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  • Fast permutation -> number -> permutation mapping algorithms

    - by ijw
    I have n elements. For the sake of an example, let's say, 7 elements, 1234567. I know there are 7! = 5040 permutations possible of these 7 elements. I want a fast algorithm comprising two functions: f(number) maps a number between 0 and 5039 to a unique permutation, and f'(permutation) maps the permutation back to the number that it was generated from. I don't care about the correspondence between number and permutation, providing each permutation has its own unique number. So, for instance, I might have functions where f(0) = '1234567' f'('1234567') = 0 The fastest algorithm that comes to mind is to enumerate all permutations and create a lookup table in both directions, so that, once the tables are created, f(0) would be O(1) and f('1234567') would be a lookup on a string. However, this is memory hungry, particularly when n becomes large. Can anyone propose another algorithm that would work quickly and without the memory disadvantage?

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  • Code Golf: Phone Number to Words

    - by Nick Hodges
    Guidelines for code-golf on SO We've all seen phone numbers that are put into words: 1-800-BUY-MORE, etc. What is the shortest amount of code you can write that will produce all the possible combinations of words for a 7 digit US phone number. Input will be a seven digit integer (or string, if that is simpler), and assume that the input is properly formed. Output will be a list of seven character strings that For instance, the number 428-5246 would produce GATJAGM GATJAGN GATJAGO GATJAHM GATJAHN GATJAHO and so on..... Winning criteria will be code from any language with the fewest characters that produce every possible letter combination. Additional Notes: To make it more interesting, words can be formed only by using the letters on a North American Classic Key Pad phone with three letters per number as defined here.That means that Z and Q are excluded. For the number '1', put a space. For the number '0', put a hyphen '-' Bonus points awarded for recognizing output as real English words. Okay, not really. ;-)

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  • Python in command line runs the wrong version?

    - by Deflect
    I have several versions of Python installed on a Windows 7 computer. I want to run Python 2.7 by default, but for whatever reason, typing python in the command line runs Python version 2.4.5. I've tried adding C:\Python27 to my system path variable as per this question, and manually combed my path variable it to make sure Python 2.4.5 wasn't tossed in there by mistake, but that didn't fix the issue. I have to type in C:\Python27\python.exe every time I want to access the correct version of python I want. What other places can I check? How can I make the command line use the correct version of python? I also found this but it's not for windows. [EDIT] My path (separated by semicolons): C:\Program Files\Common Files\Microsoft Shared\Windows Live; C:\Program Files (x86)\Common Files\Microsoft Shared\Windows Live; C:\Windows\system32; C:\Windows; C:\Windows\System32\Wbem; C:\Windows\System32\WindowsPowerShell\v1.0\; C:\Program Files\Dell\DW WLAN Card\Driver; C:\Program Files (x86)\Common Files\Roxio Shared\DLLShared\; C:\Program Files (x86)\Windows Live\Shared; c:\Program Files (x86)\Microsoft SQL Server\100\Tools\Binn\; c:\Program Files\Microsoft SQL Server\100\Tools\Binn\; c:\Program Files\Microsoft SQL Server\100\DTS\Binn\; C:\Program Files\TortoiseGit\bin; C:\Program Files\Java\jdk1.6.0_26\bin; C:\Program Files\Java\jdk1.6.0_21 ; C:\Program Files\IVI Foundation\VISA\Win64\Bin\; C:\Program Files (x86)\IVI Foundation\VISA\WinNT\Bin\; C:\Program Files (x86)\IVI Foundation\VISA\WinNT\Bin; C:\Program Files\WPIJavaCV\OpenCV_2.2.0\bin; C:\Program Files (x86)\LilyPond\usr\bin; C:\Program Files\TortoiseSVN\bin; C:\Program Files (x86)\doxygen\bin; C:\Program Files (x86)\Graphviz 2.28\bin; C:\Users\Michael\bin\Misc\cppcheck\; C:\Program Files (x86)\Git\cmd; C:\Python27\python.exe; C:\Ruby192\bin; C:\Users\Michael\AppData\Roaming\cabal\bin; C:\Python27\; [EDIT 2] Running python spews this out: 'import site' failed; used -v for traceback Python 2.4.5 (#1, Jul 22 2011, 02:01:04) [GCC 4.1.1] on mingw32 Type "help", "copyright", "credits" or "license" for more information. >>> ...and running python --version (as suggested below) seems to be an unrecognized option. (I also tried running python -v, and it appears that Python 2.4 is trying to import libraries from C:\Python27\Lib, and failed due to a syntax error when it encountered a with statement, which was added in later version, I think) Also, I'm not sure if it's significant or not, but the above python version says something about GCC and mingw32, while running C:\python27\python.exe shows this: Python 2.7.2 (default, Jun 12 2011, 15:08:59) [MSC v.1500 32 bit (Intel)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>>>

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  • Remove a file on linux using the inode number

    - by WebDevHobo
    If you create a file on UNIX/linux with special chars, like touch \"la*, you can't remove it with rm "la*. You have to use the inode number(you can if you add the \ before the name, I know, but you'd have to guess as a user that it was used in the file creation). I checked the manpage for rm, but there's no metion of the inode number. Doing rm inodenumber doesn't work either. What is the command for this?

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  • How do I assign a number value to a non-numerical value in Excel

    - by Keyslinger
    Greetings I have an some survey responses with values like "VU" for "Very Unlikely" and "S" for Sometimes. Each survey response occupies a cell. For each cell containing a survey response, I want to fill another cell with a corresponding number. For example, for every cell containing "VU" I want to fill a corresponding cell with the number 1. How is this done?

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  • Show the number of messages within a group in Outlook 2010

    - by Brendan
    In outlook 2010 I am unable to show the number of messages within a particular group. For example, I categorise my messages and then when I sort by category, there is no way to show the number of messages within that(those) category(ies). Previous versions of outlook would do this by default, but I am not finding the setting to do this in Outlook 2010. If it isn't possible, is there anything method to count those messages within a group/category easily?

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  • Tomcat 6 going down after reaching its maximum number of threads

    - by user73628
    Our Tomcat 6.0.29 goes down after reaching its maximum number of Threads. I would really appreciate any help with it because it is a production server. Here is part of the catalina.log file: INFO: Maximum number of threads (600) created for connector with address null and port 80 Mar 8, 2011 11:19:37 AM org.apache.coyote.http11.Http11Protocol pause INFO: Pausing Coyote HTTP/1.1 on http-80 Mar 8, 2011 11:19:38 AM org.apache.catalina.core.StandardService stop INFO: Stopping service Catalina Mar 8, 2011 11:19:38 AM org.apache.catalina.core.StandardWrapper unload INFO: Waiting for 8 instance(s) to be deallocated

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  • How to increase the maximum number of participants in Office Communicator conference

    - by Stephen Jennings
    We often want to make quick announcements to our group of 20 people using Office Communicator, so we highlight a group of contacts and start a new IM session. However, only a maximum of 10 people are able to join the conversation; after the maximum number of people join, all other invitees get the message: Cannot connect to the conference because it is full. Contact the conference leader for more information. Is there a way to increase the maximum number of participants?

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  • Sending a Fax without a fax number

    - by Lynda
    I have an HP Officejet 8600 Pro that has faxing capabilities. However I do not send faxes often and I do not need to pay for a dedicated fax number/line. Is there a way to send and receive faxes using the built in wifi without a fax number from the HP? I have seen online services that allow this from the PC, is that the only way to do this? I am using Windows 7 for my OS. EDIT I do not use a regular phone line.

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  • Varnish, hide port number

    - by George Reith
    My set up is as follows: OS: CentOS 6.2 running on an OpenVZ virtual machine. Web server: Nginx listening on port 8080 Reverse proxy: Varnish listening on port 80 The problem is that Varnish redirects my requests to port 8080 and this appears in the address bar like so http://mysite.com:8080/directory/, causing relative links on the site to include the port number (8080) in the request and thus bypassing Varnish. The site is powered by WordPress. How do I allow Varnish to use Nginx as the backend on port 8080 without appending the port number to the address? Edit: Varnish is set up like so: I have told the Varnish daemon to listen to port 80 by default. VARNISH_VCL_CONF=/etc/varnish/default.vcl # # # Default address and port to bind to # # Blank address means all IPv4 and IPv6 interfaces, otherwise specify # # a host name, an IPv4 dotted quad, or an IPv6 address in brackets. # VARNISH_LISTEN_ADDRESS= VARNISH_LISTEN_PORT=80 # # # Telnet admin interface listen address and port VARNISH_ADMIN_LISTEN_ADDRESS=127.0.0.1 VARNISH_ADMIN_LISTEN_PORT=6082 # # # Shared secret file for admin interface VARNISH_SECRET_FILE=/etc/varnish/secret # # # The minimum number of worker threads to start VARNISH_MIN_THREADS=1 # # # The Maximum number of worker threads to start VARNISH_MAX_THREADS=1000 # # # Idle timeout for worker threads VARNISH_THREAD_TIMEOUT=120 # # # Cache file location VARNISH_STORAGE_FILE=/var/lib/varnish/varnish_storage.bin # # # Cache file size: in bytes, optionally using k / M / G / T suffix, # # or in percentage of available disk space using the % suffix. VARNISH_STORAGE_SIZE=1G # # # Backend storage specification VARNISH_STORAGE="file,${VARNISH_STORAGE_FILE},${VARNISH_STORAGE_SIZE}" # # # Default TTL used when the backend does not specify one VARNISH_TTL=120 The VCL file that Varnish calls (through an include in default.vcl) consists of: backend playwithbits { .host = "127.0.0.1"; .port = "8080"; } acl purge { "127.0.0.1"; } sub vcl_recv { if (req.http.Host ~ "^(.*\.)?playwithbits\.com$") { set req.backend = playwithbits; set req.http.Host = regsub(req.http.Host, ":[0-9]+", ""); if (req.request == "PURGE") { if (!client.ip ~ purge) { error 405 "Not allowed."; } return(lookup); } if (req.url ~ "^/$") { unset req.http.cookie; } } } sub vcl_hit { if (req.http.Host ~ "^(.*\.)?playwithbits\.com$") { if (req.request == "PURGE") { set obj.ttl = 0s; error 200 "Purged."; } } } sub vcl_miss { if (req.http.Host ~ "^(.*\.)?playwithbits\.com$") { if (req.request == "PURGE") { error 404 "Not in cache."; } if (!(req.url ~ "wp-(login|admin)")) { unset req.http.cookie; } if (req.url ~ "^/[^?]+.(jpeg|jpg|png|gif|ico|js|css|txt|gz|zip|lzma|bz2|tgz|tbz|html|htm)(\?.|)$") { unset req.http.cookie; set req.url = regsub(req.url, "\?.$", ""); } if (req.url ~ "^/$") { unset req.http.cookie; } } } sub vcl_fetch { if (req.http.Host ~ "^(.*\.)?playwithbits\.com$") { if (req.url ~ "^/$") { unset beresp.http.set-cookie; } if (!(req.url ~ "wp-(login|admin)")) { unset beresp.http.set-cookie; } } }

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  • Excel changing decimal places on number cells when I edit the cell's formula

    - by IanC
    I have a worksheet with thousands of number cells, all formatted "Number, 3 decimal places, use 1000 Separator ()". Starting a few days ago, if I edit a formula in any of these cells to reference another cell, Excel will change the decimal places to 14. For example, "=C$53^$B$4" = "=C$53^$B$10" will cause this. I am not aware of any settings being changed. Any ideas why this is happening and how to fix this?

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  • How can I match an AWS account number to a key and secret

    - by iwein
    My client gave me a key and a secret to manage his EC2 things, but to make one of my AMI's available to run I have to fill in the Account Number. Is it possible to deduce the account number from the key and the secret? Obviously I also asked the client for this information, but since it's weekend and I'm not fond of waiting I wanted to see if I could figure it out myself. Have you done this before?

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  • Tomcat 6 going down after reaching its maximum number of threads

    - by user73628
    Our Tomcat 6.0.29 goes down after reaching its maximum number of Threads. I would really appreciate any help with it because it is a production server. Here is part of the catalina.log file: INFO: Maximum number of threads (600) created for connector with address null and port 80 Mar 8, 2011 11:19:37 AM org.apache.coyote.http11.Http11Protocol pause INFO: Pausing Coyote HTTP/1.1 on http-80 Mar 8, 2011 11:19:38 AM org.apache.catalina.core.StandardService stop INFO: Stopping service Catalina Mar 8, 2011 11:19:38 AM org.apache.catalina.core.StandardWrapper unload INFO: Waiting for 8 instance(s) to be deallocated

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  • Which OpenGL version is installed?

    - by René Nyffenegger
    I recently tried to lay my hands on OpenGL. Trying to grasp the API, I learned (or was given the advice) that I shouldn't use glBegin and glEnd anymore, since those are deprecated, but should start with OpenGL 3.1, instead. As I didn't know that the version used makes such a difference, I didn't pay much attention as to which version I actually have installed on my computer. And, as far as I can see, there is no glVersion or similar call that I could use to determine that version. I am using MinGW and I found the following lines in c:\MinGW\include\GL\gl.h: /* * Mesa 3-D graphics library * Version: 4.0 [more lines] */ [more lines] #define GL_VERSION_1_1 1 #if !defined(__WIN32__) #define GL_VERSION_1_2 1 #define GL_VERSION_1_3 1 #define GL_ARB_imaging 1 #endif [more lines] #define GL_VERSION 0x1F02 which, to me, indicates, that the installed version is as low as 1.3. Is this the case or how could I verify my suspicion? Also, where would I find a later version if I have 1.3 only?

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  • How to handle application upgrades from free to paid version while preserving any data

    - by cdonner
    Here is the context. I want to have a free version and a premium version of the same application. When people buy the application, I want them to be able to "upgrade" without losing their data, i.e. the premium version should install over the free version. I want to use the same code base and just switch a setting to build the premium version. Andoid Market does not let me convert a free app to a paid app, so the trivial option is not available. I am curious if someone has tried this successfully. How does Android Market identify an application - will it think that the premium version is a different app and just install it in parallel?

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  • T-SQL - Left Outer Joins - Fileters in the where clause versus the on clause.

    - by Greg Potter
    I am trying to compare two tables to find rows in each table that is not in the other. Table 1 has a groupby column to create 2 sets of data within table one. groupby number ----------- ----------- 1 1 1 2 2 1 2 2 2 4 Table 2 has only one column. number ----------- 1 3 4 So Table 1 has the values 1,2,4 in group 2 and Table 2 has the values 1,3,4. I expect the following result when joining for Group 2: `Table 1 LEFT OUTER Join Table 2` T1_Groupby T1_Number T2_Number ----------- ----------- ----------- 2 2 NULL `Table 2 LEFT OUTER Join Table 1` T1_Groupby T1_Number T2_Number ----------- ----------- ----------- NULL NULL 3 The only way I can get this to work is if I put a where clause for the first join: PRINT 'Table 1 LEFT OUTER Join Table 2, with WHERE clause' select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table1 LEFT OUTER join table2 --****************************** on table1.number = table2.number --****************************** WHERE table1.groupby = 2 AND table2.number IS NULL and a filter in the ON for the second: PRINT 'Table 2 LEFT OUTER Join Table 1, with ON clause' select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table2 LEFT OUTER join table1 --****************************** on table2.number = table1.number AND table1.groupby = 2 --****************************** WHERE table1.number IS NULL Can anyone come up with a way of not using the filter in the on clause but in the where clause? The context of this is I have a staging area in a database and I want to identify new records and records that have been deleted. The groupby field is the equivalent of a batchid for an extract and I am comparing the latest extract in a temp table to a the batch from yesterday stored in a partioneds table, which also has all the previously extracted batches as well. Code to create table 1 and 2: create table table1 (number int, groupby int) create table table2 (number int) insert into table1 (number, groupby) values (1, 1) insert into table1 (number, groupby) values (2, 1) insert into table1 (number, groupby) values (1, 2) insert into table2 (number) values (1) insert into table1 (number, groupby) values (2, 2) insert into table2 (number) values (3) insert into table1 (number, groupby) values (4, 2) insert into table2 (number) values (4)

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  • Visual Studio Packaging: Another version of this product is already installed

    - by Sam
    Hi All, I have a msi created for a project which uses C# & Jscript. version-1.0 is currently public. I want to release a bug-fixed version v-1.0.1 of this package but while testing it, I am getting "Another version of this product is already installed Installation of this version cannot continue.To configure or remove the existing version of this product, use Add/Remove program on the Control Panel". I want this bug-fixed version to install silently without asking user to uninstall and install new one. Please help me how can I achieve this, I am using visual studio 2008. Thanks in Advance! Sam

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  • How to open different App version for one given file extension

    - by Erik Lenaerts
    We have a data files with an extension ".ppx" for our business app here. Users will typically have multiple versions of the application installed (side by side) for example version 1 and version 2. The ppx files are xml files and they contain the version of the app they were created from (v1 or v2). Lets say that we have AFileCreatedWithAppv1.ppx and AFileCreatedWithAppv2.ppx opens with version 1 or version 2 of our app respectivly when they both have the same file extension? It must be doable since that is what Visual Studio does. In fact, they even provide different icons for the same .sln extension to indicate what Visual Studio version it will open with. I learned that Visual Studio is using the Selector or Launcher in between, but then again, how do they change the icons in Windows? cheers :)

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  • Specify artifact version outside of pom

    - by Adam B
    Is there a way to specify the artifact version outside of the POM file? I have 2 CI projects that build an artifact. One builds a "stable" development version from a 'develop' branch and the other builds an unstable version which is the result of merging all active feature branches into the develop branch. I want the stable version to build as xyz-1.0.jar and the integration build to go in as xyz-1.0-SNAPSHOT.jar. Is there a way for the CI job to run a maven task or specify via the command line if a release or snapshot jar should be built without manually modifying the POM? Currently I have the version specified as 1.0 in the pom. I considered using the release plugin but I don't want the automatic version number increase and tagging that it does.

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  • Confusion with a while statement evaluating if a number is triangular

    - by Darkkurama
    I've been having troubles trying to figure out how to solve a function. I've been assigned the development of a little programme which tells if a number is "triangular" (a number is triangular when the addition of certain consecutive numbers in the [1,n] interval is n. Following the definition, the number 10 is triangular, because in the [1,10] interval, 1+2+3+4=10). I've coded this so far: class TriangularNumber{ boolean numTriangular(int n) { boolean triangular = false; int i = n; while(n>=0 && triangular){ //UE06 is a class which contains the function "f0", which makes the addition of all the numbers in a determined interval UE06 p = new UE06(); if ((p.f0(1, i))==n) triangular = true; else i=i-1; } return triangular; } boolean testTriangular = numTriangular(10) == true && numTriangular(7) == false && numTriangular(6) == true; public static void main(String[] args){ TriangularNumber p = new TriangularNumber(); System.out.println("testTriangular = " + p.testTriangular); } } According to those boolean tests I made, the function is wrong. As I see the function, it goes like this: I state that the input number in the initial state isn't triangular (triangular=false) and i=n (determining the interval [1,i] where the function is going to be evaluated While n is greater or equals 0 and the number isn't triangular, the loop starts The loop goes like this: if the addition of all the numbers in the [1,i] interval is n, the number is triangular, causing the loop to end. If that statement is false, i goes from i to (i-1), starting the loop again with that particular interval, and so on till the addition is n. I can't spot the error in my "algorithm", any advice? Thanks!

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  • Increment the number of times an article has been read

    - by r.sendecky
    I have a situation where I need to increase the number of time article has been read. Once someone opens an article it should be reflected in the database by incrementing number of reads by one. Simple. Sending POST request to the server increments the number of reads by one. The article in question is supplied via URL parameter. Doing it manually by typing the URL in a browser works as expected. So server side is not at fault. My problems start with the javascript side of it or rather jquery. I hook the event to the article link. So every time a user clicks on the article link it increments the number of reads like so: $('#list-articles .article-link').click(function(e){ var oid = $(this).parent().parent().attr('data-oid').toString(); //Get the article id $.post( "/articles/viewed/" + oid ); }); Now this does not work! Number is not increased. I don't prevent default action since I need the link to actually open and display the article. Now if I put an alert right after the post like this: $('#list-articles .article-link').click(function(e){ var oid = $(this).parent().parent().attr('data-oid').toString(); //Get the article id $.post( "/articles/viewed/" + oid ); alert(oid); }); This variant works. After I dismiss the alert window, the number is incremented. Why is this so?? How can I fix this to actually work without the alert event present?

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  • generate k distinct number less then n

    - by davit-datuashvili
    hi i have following question task is this generate k distinct positive numbers less then n without duplication my method is following first create array size of k where we should write these numbers int a[]=new int[k]; //now i am going to cretae another array where i check if (at given number position is 1 then generate number again else put this number in a array and continue cycle i put here a piece of code and explanations int a[]=new int[k]; int t[]=new int[n+1]; Random r=new Random(); for (int i==0;i<t.length;i++){ t[i]=0;//initialize it to zero } int m=0;//initialize it also for (int i=0;i<a.length;i++){ m=r.nextInt(n);//random element between 0 and n if (t[m]==1){ //i have problem with this i want in case of duplication element occurs repeats this steps afain until there will be different number else{ t[m]=1; x[i]=m; } } so i fill concret my problem if t[m]==1 it means that this element occurs already so i want to generate new number but problem is that number of generated numbers will not be k beacuse if i==0 and occurs duplicate element and we write continue then it will switch at i==1 i need like goto for repeat step or for (int i=0;i<x.length;i++){ loop: m=r.nextInt(n); if ( x[m]==1){ continue loop; } else{ x[m]=1; a[i]=m; continue;//continue next step at i=1 and so on } } i need this code in java please help

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