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• Replace More Than 1 Instance with PHP

  - by Belgin Fish

  Hey, say i have sometext-somemore--test---test2 how could I have it replace all instaces where there are more than 1 - and have it replace them with just 1 so it would look like this sometext-somemore-test-test2

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• Problem with RegEx.Replace and trying to change a filename

  - by fraXis

  Hello, I am having a strange problem and I can't seem to figure it out. My filename is something like this: DER 1513016-3.020F.NCF. I want to be able to change it to: DER 1513016-3.020H.NCF Sometimes the filename can be this as well: DER 1513016-3.020F_NEW.NCF which would change to: DER 1513016-3.020H_NEW.NCF This is my code to do this: OpenFileDialog fDialog = new OpenFileDialog(); fDialog.Title = "Open"; fDialog.Filter = "NCF files (*.ncf)|*.ncf|All files (*.*)|*.*"; fDialog.InitialDirectory = @"C:\Program Files\"; if (fDialog.ShowDialog() == DialogResult.OK) { string newfilename; string fileext = Path.GetExtension(fDialog.FileName); newfilename = Regex.Replace(fDialog.FileName, "F.NCF", "H.NCF"); newfilename = Regex.Replace(fDialog.FileName, "F_NEW.NCF", "H_NEW.NCF"); } This is where things get wierd. The way the code works now, it will NOT change the filename to DER 1513016-3.020H.NCF If I comment out this line of code: //newfilename = Regex.Replace(fDialog.FileName, "F_NEW.NCF", "H_NEW.NCF"); it will work fine and the file will now become: DER 1513016-3.020H.NCF However, if I uncomment that line of code, the filename will not change to DER 1513016-3.020H.NCF. It will stay as DER 1513016-3.020F.NCF. Why is that line of code causing the routine to not change the filename? Thanks,

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• VS2008 - Find and Replace - Searches too many files.

  - by Pam Bullock

  I've used VS2008 a lot and have never had this problem. However, I started a new job and am using a new machine. Ever since I've gotten here the VS Find feature has been acting funny. I first noticed it when I did a replace all for "All Open Files". The project wouldn't build because the values had actually been replaced in other files within the solution that were not open and didn't even open after I pressed replace all. I have found that I can never use replace all on this machine because I never know what it is going to do. Even if I just do a find on "Current Document", once it's done with the document and I should get that message that says "No more matches found" it actually OPENS another random file from my solution where there is a match and keeps on going. It seems to never make any difference what "Look in" option I've chosen. My coworker has an install off the same disk and claims to not be experiencing this. We're in the middle of a stressful, huge project with a close deadline so I know my boss won't let me do a reinstall. Has anyone else ever had this happen? Anyone know a fix?? Thanks, Pam

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• Replace apostrophe in json string with empty string

  - by user572844

  Hi, I have problem with deserialization of json string, because string is bad format. For example json object consist string property statusMessage with value "Hello "dog" ". The correct format should be "Hello \" dog \" " . I would like remove apostrophes from this property. Something Like this. "Hello "dog" ". - "Hello dog ". Here is it original json string which I work. "{\"jancl\":{\"idUser\":18438201,\"nick\":\"JANCl\",\"photo\":\"1\",\"sex\":1,\"photoAlbums\":1,\"videoAlbums\":0,\"sefNick\":\"jancl\",\"profilPercent\":75,\"emphasis\":false,\"age\":\"-\",\"isBlocked\":false,\"PHOTO\":{\"normal\":\"http://u.aimg.sk/fotky/1843/82/n_18438201.jpg?v=1\",\"medium\":\"http://u.aimg.sk/fotky/1843/82/m_18438201.jpg?v=1\",\"24x24\":\"http://u.aimg.sk/fotky/1843/82/s_18438201.jpg?v=1\"},\"PLUS\":{\"active\":false,\"activeTo\":\"0000-00-00\"},\"LOCATION\":{\"idRegion\":\"6\",\"regionName\":\"Trenciansky kraj\",\"idCity\":\"138\",\"cityName\":\"Trencianske Teplice\"},\"STATUS\":{\"isLoged\":true,\"isChating\":false,\"idChat\":0,\"roomName\":\"\",\"lastLogin\":1294925369},\"PROJECT_STATUS\":{\"photoAlbums\":1,\"photoAlbumsFavs\":0,\"videoAlbums\":0,\"videoAlbumsFavs\":0,\"videoAlbumsExts\":0,\"blogPosts\":0,\"emailNew\":0,\"postaNew\":0,\"clubInvitations\":0,\"dashboardItems\":1},\"STATUS_MESSAGE\":{\"statusMessage\":\"\"Status\"\",\"addTime\":\"1294872330\"},\"isFriend\":false,\"isIamFriend\":false}}" Problem is here, json string consist this object: "STATUS_MESSAGE": {"statusMessage":" "some "bad" value" ", "addTime" :"1294872330"} Condition of string which I want modified: string start with "statusMessage":" string can has any *lenght from 0 -N * string end with ", "addTime So I try write pattern for string which start with "statusMessage":", has any lenght and is ended with ", "addTime. Here is it: const string pattern = " \" statusMessage \" : \" .*? \",\"addTime\" "; var regex = new Regex(pattern, RegexOptions.IgnoreCase); //here i would replace " with empty string string result = regex.Replace(jsonString, match => ???); But I think pattern is wrong, also I don’t know how replace apostrophe with empty string (remove apostrophne). My goal is : "statusMessage":" "some "bad" value" to "statusMessage":" "some bad value" Thank for advice

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• C# String.Replace with a start/index (Added my (slow) implementation)

  - by Chris T

  I'd like an efficient method that would work something like this EDIT: Sorry I didn't put what I'd tried before. I updated the example now. // Method signature, Only replaces first instance or how many are specified in max public int MyReplace(ref string source,string org, string replace, int start, int max) { int ret = 0; int len = replace.Length; int olen = org.Length; for(int i = 0; i < max; i++) { // Find the next instance of the search string int x = source.IndexOf(org, ret + olen); if(x > ret) ret = x; else break; // Insert the replacement source = source.Insert(x, replace); // And remove the original source = source.Remove(x + len, olen); // removes original string } return ret; } string source = "The cat can fly but only if he is the cat in the hat"; int i = MyReplace(ref source,"cat", "giraffe", 8, 1); // Results in the string "The cat can fly but only if he is the giraffe in the hat" // i contains the index of the first letter of "giraffe" in the new string The only reason I'm asking is because my implementation I'd imagine getting slow with 1,000s of replaces.

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• File.Replace throwing IOException

  - by WebDevHobo

  I have an app that can make modify images. In some cases, this makes the filesize smaller, in some cases bigger. The program doesn't have an option to "not replace the file if result has a bigger filesize". So I wrote a little C# app to try and solve this. Instead of overwriting the files, I make the app write the result to a folder under the current one and name that folder Test. The C# app I wrote compares grabs the contents of both folders and puts the full path to the file(s) in two List objects. I then compare and replace. The replacing isn't working however. I get the following IOException: Unable to remove the file to be replaced The location is on an external hard-drive, on which I have full rights. Now, I know I can just do File.Delete and File.Move in that order, but this exception has gotten me interested in why this particular setup wont work. Here's the source code: http://pastebin.com/4Vq82Umu And yes, the file specified as last argument of the Replace function does exist.

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• using replace to produce javascript code, django

  - by durdenk

  I want to use highcharts with my django site but it requires a comlex javascript code such as below. So I wanted to get this script in my python code and replace apropriate portions then write it in my template, first question is, is this a dump way to do that for a person not knowing javascript. I can read it tough. Second question is, Why I cant replace this string. Lets say this string is a variable like this. lineChartsTemplate = """ ... ... """ if I try and do lineChartsTemplate .replace('dataCategory', dataCategory) it basically suppossed to change dataCategory text with my dataCategory variable, but no such luck. I need guidance here. thx. $(function () { var chart = new Highcharts.Chart({ chart: { renderTo: 'container', type: 'bar' }, xAxis: { categories: dataCategory }, yAxis: { }, legend: { layout: 'vertical', floating: true, backgroundColor: '#FFFFFF', align: 'right', verticalAlign: 'top', y: 60, x: -60 }, tooltip: { formatter: function() { return '<b>'+ this.series.name +'</b><br/>'+ this.x +': '+ this.y; } }, plotOptions: { }, series: [{ data: dataList , name : 'Satislar'}] }); });

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• preg_replace, exact opposite of a preg_match

  - by SoLoGHoST

  I need to do a preg_replace for the exact opposite of this preg_match regular expression: preg_match('#^(\w+/){0,2}\w+\.\w+$#', $string); So I need to replace all strings that are not valid with an empty string - '' So it needs to remove the first / and last / if found, and all non-valid characters, that is the only valid characters are A-Z, a-z, 0-9, _, ., and / (if it's not the first or last characters of the string). How can I accomplish this with the preg_replace? Thanks :)

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• String replacement on a whole text file in Python 3.x?

  - by SkippyFire

  How can I replace a string with another string, within a given text file. Do I just loop through readline() and run the replacement while saving out to a new file? Or is there a better way? I'm thinking that I could read the whole thing into memory, but I'm looking for a more elegant solution... Thanks in advance

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• Advanced Regex: Smart auto detect and replace URLs with anchor tags

  - by Robert Koritnik

  I've written a regular expression that automatically detects URLs in free text that users enter. This is not such a simple task as it may seem at first. Jeff Atwood writes about it in his post. His regular expression works, but needs extra code after detection is done. I've managed to write a regular expression that does everything in a single go. This is how it looks like (I've broken it down into separate lines to make it more understandable what it does): 1 (?<outer>\()? 2 (?<scheme>http(?<secure>s)?://)? 3 (?<url> 4 (?(scheme) 5 (?:www\.)? 6 | 7 www\. 8 ) 9 [a-z0-9] 10 (?(outer) 11 [-a-z0-9/+&@#/%?=~_()|!:,.;cšžcd]+(?=\)) 12 | 13 [-a-z0-9/+&@#/%?=~_()|!:,.;cšžcd]+ 14 ) 15 ) 16 (?<ending>(?(outer)\))) As you may see, I'm using named capture groups (used later in Regex.Replace()) and I've also included some local characters (cšžcd), that allow our localised URLs to be parsed as well. You can easily omit them if you'd like. Anyway. Here's what it does (referring to line numbers): 1 - detects if URL starts with open braces (is contained inside braces) and stores it in "outer" named capture group 2 - checks if it starts with URL scheme also detecting whether scheme is SSL or not 3 - start parsing URL itself (will store it in "url" named capture group) 4-8 - if statement that says: if "sheme" was present then www. part is optional, otherwise mandatory for a string to be a link (so this regular expression detects all strings that start with either http or www) 9 - first character after http:// or www. should be either a letter or a number (this can be extended if you'd like to cover even more links, but I've decided not to because I can't think of a link that would start with some obscure character) 10-14 - if statement that says: if "outer" (braces) was present capture everything up to the last closing braces otherwise capture all 15 - closes the named capture group for URL 16 - if open braces were present, capture closing braces as well and store it in "ending" named capture group First and last line used to have \s* in them as well, so user could also write open braces and put a space inside before pasting link. Anyway. My code that does link replacement with actual anchor HTML elements looks exactly like this: value = Regex.Replace( value, @"(?<outer>\()?(?<scheme>http(?<secure>s)?://)?(?<url>(?(scheme)(?:www\.)?|www\.)[a-z0-9](?(outer)[-a-z0-9/+&@#/%?=~_()|!:,.;cšžcd]+(?=\))|[-a-z0-9/+&@#/%?=~_()|!:,.;cšžcd]+))(?<ending>(?(outer)\)))", "${outer}<a href=\"http${secure}://${url}\">http${secure}://${url}</a>${ending}", RegexOptions.Compiled | RegexOptions.CultureInvariant | RegexOptions.IgnoreCase); As you can see I'm using named capture groups to replace link with an Anchor tag: "${outer}<a href=\"http${secure}://${url}\">http${secure}://${url}</a>${ending}" I could as well omit the http(s) part in anchor display to make links look friendlier, but for now I decided not to. Question I would like my links to be replaced with shortenings as well. So when user copies a very long link (for instance if they would copy a link from google maps that usually generates long links) I would like to shorten the visible part of the anchor tag. Link would work, but visible part of an anchor tag would be shortened to some number of characters. I could as well append ellipsis at the end of at all possible (and make things even more perfect). Does Regex.Replace() method support replacement notations so that I can still use a single call? Something similar as string.Format() method does when you'd like to format values in string format (decimals, dates etc...).

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• Visual Studio Find and Replace Regular Expressions ~ find lines with quoted strings, not containing

  - by Darkoni

  Visual Studio Find and Replace Regular Expressions Find lines with quoted strings, not containing strings include or trace i am tryling to find out all lines in c++ project that contains some text as i have to use visual studio, i have to use its Find and Replace http://www.codinghorror.com/blog/2006/07/the-visual-studio-ide-and-regular-expressions.html so, for finding all lines like: print("abc"); it is enogh to write :q and it will find all quotted strings ok, but i also get lot of lines like #include "stdio.h" and trace("* step 1 *") i find out regex to get all lines containing include and trace <include|trace> so, mine question is, how to find all lines with "quotted strings" but NOT lines that contains strings include and trace. thanx

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• Replace or recode several different values by a single value in an Excel file

  - by Ali

  Hi all, I have an Excel worksheet which contains data in several columns. For a specific column, I will need Excel to replace all values between, say 10 to 15, by the value 1 and values between 16 and 20 by the value 2 and so forth. I know how to do it for a single value; ie: I can replace value 10 by 1, 11 by 1 and so on. But this will be a tedious exercise. Are there some lines of codes that can execute this task? Thanks for your help. regards, Ali

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• "Simple" Text replace function

  - by YourMomzThaBomb

  I have a string which is basically a list of "words" delimited by commas. These "words" can be pretty much any character e.g. "Bart Simpson, Ex-girlfriend, dude, radical" I'm trying to use javascript, jQuery, whatever i can to replace a word based on a search string with nothing (in essence, removing the word from the list). For example, the function is defined as such: function removeWord(myString, wordToReplace) {...}; So, passing the string listed above as myString and passing "dude" as wordToReplace would return the string "Bart Simpson, Ex-girlfriend, radical" Here's the line of code I was tinkering around with...please help me figure out what's wrong with it or some alternative (better) solution:$myString.val($myString.val().replace(/wordToReplace\, /, ""));

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• Replace text in folder names

  - by dannyb

  How can I replace the same text in folder names in linux? Say I have "Photos_Jun", "Photos_July", "Photos_Aug", etc. whats the simplest way I can rename them like "Photos Jun", "Photos July", etc (basically I want to replace the underscore with a space " ". I have about 200 of these folders. I was looking at solution: http://stackoverflow.com/questions/1836563/how-can-i-easily-bulk-rename-files-with-perl It looks like what im looking for however, I dont know how to make a regular expression to match folders that are alphanumeric followed by a "_". All files have non-numeric names, so I think [a-zA-Z] is the right way to start. perl -e 'foreach $f (glob("File\\ Name*")) { $nf = $f; $nf =~ s/(\d+)$/sprintf("%03d",$1)/e; print `mv \"$f\" \"$nf\"`;}' Thanks for any help!

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• C# Find and Replace RegEx question

  - by fraXis

  Hello, I am starting to get a grip on RegEx thanks to all the great help here on SO with my other questions. But I am still suck on this one: My code is: StreamReader reader = new StreamReader(fDialog.FileName.ToString()); string content = reader.ReadToEnd(); reader.Close(); I am reading in a text file and I want to search for this text and change it (the X and Y value always follow each other in my text file): X17.8Y-1. But this text can also be X16.1Y2.3 (the values will always be different after X and Y) I want to change it to this X17.8Y-1.G54 or X(value)Y(value)G54 My RegEx statement follows but it is not working. content = Regex.Replace(content, @"(X(?:\d*\.)?\d+)*(Y(?:\d*\.)?\d+)", "$1$2G54"); Can someone please modify it for me so it works and will search for X(wildcard) Y(Wildcard) and replace it with X(value)Y(value)G54? Thanks, Shawn

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• Find and Replace RegEx question

  - by fraXis

  I am starting to get a grip on RegEx thanks to all the great help here on SO with my other questions. But I am still suck on this one: My code is: StreamReader reader = new StreamReader(fDialog.FileName.ToString()); string content = reader.ReadToEnd(); reader.Close(); I am reading in a text file and I want to search for this text and change it (the X and Y value always follow each other in my text file): X17.8Y-1. But this text can also be X16.1Y2.3 (the values will always be different after X and Y) I want to change it to this X17.8Y-1.G54 or X(value)Y(value)G54 My RegEx statement follows but it is not working. content = Regex.Replace(content, @"(X(?:\d*\.)?\d+)*(Y(?:\d*\.)?\d+)", "$1$2G54"); Can someone please modify it for me so it works and will search for X(wildcard) Y(Wildcard) and replace it with X(value)Y(value)G54?

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• PHP replace backslash

  - by Skyfe

  Hi there, Been struggling with replacing a backslash by another symbol such as '.-.' just to indicate the position of backslashes as I could not send a string such as 'C\xampp\etc.' through url as GET variable so I thought I'd first replace the backslashes in that string by another symbol, then send through url, and then replace them back to backslashes in the PHP file that handles it. Though would there be a better way to send such strings through url? Because when I try a script such as: $tmp_name = preg_replace("\", ".-.", $_FILES['uploadfile']['tmp_name']); It turns out into a php error as \ is also used as delimiter.. Could anyone help me out on this? Thanks in advanced! Btw, if I'd be able to send a full array through url, this whole problem would be solved, but I don't think it's possible?

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• str_replace match only first instance

  - by kylex

  A followup question to http://stackoverflow.com/questions/3063704/ Given the following POST data: 2010-June-3 <remove>2010-June-3</remove> 2010-June-15 2010-June-16 2010-June-17 2010-June-3 2010-June-1 I'm wanting to remove ONLY the first instance of 2010-June-3, but the following code removes all the data. $i = 1; $pattern = "/<remove>(.*?)<\/remove>/"; preg_match_all($pattern, $_POST['exclude'], $matches, PREG_SET_ORDER); if (!empty($matches)) { foreach ($matches as $match) { // replace first instance of excluded data $_POST['exclude'] = str_replace($match[1], "", $_POST['exclude'], $i); } } echo "<br /><br />".$_POST['exclude']; This echos: <remove></remove> 2010-June-15 2010-June-16 2010-June-17 2010-June-1 It should echo: <remove>2010-June-3</remove> 2010-June-15 2010-June-16 2010-June-17 2010-June-3 2010-June-1

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• How do I save a macro consisting of multiple search and replace into my .vimrc

  - by Doppelganger

  I have a macro that I use to replace special characters for its html entities. I would like to save it in my .vimrc. According to this, I should use let @r=' *macro_text_goes_here* '. The problem is that my macro is a series of search and replace, something like this: :%s:á:\&aacute;:Ige :%s:é:\&eacute;:Ige :%s:í:\&iacute;:Ige So, I've tried with ^V-enter, <enter>, <CR> using real line breaks, but it never works. On the other side, if I put the text on a register and then run the macro, it works as expected.

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• C#, string replace russian to english

  - by Fabio Beoni

  Hello, I have a strange problem replacing chars in string... I read a .txt file containing russian text, and starting from a list of letters russian to english (ru=en), I loop the list and I WOULD like to replace russian characters with english characters. The problem is: I can see in the debug the right reading of the russian and the right reading of the english, but using myWord = myWord.Replace(ruChar, enChar), the string is not replaced. My txt file is a UTF-8 encoding. Any suggestions?? Thank you to all...

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• Replace text in div when image is clicked

  - by Adam

  Hello, I'm trying to replace certain text inside the div "info" when an image (which serve as links) is clicked. I'm just unsure of what methods could do this. I would prefer this be jquery. My code so far looks like: <div class="info"> <p>I would like this text replaced</p> <script> </script> </div><!--end info--> <li><a href="1.jpg"><img src="1-s.png" width="55" height="55" alt="" class="latest_img" /></a><p>Replace the div "info" text with the text here when clicked on</p></li>

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• Help with Perl Regex Recursive Replace One Liner? Replace MySQL comments '--' with '#'

  - by NJTechie

  I have various SQL files with '--' comments and we migrated to the latest version of MySQL and it hates these comments. I want to replace -- with #. I am looking for a recursive, inplace replace one-liner. This is what I have : perl -p -i -e 's/--/# /g' `fgrep -- -- * ` A sample .sql file : use myDB; --did you get an error I get the following error : Unrecognized switch: --did (-h will show valid options). p.s : fgrep skipping 2 dashes was just discussed here if you are interested. Any help is appreciated.

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• Replace text in string with delimeters using Regex

  - by user1057735

  I have a string something like, string str = "(50%silicon +20%!(20%Gold + 80%Silver)| + 30%Alumnium)"; I need a Regular Expression which would Replace the contents in between ! and | with an empty string. The result should be (50%silicon +20% + 30%Alumnium). If the string contains something like (with nested delimiters): string str = "(50%silicon +20%!(80%Gold + 80%Silver + 20%!(20%Iron + 80%Silver)|)| + 30%Alumnium)"; The result should be (50%silicon +20% + 30%Alumnium) - ignoring the nested delimiters. I've tried the following Regex, but it doesn't ignore the nesting: Regex.Replace(str , @"!.+?\|", "", RegexOptions.IgnoreCase);

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• Access VBA remove CR & LF only from the beginning of a text string by searching for them

  - by uZI

  Hi there I need to remove line breaks from the beginning of a memo type records. I dont want to use the replace function as it would remove all line breaks from the record which is not desired. Its only the line breaks at the beginning of the field that I am interested in removing. Furthermore, the my records do not always begin with a line break so I cant really use text positioning, the solution would be to look for line break at the beginning instead of always expecting it at the beginning. click here for a sample of what my data looks like any help will be greatly appreciated

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• JQuery slideToggle replace image src

  - by Rob

  Hi, This function is called when an up/down arrow is clicked to slide hidden div. If the div is hidden, the arrow points down and changes to up when the div is shown. If the div is shown, the arrow points up to hide div and changes to down when the div is closed. I just wanted to know if there was a more efficient way of doing this or if this is the correct way. Thanks. function showInfo(info_id) { var img_id = '#arrow_'+info_id; var div = '#info_'+appointment_id; $(div).slideToggle('normal',function() { if ($(this).is(':visible')) { $(img_id).attr('src',$(img_id).attr('src').replace('_down','_up')); } else { $(img_id).attr('src',$(img_id).attr('src').replace('_up','_down')); } });}

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