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• RestrictedUI: A .NET Library for restricting a user interface based on a security policy

  How to control the user interface using a policy established in a declaratively way, based on user roles and application status.

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• Delete action on a user management system [migrated]

  - by šljaker

  I'm working on User Management System in ASP.NET MVC3. Administrator/Editor can search, insert, update and delete other users from the system. What should I do when admin/editor clicks on Delete user link? Should I redirect him to new yes/no confirmation page or display some jquery popup window? Should I then redirect him to the home page and display message The user has been successfully deleted from the system, or simple redirection should be just fine?

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• Possible to set two values for two different nodes from user input in XForms?

  - by iHeartGreek

  Hi! I would like to set two values for two different nodes from user input in XForms. I am curious about how this is done, if at all possible. For example, if I have the following data model: <xf:instance id="criteria_data" xmlns=""> <criteria> <set> <root></root> <criterion></criterion> </set> </criteria> </xf:instance> <xf:instance id="choices" xmlns=""> <choices> <root label="The Choices">/AAA</root> <choice label="BBB">/@BBB</choice> </choices> </xf:instance> <xf:instance id="choices" xmlns=""> <choices> <root>/AAA</root> <choice label="BBB">/@BBB</choice> <choice label="CCC">/@CCC</choice> <choices> </xf:instance> <xf:bind id="data_criterion" nodeset="instance('criteria_data')/criteria/set/criterion"/> <xf:bind id="data_root" nodeset="instance('criteria_data')/criteria/set/root"/> <xf:bind id="choices_root" nodeset="instance('choices')/root"/> <xf:bind id="choices" nodeset="instance('choices')/choice"/> and my ui code looks like: <xf:select bind="data_criterion" appearance="full"> <xf:label>Your choices:</xf:label> <xf:itemset bind="choices"> <xf:label ref="@label"></xf:label> <xf:value ref="."></xf:value> </xf:itemset> </xf:select> But I essentially want it to be like this (though this is invalid and does not produce any xml at all): <xf:select appearance="full"> <xf:label>Your choices:</xf:label> <xf:itemset bind="choices"> <xf:label ref="@label"></xf:label> <xf:value bind="data_criterion" ref="."></xf:value> <xf:value bind="data_root" ref="instance('choices')/root"></xf:value> </xf:itemset> </xf:select> The XML output I want to achieve (if user checks "BBB"): <criteria> <set> <root>/AAA</root> <criterion>/@BBB</criterion> </set> </criteria> How can I achieve setting these two nodes for the one checkbox seletion? Hope that all made sense... Thanks! :)

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• Virtualmin & git integration

  - by weby3456

  I've installed virtualmin on my VPS to manage my websites. It's working perfect and as expected nearly a year now. Recently I wanted to add some features to one of my sites, and I need git integration. I've correctly installed git & gitweb on my server, and I can create repositories and watch them under http://sub.domain.com/git/gitweb.cgi Here is the current relevant directory tree: /home/user/domains/sub.domain.com/public_html/git/ drwxr-sr-x user user . drwxr-x--- user user .. -rw-r--r-- user user git-favicon.png -rw-r--r-- user user git-logo.png -rwxr-xr-x user user gitweb.cgi -rw-r--r-- user user gitweb.css drwxrwx--- apache user reponame.git /home/user/domains/sub.domain.com/public_html/git/reponame.git/ drwxrwx--- apache user . drwxr-sr-x user user .. drwxrwx--- apache user branches -rwxrwx--- apache user config -rwxrwx--- user user description -rwxrwx--- apache user HEAD drwxrwx--- apache user hooks drwxrwx--- apache user info drwxrwx--- apache user objects drwxrwx--- apache user refs But I have some questions: When I'm visiting http://sub.domain.com/git/gitweb.cgi, the owner is listed as 'Apache'. why? how can I change that? Usually, to create a new git repository, I'll do something like: $ mkdir proj $ cd proj $ git init Initialized empty Git repository in /home/user/proj/.git/ // here I'm creating the files or copy them from somewhere else $ git add *.php $ git add README $ git commit -m 'initial version' But after creating the repository in virtualmin, I can find a new dir named 'reponame.git' but not the '.git' dir. When I'm trying to run any git command (e.g. git status) I'm receiving "fatal: This operation must be run in a work tree". How can I work with that repository? Currently I need to explicitly grant access for users to be able to view the repositories via gitweb. How can I make certain repositories public?

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• Using two joysticks in Cocos2D

  - by Blade

  Here is what I am trying to do: With the left joystick the player can steer the figure and with the right joystick it can attack. Problem is that the left joystick seems to get all the input, the right one does not even register anything. I enabled multipletouch after the eagleView and gone thoroughly over the code. But I seem to miss something. I initiliaze both sticks and it shows me both of them in game, but like I said, only the left one works. I initialize them both. From the h. file: SneakyJoystick *joystick; SneakyJoystick *joystickRight; And in m.file I synthesize, deallocate and initialize them. In order to use one for controlling and the other for attacking I put this: -(void)updateStateWithDeltaTime:(ccTime)deltaTime andListOfGameObjects:(CCArray*)listOfGameObjects { if ((self.characterState == kStateIdle) || (self.characterState == kStateWalkingBack) || (self.characterState == kStateWalkingLeft) || (self.characterState == kStateWalkingRight)|| (self.characterState == kStateWalkingFront) || (self.characterState == kStateAttackingFront) || (self.characterState == kStateAttackingBack)|| (self.characterState == kStateAttackingRight)|| (self.characterState == kStateAttackingLeft)) { if (joystick.degrees > 60 && joystick.degrees < 120) { if (self.characterState != kStateWalkingBack) [self changeState:kStateWalkingBack]; }else if (joystick.degrees > 1 && joystick.degrees < 59) { if (self.characterState != kStateWalkingRight) [self changeState:kStateWalkingRight]; } else if (joystick.degrees > 211 && joystick.degrees < 300) { if (self.characterState != kStateWalkingFront) [self changeState:kStateWalkingFront]; } else if (joystick.degrees > 301 && joystick.degrees < 360){ if (self.characterState != kStateWalkingRight) [self changeState:kStateWalkingRight]; } else if (joystick.degrees > 121 && joystick.degrees < 210) { if (self.characterState != kStateWalkingLeft) [self changeState:kStateWalkingLeft]; } if (joystickRight.degrees > 60 && joystickRight.degrees < 120) { if (self.characterState != kStateAttackingBack) [self changeState:kStateAttackingBack]; }else if (joystickRight.degrees > 1 && joystickRight.degrees < 59) { if (self.characterState != kStateAttackingRight) [self changeState:kStateAttackingRight]; } else if (joystickRight.degrees > 211 && joystickRight.degrees < 300) { if (self.characterState != kStateAttackingFront) [self changeState:kStateAttackingFront]; } else if (joystickRight.degrees > 301 && joystickRight.degrees < 360){ if (self.characterState != kStateAttackingRight) [self changeState:kStateAttackingRight]; } else if (joystickRight.degrees > 121 && joystickRight.degrees < 210) { if (self.characterState != kStateAttackingLeft) [self changeState:kStateAttackingLeft]; } [self applyJoystick:joystick forTimeDelta:deltaTime]; [self applyJoystick:joystickRight forTimeDelta:deltaTime]; } Maybe it has something to do with putting them both to time delta? I tried working around it, but it did not work. So I am thankful for any input you guys can give me :)

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• Users in database server or database tables

  - by Batcat

  Hi all, I came across an interesting issue about client server application design. We have this browser based management application where it has many users using the system. So obvisously within that application we have an user management module within it. I have always thought having an user table in the database to keep all the login details was good enough. However, a senior developer said user management should be done in the database server layer if not then is poorly designed. What he meant was, if a user wants to use the application then a user should be created in the user table AND in the database server as a user account as well. So if I have 50 users using my applications, then I should have 50 database server user logins. I personally think having just one user account in the database server for this database was enough. Just grant this user with the allowed privileges to operate all the necessary operation need by the application. The users that are interacting with the application should have their user accounts created and managed within the database table as they are more related to the application layer. I don't see and agree there is need to create a database server user account for every user created for the application in the user table. A single database server user should be enough to handle all the query sent by the application. Really hope to hear some suggestions / opinions and whether I'm missing something? performance or security issues? Thank you very much.

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• What key on a keyboard can be detected in the browser but won't show up in a text input?

  - by Brady

  I know this one is going to sound weird but hear me out. I have a heart rate monitor that is hooked up like a keyboard to the computer. Each time the heart rate monitor detects a pulse it sends a key stroke. This keystroke is then detected by a web based game running in the browser. Currently I'm sending the following keystroke: (`) In the browser base game I'm detecting the following key fine and if when the user is on any data input screens the (`) character is ignored using a bit of JavaScript. The problem comes when I leave the browser and go back to using the Operating system in other ways the (`) starts appearing everywhere. So my question is: Is there a key that can be sent via the keyboard that is detectable in the browser but wont have any notable output on the screen if I switch to other applications. I'm kind of looking for a null key. A key that is detectable in the browser but has no effect to the browser or any other system application if pressed.

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• What is a typical scenario for and end-user reports design?

  - by Sebastian

  Hello! I'm wondering what would be the typical scenario for using an end-user report designer. What I'm thinking of is to have a base report with all the columns that I can have, also with a basic view of the report (formatting, order of columns, etc.) and then let the user to change that format and order, take out or add (from the available columns) data to it, etc. Is that a common way to address what is called end-user designer for reports or I'm off track? I know it depends on the user (if it's someone that can handle SQL or not for example), but is it common to have a scenario where the user can build everthing from the sql query to the formatting? Thanks! Sebastian

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• can not login to windows

  - by LoRdiE

  Dear, When i login to windows using domain user account, it take a min show welcome and then automatically logoff. I think user profile error, so login with the administrator account and create new local account. When i login using the local user account, it happened the same as domain user account. Only Administrator Level can login to windows. Any know how can i fix this case? Thanks

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• How do I save user specific data in an asp.net site?

  - by Greg McNulty

  I just set up user profiles using asp.net 3.5 using wvd. For each user I would like to store data that they will be updating every day. For example, every time they go for a run they will update time and distance. I intend to allow them to also look up their history of distance and time from any past date. My question is, what does the database schema usually look like for such a set up? Currently asp.net set up a db for me when I made user profiles. Do I just add an extra table for every user? Should there be one big table with all users data? How do I relate a user I'd to their specific data? Etc.... I have never done this before so any ideas on how this is usually done would be very helpful. Thank you.

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• UI suggestions on how to display suggested tags for a given text to a user?

  - by Danny

  I am writing a web-app that uses a tagging system to organize the user's submitted reports. Part of it uses ajax to get suggestions for tags to present to the user based on the content of their report. I am looking for suggestions on how to present this information for the user. I'm not quite certain what a friendly way to do this would be. Edit: Well, most of the responses here seem to be focused on the user typing in keywords. The idea I'm trying to define here is more towards presenting the user a set of suggested keywords that they may accept or decline without having to type a tag in manually. (That option is of course still available to them) --------------------------- # say they can checkoff or select tags they like. | o[tag2] x[foo] o[moo] | | x[tag1] o[bar] | ---------------------------

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• form not identifying the new input fields generated through a javascript

  - by tibin mathew

  Hi, I am developing a site in php. i have some issues with my form i have to more than one software packages at a time. so i have used javascript to append file and a dropdown to my html. i have called ajs function to add the new input fields each time when i click a link. and its displaying correctly. but its not identifying in my action page. i cant take the value of new input fields which i have created through that javascript function. below is the code page which i have used. function addInput(divName){ var newsel= document.createElement('div'); newsel.innerHTML="Operating System: --Select OS--    bc_linux    Linux   Solaris   2000/XP/Vista   XP/Vista   2K/XP/Vista/W7   HP   Windows 2000/XP/Vista zip   Windows 2000/XP/Vista exe   X Server - 2.2M   Fonts - 32.9M"; document.getElementById(divName).appendChild(newsel); var newdiv = document.createElement('div'); newdiv.innerHTML = "Upload Software File: "; document.getElementById(divName).appendChild(newdiv); } <form action="act-add-software.php" method="post" onSubmit="return validate(this);" enctype="multipart/form-data">  Operating System:  Operating System: <select name="frm_os" class="text_area" style="width:200px"> <option value="">--Select OS--</option> <optgroup label="Spind Enabled"> </optgroup> <option value="bc_linux">&nbsp;&nbsp;&nbsp;bc_linux</option> <optgroup label="Packages"> </optgroup> <option value="Linux">&nbsp;&nbsp;&nbsp;Linux</option> <option value="Solaris">&nbsp;&nbsp;&nbsp;Solaris</option> <option value="2000/XP/Vista">&nbsp;&nbsp;&nbsp;2000/XP/Vista</option> <option value="XP/Vista">&nbsp;&nbsp;&nbsp;XP/Vista</option> <option value="2K/XP/Vista/W7">&nbsp;&nbsp;&nbsp;2K/XP/Vista/W7</option> <option value="HP">&nbsp;&nbsp;&nbsp;HP</option> <option value="Windows 2000/XP/Vista zip">&nbsp;&nbsp;&nbsp;Windows 2000/XP/Vista zip</option> <option value="Windows 2000/XP/Vista exe">&nbsp;&nbsp;&nbsp;Windows 2000/XP/Vista exe</option> <option value="X Server - 2.2M">&nbsp;&nbsp;&nbsp;X Server - 2.2M</option> <option value="Fonts - 32.9M">&nbsp;&nbsp;&nbsp;Fonts - 32.9M</option> </select> <a onClick="addInput('dynamicInput');">Add More Package</a> </td> </td> </tr> <tr> <td colspan="2"><table border="0" cellpadding="0" cellspacing="0"> <tr align="center" valign="middle" class="tbl_row1"> <td height="25" align="left" class="font1" width="156" bgcolor="White"><div align="right"> <?if(strstr($frm_server_side_error,'frm_software')){?> <font class="error"><b> <font color="#dd0000">*</font>&nbsp;Upload Software File: </font> <?}else{?> <font class="form_element"> <font color="#dd0000">*</font>&nbsp;Upload Software File: <?}?> </div> </B> </td> <td class="font1" bgcolor="White" align="center" style="padding-left:2px;"><input type="file" name="frm_image[]" class="text_area"> </td> <?if($frm_sfile !=""){?> <td class="font1" bgcolor="White" align="center"></td> <?}else{?> <td class="font1" bgcolor="White" align="center">&nbsp;(Current File: NOT Uploaded Yet) </td> <?}?> </tr> </table></td> </tr> <tr> <td colspan="2"> <div id="dynamicInput"> </div> </td> </tr> <? if(isset($_REQUEST['edit'])){?> <tr> <td colspan="2"><table border="0" cellpadding="0" cellspacing="0"> <tr align="center" valign="middle" class="tbl_row1"> <td height="25" align="left" class="font1" width="156" bgcolor="White"><div align="right">&nbsp;Upload Version TXT File: </div> </B> </td> <td class="font1" bgcolor="White" align="right" style="padding-left:2px;"><input type="file" name="frm_version_txt" class="text_area"> </td> <?if($frm_vers_txt !=""){?> <td class="font1" bgcolor="White" align="center">&nbsp;(Current File: <?echo $frm_vers_txt;?>) </td> <?}else{?> <td class="font1" bgcolor="White" align="center">&nbsp;(Current File: NOT Uploaded Yet) </td> <?}?> </tr> </table></td> </tr> <?}?> <tr><td colspan="2" height="5" ></td></tr> <tr> <td align="right" width="30%" style="font-size:13px;color:#000000;" colspan="2"><div align="left"><font color="#dd0000">&nbsp;&nbsp;&nbsp;*</font> Asterisks denote required fields&nbsp;&nbsp;</div></td> </tr> <tr><td colspan="2" height="5" ></td></tr> <tr> <td align="right" width="30%" style="font-size:13px;color:#000000;" colspan="2"><div align="left"><font color="#dd0000">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</font>Note: Only one software can be uploaded per Operating System for a particular version. </div></td> </tr> <tr> <td colspan="2" height="5" ></td> </tr> <tr valign="middle" bgcolor="White"> <td nowrap colspan="2"><div align="center"> <table> <tr> <input type="hidden" name="like" value="<?=$sub_like?>"> <input type="hidden" name="offset" value="<?=$offset?>"> <input type="hidden" name="edit" value="<?=$faq_id?>"> <input type="hidden" name="add" value="<?=$_REQUEST[add]?>"> <input type="hidden" name="ex_np_link" value="<?=$ex_np_link?>"> <input type="hidden" name="frm_group_show" value="<?=$frm_bc?>"> <input type="hidden" name="frm_pd_id" value="<?=$pdct_id?>"> <input type="hidden" name="count_val" value="1" id="id_count"> <!-- <input type="hidden" name="frm_pdct" value="<?=$pdct_id?>"> <input type="hidden" name="frm_dname" value="<?=$frm_question?>"> <input type="hidden" name="frm_date_created" value="<?=$edit_created_date?>"> --> <input type="hidden" name="frm_txt_else" value="<?=$frm_vers_txt?>"> </tr> </table> </div> </td> </tr> </table> </div> </td> <th background="../admin_images/bg4.jpg" style="background-repeat:repeat-y "scope="row"></th> </tr> <tr> <th width="3%" background="../admin_images/bg8.jpg" style="background-repeat:repeat-y "scope="row">&nbsp;</th> <td colspan="2" style="padding-left:5px;padding-bottom:1px;"><table width="100%" border="0" cellspacing="0" cellpadding="0"> <tr> <td colspan="2" valign="top"><div align="right"> <table border="0"> <tr> <td vAlign="right" title="Save">&nbsp; <input type="Image" src="./../admin_images/save.jpg" name="btn_submit" value="<?=$btn_value?>" onClick="return validate(this.form);"> </td> <td title="Cancel"><a href="manage-software.php?field_name=SUnq&sort_meth=<?=$sort_meth?>&like=<?=$sub_like?>&offset=<?=$offset?>&frm_group_show=<?=$frm_bc?>"><img src="./../admin_images/cancel.jpg" border="0" align="absmiddle"></a></td> <input type="hidden" name="like" value="<?=$sub_like?>"> <input type="hidden" name="offset" value="<?=$offset?>"> </tr> </table> </div></td> </tr> </table></td> <th background="../admin_images/bg4.jpg" style="background-repeat:repeat-y "scope="row"></th> </tr> </form> For the simplicity of viewing this code page i have included only required code lines please help me to solve this issue

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• How to visually reject user input in a table?

  - by FX

  In the programming of a table-based application module (i.e. the user mostly enters tabular data in an already laid-out table), how would you reject user input for a given cell? The scenario is: the user edits the cell, enters something (text, picture, ...) and you want them to notice when they finish editing (hitting enter, for example) that their entry is not valid for your given "format" (in the wider meaning: it can be that they entered a string instead of a number, that their entry is too long, too short, they include a picture while it's not acceptable, ...). I can see two different things happening: You can rather easily fit their entry into your format, and you do so, but you want them to notice it so they can change if your guess is not good enough (example: they entered "15.47" in a field that needs to be an integer, so your program makes it "15") You cannot guess what to do with their entry, and want to inform them that it's not valid. My question specifically is: what visual display can you offer to inform the user that his input is invalid? Is it preferable to refuse to leave the editing mode, or not? The two things I can imagine are: using colors (red background if invalid, yellow background for my case 1 above) when you reject an input, do something like Apple does for password entry of user accounts: you make the cell "shaking" (i.e. oscillating left and right) for one second, and keep the focus/editing in their so they don't loose what they've typed. Let's hear your suggestions. PS: This question is, at least in my thought process, somehow a continuation and a specialization of my previous question on getting users to read error messages. PPS: Made this community wiki, was that the right thing to do on this kind of question or not?

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• jQuery: What listener do I use to check for browser auto filling the password input field?

  - by Jannis

  Hi, I have a simple problem that I cannot seem to find a solution to. Basically on this website here: http://dev.supply.net.nz/vendorapp/ (currently in development) I have some fancy label animations sliding things in and out on focus & blur. However once the user has logged in once the browser will most likely remember the password associated with the users email address/login. (Which is good and should not be disabled.) However I run into issues triggering my label slide out animation when the browser sets the value on the #password field automatically as the event for this is neither focus nor blur. Does anyone know which listener to use to run my function when the browser 'auto fills' the users password? Here is a quick screenshot of the issue:

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• lsusb - where device description comes from

  - by tommyk

  For one of my attached USB devices (2773:0104) I see no description in lsusb command output: user@Thinkpad-Laptop:~/binaries$ lsusb Bus 008 Device 002: ID 0a5c:217f Broadcom Corp. Bus 008 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 007 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 002 Device 036: ID 2773:0104 Where USB description is comming from, is it from device driver or is it stored in the hardware itself ?

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• OSX root user keeps re-enabling itself on reboot

  - by geodave

  Running Snow Leopard. Completely inexplicably, I seem to have enabled the OSX root user by accident. I honestly have no idea how it happened, but if memory serves I was looking at the login pane (with my two user accounts) when I must have hit something, and suddenly the two accounts were replaced by one that just said "Other..." Clicking the "Other..." account allows me to type a username and password, but neither of the normal two accounts would work. Since I never set a root password, it wouldn't let me in that way either. So I booted into Single User mode and ran these commands: /sbin/mount -uw / fsck -fy launchctl load /System/Library/LaunchDaemons/com.apple.DirectoryServices.plist dscl . -passwd /Users/root newpassword and that let me login as root. Then, I went to System Preferences, Accounts, Login Options, clicked Join, Open Directory Utility, and lastly in the Edit menu I clicked "Disable Root User" Great, I thought, back to normal. Except rebooting, I still only have the Other... account visible, and the root password I set beforehand doesn't work anymore! I have to reboot into Single User Mode and go through the whole process again just to get back into the system (as root) How on Earth did I accidentally enable this? I didn't even know about the Directory Utility before now. And most importantly, why the heck would it be re-enabling the root user on boot? Thanks in advance to any help!

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• How to reset the postgres super user password on mac os x

  - by Andrew Barinov

  I installed postgres on my mac running 10.6.8 and I would like to reset the password for the postgres user (I believe this is the super user password) and then restart it. All the directions I found do not work because I think my user name is not recognized by pg as having authority to change the password. (I am on the admin account of my mac) Here is what I tried: Larson-2:~ larson$ psql -U postgres Password for user postgres: psql (9.0.4, server 9.1.2) WARNING: psql version 9.0, server version 9.1. Some psql features might not work. Type "help" for help. postgres=# ALTER USER postgres with password 'mypassword' postgres-# \q and for restart I did: Larson-2:~ larson$ su postgres -c 'pg_ctl -D /opt/local/var/db/postgresql84/defaultdb/ restart > Which didn't work, as the password remained the same as it was before. Can someone provide directions for doing this and for making sure it's recognized by PG? Update I went ahead and edited the pg_hba.conf file located in /Library/PostgreSQL/9.1/data and set the settings as follows: # TYPE DATABASE USER ADDRESS METHOD # "local" is for Unix domain socket connections only local all all trust # IPv4 local connections: host all all 127.0.0.1/32 trust # IPv6 local connections: host all all ::1/128 trust However, like before, the password stayed the same after I changed it. I am not sure what further steps I can take from here.

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• chrooted sftp user with write permissions to /var/www

  - by matthew

  I am getting confused about this setup that I am trying to deploy. I hope someone of you folks can lend me a hand: much much appreciated. Background info Server is Debian 6.0, ext3, with Apache2/SSL and Nginx at the front as reverse proxy. I need to provide sftp access to the Apache root directory (/var/www), making sure that the sftp user is chrooted to that path with RWX permissions. All this without modifying any default permission in /var/www. drwxr-xr-x 9 root root 4096 Nov 4 22:46 www Inside /var/www -rw-r----- 1 www-data www-data 177 Mar 11 2012 file1 drwxr-x--- 6 www-data www-data 4096 Sep 10 2012 dir1 drwxr-xr-x 7 www-data www-data 4096 Sep 28 2012 dir2 -rw------- 1 root root 19 Apr 6 2012 file2 -rw------- 1 root root 3548528 Sep 28 2012 file3 drwxr-x--- 6 www-data www-data 4096 Aug 22 00:11 dir3 drwxr-x--- 5 www-data www-data 4096 Jul 15 2012 dir4 drwxr-x--- 2 www-data www-data 536576 Nov 24 2012 dir5 drwxr-x--- 2 www-data www-data 4096 Nov 5 00:00 dir6 drwxr-x--- 2 www-data www-data 4096 Nov 4 13:24 dir7 What I have tried created a new group secureftp created a new sftp user, joined to secureftp and www-data groups also with nologin shell. Homedir is / edited sshd_config with Subsystem sftp internal-sftp AllowTcpForwarding no Match Group <secureftp> ChrootDirectory /var/www ForceCommand internal-sftp I can login with the sftp user, list files but no write action is allowed. Sftp user is in the www-data group but permissions in /var/www are read/read+x for the group bit so... It doesn't work. I've also tried with ACL, but as I apply ACL RWX permissions for the sftp user to /var/www (dirs and files recursively), it will change the unix permissions as well which is what I don't want. What can I do here? I was thinking I could enable the user www-data to login as sftp, so that it'll be able to modify files/dirs that www-data owns in /var/www. But for some reason I think this would be a stupid move securitywise.

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• Managing arbitrary user permissions under PureFTPd

  - by Sebastián Grignoli

  I need to provide an FTP service that needs to be web-managed in the simplest way possible. My customer wants to create folders and users, and give them read only or read/write access arbitrarily. For example: The folder 'Documents' should be read only for several users, writable for internal users, and invisible for the rest. The folder 'Pictures' should be read only for journalists, writable for associates, and invisible for the rest. The folder 'Media' should be read only, writable or invisible for arbitrary users specified on the admin. There could be a large number of users and folders. I can't find a good way to accomplish that. I thought that I could give each user a home folder and put symlinks for the folders he has read access to, and make the user part of the folder's group when he has write access too, but now I think that this wouldn't work, because with PureFTPd (or ProFTPd) I can only specify the virtual user's mapping to a system user, and only one GUID for each virtual user. My approach requires that I could specify several GUIDs for each user (one by each folder he has write access to). I need to start programming this admin and I still don't know wich approach would work, if any. ¿Any ideas?

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• Win7 - Opening "Programs and Features" as Admin from command line (logged in as regular user)

  - by user1741264

  We have Win7 machines on a domain that we'd like to open the "Programs and Features" control applet via the command line while a regular user is logged in. Heres the catch: I know how to do this using runas from command line BUT after "Programs and Features" opens, I dont truly have the ability to remove a program. I am told that I need to be an Admin to do so. Here are the commands I have tried: runas /user:%computername%\administrator cmd.exe then in the new cmd window running: control appwiz.cpl runas /user:%companydomain%\%domainadminacct% cmd.exe then in the new cmd window running: control appwiz.cpl runas /user:%computername%\administrator cmd.exe then in the new cmd window running: rundll32.exe shell32.dll,Control_RunDLL appwiz.cpl runas /user:%companydomain%\%domainadminacct% cmd.exe then in the new cmd window running: rundll32.exe shell32.dll,Control_RunDLL appwiz.cpl I have also tried all of the above as one long line of code instead of launching a cmd.exe as Admin As you can see, I have tried running the command using both a local admin account (Administrator) AND a domain admin account. I have alos tried launching the runas command as one long command (opening the "programs and features") AND 1st launching a cmd.exe with admin rights and THEN launching the "Prgrams and Features" window. The result is the same: The "Programs and Features" windows opens but when I try to perform an uninstall, I am told I need Admin rights. Thus I am lead to believe that this instance of "Programs and Features" is not truly being run as an admin I am trying to avoid logging the regular user out. I am also aware that every program has its own uninstaller, I do not want to uninstall that way. I want to use the uninstaller in "Programs and Features". Any help is appreciated.

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• Mouse buttons and all keyboard buttons except alt and super randomly stops working

  - by bobbaluba

  A couple of times lately, unity appears to not accept button presses from neither the mouse or the keyboard. This happens after a random amount of time, usually a couple of hours, or right after boot. The weird thing is: I can still move the mouse around. I can press alt to get the unity menu thingy (but i can't type anything in it) I can press super to show/hide the unity search. None of the applications seem to get the input Ive tried connecting a second mouse, same issue I can press ctrl+alt+f1 to drop to a shell tty The shell works fine Now, this is definitely a bug, probably in unity(?), but it's hard to search for when I don't know what's causing it. Is there something I can do to debug? I've found some people that appears to be having the same problem with the mouse only, but most of the time, their questions are unanswered or closed for being too specific. What would be a good strategy to fix this? Should I report it as a bug?

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• Getting Wacom Bamboo Pen + Touch pressure sensitivy in GIMP

  - by Bart van Heukelom

  I've installed my Wacom Bamboo Pen + Touch (CTH-460) in Ubuntu (at least on one system, not another) and the pen works well for controlling the mouse cursor. However, I can't get pressure sensitivity to work in GIMP. I have 4 extra devices in the input devices settings screen now, two of which are the pen and eraser. I've set them both from Disabled to Screen, and left the default settings intact. However, after saving I still don't see any pressure options in the brush tool's options. I've also tried setting the mode to Window instead, but it makes no difference regarding pressure sensitivity. There are no other modes. The pressure works out-of-the-box in Blender (grease pen) so it must be something in GIMP. What can be wrong? Why don't the options appear? How can I debug this?

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• Detecting extremely fast joystick button presses?

  - by DBRalir

  Is it usually possible for the player to press and release a button within a single frame, so that the game engine doesn't have time to detect it? How do programmers usually handle this situation? Is it even necessary to handle it? Specifically, I am asking about GLFW's joystick input capabilities. I am currently using GLFW to make a game, and I've noticed that keyboard and mouse have callback functions, while joysticks do not. Also, it does not appear to be possible to enable "sticky keys" for a joystick. (I have only recently started using GLFW, so please correct me if I am wrong, as having either of those would solve the problem.)

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• IDirect3DDevice9Ex and D3DPOOL_MANAGED?

  - by bluescrn

  So I wanted to switch to IDirect3DDevice9Ex, purely for the SetFrameLatency function, as fullscreen vsynced D3D seemed to produce noticable input lag. But then it tells me 'ha ha ha! now you can't use D3DPOOL_MANAGED!': Direct3D9: (ERROR) :D3DPOOL_MANAGED is not valid with IDirect3DDevice9Ex Is this really as unpleasant as it looks (when you're relying quite heavily on managed resources) - or is there a simple solution? If it really does mean manual management of everything (reloading all static textures, VBs, and IBs on a device reset), is it worth the hassle, will IDirect3DDevice9Ex bring enough benefit to make it worth writing a new resource manager? Starting to think I must be doing something wrong, due to this: Direct3D9: (ERROR) :Lock is not supported for textures allocated with POOL_DEFAULT unless they are marked D3DUSAGE_DYNAMIC. So if I put my (static) textures in POOL_DEFAULT, they need flagging as D3DUSAGE_DYNAMIC, just because I lock them once to load the data in?

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• Joystick acts as mouse; won't stop

  - by Shazzner

  Joystick acts as a mouse, even when I'm playing a game that uses a joystick so I get random mouse events going on. I plugged a joystick in to play Spiral Knights, also installed joystick and jcalibrate. Everything is working good, except by default the joystick moves the mouse around and the button activate mouse keys. Now normally this would be good behavior if I'm on a Myth-box or something, unfortunately when I play Spiral Knights with joystick input I see my mouse cursor moving in the back ground and when I hit a button it thinks I'm pressing right-click so it minimizes everything. Also it creates folders and probably deletes stuff. So, basically how the heck do I stop it from acting as a mouse?

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