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  • Problems using HibernateTemplate: java.lang.NoSuchMethodError: org.hibernate.SessionFactory.openSession()Lorg/hibernate/classic/Session;

    - by user2104160
    I am quite new in Spring world and I am going crazy trying to integrate Hibernate in Spring application using HibernateTemplate abstract support class I have the following class to persist on database table: package org.andrea.myexample.HibernateOnSpring.entity; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.GenerationType; import javax.persistence.Id; import javax.persistence.Table; @Entity @Table(name="person") public class Person { @Id @GeneratedValue(strategy=GenerationType.AUTO) private int pid; private String firstname; private String lastname; public int getPid() { return pid; } public void setPid(int pid) { this.pid = pid; } public String getFirstname() { return firstname; } public void setFirstname(String firstname) { this.firstname = firstname; } public String getLastname() { return lastname; } public void setLastname(String lastname) { this.lastname = lastname; } } Next to it I have create an interface named PersonDAO in wich I only define my CRUD method. So I have implement this interface by a class named PersonDAOImpl that also extend the Spring abstract class HibernateTemplate: package org.andrea.myexample.HibernateOnSpring.dao; import java.util.List; import org.andrea.myexample.HibernateOnSpring.entity.Person; import org.springframework.orm.hibernate3.support.HibernateDaoSupport; public class PersonDAOImpl extends HibernateDaoSupport implements PersonDAO{ public void addPerson(Person p) { getHibernateTemplate().saveOrUpdate(p); } public Person getById(int id) { // TODO Auto-generated method stub return null; } public List<Person> getPersonsList() { // TODO Auto-generated method stub return null; } public void delete(int id) { // TODO Auto-generated method stub } public void update(Person person) { // TODO Auto-generated method stub } } (at the moment I am trying to implement only the addPerson() method) Then I have create a main class to test the operation of insert a new object into the database table: package org.andrea.myexample.HibernateOnSpring; import org.andrea.myexample.HibernateOnSpring.dao.PersonDAO; import org.andrea.myexample.HibernateOnSpring.entity.Person; import org.springframework.context.ApplicationContext; import org.springframework.context.support.ClassPathXmlApplicationContext; public class MainApp { public static void main(String[] args) { ApplicationContext context = new ClassPathXmlApplicationContext("Beans.xml"); System.out.println("Contesto recuperato: " + context); Person persona1 = new Person(); persona1.setFirstname("Pippo"); persona1.setLastname("Blabla"); System.out.println("Creato persona1: " + persona1); PersonDAO dao = (PersonDAO) context.getBean("personDAOImpl"); System.out.println("Creato dao object: " + dao); dao.addPerson(persona1); System.out.println("persona1 salvata nel database"); } } As you can see the PersonDAOImpl class extends HibernateTemplate so I think that it have to contain the operation of setting of the sessionFactory... The problem is that when I try to run this MainApp class I obtain the following exception: Exception in thread "main" java.lang.NoSuchMethodError: org.hibernate.SessionFactory.openSession()Lorg/hibernate/classic/Session; at org.springframework.orm.hibernate3.SessionFactoryUtils.doGetSession(SessionFactoryUtils.java:323) at org.springframework.orm.hibernate3.SessionFactoryUtils.getSession(SessionFactoryUtils.java:235) at org.springframework.orm.hibernate3.HibernateTemplate.getSession(HibernateTemplate.java:457) at org.springframework.orm.hibernate3.HibernateTemplate.doExecute(HibernateTemplate.java:392) at org.springframework.orm.hibernate3.HibernateTemplate.executeWithNativeSession(HibernateTemplate.java:374) at org.springframework.orm.hibernate3.HibernateTemplate.saveOrUpdate(HibernateTemplate.java:737) at org.andrea.myexample.HibernateOnSpring.dao.PersonDAOImpl.addPerson(PersonDAOImpl.java:12) at org.andrea.myexample.HibernateOnSpring.MainApp.main(MainApp.java:26) Why I have this problem? how can I solve it? To be complete I also insert my pom.xml containing my dependencies list: <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd"> <modelVersion>4.0.0</modelVersion> <groupId>org.andrea.myexample</groupId> <artifactId>HibernateOnSpring</artifactId> <version>0.0.1-SNAPSHOT</version> <packaging>jar</packaging> <name>HibernateOnSpring</name> <url>http://maven.apache.org</url> <properties> <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding> </properties> <dependencies> <dependency> <groupId>junit</groupId> <artifactId>junit</artifactId> <version>3.8.1</version> <scope>test</scope> </dependency> <!-- Dipendenze di Spring Framework --> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-core</artifactId> <version>3.2.1.RELEASE</version> </dependency> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-beans</artifactId> <version>3.2.1.RELEASE</version> </dependency> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-context</artifactId> <version>3.2.1.RELEASE</version> </dependency> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-context-support</artifactId> <version>3.2.1.RELEASE</version> </dependency> <dependency> <!-- Usata da Hibernate 4 per LocalSessionFactoryBean --> <groupId>org.springframework</groupId> <artifactId>spring-orm</artifactId> <version>3.2.0.RELEASE</version> </dependency> <!-- Dipendenze per AOP --> <dependency> <groupId>cglib</groupId> <artifactId>cglib</artifactId> <version>2.2.2</version> </dependency> <!-- Dipendenze per Persistence Managment --> <dependency> <!-- Apache BasicDataSource --> <groupId>commons-dbcp</groupId> <artifactId>commons-dbcp</artifactId> <version>1.4</version> </dependency> <dependency> <!-- MySQL database driver --> <groupId>mysql</groupId> <artifactId>mysql-connector-java</artifactId> <version>5.1.23</version> </dependency> <dependency> <!-- Hibernate --> <groupId>org.hibernate</groupId> <artifactId>hibernate-core</artifactId> <version>4.1.9.Final</version> </dependency> </dependencies> </project>

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  • Stack Overflow-like Open Source Question and Answer Systems in php

    - by creativz
    Hey, I'm searching for an open source Question and Answer System that's writting in php/mysql. The only one I found is http://www.question2answer.org but it lacks important features like deleting a question/user...It's still in its beginnings. I know that there is http://osqa.net and http://shapado.com but they are not written in php. Anybody can help me out? Thanks!

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  • XML Schema (XSD) to Rails ActiveRecord Mapping?

    - by Incomethax
    I'm looking for a way to convert an XML Schema definition file into an ActiveRecord modeled database. Does anyone know of a tool that happens to do this? So far the best way I've found is to first load the XSD into an RDBMS like postgres or mysql and then have rails connect to do a rake db:schema:dump. This however, only leaves me with a database without rails Models. What would be the best way to import/load this xsd based database into rails?

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  • How should be test with phpunit for xss + sql injection?

    - by Yosef
    Hi, How should be test with phpunit php web application for xss + sql injection? I thinking to find program that output xss+ other attacks to test my application forms. This program/service should be all time updated with new xss and other new attacks. Does such service/program exist, if not how it done today? Please give some examples if you can. (I use php 5.3 + zend framework + mysql) Thanks, Yosef

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  • How to open multiple viewer windows in Toad?

    - by RemotecUk
    Im sure this is pretty simple but I just cant seem to find the option. My Toad MySql install only seems to allow me to have one "Viewer" window open and hence its impossible to view multiple tables - or have a window open for each table Im working with. Does anyone know how to change this?

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  • CakePHP Test Fixtures Drop My Tables Permanently After Running A Test Case

    - by Frank
    I'm not sure what I've done wrong in my CakePHP unit test configuration. Every time I run a test case, the model tables associated with my fixtures are missing form my test database. After running an individual test case I have to re-import my database tables using phpMyAdmin. Here are the relevant files: This is the class I'm trying to test comment.php. This table is dropped after the test. App::import('Sanitize'); class Comment extends AppModel{ public $name = 'Comment'; public $actsAs = array('Tree'); public $belongsTo = array('User' => array('fields'=>array('id', 'username'))); public $validate = array( 'text' = array( 'rule' =array('between', 1, 4000), 'required' ='true', 'allowEmpty'='false', 'message' = "You can't leave your comment text empty!") ); database.php class DATABASE_CONFIG { var $default = array( 'driver' = 'mysql', 'persistent' = false, 'host' = 'project.db', 'login' = 'projectman', 'password' = 'projectpassword', 'database' = 'projectdb', 'prefix' = '' ); var $test = array( 'driver' = 'mysql', 'persistent' = false, 'host' = 'project.db', 'login' = 'projectman', 'password' = 'projectpassword', 'database' = 'testprojectdb', 'prefix' = '' ); } My comment.test.php file. This is the table that keeps getting dropped. <?php App::import('Model', 'Comment'); class CommentTestCase extends CakeTestCase { public $fixtures = array('app.comment', 'app.user'); function start(){ $this-Comment =& ClassRegistry::init('Comment'); $this-Comment-useDbConfig = 'test_suite'; } This is my comment_fixture.php class: <?php class CommentFixture extends CakeTestFixture { var $name = "Comment"; var $import = 'Comment'; } And just in case, here is a typical test method in the CommentTestCase class function testMsgNotificationUserComment(){ $user_id = '1'; $submission_id = '1'; $parent_id = $this-Comment-commentOnModel('Submission', $submission_id, '0', $user_id, "Says: A"); $other_user_id = '2'; $msg_id = $this-Comment-commentOnModel('Submission', $submission_id, $parent_id, $other_user_id, "Says: B"); $expected = array(array('Comment'=array('id'=$msg_id, 'text'="Says: B", 'submission_id'=$submission_id, 'topic_id'='0', 'ack'='0'))); $result = $this-Comment-getMessages($user_id); $this-assertEqual($result, $expected); } I've been dealing with this for a day now and I'm starting to be put off by CakePHP's unit testing. In addition to this issue -- Servral times now I've had data inserted into by 'default' database configuration after running tests! What's going on with my configuration?!

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  • Storing Icons and Sql with PHP

    - by Ole Jak
    So I have a simple Apache with MySql I am developing a PHP app. I have Users Table in my DB. I vant to let them store Icons. My question Is what's the best way of attaching such data as icons (100-250kb's) to DB - Is it beter to store them Inside DB or store them as File and some how attaching links to icons into DB. What's the best way? Are there any classes that automate this process (of attaching such data to DB)?

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  • Connect two database from 2 different host

    - by Maggie
    Hi, currently I have two websites: 1. A website connected to mySQL database in host A. 2. A website connected to Ms. Access database in Host B. Is there anyway if I update the database in Host B, the database in Host A can be updated automatically? Thank you. Really appreciate your help.

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  • FileFinder using SQL

    - by James Morgan
    I was thinking of working on a project while I have some free time and this one looks pretty nice: http://mindprod.com/project/filefinder.html One thing I'm wondering about is that will it really be much faster compared to the regular windows search if I use SQL? I'm planning to use MySQL since it's open source. Also, do I need to be good at databases for this? I have basic knowledge about relational databases and can definitely make some SQL statements. Thanks.

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  • Iphone web application

    - by Sunil
    Hi All, I am developing a iphone web application. I already have a website designed using php and mysql. how I can convert this website to compatile for iphone. pls share your thoughts. Thanks

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  • JavaScript Concat

    - by nobosh
    Via jquery / Javascript Given a number 1234567891234 How can I concat, or truncast By removing the 2 from the left to make that number a valid integer I can insert into MySQL:' 4567891234 Thanks

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  • Zero Downtime with Hibernate

    - by Stephan Schmidt
    What changes to a database (MySQL in this case) does Hibernate survive (data, schema, ...)? I ask this because of zero downtime with Hibernate. Change database, split app servers into two clusters, redeploy the application on one of the clusters and switch application. Thanks Stephan

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  • Free desktop client for Oracle?

    - by pugmarx
    Which is the best Open Source free client for querying an Oracle database? It may additionally support other databases (MySQL, Postgres etc), since our development environment often requires switching between different databases.

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  • How do I convert Windows 7 file-name encoding to UTF-8 for Ruby on Rails?

    - by Reilly
    Hi (Ive looked at the other questions - none seemed to quite fit my problem.) I have some file-names under Windows 7 that need to be translated in to MySQL database (UTF-8) with Ruby on Rails. An example file-name includes "íéó" in some kind of Windows 7 file-system encoding. Ive tried many combinations of gsub and ActiveSupport::Multibyte::Chars. Thanks for the help

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  • How to use second level cache for lazy loaded collections in Hibernate?

    - by Chandru
    Let's say I have two entities, Employee and Skill. Every employee has a set of skills. Now when I load the skills lazily through the Employee instances the cache is not used for skills in different instances of Employee. Let's Consider the following data set. Employee - 1 : Java, PHP Employee - 2 : Java, PHP When I load Employee - 2 after Employee - 1, I do not want hibernate to hit the database to get the skills and instead use the Skill instances already available in cache. Is this possible? If so how? Hibernate Configuration <session-factory> <property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property> <property name="hibernate.connection.password">pass</property> <property name="hibernate.connection.url">jdbc:mysql://localhost/cache</property> <property name="hibernate.connection.username">root</property> <property name="hibernate.dialect">org.hibernate.dialect.MySQLInnoDBDialect</property> <property name="hibernate.cache.use_second_level_cache">true</property> <property name="hibernate.cache.use_query_cache">true</property> <property name="hibernate.cache.provider_class">net.sf.ehcache.hibernate.EhCacheProvider</property> <property name="hibernate.hbm2ddl.auto">update</property> <property name="hibernate.show_sql">true</property> <mapping class="org.cache.models.Employee" /> <mapping class="org.cache.models.Skill" /> </session-factory> The Entities with imports, getters and setters Removed @Entity @Table(name = "employee") @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) public class Employee { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private int id; private String name; public Employee() { } @ManyToMany @JoinTable(name = "employee_skills", joinColumns = @JoinColumn(name = "employee_id"), inverseJoinColumns = @JoinColumn(name = "skill_id")) @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) private List<Skill> skills; } @Entity @Table(name = "skill") @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) public class Skill { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private int id; private String name; } SQL for Loading the Second Employee and his Skills Hibernate: select employee0_.id as id0_0_, employee0_.name as name0_0_ from employee employee0_ where employee0_.id=? Hibernate: select skills0_.employee_id as employee1_1_, skills0_.skill_id as skill2_1_, skill1_.id as id1_0_, skill1_.name as name1_0_ from employee_skills skills0_ left outer join skill skill1_ on skills0_.skill_id=skill1_.id where skills0_.employee_id=? In that I specifically want to avoid the second query as the first one is unavoidable anyway.

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  • PHP - CURL vs fopen vs fsocketopen ?

    - by TatMing
    I would write a WordPress plugin to parse all image source and check it's broken link or not. My idea is : Select all post&page's images by regex from MySQL Navigate the image url and get the response header (404 ,403 error etc) print a report Since i don't need actual to download the binary file, so in performance ,compare in CURL , fopen , fsocketopen Which one is worst to use? And one more question, which method can execute in multi-thread?

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  • XML Postback issue

    - by Mikey1980
    I have a script that is designed to parse XML postbacks from Ultracart, right now just dumps it into a MySQL table. The script works fine if I point it to a XML file on my localhost but using 'php://input' it doesn't seem to grabbing anything. My logs show apache returning 200 after the post so I have no idea what could be wrong or how to drill down the issue.. here's the code: $doc = new DOMDocument(); $doc->loadXML($page); $handle = fopen("test2/".time().".xml", "w+"); fwrite($handle,trim($page)); // it doesn't save this either :'( fclose(); require_once('includes/database.php'); $db = new Database('localhost', 'user', 'password', 'db_name'); $data = array(); $exports = $doc->getElementsByTagName("export"); foreach ($exports as $export) { $orders = $export->getElementsByTagName("order"); foreach($orders as $order) { $data['order_id'] = $order->getElementsByTagName("order_id")->item(0)->nodeValue; $data['payment_status'] = $order->getElementsByTagName("payment_status")->item(0)->nodeValue; $date_array = explode(" ",$order->getElementsByTagName("payment_date_time")->item(0)->nodeValue); if ($date_array[1] == 'JAN') { $date_array[1] = '01'; } if ($date_array[1] == 'FEB') { $date_array[1] = '02'; } if ($date_array[1] == 'MAR') { $date_array[1] = '03'; } if ($date_array[1] == 'APR') { $date_array[1] = '04'; } if ($date_array[1] == 'MAY') { $date_array[1] = '05'; } // converts Ultracart date to if ($date_array[1] == 'JUN') { $date_array[1] = '06'; } // MySQL date if ($date_array[1] == 'JUL') { $date_array[1] = '07'; } if ($date_array[1] == 'AUG') { $date_array[1] = '08'; } if ($date_array[1] == 'SEP') { $date_array[1] = '09'; } if ($date_array[1] == 'OCT') { $date_array[1] = '10'; } if ($date_array[1] == 'NOV') { $date_array[1] = '11'; } if ($date_array[1] == 'DEC') { $date_array[1] = '12'; } $data['payment_date'] = $date_array[2]."-".$date_array[1]."-".$date_array[0]; $data['payment_time'] = $date_array[3]; //... we'll skip this, there are 80 some elements $data['discount'] = $order->getElementsByTagName("discount")->item(0)->nodeValue; $data['distribution_center_code'] = $order->getElementsByTagName("distribution_center_code")->item(0)->nodeValue; } } } $db->insert('order_history',$data); } else die('ERROR: Token Check Failed!');

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  • Massive SQL issue shutting down our site.

    - by Pselus
    Our website has started timing out like crazy today. All of our clients are finding it unusable. The only error we can seem to trace down as a potential problem is this: SQLAllocHandle on SQL_HANDLE_DBC failed Error ASP Description Error Category Microsoft OLE DB Provider for ODBC Drivers I have no idea what it means or how to go about fixing it. Anyone ever encountered this error before? Currently, you can log in to our site, but then once you go to do anything else, you find yourself logged out or nothing happens. We have a lot of Ajax going on so the "nothing happens" probably has to do with the Ajax pages not loading properly due to logouts and so nothing displays to the user. Like I said, I'm at a loss. Anyone have any advice on this error? EDIT I realize that this isn't necessarily a programming question, but we are a small startup company that just yesterday started talking about how we need to get a backup server running. Apparently we talked about it too late. We don't have a DBA, just 2 mid level programmers trying their hardest to keep our clients happy. So please, if you have any assistance give it but please don't close my question right now. EDIT 2 Turns out we had something on our server running called "ServerMask" that makes our IIS server look like Apache to the outside world. Shutting it down fixed our issue. Still no idea why it was messing up but it was the problem apparently. Thanks to everyone who tried to help.

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  • Cannot populate form with ajax and populate jquery plugin

    - by Azriel_
    I'm trying to populate a form with jquery's populate plugin, but using $.ajax The idea is to retrieve data from my database according to the id in the links (ex of link: get_result_edit.php?id=34), reformulate it to json, return it to my page and fill up the form up with the populate plugin. But somehow i cannot get it to work. Any ideas: here's the code: $('a').click(function(){ $('#updatediv').hide('slow'); $.ajax({ type: "GET", url: "get_result_edit.php", success: function(data) { var $response=$(data); $('#form1').populate($response); } }); $('#updatediv').fadeIn('slow'); return false; whilst the php file states as follow: <?php $conn = new mysqli('localhost', 'XXXX', 'XXXXX', 'XXXXX'); @$query = 'Select * FROM news WHERE id ="'.$_GET['id'].'"'; $stmt = $conn->query($query) or die ($mysql->error()); if ($stmt) { $results = $stmt->fetch_object(); // get database data $json = json_encode($results); // convert to JSON format echo $json; } ?> Now first thing is that the mysql returns a null in this way: is there something wrong with he declaration of the sql statement in the $_GET part? Second is that even if i put a specific record to bring up, populate doesn't populate. Update: I changed the populate library with the one called "PHP jQuery helper functions" and the difference is that finally it says something. finally i get an error saying NO SUCH ELEMENT AS i wen into the library to have a look and up comes the following function function populateFormElement(form, name, value) { // check that the named element exists in the form var name = name; // handle non-php naming var element = form[name]; if(element == undefined) { debug('No such element as ' + name); return false; } // debug options if(options.debug) { _populate.elements.push(element); } } Now looking at it one can see that it should print out also the name, but its not printing it out. so i'm guessing that retrieving the name form the json is not working correctly. Link is at http://www.ocdmonline.org/michael/edit%5Fnews.php with username: Testing and pass:test123 Any ideas?

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  • Can you do RSS feeds on a local server? (PHP)

    - by ggfan
    I am using XAMPP and was wondering if I can code my site to include RSS feeds. Would the codes work and can I test it if I am working on a local server? I am practicing using the OReily head First PHP/Mysql book and I'm on the chapter on RSS and getting RSS videos from youtube.

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  • Pay per view video solution

    - by Bassem Hefny
    Hello, We are planning on building a pay per view (PPV) video solution but we have no idea from where to start. Here are the current givens: it will be hosted on Linux using PHP Database: MySQL And by PPV I mean: - going to website, selecting a movie to watch/download - going to payment portal and paying - being now able to watch/download So here is my question, from where to start? is there an existing (recommended) solution that we can download/buy? Any information would be really appreciated

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