Search Results

Search found 12055 results on 483 pages for 'password complexity'.

Page 5/483 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

• How do i remove a password expiration policy?

  - by jimmygee

  We had a password expiration policy recently removed from our AD but some users continued to get the "..your password will expire in x days. would you like to change it now?" message. So we added a reverse/undo policy to correct the local registry settings Maximum password age = 0 days Minimum password age = 0 days This hasn't worked as new users still seem to encounter the above "change password" message sporadically. We have now removed all custom password policy GPOs and are left with the "Default Domain Policy". Still no good. Can someone point me in the direction to fix this? And an explanation into what i was doing wrong (/how password expiration policies apply) would be useful too. thanks Environment is 2k3 server with mostly XPsp2 clients.

  Read the article

• Windows 8 Login Password Out of Sync with Windows Live ID

  - by Israel Lopez

  I'm working with a computer that has setup a local account connected under Windows Live ID. The user can login to Live ID (like hotmail) from another computer with the correct credentials. However from the Windows 8 computer using the correct password it indicates. That password is incorrect. Make sure you're using the password for you Mircrosoft Account. You can always reset it at account.live.com/password/reset. Now, I've used NTPASSWD to reset the password, but it seems that since its not a "Local Account" it wont take the new password or blank one. This account also has a "PIN" the user who also has forgotten it. I also tried to enable/password set the local Administrator account but it does not show up for login. Any ideas?

  Read the article

• Password problem while creating domain

  - by Murdock

  Hi, I'm freshman so far in server management stuff but this seems to be clearly against logic. After updating my Windows Server 2008 Standard 32bit, installing DNS server and AD DS I wanted to create domain via using CMD and dcpromo.exe setup. But no matter if I disable demand for comlex password in Password policies or create a password which fully comply with requirements for strong and complex password, still I can't get any further and it says that my password doesn't meet requirements. I'm also asked there to activate password demand by NET USER -passwordreq:yes and when I do so, this password doesn't work any more and I have to remove it from other admin account to be at least able to login with proper Administrator account.

  Read the article

• AD User Passwords expiring without any notifications?

  - by scooter133

  We setup password Policies in Active Directory to Expire peoples passwords after so many days. Well it looks like the time has come for the Expiration of the Passwords and people are getting locked out... There has been no warning of user passwords about to expire. They just come in to work and they cannot log in, the phones no longer connect, nothing. Reset the password and all is good. Some of the users are locked out, though most are not, they just cannot log in. On setting the password Expiration, I didn't see anything about nor warning the users of the impending expiration. Seems like it used to warn you 15 days or so before it would expire. Clients range from: WinXP, WinVista, Win7 and Server 2008R2 Remote Desktop Services. How can I make sure my users are warned of the Expiration? Resultant Set of Policy for User that was not prompted: Account Policies/Password Policy Policy Setting Winning GPO Enforce password history 10 passwords remembered Default Domain Policy Maximum password age 270 days Default Domain Policy Minimum password age 0 days Default Domain Policy Minimum password length 4 characters Default Domain Policy Password must meet complexity requirements Disabled Default Domain Policy Store passwords using reversible encryption Disabled Default Domain Policy Account Policies/Account Lockout Policy Policy Setting Winning GPO Account lockout duration 20 minutes Default Domain Policy Account lockout threshold 5 invalid logon attempts Default Domain Policy Reset account lockout counter after 15 minutes Default Domain Policy Local Policies/Audit Policy Policy Setting Winning GPO Audit account logon events Failure Default Domain Policy Audit account management Success, Failure Default Domain Policy Audit directory service access Success, Failure Default Domain Policy Audit logon events Failure Default Domain Policy Audit policy change Success, Failure Default Domain Policy Audit privilege use Failure Default Domain Policy Local Policies/Security Options Interactive Logon Policy Setting Winning GPO Interactive logon: Prompt user to change password before expiration 7 days Default Domain Policy

  Read the article

• How do I make Empathy match my keyring with my password?

  - by lisalisa

  I changed my password a few months ago from the password I first used when I installed Ubuntu on my machine. I tried to add a Google Talk account to Empathy, but every time Empathy gives me a message saying the following: Enter password to unlock your login keyring The password you use to log in to your computer no longer matches that of your login keyring. I do not remember my original password and I'm not sure if I should go to Prefrences Passwords and Keys and delete my login password or if there is a way to change the keyring so that it matches up with my current password.

  Read the article

• Use Outlook password for website verification

  - by Jack Lockyer

  I am currently building an internal employee dashboard for our global company (it is hosted on an external website for logistical reasons) I'd like (need) to password protect the page as we will be displaying sensitive information, my question is, is it possible to integrate with Outlook passwords? We have over 350 staff all of whom use outlook on a daily basis, I'd love for the website to check whether the visitor is logged into Outlook and if they're not, prompt them to log in. Is it possible?? If it is I'll get is developed straight away.

  Read the article

• Windows XP: Consequences of setting a password for an account

  - by sleske

  I do not quite understand how Windows (specifically Windows XP) handles accounts with/without passwords. As far as I can see, on a fresh Windows XP install I have one default account which has admin rights does not have a password will auto-login (without password prompt) when the computer boots What happens if I set a password for this account? Will it still auto-login? Or will it always prompt for the PW? And generally, what consequences does it have if I set a password? I noted that Scheduled Tasks apparently cannot run under an account w/o password (creating a scheduled task will prompt for the account PW). Is there anything that will not work with a password set? Why is it even possible to have accounts without a password? I have some Unix/Linux background, but the concepts appear a little different under Windows.

  Read the article

• Broke my sudoers password, how do I reset it without using sudo?

  - by Eric Dand

  I thought it would be a good idea to finally take the password off my little netbook since it has never actually been of any use, and has mostly just slowed down . But when I went to change my password, there wasn't even an option to make it blank, and any attempt to make it a few easy characters was met with "Password too weak". So I did what any good geek would do and popped open the terminal, read the manual entry for passwd and quickly used the -d option to remove the password from my account. It all went well for a couple days (I even managed to also make my keychain password blank) until I tried to update the thing. My sudoers password is not blank, and it's not my old password. I have no idea what it is. How do I reset it (or even better, make it blank) without the use of the sudo command?

  Read the article

• problem to change my Xenserver password

  - by Michlaou

  I try to change my root password on my Xenserver 6.0. I follow these steps: enter boot: menu.c32 selecet xe-serial and press tab add "single" before the 2nd triple hyphens and i press enter. I have that: mboot.c32 /boot/xen.gz com1=115200,8n1 console=com1, vga mem=1024G dom0_max_vcpus4 dom0_mem=752M lowmem_emergency_pool=1M crashkernel=64M@32M single --- /boot/vmlinuz-2.6-xen root=LABEL=root-rodraxar ro console=tty0 xencons=hvc console=hvc0 --- /boot/initrd-2.6-xen.img I have commande on the screen and it's stop at: ext3-fs: monted filesystem with ordered data mode. Can you help me?

  Read the article

• Using Completed User Stories to Estimate Future User Stories

  - by David Kaczynski

  In Scrum/Agile, the complexity of a user story can be estimated in story points. After completing some user stories, a programmer or team of programmers can use those experiences to better estimate how much time it might take to complete a future user story. Is there a methodology for breaking down the complexity of user stories into quantifiable or quantifiable attributes? For example, User Story X requires a rich, new view in the GUI, but User Story X can perform most of its functionality using existing business logic on the server. On a scale of 1 to 10, User Story X has a complexity of 7 on the client and a complexity of 2 on the server. After User Story X is completed, someone asks how long would it take to complete User Story Y, which has a complexity of 3 on the client and 6 on the server. Looking at how long it took to complete User Story X, we can make an educated estimate on how long it might take to complete User Story Y. I can imagine some other details: The complexity of one attribute (such as complexity of client) could have sub-attributes, such as number of steps in a sequence, function points, etc. Several other attributes that could be considered as well, such as the programmer's familiarity with the system or the number of components/interfaces involved These attributes could be accumulated into some sort of user story checklist. To reiterate: is there an existing methodology for decomposing the complexity of a user story into complexity of attributes/sub-attributes, or is using completed user stories as indicators in estimating future user stories more of an informal process?

  Read the article

• Password-free logins using your email address only?

  - by Mario

  The state of logins is horrendous. With each site having it's own rules for passwords, it can be very hard to remember what variation you used on any given site. Logins are pure pain. One thing I love about Craigslist is that it did away with logins altogether. I know this design may not suit every site, but there's something to their design that beckons to be repeated. OpenID is great on sites that have adopted it, but it's still not standard. Would it be feasible/wise to use an email address as a login and provide no password? The site would send a short-term key directly to your email address. You click on the link and you're in. When you're done, you "logout" and your key is terminated. I've toyed with this idea before. What concerns (i.e. spammers, bots, etc.) would make this impractical or unsafe and could they be overcome?

  Read the article

• password incorrect 3 times + suspected failed update

  - by Cheese

  I have been lurking your site for the past few hours, and have found myself in a bit of a pickle. Visiting my parents, I discover that neither computer, nor laptop work. Long story short, I've got the laptop working, but have completely fudged up the computer. I am a n00b, but I was at least willing to give it a go. The comp originally had ubuntu 11.10 installed, later updated to 12.04. We have cds for both. I do not understand what the initial problem was for my parents, but somehow when I turned on the computer, it worked for me. Soon after, I was nagged to install the latest updates. So, I spent the next half an hour wondering why the updates kept on asking for 11.04 cdroms, until I realised that you could turn off the cdrom necessity. After doing this via console, I installed some of the smaller updates, before being told to do a partial update. This failed a few times, and ended up freezing whilst reinstalling drivers. After a hard restart I continued to type whatever I could find on the forum into the console. At some point, the console started saying that I had 3 incorrect password inputs, and sudo commands stopped altogether. I found another thread discussing this; but people kept on suggesting changing passwords (which I did to no avail) or other things that made use of sudo (which I am locked out of, although I am technically the admin) I found myself somehow on the Ctrl+Alt+F1 console, and after being utterly confused (and Ctrl+AltF5 failing for me), another hard reset occurred. Somewhere along the way I created a USB start up for 14.04, (but this does not seem to work) Now I am left with an admin (and guest) account that log in but have blank screens (with only the desktop background showing) and I can't do anything in the console because I'm locked out. Interestingly, the console now says that I am running 14.04 although all updates said they had failed. Aside from the obvious lessons I have learnt (don't fiddle about in the console when you have no idea what you're doing "Dog wearing safety glasses "I have no idea what I am doing" GIF would be inserted here ) Is there any way I can redeem this almighty muck up? A million thanks for any help!

  Read the article

• Asymptotic complexity of a compiler

  - by Meinersbur

  What is the maximal acceptable asymptotic runtime of a general-purpose compiler? For clarification: The complexity of compilation process itself, not of the compiled program. Depending on the program size, for instance, the number of source code characters, statements, variables, procedures, basic blocks, intermediate language instructions, assembler instructions, or whatever. This is highly depending on your point of view, so this is a community wiki. See this from the view of someone who writes a compiler. Will the optimisation level -O4 ever be used for larger programs when one of its optimisations takes O(n^6)? Related questions: When is superoptimisation (exponential complexity or even incomputable) acceptable? What is acceptable for JITs? Does it have to be linear? What is the complexity of established compilers? GCC? VC? Intel? Java? C#? Turbo Pascal? LCC? LLVM? (Reference?) If you do not know what asymptotic complexity is: How long are you willing to wait until the compiler compiled your project? (scripting languages excluded)

  Read the article

• Time complexity of a certain program

  - by HokageSama

  In a discussion with my friend i am not able to predict correct and tight time complexity of a program. Program is as below. /* This Function reads input array "input" and update array "output" in such a way that B[i] = index value of nearest greater value from A[i], A[i+1] ... A[n], for all i belongs to [1, n] Time Complexity: ?? **/ void createNearestRightSidedLargestArr(int* input, int size, int* output){ if(!input || size < 1) return; //last element of output will always be zero, since no element is present on its right. output[size-1] = -1; int curr = size - 2; int trav; while(curr >= 0){ if(input[curr] < input[curr + 1]){ output[curr] = curr + 1; curr--; continue; } trav = curr + 1; while( input[ output [trav] ] < input[curr] && output [trav] != -1) trav = output[trav]; output[curr--] = output[trav]; } } I said time complexity is O(n^2) but my friend insists that this is not correct. What is the actual time complexity?

  Read the article

• Time complexity with bit cost

  - by Keyser

  I think I might have completely misunderstood bit cost analysis. I'm trying to wrap my head around the concept of studying an algorithm's time complexity with respect to bit cost (instead of unit cost) and it seems to be impossible to find anything on the subject. Is this considered to be so trivial that no one ever needs to have it explained to them? Well I do. (Also, there doesn't even seem to be anything on wikipedia which is very unusual). Here's what I have so far: The bit cost of multiplication and division of two numbers with n bits is O(n^2) (in general?) So, for example: int number = 2; for(int i = 0; i < n; i++ ){ number = i*i; } has a time complexity with respect to bit cost of O(n^3), because it does n multiplications (right?) But in a regular scenario we want the time complexity with respect to the input. So, how does that scenario work? The number of bits in i could be considered a constant. Which would make the time complexity the same as with unit cost except with a bigger constant (and both would be linear). Also, I'm guessing addition and subtraction can be done in constant time, O(1). Couldn't find any info on it but it seems reasonable since it's one assembler operation.

  Read the article

• Reducing Time Complexity in Java

  - by Koeneuze

  Right, this is from an older exam which i'm using to prepare my own exam in january. We are given the following method: public static void Oorspronkelijk() { String bs = "Dit is een boodschap aan de wereld"; int max = -1; char let = '*'; for (int i=0;i<bs.length();i++) { int tel = 1; for (int j=i+1;j<bs.length();j++) { if (bs.charAt(j) == bs.charAt(i)) tel++; } if (tel > max) { max = tel; let = bs.charAt(i); } } System.out.println(max + " keer " + let); } The questions are: what is the output? - Since the code is just an algorithm to determine the most occuring character, the output is "6 keer " (6 times space) What is the time complexity of this code? Fairly sure it's O(n²), unless someone thinks otherwise? Can you reduce the time complexity, and if so, how? Well, you can. I've received some help already and managed to get the following code: public static void Nieuw() { String bs = "Dit is een boodschap aan de wereld"; HashMap<Character, Integer> letters = new HashMap<Character, Integer>(); char max = bs.charAt(0); for (int i=0;i<bs.length();i++) { char let = bs.charAt(i); if(!letters.containsKey(let)) { letters.put(let,0); } int tel = letters.get(let)+1; letters.put(let,tel); if(letters.get(max)<tel) { max = let; } } System.out.println(letters.get(max) + " keer " + max); } However, I'm uncertain of the time complexity of this new code: Is it O(n) because you only use one for-loop, or does the fact we require the use of the HashMap's get methods make it O(n log n) ? And if someone knows an even better way of reducing the time complexity, please do tell! :)

  Read the article

• What is the complexity of this specialized sort

  - by ADB

  I would like to know the complexity (as in O(...) ) of the following sorting algorithm: there are B barrels that contains a total of N elements, spread unevenly across the barrels. the elements in each barrel are already sorted The sort takes combines all the elements from each barrel in a single sorted list: using an array of size B to store the last sorted element of each barrel (starting at 0) check each barrel (at the last stored index) and find the smallest element copy the element in the final sorted array, increment array counter increment the last sorted element for the barrel we picked from perform those steps N times or in pseudo: for i from 0 to N smallest = MAX_ELEMENT foreach b in B if bIndex[b] < b.length && b[bIndex[b]] < smallest smallest_barrel = b smallest = b[bIndex[b]] result[i] = smallest bIndex[smallest_barrel] += 1 I thought that the complexity would be O(n), but the problem I have with finding the complexity is that if B grows, it has a larger impact than if N grows because it adds another round in the B loop. But maybe that has no effect on the complexity?

  Read the article

• Password Policy seems to be ignored for new Domain on Windows Server 2008 R2

  - by Earl Sven

  I have set up a new Windows Server 2008 R2 domain controller, and have attempted to configure the Default Domain Policy to permit all types of passwords. When I want to create a new user (just a normal user) in the Domain Users and Computers application, I am prevented from doing so because of password complexity/length reasons. The password policy options configured in the Default Domain Policy are not defined in the Default Domain Controllers Policy, but having run the Group Policy Modelling Wizard these settings do not appear to be set for the Domain Controllers OU, should they not be inherited from the Default Domain policy? Additionally, if I link the Default Domain policy to the Domain Controllers OU, the Group Policy Modelling Wizard indicates the expected values for complexity etc, but I still cannot create a new user with my desired password. The domain is running at the Windows Server 2008 R2 functional level. Any thoughts? Thanks! Update: Here is the "Account policy/Password policy" Section from the GPM Wizard: Policy Value Winning GPO Enforce password history 0 Passwords Remembered Default Domain Policy Maximum password age 0 days Default Domain Policy Minimum password age 0 days Default Domain Policy Minimum password length 0 characters Default Domain Policy Passwords must meet complexity Disabled Default Domain Policy These results were taken from running the GPM Wizard at the Domain Controllers OU. I have typed them out by hand as the system I am working on is standalone, this is why the table is not exactly the wording from the Wizard. Are there any other policies that could override the above? Thanks!

  Read the article

• Is there a way to prevent password expiration when user has no password?

  - by Eric DANNIELOU

  Okay, we all care about security so users should change their passwords on a regular basis (who said passwords are like underwear?). On redhat and centos (5.x and 6.x), it's possible to make every real user password expires after 45 days, and warn them 7 days before. /etc/shadow entry then looks like : testuser:$6$m8VQ7BWU$b3UBovxC5b9p2UxLxyT0QKKgG1RoOHoap2CV7HviDJ03AUvcFTqB.yiV4Dn7Rj6LgCBsJ1.obQpaLVCx5.Sx90:15588:1:45:7::: It works very well and most users often change their passwords. Some users find it convenient not to use any password but ssh public key (and I'd like to encourage them). Then after 45 days they can't log in as they forgot their password and are asked to change it. Is there a way to prevent password expiration if and only if password is disabled? Setting testuser:!!:15588:1:45:7::: in /etc/shadow did not work : testuser is asked to change his password after 45 days. Of course, setting back password expiration to 99999 days works but : It requires extra work. Security auditors might not be happy. Is there a system wide parameter that would prompt the user to change expired password only if he really has one ?

  Read the article

• Time complexity of Sieve of Eratosthenes algorithm

  - by eSKay

  From Wikipedia: The complexity of the algorithm is O(n(logn)(loglogn)) bit operations. How do you arrive at that? That the complexity includes the loglogn term tells me that there is a sqrt(n) somewhere. Suppose I am running the sieve on the first 100 numbers (n = 100), assuming that marking the numbers as composite takes constant time (array implementation), the number of times we use mark_composite() would be something like n/2 + n/3 + n/5 + n/7 + ... + n/97 = O(n) And to find the next prime number (for example to jump to 7 after crossing out all the numbers that are multiples of 5), the number of operations would be O(n). So, the complexity would be O(n^2). Do you agree?

  Read the article

• What is meant by "no password set" for root account (and otthers)?

  - by MMA

  Several years back, we were more accustomed to changing to the root account using the su command. First, we switched to the root account, and then executed those root commands. Now we are more accustomed to using the sudo command. But we know that the root account is there. We can readily find the home directory of user root. $ ls -ld /root/ drwx------ 18 root root 4096 Oct 22 17:21 /root/ Now my point is, it is stated that "the root password in Ubuntu is left unset". Please see the answers to this question. Most of the answers have something to this effect in the first paragraph. One or two answers further state that "the account is left disabled". Now my (primary) questions are, What is meant by an unset password? Is it blank? Is it null? Or something else more cryptic? How does the account becomes enabled once I set password for it? (sudo password root) In order get a better understanding, I checked the /etc/shadow file. Since I have already set a password for the root account, I can no longer see what is there (encrypted password). So, I created another account and left it disabled. The corresponding entry in the /etc/shadow file is, testpassword:!:16020:0:99999:7::: Now perhaps my above queries need to be changed to, what does an ! in password field mean? Other encrypted passwords are those very long cryptic strings. How come this encrypted form is only one character long? And does an account become disabled if I put an ! in the (encrypted) password field?

  Read the article

• trying to set and use a password via commandline using ultraVNC on windows server 2003 vnc

  - by mustafa

  Okay, so I installed ultravnc on windows server 2003. It uses the ultravnc.i.i file to store password and configuration information. But I'd like to be able to set the password using the command line. There is a tool called vncpwd: http://www.sysworksoft.net/products/vncpwd.html But it's old, and when you use it to change the password, it changes the password in the system registry instead of the ultravnc.ini file. But, you can set ultravnc to use the registry instead of the ini file. Success? No. I set ultravnc to use the registry (which stores the hashed password that I set using vncpwd), but, it still uses the password in the .ini file. does anyone know what gives.

  Read the article

• Check username password combination in Windows

  - by mwolfe02

  I have an autohotkey script that maps multiple network drives using a series of net use commands. I enter my password once into an autohotkey inputbox, then run all of the net use commands with the entered password. This works great as long as I enter the correct password. If I mistype my password it runs all the net use commands with an incorrect password and my account ends up locked out. Aside from catching the error code/output from the net use command, is there some other way (through Autohotkey/Windows command-line) to verify the username/password combo is correct before I run it multiple times?

  Read the article

• how insecure is my short password really?

  - by rika-uehara

  Using systems like TrueCrypt, when I have to define a new password I am often informed that using a short password is insecure and "very easy" to break by brute-force. I always use passwords of 8 characters in length, which are not based on dictionary words, which consists of characters from the set A-Z, a-z, 0-9 I.e. I use password like sDvE98f1 How easy is it to crack such a password by brute-force? I.e. how fast. I know it heavily depends on the hardware but maybe someone could give me an estimate how long it would take to do this on a dual core with 2GHZ or whatever to have a frame of reference for the hardware. To briute-force attack such a password one needs not only to cycle through all combinations but also try to de-crypt with each guessed password which also needs some time. Also, is there some software to brute-force hack truecrypt because I want to try to brute-force crack my own passsword to see how long it takes if it is really that "very easy".

  Read the article

• Logging in with a different password than the database password, PHPMyAdmin

  - by Andrew M

  I am trying to install PHPMyAdmin on my server to manage my MySQL databases. Right now I have only one I want to add, but I would like to be able to manage multiple databases from the same account on PHPMyAdmin. How would I configure PMA so I could login with "andrew" and a password of "examplepassword" instead of the annoyingly long and unchangeable database user and password I am provided (ie. db3483478234, password of random characters)? I can't seem to find an area to specify a different password than the regular database username and password.

  Read the article

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >