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• Hibernate a user account when switching to different account in Windows 7 Home Premium (64bit)

  - by Sukotto

  Is there any way to have Windows 7 hibernate Bob's account when switched to Mary's account and vice versa? I.e.: Bob is logged in Bob clicks Start shutdown switch user Bob's session is saved to disk Mary logs in Mary's session is restored as it was when Bob's turn started Both are heavy users (30+ chrome tabs open, multiple documents, multiple spreadsheets, music playing, etc) I would like to set up the system so that each gets the full use of the computer while still having all their open apps the way they left them. I suppose I could try setting up a VM for each, but I'd rather not add anything else to the mix here if I don't have to. This is Windows 7 Home Premium 64-bit running on a Lenovo G550 laptop

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• How can I switch user in a shell and use the existing gnome display session?

  - by z7sg

  If I switch user in a terminal. su bob I can't open gedit because bob doesn't own the display. If I execute xhost + before switching to bob I can open the display for some applications but not all. I get the following output when trying to execute gedit: (crashreporter:4415): GnomeUI-WARNING *: While connecting to session manager: None of the authentication protocols specified are supported. * GLib-GIO:ERROR:/build/buildd/glib2.0-2.28.6/./gio/gdbusconnection.c:2279:initable_init: assertion failed: (connection-initialization_error == NULL)

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• The how of a collision engine

  - by JXPheonix

  This is a very, very broad question - what is the general algorithm of how a collision engine works? No code in specific, but rather, just a general idea of how a collision engine does what it does, constantly refreshing the points of an object and comparing it to other objects? (see, I have the general gist of it here.) A collision engine is basically an engine used in games (generally) so that your player (call him Bob), whenever bob moves into a wall, Bob stops, Bob does not walk through the wall. They also generally handle the gravity in a game and environmental things like that.

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• The how of a collision engine

  - by JXPheonix

  This is a very, very broad question - what is the general algorithm of how a collision engine works? No code in specific, but rather, just a general idea of how a collision engine does what it does, constantly refreshing the points of an object and comparing it to other objects? (see, I have the general gist of it here.) A collision engine is basically an engine used in games (generally) so that your player (call him Bob), whenever bob moves into a wall, Bob stops, Bob does not walk through the wall. They also generally handle the gravity in a game and environmental things like that.

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• How to exploit Diffie-hellman to perform a man in the middle attack

  - by jfisk

  Im doing a project where Alice and Bob send each other messages using the Diffie-Hellman key-exchange. What is throwing me for a loop is how to incorporate the certificate they are using in this so i can obtain their secret messages. From what I understand about MIM attakcs, the MIM acts as an imposter as seen on this diagram: Below are the details for my project. I understand that they both have g and p agreed upon before communicating, but how would I be able to implement this with they both having a certificate to verify their signatures? Alice prepares ?signA(NA, Bob), pkA, certA? where signA is the digital signature algorithm used by Alice, “Bob” is Bob’s name, pkA is the public-key of Alice which equals gx mod p encoded according to X.509 for a fixed g, p as specified in the Diffie-Hellman key- exchange and certA is the certificate of Alice that contains Alice’s public-key that verifies the signature; Finally, NA is a nonce (random string) that is 8 bytes long. Bob checks Alice's signature, and response with ?signB{NA,NB,Alice},pkB,certB?. Alice gets the message she checks her nonce NA and calculates the joint key based on pkA, pkB according to the Diffie-Hellman key exchange. Then Alice submits the message ?signA{NA,NB,Bob},EK(MA),certA? to Bob and Bobrespondswith?SignB{NA,NB,Alice},EK(MB),certB?. where MA and MB are their corresponding secret messages.

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• Linq to SQL case sensitivity causing problems

  - by Roger Lipscombe

  I've seen this question, but that's asking for case-insensitive comparisons when the database is case-sensitive. I'm having a problem with the exact opposite. I'm using SQL Server 2005, my database collation is set to Latin1_General_CI_AS. I've got a table, "User", like this: CREATE TABLE [dbo].[User] ( [Id] [int] IDENTITY(1,1) NOT NULL, [Name] [nvarchar](max) NOT NULL, CONSTRAINT [PK_Example] PRIMARY KEY CLUSTERED ( [Id] ASC ) ) And I'm using the following code to populate it: string[] names = new[] { "Bob", "bob", "BoB" }; using (MyDataContext dataContext = new AppCompatDataContext()) { foreach (var name in names) { string s = name; if (dataContext.Users.SingleOrDefault(u => u.Name == s) == null) dataContext.Users.InsertOnSubmit(new User { Name = name }); } dataContext.SubmitChanges(); } When I run this the first time, I end up with "Bob", "bob" and "BoB" in the table. When I run it again, I get an InvalidOperationException: "Sequence contains more than one element", because the query against the database returns all 3 rows, and... SELECT * FROM [User] WHERE Name = 'bob' ... is case-insensitive. That is: when I'm inserting rows, Linq to SQL appears to use C# case-sensitive comparisons. When I query later, Linq to SQL uses SQL Server case-insensitive comparisons. I'd like the initial insert to use case-insensitive comparisons, but when I change the code as follows... if (dataContext.Users.SingleOrDefault(u => u.Name.Equals(s, StringComparison.InvariantCultureIgnoreCase) ) == null) ... I get a NotSupportedException: "Method 'Boolean Equals(System.String, System.StringComparison)' has no supported translation to SQL." Question: how do I get the initial insert to be case-insensitive or, more precisely, match the collation of the column in the database? Update: This doesn't appear to be my problem. My problem appears to be that SingleOrDefault doesn't actually look at the pending inserts at all.

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• Is it possible for double-escaping to cause harm to the DB?

  - by waiwai933

  If I accidentally double escape a string, can the DB be harmed? For the purposes of this question, let's say I'm not using parametrized queries For example, let's say I get the following input: bob's bike And I escape that: bob\'s bike But my code is horrible, and escapes it again: bob\\\'s bike Now, if I insert that into a DB, the value in the DB will be bob\'s bike Which, while is not what I want, won't harm the DB. Is it possible for any input that's double escaped to do something malicious to the DB assuming that I take all other necessary security precautions?

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• Monit unable to start sidekiq on Opsworks server

  - by webdevtom

  I have used AWS Opsworks to create some servers. I have Sidekiq running as part of my Rails application. When I deploy Sidekiq restarts nicely. I am configuring Monit to watch the pid and start and stop Sidekiq if there are any issues. However when Monit trys to start Sidekiq I see that the wrong Ruby looks to be used. Oct 17 13:52:43 daitengu sidekiq: /usr/local/lib/ruby/gems/1.9.1/gems/bundler-1.3.4/lib/bundler/definition.rb:361:in `validate_ruby!': Your Ruby version is 1.8.7, but your Gemfile specified 1.9.3 (Bundler::RubyVersionMismatch) Oct 17 13:52:43 daitengu sidekiq: from /usr/local/lib/ruby/gems/1.9.1/gems/bundler-1.3.4/lib/bundler.rb:116:in `setup' Oct 17 13:52:43 daitengu sidekiq: from /usr/local/lib/ruby/gems/1.9.1/gems/bundler-1.3.4/lib/bundler/setup.rb:17 When I run the command from the cli Sidekiq launches correctly. $> cd /srv/www/myapp/current && RAILS_ENV=production nohup /usr/local/bin/bundle exec sidekiq -C config/sidekiq.yml >> /srv/www/myapp/shared/log/sidekiq.log 2>&1 & $> ps -aef |grep sidekiq root 1236 1235 8 20:54 pts/0 00:00:50 sidekiq 2.11.0 myapp [0 of 25 busy] My sidekiq.monitrc file check process unicorn with pidfile /srv/www/myapp/shared/pids/unicorn.pid start program = "/bin/bash -c 'cd /srv/www/myapp/current && /usr/local/bin/bundle exec unicorn_rails --env production --daemonize -c /srv/www/myapp/shared/config/unicorn.conf'" stop program = "/bin/bash -c 'kill -QUIT `cat /srv/www/myapp/shared/pids/unicorn.pid`'"

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• Rsyslog stops sending data to remote server after log rotation

  - by Vincent B.

  In my configuration, I have rsyslog who is in charge of following changes of /home/user/my_app/shared/log/unicorn.stderr.log using imfile. The content is sent to another remote logging server using TCP. When the log file rotates, rsyslog stops sending data to the remote server. I tried reloading rsyslog, sending a HUP signal and restarting it altogether, but nothing worked. The only ways I could find that actually worked were dirty: stop the service, delete the rsyslog stat files and start rsyslog again. All that in a postrotate hook in my logrotate file. kill -9 rsyslog and start it over. Is there a proper way for me to do this without touching rsyslog internals? Rsyslog file $ModLoad immark $ModLoad imudp $ModLoad imtcp $ModLoad imuxsock $ModLoad imklog $ModLoad imfile $template WithoutTimeFormat,"[environment] [%syslogtag%] -- %msg%" $WorkDirectory /var/spool/rsyslog $InputFileName /home/user/my_app/shared/log/unicorn.stderr.log $InputFileTag unicorn-stderr $InputFileStateFile stat-unicorn-stderr $InputFileSeverity info $InputFileFacility local8 $InputFilePollInterval 1 $InputFilePersistStateInterval 1 $InputRunFileMonitor # Forward to remote server if $syslogtag contains 'apache-' then @@my_server:5000;WithoutTimeFormat :syslogtag, contains, "apache-" ~ *.* @@my_server:5000;SyslFormat Logrotate file /home/user/shared/log/*.log { daily missingok dateext rotate 30 compress notifempty extension gz copytruncate create 640 user user sharedscripts post-rotate (stop rsyslog && rm /var/spool/rsyslog/stat-* && start rsyslog 2&1) || true endscript } FYI, the file is readable for the rsyslog user, my server is reachable and other log files which do not rotate on the same cycle continue to be tracked properly. I'm running Ubuntu 12.04.

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• Thin and Bundler on Windows Rails

  - by Bob

  Trying to get Thin working with Bundle on Windows, I know, major PITA but anyways, I'm new to Thin and Bundle gem, I'm on Ruby 1.8.6 and Rails 2.3.5 and trying to get someone else's app running on my laptop, the app uses Thin and Bundle gem to install gems required. I noticed that bundle created a .bundle folder under My Documents folder and put all the gems there for the app. When I tried "thin run", it reported 'thin' is not recognized as an internal or external command, operable program or batch file. I check the environment path and it doesn't point to the .bundle folder at all and I found there is a thin.bat in C:\Documents and Settings\Bob\.bundle\ruby\1.8\bin When I tried "C:\Documents and Settings\Bob.bundle\ruby\1.8\bin\thin" start, it gave me another error c:/ruby/lib/ruby/site_ruby/1.8/rubygems.rb:777:in `report_activate_error': Could not find RubyGem thin (>= 0) (Gem::LoadError) from c:/ruby/lib/ruby/site_ruby/1.8/rubygems.rb:211:in `activate' from c:/ruby/lib/ruby/site_ruby/1.8/rubygems.rb:1056:in `gem' from C:/Documents and Settings/Bob/.bundle/ruby/1.8/bin/thin:18 I get the same error if I added "C:\Documents and Settings\Bob.bundle \ruby\1.8\bin" to the env path. Anyone know I can get this working?

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• ArchBeat Link-o-Rama for 2012-09-27

  - by Bob Rhubart

  Understanding Oracle BI 11g Security vs Legacy Oracle BI 10g | Christian Screen "After conducting a large amount of Oracle BI 10g to Oracle BI 11g upgrades and after writing the Oracle BI 11g book," says Oracle ACE Christian Screen, "I still continually get asked one of the most basic questions regarding security in Oracle BI 11g; How does it compare to Oracle BI 10g? The trail of questions typically goes on to what are the differences? And, how do we leverage our current Oracle BI 10g security table schema in Oracle BI 11g?" Process Oracle OER Events using a simple Web Service | Bob Webster Bob Webster's post "provides an example of a simple web service that processes Oracle Enterprise Repository (OER) Events. The service receives events from OER and utilizes the OER REX API to implement simple OER automations for selected event types." Oracle Fusion Middleware Security: Attaching OWSM policies to JRF-based web services clients | Andre Correa "OWSM (Oracle Web Services Manager) is Oracle's recommended method for securing SOAP web services," says Oracle Fusion Middleware A-Team member Andre Correa. "It provides agents that encapsulate the necessary logic to interact with the underlying software stack on both service and client sides. Such agents have their behavior driven by policies. OWSM ships with a bunch of policies that are adequate to most common real world scenarios." His detailed post shows how to make it happen. WebCenter Content (WCC) Trace Sections | ECM Architect ECM Architect Kevin Smith shares a detailed technical post covering WebCenter Content (WCC) Trace sections. Thought for the Day "A complex system that works is invariably found to have evolved from a simple system that worked." — John Gall Source: SoftwareQuotes.com

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• How to set permissions so two users can work on the same hg repository?

  - by John Mee

  Ubuntu: Jaunty Mercurial: 1.3.1 Access: ssh (users john and bob) File permission: -rw-rw---- 1 john john 129276 May 17 13:28 dirstate User: bob Command: 'hg st' Response: **abort: Permission denied: /our/respository/.hg/dirstate** Obviously mercurial can't let bob see the state because the file it needs to read belongs to me. So I change the permissions to allow bob to read the file and everything is fine, up until I next try to do something, whence the situations are reversed. Now he owns the file and I can't read it. So I set up a "committers" group and both john and bob belong to the group, but still mercurial fiddles with the ownership and permissions whenever one or other commits. How do we configure it so two different logins in the same group can commit to the same repository over ssh?

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• How to deal with arrays of data in cookies

  - by peter

  Hi all, I want to store data in a cookie and I am not exactly sure how I will go about it. The data is the UserName, and Password values for the users that are logging into a website, e.g. sometime like this UserName = bob, Password=Passw0rd1 UserName = harry, Password=BLANK UserName = george, Password=R0jjd6s What this means is that bob and george logged into the site and chose to have their password remembered, but harry chose for his password not to be remembered. So on the login dialog a dropdown will be present with all the usernames in it 'bob', 'harry', 'george'. If they select the username bob the password will automatically be filled in, etc. So how does that information need to be stored in the cookie? Like it is above, or does it have to be, UserName1 = bob, Password1=Passw0rd1 UserName2 = harry, Password2=BLANK UserName3 = george, Password3=R0jjd6s Are the username and password values actually stored in the same cookie, or is each piece of data separate? Any information would be good.

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• Convert Normalize table to Unormalize table

  - by M R Jafari

  I have tow tables, Table A has 3 columns as StudentID, Name, Course, ClassID and Table B has many columns as StudentID, Name, Other1, Other2, Other3 ... I want convert Table A to Table B. Please help me! Table A StudentID Name Course ClassID 85001 David Data Base 11 85001 David Data Structure 22 85002 Bob Math 33 85002 Bob Data Base 44 85002 Bob Data Structure 55 85002 Bob C# 66 85003 Sara C# 77 85003 Sara Data Base 88 85004 Mary Math 99 85005 Mary Math 100 … Table B SdentdID Name Other 1 Other 2 Other 3 Other 4 … 85001 David DBase,11 DS,22 85002 Bob Math,33 DB,44 DS,55 C#,66 85003 Sara C#,77 DBase,88 85004 Mary Math,99

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• mysql true row merge... not just a union

  - by panofish

  What is the mysql I need to achieve the result below given these 2 tables: table1: +----+-------+ | id | name | +----+-------+ | 1 | alan | | 2 | bob | | 3 | dave | +----+-------+ table2: +----+---------+ | id | state | +----+---------+ | 2 | MI | | 3 | WV | | 4 | FL | +----+---------+ I want to create a temporary view that looks like this desired result: +----+---------+---------+ | id | name | state | +----+---------+---------+ | 1 | alan | | | 2 | bob | MI | | 3 | dave | WV | | 4 | | FL | +----+---------+---------+ I tried a mysql union but the following result is not what I want. create view table3 as (select id,name,"" as state from table1) union (select id,"" as name,state from table2) table3 union result: +----+---------+---------+ | id | name | state | +----+---------+---------+ | 1 | alan | | | 2 | bob | | | 3 | dave | | | 2 | | MI | | 3 | | WV | | 4 | | FL | +----+---------+---------+ First suggestion results: SELECT * FROM table1 LEFT OUTER JOIN table2 USING (id) UNION SELECT * FROM table1 RIGHT OUTER JOIN table2 USING (id) +----+---------+---------+ | id | name | state | +----+---------+---------+ | 1 | alan | | | 2 | bob | MI | | 3 | dave | WV | | 2 | MI | bob | | 3 | WV | dave | | 4 | FL | | +----+---------+---------+

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• Rails How to get all the grandchildren of an ojbect.

  - by adam

  I have 3 models User has_many :quetions has_many :corrections end Question has_one :correction belongs_to :user end Correction belongs_to :user belongs_to :question So if user Bob asks a question then user Terry can check it and if its wrong offer a correction. Lets stay with bob and assume he as kindly corrected 5 other users, i.e and lets assume he has been lucky to get 3 corrections from other users. I want to be able to do something like this @bob.corrections_offered = 5 correction objects @bob.corrections_received = 3 correction objects the first one is easy as its really just @bob.corrections under the hood. But i dont know how to implement the latter one. Can anyone help?

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• Using the public ssh key from local machine to access two remote users [closed]

  - by Nick

  I have an new Ubuntu (Hardy 8.04) server; it has two users, Alice and Bob. Alice is listed in sudoers. I appended my public ssh key (my local machine's public key local/Users/nick/.ssh/id_rsa.pub) to authorized_keys in remote_server/home/Alice/.ssh/authorized_keys, changed the permissions on Alice/.ssh/ to 700 and Alice/.ssh/authorized_keys to 600, and both the file and folder are owned my Alice. Then added I Alice to sshd_config (AllowUsers Alice). This works and I can login into Alice: ssh -v [email protected] ... debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Server accepts key: pkalg ssh-rsa blen 277 debug1: Authentication succeeded (publickey). debug1: channel 0: new [client-session] debug1: Entering interactive session. Last login: Mon Mar 15 09:51:01 2010 from 123.456.789.00 I then copied the authorized_keys file remote_server/home/Alice/.ssh/authorized_keys to remote_server/home/Bob/.shh/authorized_keys and changed the permissions and ownership and added Bob to AllowUsers in sshd_config (AllowUsers Alice Bob). Now when I try to login to Bob it will not authenticate the same public key. ssh -v [email protected] ... debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Authentications that can continue: publickey debug1: Trying private key: /Users/nick/.ssh/identity debug1: Trying private key: /Users/nick/.ssh/id_dsa debug1: No more authentication methods to try. Permission denied (publickey). Am I missing something fundamental about the way ssh works?

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• Objective-C classes, pointers to primitive types, etc.

  - by Toby Wilson

  I'll cut a really long story short and give an example of my problem. Given a class that has a pointer to a primitive type as a property: @interface ClassOne : NSObject { int* aNumber } @property int* aNumber; The class is instantiated, and aNumber is allocated and assigned a value, accordingly: ClassOne* bob = [[ClassOne alloc] init]; bob.aNumber = malloc(sizeof(int)); *bob.aNumber = 5; It is then passed, by reference, to assign the aNumber value of a seperate instance of this type of class, accordingly: ClassOne* fred = [[ClassOne alloc] init]; fred.aNumber = bob.aNumber; Fred's aNumber pointer is then freed, reallocated, and assigned a new value, for example 7. Now, the problem I'm having; Since Fred has been assigned the same pointer that Bob had, I would expect that Bob's aNumber will now have a value of 7. It doesn't, because for some reason it's pointer was freed, but not reassigned (it is still pointing to the same address it was first allocated which is now freed). Fred's pointer, however, has the allocated value 7 in a different memory location. Why is it behaving like this? What am I minsunderstanding? How can I make it work like C++ does?

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• Beginner python - stuck in a loop

  - by Jeremy

  I have two begininer programs, both using the 'while' function, one works correctly, and the other gets me stuck in a loop. The first program is this; num=54 bob = True print('The guess a number Game!') while bob == True: guess = int(input('What is your guess? ')) if guess==num: print('wow! You\'re awesome!') print('but don\'t worry, you still suck') bob = False elif guess>num: print('try a lower number') else: print('close, but too low') print('game over')`` and it gives the predictable output of; The guess a number Game! What is your guess? 12 close, but too low What is your guess? 56 try a lower number What is your guess? 54 wow! You're awesome! but don't worry, you still suck game over However, I also have this program, which doesn't work; #define vars a = int(input('Please insert a number: ')) b = int(input('Please insert a second number: ')) #try a function def func_tim(a,b): bob = True while bob == True: if a == b: print('nice and equal') bob = False elif b > a: print('b is picking on a!') else: print('a is picking on b!') #call a function func_tim(a,b) Which outputs; Please insert a number: 12 Please insert a second number: 14 b is picking on a! b is picking on a! b is picking on a! ...(repeat in a loop).... Can someone please let me know why these programs are different? Thank you!

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• Altruistic network connection bandwidth estimation

  - by datenwolf

  Assume two peers Alice and Bob connected over a IP network. Alice and Bob are exchanging packets of lossy compressed data which are generated and to be consumes in real time (think a VoIP or video chat application). The service is designed to cope with as little bandwidth available, but relies on low latencies. Alice and Bob would mark their connection with an apropriate QoS profile. Alice and Bob want use a variable bitrate compression and would like to consume all of the leftover bandwidth available for the connection between them, but would voluntarily reduce the consumed bitrate depending on the state of the network. However they'd like to retain a stable link, i.e. avoid interruptions in their decoded data stream caused by congestion and the delay until the bandwidth got adjusted. However it is perfectly possible for them to loose a few packets. TL;DR: Alice and Bob want to implement a VoIP protocol from scratch, and are curious about bandwidth and congestion control. What papers and resources do you suggest for Alice and Bob to read? Mainly in the area of bandwidth estimation and congestion control.

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• Installing ubuntuone

  - by bob

  Linux Mint 14 os I have tried to install ubuntu one onto the linux mint 14 through Synaptic package manager and software manager, both say its installed but when I go to find the programme its not there. installed as what Synaptic says........... ubuntuone client, ubuntuone client data, ubuntuone client gnome, ubuntuone control panel, what else is missing from this list please, it used to be so so easy to install but now, eeeek yours in advance Bob

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• Ubuntu 10.10 not recognizing external hard drive

  - by sr71

  Installed Ubuntu 10.10 on a hard drive by itself (no windows). All updates are up to date. Everything`works fine except when I plug in a 320 gig Toshiba external hard drive....it is not recognized. When I plug in an 8 gig flash drive it is recognized no problem. What do I mean by "not recognized"? I mean: how do you know it was not recognized. You can check the command "cat /proc/partitions" in a terminal with and without the hdd attached. If you see some difference, it's ok. If the difference is something like "sda1" (sd+letter+number) then you have partition on it, maybe it can't be handled in Ubuntu (no filesystem on it or so). If there is only "sda" in the difference for example (sd+letter, but no number after it) then the drive itself is detected, just no partition is created on it. Also you can check out the messages of the kernel, with the "dmesg" command in the terminal. If there is no disk/partition/anything in /proc/partitions, there can be an USB level problem, you can issue command "lsusb" as it was suggested before my answer. It's really matter of what do you mean about "not recognized". @Marco Ceppi @Oli @Pitto By "not recognized" I meant that when I plug in a 8 gig flash drive an icon immediately appears on the desktop imdicating that there is a flash drive plugged in and I can click on it and view the files on the flash drive. It also shows up on the "Nautilus" default file manager. When I plug in the 320 gig Toshiba external hard drive, I get no indication on the desktop or the file manager (thus "not recogized"). When I run the command "cat/proc/partitions/" I get an error message Could not open location 'file:///home/bob/cat/proc/partitions' with or without the external hard drive installed. With the "dmeg" command I get about 10 pages of info with no mention of disk/partition/anything in /proc/partitions. When I run "lsub" command I get the following: bob@bob-desktop:~$ lsusb Bus 005 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 004 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 003 Device 003: ID 04b3:3003 IBM Corp. Rapid Access III Keyboard Bus 003 Device 002: ID 04b3:3004 IBM Corp. Media Access Pro Keyboard Bus 003 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 002 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 001 Device 001: ID 1d6b:0002 Linux Foundation 2.0 root hub bob@bob-desktop:~$

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• PCI Encryption Key Management

  - by Unicorn Bob

  (Full disclosure: I'm already an active participant here and at StackOverflow, but for reasons that should hopefully be obvious, I'm choosing to ask this particular question anonymously). I currently work for a small software shop that produces software that's sold commercially to manage small- to mid-size business in a couple of fairly specialized industries. Because these industries are customer-facing, a large portion of the software is related to storing and managing customer information. In particular, the storage (and securing) of customer credit card information. With that, of course, comes PCI compliance. To make a long story short, I'm left with a couple of questions about why certain things were done the way they were, and I'm unfortunately without much of a resource at the moment. This is a very small shop (I report directly to the owner, as does the only other full-time employee), and the owner doesn't have an answer to these questions, and the previous developer is...err...unavailable. Issue 1: Periodic Re-encryption As of now, the software prompts the user to do a wholesale re-encryption of all of the sensitive information in the database (basically credit card numbers and user passwords) if either of these conditions is true: There are any NON-encrypted pieces of sensitive information in the database (added through a manual database statement instead of through the business object, for example). This should not happen during the ordinary use of the software. The current key has been in use for more than a particular period of time. I believe it's 12 months, but I'm not certain of that. The point here is that the key "expires". This is my first foray into commercial solution development that deals with PCI, so I am unfortunately uneducated on the practices involved. Is there some aspect of PCI compliance that mandates (or even just strongly recommends) periodic key updating? This isn't a huge issue for me other than I don't currently have a good explanation to give to end users if they ask why they are being prompted to run it. Question 1: Is the concept of key expiration standard, and, if so, is that simply industry-standard or an element of PCI? Issue 2: Key Storage Here's my real issue...the encryption key is stored in the database, just obfuscated. The key is padded on the left and right with a few garbage bytes and some bits are twiddled, but fundamentally there's nothing stopping an enterprising person from examining our (dotfuscated) code, determining the pattern used to turn the stored key into the real key, then using that key to run amok. This seems like a horrible practice to me, but I want to make sure that this isn't just one of those "grin and bear it" practices that people in this industry have taken to. I have developed an alternative approach that would prevent such an attack, but I'm just looking for a sanity check here. Question 2: Is this method of key storage--namely storing the key in the database using an obfuscation method that exists in client code--normal or crazy? Believe me, I know that free advice is worth every penny that I've paid for it, nobody here is an attorney (or at least isn't offering legal advice), caveat emptor, etc. etc., but I'm looking for any input that you all can provide. Thank you in advance!

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• OpenSUSE Yast permissions for user

  - by pajton

  I have an OpenSUSE 11.4 box with Kde 4.6. I am currently working to create a sandbox environment for the user, let's call hime bob. Bob isn't allowed to do much in the system, but I'd like to let him configure certain things in yast. I have dektop shortcuts for particular yast modules, e.g. the shortcut executes xdg-su -c "/sbin/yast2 lan" to launch yast lan configuration. Now, I do not want Bob to have to enter password to launch this configuration (just please don't tell me it's insecure - I know this, in this particular setting it is going to be OK). I wanted to do this with setuid, but obiously setting it on *.desktop shortcut doesn't work. There is sudo approach, but I would have to allow Bob to use all yast modules. So, is there anything more fine-grained to set the permissions for exact yast modules? Thanks in advance!

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• Which server software and configuration to retrieve from multiple POP servers, routing by address to correct user

  - by rolinger

  I am setting up a small email server on a Debian machine, which needs to pick up mail from a variety of POP servers and figure out who to send it to from the address, but I'm not clear what software will do what I need, although it seems like a very simple question! For example, I have 2 users, Alice and Bob. Any email to [email protected] ([email protected] etc) should go to Alice, all other mail to domain.example.com should go to Bob. Any email to [email protected] should go to Bob, and [email protected] should go to Alice Anything to *@bobs.place.com should go to Bob And so on... The idea is to pull together a load of mail addresses that have built up over the years and present them all as a single mailbox for Bob and another one for Alice. I'm expecting something like Postfix + Dovecot + Amavis + Spamassassin + Squirrelmail to fit the bill, but I'm not sure where the above comes in, can Postfix deal with it as a set of defined regular expressions, or is it a job for Amavis, or something else entirely? Do I need fetchmail in this mix, or is its role now included in one of the other components above. I think of it as content-filtering, but everything I read about content-filtering is focussed on detecting spam rather than routing email.

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