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  • how to COPY Attribute value in a new attribute

    - by Mukesh
    How to copy data of attribute to new attribute in the same column in sql original data <root> <child attr='hello'></child> </root> Result 1 <root> <child attr='hello' attr2='hello'></child> </root> Result 2(with a modification) <root> <child attr='hello' attr2='**H**ello **W**orld'></child> </root>

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  • problem with AddSort method

    - by netNewbi3
    Hi Could you let me know what the proboem is with sorting in this code? It doesn't work. My xml: CONTRACTS --CONTRACT ---SUPPLIER ---COMMODITIES ----COMMODITY -----COMODDITYNAME My code: Dim myString As StringBuilder = New StringBuilder(200) Dim xdoc As New XPathDocument("local_xml.xml") Dim nav As XPathNavigator = xdoc.CreateNavigator() Dim expr As XPathExpression expr = nav.Compile("/pf:CONTRACTS/pf:CONTRACT") Dim namespaceManager As XmlNamespaceManager = New XmlNamespaceManager(nav.NameTable) namespaceManager.AddNamespace("pf", "http://namespace.ac.uk/") expr.AddSort("pf:SUPPLIER", XmlSortOrder.Ascending, XmlCaseOrder.None, String.Empty, XmlDataType.Text) expr.SetContext(namespaceManager) Dim nodes As XPathNodeIterator = nav.Select(expr) If nodes.Count > 0 Then myString.AppendLine("<table width='96%' border='0' cellpadding='0' cellspacing='0' border='0' class='datatable1'>") myString.AppendLine("<th width='35%'>Name</th><th width='35%'>Commodity</th><th width='20%'>Supplier</a></th>") While nodes.MoveNext() Dim node As XPathNavigator = nodes.Current.SelectSingleNode("pf:NAME", namespaceManager) Dim supplier As XPathNavigator = nodes.Current.SelectSingleNode("pf:SUPPLIER", namespaceManager) Dim commodity As XPathNavigator = nodes.Current.SelectSingleNode("pf:COMMODITIES/pf:COMMODITY/pf:COMMODITYNAME", namespaceManager) Dim sChars As String = " " myString.AppendLine("<tr>") myString.AppendLine("<td>") myString.AppendLine(node.ToString()) myString.AppendLine("</td>") myString.AppendLine("<td>") myString.AppendLine(commodity.ToString()) myString.AppendLine("</td>") myString.AppendLine("<td>") myString.AppendLine(supplier.ToString()) myString.AppendLine("</td>") myString.AppendLine("</tr>") End While myString.AppendLine("</table>") Dim strOutput As String = myString.ToString() lblOutput.Text = strOutput Else lblOutput.Text = "No results for your search<br/>" End If

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  • remember the highlighted text in html page(add annotation to html page)

    - by ganapati hegde
    Hi, I have an HTML file, i am opening it with webkit,i want to develop an app, such that after opening it, i should be able to select some text and make it highlighted(say by pressing some button 'highlight text' ). And it should remember the highlighted text so that when i open it next time it should highlight the same text automatically...which information i got to store so that i can highlight the same in the next time ? any library is available which makes my work simple?

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  • Sorted exsl:node-set. Return node by it position.

    - by kalininew
    Good afternoon, gentlemen. Help me solve a very simple task. I have a set of nodes <menuList> <mode name="aasdf"/> <mode name="vfssdd"/> <mode name="aswer"/> <mode name="ddffe"/> <mode name="ffrthjhj"/> <mode name="dfdf"/> <mode name="vbdg"/> <mode name="wewer"/> <mode name="mkiiu"/> <mode name="yhtyh"/> and so on... </menuList> I have it sorted now this way <xsl:variable name="rtf"> <xsl:for-each select="//menuList/mode"> <xsl:sort data-type="text" order="ascending" select="@name"/> <xsl:value-of select="@name"/> </xsl:for-each> </xsl:variable> Now I need to get an arbitrary element in the sorted array to the number of its position. I write code <xsl:value-of select="exsl:node-set($rtf)[position() = 3]"/> and get a response error. How to do it right?

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  • Exclude first child with XSL-T

    - by zneak
    Hello, What I'm trying to do is fairly simple, but I can't find the way to. I just want to iterate over the children of a node excluding the first child. For instance, in this XML snippet, I would want all the <bar> elements, except the first one: <foo> <Bar>Example</Bar> <Bar>This is an example</Bar> <Bar>Another example</Bar> <Bar>Bar</Bar> </foo> There is no common attribute by which I can filter (like an id tag or something similar). Any suggestions?

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  • Formatting datetime values returned in a SELECT..FOR XML statement

    - by TelJanini
    Consider the following table: Orders OrderId Date CustomerId 1000 2012-06-05 20:03:12.000 51 1001 2012-06-16 12:02:31.170 48 1002 2012-06-18 19:45:16.000 33 When I extract the Order data using FOR XML: SELECT OrderId AS 'Order/@Order-Id', Date AS 'Order/ShipDate', CustomerId AS 'Order/Customer' FROM Orders WHERE OrderId = 1000 FOR XML PATH ('') I get the following result: <Order Order-Id="1000"> <ShipDate>2010-02-20T16:03:12</ShipDate> <Customer>51</Customer> </Order> The problem is, the ShipDate value in the XML file needs to be in the format M/DD/YYYY H:mm:ss PM. How can I change the output of the ShipDate in the XML file to the desired format? Any help would be greatly appreciated!

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  • TCL tDom Empty XML Tag

    - by pws5068
    I'm using tDom to loop through some XML and pull out each element's text(). set xml { <systems> <object> <type>Hardware</type> <name>Server Name</name> <attributes> <vendor></vendor> </attributes> </object> <object> <type>Hardware</type> <name>Server Two Name</name> <attributes> <vendor></vendor> </attributes> </object> </systems> }; set doc [dom parse $xml] set root [$doc documentElement] set nodeList [$root selectNodes /systems/object] foreach node $nodeList { set nType [$node selectNodes type/text()] set nName [$node selectNodes name/text()] set nVendor [$node selectNodes attributes/vendor/text()] # Etc... puts "Type: " puts [$nType data] # Etc .. puts [$nVendor data] } But when it tries to print out the Vendor, which is empty, it thows the error invalid command name "". How can I ignore this and just set $nVendor to an empty string?

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  • Select XML nodes as rows

    - by Bjørn
    I am selecting from a table that has an XML column using T-SQL. I would like to select a certain type of node and have a row created for each one. For instance, suppose I am selecting from a people table. This table has an XML column for addresses. The XML is formated similar to the following: <address> <street>Street 1</street> <city>City 1</city> <state>State 1</state> <zipcode>Zip Code 1</zipcode> </address> <address> <street>Street 2</street> <city>City 2</city> <state>State 2</state> <zipcode>Zip Code 2</zipcode> </address> How can I get results like this: Name         City         State Joe Baker   Seattle      WA Joe Baker   Tacoma     WA Fred Jones  Vancouver BC

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  • using XSL to replace XML nodes with new nodes

    - by iHeartGreek
    I need an XSL solution to replace XML nodes with new nodes. Say I have the following existing XML structure: <root> <criteria> <criterion>AAA</criterion> </criteria> </root> And I want to replace the one criterion node with: <criterion>BBB</criterion> <criterion>CCC</criterion> <criterion>DDD</criterion> So that the final XML result is: <root> <criteria> <criterion>BBB</criterion> <criterion>CCC</criterion> <criterion>DDD</criterion> </criteria> </root> I have tried using substring-before and substring-after to just copy the first half of the structure, then just copy the second half (in order to fill in my new nodes in between the two halves) but it appears that the substring functions only recognize text in between the nodes' tags, and not the tags themselves like I want them to. :( :( Any other solutions?

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  • How to copy child nodes to another xml document?

    - by Alex
    Below is my xml XML1 <?xml version="1.0" encoding="ISO-8859-1" ?> <CATALOG> <CD> <TITLE>1</TITLE> <ARTIST>Bob Dylan</ARTIST> <COUNTRY>USA</COUNTRY> <COMPANY>Columbia</COMPANY> <PRICE>10.90</PRICE> <YEAR>1985</YEAR> </CD> <CD> <TITLE>2</TITLE> <ARTIST>Bonnie Tyler</ARTIST> <COUNTRY>UK</COUNTRY> <COMPANY>CBS Records</COMPANY> <PRICE>9.90</PRICE> <YEAR>1988</YEAR> </CD> </CATALOG> XML2 <?xml version="1.0" encoding="ISO-8859-1" ?> <CATALOG> <CD> <TITLE>3</TITLE> <ARTIST>Dolly Parton</ARTIST> <COUNTRY>USA</COUNTRY> <COMPANY>RCA</COMPANY> <PRICE>9.90</PRICE> <YEAR>1982</YEAR> </CD> </CATALOG> i need output like this <?xml version="1.0" encoding="ISO-8859-1" ?> <CATALOG> <CD> <TITLE>1</TITLE> <ARTIST>Bob Dylan</ARTIST> <COUNTRY>USA</COUNTRY> <COMPANY>Columbia</COMPANY> <PRICE>10.90</PRICE> <YEAR>1985</YEAR> </CD> <CD> <TITLE>2</TITLE> <ARTIST>Bonnie Tyler</ARTIST> <COUNTRY>UK</COUNTRY> <COMPANY>CBS Records</COMPANY> <PRICE>9.90</PRICE> <YEAR>1988</YEAR> </CD> <CD> <TITLE>3</TITLE> <ARTIST>Dolly Parton</ARTIST> <COUNTRY>USA</COUNTRY> <COMPANY>RCA</COMPANY> <PRICE>9.90</PRICE> <YEAR>1982</YEAR> </CD> </CATALOG> How i write this in classic asp ?

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  • Trying to use an Xslt for an xml in asp.net

    - by Josemalive
    Hello, i have the following xslt sheet: <?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:variable name="nhits" select="Answer[@nhits]"></xsl:variable> <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <div> <xsl:call-template name="resultsnumbertemplate"/> </div> </xsl:template> <xsl:template name="resultsnumbertemplate"> <xsl:value-of select="$nhits"/> matches found </xsl:template> </xsl:stylesheet> And this is the xml that im trying to mix with the previous xslt: <Answer xmlns="exa:com.exalead.search.v10" context="n%3Dsl-ocu%26q%3Dlavadoras" last="9" estimated="false" nmatches="219" nslices="0" nhits="219" start="0"> <time> <Time interrupted="false" overall="32348" parse="0" spell="0" exec="1241" synthesis="15302" cats="14061" kwds="14061"> <sliceTimes>15272 </sliceTimes> </Time> </time> </Answer> Im using a xslcompiledtransform and that's working fine: XslCompiledTransform transformer = new XslCompiledTransform(); transformer.Load(HttpContext.Current.Server.MapPath("xslt\\" + requestvariables["xslsheet"].ToString())); transformer.Transform(xmlreader, null, writer); My problems comes when im trying to put into a variable the "nhits" attribute value placed on the Answer element, but i'm not rendering anything using my xslt sheet. Do you know what could be the cause? Could be the xmlns attribute in my xml file? Thanks in advance. Best Regards. Jose

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  • Problem with relative path to image in XAML?

    - by Giri
    I am trying to reference a PNG file in my applications working directory through XAML with the following: <Image Name="contactImage"> <Image.Source> <BitmapImage UriSource="/Images/contact.png"> </Image.Source> </Image> Now in my code-behind I try to get the height of the image with contactImage.Source.Height This fails with System.IOException - cannot locate resource 'images/contact.png'. If I use something like PngBitmapDecoder p = new PngBitmapDecoder(new Uri("./Images/contact.png"), UriKind.Relative, BitmapCreateOptions.PreservePixelFormat, BitmapCacheOption.Default); Everything is happy. How can I reference an image in xaml to a path relative to the working deirectory of the app. BTW- this is being run on a remote machine (if that makes a difference). I have tried "./Images/contact.png" and ".\Images\contact.png" and several other combinations of back/forward slashes and dots. Here is the primary difference- Any time the file is referenced in XAML, it shows up as pack://aplication:,,, blah blah blah when I use the PngBitmapDecoder, it shows up correctly as "./Images/contact.png". How do I reference the image file in XAML and get it show a source as "./Images/contact.png" instead of a pack://application,,,blah blah blah?

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  • Get content of XML node using c#

    - by Adam S
    Hi all, simple question but I've been dinking around with it for an hour and it's really starting to frustrate me. I have XML that looks like this: <TimelineInfo> <PreTrialEd>Not Started</PreTrialEd> <Ambassador>Problem</Ambassador> <PsychEval>Completed</PsychEval> </TimelineInfo> And all I want to do is use C# to get the string stored between <Ambassador> and </Ambassador>. So far I have: XmlDocument doc = new XmlDocument(); doc.Load("C:\\test.xml"); XmlNode x = doc.SelectSingleNode("/TimelineInfo/Ambassador"); which selects the note just fine, now how in the world do I get the content in there?

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  • Using XSLT, how do I separate nodes based on their value?

    - by Will Goring
    I have a pretty flat XML structure that I need to reorder into categorised sections and, for the life of me, I can't figure out how to do it in XSLT (not that I'm by any means an expert.) Basically, the original XML looks kinda like: <things> <thing> <value>one</value> <type>a</type> </thing> <thing> <value>two</value> <type>b</type> </thing> <thing> <value>thee</value> <type>b</type> </thing> <thing> <value>four</value> <type>a</type> </thing> <thing> <value>five</value> <type>d</type> </thing> </things> And I need to output something like: <data> <a-things> <a>one</a> <a>four</a> </a-things> <b-things> <b>two</b> <b>three</b> </b-things> <d-things> <d>five</d> </d-things> </data> Note that I can't output <c-things> if there aren't any <c> elements, but I do know ahead of time what the complete list of types is, and it's fairly short so handcoding templates for each type is definitely possible. It feels like I could probably hack something together using <xsl:if> and <xsl:for-each> but it also feels like there must be a more ... 'templatey' way to do it. Can anyone help? Cheers.

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  • Remove all nodes from xml excluding specific nodes using XSLT

    - by Grinner
    Hi, I have a bunch of xml files with a varying amount of data nodes in them and I want to change the files using XSLT to include only specific nodes. Example: <?xml version="1.0" encoding="UTF-8"?> <SomeName> <identifier> <UID> 1234 </UID> </identifier> <MainNode1> <SubNode1> <Subnode1a>DATA1a0</Subnode1a> </SubNode1> <SubNode1> <Subnode1a>DATA1a1</Subnode1a> </SubNode1> <SubNode1> <Subnode1a>DATA1a2</Subnode1a> </SubNode1> </MainNode1> <MainNode2> <SubNode2> <Subnode2a>DATA2a0</Subnode2a> </SubNode2> </MainNode2> <MainNodeIDONTCARE> <SubnodeWhatever> </SubnodeWhatever> </MainNodeIDONTCARE> <MainNodeuseless> <SubnodeWhatever> </SubnodeWhatever> </MainNodeuseless> <MainNodewhatever> <SubnodeWhatever> </SubnodeWhatever> </MainNodewhatever> </SomeName> Now my final XML file should look like: <?xml version="1.0" encoding="UTF-8"?> <SomeName> <identifier> <UID> 1234 </UID> </identifier> <MainNode1> <SubNode1> <Subnode1a>DATA1a0</Subnode1a> </SubNode1> <SubNode1> <Subnode1a>DATA1a1</Subnode1a> </SubNode1> <SubNode1> <Subnode1a>DATA1a2</Subnode1a> </SubNode1> </MainNode1> <MainNode2> <SubNode2> <Subnode2a>DATA2a0</Subnode2a> </SubNode2> </MainNode2> </SomeName> I've been trying to get it done with XSLT, but I can't seem to get it done. Thanks for any help.

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  • libxml2 on iPhone

    - by mellkord
    I'm trying to parse HTML file with libxml2. Usually this works fine, but not in this case: <p> <b>Titles</b> (Some Text) <table> <tr> <td valign="top"> …Something1... </td> <td align="right" valign="top"> …Something2... </td> </tr> </table> </p> I do this query to get the first <td> //p[b='Titles']/table/tr/td[0] but nothing is returned because libxml think that <table> tag is not a child of a tag <p> and following him. And finally the question WHY?

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  • xslt test if a variable value is contained in a node set

    - by Aamir
    I have the following two files: <?xml version="1.0" encoding="utf-8" ?> <!-- D E F A U L T H O S P I T A L P O L I C Y --> <xas DefaultPolicy="open" DefaultSubjectsFile="subjects.xss"> <rule id="R1" access="deny" object="record" subject="roles/*[name()!='Staff']"/> <rule id="R2" access="deny" object="diagnosis" subject="roles//Nurse"/> <rule id="R3" access="grant" object="record[@id=$user]" subject="roles/member[@id=$user]"/> </xas> and the other xml file called subjects.xss is: <?xml version="1.0" encoding="utf-8" ?> <subjects> <users> <member id="dupont" password="4A-4E-E9-17-5D-CE-2C-DD-43-43-1D-F1-3F-5D-94-71"> <name>Pierre Dupont</name> </member> <member id="durand" password="3A-B6-1B-E8-C0-1F-CD-34-DF-C4-5E-BA-02-3C-04-61"> <name>Jacqueline Durand</name> </member> </users> <roles> <Staff> <Doctor> <member idref="dupont"/> </Doctor> <Nurse> <member idref="durand"/> </Nurse> </Staff> </roles> </subjects> I am writing an xsl sheet which will read the subject value for each rule in policy.xas and if the currently logged in user (accessible as variable "user" in the stylesheet) is contained in that subject value (say roles//Nurse), then do something. I am not being able to test whether the currently logged in user ($user which is equal to say "durand") is contained in roles//Nurse in the subjects file (which is a different xml file). Hope that clarifies my question. Any ideas? Thanks in advance.

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  • Removing elements using XSLT 1.0

    - by pmdarrow
    I'm attempting to remove Component elements from the XML below that have File children with the extension "config." I've managed to do this part, but I also need to remove the matching ComponentRef elements that have the same IDs as these Components. <Fragment> <DirectoryRef Id="MyWebsite"> <Component Id="Comp1"> <File Source="Web.config" /> </Component> <Component Id="Comp2"> <File Source="Default.aspx" /> </Component> </DirectoryRef> </Fragment> <Fragment> <ComponentGroup Id="MyWebsite"> <ComponentRef Id="Comp1" /> <ComponentRef Id="Comp2" /> </ComponentGroup> </Fragment> Based on other SO answers, I've come up with the following XSLT to remove these Component elements: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes" /> <xsl:template match="Component[File[substring(@Source, string-length(@Source)- string-length('config') + 1) = 'config']]" /> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> </xsl:stylesheet> Unfortunately, this doesn't remove the matching ComponentRef elements. The XSLT will remove the component with the Id "Comp1" but not the ComponentRef with Id "Comp1". How do I achieve this using XSLT 1.0?

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  • Retrieving XML node from a path specified in an attribute value of another node

    - by Olivier PAYEN
    From this XML source : <?xml version="1.0" encoding="utf-8" ?> <ROOT> <STRUCT> <COL order="1" nodeName="FOO/BAR" colName="Foo Bar" /> <COL order="2" nodeName="FIZZ" colName="Fizz" /> </STRUCT> <DATASET> <DATA> <FIZZ>testFizz</FIZZ> <FOO> <BAR>testBar</BAR> <LIB>testLib</LIB> </FOO> </DATA> <DATA> <FIZZ>testFizz2</FIZZ> <FOO> <BAR>testBar2</BAR> <LIB>testLib2</LIB> </FOO> </DATA> </DATASET> </ROOT> I want to generate this HTML : <html> <head> <title>Test</title> </head> <body> <table border="1"> <tr> <td>Foo Bar</td> <td>Fizz</td> </tr> <tr> <td>testBar</td> <td>testFizz</td> </tr> <tr> <td>testBar2</td> <td>testFizz2</td> </tr> </table> </body> </html> Here is the XSLT I currently have : <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"> <xsl:output method="html" indent="yes"/> <xsl:template match="/ROOT"> <html> <head> <title>Test</title> </head> <body> <table border="1"> <tr> <!--Generate the table header--> <xsl:apply-templates select="STRUCT/COL"> <xsl:sort data-type="number" select="@order"/> </xsl:apply-templates> </tr> <xsl:apply-templates select="DATASET/DATA" /> </table> </body> </html> </xsl:template> <xsl:template match="COL"> <!--Template for generating the table header--> <td> <xsl:value-of select="@colName"/> </td> </xsl:template> <xsl:template match="DATA"> <xsl:variable name="pos" select="position()" /> <tr> <xsl:for-each select="/ROOT/STRUCT/COL"> <xsl:sort data-type="number" select="@order"/> <xsl:variable name="elementName" select="@nodeName" /> <td> <xsl:value-of select="/ROOT/DATASET/DATA[$pos]/*[name() = $elementName]" /> </td> </xsl:for-each> </tr> </xsl:template> </xsl:stylesheet> It almost works, the problem I have is to retrieve the correct DATA node from the path specified in the "nodeName" attribute value of the STRUCT block.

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  • Optional Fields in Infopath; Getting the xml node with VBA

    - by Sunscreen
    Hi all, I use vb to get data through my form. I have some optional fileds in my form and I have this problem with the following code: MsgBox(myXPathNavigator.SelectSingleNode("/my:Status/my:Questions/my:Questions1", _ Me.NamespaceManager).IsNode.ToString) When the optional filed 'Questions1' is inserted to the form I get the value 'true' by the IsNode function. If the field it is not inserted I have an exception, stating that the reference is not correct (and it is indeed true). Is there a way to verify about a node, whether it is present or not in my form? Thanks in advance, Sun

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  • XML parsing and transforming (XSLT or otherwise)

    - by observ
    I have several xml files that are formated this way: <ROOT> <OBJECT> <identity> <id>123</id> </identity> <child2 attr = "aa">32</child2> <child3> <childOfChild3 att1="aaa" att2="bbb" att3="CCC">LN</childOfChild3> </child3> <child4> <child5> <child6>3ddf</child6> <child7> <childOfChild7 att31="RR">1231</childOfChild7> </child7> </child5> </child4> </OBJECT> <OBJECT> <identity> <id>124</id> </identity> <child2 attr = "bb">212</child2> <child3> <childOfChild3 att1="ee" att2="ccc" att3="EREA">OP</childOfChild3> </child3> <child4> <child5> <child6>213r</child6> <child7> <childOfChild7 att31="EE">1233</childOfChild7> </child7> </child5> </child4> </OBJECT> </ROOT> How can i format it this way?: <ROOT> <OBJECT> <id>123</id> <child2>32</child2> <attr>aa</attr> <child3></child3> <childOfChild3>LN</childOfChild3> <att1>aaa</att1> <att2>bbb</att2> <att3>CCC</att3> <child4></child4> <child5></child5> <child6>3ddf</child6> <child7></child7> <childOfChild7>1231</childOfChild7> <att31>RR</att31> </OBJECT> <OBJECT> <id>124</id> <child2>212</child2> <attr>bb</attr> <child3></child3> <childOfChild3>LN</childOfChild3> <att1>ee</att1> <att2>ccc</att2> <att3>EREA</att3> <child4></child4> <child5></child5> <child6>213r</child6> <child7></child7> <childOfChild7>1233</childOfChild7> <att31>EE</att31> </OBJECT> </ROOT> I know some C# so maybe a parser there? or some generic xslt? The xml files are some data received from a client, so i can't control the way they are sending it to me. L.E. Basically when i am trying to test this data in excel (for example i want to make sure that the attribute of childOfChild7 corresponds to the correct identity id) i am getting a lot of blank spaces. If i am importing in access to get only the data i want out, i have to do a thousands subqueries to get them all in a nice table. Basically i just want to see for one Object all its data (one object - One row) and then just delete/hide the columns i don't need.

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  • How to get node without children in xQuery?

    - by mbrevoort
    So I have two nodes of elements that I'm essentially trying to join. I want the top level node to stay the same but the child nodes to be replaced by those cross referenced. Given: <stuff> <item foo="foo" boo="1"/> <item foo="bar" boo="2" /> <item foo="baz" boo="3"/> <item foo="blah boo="4""/> </stuff> <list a="1" b="2"> <foo>bar</foo> <foo>baz</foo> </list> I want to loop through "list" and cross reference elements in "stuff" for this result: <list a="1" b="2"> <item foo="bar" boo="2" /> <item foo="baz" boo="3"/> </list> I want to do this without having to know about what attributes might be on "list". In other words I don't want to have to explicitly call them out like attribute a { $list/@a }, attribute b { $list/@b }

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  • Removing related elements using XSLT 1.0

    - by pmdarrow
    I'm attempting to remove Component elements from the XML below that have File children with the extension "config." I've managed to do this part, but I also need to remove the matching ComponentRef elements that have the same "Id" values as these Components. <Fragment> <DirectoryRef Id="MyWebsite"> <Component Id="Comp1"> <File Source="Web.config" /> </Component> <Component Id="Comp2"> <File Source="Default.aspx" /> </Component> </DirectoryRef> </Fragment> <Fragment> <ComponentGroup Id="MyWebsite"> <ComponentRef Id="Comp1" /> <ComponentRef Id="Comp2" /> </ComponentGroup> </Fragment> Based on other SO answers, I've come up with the following XSLT to remove these Component elements: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes" /> <xsl:template match="Component[File[substring(@Source, string-length(@Source)- string-length('config') + 1) = 'config']]" /> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> </xsl:stylesheet> Unfortunately, this doesn't remove the matching ComponentRef elements (i.e. those that have the same "Id" values). The XSLT will remove the component with the Id "Comp1" but not the ComponentRef with Id "Comp1". How do I achieve this using XSLT 1.0?

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  • etree.findall: 'OR'-lookup?

    - by piquadrat
    I want to find all stylesheet definitions in a XHTML file with lxml.etree.findall. This could be as simple as elems = tree.findall('link[@rel="stylesheet"]') + tree.findall('style') But the problem with CSS style definitions is that the order matters, e.g. <link rel="stylesheet" type="text/css" href="/media/css/first.css" /> <style>body:{font-size: 10px;}</style> <link rel="stylesheet" type="text/css" href="/media/css/second.css" /> if the contents of the style tag is applied after the rules in the two link tags, the result may be completely different from the one where the rules are applied in order of definition. So, how would I do a lookup that inlcudes both link[@rel="stylesheet"] and style?

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