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• How can I create a .jar file?

  - by Roman

  In the tutorial I found out that jar files can be created in the following way: jar cf jar-file input-file(s) However, it was not clear what are the input-file(s). Is that .java files or .class files? From the examples on the same page I can assume that should be .class files. But now it is not clear which .class files should I put there. After the compilation of .java files I have a lot of .class files. One of the reason of that is that I have a lot files like that: GameWindow$2$10class, GameWindow$2$7.class and so on. Should I include all of them into the command line for the creation of the .jar file? To run my application I use java Game. So, my be I need to use only Game.class file when I create a .jar file? On the other hand other class files corresponds to classes used by the application. My software use external libraries (during compilation I specify .jar files of these libraries). Will .jar file of my application be able to run on the computer which does not contain the .jar file of used library?

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• JQuery/AJAX: Loading external DIVs using dynamic content

  - by ticallian

  I need to create a page that will load divs from an external page using Jquery and AJAX. I have come across a few good tutorials, but they are all based on static content, my links and content are generated by PHP. The main tutorial I am basing my code on is from: http://yensdesign.com/2008/12/how-to-load-content-via-ajax-in-jquery/ The exact function i need is as follows: Main page contains a permanent div listing some links containing a parameter. Upon click, link passes parameter to external page. External page filters recordset against parameter and populates div with results. The new div contains a new set of links with new parameters. The external div is loaded underneath the main pages first div. Process can then be repeated creating a chain of divs under each other. The last div in the chain will then direct to a new page collating all the previously used querystrings. I can handle all of the PHP work with populating the divs on the main and external pages. It's the JQuery and AJAX part i'm struggling with. $(document).ready(function(){ var sections = $('a[id^=link_]'); // Link that passes parameter to external page var content = $('div[id^=content_]'); // Where external div is loaded to sections.click(function(){ //load selected section switch(this.id){ case "div01": content.load("external.php?param=1 #section_div01"); break; case "div02": content.load("external.php?param=2 #section_div02"); break; } }); The problem I am having is getting JQuery to pass the dynamically generated parameters to the external page and then retrieve the new div. I can currently only do this with static links (As above).

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• Silverstripe: outputting DataObjectManager in template include

  - by Fraser

  I have followed the tutorial here http://doc.silverstripe.org/old/modules:dataobjectmanager to create a dataobjectmanager in my CMS. It's all working perfectly there however I am having an issue getting it to output in the template. My code is as follows <?php class InfoArea extends DataObject{ static $db = array( 'Title' => 'Varchar(255)', 'Content' => 'HTMLText' ); static $has_one = array( 'ResortPage' => 'ResortPage' ); public function getCMSFields_forPopup(){ return new FieldSet( new TextField('Title'), new SimpleTinyMCEField('Content') ); } } ResortPage.php ....... static $has_many = array ( "InfoAreas" => "InfoArea" ); ....... $fields->addFieldToTab("Root.Content.AdditionalInformation", new DataObjectManager( $this, 'InfoAreas', 'InfoArea', array('Title' => 'Title','Content'=>'Content'), 'getCMSFields_forPopup' )); ........ I have a template "ResortPage.ss" which has an include "ResortInfo.ss". It is from within this include file that I need to output the DataObject. I have tried the below but it doesn't output anything <% control InfoArea %> $Title $Content <% end_control %> What am I doing wrong here? Thanks

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• Windows service (hosting WCF service) stops immediately on start up

  - by Thr33Dii

  My Question: I cannot navigate to the base address once the service is installed because the service won't remain running (stops immediately). Is there anything I need to do on the server or my machine to make the baseAddress valid? Background: I'm trying to learn how to use WCF services hosted in Windows Services. I have read several tutorials on how to accomplish this and it seems very straight forward. I've looked at this MSDN article and built it step-by-step. I can install the service on my machine and on a server, but when I start the service, it stops immediately. I then found this tutorial, which is essentially the same thing, but it contains some clients that consume the WCF service. I downloaded the source code, compiled, installed, but when I started the service, it stopped immediately. Searching SO, I found a possible solution that said to define the baseAddress when instantiating the ServiceHost, but that didnt help either. My serviceHost is defined as: serviceHost = new ServiceHost( typeof( CalculatorService ), new Uri( "http://localhost:8000/ServiceModelSamples/service" ) ); My service name, base address, and endpoint: <service name="Microsoft.ServiceModel.Samples.CalculatorService" behaviorConfiguration="CalculatorServiceBehavior"> <host> <baseAddresses> <add baseAddress="http://localhost:8000/ServiceModelSamples/service"/> </baseAddresses> </host> <endpoint address="" binding="wsHttpBinding" contract="Microsoft.ServiceModel.Samples.ICalculator"/> <endpoint address="mex" binding="mexHttpBinding" contract="IMetadataExchange"/> </service> I've verified the namespaces are identical. It's just getting frustrating that the tutorials seem to assume that the Windows service will start as long as all the stated steps are followed. I'm missing something and it's probably right in front of me. Please help!

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• How to use different providers for Linq to entities?

  - by Anders Svensson

  I'm trying to familiarize myself a bit more with database programming, and I'm looking at different ways of creating a data access layer for applications. I've tried out a few ways but there is such a jungle of different database technologies that I don't know what to learn. For instance I've tried using datasets with tableadapters. Using that I am able to switch data provider rather easily (by programming against the interfaces such as IDbConnection). This is one thing I would want to achieve. But I also know everyone's talking about LINQ, and I'm trying to get to know that a bit better too. So I have tried using Linq to Sql classes as the data access layer as well, but apparently this is not provider independent (works only for SQL Server). So then I read about the Entity Framework (which just as Linq to SQL apparently has gotten its share of bashing already...). It's supposed to be provider independent everybody says, but how? I tried out a tutorial to create an entity data model, but the only providers to choose from were SQL Server/Express. Just for learning purposes, I would like to know how to use the entity framework with MS Access/OleDb. Also, I would appreciate some input on what is the preferred database technology for data access. Is it LINQ still after all the bashing, or should you just use datasets because they are provider independent? Any pointers for what to learn would be great, because it's just too much to learn it all if I'm not going to use it in the end...!

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• Remove the hash after Ajax loading (I'm ajaxing wordpress 8-) )

  - by Alberto

  Hi everybody, I followed this great tutorial to"ajax" my blog:http://www.deluxeblogtips.com/2010/05/how-to-ajaxify-wordpress-theme.html But it creates some problems and I think the problem is in the hash that ajax creates. So, after the content is loaded, how can I remove the hash from the url? I copy my code here: jQuery(document).ready(function($) { var $mainContent = $("#content"), siteUrl = "http://" + top.location.host.toString(), url = ''; $(document).delegate("a[href^='"+siteUrl+"']:not([href*=/wp-admin/]):not([href*=/wp-login.php]):not([href$=/feed/]):not([href*=/go.php]):not(.comment-reply-link)", "click", function() { location.hash = this.pathname; $('html, body').animate({scrollTop:0}, 'fast'); return false; }); $("#searchform").submit(function(e) { location.hash = '?s=' + $("#search").val(); e.preventDefault(); }); $(window).bind('hashchange', function(){ url = window.location.hash.substring(1); if (!url) { return; } url = url + " #inside"; $mainContent.html('<div id="loader">Caricamento in corso...</div>').load(url, function() { //$mainContent.animate({opacity: "1"}); scriptss(); }); }); $(window).trigger('hashchange'); }); Thank all very much!

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• For a 1view/scene to 2view/scene app, what application should I choose in Xcode?

  - by Tony Xu

  The question may be simple to some others, but I have been struggling with this for a while. The app I want would be like this: first scene/view with two big buttons (no toolbar item), click each one to get into two new scenes. So totally three scenes. In Xcode, what application should I choose? And in storyboard how/should I drag/draw? Thanks. Update: thanks for the link, the big-number-user. I actually read that tutorial before I asked. A little update on what I got so far: 1, I selected "single view", so there's view controller 1 (VC1) in the storyboard. 2, dragged a navigation controller (NC), and move the initial view arrow pointing to NC 3, control-drag to link NC and VC1, selected "relationship segue root view controller" when some small dialog popup. IS THIS CORRECT? 4, created two additional VC, VC3 and VC4, control-drag link each to NC. selected "push", IS THIS CORRECT? 5, in VC1, I added two buttons, showVC3 and showVC4. NOW I DON'T KNOW how to add IBAction to button showVC3 and showVC4. I tried to control-drag it to ViewController.m file @interface and @end section, but failed. What should I do next?

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• How to use CellRenderer for GregorianCalendar?

  - by HansDampf

  So I have been trying to use the example from Tutorial and change it so it fits my program. The getColumnValue method returns the object that holds the information that is supposed to be displayed. Is this the way to go or should it rather return the actual String to be displayed. I guess not because that way I would mix the presentation with the data, which I was trying to avoid. public class IssueTableFormat implements TableFormat<Appointment> { public int getColumnCount() { return 6; } public String getColumnName(int column) { if(column == 0) return "Datum"; else if(column == 1) return "Uhrzeit"; else if(column == 2) return "Nummer"; else if(column == 3) return "Name"; else if(column == 4) return "letzte Aktion"; else if(column == 5) return "Kommentar"; throw new IllegalStateException(); } public Object getColumnValue(Appointment issue, int column) { if(column == 0) return issue.getDate(); else if(column == 1) return issue.getDate(); else if(column == 2) return issue.getSample(); else if(column == 3) return issue.getSample(); else if(column == 4) return issue.getHistory(); else if(column == 5) return issue.getComment(); throw new IllegalStateException(); } } The column 0 and 1 contain a GregorianCalendar object, but I want column 0 to show the date and 1 to show the time. So I know using cellRenderers can help here. This is what I tried. public class DateRenderer extends DefaultTableCellRenderer { public DateRenderer() { super(); } public void setValue(Object value) { GregorianCalendar g =(GregorianCalendar) value; value=g.get(GregorianCalendar.HOUR); } } But the cell doesnt show anything, what is wrong here?

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• entering datas of php page to database

  - by Rahima farzana.S

  I have a php form with two text boxes and i want to enter the text box values into the database. I have created the table (with two columns namely webmeasurementsuite id and webmeasurements id) I used the following syntax for creating table: CREATE TABLE `radio` ( `webmeasurementsuite id` INT NOT NULL, `webmeasurements id` INT NOT NULL ); Utilising the tutorial in the following link, I wrote the php coding but unfortunately the datas are not getting entered into the database. I am getting an error in the insert sql syntax. I checked it but i am not able to trace out the error.Can anyone correct me? I got the coding from http://www.webune.com/forums/php-how-to-enter-data-into-database-with-php-scripts.html $sql = "INSERT INTO $db_table(webmeasurementsuite id,webmeasurements id) values ('".mysql_real_escape_string(stripslashes($_REQUEST['webmeasurementsuite id']))."','".mysql_real_escape_string(stripslashes($_REQUEST['webmeasurements id']))."')"; echo$sql; My error is as follows: INSERT INTO radio(webmeasurementsuite id,webmeasurements id) values ('','')ERROR: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'id,webmeasurements id) values ('','')' at line 1

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• javascript accordion - tracking time question

  - by JohnMerlino

  Hey all, I was reading up on this javascript tutorial: http://www.switchonthecode.com/tutor...ccordion-menus Basically, it shows you how to create an accordion using pure javascript, not jquery. All made sense to me until the actual part of tracking the animation. He says "Because of all that, the first thing we do in the animation function is figure out how much time has passed since the last animation iteration." And then uses this code: Code: var elapsedTicks = curTick - lastTick; lastTick is equal to the value of when the function was called (Date().getTime()) and curTick is equal to the value when the function was received. I don't understand why we are subtracting one from the other right here. I can't imagine that there's any noticeable time difference between these two values. Or maybe I'm missing something. Is that animate() function only called once every time a menu title is clicked or is it called several times to create the incremental animation effect? setTimeout("animate(" + new Date().getTime() + "," + TimeToSlide + ",'" + openAccordion + "','" + nID + "')", 33); Thanks for any response.

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• Using AJAX in Rails: How do I change a button as soon as it's clicked?

  - by sdc

  Hey! I'm teaching myself Ruby, and have been stuck on this for a couple days: I'm currently using MooTools-1.3-compat and Rails 3. I'd like to replace one button (called "Follow") with another (called "Unfollow") as soon as someone clicks on it. I'm using :remote = true and have a file ending in .js.erb that's being called...I just need help figuring out what goes in this .js file The "Follow" button is in a div with id="follow_form", but there are many buttons on the page, and they all have an id = "follow_form"...i.e. $("follow_form").set(...) replaces the first element and that's not correct. I need help replacing the button that made the call. I looked at this tutorial, but the line below doesn't work for me. Could it be because I'm using MooTools instead of Prototype? $("follow_form").update("<%= escape_javascript(render('users/unfollow')) %") ps. This is what I have so far, and this works: in app/views/shared: <%= form_for current_user.subscriptions.build(:event => @event), :remote => true do |f| %> <div><%= f.hidden_field :event %></div> <div class="actions"><%= f.submit "Follow" %></div> <% end %> in app/views/events/create.js.erb alert("follow!"); //Temporary...this is what I'm trying to replace *in app/controllers/subscriptions_controller.rb* def create @subscription = current_user.subscriptions.build(params[:subscription]) @subscription.save respond_to do |format| format.html { redirect_to(..) } format.js {render :layout} end Any help would be greatly, greatly appreciated!

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• Import Excel into Rails app

  - by Jack

  Hi, I am creating a small rails app for personal use and would like to be able to upload excel files to later be validated and added to the database. I had this working previously with csv files, but this has since become impractical. Does anyone know of a tutorial for using the roo or spreadsheet gem to upload the file, display the contents to the user and then add to the database (after validating)? I know this is quite specific, but I want to work through this step by step. All I have so far is an 'import' view: <% form_for :dump, :url=>{:controller=>"students", :action=>"student_import"}, :html => { :multipart => true } do |f| -%> Select an Excel File : <%= f.file_field :excel_file -%> <%= submit_tag 'Submit' -%> <% end -%> But have no idea how to access this uploaded file in the controller. Any suggestions/help would be welcomed. Thanks

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• Unable to run JAR file (created in Eclipse)

  - by Trist

  I hate starting a post with this but I'm new to Java... I've followed this tutorial to create a socket server (mines in Eclipse). I can run the server within Eclipse, all is well. But when I try to export the project I can't figure out how to run it. I keep getting this error (it varies depending on how I run it) Exception in thread "main" java.lang.NoClassDefFoundError: xsocketserver/Main Caused by: java.lang.ClassNotFoundException: xsocketserver.Main at java.net.URLClassLoader$1.run(URLClassLoader.java:200) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:315) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:330) at java.lang.ClassLoader.loadClass(ClassLoader.java:250) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:398) I've read this problem relates to class paths being set. I've tried the following: java -cp libs/xSocket-2.8.12.jar xsocketserver.Main java -jar xSocketServer.jar java -classpath xSocketServer:xSocketServer/libs/xSocket-2.8.12.jar xsocketserver.Main plus many others. The file structure within the JAR is as follows: xSocketServer.jar -> xsocketserver -> Main.class -> xSocketDataHandler.class -> META-INF -> MANIFEST.MF -> libs -> xSocket-2.8.12.jar Incidentally I've tried adding my own manifest file which contains the Class-Path but when I check it it always reads: Manifest-Version: 1.0 Main-Class: xsocketserver.Main I'm guessing this is a common problem based on the number of hits I've seen in Google but I can't fathom what I'm doing wrong. Wrong Export settings maybe??

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• Joomla User Login Question

  - by user277127

  I would like to enable users of my existing web app to login to Joomla with the credentials already stored in my web app's database. By using the Joomla 1.5 authentication plugin system -- http://docs.joomla.org/Tutorial:Creating_an_Authentication_Plugin_for_Joomla_1.5 -- I would like to bypass the Joomla registration process and bypass creating users in the Joomla database altogether. My thought had been that I could simply populate a User object, which would be stored in the Session, and that this would replace the need to store a user in the Joomla database. After looking through the code surrounding user management in Joomla, it seems like any time you interact with the User object, the database is being queried. It therefore seems like my initial idea won't work. Is that right? It looks like, in order to achieve the effect I want, I will have to actually register a user from within the authentication plugin at the time they first login. This is not ideal, so before I go forward with it, I wanted to check with Joomla developers whether it is possible to do what I described above. Thanks in advance -- I am new to Joomla and greatly appreciate your help!

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• jQuery - Cancel form submit (using "return false"?)?

  - by Nike

  Hey there. I'm running into a bit of trouble while trying to cancel the submit of a form. I've been following this tutorial (even though i'm not making a login script), and it seems to be working for him. Here's my form: <form action="index.php" method="post" name="pForm"> <textarea name="comment" onclick="if(this.value == 'skriv här...') this.value='';" onblur="if(this.value.length == 0) this.value='skriv här...';">skriv här...</textarea> <input class="submit" type="submit" value="Publicera!" name="submit" /> </form> And here's the jquery: $(document).ready(function() { $('form[name=pForm]').submit(function(){ return false; }); }); I've already imported jQuery in the header and i know it's working. My first thought was that it might be outdated, but it's actually "just" a year ago. So do anyone see what's wrong? Thanks in advance. EDIT: From what i've read the easiest and most appropriate way to abort the submit is to return false? But i can't seem to get it working. I've searched the forum and i've found several helpful threads but none of them actually works. I must be screwing something up.

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• Python server open all ports

  - by user1670178

  I am trying to open all ports using this code, why can I not create a loop to perform this function? http://www.kellbot.com/2010/02/tutorial-writing-a-tcp-server-in-python/ #!/usr/bin/python # This is server.py file ##server.py from socket import * #import the socket library n=1025 while n<1050: ##let's set up some constants HOST = '' #we are the host PORT = n #arbitrary port not currently in use ADDR = (HOST,PORT) #we need a tuple for the address BUFSIZE = 4096 #reasonably sized buffer for data ## now we create a new socket object (serv) ## see the python docs for more information on the socket types/flags serv = socket( AF_INET,SOCK_STREAM) ##bind our socket to the address serv.bind((ADDR)) #the double parens are to create a tuple with one element serv.listen(5) #5 is the maximum number of queued connections we'll allow serv = socket( AF_INET,SOCK_STREAM) ##bind our socket to the address serv.bind((ADDR)) #the double parens are to create a tuple with one element serv.listen(5) #5 is the maximum number of queued connections we'll allow print 'listening...' n=n+1 conn,addr = serv.accept() #accept the connection print '...connected!' conn.send('TEST') conn.close() How do I make this work so that I can specify input range and have the server open all ports up to 65535? #!/usr/bin/python # This is server.py file from socket import * #import the socket library startingPort=input("\nPlease enter starting port: ") startingPort=int(startingPort) #print startingPort def connection(): ## let's set up some constants HOST = '' #we are the host PORT = startingPort #arbitrary port not currently in use ADDR = (HOST,PORT) #we need a tuple for the address BUFSIZE = 4096 #reasonably sized buffer for data def socketObject(): ## now we create a new socket object (serv) serv = socket( AF_INET,SOCK_STREAM) def bind(): ## bind our socket to the address serv = socket( AF_INET,SOCK_STREAM) serv.bind((ADDR)) #the double parens are to create a tuple with one element serv.listen(5) #5 is the maximum number of queued connections we'll allow serv = socket( AF_INET,SOCK_STREAM) print 'listening...' def accept(): conn,addr = serv.accept() #accept the connection print '...connected!' conn.send('TEST') def close(): conn.close() ## Main while startingPort<65535: connection() socketObject() bind() accept() startingPort=startingPort+1

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• Watching variables in SSIS during debug

  - by Tom H.

  I have a project in SSIS and I've added an Execute SQL Task which sends its result out to a variable. I wanted to confirm the value because I was worried that it would try to write it out as a resultset object rather than an actual integer (in this case I'm returning a COUNT). My first thought was just to run it in debug mode and add the global variable to my Watch window. Unfortunately, when I right-click on the Watch window, the option to "Add Variable" is greyed out. What am I missing here? I've gotten around confirming that my variable is set correctly, so I'm not interested in methods like putting a script in to do a MsgBox with the value or anything like that. For future reference I'd like to be able to watch variables in debug mode. If there are some kind of constraints on that then I'd like to know the what and why of it all if anyone knows. The help is woefully inadequate on this one and every "tutorial" that I can find just says, "Add the variable to the Watch window and debug" as though there should never be a problem doing that. Thanks for any insight!

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• C++: how serialize/deserialize objects without any library?

  - by Winte Winte

  I try to understand how serializing/deserializing works in c++, so I want to do that without any libs. But I really stuck with that. I start with simple objects but when I try to deserilize a vector I understand that I can't get a vector without if I don't write it size before. Moreover, I don't know which format of file I should choose because if digits will be existed before size of vector I haven't chance to read it right. However it is only the vector but I also want to do that with classes and map container. My task is serialize/deserialize a objects as this: PersonInfo { unsigned int age_; string name_; enum { undef, man, woman } sex_; } Person : PersonInfo { vector<Person> children_; map<string, PersonInfo> addrBook_; } Currently I know how to serialize simple objects in way as this: vector<PersonInfo> vecPersonInfo; vecPersonInfo.push_back(*personInfo); vecPersonInfo.push_back(*oneMorePersonInfo); ofstream file("file", ios::out | ios::binary); if (!file) { cout<<"can not open file"; } else { vector<PersonInfo>::const_iterator iterator = vecPersonInfo.begin(); for (; iterator != vecPersonInfo.end(); iterator++) { file<<*iterator; } Could you please suggest how I can do this for this conplex object or a good tutorial that explain it clearly?

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• Printing a JFrame and its components

  - by Alex Terreaux

  I have been working in a big program and one of its functionalities should be to print the contents of the main window. I checked the API and found this example: http://docs.oracle.com/javase/tutorial/2d/printing/gui.html it was very helpful, I tried to use that code in my program by placing this inside the actionperformed method of my print button: PrinterJob job = PrinterJob.getPrinterJob(); job.setPrintable(this); boolean ok = job.printDialog(); if (ok) { try { job.print(); } catch (PrinterException ex) { /* The job did not successfully complete */ } } If I click the print button, I get a printer dialog and when I tell it to print, it just prints a blank document. I know the above code is not all I need, as I've seen in the API's examples there is a print() method, but apparently they never call it, so it is pretty confusing. I've tried calling and using it many times, but with no success. Also, I think that when I finally get it to print, my window will need to be printed in the landscape orientation, it even may need some scaling. Any ideas on how to do that? I would like any useful help to help me implement this code successfully. I know I should be able to do it by myself just by checking the documentation (I've tried for almost 2 days now) but I can't get it to work. I've learned all the programming I know through the internet. Any help will be greatly appreciated.

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• How can I load a div in rails in response to clicks on another div?

  - by mmr

  I'm very new to Rails (and web) programming, so I'm not even sure what technology I should be looking for for this. I've downloaded and run through the first five chapters of the Rails tutorial, but now have a very simple request. On the left hand side of a web page, I will have a table. If the user clicks on an element in that table, I want to have the right hand side of the page show something new. I already have a page to display the table, viz: <div class="center hero-unit"> <div class="container"> <h2>2012 Yearly Report</h2> <div class="row-fluid"> <div class="span12"> <div class="span4"> <table border="1"> </table> </div> <div class="span6"> <!-- load stuff here based on what someone clicks on in the table --> </div> </div> </div> </div> </div> And I'm using bootstrap layouts to display everything. I just don't understand how to change the contents of the 'span6' div based on user behavior in 'span4'.

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• Graph not following orientation

  - by user1214037

  so I am trying to draw some grid lines that in landscape go all the way down to the bottom, however when I switch to landscape the the graph doesn't follow and the grid lines go smaller. I have set the - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation { // Return YES for supported orientations return YES; } However it still doesn't work, here is my code. Can anyone spot the problem? this is the custom view file, the view controller is the default apart from the code above that returns yes. .h file #import <UIKit/UIKit.h> #define kGraphHeight 300 #define kDefaultGraphWidth 900 #define kOffsetX 10 #define kStepX 50 #define kGraphBottom 300 #define kGraphTop 0 @interface GraphView : UIView @end And here is the implementation - (void)drawRect:(CGRect)rect { CGContextRef context = UIGraphicsGetCurrentContext(); CGContextSetLineWidth(context, 0.6); CGContextSetStrokeColorWithColor(context, [[UIColor lightGrayColor] CGColor]); // How many lines? int howMany = (kDefaultGraphWidth - kOffsetX) / kStepX; // Here the lines go for (int i = 0; i < howMany; i++) { CGContextMoveToPoint(context, kOffsetX + i * kStepX, kGraphTop); CGContextAddLineToPoint(context, kOffsetX + i * kStepX, kGraphBottom); } CGContextStrokePath(context); } Any help would be appreciated btw I am following this tutorial http://buildmobile.com/creating-a-graph-with-quartz-2d/#fbid=YDPLqDHZ_9X

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• Make UIViewController outside Navigation Controller

  - by user1447316

  i have a question for you. I'm working on this app that has a walkthrough/tutorial screens and also login ones. On each of this screens there is a button to skip this part and go directly to use the app, without completing the registration (you know, so that people can test it before signing-in). As you can see i'm using Storyboards. The NowPlaying04 ViewController is actually the app itself. Obviously, when the user will be a registered one, i should also be able to jump right back to that screen, skipping the walkthrough and signin process. The first question is: how is the best way to structure this? The second quesion is: how i can make a ViewController outside that Navigation controller. Cause as you can see now, the NowPlaying04 ViewController inherits the top navigation bar. Which is a thing that i don't want. I don't need that. I hope that you have understood my question. I'll appreciate any help. Programmatically or by dragging stuff around, i'm ok with all the solutions. The important thing is that it works correctly! :-)

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• jQuery validation plugin: valid() does not work with remote validation ?

  - by a-dilla

  I got started by following this awesome tutorial, but wanted to do the validation on on keyup and place my errors somewhere else. The remote validation shows its own error message at the appropriate times, making me think I had it working. But if I ask specifically if a field with remote validation is valid, it says no, actually, its not. In application.js I have this... $("#new_user").validate({ rules: { "user[login]": {required: true, minlength: 3, remote: "/live_validations/check_login"}, }, messages: { "user[login]": {required: " ", minlength: " ", remote: " "}, } }); $("#user_login").keyup(function(){ if($(this).valid()){ $(this).siblings(".feedback").html("0"); }else{ $(this).siblings(".feedback").html("1"); } }) And then this in the rails app... def check_login @user = User.find_by_login(params[:user][:login]) respond_to do |format| format.json { render :json => @user ? "false" : "true" } end end I think that my problem might have everything to do with this ticket over at jQuery, and tried to implement that code, but, being new to jQuery, it's all a bit over my head. When I say bit, I mean way way. Any ideas to fix it, or a new way to look at it, would be a big help.

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• Can't push to git hub

  - by John

  I just completed chapter one of the Ruby on Rails Tutorial by Hartl. Posted about one minor hitch previously. Now I started chapter two. I swear I did everything by the book, but now when I try: git push -u origin master I get the following messages after entering my passphrase: ERROR: repository not found fatal: could not read from remote repository Please make sure you have the correct access rights and that the repository exists. When I down loaded heroku tools I think it installed a second version of ruby on my machine. In any case I now have two version listed under All Programs. Could this have screwed thing up? The two versions are Ruby 1.9.2-p290 and 1.9.3-p327. Also when I open the command prompt using 1.9.2 there is a wierd thing at the top before I do anything: 'C:\Program' is not recognized as an internal or external command, operable program or batch file. This is then followed by the normal prompt on the next line. I'm wondering if the use of my public keys have some how gotten screwed up. Any help would be appreciated.

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• check if foler exists in the root jquery

  - by Dimal Chandrasiri

  I'm trying to load an image to a div background using the following file structure in the root. WebContent -- | zharaimages -- | [ItemID] -- | Image.jpg This is done by jQuery and the file structure is inside the root. The ItemID folder is dynamic and I have to check whether the path exists using jQuery and if the path is not valid, I should go to a default path to fetch the default image. How can I check the path is valid using jQuery. I'm hoping to this can be done without an ajax call. Can any one help me on a tutorial or an API I can use for this! UPDATE The files are on the server. The concept I have is that I have 100s of item elements & I want to load an image for each item element. The images are saved in the server ( a local host ) and the folder hierarchy is divided using the item ID as shown. What I want to do is check whether the image file exists before appending it to the background of the item element div. Is this possible. This is a web application developed using spring.

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