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  • Ajax call from a form rendered as Ajax response (jQuery + Grails: chaining ajax requests)

    - by bsreekanth
    Hello, I was expecting the below scenario common, but couldn't find much help online. I have a form loaded through Ajax (say, create entity form). It is loaded through a button click (load) event $("#bt-create").click(function(){ $ ('#pid').load('/controller/vehicleModel/create3'); return false; }); the response (a form) is written in to the pid element. The name and id of the form is ajax-form, and the submit event is attached to an ajax post request $(function() { $("#ajax-form").submit(function(){ // do something... var url = "/app/controller/save" $.post(url, $(this).serialize(), function(data) { alert( data ) ; /// alert data from server }); I could make the above ajax operations individually. That is the ajax post operation succeeds if it calls from a static html file. But if I chain the requests (after completing the first), so that it calls from the output form generated by the first request, nothing happens. I could see the post method is called through firebug. Is there a better way to handle above flow? One more interesting thing I noticed. As you could see, I use grails as my platform. If I keep the javascripts in the main.gsp (master layout), the submit event would not register as the breakpoint is not hit in firebug. But, if I define the javascript in the template file (which renders the form above), the breakpoint is hit, but as I explained, the action is not called at the controller. I changes the javascript to the head section but same result. any help greatly appreciated. thanks, Babu.

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  • Modify POST vars before post, using jQuery

    - by aidan
    I have a form, and a submit handler in jQuery. When the user submits the form, I want to modify (add) some parameters to the POST request, before it is despatched from the client to the server. i.e. User clicks 'submit' My jQuery submit hander begins execution... I create some new key/value pairs and add them to the POST payload At the moment, it looks like my only options are to use $.post(), or $('form').append(' Thanks for any help.

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  • How do I Reset the Values in My ASP.NET Fields?

    - by Giffyguy
    The current form is here. It is not complete, and only a couple options will work. Select "Image CD" and then any resolution and click "Add to Order." The order will be recorded on the server-side, but on the client-side I need to reset the product drop-down to "{select}" so that the user will know that they need to select another product. This is consistant with the idea that the sub-selections disappear. I don't know whether I should be using ASP postback or standard form submittal, and most of the fields need to be reset when the user adds an item to the order.

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  • MVC/HTML - input submit won't trigger when HTML is in a text area

    - by cw
    Any idea why the below code doesn't trigger if I were to put some HTML inside the textarea? It works fine it I don't have HTML in it, but I'm not sure why it doesn't work with it. Here is the code. <form action="/Home/AddPost" method="post"> <table> <tr> <td>Post Title:</td> <td><input id="Title" type="text" name="title" /></td> </tr> <tr> <td>Post Description:</td> <td><textarea id="Description" rows="10" cols="60" name="description"></textarea></td> </tr> </table> <input type="submit" value="Save" /> </form>

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  • Zend Form Radio Elements, using images instead of default radio elements.

    - by Davy
    Hello, Ultimately here is my goal. Using Zend_Form I want to turn this idea http://www.sohtanaka.com/web-design/fancy-thumbnail-hover-effect-w-jquery/ into a list of radio buttons. Kind of using this concept. http://theodin.co.uk/tools/tutorials/jqueryTutorial/fancyRadio/ I know there has to be a way to do this but I can't seem to figure anything out! Any ideas? Thanks! -d

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  • error handler isn't called when file is uploaded via ajax using jQuery form plugin

    - by scompt.com
    Here's my test case. If the form is posted, a 500 error response is sent. If not, the form is sent. If the file input tag is commented out, the error handler is called. If the file input tag is present, the error handler isn't called. I think this might have something to do with the fact that jQuery needs to use an iframe to handle the upload and iframes don't seem to respond to the error handler. Edit: If I add iframe: true to the options passed to ajaxSubmit to force the use of an iframe, the non-file-upload case stops working also, so it definitely has to do with the iframe. Edit2: I'm using the jQuery Form Plugin. <?php if($_SERVER['REQUEST_METHOD'] == 'POST') { header('HTTP/1.1 500 Internal Server Error'); die; } else {?> <html><head> <script type='text/javascript' src='http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js?ver=2.9.2'></script> <script type='text/javascript' src='http://github.com/malsup/form/raw/master/jquery.form.js?v2.43'></script> <script type="text/javascript"> jQuery(document).ready(function() { jQuery('a').click(function() {jQuery('form').ajaxSubmit({error: function(){alert('error handler called');}})}); }); </script> </head><body> <form method="POST"> <input type="text" name="mytext" /> <input type="file" name="myfile" /><!-- comment this element out --> <input type="hidden" name="blah" value="blah" /> <a>submit</a> </form> </body></html> <?php } Is there any way to get the error handler to be called in both situations?

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  • cgi.FieldStorage always empty - never returns POSTed form Data

    - by Dan Carlson
    This problem is probably embarrassingly simple. I'm trying to give python a spin. I thought a good way to start doing that would be to create a simple cgi script to process some form data and do some magic. My python script is executed properly by apache using mod_python, and will print out whatever I want it to print out. My only problem is that cgi.FieldStorage() is always empty. I've tried using both POST and GET. Each trial I fill out both form fields. <form action="pythonScript.py" method="POST" name="ARGH"> <input name="TaskName" type="text" /> <input name="TaskNumber" type="text" /> <input type="submit" /> </form> If I change the form to point to a perl script it reports the form data properly. The python page always gives me the same result: number of keys: 0 #!/usr/bin/python import cgi def index(req): pageContent = """<html><head><title>A page from""" pageContent += """Python</title></head><body>""" form = cgi.FieldStorage() keys = form.keys() keys.sort() pageContent += "<br />number of keys: "+str(len(keys)) for key in keys: pageContent += fieldStorage[ key ].value pageContent += """</body></html>""" return pageContent I'm using Python 2.5.2 and Apache/2.2.3. This is what's in my apache conf file (and my script is in /var/www/python): <Directory /var/www/python/> Options FollowSymLinks +ExecCGI Order allow,deny allow from all AddHandler mod_python .py PythonHandler mod_python.publisher </Directory>

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  • How can I get VS2008 winforms designer to render a Form that implements an abstract base class

    - by BeowulfOF
    Hi, I engadged a problem with inherited Controls in WinForms, and need some advice on it. I do use a base class for items in a List (selfmade GUI list made of a panel) and some inherited controls that are for each type of data that could be added to the list. There was no problem with it, but I know found out, that it would be right, to make the base-control an abstract class, since it has methods, that need to be implemented in all inherited controls, called from the code inside the base-control, but must not and can not be implemented in the base class. When I mark the base-control as abstract, the VS2008 Designer refuses to load the window. Is there any way to get the Designer work with the base-control made abstract?

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  • Calling a method within Portlet when submitting form

    - by Roland
    I have a Portlet that contains a form. Now what I want to achieve is the following. 1) A Porlet containing a form is called within a page via <?php $this->widget('form'); ?> 2) The user fills in this form and clicks on submit "The submit button should be an ajax button" 3) When submit has been pressed the form should call a method within the form portlet class and the form should be replaced with a Thank you message. 4) I only want the current view in the portlet replaced with another view. My portlet class looks like this Yii::import('zii.widgets.CPortlet'); class Polls extends CPortlet{ public $usr_id=''; public function init(){ $cs = Yii::app()->clientScript; $cs->registerCoreScript('jquery'); parent::init(); } protected function renderContent(){ $this->render('form'); } public function update(){ $this->render('thankyou'); } } } Any advise, help would be highly appreciated.

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  • change prototype script to jquery one

    - by steve
    I have this form submit code: Event.observe(window, 'load', init, false); function init() { Event.observe('addressForm', 'submit', storeAddress); } function storeAddress(e) { $('response').innerHTML = 'Adding email address...'; var pars = 'address=' + escape($F('address')); var myAjax = new Ajax.Updater('response', 'ajaxServer.php', {method: 'get', parameters: pars}); Event.stop(e); } How can I change it to work with jQuery? Here is the html form: <form id="addressForm" action="index.php" method="get"> <b>Email:</b> <input type="text" name="address" id="address" size="25"><br> <input name="Submit" value="Submit" type="submit" /> <p id="response"><?php echo(storeAddress()); ?></p> </form> and this is php code at start of document: <?php require_once("inc/storeAddress.php"); ?>

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  • HTML Form HIdden Fields added with Javascript not POSTing

    - by dscher
    I have a form where the user can enter a link, click the "add link" button, and that link is then(via jQuery) added to the form as a hidden field. The problem is it's not POSTing when I submit the form. It's really starting to confound me. The thing is that if I hardcode a hidden field into the form, it is posted, but my function isn't working for some reason. The hidden field DOES get added to my form as I can see with Firebug but it's just not being sent with the POST data. Just to note, I'm using an array in Javascript to hold the elements until the form is submitted which also posts them visibly for the user to see what they've added. I'm using [] notation on the "name" field of the element because I want the links to feed into an array in PHP. Here is the link creation which is being appended to my form: function make_hidden_element_tag(item_type, item_content, item_id) { return '<input type="hidden" name="' + item_type + '[]" id="hidden_link_' + item_id + '" value="' + item_content + '"/>'; Does anyone have an idea why this might not be posting. As stated above, any hard-coded tags that are nearly identical to the above works fine, it's just that this tag isn't working. Here is how I'm adding the tag to the form with jQUery: $('#link_td').append( make_hidden_element_tag('links', link, link_array.length - 1)); I'm using the Kohana 3 framework, although I'm not sure that has any bearing on this because it's not really doing anything from the time the HTML is added to the page and the submit button is pressed.

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  • inserting a form to session raises picklingerror - django

    - by shanyu
    I receive an exception when I add a form to the session: PicklingError: Can't pickle <class 'django.utils.functional.__proxy__'>: attribute lookup django.utils.functional.__proxy__ failed The form includes a few simple fields and has some javascript attached to a widget. It might be that Django forms cannot be pickled at all, but the exception seems to point to unicode lazy translation. To test further, I have also tried to insert only the form errors (an errordict) to the session and received the same error. I appreciate some help here, thanks in advance. EDIT: Here's why I insert a form into the session: I have an app that has a form. This form is rendered by a template tag in another app. When posted, if the form is valid, no problem, I do stuff and redirect to "next". However if it is not valid, I want to go back to the posting page to show errors. Recall that the comments app in this case redirects to an intermediate "hey, please fix the errors" page. I am trying to avoid this, and hence redirect back to the posting page with the form and its errors in the session that the template tag will render.

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  • How to add a specific class to an input which has generated a form error?

    - by Kamil Mroczek
    I want to add a specific class to an input if an error is genereted by the input. For example, if input is empty and has required validator it shouls look like this: <dd id="login-element"> <input type="text" name="login" id="login" value="" class="input-text error" /> <ul class="errors"> <li>Value is required and can't be empty</li> </ul> </dd> class="input-text error" Please tell me how to do that.

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  • JQuery Autocomplete - Stop mouseover+Return submitting data

    - by ILT
    I'm using JQuery Autocomplete (bassistance) and have run into a problem. If the mouse rolls over one of the autocomplete suggestions and the user hits the return key (rather than clicking to make selection), the form is submitted and goes to whatever link was rolled over at the time. This is a problem as people click in the textbox, and when typing their search, leave the pointer where the autocomplete popup appears. So when they hit enter, it doesn't do the search for whatever they typed in the box but whatever was highlighted in the autocomplete suggestions. Is there a way to stop this? Using Google as the functionality I'm after... So just to clarify - I want selections via mouse and keyboard to go to the same place, but if the UP or DOWN arrow has not been pressed (user not selected an autocomplete option via the keyword), dont go to the URL specified in the autosuggest - instead submit the form (traditional method without JQuery) based on what has been typed in the textbox. I hope I'm explaining this clearly? :S

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  • How can I adjust the position of a label for a zend form Radio element?

    - by murze
    Hi, with this piece of code $feOnline = New Zend_Form_Element_Radio('online'); $feOnline->setValue($article->online) ->addMultiOptions(array(0=>'offline', 1=>'online')) ->setLabel('Online'); this html is generated <dd id="online-element"> <label for="online-0"> <input type="radio" checked="checked" value="0" id="online-0" name="online">offline </label><br> <label for="online-1"><input type="radio" value="1" id="online-1" name="online">online </label> </dd> However I don't want the input-tag inside the label-tag. No need for the "" either... What decorators must I add to get this output? <dd id="online-element"> <input type="radio" checked="checked" value="0" id="online-0" name="online"><label for="online-0">offline</label> <input type="radio" value="1" id="online-1" name="online"><label for="online-1">online</label> </dd>

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  • How to disable form submit if the username is not available

    - by Rajasekar
    I have checked the user name availability. The problem is, even if the username is not available, the form is posting. Edited Code: <SCRIPT type="text/javascript"> $(document).ready(function(){ $("#emailch").change(function() { var usr = $("#emailch").val(); if(usr.length >= 3) { $("#status").html('<img src="images/loader.gif" align="absmiddle">&nbsp;Checking availability...'); $.ajax({ type: "POST", url: "includes/check.php", data: "username="+ usr, success: function(msg){ $("#status").ajaxComplete(function(event, request, settings){ if(msg == 'OK') { $("#username").removeClass('object_error'); // if necessary $("#username").addClass("object_ok"); $(this).html('&nbsp;<img src="images/tick.gif" align="absmiddle">'); } else { $("#username").removeClass('object_ok'); // if necessary $("#username").addClass("object_error"); $(this).html(msg); } }); } }); } else { $("#status").html('<font color="red">The username should have at least <strong>3</strong> characters.</font>'); $("#username").removeClass('object_ok'); // if necessary $("#username").addClass("object_error"); } }); }); </SCRIPT> What I want is that, the form should not be posted if the user name is not available. I have tried by using return false; in IF CONDITION but it fails. Please suggest any alternate method. Any help will be appreciated.

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  • Symfony2 Forms: is it possible to bind a form in an "unconventional way"?

    - by DonCallisto
    Imagine this scenario: in our company there is an employee that "play" around graphic,css,html and so on. Our new project will born under symfony2 so we're trying some silly - but "real" - stuff (like authentication from db, submit data from a form and persist it to db and so on..) The problem As far i know, learnt from symfony2 "book" that i found on the site (you can find it here), there is an "automated" way for creating and rendering forms: 1) Build the form up into a controller in this way $form = $this->createFormBuilder($task) ->add('task','text'), ->add('dueDate','date'), ->getForm(); return $this->render('pathToBundle:Controller:templateTwig', array('form'=>$form->createview()); 2) Into templateTwig render the template {{ form_widget(form) }} // or single rows method 3) Into a controller (the same that have a route where you can submit data), take back submitted information if($rquest->getMethod()=='POST'){ $form->bindRequest($request); /* and so on */ } Return to scenario Our graphic employee don't want to access controllers, write php and other stuff like those. So he'll write a twig template with a "unconventional" (from symfony2 point of view, but conventional from HTML point of view) method: /* into twig template */ <form action="{{ path('SestanteUserBundle_homepage') }}" method="post" name="userForm"> <div> USERNAME: <input type="text" name="user_name" value="{{ user.username}}"/> </div> <div> EMAIL: <input type="text" name="user_mail" value="{{ user.email }}"/> </div> <input type="hidden" name="user_id" value="{{ id }}" /> <input type="submit" value="modifica i dati"> </form> Now, if into the controller that handle the submission of data we do something like that public function indexAction(Request $request) { if($request->getMethod() == 'POST'){ // sono arrivato per via di un submit, quindi devo modificare i dati prima di farli vedere a video $defaultData = array('message'=>'ho visto questa cosa in esempio, ma non capisco se posso farne a meno'); $form = $this->createFormBuilder($defaultData) ->add('user_name','text') ->add('user_mail','email') ->add('user_id','integer') ->getForm(); $form->bindRequest($request); //bindo la form ad una request $data = $form->getData(); //mi aspetto un'array chiave=>valore /* .... */ We expected that $data will contain an array with key,value from the submitted form. We found that it isn't true. After googling for a while and try with other "bad" ideas, we're frozen into that. So, if you have a "graphic office" that can't handle directly php code, how can we interface from form(s) to controller(s) ? UPDATE It seems that Symfony2 use a different convention for form's field name and lookup once you've submitted that. In particular, if my form's name is addUser and a field is named userName, the field's name will be AddUser[username] so maybe it have a "dynamic" lookup method that will extract form's name, field's name, concat them and lookup for values. Is it possible?

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  • Ruby on Rails user login form in main layout

    - by Jimmy
    Hey guys I have a simple ror application for some demo stuff. I am running into a problem with trying to move my login form from the users controller and just have it displayed in the main navigation so that a user can easily log in from anywhere. The problem is the form doesn't generate the correct action for the html form. Ruby code: <% form_for(url_for(:action => 'login'), :method => 'post') do |f| %> <li><%= f.text_field("username") %></li> <li><%= f.password_field("password") %></li> <li><%= submit_tag("Login")%></li> <% end %> The problem is depending on the controller I am currently in this generates HTML actions like <form action="/home" method="post">...</form> when it should be generating HTML like so <form action="/login" method="post">...</form> I know I could simply do an HTML form here but I want to keep things as easy to maintain as possible. Any help?

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  • Can JQuery.Validate plugin prevent submission of an Ajax form

    - by berko
    I am using the JQuery form plugin (http://malsup.com/jquery/form/) to handle the ajax submission of a form. I also have JQuery.Validate (http://docs.jquery.com/Plugins/Validation) plugged in for my client side validation. What I am seeing is that the validation fails when I expect it to however it does not stop the form from submitting. When I was using a traditional form (i.e. non-ajax) the validation failing prevented the form for submitting at all.... which is my desired behaviour. I know that the validation is hooked up correctly as the validation messages still appear after the ajax submit has happened. So what I am I missing that is preventing my desired behaviour? Sample code below.... <form id="searchForm" method="post" action="/User/GetDetails"> <input id="username" name="username" type="text" value="user.name" /> <input id="submit" name="submit" type="submit" value="Search" /> </form> <div id="detailsView"> </div> <script type="text/javascript"> var options = { target: '#detailsView' }; $('#searchForm').ajaxForm(options); $('#searchForm').validate({ rules: { username: {required:true}}, messages: { username: {required:"Username is a required field."}} }); </script>

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