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  • soap response to xml (simple_xml)

    - by ntan
    Hi i am trying to convert a soap response to XML. Soap has an envelop and a body <soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <soap:Body> When try to convert $responseXML = simplexml_load_string($string); I get object(SimpleXMLElement)#20 (0) { } If i edit the $string as soap-Envelope and soap-Body i can get the XML Whats wrong with : and can not get XML I hope its clear. Anyone

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  • receive xml file via post in php

    - by thegunner
    Hi, I'm looking for a PHP script that can accept an XML file via a POST, then send a response.... Does anyone have any code that could do this? So far the only code I have is this but not sure about the response or if indeed I am even going in the right direction as XML characters are not saved correctly. Any ideas? <?php if ( $_SERVER['REQUEST_METHOD'] === 'POST' ){ $postText = file_get_contents('php://input'); } $datetime=date('ymdHis'); $xmlfile = "myfile" . $datetime . ".xml"; $FileHandle = fopen($xmlfile, 'w') or die("can't open file"); fwrite($FileHandle, $postText); fclose($FileHandle); ?> Thanks,

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  • Opening a new screen from xml file text.

    - by Clozecall
    Hey all I'm looking to edit my app so that when a text within an xml file is selected, a new window opens. I've found various ways of making a new screen open via a class, but I need it done from a xml file. My program as a tablayout, and here is some of the stuff displayed within my first tab: <LinearLayout android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent"> android:id="@+id/ScrollView01" android:layout_height="wrap_content" android:layout_width="fill_parent" <TextView android:textColor="#FFFFFF" android:text="First Header here" android:textStyle="bold" android:layout_width="fill_parent" android:layout_height="wrap_content" /> <TextView android:textColor="#FFFFFF" android:text="First body text here" android:layout_width="fill_parent" android:layout_height="wrap_content" /> So basically I need it so that when a text is selected, a new screen pops up. As said the reason this specifically has to be done in xml is because this is all apart of a tab layout, It would be great if the next within each tab could open a a new screen. Thanks.

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  • Is there any Android XML documentation?

    - by Eddified
    Is there any sort of xml reference? I found this which turned out to be invaluable for me http://groups.google.com/group/android-developers/msg/d334017d72909c79 but I can't figure out how I was supposed to know how to do that, had I not found that post. I know that the api reference has xml attributes listed for many of the classes... but what about xml tags? Where is it documented that I could build a shape using , , tags? I'd really like to know where I can find such documentation.

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  • Python universal feedparser xml

    - by timg
    I am trying to read an xml feed with the python feedparser, but cannot seem to navigate the elements. Here is what I am trying: import feedparser d = feedparser.parse('http://www.website.com/feed') text= d.status.test and here is the xml: <?xml version="1.0" encoding="UTF-8"?> <statuses type="array"> <status> <created>Tue Dec 21 14:16:12 +0000 2010</created> <id>123</id> <text>Hello</text> </status> </statuses>

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  • Parse XML with XPath & namespaces in Java

    - by ripper234
    Can you help me adjust this code so it manages to parse the XML? If I drop the XML namespace it works: String webXmlContent = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n" + "<foo xmlns=\"http://foo.bar/boo\"><bar>baz</bar></foo>"; DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance(); domFactory.setNamespaceAware(true); DocumentBuilder builder = domFactory.newDocumentBuilder(); org.w3c.dom.Document doc = builder.parse(new StringInputStream(webXmlContent)); NamespaceContextImpl namespaceContext = new NamespaceContextImpl(); namespaceContext.startPrefixMapping("foo", "http://www.w3.org/2001/XMLSchema-instance"); XPath xpath = XPathFactory.newInstance().newXPath(); xpath.setNamespaceContext(namespaceContext); XPathExpression expr = xpath.compile("/foo/bar"); Object result = expr.evaluate(doc, XPathConstants.NODESET); NodeList nodes = (NodeList) result; System.out.println("Got " + nodes.getLength() + " nodes");

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  • Processing XML file with Huge data

    - by Manish Dhanotiya
    Hi,be m I am working on an application which has below requiements - 1. Download a ZIP file from a server. 2. Uncompress the ZIP file, get the content (which is in XML format) from this file into a String. 3. Pass this content into another method for parsing and further processing. Now, my concerns here is the XML file may be of Huge size say like '100MB', and my JVM has memory of only 512 MB, so how can I get this content into Chunks and pass for Parsing and then insert the data into PL/SQL tables. Since there can be multiple requests running at the same time and considering 512MB of memory what will be the best possible to process this. How I can get the data into Chunks and pass it as Stream for XML parsing. I googled on this, but didnt find any implementation. :( Thanks,

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  • Accessing XML/PHP with period in tag

    - by LuckyShot
    Hi guys, Quick newbie question here, how do I access totalResults? XML <?xml version="1.0" encoding="UTF-8"?> <OpenSearchDescription> <opensearch:totalResults>1</opensearch:totalResults> <posts> <post> <score>10</score> </post> </posts> </OpenSearchDescription> To access the score I would do this: PHP $xmlObj = simplexml_load_string($theXMLabove); echo $xmlObj->posts->post[0]->score; But none of these work for the totalResults: echo $xmlObj->opensearch:totalResults; echo $xmlObj->opensearch->totalResults; Sorry for asking such a lame question... Documentation on how to traverse XML with PHP is also appreciated :) Thanks!

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  • reading variable from xml file in flex

    - by m0j1
    hi , I'm trying to read the address of a flv file from an xml file and then put it in the "source" property of a videodisplay tag . here's my code : //in decleration tags <fx:Model id="myModel" source="myXML.xml"/> <s:ArrayList id="myArrList" source="{myModel.main}"/> //in the main code <mx:VideoDisplay id="videoDisplay" source="{myArrList.getItemAt(0)}" /> and the xml file is: <main> <myFile>"g:\myflv.flv"</myFile> </main> anyone knows what's wrong? tnx

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  • Tool that auto-generate a code for accesing a xml-file

    - by alex
    My application have a configuration xml-file. That file contains more than 50 program settings. At the present time I read and save each program setting separately. I guess It is not effi?iently for such tasks. I need something that can auto-generate a code for load and save my program settings using predefined xml-schema. I found a dataset in Add New Item dialog. Unfortunately, i cannot add new code to dataset1 such as events in set-accessors of properties because of this // Changes to this file may cause incorrect behavior and will be lost if // the code is regenerated. Maybe, there is a tool that allows a user to generate a wrapper for accesing a xml-file ? Such as DataSet1, but with availability to add events.

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  • Problem with parsing XML into table variable

    - by Stanley Ross
    I'm using the following code to read a SQL XML Variable into a table variable. I am getting the following error. " Incorrect syntax near '.'. " Can't quite Figure it out DECLARE @LOBS Table ( LineGUID varchar(40) ) DECLARE @lg xml SET @lg = '<?xml version="1.0" encoding="utf-16" standalone="yes"?> <Table> <LOB> <LineGuid>d6e3adad-8c53-4768-91a3-745c0dae0e08</LineGuid> </LOB> <LOB> <LineGuid>4406db8f-0d19-47da-953b-afc1db38b124</LineGuid> </LOB> </Table>' INSERT INTO @LOBS(LineGUID) SELECT ParamValues.ID.value('.','VARCHAR(40)') FROM @lg.nodes('/Table/LOB/LineGuid') AS ParamValues(ID)

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  • how to write xsd for the following xml?

    - by Venkats
    <?xml version="1.0"?> <datatype xmlns:xs="http://www.w3.org/2001/XMLSchema-instance" xs:noNamespaceSchemaLocation="sampletype.xsd"> <table name="emp"> <columns> <column> <name>emp_id</name> <data_type>int(200) </data_type> </column> </columns> </table> </datatype> Here i generate the xsd for above xml, but it was not correct. can you help me generate the xsd for the xml? thanks in advance.

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  • Regex for xml parsing

    - by ogmios
    What is your opinon about following regexes - is it correct? To find element with spcific and required attribute "<(" + elem_name + ")(\s+(?:[^<]?\s+)" + attr_name + "\s*=\s*(['\"])((?:(?!\3).))\3[^<])(.*?)" To find element with spcific but optional attribute "<(" + elem_name + ")(\s*|\s+(?:[^<]?\s+)(?:" + attr_name + "\s*=\s*(['\"])((?:(?!\3).))\3)?[^<])(.*?)" Pleas not another answer "use existing xml parser". Question is - are the regexes proper or not? This is specific situation - C language in embedded system and xml is not well-formed (cannot be fixed - does not depend on me). Xml have specified schema and no problem with namespaces etc. exists.

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  • Deserializing different named xml nodes

    - by Andreas
    Hi. Is there a way to convert different named xml nodes into one class when deserializing an XML Example XML: <items> <aaa>value</aaa> <bbb>value</bbb> </items> Normaly i would write: [XmlRoot("items")] class Items { [XmlElement("aaa")] public string aaa; [XmlElement("bbb")] public string bbb; } But now i would like to do something like this [XmlRoot("items")] class Items { [XmlElement("aaa")] [XmlElement("bbb")] public List<string> item; } Here I would love if "aaa" and "bbb" was added to the same list.

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  • OpenOffice/Libre office xml filter import

    - by marechs
    I'm using OpenOffice to convert documents to pdf/xls; Main system where usually is running Openoffice is Linux; There(in openoffice) is such thing as XML filters; A have package of those filters and usually to import this package I using(from launched openoffice): Tools-XML Filter settings -open package; It's like little converting server, but there is one problem - system needs X server to be running; So is there a way to import this XML filter package to Openoffice(or Libre office) from command line?

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  • How can I pass an object as a parameter in the google app engine RPC flow?

    - by jimmartens
    I'm building a pretty basic app, and one thing I want to do is pass an object as a parameter up through the service - async - impl instead of passing up a million separate parameters. so in async, I do something like this: import shared.Profile; ... public interface ProfileServiceAsync { public void addProfile(Profile inProf, AsyncCallback<Void> async); Now, profile is a class in com. ... .shared and I have the following in my ... .gwt.xml <source path='shared'/> That being said when I try to compile I get this error. [ERROR] Errors in 'file:/D:/projects/eclipse/workspace/.../src/com/.../client/ProfileServiceAsync.java' [ERROR] Line 11: No source code is available for type shared.Profile; did you forget to inherit a required module? Any ideas on this?

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  • How to access a subset of XML data in Java when the XML data is too large to fit in memory?

    - by Michael Jones
    What I would really like is a streaming API that works sort of like StAX, and sort of like DOM/JDom. It would be streaming in the sense that it would be very lazy and not read things in until needed. It would also be streaming in the sense that it would read everything forwards (but not backwards). Here's what code that used such an API would look like. URL url = ... XMLStream xml = XXXFactory(url.inputStream()) ; // process each <book> element in this document. // the <book> element may have subnodes. // You get a DOM/JDOM like tree rooted at the next <book>. while (xml.hasContent()) { XMLElement book = xml.getNextElement("book"); processBook(book); } Does anything like this exist?

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  • Modifying SQL XML ?olumn

    - by Chinjoo
    I have an XML column in one of my table. For example I have an Employee table with following fields: Name (varhcar) | Address (XML) The Address field is having values like <Address> <Street></Street> <City></City> </Address> I have some n number of rows already in the table. Now I want to insert a new node - Country to all the rows in tha table. With default: <Country>IND</Country>. How can I write the query for this. I want all the existing data to be as it is with adding the country node to all the Address column XML.

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  • How to serialize this Xml in .NET (array)

    - by Morri
    I need Xml that looks like this <foo> <bar ... /> <bar ... /> </foo> And currently have the following class structure : [XmlRoot("foo")] public class Foo { [XmlArrayItem("bar")] public List<Bar> myBars; } But this gives me Xml where bar items are wrapped inside a bars element. How should I define my custom XmlAttributes so I'd get the Xml structure I need?

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  • how can I enter character "<" in strings.xml?

    - by yrajabi
    I want to enter string " -< " in strings.xml file, the string has character < and I couldn't add it to xml file without error! I even tried to escaping by \ character: <string name="search_target_arrow"> -\< </string> or enclosing it between "" as below: <string name="search_target_arrow">" -< "</string> but none worked. Maybe I'm very amateur at this and the answer is not hard for you. so please tell me how you add such special chars in strings.xml?

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  • javascript xml saving problem

    - by Guru
    hi there, I want to modify some data on XML file residing on server side by using javascript. I'm using following code var xh; if(window.XMLHttpRequest) { xh=new XMLHttpRequest(); } else { xh=new ActiveXObject("Microsoft.XMLHTTP"); } xh.open("get","books.xml",false); xh.send(""); var xdoc=xh.responseXML; var x=xdoc.getElementsByTagName("title"); x[0].getAttributeNode("lang").nodeValue="zh"; xh.save("books.xml"); but its not working Thanks in advance, Guru

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  • populating word doc from xml in c#

    - by shdu1
    how do i populate a word doc from an xml template using c#. I know how to open a blank document but I cant figure out how to populate it. Word.Document wordDoc = wordApp.Documents.Add(ref objMissing, ref objMissing, ref objMissing, ref objMissing); Word.Paragraph wordParagraph = wordDoc.Paragraphs.Add(ref objMissing); Here's a basic look at my xml form. <?xml version="1.0" encoding="utf-8"?> <Cover> <CaseNo>Case No:</CaseNo> <Title>Title:</Title> <Date>Date:</Date> </Cover> What I eventually want to do is get the user to fill in textboxes in a c# program which will populate the word document. PLEASE HELP ME!!! I've been trying to figure this out for days Note the information is not coming from an sql database

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  • Load big XML files to mySQL database (PHP)

    - by Kees
    Hello There, For a new project I need to load big XML files (200MB+) to a mySQL database. There are +- 20 feeds i need to match with that (not all fields are the same). Now when i want to catch the XML I get this error: Fatal error: Allowed memory size of 134217728 bytes exhausted (tried to allocate 171296569 bytes) in E:\UsbWebserver\Root\****\application\libraries\MY_xml.php on line 21 Is there an easy solution for this? It's not possible to get te feed in parts of a few MB's each. Thank you very much! P.s. has somebody an idea to match xml-feeds easy?

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  • Flex 4: Loading XML into a Model Actionsript Class

    - by Steve
    I'm trying to create an actionscript class to serve as a data model for my Flex app. I already have a formatted XML file to read from, and when I was simply declaring the data service in my MXML app I used this code inside the declarations: I'm now trying to create a model class and can't seem to get the same functionality. I've tried importing mx.rpc.http.HTTPService but i think this is different. And using the XML class doesn't seem to allow the ability to define a source url. I'm assuming that I am able to declare a public var inside my class that will read this XML source file as I had done in the main app. If this is possible, how do I do it?

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  • Changing XML Namespace with Scala

    - by toddk
    I am using scala to load a XML file from file via the scala.xml.XML.loadFile() method. The documents I'm working with have namespaces already defined and I wish to change the namespace to something else using scala. For example, a document has a xmlns of "http://foo.com/a" with a prefix of "a" - I would like to change the namespace and prefix for the document to "http://foo.com/b" and "b" respectively. Seems easy and I feel like I'm missing something obvious here. I do not have a problem getting the namespace from the return Elem from the referenced loadFile() method.

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