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  • XML Schema - how do you conditionally require address elements? (street, city, state, etc)

    - by Sly
    If an address can be composed of child elements: Street, City, State, PostalCode...how do you allow this XML: <Address> <Street>Somestreet</Street> <PostalCode>zip</PostalCode> </Address> and allow this: <Address> <Street>Somestreet</Street> <City>San Jose</City> <State>CA</State> </Address> but not this: <Address> <Street>Somestreet</Street> <City>San Jose</City> </Address> What schema will do such things!?

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  • Web.xml: Are url-pattern tags relative to each other?

    - by sixtyfootersdude
    <servlet-mapping> <servlet-name>myName</servlet-name> <url-pattern>/aName</url-pattern> </servlet-mapping> <security-constraint> <web-resource-collection> ... <url-pattern> /* </url-pattern> </web-resource-collection> ... </security-constraint> This is an excerpt from web.xml (using it to configure a jboss/tomcat webservice). Just wondering if the url-pattern in web-resource-collection is relative to the url-pattern in servlet-mapping.

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  • How could I do something like this in a XML schema?

    - by chobo2
    Hi I want to mass create some users and I want to set the users timezone automatically. However I am using timezones generated by this Dictionary<string, TimeZoneInfo> storeZoneName = TimeZoneInfo.GetSystemTimeZones().ToDictionary(z => z.DisplayName); So I need the names to be exactly like the ones this list returns. So can I put like a constraint on that xml node that the name has to exactly match one of the names. So I am guessing I will need to write this list somewhere in the file and that's what I am not sure if you can do something like that in a schema.

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  • Web.xml: Are url-pattern tags relitive to each other?

    - by sixtyfootersdude
    <servlet-mapping> <servlet-name>myName</servlet-name> <url-pattern>/aName</url-pattern> </servlet-mapping> <security-constraint> <web-resource-collection> ... <url-pattern> /* </url-pattern> </web-resource-collection> ... </security-constraint> This is an excerpt from web.xml (using it to configure a jboss/tomcat webservice). Just wondering if the url-pattern in web-resource-collection is relative to the url-pattern in servlet-mapping.

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  • Hibernate: Dirty Checking and Only Update of Dirty Attributes?

    - by jens
    Hello Experts, in "good old JDBC days" I wrote a lot of SQL Queries that did very targeted updates of only the "attributes/members" that were actually changed: For Example having an object with the following members: public String name; public String address; public Date date; If only date was changed in some Business Method I would only issue an SQL UPDATE for the date member. ==It seems however (thats my "impression" of hibernate) that when working with a standard Hibernate mapping (mapping the full class), even updates of only one single member lead to a full update of the object in SQL Statements generated by Hibernate. My Questions are: 1.) Is this observation correct, that hibernate DOES NOT intelligently check (in a fully mapped class), what member(s) where changed and then only issue updates for the specific changed members, but rather always will update (in the generated SQL Update Statement) all mapped members (of a class), even if they were not changed (in case the object is dirty due to one member being dirty...) 2.) What can I do to make Hibernate only update those members, that have been changed? I am searching for a solution to have hibernate only update the member that actually changed. (I know hibernate does some big work on doing dirty-checking, but as far as I know this dirtychecking is only relevant to identify if the object as whole is dirty, not what single member is dirty.) Thank you very much! Jens

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  • Hibernate - how to delete bidirectional many-to-many association

    - by slomir
    Problem: I have many-to-many association between two entities A and B. I set A entity as an owner of their relationship(inverse=true is on A's collection in b.hbm.xml). When i delete an A entity, corresponding records in join table are deleted. When i delete an B entity, corresponding records in join table are not deleted (integrity violation exception). -- Let's consider some very simple example: class A{ Set<B> bset=new HashSet<B>(); //... } class B{ Set<A> aset=new HashSet<A>(); //... } File a.hbm.xml [m-to-m mappings only]: <set name="bset" table="AB"> <key name="a_id"/> <many-to-many column="b_id" class="B"/> </set> File b.hbm.xml [m-to-m mappings only]: <set name="aset" table="AB" inverse="true"> <key name="b_id"/> <many-to-many column="a_id" class="A"/> </set> Database relations: A(id,...) B(id,...) AB(a_id,b_id) Suppose that we have some records in AB joint table. For example: AB = {(1,1),(1,2)} where AB= { (a_id , b_id) | ... ... } -- Situation 1 - works probably because A is owner of AB relationship: A a=aDao.read(1); //read A entity with id=1 aDao.delete(a); //delete 'a' entity and both relations with B-entities Situation 2 - doesn't work: B b=bDao.read(1); //read B entity with id=1 bDao.delete(b); //foreign key integrity violation On the one hand, this is somehow logical to me, because the A entity is responsible for his relation with B. But, on the other hand, it is not logical or at least it is not orm-like solution that I have to explicitly delete all records in join table where concrete B entity appears, and then to delete the B entity, as I show in situation 3: Situation 3 - works, but it is not 'elegant': B b=bDao.read(1); Set<A> aset=b.getA(); //get set with A entities Iterator i=aset.iterator(); //while removes 'b' from all related A entities //while breaks relationships on A-side of relation (A is owner) while(i.hasNext()){ A a=i.next(); a.bset.remove(b); //remove entity 'b' from related 'a' entity aDao.update(a); //key point!!! this line breaks relation in database } bDao.delete(b); //'b' is deleted because there is no related A-entities -- So, my question: is there any more convenient way to delete no-owner entity (B in my example) in bidirectional many-to-many association and all of his many-to-many relations from joint table?

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  • how to filter data from xml file for displaying only selected as nodes in treeview

    - by michale
    I have an xml file named "books.xml" provided in the link "http://msdn.microsoft.com/en-us/library/windows/desktop/ms762271(v=vs.85).aspx". What my requirement was to disaplay only the <title> from xml information as nodes in tree view. But when i did the following coding its displaying all the values as nodes like "catalog" as rootnode, book as parent node for all then author,title,genre etc as nodes but i want only root node catalogue and title as nodes not even book. Can any body guide me what modification i need to do in the exisitng logic for displaying title as nodes OpenFileDialog dlg = new OpenFileDialog(); dlg.Title = "Open XML document"; dlg.Filter = "XML Files (*.xml)|*.xml"; dlg.FileName = Application.StartupPath + "\\..\\..\\Sample.xml"; if (dlg.ShowDialog() == DialogResult.OK) { try { //Just a good practice -- change the cursor to a //wait cursor while the nodes populate this.Cursor = Cursors.WaitCursor; //First, we'll load the Xml document XmlDocument xDoc = new XmlDocument(); xDoc.Load(dlg.FileName); //Now, clear out the treeview, //and add the first (root) node treeView1.Nodes.Clear(); treeView1.Nodes.Add(new TreeNode(xDoc.DocumentElement.Name)); TreeNode tNode = new TreeNode(); tNode = (TreeNode)treeView1.Nodes[0]; //We make a call to addTreeNode, //where we'll add all of our nodes addTreeNode(xDoc.DocumentElement, tNode); //Expand the treeview to show all nodes treeView1.ExpandAll(); } catch (XmlException xExc) //Exception is thrown is there is an error in the Xml { MessageBox.Show(xExc.Message); } catch (Exception ex) //General exception { MessageBox.Show(ex.Message); } finally { this.Cursor = Cursors.Default; //Change the cursor back } }} //This function is called recursively until all nodes are loaded private void addTreeNode(XmlNode xmlNode, TreeNode treeNode) { XmlNode xNode; TreeNode tNode; XmlNodeList xNodeList; if (xmlNode.HasChildNodes) //The current node has children { xNodeList = xmlNode.ChildNodes; for (int x = 0; x <= xNodeList.Count - 1; x++) //Loop through the child nodes { xNode = xmlNode.ChildNodes[x]; treeNode.Nodes.Add(new TreeNode(xNode.Name)); tNode = treeNode.Nodes[x]; addTreeNode(xNode, tNode); } } else //No children, so add the outer xml (trimming off whitespace) treeNode.Text = xmlNode.OuterXml.Trim(); }

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  • How can I create the XML::Simple data structure using a Perl XML SAX parser?

    - by DVK
    Summary: I am looking a fast XML parser (most likely a wrapper around some standard SAX parser) which will produce per-record data structure 100% identical to those produced by XML::Simple. Details: We have a large code infrastructure which depends on processing records one-by-one and expects the record to be a data structure in a format produced by XML::Simple since it always used XML::Simple since early Jurassic era. An example simple XML is: <root> <rec><f1>v1</f1><f2>v2</f2></rec> <rec><f1>v1b</f1><f2>v2b</f2></rec> <rec><f1>v1c</f1><f2>v2c</f2></rec> </root> And example rough code is: sub process_record { my ($obj, $record_hash) = @_; # do_stuff } my $records = XML::Simple->XMLin(@args)->{root}; foreach my $record (@$records) { $obj->process_record($record) }; As everyone knows XML::Simple is, well, simple. And more importantly, it is very slow and a memory hog—due to being a DOM parser and needing to build/store 100% of data in memory. So, it's not the best tool for parsing an XML file consisting of large amount of small records record-by-record. However, re-writing the entire code (which consist of large amount of "process_record"-like methods) to work with standard SAX parser seems like an big task not worth the resources, even at the cost of living with XML::Simple. I'm looking for an existing module which will probably be based on a SAX parser (or anything fast with small memory footprint) which can be used to produce $record hashrefs one by one based on the XML pictured above that can be passed to $obj->process_record($record) and be 100% identical to what XML::Simple's hashrefs would have been. I don't care much what the interface of the new module is; e.g whether I need to call next_record() or give it a callback coderef accepting a record.

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  • XML pass values to timer, AS3

    - by VideoDnd
    My timer has three variables that I can trace to the output window, but don't know how to pass them to the timer. How to I pass the XML values to my timer? Purpose I want to test with an XML document, before I try connecting it to an XML socket. myXML <?xml version="1.0" encoding="utf-8"?> <SESSION> <TIMER TITLE="speed">100</TIMER> <COUNT TITLE="starting position">-77777</COUNT> <FCOUNT TITLE="ramp">1000</FCOUNT> </SESSION> myFlash //myTimer 'instance of mytext on stage' /* fields I want to change with XML */ //CHANGE TO 100 var timer:Timer = new Timer(10); //CHANGE TO -77777 var count:int = 0; //CHANGE TO 1000 var fcount:int = 0; timer.addEventListener(TimerEvent.TIMER, incrementCounter); timer.start(); function incrementCounter(event:TimerEvent) { count++; fcount=int(count*count/1000);//starts out slow... then speeds up mytext.text = formatCount(fcount); } function formatCount(i:int):String { var fraction:int = i % 100; var whole:int = i / 100; return ("0000000" + whole).substr(-7, 7) + "." + (fraction < 10 ? "0" + fraction : fraction); } //LOAD XML var myXML:XML; var myLoader:URLLoader = new URLLoader(); myLoader.load(new URLRequest("time.xml")); myLoader.addEventListener(Event.COMPLETE, processXML); //PARSE XML function processXML(e:Event):void { myXML = new XML(e.target.data); trace(myXML.ROGUE.*); trace(myXML); //TEXT var text:TextField = new TextField(); text.text = myXML.TIMER.*; text.textColor = 0xFF0000; addChild(text); } RESOURCES OReilly's ActionScript 3.0 Cookbook, Chapter 12 Strings, Chapter 20 XML

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  • can not access http://localhost/phpmyadmin/

    - by nik parsa
    I installed wamp server2 it didn't have password and it had this error below then I went to mysql and set the password for root with this command and I can login using this password but again I can not access phpmyadmin.I restarted the services too. update user.mysql set password=password('root') where user='root'; then i went to config.inc changed the pass to this one: $cfg['Servers'][$i]['password'] = 'root'; again I restarted and again no result. the phpmyadmin page: Welcome to phpMyAdmin Error MySQL said: Documentation #1045 - Access denied for user 'root'@'localhost' (using password: NO) phpMyAdmin tried to connect to the MySQL server, and the server rejected the connection. You should check the host, username and password in your configuration and make sure that they correspond to the information given by the administrator of the MySQL server. config.inc: <?php /* Servers configuration */ $i = 0; /* Server: localhost [1] */ $i++; $cfg['Servers'][$i]['verbose'] = 'localhost'; $cfg['Servers'][$i]['host'] = 'localhost'; $cfg['Servers'][$i]['port'] = ''; $cfg['Servers'][$i]['socket'] = ''; $cfg['Servers'][$i]['connect_type'] = 'tcp'; $cfg['Servers'][$i]['extension'] = 'mysqli'; $cfg['Servers'][$i]['auth_type'] = 'config'; $cfg['Servers'][$i]['user'] = 'root'; $cfg['Servers'][$i]['password'] = 'root'; $cfg['Servers'][$i]['AllowNoPassword'] = true; /* End of servers configuration */ $cfg['DefaultLang'] = 'en-utf-8'; $cfg['ServerDefault'] = 1; $cfg['UploadDir'] = ''; $cfg['SaveDir'] = ''; /* rajk - for blobstreaming */ $cfg['Servers'][$i]['bs_garbage_threshold'] = 50; $cfg['Servers'][$i]['bs_repository_threshold'] = '32M'; $cfg['Servers'][$i]['bs_temp_blob_timeout'] = 600; $cfg['Servers'][$i]['bs_temp_log_threshold'] = '32M'; ?> It was firstly this line $cfg['Servers'][$i]['password'] = ''; setting allow to false and restarting will not change the error either with the help of Erika I understood that it can't read confg.inc file how to make it read from this file?

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  • Single Table Per Class Hierarchy with an abstract superclass using Hibernate Annotations

    - by Andy Hull
    I have a simple class hierarchy, similar to the following: @Entity @Table(name="animal") @Inheritance(strategy=InheritanceType.SINGLE_TABLE) @DiscriminatorColumn(name="animal_type", discriminatorType=DiscriminatorType.STRING) public abstract class Animal { } @Entity @DiscriminatorValue("cat") public class Cat extends Animal { } @Entity @DiscriminatorValue("dog") public class Dog extends Animal { } When I query "from Animal" I get this exception: "org.hibernate.InstantiationException: Cannot instantiate abstract class or interface: Animal" If I make Animal concrete, and add a dummy discriminator... such as @DiscriminatorValue("animal")... my query returns my cats and dogs as instances of Animals. I remember this being trivial with HBM based mappings but I think I'm missing something when using annotations. Can anyone help? Thanks!

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  • Detach an entity from a JPA persistence context (JPA 2.0 / Hibernate / EJB 3 / J2EE 6)

    - by Julien
    Hi, I wrote a stateless EJB method allowing to get an entity in "read-only" mode. The way to do this is to get the entity with the EntityManager then detach it (using the JPA 2.0 EntityManager). My code is the following: @PersistenceContext private EntityManager entityManager; public T getEntity(int entityId, Class<T> specificClass, boolean readOnly) throws Exception{ try{ T entity = (T)entityManager.find(specificClass, entityId); if (readOnly){ entityManager.detach(entity); } return entity; }catch (Exception e){ logger.error("", e); throw e; } } Getting the entity works fine, but the call to the detach method returns the following error: GRAVE: javax.ejb.EJBException at ... Caused by: java.lang.AbstractMethodError: org.hibernate.ejb.EntityManagerImpl.detach(Ljava/lang/Object;)V at com.sun.enterprise.container.common.impl.EntityManagerWrapper.detach(EntityManagerWrapper.java:973) at com.mycomp.dal.MyEJB.getEntity(MyEJB.java:37) I can't get more information and don't understand what the problem is... Could somebody help ?

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  • JPA/Hibernate and MySQL transaction isolation level

    - by armandino
    I have a native query that does a batch insert into a MySQL database: String sql = "insert into t1 (a, b) select x, y from t2 where x = 'foo'"; EntityTransaction tx = entityManager.getTransaction(); try { tx.begin(); int rowCount = entityManager.createNativeQuery(sql).executeUpdate(); tx.commit(); return rowCount; } catch(Exception ex) { tx.rollback(); log.error(...); } This query causes a deadlock: while it reads from t2 with insert .. select, another process tries to insert a row into t2. I don't care about the consistency of reads from t2 when doing an insert .. select and want to set the transaction isolation level to READ_UNCOMMITTED. How do I go about setting it in JPA backed by Hibernate?

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  • org.hibernate.MappingException: No Dialect mapping for JDBC type: 2002

    - by Moli
    Hi at all, I'm having a issue trying to get working a JPA nativeQuery. I'm having a org.hibernate.MappingException: No Dialect mapping for JDBC type: 2002 when a try to do a nativeQuery and get a geometry field type. I use oracle and org.hibernatespatial.oracle.OracleSpatial10gDialect. The geom fields is mapped as: @Column(name="geometry") @Type(type = "org.hibernatespatial.GeometryUserType") private Geometry geometry; List<Object> listFeatures= new LinkedList<Object>(); Query query= entityManager.createNativeQuery( "SELECT "+ slots +" , geometry FROM edtem_features feature, edtem_dades dada WHERE" + " feature."+ tematic.getIdGeomField() +" = dada."+ tematic.getIdDataField()+ " AND dada.capesid= "+ tematic.getCapa().getId() + " AND feature.geometriesid= "+ tematic.getGeometria().getId()); listFeatures.addAll( query.getResultList()); Anybody knows a solution? or how to force the type of the geometry to get wroking this... MANY Thanks in advance. Moli

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  • [hibernate - jpa ] good practices and bad practices

    - by blow
    Hi all, i have some questions about interaction with hibernate. openSession or getCurrentSession (without jta, thread insted)? How mix session operations with swing gui? Is good have something like this in a javabean class? public void actionPerformed(ActionEvent event) { // session code } Can i add methods to my entities that contains hql queries or is a bad practice? For example: // This method is in an entity MyOtherEntity.java class public int getDuration(){ Session session=HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); int sum=(Integer)session.createQuery("select sum(e.duration) as duration from MyEntity as e where e.myOtherEntity.id=:id group by e.name"). .setLong("id", getId()); .uniqueResult(); return sum; } In alternative how can i do this in a better and elegant way? Thanks.

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  • How to configure hbm2java and hbm2dao to add packagename to generated classes

    - by mmm
    Hi, I'm trying to configure hbm2java with maven to generate POJO classes and DAO objects. One of the issues I'm dealing with is package names aren't generated. I'm using the following pom for that: <execution> <id>hbm2java</id> <phase>generate-sources</phase> <goals> <goal>hbm2java</goal> </goals> <inherited>false</inherited> <configuration> <components> <component> <name>hbm2java</name> <implementation>configuration</implementation> </component> </components> <componentProperties> <packagename>package.name</packagename> <configurationfile>target/hibernate3/generated-mappings/hibernane.cfg.xml</configurationfile> </componentProperties> </configuration> </execution> Yet the generated code begins with the following: // default package // Generated 2010-05-17 13:11:51 by Hibernate Tools 3.2.2.GA /** * Messages generated by hbm2java */ public class Messages implements java.io.Serializable { Is there a way to force maven to generate the package part as defined in packagename?

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  • Parsing XML with the PHP XMLReader

    - by coffeecoder
    Hi Guys, I am writing program that reads in some XML from the $_POST variable and then parses using the PHP XMLReader and the data extracted input into a database. I am using the XMLReader as the XML supplied will more than likely be too big to place into memory. However I am having some issues, my XML and basic code as are follows: '<?xml version="1.0"?> <data_root> <data> <info>value</info> </data> <action>value</action> </data_root>' $request = $_REQUEST['xml']; $reader = new XMLReader(); $reader->XML($request); while($reader->read()){ //processing code } $reader->close() My problem is that the code will work perfectly if the XML being passed does not have the <?xml version="1.0"?> line, but if i include it, and it will be included when the application goes into a live production environment, the $reader->read() code for the while loop does not work and the XML is not parsed within the while loop. Has anyone seen similar behaviour before or knows why this could be happening? Thanks in advance.

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  • Bean is not instantiating while using hibernate interceptor

    - by amit sharma
    I am using hibernate interceptor with spring framework,but when i pass a bean reference of DAO class its not instantiating the bean. My interceptor class has: private IMyService myService; // and getters and setters while application-context.xml having entries: <bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean"> <property name="entityInterceptor" ref="logInterceptor"></property> </bean> <bean name="logInterceptor" class="com.amit.project.Utility.TableLogInterceptor" > <property name="myService" ref="myService"/> </bean> <bean name="myService" class="com.amit.project.service.impl.MyService"> But my bean is not instantiating in class, showing null. entityInterceptor is not allowing to do that or anything else? plz suggest a way if anybody knows.

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  • Tips for resolving Hibernate/JPA EntityNotFoundException

    - by Damo
    I'm running into a problem with Hibernate where when trying to delete a group of Entities I encounter the following error: javax.persistence.EntityNotFoundException: deleted entity passed to persist: [com.locuslive.odyssey.entity.FreightInvoiceLine#<null>] These are not normally so difficult to track down as they are usually caused by an entity being deleted but not being removed from a Collection that it is a member of. In this case I have removed the entity from every list that I can think of (it's a complex datamodel). I've put JBoss logging into Trace and I can see the collections that are being cascaded. However I can't seem to find the Collection containing the entity that I'm deleting. Does anyone have any tips for resolving this particular Exception? Thanks.

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  • Will JSON replace XML as a data format?

    - by 13ren
    When I first saw XML, I thought it was basically a representation of trees. Then I thought: the important thing isn't that it's a particularly good representation of trees, but that it is one that everyone agrees on. Just like ASCII. And once established, it's hard to displace due to network effects. The new alternative would have to be much better (maybe 10 times better) to displace it. Of course, ASCII has been (mostly) replaced by Unicode, for internationalization. According to google trends, XML has a x43 lead, but is declining - while JSON grows. Will JSON replace XML as a data format? (edited) for which tasks? for which programmers/industries? NOTES: S-expressions (from lisp) are another representation of trees, but which has not gained mainstream adoption. There are many, many other proposals, such as YAML and Protocol Buffers (for binary formats). I can see JSON dominating the space of communicating with client-side AJAX (AJAJ?), and this possibly could back-spread into other systems transitively. XML, being based on SGML, is better than JSON as a document format. I'm interested in XML as a data format. XML has an established ecosystem that JSON lacks, especially ways of defining formats (XML Schema) and transforming them (XSLT). XML also has many other standards, esp for web services - but their weight and complexity can arguably count against XML, and make people want a fresh start (similar to "web services" beginning as a fresh start over CORBA).

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  • Unique items in Hibernate collections

    - by Rickard Lindberg
    I have defined a collection in Hibernate like this: ... public class Item { ... @ElementCollection List<Object> relatedObjects; } It creates a mapping table with colums item_id and object_id. The problem is that object_id seems to be unique. In other words I can not have two different items being related to the same object. But that is what I want. I would like the combination of item_id and object_id to be unique. How do I do that?

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  • NULL handling with subselect in Hibernate Criteria API

    - by Jens Schauder
    I'm constructing a Hibernate Criterion, using a subselect as follows DetachedCriteria subselect = DetachedCriteria.forClass(NhmCode.class, "sub"); // the subselect selecting the maximum 'validFrom' subselect.add(Restrictions.le("validFrom", new Date())); // it should be in the past (null needs handling here) subselect.add(Property.forName("sub.lifeCycle").eqProperty("this.id")); // join to owning entity subselect.setProjection(Projections.max("validFrom")); // we are only interested in the maximum validFrom Conjunction resultCriterion = Restrictions.conjunction(); resultCriterion.add(Restrictions.ilike(property, value)); // I have other Restrictions as well resultCriterion.add(Property.forName("validFrom").eq(subselect)); // this fails when validFrom and the subselect return NULL return resultCriterion; It works ok so far, but the restriction on the last line before the return statement is false when validFrom and subselect result in NULL. What I need is a version which handles this case as true. Possibly by applying a NVL or coalesce or similar. How do I do this?

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  • Hibernate, EHCache, Read-Write cache, adding item to a list

    - by Walter White
    Hi all, I have an entity that has a collection in it. The collection is a OneToMany unidirectional relationship storing who viewed a particular file. The problem I am having is that after I load the entity and try to update the collection, I don't get any errors, but the collection is never updated: Entity: @OneToMany(cascade = CascadeType.PERSIST) @JoinTable protected List<User> users; File Servlet @In private EntityQuery<File> File_findById; ... File file = File_findById(fileId); file.getUsers().add(user); session.update(file); Even though I call session.update(file) and I see stuff in hibernate logs, I don't see anything in the database indicating that it was saved. Walter

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  • How to read utf-8 xml from vbs and get correct character code

    - by vkjr
    I'm trying to read xml file from vbs script. Xml is encoded in utf-8 and has appropriate header From vbs script I use microsoft xmldom parser to read xml: Dim objXMLDoc Set objXMLDoc = CreateObject( "Microsoft.XMLDOM" ) objXMLDoc.load("vbs_strings.xml") Inside xml I'm trying to write character by code using &#nnn; notation. Then I read this character from vbscript and try to get it's code using Asc() function. For some characters it works fine and read code is equal to one written. But for some characters Asc() always returns code 63. What could it be? Examples: If xml contains <section>&#195;<section> and in script I have Section variable for representing this xml node then code: Asc(Section.Text) will return value 195 and it's ok. If xml contains <section>&#110;<section> then code: Asc(Section.Text) will return value 110 and it's ok. But if xml contains <section>&#130;<section> or <section>&#156;<section> or <section>&#140;<section> Asc(Section.Text) will return value 63 and it's definitely not good. Do you know why?

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