0000000-00:00" T2="EX-DIRECTORY" T4="Blocked drain" TRI_SYSID="9" TRI_RETRY="3" TRI_RETRYTIME="0" /> can anyone help me please

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  • Debugging a working program on Mathematica 5 with Mathematica 7

    - by Neuschwanstein
    Hi everybody, I'm currently reading the Mathematica Guidebooks for Programming and I was trying to work out one of the very first program of the book. Basically, when I run the following program: Plot3D[{Re[Exp[1/(x + I y)]]}, {x, -0.02, 0.022}, {y, -0.04, 0.042}, PlotRange -> {-1, 8}, PlotPoints -> 120, Mesh -> False, ColorFunction -> Function[{x1, x2, x3}, Hue[Arg[Exp[1/(x1 + I x2)]]]]] either I get a 1/0 error and e^\infinity error or, if I lower the PlotPoints options to, say, 60, an overflow error. I have a working output though, but it's not what it's supposed to be. The hue seems to be diffusing off the left corner whereas it should be diffusing of the origin (as can be seen on the original output) Here is the original program which apparently runs on Mathematica 5 (Trott, Mathematica Guidebook for Programming): Off[Plot3D::gval]; Plot3D[{Re[Exp[1/(x + I y)]], Hue[Arg[Exp[1/(x + I y)]]]}, {x, -0.02, 0.022}, {y, -0.04, 0.042}, PlotRange -> {-1, 8}, PlotPoints -> 120, Mesh -> False] Off[Plot3D::gval]; However, ColorFunction used this way (first Plot3D argument) doesn't work and so I tried to simply adapt to its new way of using it. Well, thanks I guess!

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  • Problem getting weeks in a month...

    - by AngrySpade
    I am creating a calendar control of sorts... One thing I need to know is how many weeks are there in a Month... So NSCalendar rangeOfUnit:inUnit:forDate Seems to be exactly what I need... Except I am noticing something that seems off and I can't quite figure out why this is happening... The following code... NSCalendar *calendar = [NSCalendar currentCalendar]; NSDateComponents *dateComponents = [[NSDateComponents alloc] init]; [dateComponents setYear: 2010]; [dateComponents setDay: 1]; for (int x=1; x<=12; x++) { [dateComponents setMonth: x]; NSDate *date = [calendar dateFromComponents:dateComponents]; NSLog(@"Date: %@", date); NSRange range = [calendar rangeOfUnit: NSWeekCalendarUnit inUnit: NSMonthCalendarUnit forDate:date]; NSLog(@"%d Weeks in Month %d", range.length, [dateComponents month]); } Is returning the following debug messages... 2010-03-14 13:08:10.350 Scrap[4256:207] Date: 2010-01-01 00:00:00 -0500 2010-03-14 13:08:10.351 Scrap[4256:207] 5 Weeks in Month 1 2010-03-14 13:08:10.352 Scrap[4256:207] Date: 2010-02-01 00:00:00 -0500 2010-03-14 13:08:10.352 Scrap[4256:207] 4 Weeks in Month 2 2010-03-14 13:08:10.353 Scrap[4256:207] Date: 2010-03-01 00:00:00 -0500 2010-03-14 13:08:10.353 Scrap[4256:207] 5 Weeks in Month 3 2010-03-14 13:08:10.354 Scrap[4256:207] Date: 2010-04-01 00:00:00 -0400 2010-03-14 13:08:10.355 Scrap[4256:207] 5 Weeks in Month 4 2010-03-14 13:08:10.356 Scrap[4256:207] Date: 2010-05-01 00:00:00 -0400 2010-03-14 13:08:10.357 Scrap[4256:207] 5 Weeks in Month 5 2010-03-14 13:08:10.358 Scrap[4256:207] Date: 2010-06-01 00:00:00 -0400 2010-03-14 13:08:10.358 Scrap[4256:207] 5 Weeks in Month 6 2010-03-14 13:08:10.359 Scrap[4256:207] Date: 2010-07-01 00:00:00 -0400 2010-03-14 13:08:10.360 Scrap[4256:207] 5 Weeks in Month 7 2010-03-14 13:08:10.361 Scrap[4256:207] Date: 2010-08-01 00:00:00 -0400 2010-03-14 13:08:10.364 Scrap[4256:207] 5 Weeks in Month 8 2010-03-14 13:08:10.364 Scrap[4256:207] Date: 2010-09-01 00:00:00 -0400 2010-03-14 13:08:10.365 Scrap[4256:207] 5 Weeks in Month 9 2010-03-14 13:08:10.366 Scrap[4256:207] Date: 2010-10-01 00:00:00 -0400 2010-03-14 13:08:10.366 Scrap[4256:207] 5 Weeks in Month 10 2010-03-14 13:08:10.367 Scrap[4256:207] Date: 2010-11-01 00:00:00 -0400 2010-03-14 13:08:10.367 Scrap[4256:207] 5 Weeks in Month 11 2010-03-14 13:08:10.369 Scrap[4256:207] Date: 2010-12-01 00:00:00 -0500 2010-03-14 13:08:10.369 Scrap[4256:207] 52 Weeks in Month 12 I cant quite figure out why I get 52 weeks in month 12. Any clues? Edit on 3/20/2010: Seeing as how I couldnt use rangeOfUnit:inUnit:forDate to calculate the number of weeks in a month. I decided to figure out a different way of calculating the same value. I figured I should do this in a non-Gregorian localized way, so I attempted to start with getting the number of days in a week, but I got the result of 28 days in a week. So I started writing more code to figure out why... I wanted to make sure that the type of NSCalendar that I was playing with was in fact what I was supposed to be getting... And that led me to finding some differences... NSCalendar *currentCalendar = [NSCalendar currentCalendar]; NSLog(@"Calendar with 'currentCalendar' Identifier: %@", [currentCalendar calendarIdentifier]); NSCalendar *calendarWithIdentifier = [[[NSCalendar alloc] initWithCalendarIdentifier: NSGregorianCalendar] autorelease]; NSLog(@"Calendar created with identifier Identifier: %@", [calendarWithIdentifier calendarIdentifier]); NSDate *now = [[NSDate alloc] init]; NSDateComponents *currentMonth = [currentCalendar components: NSMonthCalendarUnit | NSYearCalendarUnit fromDate: now]; NSDate *currentMonthDate = [currentCalendar dateFromComponents: currentMonth]; NSRange daysInWeekRange = [currentCalendar rangeOfUnit: NSDayCalendarUnit inUnit: NSWeekCalendarUnit forDate: currentMonthDate]; NSLog(@"CurrentCalendar: Length:%u Location:%u", daysInWeekRange.length, daysInWeekRange.location); currentMonth = [calendarWithIdentifier components: NSMonthCalendarUnit | NSYearCalendarUnit fromDate: now]; currentMonthDate = [calendarWithIdentifier dateFromComponents: currentMonth]; daysInWeekRange = [calendarWithIdentifier rangeOfUnit: NSDayCalendarUnit inUnit: NSWeekCalendarUnit forDate: currentMonthDate]; NSLog(@"GregorianCalendar: Length:%u Location:%u", daysInWeekRange.length, daysInWeekRange.location); And that got me the following log results... 2010-03-20 21:02:27.245 Scrap[52189:207] Calendar with 'currentCalendar' Identifier: gregorian 2010-03-20 21:02:27.246 Scrap[52189:207] Calendar created with identifier Identifier: gregorian 2010-03-20 21:02:27.248 Scrap[52189:207] CurrentCalendar: Length:28 Location:1 2010-03-20 21:02:27.249 Scrap[52189:207] GregorianCalendar: Length:7 Location:1 Taking direction from @CarlNorum's experience, I compiled the code snippet as a 10.6 Cocoa application, and I got the following... 2010-03-20 21:05:35.636 ScrapCocoa[52238:a0f] Calendar with 'currentCalendar' Identifier: gregorian 2010-03-20 21:05:35.636 ScrapCocoa[52238:a0f] Calendar created with identifier Identifier: gregorian 2010-03-20 21:05:35.637 ScrapCocoa[52238:a0f] CurrentCalendar: Length:6 Location:1 2010-03-20 21:05:35.638 ScrapCocoa[52238:a0f] GregorianCalendar: Length:7 Location:1 I saw hope in that creating a NSCalendar Instance explicitly as a Gregorian Calendar would lead to better results in my original problem... So I modified that original code NSCalendar *currentCalendar = [NSCalendar currentCalendar]; NSLog(@"Calendar with 'currentCalendar' Identifier: %@", [currentCalendar calendarIdentifier]); NSCalendar *calendarWithIdentifier = [[[NSCalendar alloc] initWithCalendarIdentifier: NSGregorianCalendar] autorelease]; NSLog(@"Calendar created with identifier Identifier: %@", [calendarWithIdentifier calendarIdentifier]); NSDateComponents *dateComponents = [[[NSDateComponents alloc] init] autorelease]; [dateComponents setYear: 2010]; [dateComponents setDay: 1]; for (int x=1; x<=12; x++) { [dateComponents setMonth: x]; NSDate *date = [currentCalendar dateFromComponents: dateComponents]; NSRange range = [currentCalendar rangeOfUnit: NSWeekCalendarUnit inUnit: NSMonthCalendarUnit forDate: date]; NSLog(@"CurrentCalendar Date: %@", date); NSLog(@"CurrentCalendar: %d Weeks in Month %d", range.length, [dateComponents month]); date = [calendarWithIdentifier dateFromComponents: dateComponents]; range = [calendarWithIdentifier rangeOfUnit: NSWeekCalendarUnit inUnit: NSMonthCalendarUnit forDate: date]; NSLog(@"GregorianCalendar Date: %@", date); NSLog(@"GregorianCalendar: %d Weeks in Month %d", range.length, [dateComponents month]); } Unfortunately using a calendar created that way did not return a different result. 2010-03-20 21:15:40.465 Scrap[52367:207] Calendar with 'currentCalendar' Identifier: gregorian 2010-03-20 21:15:40.466 Scrap[52367:207] Calendar created with identifier Identifier: gregorian 2010-03-20 21:15:40.468 Scrap[52367:207] CurrentCalendar Date: 2010-01-01 00:00:00 -0500 2010-03-20 21:15:40.468 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 1 2010-03-20 21:15:40.469 Scrap[52367:207] GregorianCalendar Date: 2010-01-01 00:00:00 -0500 2010-03-20 21:15:40.470 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 1 2010-03-20 21:15:40.471 Scrap[52367:207] CurrentCalendar Date: 2010-02-01 00:00:00 -0500 2010-03-20 21:15:40.471 Scrap[52367:207] CurrentCalendar: 4 Weeks in Month 2 2010-03-20 21:15:40.472 Scrap[52367:207] GregorianCalendar Date: 2010-02-01 00:00:00 -0500 2010-03-20 21:15:40.473 Scrap[52367:207] GregorianCalendar: 4 Weeks in Month 2 2010-03-20 21:15:40.473 Scrap[52367:207] CurrentCalendar Date: 2010-03-01 00:00:00 -0500 2010-03-20 21:15:40.474 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 3 2010-03-20 21:15:40.475 Scrap[52367:207] GregorianCalendar Date: 2010-03-01 00:00:00 -0500 2010-03-20 21:15:40.475 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 3 2010-03-20 21:15:40.476 Scrap[52367:207] CurrentCalendar Date: 2010-04-01 00:00:00 -0400 2010-03-20 21:15:40.477 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 4 2010-03-20 21:15:40.478 Scrap[52367:207] GregorianCalendar Date: 2010-04-01 00:00:00 -0400 2010-03-20 21:15:40.479 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 4 2010-03-20 21:15:40.480 Scrap[52367:207] CurrentCalendar Date: 2010-05-01 00:00:00 -0400 2010-03-20 21:15:40.480 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 5 2010-03-20 21:15:40.482 Scrap[52367:207] GregorianCalendar Date: 2010-05-01 00:00:00 -0400 2010-03-20 21:15:40.482 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 5 2010-03-20 21:15:40.483 Scrap[52367:207] CurrentCalendar Date: 2010-06-01 00:00:00 -0400 2010-03-20 21:15:40.483 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 6 2010-03-20 21:15:40.484 Scrap[52367:207] GregorianCalendar Date: 2010-06-01 00:00:00 -0400 2010-03-20 21:15:40.485 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 6 2010-03-20 21:15:40.485 Scrap[52367:207] CurrentCalendar Date: 2010-07-01 00:00:00 -0400 2010-03-20 21:15:40.486 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 7 2010-03-20 21:15:40.486 Scrap[52367:207] GregorianCalendar Date: 2010-07-01 00:00:00 -0400 2010-03-20 21:15:40.487 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 7 2010-03-20 21:15:40.488 Scrap[52367:207] CurrentCalendar Date: 2010-08-01 00:00:00 -0400 2010-03-20 21:15:40.488 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 8 2010-03-20 21:15:40.489 Scrap[52367:207] GregorianCalendar Date: 2010-08-01 00:00:00 -0400 2010-03-20 21:15:40.489 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 8 2010-03-20 21:15:40.490 Scrap[52367:207] CurrentCalendar Date: 2010-09-01 00:00:00 -0400 2010-03-20 21:15:40.491 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 9 2010-03-20 21:15:40.491 Scrap[52367:207] GregorianCalendar Date: 2010-09-01 00:00:00 -0400 2010-03-20 21:15:40.492 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 9 2010-03-20 21:15:40.493 Scrap[52367:207] CurrentCalendar Date: 2010-10-01 00:00:00 -0400 2010-03-20 21:15:40.493 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 10 2010-03-20 21:15:40.494 Scrap[52367:207] GregorianCalendar Date: 2010-10-01 00:00:00 -0400 2010-03-20 21:15:40.494 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 10 2010-03-20 21:15:40.495 Scrap[52367:207] CurrentCalendar Date: 2010-11-01 00:00:00 -0400 2010-03-20 21:15:40.496 Scrap[52367:207] CurrentCalendar: 5 Weeks in Month 11 2010-03-20 21:15:40.496 Scrap[52367:207] GregorianCalendar Date: 2010-11-01 00:00:00 -0400 2010-03-20 21:15:40.497 Scrap[52367:207] GregorianCalendar: 5 Weeks in Month 11 2010-03-20 21:15:40.498 Scrap[52367:207] CurrentCalendar Date: 2010-12-01 00:00:00 -0500 2010-03-20 21:15:40.498 Scrap[52367:207] CurrentCalendar: 52 Weeks in Month 12 2010-03-20 21:15:40.499 Scrap[52367:207] GregorianCalendar Date: 2010-12-01 00:00:00 -0500 2010-03-20 21:15:40.500 Scrap[52367:207] GregorianCalendar: 52 Weeks in Month 12 Compiling the code for Cocoa just for kicks, was actually amusing... As the results are really really different 2010-03-20 21:11:24.610 ScrapCocoa[52313:a0f] Calendar with 'currentCalendar' Identifier: gregorian 2010-03-20 21:11:24.611 ScrapCocoa[52313:a0f] Calendar created with identifier Identifier: gregorian 2010-03-20 21:11:24.613 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-01-01 00:00:00 -0500 2010-03-20 21:11:24.613 ScrapCocoa[52313:a0f] CurrentCalendar: 6 Weeks in Month 1 2010-03-20 21:11:24.614 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-01-01 00:00:00 -0500 2010-03-20 21:11:24.615 ScrapCocoa[52313:a0f] GregorianCalendar: 5 Weeks in Month 1 2010-03-20 21:11:24.616 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-02-01 00:00:00 -0500 2010-03-20 21:11:24.616 ScrapCocoa[52313:a0f] CurrentCalendar: 5 Weeks in Month 2 2010-03-20 21:11:24.617 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-02-01 00:00:00 -0500 2010-03-20 21:11:24.618 ScrapCocoa[52313:a0f] GregorianCalendar: 4 Weeks in Month 2 2010-03-20 21:11:24.619 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-03-01 00:00:00 -0500 2010-03-20 21:11:24.619 ScrapCocoa[52313:a0f] CurrentCalendar: 5 Weeks in Month 3 2010-03-20 21:11:24.620 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-03-01 00:00:00 -0500 2010-03-20 21:11:24.621 ScrapCocoa[52313:a0f] GregorianCalendar: 5 Weeks in Month 3 2010-03-20 21:11:24.622 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-04-01 00:00:00 -0400 2010-03-20 21:11:24.622 ScrapCocoa[52313:a0f] CurrentCalendar: 5 Weeks in Month 4 2010-03-20 21:11:24.623 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-04-01 00:00:00 -0400 2010-03-20 21:11:24.623 ScrapCocoa[52313:a0f] GregorianCalendar: 5 Weeks in Month 4 2010-03-20 21:11:24.624 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-05-01 00:00:00 -0400 2010-03-20 21:11:24.625 ScrapCocoa[52313:a0f] CurrentCalendar: 6 Weeks in Month 5 2010-03-20 21:11:24.625 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-05-01 00:00:00 -0400 2010-03-20 21:11:24.626 ScrapCocoa[52313:a0f] GregorianCalendar: 6 Weeks in Month 5 2010-03-20 21:11:24.627 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-06-01 00:00:00 -0400 2010-03-20 21:11:24.627 ScrapCocoa[52313:a0f] CurrentCalendar: 5 Weeks in Month 6 2010-03-20 21:11:24.628 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-06-01 00:00:00 -0400 2010-03-20 21:11:24.628 ScrapCocoa[52313:a0f] GregorianCalendar: 5 Weeks in Month 6 2010-03-20 21:11:24.629 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-07-01 00:00:00 -0400 2010-03-20 21:11:24.630 ScrapCocoa[52313:a0f] CurrentCalendar: 5 Weeks in Month 7 2010-03-20 21:11:24.630 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-07-01 00:00:00 -0400 2010-03-20 21:11:24.631 ScrapCocoa[52313:a0f] GregorianCalendar: 5 Weeks in Month 7 2010-03-20 21:11:24.632 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-08-01 00:00:00 -0400 2010-03-20 21:11:24.632 ScrapCocoa[52313:a0f] CurrentCalendar: 5 Weeks in Month 8 2010-03-20 21:11:24.633 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-08-01 00:00:00 -0400 2010-03-20 21:11:24.633 ScrapCocoa[52313:a0f] GregorianCalendar: 6 Weeks in Month 8 2010-03-20 21:11:24.634 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-09-01 00:00:00 -0400 2010-03-20 21:11:24.635 ScrapCocoa[52313:a0f] CurrentCalendar: 5 Weeks in Month 9 2010-03-20 21:11:24.636 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-09-01 00:00:00 -0400 2010-03-20 21:11:24.636 ScrapCocoa[52313:a0f] GregorianCalendar: 5 Weeks in Month 9 2010-03-20 21:11:24.637 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-10-01 00:00:00 -0400 2010-03-20 21:11:24.637 ScrapCocoa[52313:a0f] CurrentCalendar: 6 Weeks in Month 10 2010-03-20 21:11:24.638 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-10-01 00:00:00 -0400 2010-03-20 21:11:24.639 ScrapCocoa[52313:a0f] GregorianCalendar: 5 Weeks in Month 10 2010-03-20 21:11:24.640 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-11-01 00:00:00 -0400 2010-03-20 21:11:24.640 ScrapCocoa[52313:a0f] CurrentCalendar: 5 Weeks in Month 11 2010-03-20 21:11:24.641 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-11-01 00:00:00 -0400 2010-03-20 21:11:24.641 ScrapCocoa[52313:a0f] GregorianCalendar: 5 Weeks in Month 11 2010-03-20 21:11:24.642 ScrapCocoa[52313:a0f] CurrentCalendar Date: 2010-12-01 00:00:00 -0500 2010-03-20 21:11:24.642 ScrapCocoa[52313:a0f] CurrentCalendar: 5 Weeks in Month 12 2010-03-20 21:11:24.643 ScrapCocoa[52313:a0f] GregorianCalendar Date: 2010-12-01 00:00:00 -0500 2010-03-20 21:11:24.644 ScrapCocoa[52313:a0f] GregorianCalendar: 5 Weeks in Month 12 I think this is when I give up...

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  • Human age program in pascal

    - by bah
    Hi, I have this task and i can't figure out how to do it. I need to find persons age in days, there are given birth and death dates, there's data file: 8 Albertas Einšteinas 1879 03 14 1955 04 18 Balys Sruoga 1896 02 02 1947 10 16 Antanas Vienuolis 1882 04 07 1957 08 17 Ernestas Rezerfordas 1871 08 30 1937 10 17 Nilsas Boras 1885 10 07 1962 11 18 Nežiniukas Pirmasis 8 05 24 8 05 25 Nežiniukas Antrasis 888 05 25 888 05 25 Nežiniukas Treciasis 1 01 01 125 01 01 and there's how result file should look like: 1879 3 14 1955 4 18 27775 1896 2 2 1947 10 16 18871 1882 4 7 1957 8 17 27507 1871 8 30 1937 10 17 24138 1885 10 7 1962 11 18 28147 8 5 24 8 5 25 1 888 5 25 888 5 25 0 1 1 1 125 1 1 45260 Few things to notice: all februarys have 28 days. My function for calculating age: function AmziusFunc(Mas : TZmogus) : longint; var i, s : integer; amzius, max : longint; begin max := 125 * 365; amzius := (Mas.mirY - Mas.gimY) * 365 + (Mas.mirM - Mas.gimM) * 31 + (Mas.mirD - Mas.gimD); if ( amzius >= max ) then amzius := 0; AmziusFunc := amzius; end; What should i change there? Thanks.

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  • SSIS Lookup with Lookup Component Vs Script Component.

    - by Nev_Rahd
    Hello, I need to load Dimensions from EDW Tables (which does maintain historical records) and is of type Key-Value-Parameter. My scenario is ok if got a record in EDW as below Key1 Key2 Code Value EffectiveDate EndDate CurrentFlag 100 555 01 AAA 2010-01-01 11.00.00 9999-12-31 Y 100 555 02 BBB 2010-01-01 11.00.00 9999-12-31 Y This need to be loaded into DM by pivoting it as key1 and key2 combinations makes Natural key for DM SK NK 01 02 EffectiveDate EndDate CurrentFlag 1 100-555 AAA BBB 2010-01-01 11.00.00 9999-12-31 Y My ssis package does this all good pivoting... looking up the incoming NK in DIM.. if new will insert .. else with further lookup with effective date and determine if the incoming for same natural key got any new (change) in attribute.. if so updates the current record byy setting its end date and insert the new one with new attribute value and pulling the recent records values for other attributes. My problem is if the same natural key comes twice with same attribute in single extract my first lookup which on natural key .. will let both records pass and try to insert.. where its fails. If i get distinct records on NK the second is not picked and need to run package again. So my question how can i configure lookup or alernative way to handle this scenario when same NK comes twice in single extract, would be able to insert first record if not exists in Dim table and for second one should be able to updated with the changes with reference to one inserted above. Not sure this makes sense what am trying to explain. Will attached the screenshot once back to work desk (on monday). Thanks

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  • How do I debug a HTTP 502 error?

    - by Bialecki
    I have a Python Tornado server sitting behind a nginx frontend. Every now and then, but not every time, I get a 502 error. I look in the nginx access log and I see this: 127.0.0.1 - - [02/Jun/2010:18:04:02 -0400] "POST /a/question/updates HTTP/1.1" 502 173 "http://localhost/tagged/python" "Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3" and in the error log: 2010/06/02 18:04:02 [error] 14033#0: *1700 connect() failed (111: Connection refused) while connecting to upstream, client: 127.0.0.1, server: _, request: "POST /a/question/updates HTTP/1.1", upstream: "http://127.0.0.1:8888/a/question/updates", host: "localhost", referrer: "http://localhost/tagged/python" I don't think any errors show up in the Tornado log. How would you go about debugging this? Is there something I can put in the Tornado or nginx configuration to help debug this? EDIT: In addition, I get a fair number of 504, gateway timeout errors. Is it possible that the Tornado instance is just busy or something?

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  • Comparing UIColors or CGColor or CGColorSpace

    - by wiznaibus
    I'm having an issue comparing UIColors. I have an image, which I have successfully extracted the color on the image at which the user clicked. Now I want to compare that color with other colors, but I'm getting some strange results. Here's what I've tried: CGColorRef pixelColor = [[buttonImage colorAtPixel:point] CGColor]; UIColor* color = [UIColor colorWithCGColor:pixelColor]; UIColor* aqua = [UIColor colorWithRed:0.521569 green:0.768627 blue:0.254902 alpha:1]; if (CGColorEqualToColor(color.CGColor, aqua.CGColor)) { DLog(@"Apparently, it works"); } DLog(@"%@", color.CGColor); DLog(@"%@", aqua.CGColor); Output: 2011-05-21 19:48:27.144 Coffee[66860:207] -[DescriptorsViewController touchesEnded:withEvent:] <CGColor 0x4d1eb80> [<CGColorSpace 0x4d1a070> (kCGColorSpaceDeviceRGB)] ( 0.521569 0.768627 0.254902 1 ) 2011-05-21 19:48:27.145 Coffee[66860:207] -[DescriptorsViewController touchesEnded:withEvent:] <CGColor 0x4d1f750> [<CGColorSpace 0x4d1a070> (kCGColorSpaceDeviceRGB)] ( 0.521569 0.768627 0.254902 1 ) It looks like the CGColor addresses are different, but the CGColorSpaces are the same, but I can't figure out how to compare the CGColorSpaces I've also tried this: CGColorRef pixelColor = [[buttonImage colorAtPixel:point] CGColor]; UIColor* color = [UIColor colorWithCGColor:pixelColor]; UIColor* aqua = [UIColor colorWithRed:0.521569 green:0.768627 blue:0.254902 alpha:1]; if ([color isEqual:aqua]) { DLog(@"Apparently, it works"); } DLog(@"%@", color.CGColor); DLog(@"%@", aqua.CGColor); The same silliness occurs. 2011-05-21 20:02:49.277 Coffee[67013:207] -[DescriptorsViewController touchesEnded:withEvent:] <CGColor 0x4d3b810> [<CGColorSpace 0x5912010> (kCGColorSpaceDeviceRGB)] ( 0.521569 0.768627 0.254902 1 ) 2011-05-21 20:02:49.278 Coffee[67013:207] -[DescriptorsViewController touchesEnded:withEvent:] <CGColor 0x4d3ba20> [<CGColorSpace 0x5912010> (kCGColorSpaceDeviceRGB)] ( 0.521569 0.768627 0.254902 1 )`

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  • HTML Doctype Setting / IE Quirks Mode

    - by Frederico
    I'm working within the parameters of an un-reachable developer, whom has created an html generation system for our products.. Whenever a new page is generated he places: <!-- updated page at 05/MAY/2010 02:58.58 --> <!-- You must use the template manager to modify the formatting of this page. --> resulting in my code looking like: <!-- updated page at 05/MAY/2010 02:55.30 --> <!-- You must use the template manager to modify the formatting of this page. --> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html lang="en" xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"> I don't believe IE read's this doctype at all, as when looking at the developer screen, it renders in Quirks mode... is there any other way to force IE out of this horrible Quirks mode? I've been trying to reach the developer but he has been rather un-available.. Thank you in advance for any help you might have to offer.

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  • Regex statements for date ranges <=4/1/2009 and <=10/01/2009

    - by reggiereg
    Hi, I need serious help building two Regex statements for a project. The software we're using ONLY accepts Regex for validation. I need one that fires for any date <4/1/2009 and a second that fires for any date <10/1/2009 My co-worker gave me the following code to check for <=10/01/2010, but it checks leap years and all that stuff. I need something a little more streamlined than this in the MM/DD/YYYY format. Thanks in advance! ^(?:(?:0?[1-9])|(?:1[0-2]))(\/|-|.)(?:0?[1-9]|1\d|2[0-8])(\/|-|.)(?:2[0-9][2-9][0-9])$|^(?:(?:0?[1-9])|(?:1[0-2]))(\/|-|.)(?:0?[1-9]|1\d|2[0-8])(\/|-|.)(?:201[1-9])$|^(?:(?:(?:0?[13578]|1[02])(\/|-|.)31)|(?:(?:0?[1,3-9]|1[0-2])(\/|-|.)(?:29|30)))(\/|-|.)(?:201[1-9])$|^(?:(?:(?:11)(\/|-|.))(?:0?[1-9]|1\d|2[0-9]|30)(\/|-|.))(2010)$|^(?:(?:(?:10|12)(\/|-|.))(?:0?[1-9]|1\d|2[0-9]|30|31)(\/|-|.))(2010)$|^(?:(?:0?[1-9])|(?:1[0-2]))(\/|-|.)(?:0?[1-9]|1\d|2[0-8])(\/|-|.)(?:2[0-9][2-9][0-9])$|^(?:(?:(?:0?[13578]|1[02])(\/|-|.)31)\1|(?:(?:0?[1,3-9]|1[0-2])(\/|-|.)(?:29|30)))(\/|-|.)(?:2[0-9][2-9][0-9])$|^(?:(?:0?[1-9])|(?:1[0-2]))(\/|-|.)(?:0?[1-9]|1\d|2[0-8])(\/|-|.)(?:2011)$|^(?:0?2(\/|-|.)29\3(?:(?:(?:2[0-9][1-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$

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  • String Comparison containing hyphens not matching

    - by Christo Fur
    I have a method in a url rewriting module that looks like this public bool Match(Uri url) { string x = url.PathAndQuery.ToLowerInvariant(); string y = RuleData.ToLowerInvariant(); return x.Contains(y); } However, it is not returning true for the following values: x = "/xx09-02-09xx"; y = "09-02-09"; but if I write a unit test with the raw strings, like below, it does return true [Test] public void Contains() { string x = "/xx09-02-09xx"; string y = "09-02-09"; Assert.IsTrue(x.Contains(y)); // this returns true } What could be the difference? The encoding? The culture? Have tried removing the ToLowerInvarient(), but that makes no difference have tried all the following in the Match method bool contains = x.Contains(y); bool contains1 = x.IndexOf(y) != -1; bool contains2 = x.IndexOf(y, StringComparison.OrdinalIgnoreCase) != -1; bool contains3 = x.IndexOf(y, StringComparison.InvariantCultureIgnoreCase) != -1; bool contains4 = x.IndexOf(y, StringComparison.CurrentCultureIgnoreCase) != -1; but none return true for those values, when run in the rewrite module. But they do in the unit test. So something about the strings is clearly different any ideas?

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  • Get the current array key in a multi dimensional array

    - by johlton
    Hi *, I have a session array *$_SESSION['cart']* with some items in it. The structure ist like this (via *print_r*): Array ( [2-1] => Array ( [color] => 7 [articlenumber] => WRG70 10 [quantity] => 1 [price] => 17.50 ) [3-8] => Array ( [color] => 2 [articlenumber] => QRG50 02 [quantity] => 1 [price] => 13.50 ) ) Looping over the values for display is fine ... foreach($_SESSION['cart'] as $item_array) { foreach($item_array as $item => $value) { echo $value . ' | '; } } ... since it results in something like this: 7 | WRG70 10 | 1 | 17.50 | 2 | QRG50 02 | 1 | 13.50 | But Now: How can I output the matching key (e.g. '2-1') as well? I tried some array functions like key() & current but couldn't get it to work (one of these days). Any quick hint on this? Thanks a lot and best from Berlin Fabian

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  • Filtering most out of XML with XSL?

    - by Gnudiff
    I need to transform a lot of XML files (Fedora export) into a different kind of XML. Trying to do it with XSL stylesheets and checking with the msxsl transformer. Supposedly I have xml file like this (assuming there are actually other nodes inside AAA, OBJ, amd all other nodes), Source.XML: <DOC> <AAA> <STUFF>example</STUFF> <OBJ> <OBJVERS id="A1" CREATED="2008-02-18T13:28:08.245Z"/> <OBJVERS id="A2" CREATED="2008-02-19T10:42:41.965Z"/> <OBJVERS id="A13" CREATED="2009-03-16T12:43:11.703Z"/> </OBJ> </AAA> <FFF/> <GGG/> <DDD> <FILE /> </DDD> </DOC> Which I need to look something like this (Target.XML): <MYOBJ> <ELEM>contents of OBJVERS with the biggest id OR creation date (whichever is easier to do) go here</ELEM> <IMAGE> contents of <FILE> node go here</IMAGE> </MYOBJ> The main problem that I have is that since I am new to XSL (and for this particular task do not have enough time to learn it properly) is that I can't understand how to tell XSL processor not to process anything else, I keep getting output from , for example. Update: basically, I solved this problem meanwhile. I will post my own answer and close the question. Update2: OK, Andrew's answer works, too, so I am just accepting it. :)

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  • Parsing back to 'messy' API strcuture

    - by Eric Fail
    I'm fetching data from an online database (REDcap) via API and the data gets delivered in as comma separated string like this, RAW.API <- structure("id,event_arm,name,dob,pushed_text,pushed_calc,complete\n\"01\",\"event_1_arm_1\",\"John\",\"1979-05-01\",\"\",\"\",2\n\"01\",\"event_2_arm_1\",\"John\",\"2012-09-02\",\"abc\",\"123\",1\n\"01\",\"event_3_arm_1\",\"John\",\"2012-09-10\",\"\",\"\",2\n\"02\",\"event_1_arm_1\",\"Mary\",\"1951-09-10\",\"def\",\"456\",2\n\"02\",\"event_2_arm_1\",\"Mary\",\"1978-09-12\",\"\",\"\",2\n", "`Content-Type`" = structure(c("text/html", "utf-8"), .Names = c("", "charset"))) I have this script that nicely parses it into a data frame, (df <- read.table(file = textConnection(RAW.API), header = TRUE, sep = ",", na.strings = "", stringsAsFactors = FALSE)) id event_arm name dob pushed_text pushed_calc complete 1 1 event_1_arm_1 John 1979-05-01 <NA> NA 2 2 1 event_2_arm_1 John 2012-09-02 abc 123 1 3 1 event_3_arm_1 John 2012-09-10 <NA> NA 2 4 2 event_1_arm_1 Mary 1951-09-10 def 456 2 5 2 event_2_arm_1 Mary 1978-09-12 <NA> NA 2 I then do some calculations and write them to pushed_text and pushed_calc whereafter I need to format the data back to the messy comma separated structure it came in. I imagine something like this, API.back <- `some magic command`(df, ...) identical(RAW.API, API.back) [1] TRUE Some command that can format my data from the data frame I made, df, back to the structure that the raw API-object came in, RAW.API. Any help would be very appreciated.

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  • Why would I be seeing execution timeouts when setting $_SESSION values?

    - by Kev
    I'm seeing the following errors in my PHP error logs: PHP Fatal error: Maximum execution time of 60 seconds exceeded in D:\sites\s105504\www\index.php on line 3 PHP Fatal error: Maximum execution time of 60 seconds exceeded in D:\sites\s105504\www\search.php on line 4 The lines in question are: index.php: 01 <?php 02 session_start(); 03 ob_start(); 04 error_reporting(E_All); 05 $_SESSION['nav'] = "range"; // <-- Error generated here search.php 01 <?php 02 03 session_start(); 04 $_SESSION['nav'] = "range"; 05 $_SESSION['navselected'] = 21; // <-- Error generated here Would it really take as long as 60+ seconds to assign a $_SESSION[] value? The platform is: Windows 2003 SP2 + IIS6 FastCGI for Windows 2003 (original RTM build) PHP 5.2.6 Non thread-safe build There aren't any issues with session data files being cleared up on the server as sessions expire. The oldest sess_XXXXXXXXXXXXXX file I'm seeing is around 2 hours old. There are no disk timeouts evident in the event logs or other such disk health issues that might suggest difficulty creating session data files. The site is also on a server that isn't under heavy load. The site is busy but not being hammered and is very responsive. It's just that we get these errors, three or four in a row, every three or four hours. I should also add that I'm not the original developer of this code and that it belongs to a customer who's developer has long since departed.

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  • Trouble with applying a nested loop on a list

    - by user1665355
    I have a list consisting of 3 elements: datalist=list(a=datanew1,b=datanew2,c=datanew3) datalist$a : Inv_ret Firm size leverage Risk Liquidity Equity 17 0.04555968 17.34834 0.1323199 0.011292273 0.02471489 0 48 0.01405835 15.86315 0.6931730 0.002491093 0.12054914 0 109 0.04556252 16.91602 0.1714068 0.006235836 0.01194579 0 159 0.04753472 14.77039 0.3885720 0.007126830 0.06373028 0 301 0.03941040 16.94377 0.1805346 0.005450653 0.01723319 0 datalist$b : Inv_ret Firm size leverage Risk Liquidity Equity 31 0.04020832 18.13300 0.09326265 0.015235240 0.01579559 0.005025379 62 0.04439078 17.84086 0.11016402 0.005486982 0.01266566 0.006559096 123 0.04543250 18.00517 0.12215307 0.011154742 0.01531451 0.002282790 173 0.03960613 16.45457 0.10828643 0.011506857 0.02385191 0.009003780 180 0.03139643 17.57671 0.40063094 0.003447233 0.04530395 0.000000000 datalist$c : Inv_ret Firm size leverage Risk Liquidity Equity 92 0.03081029 19.25359 0.10513159 0.01635201 0.025760806 0.000119744 153 0.03280746 19.90229 0.11731517 0.01443786 0.006769735 0.011999005 210 0.04655847 20.12543 0.11622403 0.01418010 0.003125632 0.003802365 250 0.03301018 20.67197 0.13208234 0.01262499 0.009418828 0.021400052 282 0.04355975 20.03012 0.08588316 0.01918129 0.004213846 0.023657440 I am trying to create a cor.test on the datalist above : Cor.tests=sapply(datalist,function(x){ for(h in 1:length(names(x))){ for(i in 1:length(names(x$h[i]))){ for(j in 1:length(names(x$h[j]))){ cor.test(x$h[,i],x$h[,j])$p.value }}}}) But I get an error : Error in cor.test.default(x$h[, i], x$h[, j]) : 'x' must be a numeric vector Any suggestions about what I am doing wrong? P.S. If I simply have one dataframe, datanew1 : Inv_ret Firm size leverage Risk Liquidity Equity 17 0.04555968 17.34834 0.1323199 0.011292273 0.02471489 0 48 0.01405835 15.86315 0.6931730 0.002491093 0.12054914 0 109 0.04556252 16.91602 0.1714068 0.006235836 0.01194579 0 159 0.04753472 14.77039 0.3885720 0.007126830 0.06373028 0 301 0.03941040 16.94377 0.1805346 0.005450653 0.01723319 0 I use this loop : results=matrix(NA,nrow=6,ncol=6) for(i in 1:length(names(datanew1))){ for(j in 1:length(names(datanew1))){ results[i,j]<-cor.test(datanew1[,i],datanew1[,j])$p.value }} And the output is: results : [,1] [,2] [,3] [,4] [,5] [,6] [1,] 0.000000e+00 7.085663e-09 3.128975e-10 3.018239e-02 4.806400e-10 0.475139526 [2,] 7.085663e-09 0.000000e+00 2.141581e-21 0.000000e+00 2.247825e-20 0.454032499 [3,] 3.128975e-10 2.141581e-21 0.000000e+00 2.485924e-25 2.220446e-16 0.108643838 [4,] 3.018239e-02 0.000000e+00 2.485924e-25 0.000000e+00 5.870007e-15 0.006783324 [5,] 4.806400e-10 2.247825e-20 2.220446e-16 5.870007e-15 0.000000e+00 0.558827862 [6,] 4.751395e-01 4.540325e-01 1.086438e-01 6.783324e-03 5.588279e-01 0.000000000 Which is exactly what I want. But I want to get 3 matrices, one for each element of the datalist above.

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  • converting numbers into alphabets.

    - by Nina
    Hi! i want to convert number into alphabets using javascript e.g. 01=n, 02=i 03=n,04=a and when someone enters the numbers:01020304 in the form he will get like this: nina. or whatever he enters it get replace with equivalent alphabets including spaces. i will be really thankful if you can provide full code including html form code as i am beginner. Thank you all for quick response. I have found this code in one site it converts alphabets into numbers, but code for converting numbers into alphabets isn't working. here is a code for converting alphabets into numbers: var i,j; var getc; var len; var num,alpha; num=new Array("01","02","03","04","05","06","07","08","09","10","11","12","13","14","15","16","17", "18","19","20","21","22","23","24","25","26","00","##","$$"); alpha=new Array("a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u"," v","w","x","y","z"," ",".",","); function encode() { len=document.f1.ta1.value.length; document.f1.ta2.value=""; for(i=0;i

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  • curl not returning content length header

    - by Michael P. Shipley
    Trying to get image file size using curl but content length header is not returned: $url ="http://www.collegefashion.net/wp-content/plugins/feed-comments-number/image.php?1263"; $fp = curl_init(); curl_setopt($fp, CURLOPT_NOBODY, true); curl_setopt($fp, CURLOPT_RETURNTRANSFER, 1); curl_setopt($fp, CURLOPT_FAILONERROR,1); curl_setopt($fp, CURLOPT_REFERER,''); curl_setopt($fp, CURLOPT_URL, $url); curl_setopt($fp, CURLOPT_HEADER,1); curl_setopt($fp, CURLOPT_USERAGENT,'Mozilla/5.0'); $body = curl_exec($fp); var_dump($body): HTTP/1.1 200 OK Date: Sun, 02 May 2010 02:50:20 GMT Server: Apache/2.0.63 (CentOS) X-Powered-By: W3 Total Cache/0.8.5.2 X-Pingback: http://www.collegefashion.net/xmlrpc.php Cache-Control: no-cache, must-revalidate Expires: Sat, 26 Jul 1997 05:00:00 GMT Content-Type: image/png It works via ssh though: curl -i http://www.collegefashion.net/wp-content/plugins/feed-comments-number/image.php?1263 HTTP/1.1 200 OK Date: Sun, 02 May 2010 03:38:43 GMT Server: Apache/2.0.63 (CentOS) X-Powered-By: W3 Total Cache/0.8.5.2 X-Pingback: http://www.collegefashion.net/xmlrpc.php Cache-Control: no-cache, must-revalidate Expires: Sat, 26 Jul 1997 05:00:00 GMT Content-Length: 347 Content-Type: image/png

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  • Parsing data with Clojure, interval problem.

    - by Andrea Di Persio
    Hello! I'm writing a little parser in clojure for learning purpose. basically is a TSV file parser that need to be put in a database, but I added a complication. The complication itself is that in the same file there are more intervals. The file look like this: ###andreadipersio 2010-03-19 16:10:00### USER COMM PID PPID %CPU %MEM TIME root launchd 1 0 0.0 0.0 2:46.97 root DirectoryService 11 1 0.0 0.2 0:34.59 root notifyd 12 1 0.0 0.0 0:20.83 root diskarbitrationd 13 1 0.0 0.0 0:02.84` .... ###andreadipersio 2010-03-19 16:20:00### USER COMM PID PPID %CPU %MEM TIME root launchd 1 0 0.0 0.0 2:46.97 root DirectoryService 11 1 0.0 0.2 0:34.59 root notifyd 12 1 0.0 0.0 0:20.83 root diskarbitrationd 13 1 0.0 0.0 0:02.84 I ended up with this code: (defn is-header? "Return true if a line is header" [line] (> (count (re-find #"^\#{3}" line)) 0)) (defn extract-fields "Return regex matches" [line pattern] (rest (re-find pattern line))) (defn process-lines [lines] (map process-line lines)) (defn process-line [line] (if (is-header? line) (extract-fields line header-pattern)) (extract-fields line data-pattern)) My idea is that in 'process-line' interval need to be merged with data so I have something like this: ('andreadipersio', '2010-03-19', '16:10:00', 'root', 'launchd', 1, 0, 0.0, 0.0, '2:46.97') for every row till the next interval, but I can't figure how to make this happen. I tried with something like this: (def process-line [line] (if is-header? line) (def header-data (extract-fields line header-pattern))) (cons header-data (extract-fields line data-pattern))) But this doesn't work as excepted. Any hints? Thanks!

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  • Encoding/Decoding hex packet

    - by Roberto Pulvirenti
    I want to send this hex packet: 00 38 60 dc 00 00 04 33 30 3c 00 00 00 20 63 62 39 62 33 61 36 37 34 64 31 36 66 32 31 39 30 64 30 34 30 63 30 39 32 66 34 66 38 38 32 62 00 06 35 2e 31 33 2e 31 00 00 02 3c so i build the string: string packet = "003860dc0000" + textbox1.text+ "00000020" + textbox2.text+ "0006" + textbox3.text; then "convert" it to ascii: conn_str = HexString2Ascii(packet); then i send the packet... but i have this: 00 38 60 **c3 9c** 00 00 04 33 30 3c 00 00 00 20 63 62 39 62 33 61 36 37 34 64 31 36 66 32 31 39 30 64 30 34 30 63 30 39 32 66 34 66 38 38 32 62 00 06 35 2e 31 33 2e 31 00 00 02 3c **0a** why?? Thank you! P.S. the function is: private string HexString2Ascii(string hexString) { byte[] tmp; int j = 0; int lenght; lenght=hexString.Length-2; tmp = new byte[(hexString.Length)/2]; for (int i = 0; i <= lenght; i += 2) { tmp[j] =(byte)Convert.ToChar(Int32.Parse(hexString.Substring(i, 2), System.Globalization.NumberStyles.HexNumber)); j++; } return Encoding.GetEncoding(1252).GetString(tmp); }

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  • Returning an array of culture formatted dates C# MVC3

    - by user1875797
    I'm new to programming and trying to do an exercise that formats a date to the Thai culture in a variety of formats this is what I have for my code so far: public String[] FormatAsSpecified(DateTime theDate, String theCulture, String[] formats) { String[] dateResults = new String[formats.Length]; CultureInfo culture = CultureInfo.GetCultureInfo(theCulture); for (int i = 0; i < formats.Length; i++) { String culture_formatted_date = theDate.ToString(formats[i], culture); dateResults[i] = culture_formatted_date; } return dateResults; } This is the test method that goes with it: [TestMethod] public void FormatAsSpecifiedReturnsDateLiteralsInSpecifiedFormatForAllStandardFormatStrings() { //Arrange var controller = new DateController(); var theDate = new DateTime(2014, 2, 14, 9, 15, 32, 376); String theCulture = "th-TH"; // Array of all supported standard date and time format specifiers. String[] formats = { "d", "D", "f", "F", "g", "G", "m", "o", "r", "s", "t", "T", "u", "U", "Y" }; //Corresponding date literals for the standard Thai regional settings String[] expectedResults = {"14/2/2557" , "14 ?????????? 2557" , "14 ?????????? 2557 9:15" , "14 ?????????? 2557 9:15:32" , "14/2/2557 9:15" , "14/2/2557 9:15:32" , "14 ??????????" , "2014-02-14T09:15:32.3760000" , "Fri, 14 Feb 2014 09:15:32 GMT" , "2014-02-14T09:15:32" , "9:15" , "9:15:32" , "2014-02-14 09:15:32Z" , "??????????? 14 ?????????? 2014 9:15:32" , "?????????? 2557"}; //Act String[] actualResults = new String[15]; for (int i = 0; i < formats.Length; i++) { actualResults[i] = controller.FormatAsSpecified(theDate, theCulture, formats[i]); } //Assert CollectionAssert.AreEqual(expectedResults, actualResults); } I get an error in the test method at 'controller.FormatAsSpecified(theDate, theCulture, formats[i]);' that says "Argument 3, cannot convert from 'string' to 'string[]'" What am I doing wrong?

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  • How to get the second sub element of every element in a list in R

    - by PaulHurleyuk
    I know I've come across this problem before, but I'm having a bit of a mental block at the moment. and as I can't find it on SO, I'll post it here so I can find it next time. I have a dataframe that contains a field representing an ID label. This label has two parts, an alpha prefix and a numeric suffix. I want to split it apart and create two new fields with these values in. structure(list(lab = c("N00", "N01", "N02", "B00", "B01", "B02", "Z21", "BA01", "NA03")), .Names = "lab", row.names = c(NA, -9L ), class = "data.frame") df$pre<-strsplit(df$lab, "[0-9]+") df$suf<-strsplit(df$lab, "[A-Z]+") Which gives lab pre suf 1 N00 N , 00 2 N01 N , 01 3 N02 N , 02 4 B00 B , 00 5 B01 B , 01 6 B02 B , 02 7 Z21 Z , 21 8 BA01 BA , 01 9 NA03 NA , 03 So, the first strsplit works fine, but the second gives a list, each having two elements, an empty string and the result I want, and stuffs them both into the dataframe column. How can I select the second sub-element from each element of the list ? (or, is there a better way to do this) Thanks Paul.

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  • Rails 3 Timezone error

    - by Juan
    I am struggling with time zone support in Rails 3 beta and I would like to know if it is a bug or if I am doing something wrong. He is the problem: > Time.zone = 'Madrid' # it is GMT+2 = "Madrid" > c = Comment.new = #<Comment id: nil, title: "", pub_at: nil> > c.pub_at = Time.zone.parse('10:00:00') = Mon, 31 May 2010 10:00:00 CEST +02:00 > c.save > c = #<Comment id: 3, title: "", pub_at: "2010-05-31 08:00:00"> > c.reload = #<Comment id: 3, title: "", pub_at: "2010-05-31 08:00:00"> ruby-1.8.7-p249 c.pub_at = Mon, 31 May 2010 13:00:00 CEST +02:00 As you can see, the pub_at attribute is stored correctly in the database but when it is retrieved it adds 3 hours and I suspect that it is because it is using my local machine timezone that is in GMT-3. The same sequence of commands in rails 2.3.5 works perfectly. Any toughts? Should I report a ticket?

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  • How to link jQuery UI datepicker functionality with a select list

    - by take2
    I'm trying to connect jQuery UI's datepicker with a select list. I have found one explanation on jQuery's Forum ( forum.jquery.com/topic/jquery-ui-datepicker-with-select-lists), but I can't get it working. There are input and select list both declared: <select id="selectMonth"><option value="01">Jan</option><option value="02">Feb</option> <option value="03">Mar</option><option value="04">Apr</option>...</select> <select id="selectDay"><option value="01">1</option><option value="02">2</option> <option value="03">3</option><option value="04">4</option>...</select> <select id="selectYear"><option value="2012">2012</option><option value="2013">2013</option> <option value="2014">2014</option>...</select> <p>Date: <input type="text" id="selectedDatepicker" /></p> This is the script: $(function() { $('#selectedDatepicker').datepicker({ beforeShow: readSelected, onSelect: updateSelected, minDate: new Date(2012, 1 - 1, 1), maxDate: new Date(2014, 12 - 1, 31), showOn: 'both', buttonImageOnly: true, buttonImage: 'img/calendar.gif'}); // Prepare to show a date picker linked to three select controls function readSelected() { $('#selectedDatepicker').val($('#selectMonth').val() + '/' + $('#selectDay').val() + '/' + $('#selectYear').val()); return {}; } // Update three select controls to match a date picker selection function updateSelected(date) { $('#selectMonth').val(date.substring(0, 2)); $('#selectDay').val(date.substring(3, 5)); $('#selectYear').val(date.substring(6, 10)); } }); And here is the fiddle: http://jsfiddle.net/xKXZm/ They are not connected properly, the only "connected behaviour" is that when you click on the input button, it picks up the value of the select list. On the other hand, the select list never picks up the value of the input nor will the input pick up the value of the select list until you click on it.

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  • Mule ESB 3.2 Splitter destroys Enricher results

    - by Eddie
    Here is the snippet of my flow: <logger message="PRODUCT_ID = #[header:productID]" level="INFO" doc:name="Logger"/> <splitter evaluator="jxpath" expression="//*/BisacHeaderCodes" doc:name="Splitter"/> <logger message="PRODUCT_ID_POST_SPLITTER = #[header:productID]" level="INFO" doc:name="Logger"/> #[header:productID] was set up prior to Logger call. I tried #[variable:productID] and got the same result. When I run it, this is the out put I get: INFO 2012-04-05 23:12:47,865 [[bookinista_order_management].connector.http.mule.default.receiver.02] org.mule.api.processor.LoggerMessageProcessor: PRODUCT_ID = 72 ERROR 2012-04-05 23:12:47,871 [[bookinista_order_management].connector.http.mule.default.receiver.02] org.mule.exception.DefaultSystemExceptionStrategy: Caught exception in Exception Strategy: Expression Evaluator "header" with expression "outbound:productID" returned null but a value was required. org.mule.api.expression.RequiredValueException: Expression Evaluator "header" with expression "outbound:productID" returned null but a value was required. So, right before Splitter, I have a perfect value in my header, and right after Splitter, that value disappears! I understand that Splitter propagates only part of payloda, but shouldn't it leave headers and variables alone? Any ideas for a workaround?

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