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  • XmlDocument.Load() throws XmlSchemaValidationException

    - by Praetorian
    Hi, I'm trying to validate an XML document against a schema (which is embedded in my program as a resource). I got everything to work, so I tried to test for errors by adding a second sibling node in the XML at a location where the schema specifies maxOccurs="1". The problem is that my ValidationEventHandler is never getting called, also XmlDocument.Load() is throwing an XmlSchemaValidationException exception when I'd expected XmlDocument.Validate() to do that. This is the code I have: private void ValidateUserData( string xmlPath ) { var resInfo = Application.GetResourceStream( new Uri( @"MySchema.xsd", UriKind.Relative ) ); var schema = XmlSchema.Read( resInfo.Stream, SchemaValidationCallBack ); XmlSchemaSet schemaSet = new XmlSchemaSet(); schemaSet.Add( schema ); schemaSet.ValidationEventHandler += SchemaValidationCallBack; XmlReaderSettings settings = new XmlReaderSettings(); settings.Schemas = schemaSet; settings.ValidationType = ValidationType.Schema; XmlDocument doc = new XmlDocument(); using( XmlReader reader = XmlReader.Create( xmlPath, settings ) ) { doc.Load( reader ); // <-- This line throws an exception if XML is ill-formed reader.Close(); } doc.Validate( SchemaValidationCallBack );// <-- This is never reached } private void SchemaValidationCallBack( object sender, ValidationEventArgs e ) { Console.WriteLine( "SchemaValidationCallBack: " + e.Message ); } How do I get the callback to be called so I can handle validation errors? Thanks for your help!

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  • Output array of XML to plain XML

    - by danit
    I have a script which collects 4 URL's (XML) using CURL and returns an array with 4 items each ocntaining the results of the URL's. Here is the array: array(3) { [0]=> string(41772) "<?xml version="1.0" encoding="UTF-8"?> <statuses type="array"> <status> <created_at>Tue Mar 30 20:58:53 +0000 2010</created_at> <id>11328253513</id> <text>...</text> <source...</source> <truncated>false</truncated> <in_reply_to_status_id></in_reply_to_status_id> <in_reply_to_user_id></in_reply_to_user_id> <favorited>true</favorited> <in_reply_to_screen_name></in_reply_to_screen_name> <user> <id>1...</id> <name>....</name> </status> </statuses> " [1]=> string(20630) "<?xml version="1.0" encoding="UTF-8"?> <statuses type="array"> <status> <created_at>Sun Feb 28 14:12:30 +0000 2010</created_at> <id>...</id> <text>...</text> <source>&lt;a etc... How can I easily output the XML from the array? I also need to combine the 3 XML structures into one where begins and ends in between each array.

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  • PHP XML Parsing

    - by ashchawla
    Hi I am making get request in PHP but the parser is having issues. I am looking for a way to retreive the value of URL in the following example. The response xml looks like this. <?xml version="1.0" encoding="iso-8859-1" standalone="no"?> <testtemplate JobName="test1"> <Sources> <Source xmlns="http://www.microsoft.com/test/schema/api"> <System> <SystemIdentifier>HTTPS</SystemIdentifier> <URL>http://example.com</URL> </System> </Source> </Sources> <testtemplate> and my PHP code looks like this: $xml = DOMDocument::LoadXML($response); $mypath = new DOMXPath($xml); $mypath->registerNamespace("a", "http://www.microsoft.com/test/schema/api"); $url = $mypath->evaluate("/testtemplate/Sources/Source/System/URL"); $message = $url->item(0)->value; print($message); Any help would be appreciated. Thanks Ashish

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  • Add xml-stylesheet and get standalone = yes.

    - by tumba25
    The code at the bottom is what I have. I removed the creation of all tags. At the top in the xml file I get.<?xml version="1.0" encoding="UTF-8" standalone="no"?> Note that standalone is no, even thou I have it set to yes. The first question: How do I get standalone = yes? I would like to add <?xml-stylesheet type="text/xsl" href="my.stylesheet.xsl"?> at line two in the xml file. Second question: How do I do that? Some useful links? Anything? DocumentBuilderFactory dbfac = DocumentBuilderFactory.newInstance(); DocumentBuilder docBuilder = dbfac.newDocumentBuilder(); Document doc = docBuilder.newDocument(); <cut> TransformerFactory transfac = TransformerFactory.newInstance(); transfac.setAttribute("indent-number", new Integer(2)); Transformer trans = transfac.newTransformer(); trans.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "no"); trans.setOutputProperty(OutputKeys.STANDALONE, "yes"); trans.setOutputProperty(OutputKeys.INDENT, "yes"); trans.setOutputProperty(OutputKeys.CDATA_SECTION_ELEMENTS, "name"); FileOutputStream fout = new FileOutputStream(filepath); BufferedOutputStream bout= new BufferedOutputStream(fout); trans.transform(new DOMSource(doc), new StreamResult(new OutputStreamWriter(bout, "utf-8")));

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  • Producing a static HTML site from XML content

    - by Skilldrick
    I have a long document in XML from which I need to produce static HTML pages (for distribution via CD). I know (to varying degrees) JavaScript, PHP and Python. The current options I've considered are listed here: I'm not ruling out JavaScript, so one option would be to use ajax to dynamically load the XML content into HTML pages. Learn some basic XSLT and produce HTML to the correct spec this way. Produce the site with PHP (for example) and then generate a static site. Write a script (in Python for example) to convert the XML into HTML. This is similar to the XSLT option but without having to learn XSLT. Useful information: The XML will likely change at some point, so I'd like to be able to easily regenerate the site. I'll have to produce some kind of menu for jumping around the document (so I'll need to produce some kind of index of the content). I'd like to know if anyone has any better ideas that I haven't thought of. If not, I'd like you to tell me which of my options seems the most sensible. I think I know what I'm going to do, but I'd like a second opinion. Thanks.

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  • Converting Python Script to Vb.NET - Involves Post and Input XML String

    - by Jason Shoulders
    I'm trying to convert a Python Script to Vb.Net. The Python Script appears to accept some XML input data and then takes it to a web URL and does a "POST". I tried some VB.NET code to do it, but I think my approach is off because I got an error back "BadXmlDataErr" plus I can't really format my input XML very well - I'm only doing string and value. The input XML is richer than that. Here is an example of what the XML input data looks like in the Python script: <obj is="MyOrg:realCommand_v1/" > <int name="priority" val="1" /> <real name="value" val="9.5" /> <str name="user" val="MyUserName" /> <reltime name="overrideTime" val="PT60S"/> </obj> Here's the Vb.net code I attempted to convert that: Dim reqparm As New Specialized.NameValueCollection reqparm.Add("priority", "1") reqparm.Add("value", "9.5") reqparm.Add("user", "MyUserName") reqparm.Add("overrideTime", "PT60S") Using client As New Net.WebClient Dim sTheUrl As String = "[My URL]" Dim responsebytes = client.UploadValues(sTheUrl, "POST", MyReqparm) Dim responsebody = (New System.Text.UTF8Encoding).GetString(responsebytes) End Using I feel like I should be doing something else. Can anyone point me to the right direction?

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  • How to compare dictonary key with xml attribute value in xml using LINQ in c #?

    - by Pramodh
    Dear all, i've a dictonary " dictSample " which contains 1 data1 2 data2 3 data3 4 data4 and an xml file"sample.xml" in the form of: <node> <element id="1" value="val1"/> <element id="2" value="val2"/> <element id="3" value="val3"/> <element id="4" value="val4"/> <element id="5" value="val5"/> <element id="6" value="val6"/> <element id="7" value="val7"/> </node> i need to match the dictonary keys with the xml attribute id and to insert the matching id and the value of attribute"value" into another dictonary now i'm using like: XmlDocument XDOC = new XmlDocument(); XDOC.Load("Sample.xml"); XmlNodeList NodeList = XDOC.SelectNodes("//element"); Dictionary<string, string> dictTwo = new Dictionary<string, string>(); foreach (string l_strIndex in dictSample .Keys) { foreach (XmlNode XNode in NodeList) { XmlElement XEle = (XmlElement)XNode; if (dictSample[l_strIndex] == XEle.GetAttribute("id")) dictTwo.Add(dictSample[l_strIndex], XEle.GetAttribute("value").ToString()); } } please help me to do this in a simple way using LINQ

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  • Parsing XML in Javascript getElementsByTagName not working

    - by Probocop
    Hi, I am trying to parse the following XML with javascript: <?xml version='1.0' encoding='UTF-8'?> <ResultSet> <Result> <URL>www.asd.com</URL> <Value>10500</Value> </Result> </ResultSet> The XML is generated by a PHP script to get how many pages are indexed in Bing. My javascript function is as follows: function bingIndexedPages() { ws_url = "http://archreport.epiphanydev2.co.uk/worker.php?query=bingindexed&domain="+$('#hidden_the_domain').val(); $.ajax({ type: "GET", url: ws_url, dataType: "xml", success: function(xmlIn){ alert('success'); result = xmlIn.getElementsByTagName("Result"); $('#tb_actualvsindexedbing_indexed').val($(result.getElementsByTagName("Value")).text()); $('#img_actualvsindexedbing_worked').attr("src","/images/worked.jpg"); }, error: function() {$('#img_actualvsindexedbing_worked').attr("src","/images/failed.jpg");} }); } The problem I'm having is firebug is saying: 'result.getElementsByTagName is not a function' Can you see what is going wrong? Thanks

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  • read xml in javascript problem

    - by Najmi
    hai all, i have a problem with my code to read the xml.I have use ajax to read xml data and populate it in combobox. My problem is it only read the first data.Here is my code my xml like this <area> <code>1</code> <name>area1</name> </area> <area> <code>2</code> <name>area2</name> </area> and my javascript if(http.readyState == 4 && http.status == 200) { //get select elements var item = document.ProblemMaintenanceForm.elements["probArea"]; //empty combobox item.options.length = 0; //read xml data from action file var test = http.responseXML.getElementsByTagName("area"); alert(test.length); for ( var i=0; i < test.length; i++ ){ var tests = test[i]; item.options[item.options.length] = new Option(tests.getElementsByTagName("name")[i].childNodes[i].nodeValue,tests.getElementsByTagName("code")[i].childNodes[i].nodeValue); } }

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  • Using FOR XML AUTO against a synonym

    - by Rick
    We've just switched to synonyms for linked server stuff, and noticed that our FOR XML output is no longer correct. When returning XML results from a view, we could alias the view and that would be assigned as the element name. With synonyms, however, it seems to ignore the alias? We're still mostly on SQL 2005 - this bug doesn't seem to happen on our 2008 instance. Is this a known problem, and any ideas for work-arounds? For example, this is what we used to be able to do: select top 3 number from Numbers as elementname for xml auto <elementname number="0"/><elementname number="1"/><elementname number="2"/> And this is what happens with a synonym: select top 3 number from Numbers_synonym as elementname for xml auto <dbo.Numbers number="0"/><dbo.Numbers number="1"/><dbo.Numbers number="2"/> As you can see, SQL Server seems to use the name of the actual referenced object instead of the alias. This gets worse for cross server queries, because you get the four-part name instead of the nice alias. (eg: <rick_server.rick_database.dbo.Numbers number="0"/>...)

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  • How is it possible the class inheritance in namespaces using Ruby on Rails 3?

    - by user502052
    In my RoR3 application I have a namespace called NS1 so that I have this filesystem structure: ROOT_RAILS/controllers/ ROOT_RAILS/controllers/application_controller.rb ROOT_RAILS/controllers/ns/ ROOT_RAILS/controllers/ns/ns_controller.rb ROOT_RAILS/controllers/ns/names_controller.rb ROOT_RAILS/controllers/ns/surnames_controller.rb I wuold like that 'ns_controller.rb' inherits from application controller, so in 'ns_controller.rb' file I have: class Ns::NsController < ApplicationController ... end Is this the right approach? Anyway if I have this situation... in 'application_controller.rb' class ApplicationController < ActionController::Base @profile = Profile.find(1) end in 'ns_controller.rb' class Ns::NsController < ApplicationController @name = @profile.name @surname = @profile.surname end ... '@name' and '@surname' variables are not set. Why?

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  • rails xml to active record object

    - by Brian D.
    I've been googling for a while to try and convert and incoming XML request into an active record object. I've tried using the ActiveRecordObject.new.from_xml method but it doesn't seem to handle relationships. For example, say I have the following xml: <blog> <title></title> <blog-pages> <blog-page> <page-number></page-number> <content></content> </blog-page> </blog-pages> </blog> And I have the following model objects: class Blog < ActiveRecord::Base has_many :blog_pages end class BlogPage < ActiveRecord::Base belongs_to :blog end Is there a way to convert the xml into a blog object WITH relationships? Or do I need to manually parse the XML? Thanks in advance.

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  • How to append new elements to Xml from stream

    - by Wololo
    I have a method which returns some xml in a memory stream private MemoryStream GetXml() { XmlWriterSettings settings = new XmlWriterSettings(); settings.Indent = true; using (MemoryStream memoryStream = new MemoryStream()) { using (XmlWriter writer = XmlWriter.Create(memoryStream, settings)) { writer.WriteStartDocument(); writer.WriteStartElement("root"); writer.WriteStartElement("element"); writer.WriteString("content"); writer.WriteEndElement(); writer.WriteEndElement(); writer.WriteEndDocument(); writer.Flush(); } return memoryStream; } } In this example the format of the xml will be: <?xml version="1.0" encoding="utf-8"?> <root> <element>content</element> </root> How can i insert a new element under the root e.g <?xml version="1.0" encoding="utf-8"?> <root> <element>content</element> ----->New element here <------ </root>

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  • Sorting XML file through multiple attributes

    - by jbugeja
    I want to sort a 'free-form' XML file through multiple attributes (first by T and then by L). The XML is a bit complex and it is structured as shown below: <?xml version="1.0" encoding="utf-8"?> <wb xmlns:cf="http://www.macromedia.com/2004/cfform" xmlns:a="urn:dummy"> <a:form name="chart"> <a:fieldset FIELD="a" FIELDNAME="FieldSet1"> <a:select1 FIELDNUMBER="01" L="1" T="2" /> <a:input FIELDNUMBER="02" INDEX="4" L="200" T="1" /> </a:fieldset> <a:fieldset FIELD="b" FIELDNAME="FieldSet1"> <a:select1 FIELDNUMBER="03" T="3" L="1" /> <a:input FIELDNUMBER="04" INDEX="7" T="4" L="200" /> <a:fieldset FIELD="c" FIELDNAME="FieldSet1"> <a:input FIELDNUMBER="05" T="10" INDEX="6" L="400" /> <a:input FIELDNUMBER="06" T="8" INDEX="8" L="200" /> </a:fieldset> </a:fieldset> <a:input FIELDNUMBER="08" INDEX="3" L="3" T="5" /> <a:input FIELDNUMBER="09" INDEX="2" L="2" T="4" /> </a:form> </wb> PS: The root element is wb and this is always followed by a:form The L and T are always found in elements that have a tag in the namespace a, the only exception being a:fieldset which does not have L and T a:fieldset could have multiple children of the namespace a including another a:fieldset We can also assume that L denotes Left and T denotes Top. So, the idea of this is that when I view the transformed XML I can immediately note which elements precede what. What's your take on this?

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  • XML File as Excel file.

    - by FrustratedWithFormsDesigner
    I have a number of reports that I run against my database that need to eventually go to the end-users as Excel spreadsheets. Initially, I was creating text reports, but the steps to convert the text to a spreadsheet were a bit cumbersome. There were too many steps to import text to the spreadsheet, and multi-line text rows were imported as individual rows in Excel (which was incorrect). Currently, I am generating simple XML saving the file with an ".xls" extension. This works better, but there is still the problem of Excel prompting the user with an XML import dialogue every time they open the file, and then having to save a new file if they add notes or change the layout to the file (which they almost certainly will be doing). Sample "xls" file: <?xml version="1.0" standalone="yes"?> <report_rows> <row> <NAME>Test Data</NAME> <COUNT>345</COUNT> </row> <!-- many more row elements... --> </report_rows> Is there any way to add markup to the file to hint to Excel how it should import and handle the file? Ideally, the end user should be able to open and save the file like any othe spreadsheet they create directly from Excel. Is this even possible? UPDATE: We are running Office 2003 here. UPDATE: The XML is generated from a sqlplus script, no option to use C#/.NET here.

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  • JavaScript, jQuery, XML - if statement not executing for unknown reason

    - by Jack Roscoe
    Hi, I have a 'for' loop which extracts data from an XML document and adds it into some JavaScript objects, each time the loop executes I want it to run a certain function depending on the value of the attribute 'typ' which is being retrieved from the xml. Currently, the data from the XML is successfully being parsed, which is proven by the first 'alert' you can see which produces the correct value. However, neither of the 'alert' lines in the 'if' statement lower down are being executed and as a result I cannot test the 'ctyp3' function which is supposed to be called. Where have I gone wrong? for (j=0; j<arrayIds.length; j++) { $(xml).find("C[ID='" + arrayIds[j] + "']").each(function(){ // pass values questions[j] = { typ: $(this).attr('typ'), width: $(this).find("I").attr('wid'), height: $(this).find("I").attr('hei'), x: $(this).find("I").attr('x'), y: $(this).find("I").attr('x'), baC: $(this).find("I").attr('baC'), boC: $(this).find("I").attr('boC'), boW: $(this).find("I").attr('boW') } alert($(this).attr('typ')); if ($(this).attr('typ') == '3') { ctyp3(x,y,width,height,baC); alert('pass'); } else { // Add here alert('fail'); } }); }

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  • Navigating sorted XML data (XSLT)

    - by Andrew Parisi
    I have an XML file with company data in it, for 30 companies across 8 industries, on a portfolio page. The user has the option to sort this data by Industry, and this XML file will be added to constantly. This sorting is done in my XSL file using <xsl:choose>. Example: <xsl:when test="(invest[@investid='con'])"> <xsl:for-each select="$invest-port/portfolio/company[@industry='Communications']"> <xsl:sort select="name" /> <div class="invest-port-thumb"> <a> <xsl:attribute name="href"> <xsl:value-of select="link" /> </xsl:attribute> </a> </div> </xsl:for-each> </xsl:when> When navigating to an individual company's page, there are "previous" and "next" buttons at the bottom of the window. My issue is that I need these to dynamically link to the previous and next elements from within the XML data that has been sorted. Is this possible? Or is there an easier way to do this? (such as place each company in industry-divided XML files instead of one) Any insight would be greatly appreciated!

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  • XML parsing problem

    - by Albinoswordfish
    I'm having this strange XML parsing problem. I have this XML string I'm trying to parse <?xml version="1.0"?> <response status="success"> <lot>32342</lot> </response> I'm using XPath with Java in order to do this. I'm using the Xpath expression "/response/@status" to find the text "success". However whenever I evaluate this expression I get an empty string. However I am able to successfully parse this string using "/response/@type" <?xml version="1.0"?> <response type="success"> <lot>32342</lot> </response> So why would simply changing the name of the attribute change the return string to nothing? is = new InputSource(testWOcreateStrGood); xPathexpressionSuccess = xPath.compile("/response/@status"); responseStr = xPathexpressionSuccess.evaluate(is); reponseStr is the string I posted earlier with the "status" attribute

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  • Call stored proc using xml output from a table

    - by user263097
    Under a tight deadline and I know I can figure this out eventually but I don't have much time to do it on my own. I have a table that has columns for customer id and account number among many other additional columns. There could be many accounts for a single customer (Many rows with the same customer id but different account number). For each customer in the table I need to call a stored procedure and pass data from my table as xml in the following format. Notice that the xml is for all of the customers accounts. <Accounts> <Account> <AccountNumber>12345</AccountNumber> <AccountStatus>Open</AccountStatus> </Account> <Account> <AccountNumber>54321</AccountNumber> <AccountStatus>Closed</AccountStatus> </Account> </Accounts> So I guess I need help with 2 things. First, how to get the data in this xml format. I assuming I'll use some variation of FOR XML. The other thing is how do I group by customer id and then call a sproc for each customer id?

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  • How do I insert XML into another XML file with XSLT?

    - by Sandra
    Hello, I looked at this thread to find out how to insert XML into XML with XSLT http://stackoverflow.com/questions/862954/insert-xml-node-at-a-specific-position-of-an-existing-document But I have a problem since I need to insert XML between two grand child nodes. For example I want to insert <s>...</s> between <r>...</r> and <t>...</t> in this file <root> <child1> <a>...</a> <r>...</r> <t>...</t> <z>...</z> </child1> </root> to create this file <root> <child1> <a>...</a> <r>...</r> <s>...</s> <t>...</t> <z>...</z> </child1> </root> Thanks for your help.

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  • Display attribute from XML using PHP

    - by user560411
    Hello. I need to display the id attribute of CD from the following XML file. I display correctly everything except the id. Any help would be appreciate. display code <?php $doc = new DOMDocument(); $doc->load( 'insert.xml' ); $CATEGORIES = $doc->getElementsByTagName( "CD" ); foreach( $CATEGORIES as $CD ) { $TITLES = $CD->getElementsByTagName( "TITLE" ); $TITLE = $TITLES->item(0)->nodeValue; $BANDS= $CD->getElementsByTagName( "BAND" ); $BAND= $BANDS->item(0)->nodeValue; $YEARS = $CD->getElementsByTagName( "YEAR" ); $YEAR = $YEARS->item(0)->nodeValue; echo "<b>$TITLE - $BAND - $YEAR\n</b><br>"; } ?> XML <?xml version="1.0" encoding="utf-8"?> <MY_CD> <CATEGORIES> <CD id="3231"> <TITLE>NEVER MIND THE BOLLOCKS</TITLE> <BAND>SEX PISTOLS</BAND> <YEAR>1977</YEAR> </CD> <CD id="2453"> <TITLE>NEVERMIND</TITLE> <BAND>NIRVANA</BAND> <YEAR>1991</YEAR> </CD> </CATEGORIES> </MY_CD>

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  • Java - Image encoding in XML

    - by Hoopla
    Hi everyone, I thought I would find a solution to this problem relatively easily, but here I am calling upon the help from ye gods to pull me out of this conundrum. So, I've got an image and I want to store it in an XML document using Java. I have previously achieved this in VisualBasic by saving the image to a stream, converting the stream to an array, and then VB's xml class was able to encode the array as a base64 string. But, after a couple of hours of scouring the net for an equivalent solution in Java, I've come back empty handed. The only success I have had has been by: import it.sauronsoftware.base64.*; import java.awt.image.BufferedImage; import org.w3c.dom.*; ... BufferedImage img; Element node; ... java.io.ByteArrayOutputStream os = new java.io.ByteArrayOutputStream(); ImageIO.write(img, "png", os); byte[] array = Base64.encode(os.toByteArray()); String ss = arrayToString(array, ","); node.setTextContent(ss); ... private static String arrayToString(byte[] a, String separator) { StringBuffer result = new StringBuffer(); if (a.length > 0) { result.append(a[0]); for (int i=1; i<a.length; i++) { result.append(separator); result.append(a[i]); } } return result.toString(); } Which is okay I guess, but reversing the process to get it back to an image when I load the XML file has proved impossible. If anyone has a better way to encode/decode an image in an XML file, please step forward, even if it's just a link to another thread that would be fine. Cheers in advance, Hoopla.

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  • Updating DIV with XML content on Hover (JQuery)

    - by Andrew Parisi
    Hi everyone! The concept of what I'm trying to do is fairly simple. I have a grid of company logos loaded through XSLT from an XML document, each with their own unique links to the company profiles. I have a separate div on the page, essentially a "preview" box. What I want to do is this: I roll over a logo, and it loads the name of the company and a short description into the preview div. This content is loaded through XML. I have been messing around with the Jquery load() function, changing the target document to load on Hover—and it almost gets what I want, but it loads the whole target XML document into the div. How can I separate this target XML data into separate divs? (which I have styled differently) I'd assume I would make use of Ajax in some way. I want to load the <name> node into the name_div, and the <desc> node into the description_div, and have them update on hover. Thanks in advance for the help!

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  • Xml updating with linq not working when quering

    - by user1734230
    I have problem i'm trying to update a specific part of the XML with the linq query but it doesn't work. So i an xml file: <?xml version="1.0" encoding="utf-8"?> <DesignConfiguration> <Design name="CSF_Packages"> <SourceFolder>C:\CSF_Packages</SourceFolder> <DestinationFolder>C:\Documents and Settings\xxx</DestinationFolder> <CopyLookups>True</CopyLookups> <CopyImages>False</CopyImages> <ImageSourceFolder>None</ImageSourceFolder> <ImageDesinationFolder>None</ImageDesinationFolder> </Design> </DesignConfiguration> I want to select the part where the part where there is Design name="somethning" and get the descendants and then update the descendants value that means this part: <SourceFolder>C:\CSF_Packages</SourceFolder> <DestinationFolder>C:\Documents and Settings\xxx</DestinationFolder> <CopyLookups>True</CopyLookups> <CopyImages>False</CopyImages> <ImageSourceFolder>None</ImageSourceFolder> <ImageDesinationFolder>None</ImageDesinationFolder> I have this code: XDocument configXml = XDocument.Load(configXMLFileName); var updateData = configXml.Descendants("DesignConfiguration").Elements().Where(el => el.Name == "Design" && el.Attribute("name").Value.Equals("AFP_GRAFIKA")).FirstOrDefault(); configXml.Save(configXMLFileName); I'm getting the null data in the updateData varibale. When I'm trying the Descendat's function through QuickWatch it also returns a null value. When I'm checking the configXML variable it has data that is my whole xml. What am I doing wrong?

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