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  • Can I use string concatenation to define a class CONST in PHP?

    - by selfsimilar
    I know that you can create global constants in terms of each other using string concatenation: define('FOO', 'foo'); define('BAR', FOO.'bar'); echo BAR; will print 'foobar'. However, I'm getting an error trying to do the same using class constants. class foobar { const foo = 'foo'; const foo2 = self::foo; const bar = self::foo.'bar'; } foo2 is defined without issue, but declaring const bar will error out Parse error: syntax error, unexpected '.', expecting ',' or ';' I've also tried using functions like sprintf() but it doesn't like the left paren any more than the string concatenator '.'. So is there any way to create class constants in terms of each other in anything more than a trivial set case like foo2?

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  • PHP export to text file - Only saving first line.

    - by wertz8090
    I'm trying to export some extracted $_POST information into a text file, however my code is only capturing the first variable and ignoring the rest. I'm saving the information to the text file in this manner: $values = "First Name: $fName\r\n"; $values .= "Last Name: $lName\r\n"; $values .= "Address: $address\r\n"; etc. This is the code I use to write to the text file: $fp = @fopen("person.data", "w") or die("Couldn't open person.data for writing!"); $numBytes = @fwrite($fp, $values) or die("Couldn't write values to file!"); @fclose($fp); Any ideas on why it would only save the first $values ($fName) variable but not the rest of them? It actually saves the first part of the $values string for all of them (so I see Last Name:, Address:, etc. on separate lines in the text file) but the called variables $lName and $address do not appear.

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  • CodeIgniter -- unable to use an object

    - by Smandoli
    THE SUMMARY: When I call .../index.php/product, I receive: Fatal error: Call to a member function get_prod_single() on a non-object in /var/www/sparts/main/controllers/product.php on line 16 The offending Line 16 is: $data['pn_oem'] = $this->product_model->get_prod_single($product_id); Looks like I don't know how to make this a working object. Can you help me? THE CODE: In my /Models folder I have product_model.php: <?php class Product_model extends Model { function Product_model() { parent::Model(); } function get_prod_single($product_id) { //This will be a DB lookup ... return 'foo'; //stub to get going } } ?> In my /controllers folder I have product.php: <?php class Product extends Controller { function Product() { parent::Controller(); } function index() { $this->load->model('Product_model'); $product_id = 113; // will get this dynamically $data['product_id'] = $product_id; $data['pn_oem'] = $this->product_model->get_prod_single($product_id); $this->load->view('prod_single', $data); } } ?>

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  • Basic class returns object reference instead of Array

    - by php-b-grader
    I have very basic class: class Customer { protected $id; protected $customer; public function __construct($customer_id) { $this->id = $customer_id; return $this->set_customer(); } protected function set_customer() { $query = mysql_query("SELECT * FROM customer WHERE id = '$this->id'"); $this->customer = mysql_fetch_row($query); return $this->customer; } } $customer = new Customer($order->customer->id); print_r($customer); This is not doing what I want it to but I understand why... $customer returns a reference to the Customer Object... What I want is the MySQL row array from the mysql_fetch_row() - How do I return the array? What am I missing?

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  • transforming flat php array into multidimensional one based on key value?

    - by PopRocks4344
    I have a flat array that I'm trying to make multidimensional. Basically, I want to find the items that have parents and create a subarray for that parent id. Right now (and this is simplified), it looks like this: Array ( [0] => stdClass Object ( [id] => 1 [parent] => 0 [name ] => Parent1 ) [1] => stdClass Object ( [id] => 7 [parent] => 1 [name] => Child1 ) [2] => stdClass Object ( [id] => 9 [parent] => 1 [name] => Child2 ) [3] => stdClass Object ( [id] => 2 [parent] => 0 [name ] => Parent2 ) [4] => stdClass Object ( [id] => 88 [parent] => 2 [name] => Childof2 ) ) I'm trying to make this: Array ( [0] => stdClass Object ( [id] => 1 [parent] => 0 [name ] => Parent1 [children] => stdClass Object ( [1] => stdClass Object ( [id] => 7 [parent] => 1 [name] => Child1 ) [2] => stdClass Object ( [id] => 9 [parent] => 1 [name] => Child2 ) ) ) [1] => stdClass Object ( [id] => 2 [parent] => 0 [name ] => Parent2 [children] => stdClass Object ( [0] => stdClass Object ( [id] => 88 [parent] => 2 [name] => Childof2 ) ) ) )

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  • How to generate all permutations of a string in PHP ?

    - by Johan
    I need an algorithm that return all possible combination of all characters in one string. I've tried: $langd = strlen($input); for($i = 0;$i < $langd; $i++){ $tempStrang = NULL; $tempStrang .= substr($input, $i, 1); for($j = $i+1, $k=0; $k < $langd; $k++, $j++){ if($j > $langd) $j = 0; $tempStrang .= substr($input, $j, 1); } $myarray[] = $tempStrang; } But that only returns the same amount combination as the length of the string. Say the $input is = "hey", the result would be: hey, hye, eyh, ehy, yhe, yeh.

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  • PHP - Why does my computation produce a different result when I assign it to a variable?

    - by David
    I want to round a number to a specific number of significant digits - basically I want the following function: round(12345.67, 2) -> 12000 round(8888, 3) -> 8890 I have the following, but there's a strange problem. function round_to_sf($number, $sf) { $mostsigplace = floor(log10(abs($number)))+1; $num = $number / pow(10, ($mostsigplace-$sf)); echo ($number / pow(10, ($mostsigplace-$sf))).' '.$num.'<BR>'; } round_to_sf(41918.522, 1); Produces the following output: 4.1918522 -0 How can the result of a computation be different when it's assigned to a variable?

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  • Why did I get a 400 Bad Request when getting a page with PHP Curl?

    - by user307272
    Hi, I was trying to access a page using curl. I could access it perfectly using the browser and using "static" strings as the URL, like: $url = "http://www.example.com/?q=1234" But when I tried to access the page using a variable in the URL string like: $url = "http://www.example.com/?q=$param" I got a 400 error code. I checked out on the web and found some comments here in this stackoverflow thread: Then, just for curiosity I did the following: $url = "http://www.example.com/?q=" . trim($param); and it worked! And no, $param did NOT contain any spaces. To me, it seems that it can be some encoding error, but I really can't find an explanation for it. Does anyone here in stackoverflow know what it can possibly be? Thanks in advance :)

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  • How to get a list of unrepeatable date from my db in PHP?

    - by SzamDev
    Hi in my db there are 5 fields (id, list_date, amount, total, m_from) and contain data, for example : 1 - 1/1/2010 - 10 - 50 - 'example111' 1 - 1/1/2010 - 10 - 50 - 'example111' 1 - 1/4/2010 - 10 - 50 - 'example154 1 - 1/1/2010 - 10 - 50 - 'example111' 1 - 1/5/2010 - 10 - 50 - 'test' I need to know how I can get dates from list_date but without repeatable dates like '1/1/2010, 1/5/2010, 1/4/2010' Thanks in Advance.

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  • codeigniter cron job with http access

    - by user1313850
    Sorry if this is a duplicate question...I've searched around and found similar advice but nothing that helps my exact problem. And please excuse the noob questions, CRON is a new thing for me. I have a codeigniter script that scrapes the html DOM of another site and stores some of that in a database. I'd like to run this script at a regular interval. This has lead me to looking into cron jobs. The page I have is at myserver.com/index.php/update I realize I can run a cron job with curl and run this page. If I want to be a bit more secure I can put a string at the end like: myserver.com/index.php/update/asdfh2784fufds And check for that in my CI controller. This seems like it would be mostly secure, but doesn't seem like the "right" way to do things. I've looked into running CI from the command line, and can execute basic pages like: php index.php mycontroller But when I try to do: php index.php update It doesn't work. I suspect this is because it needs to use HTTP to scrape the DOM of the outside page. So, my question: How do I securely run a codeigniter script with a cron job that needs HTTP access?

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  • How can I set time limit on get_file_contents in PHP?

    - by Jagira
    Hello, At times the get_file_contents takes too long and that hangs the entire script. Is there any way of setting a time out limit on get_file_contents, without modifying the maximum execution time of the script? Edit: Its taking long because the file does not exist. I am getting "failed to open stream: HTTP request failed!" error. But it takes forever.

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  • Simple php statement, I can't get it to work!

    - by eberswine
    How to get $schedule = true and $schedule = true to work??? I know this is easy and I'm overlooking something simple! else { if($schedule){ $where[] = 'date > '.(time() + $config_date_adjust * 60 - 432000); } else{ $where[] = 'date < '.(time() + $config_date_adjust * 60); } $schedule = false; } else { if($schedule2){ $where[] = 'date > '.(time() + $config_date_adjust * 60 - 86400); } else{ $where[] = 'date < '.(time() + $config_date_adjust * 60); } $schedule2 = false; }

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  • Can a dropdown box using PHP / MySQL automatically select what was last saved in the database with it?

    - by wertz8090
    I am currently working on trying to get a dropdown box to display the most recently saved field each time I open a page for editing an item in an inventory. For example, let's say that my dropdown box selections are Iron, Copper, Gold, Silver, Titanium. The first time the dropdown box loads, I would like it to load in that order (the default order that I set it to). However, once a user submits a form that specifies a selection, I would like that selection to appear as the new default for the dropdown box (for example, if the user picks Gold, Gold will now display as the default). However - the new default that is selected and submitted can only appear for those fields which it is saved under (for example, since the user selected Gold, their preference is now saved as Gold and will appear as such under the field Necklace - however, Gold should not be the default for the fields Ring, Bracelet, and Earring when I open a page to view them). Basically, I need a dropdown box that can save the option of the latest selection on a page after the form is submitted, while at the same time making sure not to affect the default order of the dropdown box across other pages. Your help is much appreciated.

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  • PHP class that changes an image and reloads the page not displaying new image in Internet Explorer

    - by Stuart
    I have a class that runs a function when the image is clicked on to display an additional image. This function produces a linked div tag that reloads the page with a set of variables that then produces another image. The image is set as a background image on a large div tag behind the linked div tags to give the same effect as an image map but without using an image map or a SVG. This works perfectly in Chrome and Firefox but will not display the new image in Internet Explorer until you F5 the page again with the get variables in the URL? Does anyone know how to fix this issue so that it works in IE the same as the other browsers? Many thanks.

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  • How to get a nicely formatted PHP Web Service response?

    - by Bruno
    I called an API like this: $service = new Class_Service(); $parameters = new GetClasses(); $parameters->Request = new GetClassesRequest(); $parameters->Request->SourceCredentials = new SourceCredentials(); $parameters->Request->SourceCredentials->SourceName = "Name"; $parameters->Request->SourceCredentials->Password = "Pass"; $parameters->Request->SourceCredentials->SiteIDs = array( 12 ); $classes = $service->GetClasses($parameters); var_dump($classes); And received a response like this: object(GetClassesResponse)#7 (1) { ["GetClassesResult"]=> object(GetClassesResult)#8 (6 { ["Classes"]=> object(stdClass)#9 (1) { ["Class"]=> array(25) { [0]=> object(Mi_Class)#10 (21) { ["ClassScheduleID"]=> int(15) ["Visits"]=> NULL ["Clients"]=> NULL ["Location"]=> object(Location)#11 (30) { ["BusinessID"]=> NULL ["SiteID"]=> int(12) ["BusinessDescription"]=> NULL ["AdditionalImageURLs"]=> object(stdClass)#12 (0) { } ["FacilitySquareFeet"]=> NULL Does a response normally look like this? How do I go about getting the data in a formatted manner?

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  • Why is my upload-of-a-file code putting 2 sets of files into my directory? (PHP)

    - by ggfan
    When I upload a file using this code, it puts a copy of the file in the "uploads" folder(which is what I want) but it also puts a copy in my root. I only want the files going to the uploads folder. define ('GW_UPLOADPATH', 'uploads/'); $upfile= GW_UPLOADPATH . $_FILES['userfile']['name']; if(is_uploaded_file($_FILES['userfile']['tmp_name'])) { if(!move_uploaded_file($_FILES['userfile']['tmp_name'], $upfile)) //this is saying if the file isn't moved to $upfile. { echo 'Problem: could not move file to destination directory'; exit; } } else { echo 'Problem: Possible file upload attack. Filename: '; //this could be an attack b/c it might be from localhost. echo $_FILES['userfile']['name']; exit; } echo 'File uploaded successfully<br><br>';

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