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  • Is there a keyboard shortcut to toggle Tree view / Places View?

    - by zinzolin
    I find both the Tree view and the Places view useful. Changing from one view to the other is not fast because one have to go into the appearance menu. It's even slower with Oneiric because this menu can now be far away. (Before Unity, I always had the tree view on and I used my bookmarks directly from the Places menu. That was fine) Is there a keyboard shortcut to toggle from one view to the other? Or is it possible to create one oneself? Thanks a lot the help !

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  • Example usage of a custom delegate in c#

    - by Freakishly
    Hi, I found this question on SO about a tree implementation in C#. I have no idea about delegates and I was wondering how the following code could be used to implement a tree. Also, what would be the most efficient way to keep a track of parent nodes? delegate void TreeVisitor<T>(T nodeData); class NTree<T> { T data; LinkedList<NTree<T>> children; public NTree(T data) { this.data = data; children = new LinkedList<NTree<T>>(); } public void addChild(T data) { children.AddFirst(new NTree<T>(data)); } public NTree<T> getChild(int i) { foreach (NTree<T> n in children) if (--i == 0) return n; return null; } public void traverse(NTree<T> node, TreeVisitor<T> visitor) { visitor(node.data); foreach (NTree<T> kid in node.children) traverse(kid, visitor); } }

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  • Deeply nested subqueries for traversing trees in MySQL

    - by nickf
    I have a table in my database where I store a tree structure using the hybrid Nested Set (MPTT) model (the one which has lft and rght values) and the Adjacency List model (storing parent_id on each node). my_table (id, parent_id, lft, rght, alias) This question doesn't relate to any of the MPTT aspects of the tree but I thought I'd leave it in in case anyone had a good idea about how to leverage that. I want to convert a path of aliases to a specific node. For example: "users.admins.nickf" would find the node with alias "nickf" which is a child of one with alias "admins" which is a child of "users" which is at the root. There is a unique index on (parent_id, alias). I started out by writing the function so it would split the path to its parts, then query the database one by one: SELECT `id` FROM `my_table` WHERE `parent_id` IS NULL AND `alias` = 'users';-- 1 SELECT `id` FROM `my_table` WHERE `parent_id` = 1 AND `alias` = 'admins'; -- 8 SELECT `id` FROM `my_table` WHERE `parent_id` = 8 AND `alias` = 'nickf'; -- 37 But then I realised I could do it with a single query, using a variable amount of nesting: SELECT `id` FROM `my_table` WHERE `parent_id` = ( SELECT `id` FROM `my_table` WHERE `parent_id` = ( SELECT `id` FROM `my_table` WHERE `parent_id` IS NULL AND `alias` = 'users' ) AND `alias` = 'admins' ) AND `alias` = 'nickf'; Since the number of sub-queries is dependent on the number of steps in the path, am I going to run into issues with having too many subqueries? (If there even is such a thing) Are there any better/smarter ways to perform this query?

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  • How to get child nodes after store load

    - by Azincourt
    Version: ExtJs 4.1 To change the child items I use this function: TreeStore (Ext.data.TreeStore) storeId : 'treeStore', ... constructor: function( oConfig ) { ... this.on( 'expand', function( oObj ) { oObj.eachChild(function(oNode) { switch(oNode.data.type) { case "report": oNode.set('icon', strIconReport); break; case "view": oNode.set('icon', strIconView); break; } }); }); Reload After removing or adding items in the tree, I reload the tree somewhere else with: var oStore = Ext.getStore('treeStore'); oStore.load({ node : oNode, params : { newpath : oNode.data.path, overwrite : true } }); Although it is the same store treeStore, after loading and expanding to the correct path, the icons are not changed since the .on( 'expand') function is not called. Why? Question How can I change the icons of this newly loaded store before it expands to the node path? What I tried Before calling .load() I tried to edit the children with oNode.eachChild(function(oChild) {} but no success.

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  • SSTP BPDU with bad TLV and macflap -- info please

    - by Adeodatus
    Hi All, I'm slowly locking down the network I've inherited and mac-flapping has been a problem in the past with customers doing all kinds of crazy things. Thats changing but I am now encountering this error: Dec 30 18:31:31 10.50.1.50 1565: 001567: Dec 30 18:31:30: %SW_MATM-4-MACFLAP_NOTIF: Host xxxx.xxxx.f681 in vlan 1 is flapping between port Gi0/5 and port Gi0/48 Dec 30 18:43:28 10.50.1.50 1566: 001568: Dec 30 18:43:26: %SPANTREE-2-RECV_BAD_TLV: Received SSTP BPDU with bad TLV on GigabitEthernet0/5 VLAN1. Dec 30 18:48:18 10.50.1.50 1567: 001569: .Dec 30 18:48:17: %SPANTREE-2-RECV_BAD_TLV: Received SSTP BPDU with bad TLV on GigabitEthernet0/5 VLAN1. unfortunately, that mac address is the mac of our core router, the only link to the internet, on port gi0/48 On the other end of gi0/5, I have about 50 bridged customer machines connected through a series of managed and unmanaged L2 switches. Yes, on VLAN1 too ... like I said, working on changing this slowly. In the mean time, it has me quite baffled on how to deal with this and track down the customer or switch that is the problem. What else could be going on with these messages ... the bad TLV is a new one for me. Any ideas? Thank you and Happy New Year to you all!!

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  • Confirm that two filesystems are identical, ignoring special files

    - by endolith
    /media/A and /media/B should be identical, but I want to confirm before deleting one. Duplicate file finders don't work, because they'll find two copies of the same file within B, for instance. I only want to confirm that every file in one is identical to the other. diff -qr /media/A/ /media/B/ seems to work, but the output is cluttered with garbage like diff: /media/A//etc/alternatives/ControlPanel: No such file or directory and File /media/A//dev/tty8 is a character special file while file /media/B//dev/tty8 is a character special file I can suppress the former with 2> /dev/null, but I don't know about the latter. rsync -avn /media/A/ /media/B/ also produces a bunch of clutter, like "skipping non-regular file". How can I compare the two trees and just make sure that all the real files exist in both and are identical?

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  • Solving the context menu problem with drag and drop in trees

    - by Frank Nimphius
    Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} The following drag-and-drop problem has been reported on OTN: An ADF Faces tree component is configured with a af:collectionDropTarget tag to handle drop events. The same tree component also has a context menu defined that is shown when users select the tree with the right mouse button. The problem now was - and I could reproduce this - that the context menu stopped working after the first time the tree handled a drop event. The drag and drop use case is to associate employees from a table to a department in the tree using drag and drop. The drop handler code in the managed bean looked up the tree node that received the drop event to determine the department ID to assign to the employee. For this code similar to the one shown below was used List dropRowKey = (List) dropEvent.getDropSite(); //if no dropsite then drop area was not a data area if(dropRowKey == null){    return DnDAction.NONE; }                tree.setRowKey(dropRowKey); JUCtrlHierNodeBinding dropNode = (JUCtrlHierNodeBinding) tree.getRowData(); Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} So what happens in this code? The drop event contains the dropSite reference, which is the row key of the tree node that received the drop event. The code then sets the key to the tree in a call to getRowDate() returns the node information for the drop target (the department). This however causes the tree state to go out of synch with its model (ADF tree binding), which is known to cause issues. In this use case the issue caused by this is that the context menu no longer shows up. To fix the problem, the code needs to be changes to read the current row key from the key, then perform the drop operation and at the end set the origin (or model) row key back //memorize current row key Object currentRowKey = tree.getRowKey();        List dropRowKey = (List) dropEvent.getDropSite(); //if no dropsite then drop area was not a data area if(dropRowKey == null){   return DnDAction.NONE;   }              tree.setRowKey(dropRowKey); JUCtrlHierNodeBinding dropNode = (JUCtrlHierNodeBinding) tree.getRowData(); ... do your stuff here .... //set current row key back tree.setRowKey(currentRowKey); AdfFacesContext.getCurrentInstance().addPartialTarget(tree); Node the code line that sets the row key back to its original value.

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  • Using antlr and the DLR together -- AST conversion

    - by RCIX
    I have an AST generated via ANTLR, and I need to convert it to a DLR-compatible one (Expression Trees). However, it would seem that i can't use tree pattern matchers for this as expression trees need their subtrees at instantiation (which i can't get). What solution would be best for me to use?

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  • How do I replace XmlTreeLoader in Ext JS?

    - by stinkycheeseman
    Ext.ux.xmltreeloader is now deprecated and I'm trying to update it but I'm not sure exactly how to do so. Here's my code: rmg.sscp.search.xmlLoader = Ext.extend(Ext.ux.tree.XmlTreeLoader, { processAttributes : function(attr){ var text = attr.tagName; attr.text = text + ' ' + attr.textContent; attr.loaded = true; attr.expanded = true; } });

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  • Alpha-Beta cutoff

    - by Becky
    I understand the basics of this search, however the beta cut-off part is confusing me, when beta <= value of alphabeta I can either return beta, break, or continue the loop. return beta doesn't seem to work properly at all, it returns the wrong players move for a different state of the board (further into the search tree) break seems to work correctly, it is very fast but it seems a bit TOO fast continue is a lot slower than break but it seems more correct...I'm guessing this is the right way but pseudocode on google all use 'break' but because this is pseudocode I'm not sure what they mean by 'break'

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  • Recursive N-way merge/diff algorithm for directory trees?

    - by BobMcGee
    What algorithms or Java libraries are available to do N-way, recursive diff/merge of directories? I need to be able to generate a list of folder trees that have many identical files, and have subdirectories with many similar files. I want to be able to use 2-way merge operations to quickly remove as much redundancy as possible. Goals: Find pairs of directories that have many similar files between them. Generate short list of directory pairs that can be synchronized with 2-way merge to eliminate duplicates Should operate recursively (there may be nested duplicates of higher-level directories) Run time and storage should be O(n log n) in numbers of directories and files Should be able to use an embedded DB or page to disk for processing more files than fit in memory (100,000+). Optional: generate an ancestry and change-set between folders Optional: sort the merge operations by how many duplicates they can elliminate I know how to use hashes to find duplicate files in roughly O(n) space, but I'm at a loss for how to go from this to finding partially overlapping sets between folders and their children. EDIT: some clarification The tricky part is the difference between "exact same" contents (otherwise hashing file hashes would work) and "similar" (which will not). Basically, I want to feed this algorithm at a set of directories and have it return a set of 2-way merge operations I can perform in order to reduce duplicates as much as possible with as few conflicts possible. It's effectively constructing an ancestry tree showing which folders are derived from each other. The end goal is to let me incorporate a bunch of different folders into one common tree. For example, I may have a folder holding programming projects, and then copy some of its contents to another computer to work on it. Then I might back up and intermediate version to flash drive. Except I may have 8 or 10 different versions, with slightly different organizational structures or folder names. I need to be able to merge them one step at a time, so I can chose how to incorporate changes at each step of the way. This is actually more or less what I intend to do with my utility (bring together a bunch of scattered backups from different points in time). I figure if I can do it right I may as well release it as a small open source util. I think the same tricks might be useful for comparing XML trees though.

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  • BST insert operation. don't insert a node if a duplicate exists already

    - by jeev
    the following code reads an input array, and constructs a BST from it. if the current arr[i] is a duplicate, of a node in the tree, then arr[i] is discarded. count in the struct node refers to the number of times a number appears in the array. fi refers to the first index of the element found in the array. after the insertion, i am doing a post-order traversal of the tree and printing the data, count and index (in this order). the output i am getting when i run this code is: 0 0 7 0 0 6 thank you for your help. Jeev struct node{ int data; struct node *left; struct node *right; int fi; int count; }; struct node* binSearchTree(int arr[], int size); int setdata(struct node**node, int data, int index); void insert(int data, struct node **root, int index); void sortOnCount(struct node* root); void main(){ int arr[] = {2,5,2,8,5,6,8,8}; int size = sizeof(arr)/sizeof(arr[0]); struct node* temp = binSearchTree(arr, size); sortOnCount(temp); } struct node* binSearchTree(int arr[], int size){ struct node* root = (struct node*)malloc(sizeof(struct node)); if(!setdata(&root, arr[0], 0)) fprintf(stderr, "root couldn't be initialized"); int i = 1; for(;i<size;i++){ insert(arr[i], &root, i); } return root; } int setdata(struct node** nod, int data, int index){ if(*nod!=NULL){ (*nod)->fi = index; (*nod)->left = NULL; (*nod)->right = NULL; return 1; } return 0; } void insert(int data, struct node **root, int index){ struct node* new = (struct node*)malloc(sizeof(struct node)); setdata(&new, data, index); struct node** temp = root; while(1){ if(data<=(*temp)->data){ if((*temp)->left!=NULL) *temp=(*temp)->left; else{ (*temp)->left = new; break; } } else if(data>(*temp)->data){ if((*temp)->right!=NULL) *temp=(*temp)->right; else{ (*temp)->right = new; break; } } else{ (*temp)->count++; free(new); break; } } } void sortOnCount(struct node* root){ if(root!=NULL){ sortOnCount(root->left); sortOnCount(root->right); printf("%d %d %d\n", (root)->data, (root)->count, (root)->fi); } }

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  • Translate C# code into AST?

    - by Erik Forbes
    Is it currently possible to translate C# code into an Abstract Syntax Tree? Edit: some clarification; I don't necessarily expect the compiler to generate the AST for me - a parser would be fine, although I'd like to use something "official." Lambda expressions are unfortunately not going to be sufficient given they don't allow me to use statement bodies, which is what I'm looking for.

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  • SQL: Recursive Path

    - by Chris
    Is it possible to create a "tree resolver" in SQL? I have a table: ID Name Parent 1 a 2 b 1 3 c 1 4 d 3 Now I want a SQL query that returns: ID PATH 1 /a 2 /a/b 3 /a/c 4 /a/c/d Is this possible with SQL? It would make many things easier for me. Any help would really be appreciated!

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  • AST generation for a an application developed both in visual basic and c#

    - by Dev
    Hi, I'm currently understanding one application developed both in visual basic and c#. Running through the code is getting tough as code is around 50KLOC. So i'm planning for generation of AST (abstract syntax tree). Will it be possible to generate for both language together. Atleast a call graph generation will be helpful (but can't find any tool which works for both languages) Please let me know if this question is confusing. Thanks in Advance Dev

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  • How to get all objects with their children using django orm?

    - by kender
    Hi, I got very simple hierarchical structure: every object can have 0 or 1 parent. There's no limit on how many children each object can have. So in my application I got such a model: class O(Model): name = CharField(max_length = 20) parent = ForeignKey('O', related_name = 'children') Now I would like to be able to fetch all objects who have a particular one Object1 in their parent-tree (as in their parent or parent of their parents, etc). Should I use mptt or is there a simpler approach?

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  • Getting all database entries into organized array

    - by Industrial
    Hi everyone, I have just made the update/add/delete part for the "Closure table" way of organizing query hierarchical data that are shown on page 70 in this slideshare: http://www.slideshare.net/billkarwin/sql-antipatterns-strike-back However, I have a bit of an issue getting the full tree back as an multidimensional array from a single query. Here's what I would like to get back: array ( 'topvalue' = array ( 'Subvalue', 'Subvalue2', 'Subvalue3' = array ('Subvalue 1', 'Subvalue 2', 'Subvalue 3' ) ); );

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  • m-estimate for continuous values

    - by Null
    I'm building a custom regression tree and want to use m-estimate for pruning. Does anyone know how to calculate that. http://www.ailab.si/blaz/predavanja/UISP/slides/uisp07-RegTrees.ppt might help (slide 12, how should Em look like?)

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  • Return extra data besides tree data from ExtJS TreeLoader dataUrl?

    - by Chad Johnson
    I asked this question in the Ext JS forums, but I received no responses, so I am asking here. I have a TreePanel (code below) that uses a TreeLoader and an AsyncTreeNode. In my API method specified by the TreeLoader's dataUrl, I return a JSON array to populate the tree. This works great, of course. However, I need to return an additional item--an integer--in addition to the array, and I need to display that value somewhere else in my UI. Is this possible? If not, what else would be a good solution? Here's the code I have currently: tree = new Ext.tree.TreePanel({ enableDD: true, rootVisible: false, useArrows: true, loader: new Ext.tree.TreeLoader({ dataUrl: '/api/method' }), root: new Ext.tree.AsyncTreeNode() });

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  • Is it possible to find the KNN for a node that is *IN* the KD-tree?

    - by Stephen
    Hi there, Trying to create a KNN search using a KD-tree. I can form the KD-tree fine (or at least, I believe I can!). My problem is that I am searching to find the closest 2 neighbours to every point in a list of points. So, is there a method to find the K nearest neighbours to a point using a KD tree even if the point is actually IN the tree, or do I need to construct a seperate KD tree for each point, leaving out the point that I wish to search for? My implementation language is C++, but I am more looking for either an algorithm or general help, thanks! Thanks, Stephen

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  • How to see if type is instance of a class in Haskell?

    - by Raekye
    I'm probably doing this completely wrong (the unhaskell way); I'm just learning so please let me know if there's a better way to approach this. Context: I'm writing a bunch of tree structures. I want to reuse my prettyprint function for binary trees. Not all trees can use the generic Node/Branch data type though; different trees need different extra data. So to reuse the prettyprint function I thought of creating a class different trees would be instances of: class GenericBinaryTree a where is_leaf :: a -> Bool left :: a -> a node :: a -> b right :: a -> a This way they only have to implement methods to retrieve the left, right, and current node value, and prettyprint doesn't need to know about the internal structure. Then I get down to here: prettyprint_helper :: GenericBinaryTree a => a -> [String] prettyprint_helper tree | is_leaf tree = [] | otherwise = ("{" ++ (show (node tree)) ++ "}") : (prettyprint_subtree (left tree) (right tree)) where prettyprint_subtree left right = ((pad "+- " "| ") (prettyprint_helper right)) ++ ((pad "`- " " ") (prettyprint_helper left)) pad first rest = zipWith (++) (first : repeat rest) And I get the Ambiguous type variable 'a0' in the constraint: (Show a0) arising from a use of 'show' error for (show (node tree)) Here's an example of the most basic tree data type and instance definition (my other trees have other fields but they're irrelevant to the generic prettyprint function) data Tree a = Branch (Tree a) a (Tree a) | Leaf instance GenericBinaryTree (Tree a) where is_leaf Leaf = True is_leaf _ = False left (Branch left node right) = left right (Branch left node right) = right node (Branch left node right) = node I could have defined node :: a -> [String] and deal with the stringification in each instance/type of tree, but this feels neater. In terms of prettyprint, I only need a string representation, but if I add other generic binary tree functions later I may want the actual values. So how can I write this to work whether the node value is an instance of Show or not? Or what other way should I be approaching this problem? In an object oriented language I could easily check whether a class implements something, or if an object has a method. I can't use something like prettyprint :: Show a => a -> String Because it's not the tree that needs to be showable, it's the value inside the tree (returned by function node) that needs to be showable. I also tried changing node to Show b => a -> b without luck (and a bunch of other type class/preconditions/whatever/I don't even know what I'm doing anymore).

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