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  • Nginx and Django on Dotcloud

    - by jmetz
    I currently have a dotcloud app that uses django to serve everything. It works great, however, we recently had our site redone in angular.js, and I don't want to use django to serve the actual html pages (I want to just use nginx for that), but I want django to serve some links for the API we built for the angular code to use. Is it possible for me, in the same app, to configure nginx to serve some static files for particular urls, and have it send other urls for django to serve? I want nginx to serve my index.html page is a request comes in to wwww.example.com, but if a request for example.com/api/login/ comes in, I want that to be handled by django. Is this possible?

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  • Is there a 'hello world' website for django? OR (I've installed django, now what) ?

    - by morpheous
    I'm learning Python and decided to start familiarizing myself with the (defacto?) Python web framework - django. I have successfully installed the latest release of django. I want a simple 'hello world' website that will get me up and running quickly. I am already familiar with web frameworks (albeit for different languages) - so I just need a simple 'hello world' example website to help me get going. Ideally, I don't want to mess up with my Apache server settings (as I am still experimenting), so I want to use the lightweight web server that django bundles. I cant seem to find how to do this on the django website though - no doubt someone will post a link and shame me ... So, does anyone know of a link that shows how to get a simple 'hello world' django website up and running with minimal fuss?

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  • Check something before django server starts

    - by Vijay Shankar Kalyanaraman
    I am running my api behind a django server and say I have a one time token that is needed by the django application and used through out its existence until the process quits. To check if I can proceed and serve requests (using the django server) I need to validate this token against a database entry. Now, I can have a script that hits the db, then issues the run server command if the token is valid. But if the db used by the django applications change, I will have to change the script also to point to the same db. Is there a way I can pass this token into the runserver command as an additional parameter (along with hostname:port) and validate this before django serves any requests? How can I access this parameter that is sent into ./manage.py runserver. Thanks.

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  • How to transition from PHP to Python Django?

    - by ggfan
    Here's my background: Decent experience with PHP/MySql. Beginner's experience with OOP Why I want to learn Python Django? I gave in, based on many searches on SO and reading over some of the answers, Python is a great, clean, and structured language to learn. And with the framework Django, it's easier to write codes that are shorter than with PHP Questions Can i do everything in Django as in PHP? Is Django a "big" hit in web development as PHP? I know Python is a great general-purpose language but I'm focused on web development and would like to know how Django ranks in terms of web development.

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  • Why repeat database constraints in models?

    - by BWelfel
    In a CakePHP application, for unique constraints that are accounted for in the database, what is the benefit of having the same validation checks in the model? I understand the benefit of having JS validation, but I believe this model validation makes an extra trip to the DB. I am 100% sure that certain validations are made in the DB so the model validation would simply be redundant. The only benefit I see is the app recognizing the mistake and adjusting the view for the user accordingly (repopulating the fields and showing error message on the appropriate field; bettering the ux) but this could be achieved if there was a constraint naming convention and so the app could understand what the problem was with the save (existing method to do this now?)

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  • Trying to make models in Kohana, relations problem.

    - by Asaf
    I have a table of Hits, Articles and Categories Now, a Hit belongs_to an Article/Category (depends on where it was done). so I have a column on Hits table with the name 'parenttype' That tells me 'Article' or 'Category'. I wrote in the Hit model (extends ORM) protected $_belongs_to= array( 'page' => array('model'=> $this->parenttype) ); Now it complains about $this-parenttype not being expected?

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  • Can I use Visual studio for Python and Django development?

    - by Pankaj Upadhyay
    I have been using Visual Studio for quite some time now, in fact from the VS 2005 version. Right now, I am not only comfortable but addict to using it(VS 2010) for all my development needs. Recently I have been learning Python and Django. In that getting the tutorial tasks up and running with IDLE seems very lame and outdated(I am following the Django Book). Therefore, I downloaded and configured Eclipse & PyDev. Eclipse seems good and fine but needs a bit of learning curve for itself. So, I am looking for a way to configure Visual Studio 2010 for Python and Django development if possible. Please tell me if that's possible and How ?

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  • reddit style voting with django

    - by dotty
    Hay i need to hand implemeneting a voting system into a model. I've had a huge helping hand from Mike DeSimone making this work in the first place, but i need to expand upon his work. Here is my current code View def show_game(request): game = Game.objects.get(pk=1) discussions = game.gamediscussion_set.filter(reply_to=None) d = { 'game':game, 'discussions':discussions } return render_to_response('show_game', d) Template <ul> {% for discussion in discussions %} {{ discussion.html }} {% endfor %} </ul> Model class GameDiscussion(models.Model): game = models.ForeignKey(Game) message = models.TextField() reply_to = models.ForeignKey('self', related_name='replies', null=True, blank=True) created_on = models.DateTimeField(blank=True, auto_now_add=True) userUpVotes = models.ManyToManyField(User, blank=True, related_name='threadUpVotes') userDownVotes = models.ManyToManyField(User, blank=True, related_name='threadDownVotes') def html(self): DiscussionTemplate = loader.get_template("inclusions/discussionTemplate") return DiscussionTemplate.render(Context({ 'discussion': self, 'replies': [reply.html() for reply in self.replies.all()] })) DiscussionTemplate <li> {{ discussion.message }} {% if replies %} <ul> {% for reply in replies %} {{ reply }} {% endfor %} </ul> {% endif %} </li> As you can see we have 2 fields userUpVotes and userDownVotes on the model, these will calculate how to order the discussions and replies. How would i implement these 2 fields to order the replies and discussions based on votes? Any help would be great!

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  • Strange behavior with complex Q object filter queries in Django

    - by HWM-Rocker
    Hi I am trying to write a tagging system for Django, but today I encountered a strange behavior in filter or the Q object (django.db.models.Q). I wrote a function, that converts a search string into a Q object. The next step would be to filter the TaggedObject with these query. But unfortunately I get a strange behavior. when I search (id=20) = Q: (AND: ('tags__tag__id', 20)) and it returns 2 Taged Objects with the ID 1127 and 132 when I search (id=4) = Q: (AND: ('tags__tag__id', 4)) and it returns also 2 Objects, but this time 1180 and 1127 until here is everything fine, but when i make a little bit more complex query like (id=4) or (id=20) = Q: (OR: ('tags__tag__id', 4), ('tags__tag__id', 20)) then it returns 4(!) Objects 1180, 1127, 1127, 132 But the object with the ID 1127 is returned twice, but thats not the behaviour I want. Do I have to live with it, and uniqify that list or can I do something different. The representation of the Q object looks fine for me. But the worst is now, when I search for (id=20) and (id=4) = Q: (AND: ('tags__tag__id', 20), ('tags__tag__id', 4)) then it returns no object at all. But why? The representation should be ok and the object with the id 1127 is tagged by both. What am I missing? Here are also the relevant parts of the classes, that are involved: class TaggedObject(models.Model): """ class that represent a tagged object """ tags = generic.GenericRelation('ObjectTagBridge', blank=True, null=True) class ObjectTagBridge(models.Model): """ Help to connect a generic object to a Tag. """ # pylint: disable-msg=W0232,R0903 content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField() content_object = generic.GenericForeignKey('content_type', 'object_id') tag = models.ForeignKey('Tag') class Tag(models.Model): ... Thanks for your help

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  • Adding a button or link to an inline in Django admin

    - by Lexo
    Hello, I have created the following django models: class Entry(SiteObject): parent = models.ForeignKey(Blog, related_name="entries") content = models.TextField(help_text = "The Content of the blog post") class EntryImage(models.Model): entry = models.ForeignKey(Entry, related_name="entryimages") imagewidth = models.PositiveIntegerField(editable=False,) imageheight = models.PositiveIntegerField(editable=False,) image_file = ImageWithThumbnailsField( #from sorl-thumbnail. Basically a wrapper for an ImageField that generates a thumbnail. upload_to="images/blogs", height_field="imageheight", width_field="imagewidth", help_text = "Select an image to upload.", thumbnail={'size': (360,720)}, generate_on_save=True, ) The EntryImage class shows up as an inline in the admin page for Entry. What I'd like to do is place a link or a button beside each of these inlines that does the following: Save the EntryImage Append <Image x> to the content of the Entry, where x is the number of the EntryImage. This will be replaced by the image's thumbnail using a template filter. Save the Entry Return to editing the Entry I have looked into this, but I just can't wrap my head around where I'm supposed to add this button or link. Has anyone else tried something similar? I've got JQuery available, since I'm using WYMEditor for the content field of the Entry class. Would this help? Thanks in advance, Lexo

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  • Need a workaround to filter on related model and aggregated fields in Django

    - by parxier
    I opened a ticket for this problem. In a nutshell here is my model: class Plan(models.Model): cap = models.IntegerField() class Phone(models.Model): plan = models.ForeignKey(Plan, related_name='phones') class Call(models.Model): phone = models.ForeignKey(Phone, related_name='calls') cost = models.IntegerField() I want to run a query like this one: Phone.objects.annotate(total_cost=Sum('calls__cost')).filter(total_cost__gte=0.5*F('plan__cap')) Unfortunately Django generates bad SQL: SELECT "app_phone"."id", "app_phone"."plan_id", SUM("app_call"."cost") AS "total_cost" FROM "app_phone" INNER JOIN "app_plan" ON ("app_phone"."plan_id" = "app_plan"."id") LEFT OUTER JOIN "app_call" ON ("app_phone"."id" = "app_call"."phone_id") GROUP BY "app_phone"."id", "app_phone"."plan_id" HAVING SUM("app_call"."cost") >= 0.5 * "app_plan"."cap" and errors with: ProgrammingError: column "app_plan.cap" must appear in the GROUP BY clause or be used in an aggregate function LINE 1: ...."plan_id" HAVING SUM("app_call"."cost") >= 0.5 * "app_plan".... Is there any workaround apart from running raw SQL?

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  • Accessing data entered into multiple Django forms and generating them onto a new URL

    - by pedjk
    I have a projects page where users can start up new projects. Each project has two forms. The two forms are: class ProjectForm(forms.Form): Title = forms.CharField(max_length=100, widget=_hfill) class SsdForm(forms.Form): Status = forms.ModelChoiceField(queryset=P.ProjectStatus.objects.all()) With their respective models as follows: class Project(DeleteFlagModel): Title = models.CharField(max_length=100) class Ssd(models.Model): Status = models.ForeignKey(ProjectStatus) Now when a user fills out these two forms, the data is saved into the database. What I want to do is access this data and generate it onto a new URL. So I want to get the "Title" and the "Status" from these two forms and then show them on a new page for that one project. I don't want the "Title" and "Status" from all the projects to show up, just for one project at a time. If this makes sense, how would I do this? I'm very new to Django and Python (though I've read the Django tutorials) so I need as much help as possible. Thanks in advance Edit: The ProjectStatus code is (under models): class ProjectStatus(models.Model): Name = models.CharField(max_length=30) def __unicode__(self): return self.Name

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  • Python/Django Concatenate a string depending on whether that string exists

    - by Douglas Meehan
    I'm creating a property on a Django model called "address". I want address to consist of the concatenation of a number of fields I have on my model. The problem is that not all instances of this model will have values for all of these fields. So, I want to concatenate only those fields that have values. What is the best/most Pythonic way to do this? Here are the relevant fields from the model: house = models.IntegerField('House Number', null=True, blank=True) suf = models.CharField('House Number Suffix', max_length=1, null=True, blank=True) unit = models.CharField('Address Unit', max_length=7, null=True, blank=True) stex = models.IntegerField('Address Extention', null=True, blank=True) stdir = models.CharField('Street Direction', max_length=254, null=True, blank=True) stnam = models.CharField('Street Name', max_length=30, null=True, blank=True) stdes = models.CharField('Street Designation', max_length=3, null=True, blank=True) stdessuf = models.CharField('Street Designation Suffix',max_length=1, null=True, blank=True) I could just do something like this: def _get_address(self): return "%s %s %s %s %s %s %s %s" % (self.house, self.suf, self.unit, self.stex, self.stdir, self.stname, self.stdes, self.stdessuf) but then there would be extra blank spaces in the result. I could do a series of if statements and concatenate within each, but that seems ugly. What's the best way to handle this situation? Thanks.

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  • Re: How can Django/WSGI and PHP share / on Apache?

    - by Bogdan
    in response to: How can Django/WSGI and PHP share / on Apache? Hello, could you please post the complete config file from /sites-available I am having a problem seems like rewrite engine redirects all requests to django, so static and php files are not served and instead i see the django 404 page. If I get rid of rewrite rule then static files and php works. here is my apache config file from /sites-available <VirtualHost *:80> ServerAdmin webmaster@localhost DocumentRoot /home/www/django <Directory /> Options +FollowSymLinks ExecCGI Indexes AllowOverride None DirectoryIndex index.php AddHandler wsgi-script .wsgi </Directory> RewriteEngine On RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^(.*)$ /mysite.wsgi/$1 [QSA,PT,L] ~ and my .wsgi file: import site site.addsitedir('/home/user/.virtualenvs/url.com/lib/python2.6/site-packages') import os, sys path = '/home/www/django' if path not in sys.path: sys.path.append(path) os.environ['DJANGO_SETTINGS_MODULE'] = 'mysite.settings' sys.path.append(path + '/mysite') import django.core.handlers.wsgi _application = django.core.handlers.wsgi.WSGIHandler() import posixpath def application(environ, start_response): # Wrapper to set SCRIPT_NAME to actual mount point. environ['SCRIPT_NAME'] = posixpath.dirname(environ['SCRIPT_NAME']) if environ['SCRIPT_NAME'] == '/': environ['SCRIPT_NAME'] = '' return _application(environ, start_response) the document root directory on disk (/home/www/django) contains php files, images, and the mysite.wsgi file.. thanks for your help

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  • Forward Apache to Django dev server

    - by Alex Jillard
    I'm trying to get apache to forward all requests on port 80 to 127.0.0.1:8000, which is where the django dev server runs. I think I have it forwarding properly, but there must be an issue with 127.0.0.1:8000 not being run by apache? I'm running the django dev server in an ubuntu vmware instance, and I'd other people in the office to see the apps in development without having to promote anything to our actual dev/staging servers. Right now the virtual machine picks up an IP for itself, and when I point a browser to that url with the defualt apache config, I get the default apache page. I've since changed the httpd.conf file to the following to try and get it to forward the requests to the django dev server: ServerName localhost <Proxy *> Order deny,allow Allow from all </Proxy> <VirtualHost *> ServerName localhost ServerAdmin [email protected] ProxyRequests off ProxyPass * http://127.0.0.1:8000 </VirtualHost> All I get are 404s with this, and in error.log I get the following (192.168.1.101 is the IP of my computer 192.168.1.142 is the IP of the virtual machine): [Mon Mar 08 08:42:30 2010] [error] [client 192.168.1.101] File does not exist: /htdocs

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  • Getting a "403 access denied" error instead of serving file (using django, gunicorn nginx)

    - by Finglish
    Getting a "403 access denied" error instead of serving file (using django, gunicorn nginx) I am attempting to use nginx to serve private files from django. For X-Access-Redirect settings I followed the following guide http://www.chicagodjango.com/blog/permission-based-file-serving/ Here is my site config file (/etc/nginx/site-available/sitename): server { listen 80; listen 443 default_server ssl; server_name localhost; client_max_body_size 50M; ssl_certificate /home/user/site.crt; ssl_certificate_key /home/user/site.key; access_log /home/user/nginx/access.log; error_log /home/user/nginx/error.log; location / { access_log /home/user/gunicorn/access.log; error_log /home/user/gunicorn/error.log; alias /path_to/app; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_set_header Host $http_host; proxy_redirect off; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Scheme $scheme; proxy_pass http://127.0.0.1:8000; proxy_connect_timeout 100s; proxy_send_timeout 100s; proxy_read_timeout 100s; } location /protected/ { internal; alias /home/user/protected; } } I then tried using the following in my django view to test the download: response = HttpResponse() response['Content-Type'] = "application/zip" response['X-Accel-Redirect'] = '/protected/test.zip' return response but instead of the file download I get: 403 Forbidden nginx/1.1.19 Please note: I have removed all the personal data from the the config file, so if there are any obvious mistakes not related to my error that is probably why. My nginx error log gives me the following: 2012/09/18 13:44:36 [error] 23705#0: *44 directory index of "/home/user/protected/" is forbidden, client: 80.221.147.225, server: localhost, request: "GET /icbdazzled/tmpdir/ HTTP/1.1", host: "www.icb.fi"

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  • Server Clustering (Django, Apache, Nginx, Postgres)

    - by system-matrix
    I have a project deployed with django, Apache, Nginx and Postgres. The project has requirement of live data viewable to customers. The projects main points are: 1. Devices in field send data to server(devices are also like website users) after login. 2. There is background import process which imports the uploaded data in postgres. 3. The webusers of the system use this data and can send commands to the devices, which devices read when they login. 4. There are also background analysis routines running on the data. All the above mentioned setup and system is deployed on one amazon EC2 cloud machine. The project currently supports over 600 devices and 400 users. But as the number of devices are increasing with time the performance of the server is going down. We want to extend this project so that it can support more and more devices. My initial thinking is, We will create one more server like current one and divide the devices amongst these to servers. But Again We need a central user and device managment point though django admin. Any Ideas? What are the best possible ways to create a scalable architecture? How can I create a Postgres Cluster and Use it with Django, if possible?

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  • EC2 configuration for medium load service on Django

    - by Luberg
    I have created a very basic Django application which puts an email to the database (Coming soon page for a startup). I launched a t1.micro instance to try out which load it can carry out. Nginx+FastCGI from Django+sqllite/postgres - tried both. blitz.io test gave me a pretty unhappy result (just 100 users within 1 minute): This rush generated 542 successful hits in 1.0 min and we transferred 809.01 KB of data in and out of your app. The average hit rate of 8.81/second translates to about 761,612 hits/day. You got bigger problems though: 87.28% of the users during this rush experienced timeouts or errors! I tried both to put varnish, disabled Debub mode in django and started fastcgi in threaded mode - nothing helps. This is not gonna be a super highload page - just a coming soon page to save email of subscribers, it should carry at least 500-1000 users at the same time in peak... I believe t1.micro is super small for that, but I also have tried small instance - not better result.. Please let me know should I use something different from Amazon EC2, or to pick smth better than t1.micro, or I that is definetely a configuration issues?...

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  • safely hosting a django project over apache using centos

    - by tipu
    Error can be seen at: http://djaffry.selfip.com:8080/ I had a project working great, but I had all the files under /var/www/ and with my limited understanding it's bad, according to django's site: "If your background is in PHP, you’re probably used to putting code under the Web server’s document root (in a place such as /var/www). With Django, you don’t do that. It’s not a good idea to put any of this Python code within your Web server’s document root, because it risks the possibility that people may be able to view your code over the Web. That’s not good for security. Put your code in some directory outside of the document root, such as /home/mycode." So I went to /home/tipu/stuff/ and executed django-admin.py startproject twingle. Then I went to apache and did <VirtualHost *:8080> ServerName tweet_search_engine DocumentRoot /home/tipu/stuff/twingle/ </VirtualHost> <Directory /home/tipu/stuff/twingle> SetHandler python-program PythonHandler django.core.handlers.modpython SetEnv DJANGO_SETTINGS_MODULE settings PythonOption django.root /home/tipu/stuff/twingle PythonDebug On PythonPath "['/home/tipu/stuff/', '/home/tipu/stuff/twingle/'] + sys.path" </Directory> Now I am getting a 403 Forbidden error.. any idea what I'm doing wrong? I'm newer to Linux (CentOS) and django, so I could be over looking some very simple things.

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  • eclipse django using wrong settings.py in pythonpath

    - by user1290264
    I have pydev/django installed in eclipse, and it runs fine. However, after adding a second django project to eclipse and running the server ('http://127.0.0.1:8000') the pythonpath seems to be stuck on project2 even when I run project1. As a summary, I have two django projects: project1, project2. When I run the django server for project1 I get: Validating models... 0 errors found Django version 1.5, using settings 'project1.settings' Development server is running at 'http://127.0.0.1:8000/' Quit the server with CTRL-BREAK. The above seems to suggest that django is using the correct settings file; however, when I go to 'http://127.0.0.1:8000/' it displays the urls from project2. Also, if I go to 'http://127.0.0.1:8000/admin' the models are getting pulled from the sqlite.db file in project2 as well. I've even tried removing project2 from eclipse entirely and now at 'http://127.0.0.1:8000/admin' I get this error: Python Path: ['C:\Users\Brad\workspaces\In Progress\project2', 'C:\Users\Brad\workspaces\In Progress\project2', 'C:\Python27\DLLs', 'C:\Python27\lib', 'C:\Python27\lib\plat-win', 'C:\Python27\lib\lib-tk', 'C:\Python27', 'C:\Python27\lib\site-packages', 'C:\Windows\system32\python27.zip'] If I run the server on a different port with project1 the path seems to be fine: runserver 7000 --noreload Then 'http://127.0.0.1:7000/' uses project1's paths, but it doesn't seem like I should have to do this. Note: I have setup the run configurations as correctly as I know how. In the main tab, the project and main module both point to the correct project (project1), and the "PYTHONPATH that will be used in the run:" includes project1. Also, I have cleared my browser history, cookies, and everything that chrome would let me delete.

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  • Use Django ORM as standalone [closed]

    - by KeyboardInterrupt
    Possible Duplicates: Use only some parts of Django? Using only the DB part of Django I want to use the Django ORM as standalone. Despite an hour of searching Google, I'm still left with several questions: Does it require me to set up my Python project with a setting.py, /myApp/ directory, and modules.py file? Can I create a new models.py and run syncdb to have it automatically setup the tables and relationships or can I only use models from existing Django projects? There seems to be a lot of questions regarding PYTHONPATH. If you're not calling existing models is this needed? I guess the easiest thing would be for someone to just post a basic template or walkthrough of the process, clarifying the organization of the files e.g.: db/ __init__.py settings.py myScript.py orm/ __init__.py models.py And the basic essentials: # settings.py from django.conf import settings settings.configure( DATABASE_ENGINE = "postgresql_psycopg2", DATABASE_HOST = "localhost", DATABASE_NAME = "dbName", DATABASE_USER = "user", DATABASE_PASSWORD = "pass", DATABASE_PORT = "5432" ) # orm/models.py # ... # myScript.py # import models.. And whether you need to run something like: django-admin.py inspectdb ... (Oh, I'm running Windows if that changes anything regarding command-line arguments.).

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  • Macports and virtualenv site-packages Fallback

    - by Streeter
    I've installed django and python as this link suggested with macports. However, I'd like to use virtualenv to install more packages. My understanding is that if I do not pass in the --no-site-packages to virtualenv, I should get the currently installed packages in addition to whatever packages I install into the virtual environment. Is this correct? As an example, I've installed django through macports and then create a virtual environment, but I cannot import django from within that virtual environment: [streeter@mordecai]:~$ mkvirtualenv django-test New python executable in django-test/bin/python Installing setuptools............done. ... (django-test)[streeter@mordecai]:~$ pip install django-debug-toolbar Downloading/unpacking django-debug-toolbar Downloading django-debug-toolbar-0.8.4.tar.gz (80Kb): 80Kb downloaded Running setup.py egg_info for package django-debug-toolbar Installing collected packages: django-debug-toolbar Running setup.py install for django-debug-toolbar Successfully installed django-debug-toolbar Cleaning up... (django-test)[streeter@mordecai]:~$ python Python 2.6.1 (r261:67515, Jun 24 2010, 21:47:49) [GCC 4.2.1 (Apple Inc. build 5646)] on darwin Type "help", "copyright", "credits" or "license" for more information. >>> import django Traceback (most recent call last): File "<stdin>", line 1, in <module> ImportError: No module named django >>> So I can install packages into the virtual environment, but it isn't picking up the global site-packages. Or am I not doing something correctly / missing something / misunderstanding how virtualenv works? I've got Mac OS 10.6 (Snow Leopard), have updated my macports packages and am using macports' python26 (via python_select python26).

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  • Django + GAE (Google App Engine) : most convenient path for a beginner?

    - by mac
    Some background info first: Goal: a medium-level complexity web app that I will need to maintain and possibly extend for a few years. Experience: good knowledge of python, some experience of MVC frameworks (in PHP). Desiderata: using django and google app engine. I read extensively about the compatibility issues between GAE and Django, and I am aware of the GAE patch, the norel project, and other similar pieces of code. I have also understood that the SDK provides some of the features of django "out of the box". Yet, given that I have no previous experience with neither Django nor GAE, I am unable to evaluate to which extent using a patched version of Django will strip away important features, or how far the framework provided in the SDK is compatible with Django. So I am rather confused on what would be the best way to proceed in my situation: Should I simply use a patched version of Django as the differences with the original Django are so minor that I would hardly notice them? Should I write my app completely in "regular django" and try to port it to GAE only afterwards, when I will have got a grasp on Django internals and philosophy? Should I write my app using the framework provided with the SDK and port it to django only afterwards? Should I... ? Thank you in advance for your time and advice.

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  • Potential Django Bug In QuerySet.query?

    - by Mike
    Disclaimer: I'm still learning Django, so I might be missing something here, but I can't see what it would be... I'm running Python 2.6.1 and Django 1.2.1. (InteractiveConsole) >>> from myproject.myapp.models import * >>> qs = Identifier.objects.filter(Q(key="a") | Q(key="b")) >>> print qs.query SELECT `app_identifier`.`id`, `app_identifier`.`user_id`, `app_identifier`.`key`, `app_identifier`.`value` FROM `app_identifier` WHERE (`app_identifier`.`key` = a OR `app_identifier`.`key` = b ) >>> Notice that it doesn't put quotes around "a" or "b"! Now, I've determined that the query executes fine. So, in reality, it must be doing so. But, it's pretty annoying that printing out the query prints it wrong. Especially if I did something like this... >>> qs = Identifier.objects.filter(Q(key=") AND") | Q(key="\"x\"); DROP TABLE `app_identifier`")) >>> print qs.query SELECT `app_identifier`.`id`, `app_identifier`.`user_id`, `app_identifier`.`key`, `app_identifier`.`value` FROM `app_identifier` WHERE (`app_identifier`.`key` = ) AND OR `app_identifier`.`key` = "x"); DROP TABLE `app_identifier` ) >>> Which, as you can see, not only creates completely malformed SQL code, but also has the seeds of a SQL injection attack. Now, obviously this wouldn't actually work, for quite a number of reasons (1. The syntax is all wrong, intentionally, to show the oddity of Django's behavior. 2. Django won't actually execute the query like this, it will actually put quotes and slashes and all that in there like it's supposed to). But, this really makes debugging confusing, and it makes me wonder if something's gone wrong with my Django installation. Does this happen for you? If so/not, what version of Python and Django do you have? Any thoughts?

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